Answer:
69.79
Explanation:
According to this question, Gallium element (Ga) has two isotopes namely: 69Ga and 71Ga respectively.
- Isotope 69Ga contains a percent abundance of 60.11 %, the decimal abundance= 0.6011
- Isotope 71Ga contains a percent abundance of 39.89 %, the decimal abundance = 0.3989
Atomic mass of Ga = (mass of isotope 1 × decimal abundance) + (mass of isotope 2 × decimal abundance)
Atomic mass of Ga = (0.6011 × 69) + (0.3989 × 71)
Atomic mass of Ga = 41.4759 + 28.3219
Atomic mass of Ga = 69.797
Atomic mass of Gallium = 69.79
Of the following, which most likely involves a chemical reaction?
NEED ASAP PLEASE
Select one:
a. Boiling water turns a fresh egg into a hard boiled egg.
b. Dissolving salt in water produces a transparent liquid.
c. A huge wave knocks down a beach home.
d. Wind turns a generator to produce electricity.
Evaluate
0.411 + 9.9 + 0.8
and round the answer appropriately,
Answer:
the answer is 11.111 and when you round it to the nearest one it’s 11, but to the nearest tenth it’s 10
Explanation:
What can the flow of electrons be easily compared to?
a.The flow of mud
b.The flow of water
c.The flow of wind
d.The flow of gravity
Gaseous methane CH4 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is the theoretical yield of water formed from the reaction of 15.4g of methane and 90.3g of oxygen gas
Answer:
50.8 g
Explanation:
Equation of reaction.
[tex]CH_4 + 2O_2 \to CO_2 + 2H_2O[/tex]
From the given information, the number of moles of methane = mass/ molar mass
= 15.4 g / 16.04 g/mol
= 0.960 mol
number of moles of oxygen gas = 90.3 g / 32 g/ mol
= 2.82 mol
Since 1 mol of methane requires 2 moles of oxygen
Then 0.960 mol of methane will require = 0.960 mol × 2 = 1.92 mol of oxygen gas
Thus, methane serves as a limiting reagent.
2.82 mol oxygen gas will result in 2.82 moles of water
So, the theoretical yield of water = moles × molar mass
= 2.82 mol × 18.01528 g/mol
= 50.8 g
3: Consider molecules of hydrogen (tiny ones) and oxygen (bigger ones) in a gas mixture. If they have the same average kinetic energy (they will at the same temperature), which molecules have the greatest average speed
Answer: Hydrogen molecules will have greatest average speed.
Explanation:
The formula for average speed is :
[tex]\mu_{av}={\sqrt{\frac{8RT}{\pi\times M}}}[/tex]
R = gas constant
T = temperature
M = Molecular Mass
Now putting all the values:
[tex]\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{8RT}{\pi\times M_{H_2}}}/{\sqrt{\frac{8RT}{\pi\times M_{O_2}}}[/tex]
[tex]\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{16}{2}}[/tex]
[tex]\frac{\nu_{av}_{H_2}}{\nu_{av}_{O_2}}=8[/tex]
Thus average speed of hydrogen is 8 times the average speed of oxygen. Thus hydrogen molecules will have greatest average speed
How many moles are in 563.9 grams of arsenic?
Answer:
No. of moles, n = 7.52 moles
Explanation:
Given that,
Mass, m = 563.9 grams
Molar mass of arsenic = 74.92 g/mol
We need to find the number of moles in 563.9 grams of arsenic. Let it is denoted by n. It is equal to given mass divided by total molar mass.
[tex]n=\dfrac{563.9 }{74.92}\\\\=7.52\ \text{moles}[/tex]
So, there are 7.52 moles in 563.9 grams of arsenic.
6.How many molecules of carbon dioxide are in 400 grams of the substance?
Answer: 5.47x10^24 molecules
Explanation:
6.02214076x10^23 molecules CO2 = 44g
400g = (400/44)*6.02214076*10^23 = 5.47x10^24
According to the concept of Avogadro's number, there are 54.75 ×10²³ molecules of carbon dioxide are 400 grams of the substance.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number .Number of moles= 400/44=9.09 moles which is number of molecules =9.09×6.023×10²³= 54.75 ×10²³ .
Learn more about Avogadro's number,here:
https://brainly.com/question/28812626
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Suppose a current of 220.mA is passed through an electroplating cell with an aqueous solution of AgNO3 in the cathode compartment for 79.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.
