The circuit of an electric bell consists of an electromagnet, a switch, and a source of power. When the switch is activated, the electromagnet is energized, creating a magnetic field. This magnetic field attracts a metal hammer, which strikes a bell and produces a ringing sound. When the switch is released, the circuit is broken, de-energizing the electromagnet and allowing the hammer to return to its original position. This process repeats each time the switch is activated.
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Two identical balls are at rest side by side at the bottom of a hill. Some time after ball A is kicked up the hill, ball B is given a kick up the hill. Ball A is headed downhill when it passes ball B headed up the hill. At the instant when ball A passes ball B, it has the same position and velocity as ball B. Pit has the same position and acceleration as ball B. c. it has the same velocity and acceleration as ball B. d. it has the same displacement and velocity as ball B. e. it has the same position, displacement and velocity as ball B.
When ball A passes ball B, A's position and acceleration are the same as those of B.
Describe acceleration.
The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not necessarily. An item that follows a circular course while maintaining a constant speed is still moving forward because the direction of its motion is shifting.
The motion of an item is related to the forces operating on it by Newton's equations of motion. According to the first law, until a force acts on an item, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. The third rule states that when two things come into contact, they exert forces on one another of equal magnitude and opposite direction.
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Which equation represents inverse proportionality?
Responses
y=m/x
y equals m divided by x
y=mx2+b for nonzero b
y equals m x squared plus b for nonzero b
y=mx
y equals m x
y=mx2
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Inverse proportionality means that the two terms should be proportional to inverse of each other ~
That is :
[tex]\qquad \sf \dashrightarrow \: y \propto \dfrac{1}{x} [/tex]
And according to given options, only option 1 shows inverse proportionality. where y is inversely proportional to x and m is proportionality constant.
[tex]\qquad \sf \dashrightarrow \: y = \dfrac{m}{x} [/tex]
Find the work WAB in electron volts done by the electric force on a proton that moves from point A to point B. Similarly, find WAC, WAD, and WAE. (Assume the proton starts and stops at rest. Enter your answers in eV.)
The work WAB in electron volts done by the electric force on a proton that moves from point A to point B can be calculated using the equation W = qE, where q is the charge of the proton and E is the electric field at point B.
Similarly, the work WAC, WAD, and WAE can be calculated using the same equation, substituting in the electric field at points C, D, and E respectively.
Assuming the proton starts and stops at rest, the answers in eV will be equal to the product of the proton's charge and the electric field at the respective points.
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Use the provided Smith charts to find the normalized input impedance of a lossless line of length l terminated in a normalized load impedance zL for each of the following combinations. Show your work on the Smith chart clearly
a) l = 0.75λ, zL = 1+ j0
(b) l = 0.5λ, zL = 1- j1
(c) l = 0.2λ, zL = 1+ j1
(d) l = 1.3λ, zL = 0.5 + j0.5
(e) l = 0.2λ, zL = 0 (short circuit)
Use the provided Smith charts to find the normalized input impedance of a lossless line of length l terminated in a normalized load impedance zL for each of the following combinations. l = 1.3λ, zL = 0.5 + j0.5.so, option (c) is correct.
What is impedance?The measure of resistance to electrical flow is called impedance, and it is denoted by the letter Z. In ohms, it is measured.
What is resistor?An electrical component known as a resistor controls or restricts the passage of electrical current in an electronic circuit.
Knowing about different parts, such as resistors, inductors, capacitors, power sources, connecting wires, and more, is necessary when building a circuit. Among the circuit's essential elements is the resistor.
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One pass traveled 63 yards from quarterback to receiver. The pass was thrown at 45 degree angle, what was the speed at which the ball left the quaterback’s hand?
The speed at which the ball left the quaterback’s hand was 23.76 m/s.
What is projectile motion?When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's centre.
Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.
The range of the pass is = 63 yards = 63 × 0.9144 meter = 57.6072 meter
Angle of projection = 45 °
Acceleration due to gravity = 9.8 m/s²
Hence, the initial speed is = √{(9.8 × 57.6072)/sin(2×45°)} m/s
= 23.76 m/s
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A wheel turning 4.50 rad/s
experiences an angular
acceleration of -0.822 rad/s^2.
