of the following sets of reagents and conditions, which one represents the most efficient synthesis of 1-bromo-2-methylcyclohexane?

The product that is used on the natural nail prior to application to assist in adhesion and serves to chemically bond the enhancement product to the natural nail is known as nail primer.

A nail primer is a chemical agent used in esthetic centers before applying a colored polish to the nails and serves as an adhesive product.

The nail primers are also very useful for improving the cleaning efficiency of the product before its application.

Nail care products include different types of chemical formulations such as, for example, creams that reinvigorate the cuticle.

In conclusion, the chemical formulation employed on the natural nail that is capable of enhancing and also assisting adhesion is called the nail primer.

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Answer:

.5 gm / ml

Explanation:

Density is defined as   mass/ volume

  so   density of this substance is   5 gm / 10 ml =  .5  gm/ ml

Transferred to the lipoamide by an earlier intermediate in the process.

The pyruvate dehydrogenase complex (PDC) is a mitochondrial multienzyme complex composed of three different enzymes

the pyruvate dehydrogenase complex is the bridge between glycolysis and the citric acid cycle

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Utilizing wireless communication and camera imagery is the most effective technological solution to this problem.

To find the answer, we need to know more about the wireless communication and camera imagery

Thus, we can conclude that, the wireless connectivity and camera imaging method meet this obstacle.

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It is a thermodynamically spontaneous process that means Protein folding occurs. The value of ΔG must be negative in the case of folding but in the case of unfolding, the value of ΔG must be positive.

When the process is thermodynamically spontaneous process results in Protein folding otherwise the process is unfolding.

The value for ΔG must be negative in the case of the folding process and the value for ΔG must be positive in the case of the unfolding process. The value of a thermodynamic parameter for the reverse reaction has an opposite sign but the same value that's why the value for ΔG must be positive and known as unfolding (denaturation) process.

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Answer:

0.702 L H₂O

Explanation:

To find the volume of water needed to dilute the stock solution, you need to (1) find the moles of the stock solution (via molarity formula), then (2) find the volume of the diluted solution (via molarity formula), and then (3) find the volume of water needed.

(Step 1)

Molarity (M) = moles / volume (L)                 <----- Molarity formula

5 M = moles / 0.500 L                                  <----- Insert values

2.5 = moles HCl                                           <----- Multiply both sides by 0.500

(Step 2)

Molarity = moles / volume                           <----- Molarity formula

2.08 M = 2.5 moles / volume                      <----- Insert values

(2.08 M) x volume = 2.5 moles                   <----- Multiply both sides by volume

volume = 1.20 L                                           <----- Divide both sides by 2.08

(Step 3)

Diluted Volume = 1.20 L

Stock Volume = 0.500 L

Water Volume = ? L

Diluted Volume = Stock Volume + Water Volume

1.20 L =  0.500 L + Water Volume

0.702 L = Water Volume

Explanation:

125)118

126)6

127)9

128)Au

There are 118 elements discovered yet and they are included in the periodic table.There are 6 hydrogens in ethanol. Number of total atoms in it is 9. The symbol of gold is Au.

Periodic table is a classification of elements discovered in nature. There are groups and periods for these elements where groups are vertical columns of elements with similar physical and chemical properties.

There are 118 elements in the periodic table. Thus option C is correct.

Ethanol is a simple alcohol formed by 2 carbons and 5 hydrogens with an OH group. Thus there are total 6  (option C) hydrogens and a total of 9 atoms (option C).  Ethanol is widely used in making of alcoholic products.

The chemical symbol of gold is Au. Chemical symbols are elements are derived from their latin names. The latin name of gold is Aurom. Thus it has the symbol Au. Therefore, option B is correct.

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Answer:

Just add what they equal to hope this helps :)

Explanation:

The equilibrium constant expression for this system is Keq=[NH3][H2S]

The ratio of the equilibrium concentrations of the products to the concentrations of the reactants raised to their respective powers to match the coefficients in the equilibrium equation is K for a system in equilibrium, according to the law of mass action. The equilibrium constant expression is known as the ratio.