Answer:
0.0195 g
Explanation:
Ag^+(aq) + e -------> Ag(s)
Since 1 electron was transferred, that means 96500C of electricity was required
108 g is deposited 96500 C
xg is deposited 220 × 10^-3 × 79.0
x = 108 × 220 × 10^-3 × 79.0/96500
x= 19.5 × 10^-3 g
x= 0.0195 g
If you had excess chlorine, how many moles of of aluminum chloride could be produced from 11.0 g of aluminum
Answer: 0.407 moles of aluminum chloride could be produced from 11.0 g of aluminum.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of aluminium}=\frac{11.0g}{27g/mol}=0.407moles[/tex]
[tex]2Al+3Cl_2\rightarrow 2AlCl_3[/tex]
According to stoichiometry :
[tex]Al[/tex] is the limiting reagent as it limits the formation of product and [tex]Cl_2[/tex] is the excess reagent.
As 2 moles of [tex]Al[/tex] give = 2 moles of [tex]AlCl_3[/tex]
Thus moles of [tex]Al[/tex] give =[tex]\frac{2}{2}\times 0.407=0.407moles[/tex] of [tex]AlCl_3[/tex]
Thus 0.407 moles of aluminum chloride could be produced from 11.0 g of aluminum.
The food web above shows how energy moves through a lake environment. If a chemical company were to put a harmful chemical
that kills off all of the phytoplankton, which animal would be immediately affected?
)
A)
bacteria
B)
invertebrates
human
D)
prey fish
Answer:
Invertebrates than eventually everything would die
What is the concentration of a solution with a volume of 1.38 mL that contains 17.36
grams of ammonium sulfite [(NH4)2SO3)?
Answer:
C = 107.97 mol/L
Explanation:
Given data:
Volume of solution = 1.38 mL (1.38 mL× 1 L /1000 mL = 0.00138 L)
Mass of ammonium sulfite = 17.36 g
Concentration of solution =?
Solution:
We will calculate the number of moles of ammonium sulfite.
Number of moles = mass/molar mass
Number of moles = 17.36 g / 116.15 g/mol
Number of moles = 0.149 mol
Concentration:
C = n/V
C = concentration
n = number of moles of solute
v = volume in L
C = 0.149 mol / 0.00138 L
C = 107.97 mol/L
How many particles of argon (Ar) are present in 18.4L of argon? please
Answer:
Explanation:
C
[tex]4.9 \times 10^{23}[/tex] are present in 18.4L of argon (Ar).
To calculate the amount of particles present in a given amount of volume, it is necessary to have knowledge of the molar volume:
[tex]1 mol = 22.4L[/tex]
Thus, in 22.4L there is 1 mol of an element, remembering that:
[tex]1 mol = 6\times10^{23}[/tex] particles
In this way, it is enough to relate the value of the molar volume given with the value requested by the question:
[tex]\frac{6\times10^{23}particles}{xparticles} = \frac{22.4L}{18.4L}[/tex]
[tex]x = 4.9 \times 10^{23}[/tex] particles
So, [tex]4.9 \times 10^{23}[/tex] are present in 18.4L of argon (Ar).
Learn more about mole calculation in: brainly.com/question/15209553
Two electron(s) are removed from an carbon atom. Enter the chemical symbol of the element.
Answer:
[tex]C^{2+}[/tex]
Explanation:
When a proton is removed, it changes the whole element. However, when electrons are removed, it becomes an ion. Since we are removing two electrons, we are subtracting a negative number, giving us positive two as our net ionic charge. Therefore, the answer is [tex]C^{2+}[/tex]
Calculate the percentage of water in the compound CaSO4 x 6H2O
The percentage of water in the compound CaSO₄.6H₂O = 44.26%
Further explanationGiven
Compound CaSO₄. 6H₂O
Required
The percentage of water
Solution
MW CaSO₄. 6H₂O :
= 40 + 32 + 4.16 + 12.1 + 6.16
= 244
MW 6H2O :
= 12.1 + 6.16
= 108
%water = (108 : 244) x 100%
%water = 44.26
The percentage of water in the compound CaSO₄.6H₂O is 44.26%
Calculation of percentage:Since MW CaSO₄. 6H₂O :
= 40 + 32 + 4.16 + 12.1 + 6.16
= 244
Now
MW 6H2O :
= 12.1 + 6.16
= 108
So, percentage of water = (108 : 244) x 100%
= 44.26
learn more about water here: https://brainly.com/question/5534000
according to the kinetic molecular theory the pressure exerted by a sample of gas at constats volume doubles when the absolute temperature is doubled because
Answer: gas molecules will hit the container walls more frequently and with greater force
Explanation:
According to the postulates of kinetic molecular theory:
1. The pressure exerted by a gas in a container results from collisions between the gas molecules and the container walls.