What is its angular velocity
after 12.0 s?
angular velocity after 12.0 s = 4.50 rad/s - (0.822 rad/s^2 * 12.0s)
angular velocity after 12.0 s = 2.052 rad/s
What is angular velocity?
Angular velocity is a measure of the angular displacement over time of a rotating object. It is expressed as the rate of change of angular displacement with respect to time, and is usually expressed in radians per second or revolutions per minute. Angular velocity is considered to be a vector quantity, meaning it has magnitude and direction. It is also a measure of the speed at which an object is rotating. When an object is rotating in a circular motion, its angular velocity is the same as its tangential velocity. Angular velocity can also be used to calculate the linear velocity of an object, by multiplying its angular velocity by the radius of its circular path.
Therefore, angular velocity after 12.0 s = 2.052 rad/s
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Answer: -5.36
Explanation:
ik this can help you now but i was doing this problem and figured id leave this here lolz
Which one of the following can be done to shorten the half-life of the radioactive decay of uranium-238? a. oxidize it to the +2 oxidation state b. freeze it c. none of the above d. heat it e. convert it to UF6
First off, no known chemical, physical, or environmental approach can change the half-life of a radioactive species so option c. is the correct choice.
Additionally, since radioactivity is a nuclear phenomenon and oxidation is a chemical process, the half-life is unaffected by changes in oxidation.
Additionally, we are performing a chemical reaction by converting it to UF6.
Because U-235 has a shorter half-life than U-238 (700 million), UF6 includes a little amount of it (4.7 billion).
Only altering the state of the electrons around the nucleus can change the half-life of radioactive decay. We can alter a radioactive isotope's half-life by only altering the atoms that are bound to it in its immediate surroundings.
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Transmission describes what happens when ____
A. two waves collide in the same medium.
B. a wave splits into two waves within the same medium.
C. multiple waves exchange energy within a single medium.
D. a wave passes into a new medium and travels through that medium.
Answer:
Explanation:
D. a wave passes into a new medium and travels through that medium.
Transmission refers to the process of a wave traveling through a new medium, such as when light passes through a pane of glass or sound travels through air.
How much work must we do on an electron to move it from point A, which is at a potential of +50V, to point B, which is at a potential of -50V, along the semicircular path shown in the figure? Assume the system is isolated from outside forces
[tex]1.602 x 10^-17[/tex] is the work must we do on an electron to move it from point A, , to point B, that is at a potential of -50V, along the semicircular path.
What is electron?In order to move the electron from point A to point B, we need to do work on it to overcome the electric potential difference between the two points. Since the two points have potentials of +50V and -50V respectively, the total potential difference is 100V.
Since the electric field is conservative, the work done by it depends only on the potential difference between points A and B and not on the path taken. The potential difference between points A and B is given by:
ΔV = V_B - V_A = -50 V - (+50 V) = -100 V
To move an electron from point A to point B, we need to do work on it equal to the change in its potential energy. The potential energy of an electron in an electric field is given by:
U = qΔV
where q is the charge of the electron, and ΔV is the potential difference.
The charge of an electron is:
q = -1.6 x [tex]10^{-19 }[/tex]C
Substituting the values, we get:
U = (-1.6 x [tex]10^{-19 }[/tex] C) x (-100 V)
U = 1.6 x [tex]10^{-19 }[/tex]
Therefore, we need to do work on the electron equal to 1.6 x 10^-17 J to move it from point A to point B along the given semicircular path.
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a current of 2 Ampere passes through a wire of resistance 4ohms for 3mins calculate the energy Lost
The amount of energy lost is equal to 2880 joules if a current of 2A flows through a wire with a resistance of 4 for 3 minutes.
Given according to the question-
Current passing through the wire (I) = 2A
Resistance of the wire (R) = 4Ω
Time for which the current passed in the wire (t) = 3mins = 3 x 60
sec= 180sec. {converting minutes into seconds}
To be calculated
Energy loss (E)
According to Formulae
The electric energy that an electric current delivers is a function of both its strength and the amount of time it flows, and is thus a function of voltage, current and time.
[tex]E = Pt = VIt[/tex]
In order to create variants, this equation and Ohm's law can be used together.