Therefore, the equilibrium constant expression for this system is Keq=[NH3][H2S]

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According to Charle's law equation, the volume of a sample of carbon dioxide will be 684.6 mL and the temperature will be 283.60 K.

According to Charles' Law, the volume of a gas container with a certain amount of gas within is precisely proportional to the temperature when the pressure is constant.

[tex]V_{1}[/tex] = 684.6 mL

[tex]V_{2}[/tex] = 933.9 mL

[tex]T_{1}[/tex] = ?

[tex]T_{2}[/tex] = 387 K

Using Charle's law equation

[tex]\frac{684.6}{T_{1} } = \frac{933.9}{387}[/tex]

[tex]T_{1} = \frac{2,64,862.8}{933.9}[/tex]

[tex]T_{1} = 283.60 K[/tex]

According to Charle's law equation, the temperature at 684.6 mL volume was 283.60 K.

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The Haber process (a) is used to manufacture ammonia.

The Haber process, which artificially fixes nitrogen, is currently the primary industrial method for producing ammonia.

Using a metal catalyst and high temperatures and pressures, the process turns atmospheric nitrogen (N2) into ammonia (NH3) by reacting with hydrogen (H2).

Haber's reaction is -   N2   +    H2   ------>     NH3

The gases (nitrogen and hydrogen) are passed through four beds of catalyst in this conversion, which is normally carried out at pressures above 10 MPa (100 bar; 1,450 psi) and between 400 and 500 °C (752 and 932 °F). Cooling is applied between each pass to maintain a reasonable equilibrium constant.

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The coordination number for pb will be 12

Four atoms make up each unit cell of the face-centered cubic (fcc), which has a coordination number of 12. Two atoms make up each unit cell of the body-centered cubic (bcc), which has a coordination number of eight.

The number of atoms, ions, or molecules that a central atom or ion in a complex, coordination compound, or crystal holds as its closest neighbours.

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Excited state configuration are 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹ , [Kr] 5s¹ 4d¹⁰ , [He] 2s¹ 2p⁵and  Ground state configuration are [Ne] 3s²3p³ ,  [Ar] 4s¹ 3d⁶.

The electronic configuration of an element describe the symbolic notation that how electrons are distributed in its atomic orbitals.

The ground state electronic configuration of an element describe the arrangement of an atom at its lowest possible energy state.

Cr has the ground state electronic configuration [Ar] 4s¹ 3d⁶.

Ag has the excited state electronic configuration [Kr] 5s¹ 4d¹⁰ .

Thus from the above conclusion we can say that Excited state configuration are 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹ , [Kr] 5s¹ 4d¹⁰ , [He] 2s¹ 2p⁵and  Ground state configuration are [Ne] 3s²3p³ ,  [Ar] 4s¹ 3d⁶.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Classify the electron configurations of neutral atoms based on whether they represent an excited state configuration or a ground state configuration.

Excited State                       Ground State

Answer Bank:

1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹

[Ar] 4s¹ 3d⁶

[Ne] 3s²3p³

[He] 2s¹ 2p⁵

[Kr] 5s¹ 4d¹⁰

(1.) Which neutral atom has the excited or ground state electronic configuration, [Ar] 4s¹ 3d⁶ ? Enter the name of the element.

(2.) Which neutral atom has the excited or ground state electronic configuration, [Kr] 5s¹ 4d¹⁰ ? Enter the name of the element

The statement that identifies an oxidation-reduction reaction is a reaction in which oxidation numbers change (option C).

A redox or oxidation-reduction reaction is a chemical reaction in which some of the atoms have their oxidation number changed.

In a chemical reaction that involves oxidation and reduction, the oxidation number of the involved ions either decreases or increases.

Therefore, the statement that identifies an oxidation-reduction reaction is a reaction in which oxidation numbers change.