2. The average kinetic energy of the gas molecules is proportional to the kelvin temperature of the gas.
When the temperature is increased, so the average kinetic energy and the rms speed also increase. This means that the gas molecules will hit the container walls more frequently and with greater force because they are all moving faster. This increase the pressure.
mass
6.00 g of a certain compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 180. g/mol, is burned
completely in excess oxygen, and the mass of the products carefully measured:
product
carbon dioxide 8.80 g
3.60 g
Use this information to find the molecular formula of X.
water
alo
O
х
?
The molecular formula =C₆H₁₂O₆
Further explanationGiven
6.00 g of a certain compound X
The molecular molar mass of 180. g/mol
CO₂=8.8 g
H₂O=3.6 g
Required
The molecular formula
Solution
mass C in CO₂ :
= 1.12/44 x 8.8
= 2.4 g
mass H in H₂O :
= 2.1/18 x 3.6
= 0.4 g
Mass O in compound :
= 6-(2.4+0.4)
= 3.2 g
Mol ratio C : H : O
= 2.4/12 : 0.4/1 : 3.2/16
= 0.2 : 0.4 : 0.2
= 1 : 2 : 1
The empirical formula : CH₂O
(CH₂O)n=180 g/mol
(12+2+16)n=180
(30)n=180
n=6
(CH₂O)₆=C₆H₁₂O₆
A homogeneous mixture is?
Answer:
two components of the same thing
Explanation:
CONVERSIONS
Complete the following conversions
3. Given the following reaction, how many moles of Al2O3 will be produced if 1.35 moles of Fe are produced?
(8 points)
2 AI 3 Feo
3 Fe + Al2O3
+
it’s number 3 pls help
Answer:
Number of moles of Al₂O₃ = 0.45 mol
Explanation:
Given data:
Number of moles of Fe produced = 1.35 mol
Number of moles of Al₂O₃ = ?
Solution:
2Al + 3FeO → 3Fe + Al₂O₃
now we will compare the moles of iron and Al₂O₃
Fe : Al₂O₃
3 : 1
1.35 : 1/3×1.35 = 0.45 mol
What is the mass in grams of 2.25 mol of the element iron, Fe?
126 g Fe
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableUsing Dimensional AnalysisExplanation:Step 1: Define
2.25 mol Fe
Step 2: Identify Conversions
Molar Mass of Fe - 55.85 g/mol
Step 3: Convert
Set up: [tex]\displaystyle 2.25 \ mol \ Fe(\frac{55.85 \ g \ Fe}{1 \ mol \ Fe})[/tex]Multiply: [tex]\displaystyle 125.663 \ g \ Fe[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
125.663 g Fe ≈ 126 g Fe
the system that acts as a barrier from the outside the environment is called________
The air barrier system
An aqueous solution of ethanol, CH3CH2OH, has a concentration of 5.82 mol/L and has a density of 0.957 g/mL. What are the mass percent and mole fraction of CH3CH2OH in this solution
Answer:
1. Mass percent of ethanol = 28.02 %.
2. Mole fraction of ethanol = 0.13.
Explanation:
1. To find the mass percent we need to use the following equation:
[tex]\%_{m/m} = \frac{m_{e}}{m_{s}} \times 100[/tex]
Where:
[tex]m_{e}[/tex] is the mass of ethanol
[tex]m_{s}[/tex] is the mass of the solution
We need to calculate the mass of ethanol and the mass of the solution:
[tex] d = \frac{m_{s}}{V} [/tex]
Where:
d: is the density of the solution = 0.957 g/mL
V: is the volume = 1 L
[tex] m_{s} = d*V = 0.957 \frac{g}{mL}*\frac{1000 mL}{1 L}*1 L = 957 g [/tex]
Now, from the concentration we can find the mass of ethanol:
[tex] C = \frac{n_{e}}{V} = \frac{m_{e}}{M_{e}*V} [/tex]
Where:
[tex]M_{e}[/tex]: is the molar mass of ethanol = 46.07 g/mol
[tex]n_{e}[/tex]: is the number of moles of ethanol = m/M
[tex] m_{e} = C*M*V = 5.82 \frac{mol}{L}*46.07 \frac{g}{mol}*1 L = 268.13 g [/tex]
Finally, the mass percent of ethanol is:
[tex]\%_{m/m} = \frac{268.13 g}{957 g} \times 100 = 28.02 \%[/tex]
2. The mole fraction of ethanol is given by:
[tex] \chi_{e} = \frac{n_{e}}{n_{s}} [/tex]
The number of moles of ethanol is:
[tex]n_{e} = \frac{m_{e}}{M_{e}} = \frac{268.13 g}{46.07 g/mol} = 5.82 moles[/tex]
And the moles of the solution is:
[tex] n_{s} = n_{e} + n_{w} [/tex]
Where w is for water
[tex] n_{s} = n_{e} + \frac{m_{w}}{M_{w}} [/tex]
[tex] n_{s} = n_{e} + \frac{m_{s} - m_{e}}{M_{w}} [/tex]
[tex]n_{s} = 5.82 moles + \frac{957 g - 268.13 g}{18 g/mol} = 44.09 moles[/tex]
Hence, the mole fraction of ethanol is:
[tex]\chi_{e} =\frac{5.82 moles}{44.09 moles}=0.13[/tex]
I hope it helps you!
A ball thrown across a football field is an example of a(n)
I don't know what you mean by the question, but in science it is Newton's second law.
"The second law explains how the velocity of an object changes when it is subjected to an external force."
I hope this helped!+*♡
What is the molar mass of CuCIO3
147.05 g/mol
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableExplanation:Step 1: Define
CuClO₃
Step 2: Find MM
Molar Mass of Cu - 63.55 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CuClO₃ - 63.55 + 35.45 + 3(16.00) = 147.05 g/mol
How many moles of calcium, Ca, are in 5.00 g of calcium?
0.125 mol Ca
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableUsing Dimensional AnalysisExplanation:Step 1: Define
5.00 g Ca
Step 2: Identify Conversions
Molar mass of Ca - 40.08 g/mol
Step 3: Convert
Set up: [tex]\displaystyle 5.00 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca})[/tex]Multiply: [tex]\displaystyle 0.12475 \ mol \ Ca[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
0.12475 mol Ca ≈ 0.125 mol Ca
17. Which of the following
hydrocarbon undergo addition
reaction:
С3Н6
С2Н6
ОООО
С3Н8
CH4
Answer:
С3Н6.
Explanation:
Hello!
In this case, since addition reactions imply that a radical or some radicals are added to the parent chain, we notice that only unsaturated hydrocarbons are able to undergo addition whereas saturated ones undergo substitution reactions as they already have all the carbon bonds bonded to leaving groups.
In such a way, we can rule out C2H6, C3H8 and CH4 as they are all alkanes; therefore, only С3Н6 is able to undergo an addition reaction due to the C=C which is able to lose one of those bonds and allow an incoming radical to get included into the parent chain.
Best regards!
which type of organism carries out cellular respiration
Answer:Prokaryotic cells carry out cellular respiration within the cytoplasm and eukaryotic cells carry out respiration in the mitochondria
Explanation:
The wrist is ________________ to the hand.
Answer:
complimentary
Explanation:
Answer:
Proximal
Explanation:
Trees are to renewable as____is to nonrenewable.
A. water
B. oil
C. corn
D. paper
Answer:
b.oil
Explanation:
oil is a nonrewnewable resource
A sample of 25.0 mL of 0.120 M Ca(OH)2(aq) is titrated with 0.150 M HCl(aq). What volume of HCl(aq) is needed to completely neutralize the Ca(OH)2(aq)
Answer:
[tex]V_{HCl}=48.0 mL[/tex]
Explanation:
Hello!
In this case, since the reaction between calcium hydroxide and hydrochloric acid shows a 2:1 mole ratio between them:
[tex]2HCl+Ca(OH)_2\rightarrow CaCl_2+2H_2O[/tex]
We need to use the following mole ratio:
[tex]2n_{Ca(OH)_2}=n_{HCl}[/tex]
That can be written in volumes and concentrations:
[tex]2M_{Ca(OH)_2}V_{Ca(OH)_2}=M_{HCl}V_{HCl}[/tex]
Thus, we solve for the volume of HCl as it is the unknown:
[tex]V_{HCl}=\frac{2M_{Ca(OH)_2}V_{Ca(OH)_2}}{M_{HCl}}[/tex]
Therefore, we plug in to obtain:
[tex]V_{HCl}=\frac{2*0.120M*25.0mL}{0.150M} \\\\V_{HCl}=48.0 mL[/tex]
Best regards!
At 400K both compounds are gases. At this temperature, which compound, CH4(g) or CCl4(g) , behaves more like an ideal gas
Answer:
CH4
Explanation:
The ideal gas behavior of individual gases often depend on the magnitude of intermolecular interaction between the molecules of the gas as well as the presence or absence of polar bonds.
In CCl4, there are polar bonds and the presence of the more electronegative chlorine atom in the molecule and consequently a greater degree of intermolecular interaction at 400K compared to CH4 which contains only non polar bonds.
Therefore, CH4 displays greater ideal gas behavior at 400K than CCl4.