[tex]E = VIt = I^{2} Rt[/tex]
E = I²Rt
E = 2² × 4 × 180
E = 2880J
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EXPERIMEXPERIMENT: SIMPLE MACHINES When we think of a machine, car engines, cranes, lifts, power drills, and vacuum cleaners usually come to mind. These devices are complex machines. Simple machines are the wedge, inclined plane, screw (an inclined plane wrapped on an axle), pulley, and lever. The jack used to lift a car is an example of a simple machine; it is simply a lever. In this investigation you will use a lever as a simple machine, and calculate its mechanical advantage and efficiency. Here are your goals for this lesson: Make quantitative observations and measurements with precision Analyze, evaluate and predict patterns from data Communicate findings These supplies are needed: meter stick string weights Play Mute Remaining TimeÂ-1:08 Picture-in-Picture Follow these directions and complete the activities. 1. Suspend the meter stick by a string from its center. 2. Notice carefully where it balances. It probably will not balance exactly at 50 cm. All distances must be measured to this point (called the fulcrum). 3. Hang a 200 g mass on one side and a 50 g mass on the other and adjust the distances from the fulcrum until the meter stick balances.(Be sure to account for the mass of the hanger from which you are suspending the masses. This can either be part of the total mass or, alternatively, if you are using something like coffee cups to hold the masses, their masses need to be matched perfectly before starting the experiment. You can do this by first checking to see how close they com
Answer:
This a practical that you have to do. Not to us.
Explanation:
EXPERIMEXPERIMENT: SIMPLE MACHINES When we think of a machine, car engines, cranes, lifts, power drills, and vacuum cleaners usually come to mind. These devices are complex machines. Simple machines are the wedge, inclined plane, screw (an inclined plane wrapped on an axle), pulley, and lever. The jack used to lift a car is an example of a simple machine; it is simply a lever. In this investigation you will use a lever as a simple machine, and calculate its mechanical advantage and efficiency. Here are your goals for this lesson: Make quantitative observations and measurements with precision Analyze, evaluate and predict patterns from data Communicate findings These supplies are needed: meter stick string weights Play Mute Remaining TimeÂ-1:08 Picture-in-Picture Follow these directions and complete the activities. 1. Suspend the meter stick by a string from its center. 2. Notice carefully where it balances. It probably will not balance exactly at 50 cm. All distances must be measured to this point (called the fulcrum). 3. Hang a 200 g mass on one side and a 50 g mass on the other and adjust the distances from the fulcrum until the meter stick balances.(Be sure to account for the mass of the hanger from which you are suspending the masses. This can either be part of the total mass or, alternatively, if you are using something like coffee cups to hold the masses, their masses need to be matched perfectly before starting the experiment. You can do this by first checking to see how close they com
For the following questions consider the electric field and forces produced by a pair of charged particles that are held at fixed positions on the x-axis at x= +d and x=−d.
The charge at +d is positive q and the one at−d is negative q. A third positive charge of q is placed at y= 10d. What is the approximate magnitude of the force on this third charge?
The correct option is E. The magnitude and direction of the force on this third charge [tex]2kq^2/d[/tex]; the positive x-direction.
An electric area (now and again E-discipline) is the bodily field that surrounds electrically charged particles and exerts force on all other charged debris in the subject, either attracting or repelling them. It also refers to the physical discipline for a system of charged debris. electric powered fields originate from electric expenses and time-varying electric powered currents. electric powered fields and magnetic fields are both manifestations of the electromagnetic discipline, one of the four fundamental interactions (also called forces) of nature.
Electric fields are critical in lots of regions of physics and are exploited in electrical technology. In atomic physics and chemistry, for instance, the electric field is the attractive pressure protecting the atomic nucleus and electrons together in atoms. it is also the pressure accountable for chemical bonding among atoms that bring about molecules. the electrical discipline is defined as a vector area that friends to each factor in space the electrostatic (Coulomb) force in keeping with unit of fee exerted on a tiny tremendous check rate at relaxation at that factor.
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Complete Question:
For the following question, consider the electric field and forces produced by a pair of charged particles held at fixed positions on the x-axis at x= +d and x=−d.
The charge at +d is positive q and the one at −d is negative q. A third negative charge of −q is placed at the origin. What is the magnitude and direction of the force on this third charge?
A). [tex]2kq^2/d^2[/tex]; the negative direction
B).[tex]2kq^2/d[/tex]; the positive x-direction
C). [tex]2kq^2/d[/tex]; the negative direction
D). [tex]2kq/d^2[/tex]; the positive x-direction
E).[tex]2kq^2/d[/tex]; the positive x-direction
F). [tex]2kq/d^2[/tex]; the negative x-direction
A skier starts down a 10 degree incline at 2 m/s, reaching a speed of 15m/s at the bottom. What is the length of the incline?
How long does it take the skier to reach the bottom.
The length of the incline is 65 meter.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Initial speed is = 2 m/s
Final speed is = 15 m/s
Acceleration of the skier is = gsin10° = 9.8 × sin10° m/s² = 1.7 m/s
Let the length of the incline is l
Hence,
15² = 2² + 2×1.7×s
s = 65
Hence, the length of the incline is 65 meter.
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The takeoff speed for an Airbus A320 jetliner is 80 m/s. Velocity data measured during takeoff are as shown.a. Is the jetliner’s acceleration constant during takeoff? Explain.b. At what time do the wheels leave the ground?c. For safety reasons, in case of an aborted takeoff, the runway must be three times the takeoff distance. Can an A320 take off safely on a 2.5-mi-long runway?
The acceleration is expressed as the product of the change in time and the change in velocity, and it is 2.3 m/s. 34.78 seconds pass before the wheels lift off the ground.
How do velocity and speed differ?Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion.
Taking the first interval, we find
a = Δvx/Δt
a = 23m/s/10m/s
a = 2.3m/s
By dividing the acceleration in m/s2 by the value of g, or the acceleration of gravity (9.81 m/s2), we may determine the jet's acceleration in g's.
ag = a/g
2.3/9,8
ag = 0.33g
When the jet reaches its takeoff velocity, which is 80 m/s, the wheels come off the ground.
The jet's velocity is zero at time t=0 s. Since we are aware that the acceleration is constant (a=2.3 m/s2), we can use the equation to determine the time t at which the jet achieves a velocity of vf=80 m/s.
vf = vi + at
Re-arranging and substituting numbers, we find
t = vf/a
t = 80/2.3
t = 34.78s
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The equation of a wave traveling in a horizontal direction is expressed as y - 5sin(60t - x)
What's the phase angle
(a)90° (b)180° (c)270° (d)360° (e)0°
what's the wave number?
(a) 2m-¹ (b) 3.142m (c) 1m (d) 0.2m (e) non of the above
Basic function of a wave is given as, [tex]y(x,t)=Asin(kx\pm wt \pm $\Phi$)[/tex]. Where
"A" is amplitude, "k" is the wave number, "w" is angular frequency, and "Ф" is the phase angle.
Based off the given wave function, [tex]y(x,t)=5sin(60t - x)[/tex], we can say that the phase angle is 0° and the wave number is 1 m.
A heavy dart and a light dart are launched horizontally on a frictionless table by identical ideal springs. Both springs were initially compressed by the same amount. Which of the following statements about these darts are correct?
The statement which is correct about the lighter dart leaves the spring moving faster than the heavy dart. Option B is correct.
This is because both darts are launched with the same initial elastic potential energy from the compressed springs, but the lighter dart has less mass than the heavier dart. According to the law of conservation of energy, the lighter dart must move faster than the heavier dart in order to have the same amount of kinetic energy as the heavier dart once it leaves the spring.
The initial potential energy is the same for both darts, and since the potential energy is converted to kinetic energy, the lighter dart must have a higher velocity than the heavier dart in order to have the same amount of kinetic energy.
Therefore, option B is correct, while options A, C, D, and E are not, as they do not accurately describe the behavior of the darts in this scenario.
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--The complete question is, A heavy dart and a light dart are launched horizontally on a frictionless table by identical ideal springs. Both springs were initially compressed by the same amount. Which of the following statements about these darts are correct?
A) The darts both have the same kinetic energy just as they move free of the spring.
B) The lighter dart leaves the spring moving faster than the heavy dart.
C) The heavy dart had more initial elastic potential energy than the light dart.
D) Both darts move free of the spring with the same speed. E) Both darts had the same initial elastic potential energy.--
Electric field lines always begin at _______ charges (or at infinity) and end at _______ charges (or at infinity). One could also say that the lines we use to represent an electric field indicate the direction in which a _______ test charge would initially move when released from rest. Which of the following fills in the three missing words correctly?
Electric field lines always begin at positive charges (or at infinity) and end at negative charges (or at infinity). One could also say that the lines we use to represent an electric field indicate the direction in which a positive test charge would initially move when released from rest.
The field lines show us the motion of a positive test charge on one of those field lines. As a result, the field lines point in the direction of negative charges and away from positive charges. Instead, we may state that what we need is information about the movement of negative test charges from the field lines. Then the arrows would turn around, and someone would innocently inquire about the exact opposite.
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Which of the following is an advantage that electronic brainstorming has over traditional brainstorming?It prevents participants from all answering at once.Cost effectiveIt allows participants to answer anonymously.It allows only one person to talk at a time.It encourages "social loafing".
An advantage that electronic brainstorming has over traditional brainstorming: Option. It allows participants to answer anonymously.
Electronic brainstorming provides anonymity, allowing participants to contribute freely without fear of judgement.
Electronic brainstorming provides a unique advantage over traditional brainstorming in that it allows participants to answer anonymously. This means that participants can contribute freely without the fear of judgement or criticism from others.
This allows more honest and open dialogue, as participants can express their ideas without the worry of being judged or having their ideas dismissed.
Additionally, electronic brainstorming is usually more cost-effective, as there is no need to arrange a physical meeting space or provide food and beverages. This makes it an ideal choice for those looking to brainstorm without the hassle or cost of traditional brainstorming.
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Humans have used many natural resources to the point of depletion.
They have also caused problems such as desertification and loss of
habitat. What is an example of a sustainable management practice
for natural resources?
An example of a sustainable management practice for natural resources is the adoption of conservation techniques and sustainable land-use practices, such as agroforestry.
What is agroforestry?Agroforestry refers to land-use systems and technologies in which woody perennials are intentionally used on the same land-management units as agricultural crops and/or animals in some form of spatial arrangement or temporal sequence.
Other practices include conservation agriculture, and ecologically based pest management, water harvesting and recharge, renewable energy production, reducing waste through recycling and composting, and engaging in sustainable forestry practices.
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The given diagram shows the motion of a mass on a string which is swung in a circle. Which of the given arrows correctly shows the direction of the tangential velocity at the instant the mass is at the position shown?
- A
- B
- C
- D
The direction of the tangential velocity at the instant the mass is at position is diagram A.
What is tangential velocity?Tangential velocity is the velocity of an object along a circle or curved path, at any given point. It is the component of the velocity that is perpendicular to the radius of the circle, and it is perpendicular to the radial velocity, which is the component of velocity that points towards or away from the center of the circle.
The tangential velocity determines the speed of an object as it moves along the circular path.
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the conductor offers some amount of ohmic resistance to the flow of electrons, depending on the type of material from which the conductor is made, its length, and its .
Depending on the type of material used, the length, and other factors, the conductor provides some ohmic resistance to the flow of electrons.
Because electrons in a conducting wire reject one another, a conducting wire provides resistance to the flow of electrons. The electrolyte resistance, the current collector resistance, the active mass, and the transition resistance between the current collector and active mass are added to create the ohmic resistance, or RB.
Theoretically, in accordance with Ohm's rule, the voltage at the ohmic resistance instantly follows the battery current. A substance or material that permits the flow of electricity is known as an electrical conductor. Electrical charge carriers, often electrons or ions, flow freely in a conductor.
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Contingent upon the sort of material utilized, the length, and different variables, the guide gives ohmic protection from the progression of electrons.
Since electrons in a directing wire reject each other, a leading wire gives protection from the progression of electrons. The electrolyte obstruction, the ongoing authority opposition, the dynamic mass, and the progress obstruction between the ongoing gatherer and dynamic mass are added to make the ohmic obstruction or RB.
Hypothetically, as per Ohm's standard, the voltage at the ohmic obstruction in a split second follows the battery current. A substance or material that allows the progression of power is known as an electrical transmitter. Electrical charge transporters, frequently electrons or particles, stream uninhibitedly in a transmitter.
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Rigid rods of negligible mass lying along the y axis connected three particles. The system rotates about the x axis with an angular speed of 2.00 rad/s. Find the total rotational kinetic energy evaluated from 1/2 Iω ^2
The total rotational kinetic energy of the system can be found by evaluating the above expression using the given values of m, r, and ω [tex]KE = 1/2 * (m1 * r1^2 + m2 * r2^2 + m3 * r3^2) * (2.00 rad/s)^2[/tex]
The total rotational kinetic energy of a system can be found by evaluating the expression 1/2 Iω^2, where I is the moment of inertia of the system and ω is its angular velocity. In this case, the moment of inertia of the system can be found by adding the moments of inertia of each particle and the connecting rods.
Since the rods have negligible mass, their moment of inertia is also negligible and can be ignored. The moment of inertia of each particle is given by the formula:
I = mr^2
where m is the mass of the particle and r is its distance from the axis of rotation.
Assuming the particles have masses m1, m2, and m3 and distances from the axis of rotation r1, r2, and r3, respectively, the total moment of inertia is:
[tex]I = m1 * r1^2 + m2 * r2^2 + m3 * r3^2[/tex]
Substituting the given values, we find:
I = (m1 * r1^2 + m2 * r2^2 + m3 * r3^2)
Finally, substituting the moment of inertia and angular velocity into the expression for rotational kinetic energy, we find:
KE = 1/2 * I * ω^2
[tex]KE = 1/2 * (m1 * r1^2 + m2 * r2^2 + m3 * r3^2) * (2.00 rad/s)^2[/tex]
So, the total rotational kinetic energy of the system can be found by evaluating the above expression using the given values of m, r, and ω.
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A container with volume 1.54 L is initially evacuated. Then it is filled with 0.221 g of N2. Assume that the pressure of the gas is low enough for the gas to obey the ideal-gas law to a high degree of accuracy.
If the root-mean-square speed of the gas molecules is 182 m/s , what is the pressure of the gas?
The pressure of the gas in a container with a volume of 1.54 L is initially evacuated. Then it is filled with 0.221 g of N2 is 1619Pa.
A gas with a small density and at a sufficiently high temperature so that the interaction between its particles can be neglected can be considered an ideal gas. In this case, the pressure, volume, and temperature of the gas are related as follows:
PV=mMRT, where m is the mass of the gas and M is the molar mass of the gas. The pressure of the gas can be found using the ideal gas law:p =mRT/MV.
The temperature of the gas can be found from the RMS speed of the molecules of nitrogen, which is given by: vrms=√3RT/M. Solving for the temperature, we obtain: T= Mv² / 3 R. And pressure is P= mv² /3V. So P=[ 0.221×(184)²]/ 3×1.54 = 1619 Pa.
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you got to the edge of the roof of the physics building and throw one of those other physics textbooks straight up with a speed of 15 m/s. how fast will the book be traveling just before it hits the ground 12m blow you
The book will be traveling at a speed of 15 m/s just before it hits the ground 12 m below you. Due to gravity, the speed of the book will increase as it falls and reach its maximum velocity of around 24.5 m/s just before it reaches the ground.
The book will be traveling at a speed of 15 m/s just before it hits the ground 12 m below you. Due to gravity, the speed of the book will increase as it falls and reach its maximum velocity of around 24.5 m/s just before it reaches the ground.
As the book falls, gravity will accelerate it toward the ground. The acceleration due to gravity, denoted as g, is a constant value of 9.8 m/s2. This means the book's velocity will increase by 9.8 m/s every second. Therefore, the book will reach its maximum velocity of 24.5 m/s after 2.5 seconds. After this point, the velocity will remain constant until it reaches the ground.
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Part A: How much pressure is needed to compress the volume of an iron block by 0.20% ? Express your answer in N/m2. Use Biron=9.0×10^10 N/m^2.
Express your answer using two significant figures.
Part B: Compare it to atmospheric pressure (1.0×10^5 N/m^2).