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Answer:

best answer is D

Explanation:

if element has even number then protons and neutrons are same but if element has odd number then we should add 1 number in number of protons to know neutrons. but this rule is not work in 4 element that element are argon, nitrogen, hydrogen and one other

Taking into account the reaction stoichiometry, 3.33 moles of ammonia are produced when 5.0 moles of hydrogen react with excess nitrogen.

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 3 moles of hydrogen form 2 moles of ammonia, 5 moles of hydrogen form how many moles of ammonia?

[tex]moles of ammonia=\frac{5 moles of hydrogenx 2 moles of ammonia}{3 moles of hydrogen}[/tex]

moles of ammonia= 3.33 moles

Finally, 3.33 moles of ammonia are produced when 5.0 moles of hydrogen react with excess nitrogen.

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Answer:

door

Explanation:

door I guess..................

Answer:

according to the law,the pressure would increase if volume has been decreased.

Explanation:

the reason is that,pressure and volume are inversely proportional,if volume has been decreased that means the pressure would increase because decreased volume would create a sort of compacted situation for particles either of a liquid or gas,decreasing volume would bring these particle together, closer to each other because of decreased  and since the volume has decreased they dont have enough space,they would end up getting closer to each other most likely to collide, which drastically increase pressure .

- 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

The dilution problem uses the equation :

[tex]M_aV_a= M_bV_b[/tex]

The initial molarity (concentration) [tex]M_a =[/tex] 0.13 M

The initial volume [tex]V_a[/tex] = 0.12 L

The desired molarity (concentration) [tex]M_b[/tex] = 0.23 M

The volume of the desired solution [tex]V_b[/tex] = ( 0.12 + x L )

Substituting values in above equation;

(0.13 M ) (0.12 L) = (0.23 M ) (0.12 L + x L)

0.0156 M L = 0.0276 M L + 0.23 x M L

- 0.012 M L = 0.23 x M L

x = - 0.05

Therefore, - 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

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The amino acid and which atom which has most to do with myoglobin’s ability to bind o2 is histidine and haemoglobin respectively

Amino acids simply refers to those molecular substances which combine together to form proteins. However, they are the end products of protein digestion

So therefore, the amino acid and which atom which has most to do with myoglobin’s ability to bind o2 is histidine and haemoglobin respectively

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Answer:

I'm pretty sure the answer Is c because I think I remember doing something like that so yeah

The amount, in pounds of chlorine that will be needed, will be 201.37 pounds

Calcium hypochlorite goes by the chemical formula, [tex]Ca(ClO)_2[/tex].

In order to know the amount of calcium hypochlorite that will be needed for the operation, we first need to know the percent composition of chlorine in calcium hypochlorite.

Molar mass of calcium hypochlorite = 142.98 g/mol

There are 2 molecules of Cl in calcium hypochlorite. The molar mass will be 35.5 x 2 = 71 g/mol

Percent chlorine in calcium hypochlorite = 71/142.98 x 100 = 49.66%

So, what amount of calcium hypochlorite will give us 100 pounds of chlorine knowing that chlorine is 49.66% of calcium hypochlorite?

49.66% of X = 100 pounds

            X = 100 x 100/49.66 = 201.37 pounds

Thus, 201.37 pounds of calcium hypochlorite will give us approximately 100 pounds of chlorine.

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The composition of a given pure compound is always the same no matter what the source of the compound.

A compound seems to be a substance that is entirely made of one kind of molecule.

Every component of compounds shares the same traits and features because of their homogenous makeup. However, because mixtures are composed of several sorts of chemicals, they frequently differ in terms of content, qualities, and samples.

Therefore, the composition of a given pure compound is always the same no matter what the source of the compound.

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Green, because it has less volume and less amount of matter.

Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimeter are a typical unit of measurement for density.

Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion. If an object's density is lower than the liquid's, it will often float.

The dimensions of two colored cubes.

Red: 4 12

Green: 3 10

density = mass/volume

so compare

[tex]12/4^{3}[/tex] and [tex]10/3^{3}[/tex]

None of the choices is the real reason. But is the closest. It is green because 10/27 > 12/64

But red would have been denser for a side of 3.9, and green would still have had less volume and less matter.

Green, because it has less volume and less amount of matter.

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Answer:

1.28 x 10⁻¹⁵ eV

Explanation:

To find the energy, you can use the photon energy equation:

E = hc / λ

In this equation,

-----> E = energy (eV)

-----> h = Plank's Constant (4.136 x 10⁻¹⁵ eV*s)

-----> c = speed of light (3.00 x 10⁸ m/s)

-----> λ = wavelength (m)

You can find the energy of the photon by plugging the given values into the equation and solving.

E = hc / λ

E = (4.136 x 10⁻¹⁵ eV*s)(3.00 x 10⁸ m/s) / 9.7 x 10⁸ m

E = 1.2408 x 10⁻⁶ / 9.7 x 10⁸ m

E = 1.28 x 10⁻¹⁵ eV

Answer:

B₂

Explanation:

The limiting reactant is always a reactant. You can determine which reactant is limiting by identifying which has the smaller mole-to-mole ratio with the product. This ratio can be found via the coefficients of the balanced reaction.

4 A₂ + 3 B₂ ---> 6 AB

4 moles A₂
------------------  = mole-to-mole ratio A₂/AB
6 moles AB

3 moles B₂
------------------  =  mole-to-mole ratio B₂/AB
6 moles AB

Since the mole-to-mole ratio between B₂ and AB is smaller, B₂ must be the limiting reactant.
                           

CH3 is the empirical formula for the compound.

A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.

The number of atom or moles in the compound is

1.17 g C X  1 mol of C / 12.011 g C = 0.097411 mol of C.

0.287 g H x 1 mol of  H / 1 g H = 0.28474 mol H.

This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.

So we can represent the compound with the formula C0.974H0.284.

Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.

we can divide 0.284 by 0.0974.

0.284 / 0.0974 = 3.

So here, Carbon is one and hydrogen is 3.

We can write the above formula as a CH3.

Hence the empirical formula for the sample compound is CH3.

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1. The amount of OH¯ present in the solution is 0.1 mol/L

2. The amount of H⁺ present in the solution is 0.0000000000001 mol/L

3. The pH of the solution with H⁺ concentration of 1×10⁻⁴ mol/L is 4

We'll begin by obtaining the pOH of the solution

pH + pOH = 14

13 + pOH = 14

Collect like terms

pOH = 14 - 13

pOH = 1

Finally, we can determine the OH¯

pOH = –Log [OH¯]

1 = –Log [OH¯]

Multiply through by –1

–1 = Log [OH¯]

Take the anti-log of –1

[OH¯] = anti-log of (–1)

[OH¯] = 0.1 mol/L

pH = –Log [H⁺]

13 = –Log [OH¯]

Multiply through by –1

–13 = Log [H⁺]

Take the anti-log of –13

[H⁺] = anti-log of (–13)

[H⁺] = 0.0000000000001 mol/L

pH = –Log [H⁺]

pH = –Log 1×10⁻⁴

pH = 4

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The carbon atom reduced in the transformation of chloromethane to methyllithium.

The reaction between chloromethane  and lithium form methyllithium.

[tex]CH_{3} Cl+ 2Li[/tex] → [tex]CH_{3} Li+ LiCl[/tex]

In above reaction, methyllithium is formed by the dispersing of lithium metal and adding chloromethane  .

The carbon atom in chloromethane  is partial positive charge because chlorine is high electronegative atom. The carbon atom in methyllithium is partial negative charge because carbon is more electronegative than lithium.

So, in above reaction two lithium metal donate two electron ( each lithium donate one electron) to the carbon atom(having positive charge) of chloromethane and get negative charge in methyllithium .

The gain of electron is reduction. So,The carbon atom reduced in the transformation of chloromethane to methyllithium.

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