Object A has a charge of -1 C. Object A has a charge of -1 C. At a given distance, the object with which
charge would be most strongly attracted by object A?*
+1 C
-1 C
+2 C
-2 C

Answer:

1. You can block the person bullying you.

2. Tell an adult about whats going on.

3. Try to stay off any social media apps. (turn off all notifications)

4. Don't respond to any of the comments or post. (Ignore them)

Explanation:

Hope this helps.

Answer:

they both hit at the same time

Answer:

The total system kinetic energy before the collision equals the total system kinetic energy after the collision. If total kinetic energy is not conserved, then the collision is referred to as an inelastic collision.

Explanation:

Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.

Answer:

room temperature water

Explanation:

Answer:

In the figure, the particles of cocoa are moving faster than the particles of bathwater. Therefore, the cocoa has a higher temperature. However, the bath water has more thermal energy because there is so much more of it. It has many more moving particles.

Explanation:

Answer:

I think it's just 100+70+140

Answer:

(a) α = - 1000 rad/s²

Negative sign represents deceleration.

(b) θ = 3581 rotations

(c) L = 1800 m

(d) a = - 80 m/s²  

Explanation:

(a)

using First equation of motion for angular motion:

ωf = ωi + αt

where,

ωf = Final Angular Speed = 2000 rad/s

ωi = Initial Angular Speed = 7000 rad/s

α = Angular Acceleration = ?

t = time = 5 s

Therefore,

2000 rad/s = 7000 rad/s + α(5s)

α = (2000 rad/s - 7000 rad/s)/5 s

α = - 1000 rad/s²

Negative sign represents deceleration.

(b)

Using second equation of motion:

θ = ωi t + (1/2)αt²

where,

θ = No. of Rotations = ?

Therefore,

θ = (7000 rad/s)(5 s) + (1/2)(- 1000 rad/s²)(5 s)²

θ = 35000 rad - 12500 rad

θ = (22500 rad)(1 rotation/2π rad)

θ = 3581 rotations

(c)

Length of String = L = (Circumference of Pulley)(θ)

L = [2π(0.08 m)][3581 rotations]

L = 1800 m

(d)

Tangential Acceleration = a = rα

a = (0.08 m)(-1000 rad/s²)

a = - 80 m/s²

Answer:

29.4 kW

Explanation:

time t = 10 s, height h = 30 m, mass m = 1,000 kg

power output = work done/time

work done = increase in potential energy = mgh = 1,000 * 9.8 * 30 = 294,000 J = 294 kJ

power output = 294/10 = 29.4 kW

Answer:

Explanation:

from highest to lowest frequency

gamma-ray, x-ray, ultraviolet, visible light, infrared, microwave, radio

hope this helps have a good day :)

The electromagnetic waves with the lowest frequencies are the ones we call "radio" waves.

The electromagnetic waves with the highest frequencies are the ones we call "gamma rays".

In between those are all the others . . . the microwaves, the heat ('thermal') waves, the infrared waves, the light waves, the ultraviolet waves, and the X-rays.

Answer:

Conduction

Explanation:

conduction is one of the three main ways that heat energy moves from place to place the other two ways heat moves around our radiation and convection conduction is the process by which heat energy is transmitted through Collisons between neighboring atoms or molecules.

hope this helps :)

Answer:

A

Explanation:

Answer:

25 kg m^2/s

Explanation:

The angular acceleration due to the application of torque to the grinding wheel is:

[tex]\tau=I\alpha \rightarrow \alpha=\frac{2.5}{2}=1.25[/tex] (in radian per square second)

So, by the basic equation of the angular acceleration, we can get the angular velocity at t = 10 s as follows:

[tex]\omega=\omega_{o}+\alpha t \rightarrow \omega =0+(1.25)(10) =12.5[/tex] rad/s.

So, the angular momentum at t = 10 s:

[tex]L=I\omega=(2)(12.5) = 25[/tex]  kg m^2/s

For a 2-kg ball moving with a constant speed of 5 m/s in a horizontal circle whose radius,  the magnitude of the net force on the ball is 50 cm. is mathematically given as

F= 100 N

Generally, the equation for the Net force   is mathematically given as

F = m*r*w^2

Where

w = angular velocity

w= 5/r

w= 10 rad/s

Therefore

F = 2/0.5/10^2

F= 100 N

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A soundwave will go through a medium but once it goes through, the sound that you hear is muffled or not as clear usually just like sound going through a wall. The soundwaves will be something like moved and the sound you hear might not be the same or as clear as the original sound was

Answer:

sound waves

Explanation:

The sound waves can go through different mediums depending on the crest and trough

Friction affects the motion of two objects sliding past each other. This frictional force results into the loss of energy and hence slow down the motion of the two objects in contact.

Frictional force is the force that is resisting the relative motion of solid surfaces, fluid layers, and the two material elements which are sliding against each other. There are several types of friction such as dry friction, it is a force that opposes the relative lateral motion of the two solid surfaces which are in contact.