Express your answer using two significant figures.
The bulk modulus of the iron block is given 9 × 10¹⁰ N/m². The volume change is 0.20 %. Then the pressure required for the compression is 1.8 × 10⁸ N/m².
What is bulk modulus?Bulk modulus of an object is the measure of its resistance to compression. It is the ratio of infinitesimal increase in pressure to the decrease in volume.
B = ΔP/ΔV/V
= ΔPV/ΔV.
Given B = 9 × 10¹⁰ N/m²
ΔV/V = 0.20/100 = 0.002
then ΔP = B ΔV/V
ΔP = 9 × 10¹⁰ N/m² × 0.002 = 1.8 × 10⁸ N/m²
Atmospheric pressure = 1 × 10⁵ N/m²
then ΔP/Patm = 1.8 × 10⁸ N/m²/1 × 10⁵ N/m² = 1800
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a metal having a cubic structure has a density of 19.302 g/cm 3 an atomic weight of 196.97 g/mol and a lattice paramater of 4,0786 a one atom is associated with each lattice point determine the crystal structure of the metal
The metal's crystal structure is FCC.
Finding a metal's density to atomic weight ratio and lattice parameter value will reveal the metal's crystal structure. The ratio of density to atomic weight is about equivalent to the quantity of atoms per unit cell in the crystal structure if the metal has a density of 19.302 g/cm3 and an atomic weight of 196.97 g/mol.
One atom per lattice point in a cubic structure with a lattice parameter of 4.0786 corresponds to a simple cubic (SC), body-centered cubic (BCC), or face-centered cubic (FCC) structure. The lattice parameter and density to atomic weight ratio are most consistent with an FCC crystal structure.
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Someone tries to tell you that a freezer cools food by transferring cold to the particles in the food. (has to be 1 sentence)
How would you respond? Construct an argument.
am in 8th grade
pls explain as well bc I’m like rlly slow
Freezing keeps food safe by slowing the movement of molecules, causing microbes to enter a dormant stage. Freezing preserves food for extended periods because it prevents the growth of microorganisms that cause both food spoilage and foodborne illness.
What is freezing food?
Food is preserved when frozen, keeping it fresh from preparation until consumption.Farmers, fishers, and trappers have traditionally stored their produce and grains over the winter months in unheated structures.By turning any remaining moisture in food into ice, freezing it slows the breakdown process and prevents the majority of bacterial species from proliferating.Mechanical and cryogenic techniques are used in the food commodities industry (or flash freezing).To maintain the food's flavour and texture, freezing kinetics is crucial. Smaller ice crystals are produced more quickly, preserving cellular structure.To know more about the freezing food, click the link given below:
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What did each of the boys add to the success of the science fair win? Would Homer have been able to full-fill his dream without each of his friends or others? - October Sky
Find the amount of heat needed to increase the temperature of 5.0Mol of an ideal monatomic gas by 23K if (a)the pressure or (b)the volume is held constant.
The amount of heat needed is 2812.5 Joules.
To find the amount of heat needed to increase the temperature of 5.0 moles of an ideal monatomic gas by 23K when the pressure or volume is held constant, you can use the formula Q = nCΔT, where Q is the amount of heat, n is the number of moles, C is the heat capacity of the gas, and ΔT is the change in temperature.
In this case, n = 5.0 moles, C = 24.5 (the heat capacity of an ideal monatomic gas at constant pressure), and ΔT = 23K. Therefore, the amount of heat needed is Q = 5.0 * 24.5 * 23 = 2812.5 Joules.
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a space shuttle is in a 250 mile high orbit what are the shuttle's orbit period in minutes and its speed
The orbital period of a space shuttle in a 250 mile high orbit is approximately 91.3 minutes, and the orbital speed is approximately 17,500 miles per hour (7.68 kilometers per second).
This speed is determined by the gravitational pull from Earth, as well as the height of the orbit. The higher the orbit, the slower the orbital speed. For a 250 mile high orbit, the shuttle will need to maintain a constant speed in order to stay in orbit. The speed and orbital period of a space shuttle in orbit depend on a number of factors, including the height of the orbit, the mass of the shuttle, and the gravitational pull of the Earth.
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