Frictional force generates when the two surfaces slide past one another in motion. The force of friction opposes the motion of an object which is in contact, causing the moving objects to lose energy and slow down. The frictional force is important as it helps us in walking, driving a car, and in doing other works.

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Superposition is the most correct option

When two waves meet it is generally called inteference. Superposition occurs when the waves adds up to form a stronger wave. This is called constructive interference

hope this helps....

For the following statements

A) The motor speed is less than wheel speed.

B) The output power of the motor is positive during hill climbing.

C) The wheel torque is more than motor torque

These assertions are given respectively as

Speed: defined as the ratio of operation with respect to distance and time

Power: defined as the ability to work

Torque: This is the speed of a rotating object

Generally, the equation for Speed, Power, Torque  is mathematically given as

V=m/s

P=w/t

T=rfsin\theta

In conclusion

For a moving car, the wheels speed is in equilibrium with the motor speed Hence false

The output power during a hill climb is positive cause work is been done, Hence true

The wheel torque also is in equilibrium with the motor Torque, Hence false

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Answer: You feel the gravitation on the Earth greater

Explanation:

Because the mass of the Earth is heavier than the Moon, you can replace specifi number of the weight of the Moon and the man compare the weight of the Earth and the man into the formula!

Answer:

value is obtained than the real one.

        ρ >  ρ_real

Explanation:

A widely used method to determine the density of a body is to measure its mass and measure its volume by immersing it in a transparent liquid, to measure its volume by the difference in volumes of the liquid then use the relationship

        ρ = m / V

In this case, part of the body remains the force of the liquid, in this case using Archimedes' principle that establishes that the weight of the desalted liquid is equal to the thrust, let's use the equilibrium equation

              B - W = 0

              B = W

              ρ_liquid  g V_submerged = ρ_body g V_body

              V_submerged = (ρ_body /ρ-liquid)   V_body

We can see that the volume is only a fraction of the volume of the body, therefore when performing the division a higher value is obtained than the real one.

Answer:

[tex]-0.902 \frac ms[/tex]

Explanation:

We apply conservation of momentum here. Before the toss, everything was still, so the momentum was 0. After the toss, we have the sum of the momentum of the package (1st term) and the boat+child combo (2nd term). Let's call v the velocity of the boat.

[tex]0= 6.6kg \cdot 10.2\frac ms + (29.9+44.7)kg\cdot v\\v= - \frac{6.6 \cdot 10.2 }{74.6} \frac ms \approx -0.902 \frac ms[/tex]

The term is negative since it expresses the boat+child system is going the opposite way from where the package flew.

Answer:

The two balls pass each other at a height of 5.53 m

vf1=17.97 m/s

vf2=-5.96 m/s

Explanation:

Vertical Motion

An object thrown from the ground at speed vo, is at a height y given by:

[tex]y=vo.t-g.t^2/2[/tex]

Where t is the time and [tex]g=9.8\ m/s^2[/tex]

Furthermore, an object dropped from a certain height h will fall a distance y, given by:

[tex]y=g.t^2/2[/tex]

Thus, the height of this object above the ground is:

[tex]H = h-g.t^2/2[/tex]

The question describes that ball 1 is dropped from a height of h=22 m. At the same time, ball 2 is thrown straight up with vo=12 m/s.

We want to find at what height both balls coincide. We'll do it by finding the time when it happens. We have written the equations for the height of both balls, we only have to equate them:

[tex]vo.t-g.t^2/2=h-g.t^2/2[/tex]

Simplifying:

[tex]vo.t=h[/tex]

Solving for t:

[tex]t=h/vo=22/12=1.833\ s[/tex]

The height of ball 1 is:

[tex]H = 22-9.8.(1.833)^2/2[/tex]

H = 5.53 m

The height of ball 2 is:

[tex]y=12\cdot(1.833)-9.8\cdot(1.833)^2/2[/tex]

y=5.53 m

As required, both heights are the same.

The speed of the first ball is:

[tex]vf1=g.t=9.8\cdot 1.833=17.97\ m/s[/tex]

vf1=17.97 m/s

The speed of the second ball is:

[tex]vf2=vo-gt=12-9.8\cdot 1.833=-5.96\ m/s[/tex]

vf2=-5.96 m/s

This means the second ball is returning to the ground when both balls meet

Valid Expressions are; t = ∛(d²/va), a = d/t², a = √(vd/t³), v = at

while the Invalid expressions are;  v = a/t and  d = at

Explanation:

Given expressions

1) v = a/t

2) t = ∛(d²/va)

3) d = at

4) a = d/t²

5) a = √(vd/t³)

6) v = at

First we get our units of parameters

V = m/s, t = sec, d = m, a = m/s²

so

1)

v = a/t

we substitute in our units of parameters

v = m/s² / s = m/s² × 1/s = m/s³

v ≠ m/s³

therefore it is false

2)

t = ∛(d²/va)

we substitute

t = ∛(m² / m/s × m/s²)

t = ∛(m² / m²/s³)

t = ∛(s³)

t = s

correct, the expression is true

3)

d = at

we substitute

d = m/s² × s

d = m/s² × s/1 =  ms/s² = m/s

d ≠ m/s (because d = m)

so expression is false

4)

a = d/t²

we substitute

a = m / s² = m/s²

correct

the expression is true

5)

a = √(vd/t³)

we substitute

a = √(m/s×m / s³) = √(m²/s / s³) = √(m²/s × 1/s³)  = √(m²/s⁴) = m/s²

so a = m/s²

correct

the expression is true

6)

v = at

we substitute in the units

v = m/s² × s = m/s² ×s/1 = ms/s² = m/s

v = m/s

correct

the expression is correct

The serve, forehand groundstroke, backhand groundstroke, forehand volley, backhand volley, and overhead smash are the six basic strokes in tennis. The 6 basic "strokes" are the basic actions a tennis player makes to hit the ball.

Stay safe & humble <3

Answer:

a)   m =1  θ = sin⁻¹  λ  / d,  m = 2        θ = sin⁻¹ ( λ  / 2d) ,   c)     m = 3

Explanation:

a) In the interference phenomenon the maxima are given by the expression

         d sin θ = m λ

the maximum for m = 1 is at the angle

          θ = sin⁻¹  λ  / d

the second maximum m = 2

          θ = sin⁻¹ ( λ  / 2d)

the third maximum m = 3

        θ = sin⁻¹ ( λ  / 3d)

the fourth maximum m = 4

       θ = sin⁻¹ ( λ  / 4d)

b) If we take into account the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.

       I = I₀ cos² (Ф) (sin x / x)²

       Ф = π d sin θ /λ

       x = pi a sin θ /λ

where a is the width of the slits

with the values ​​of part a are introduced in the expression and we can calculate intensity of each maximum

c) The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present

maximum interference       d sin θ = m λ

first diffraction minimum    a sin θ = λ

we divide the two expressions

                       d / a = m

In our case

                   3a / a = m

                    m = 3

order three is no longer visible

(a)  The next four angles from the central maxima are sin⁻¹  λ  / d, sin⁻¹  λ  / 2d , sin⁻¹  λ  / 3d, and sin⁻¹  λ  / 4d respectively.

(b)   With the values ​​of part a are the expression of intensity of each maximum can be calculated accordingly.

(c)   The third order maxima (m = 3) is missing from the pattern obtained through the double-slit experiment.

a)

In the interference phenomenon the maxima are given by the expression

d sin θ = m λ

Here,

d is the slit separation and m is the order of interference.

The maximum for m = 1 is at the angle is,

θ = sin⁻¹  λ  / d

For the second maximum m = 2

θ = sin⁻¹ ( λ  / 2d)

For the third maximum m = 3

θ = sin⁻¹ ( λ  / 3d)

For the fourth maximum m = 4

θ = sin⁻¹ ( λ  / 4d)

Thus, we can conclude that the next four angles from the central maxima are sin⁻¹  λ  / d, sin⁻¹  λ  / 2d , sin⁻¹  λ  / 3d, and sin⁻¹  λ  / 4d respectively.

b)

Considering the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.

I = I₀ cos² (Ф) (sin x / x)²

Where Ф is the phase angle, and its value is,

 Ф = π d sin θ /λ

x = π  a sin θ /λ

Here a is the width of the slits

Thus, with the values ​​of part a are introduced in the expression the  intensity of each maximum can be calculated accordingly.

c)

The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present.

For the maximum interference:        

d sin θ = m λ

For the first diffraction minimum:    

a sin θ = λ

Dividing both the expressions as,

d / a = m

Since, d = 3a. Then,

3a / a = m

m = 3

Thus, we can conclude that the third order maxima (m = 3) is missing from the pattern obtained through the double-slit experiment.

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Answer:

Electrons being pulled from one surface to another

Explanation:

The movement of electrons creates electrical charge.

Answer:

The person's hand will warm up the jar

Explanation:

Thermal energy will be conducted from his hand to the jar

the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period

Thank you

The area between the line and the x axis represent on a velocity vs time graph is the displacement.

The area under velocity-time graph is known as displacement.

In velocity-time graph, the y-axis represents the velocity axis while the x-axis represents the time axis.

Velocity is defined as the change in displacement per change in time.

[tex]v = \frac{dx}{dt}[/tex]

where;

The integration of the velocity gives the area under the curve and that will be equal to the displacement.

[tex]\int\limits^a_b {v} \, dt = x[/tex]

Thus, the area between the line and the x axis represent on a velocity vs time graph is the displacement.

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Answer:

All of Above

Explanation:

Answer:

The is: Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

Hope this helps! ;-)

Answer:

Although it is possible to have more than one state, it is also possible to have only one state.

Explanation: