NO LINKS OR ELSE YOU'LL BE REPORTED! Only answer if you're very good at Math.No guessing please.

Compare the rules of two games:

Game A: Two six-sided dice are thrown.The numbers on the dice determine which player gets a point.Player 1 gets a point if the product of the numbers on the dice is even.Player 2 gets a point if the product is odd.

Game B: Two six - sided dice are thrown.The numbers on the dice determine which player gets a point.Player 1 gets a point if the sum of the numbers on the dice is even.Player 2 gets a point if the sum is odd.

Which statement accurately describes whether these games are fair?

A: Both Game A and Game B are fair.

B: Game A is not fair,and Game B is fair.

C: Neither Game A nor Game B is fair.

D: Game A is fair,and Game B is not fair.


Answers

Answer 1

Answer: Choice B

Game A is not fair, and game B is fair.

==============================================================

We'll start with game A.

The sides of the dice are {1,2,3,4,5,6}

There are 6*6 = 36 ways to roll two dice.

If we roll two odd numbers, say 3 and 5, the product is odd because 3*5 = 15.

If any of the numbers are even, then the product is even. Eg: 4*5 = 20 or 2*6 = 12.

To be an even number, 2 must be a factor.

So you can probably see that it's more likely to get an even number product considering that in order to get an odd product, both values must be odd (which narrows the selection pool). We can say that game A is not fair. It favors player 1 more. If you're sure about this, then I recommend looking at a multiplication table but only focus on the first 6 rows and 6 columns. Ignore the row and column that has 0s in it.

------------------------------

Now onto game B

The rules are nearly the same, except now instead of multiplying the dice values, we add them up.

We still have 6*6 = 36 outcomes.

Here are some handy rules we'll take into account

even+even = eveneven+odd = oddodd+odd = even

If the first dice rolls to '1', then there are 3 ways to get an even number (rolling either 1,3,or 5 on the second dice) and there are 3 ways to get an odd number (rolling either 2,4,or 6 on the second dice). We can see that there are the same number of ways to get an even sum or an odd sum. Apply this in general to any result that the first dice shows, and this basically leads to the conclusion that half of the 36 sums are even, and the other half are odd. We have a fair game now. Refer to a sum of dice chart if you need more convincing.

Answer 2

Answer:

Game A is not fair, and game B is fair.

Step-by-step explanation:

test on iready


Related Questions

The ratio of copper to zinc in a certain alloy is 3 to 2. If 30 grams of copper are used, how many grams of zinc are needed to make this alloy?

Answers

Answer:

zinc is 20grams

Step-by-step explanation:

Given data

Ratio copper :zinc = 3:2

Copper =30 grams

Applying the ratio

3/2=30/x

Cross multiply

3x=30*2

3x=60

Divide both sides by 3

x=60/3

x=20

Hence zinc is 20grams

How is the graph of y = 8x2 − 1 different from the graph of y = 8x2?


It is shifted 1 unit down.


It is shifted 1 unit to the right.


It is shifted 1 unit to the left.


It is shifted 1 unit up.

Answers

Answer:

since it's the lhs we are concerned about, i. e., Y axis, so it must be either up or down. now look at the question, it says 8x2 - (1), it means one lower value of y i. e., 1 unit down

Answer:It is shifted 1 unit down.

Step-by-step explanation:

Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. The profit contribution and production time in hours per unit are as follows:
Category Product 1 Product 2 Product 3
Profit/unit $30 $50 $20
Machine 1 time/unit 0.5 2.0 0.75
Machine 2 time/unit 1.0 1.0 0.5
Two operators are required for machine 1; thus, 2 hours of labor must be scheduled for each hour of machine 1 time. Only one operator is required for machine 2. A maximum of 100 labor-hours is available for assignment to the machines during the coming week. Other production requirements are that product 1 cannot account for more than 50% of the units produced and that product 3 must account for at least 20% of the units produced.
How many units of each product should be produced to maximize the total profit contribution?
Product # of units
1
2
3
What is the projected weekly profit associated with your solution?
Profit = $
How many hours of production time will be scheduled on each machine? If required, round your answers to two decimal places.
Machine Hours Schedule:
Machine 1 Hours
Machine 2 Hours
What is the value of an additional hour of labor? If required, round your answers to two decimal places.
$
Assume that labor capacity can be increased to 120 hours. Develop the optimal product mix, assuming that the extra hours are made available.
Product # of units
1
2
3
Profit = $
Would you be interested in using the additional 20 hours available for this resource?

Answers

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

this question is much too hard would anyone please help me

Answers

Answer:

B and C are the same angles so if B is 60 so is C

Answer:

b= 60

c= 60

Step-by-step explanation:

<b and 120 form a straight line so the add to 180

b+120 =180

b = 180-120

b = 60

angles b and c are alternate interior angles so they are equal

b = c= 60

7)
8)
13x + 1/9x + 3
A) 6
C) -7
B) 8
D) 7
Α)
C)
I

Answers

Answer:

b) 8

Step-by-step explanation:

the angles are a linear pair meaning that they have a sum of 180. So 22x+4+180. Solve that and x=8

Answer:

B)     8

Step-by-step explanation:

(13x + 1) + (9x + 3) = 180

Combine like terms

22x + 4 = 180

Subtract 4 from both sides

22x = 176

Divide both sides by 22

x = 8

The volume of a rectangular prism is given by 24x3+78x2+49x+10. The height of the prism is given by 2x+5. Find an expression for the area of the base of the prism

Answers

Answer:

?

Step-by-step explanation:

i cant not explian that

5n+15 as an undistributed expression

Answers

Answer:

5(n + 3)

Step-by-step explanation:

Factor out 5

5(n + 3)

Answer:

5(n + 3)

should I also give u an explanation

I really need your help. I am having a lot of difficulty in solving this question, so please help me..​

Answers

Answer:

Step-by-step explanation:

[tex]log\ \frac{1}{x} = - log \ x \\\\log_a \ a = 1\\\\log \ a^x = x \ log \ a[/tex]

(iii)

[tex]m = log_2 \ \frac{1}{32}\\\\m = log_2 \ \ 32^{-1}\\\\m = - 1 \ log_2 32\\\\m = - 1 \ log_2 \ 2^5\\\\m = -1 \times 5 \ log_2 \ 2\\\\m = -5 \ log_2 \ 2\\\\m = -5 \times 1 = -5[/tex]

(iv)

[tex]log_a \ m = 0\\\\m = a^0 = 1[/tex]                       [tex][ \ log _a \ 1 = 0 \ ][/tex]

(vii)

[tex]log_{32} \ 8 = m\\\\8 = 32^m\\\\8^{ \frac{1}{m}} = 32 \\\\(2^{3 })^ { \frac{1}{m}} = 2^{5}\\\\2^{\frac{3}{m}} = 2^5 \\\\\frac{3}{m} = 5\\\\3 = 5 \times m \\\\m = \frac{3}{5}[/tex]

(viii)

[tex]log_5 \ ( 2m + 5 ) = 3\\\\(2m +5 ) = 5^3\\\\2m + 5 = 125\\\\2m = 125 - 5 \\\\2m = 120 \\\\m = 60[/tex]

(x)

[tex]log_{m^3} \ 64 = \frac{2}{3}\\\\64 = (m^3)^{ \frac{2}{3}}\\\\64 = m^{ 3 \times \frac{2}{3}}\\\\64 = m ^2\\\\\sqrt{64} = m \\\\8 = m[/tex]

The temperature at 2 a.m. was -10°C.
At an earlier time the temperature was
0°C. It changed by -2°C each hour
until 2 a.m. At what earlier time was
the temperature 0°C?

Answers

Answer:

-1

Step-by-step explanation:

The side of an equilateral triangle is 12. Its area is
Select one:
a. 144
b. 72
c. 36 √3
d. 48

Answers

Answer:

area is 1/2bh

in an euqilateral triangle, all sides are equal so base and height are 12

1/2 x 12 x 12

1/2 x 144= 72 (B)

Answer: Choice C. [tex]36\sqrt{3}[/tex]

This is the same as writing 36*sqrt(3)

===================================================

Work Shown:

x = 12 = side length of equilateral triangle

A = area of equilateral triangle

A = 0.25*sqrt(3)*x^2

A = 0.25*sqrt(3)*12^2

A = 0.25*sqrt(3)*144

A = 0.25*144*sqrt(3)

A = 36*sqrt(3) .... answer is choice C

Side note: the area approximates to 62.354 square units.

A checker board is a square board that is divided into smaller squares, with eight squares along each side. Describe how to find the number of small squares on a checker board without counting.

Answers

Multiply. Just multiply the number of squares in the width by the number of squares in the length. So, in this case, 8 times 8, which gets you 64.
The answer to the question is 64

course
Look at the following number line:
- 10
-5
0
5
10
What are two ways to write the inequality graphed?
x>-1 and -1 XS-1 and -12X
x < -1 and -1 > X
x2-1 and -1 5x

Answers

first and last one i think

8. A bag contains 72 toffees. How many toffees can be stored in 122 such bags? Estimate the number of toffees to nearest tens.
9.The working of a metro station is controlled by 28 persons. Estimate the number of persons required to control the working of 88 such stations to the nearest tens.

Answers

Answer:

8.) 8,780 toffees can be stored in 122 such bags.

9.) 2,460 people are required to control the working of 88 such stations.

Step-by-step explanation:

QUESTION 8:

We know that there are 72 toffees per bag

So if we want to know how many toffees can be stored in 122 such bags:

72 x 122 = 8,784

ROUND IT TO THE NEAREST TENS:

Look at the digit to the right of the tens place: 8,784–>4. 4 and below means that the digit will be repkaced by 0 and the tens place remains the same.

So 8,784 rounded to tens is 8,780

Tye answer for question 9 is

2,460 (do the same thing)

Line A passes through the points (10,6) qnd (2,15). Line B passes through the points (5,9) and (14,-1).

Answers

Answer:

Line A equation = y=-9/8x+69/4

Line B equation = y=-10/9x+131/9

Step-by-step explanation:

The elevation of Sports Authority Field in Denver, Colorado is 5280ft. If this is 275ft higher than seven times the elevation of Lucas Oil Field in Indinapolis, what is the elevation of Lucas Oil Field?

Answers

Answer:

The elevation of Lucas Oil Field is of 715 feet.

Step-by-step explanation:

Elevation of Sports Authority Field:

Of 5280 ft.

Compared to Lucas Oil Field:

275ft than seven times the Lucas Oil Field elevation of x.

Equation:

[tex]275 + 7x = 5280[/tex]

What is the elevation of Lucas Oil Field?

Solving the above equation:

[tex]7x = 5280 - 275[/tex]

[tex]7x = 5005[/tex]

[tex]x = \frac{5005}{7}[/tex]

[tex]x = 715[/tex]

The elevation of Lucas Oil Field is of 715 feet.

help what's the answer??

Answers

2 7/12 also known as 31/12
5 3/4 - 2/3 - 2 1/2
= 69/12 - 8/12 - 30/12
= 31/12

PLEASE HELP WKLL MARK IF YOU HELP ME !!!

Answers

Answer :

Let in Triangle abc,

a=90,

b = (we have to find)

c = (we have to find)

c + 144=180 (linear pair)

c = 180 - 144

c = 36

a + b + c = 180 (Angle sum property)

90 + b + 36 = 180

126 + b = 180

b = 180-126

b = 54

HW HELP ASAP PLZZZZZ

Answers

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: (x - 5)(x - 4) }}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\blue{Step-by-step\:explanation}}{\blue{:}}}}}[/tex]

[tex] {x}^{2} - 9x + 20[/tex]

[tex] = {x}^{2} - 4x - 5x + 20[/tex]

Taking "[tex]x[/tex]" as common from first two terms and "[tex]5[/tex]" from last two terms, we have

[tex] = x(x - 4) - 5(x - 4)[/tex]

Taking the factor [tex](x-4)[/tex] as common,

[tex] = (x - 5)(x - 4)[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

Wbich of the following statements describes the set of integers gieater than --3 but less than 6?​

Answers

-4,-5,0,1,2,2,4,5

Hope it works perfectly...

simplify (1+3i) + (2-5i)​

Answers

Answer:

3 - 2i

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Terms/Coefficients

Algebra II

Imaginary number i = √-1

Step-by-step explanation:

Step 1: Define

Identify

(1 + 3i) + (2 - 5i)

Step 2: Simplify

[Addition] Combine like terms:                                                                        3 + 3i - 5i[Subtraction] Combine like terms (i):                                                               3 - 2i

Two points on the line are (0, 4) and (7, 18). Use the points to first determine the slope and y-intercept. Then write the equation of the line. a. m = 2; y intercept = (0, 4); y = 2 x + 4 b. m = negative 2; y intercept = (0, 4); y = negative 2 x + 4 c. m = negative 2; y intercept = (4, 0); y = negative 2 x + 4 d. m = 2; y intercept = (0, 4); y = 4 x + 2

Answers

9514 1404 393

Answer:

  a.  m = 2; y intercept = (0, 4); y = 2 x + 4

Step-by-step explanation:

The slope can be found using the formula ...

  m = (y2 -y1)/(x2 -x1)

  m = (18 -4)/(7 -0) = 14/7

  m = 2

The y-intercept is the first given point: (0, 4).

The equation for the line in slope-intercept form is

  y = mx + b

Here, we have m=2 and b=4, so the equation is ...

  y = 2x +4

Which equation is equivalent to 4 x = t + 2
s = t-2
s=4/t+2
s=t+2/4
s=t+6

Answers

B= S=4/t+2
whenever you have the equation 4 x = t+2 you are trying to isolate the X by doing that you have ti take the 4 and divide it to the other side so the x can stay on that side

The square below represents one whole.
What percent is represented by the shaded area?
%



The anwser is 6%

Answers

Answer:

the answer is 6%

hdhxbxcbxbxszznzj

Please help me with solving these. Thank you very much. Have a great day!

Answers

Answer:

Problem 20)

[tex]\displaystyle \frac{dy}{dx}=(\cos x)^x\left(\ln \cos x-x\tan x\right)[/tex]

Problem 21)

A)

The velocity function is:

[tex]\displaystyle v(t) =2\pi(\cos(2\pi t)-\sin(\pi t))[/tex]

The acceleration function is:

[tex]\displaystyle a(t)=-2\pi^2(2\sin(2\pi t)+\cos(\pi t))[/tex]

B)

[tex]s(0)=2\text{, }v(0) = 2\pi \text{ m/s}\text{, and } a(0) = -2\pi^2\text{ m/s$^2$}[/tex]

Step-by-step explanation:

Problem 20)

We want to differentiate the equation:

[tex]\displaystyle y=\left(\cos x\right)^x[/tex]

We can take the natural log of both sides. This yields:

[tex]\displaystyle \ln y = \ln((\cos x)^x)[/tex]

Since ln(aᵇ) = bln(a):

[tex]\displaystyle \ln y =x\ln \cos x[/tex]

Take the derivative of both sides with respect to x:

[tex]\displaystyle \frac{d}{dx}\left[\ln y \right]=\frac{d}{dx}\left[x \ln \cos x\right][/tex]

Implicitly differentiate the left and use the product rule on the right. Therefore:

[tex]\displaystyle \frac{1}{y}\frac{dy}{dx}=\ln \cos x+x\left(\frac{1}{\cos x}\cdot -\sin(x)\right)[/tex]

Simplify:

[tex]\displaystyle \frac{1}{y}\frac{dy}{dx}=\ln \cos x-\frac{x\sin x}{\cos x}[/tex]

Simplify and multiply both sides by y:

[tex]\displaystyle \frac{dy}{dx}=y\left(\ln \cos x-x \tan x\right)[/tex]

Since y = (cos x)ˣ:

[tex]\displaystyle \frac{dy}{dx}=(\cos x)^x\left(\ln \cos x-x\tan x\right)[/tex]

Problem 21)

We are given the position function of a particle:

[tex]\displaystyle s(t)= \sin (2\pi t)+2\cos(\pi t)[/tex]

A)

Recall that the velocity function is the derivative of the position function. Hence:

[tex]\displaystyle v(t)=s'(t)=\frac{d}{dt}[\sin(2\pi t)+2\cos(\pi t)][/tex]

Differentiate:

[tex]\displaystyle \begin{aligned} v(t) &= 2\pi \cos(2\pi t)-2\pi \sin(\pi t)\\&=2\pi(\cos(2\pi t)-\sin(\pi t))\end{aligned}[/tex]

The acceleration function is the derivative of the velocity function. Hence:

[tex]\displaystyle a(t)=v'(t)=\frac{d}{dt}[2\pi(\cos(2\pi t)-\sin(\pi t))][/tex]

Differentiate:

[tex]\displaystyle \begin{aligned} a(t)&=2\pi[-2\pi\sin(2\pi t)-\pi\cos(\pi t)]\\&=-2\pi^2(2\sin(2\pi t)+\cos(\pi t))\end{aligned}[/tex]

B)

The position at t = 0 will be:

[tex]\displaystyle \begin{aligned} s(0)&=\sin(2\pi(0))+2\cos(\pi(0))\\&=\sin(0)+2\cos(0)\\&=(1)+2(1)\\&=2\end{aligned}[/tex]

The velocity at t = 0 will be:

[tex]\displaystyle \begin{aligned} v(0)&=2\pi(\cos(2\pi (0)-\sin(\pi(0))\\&=2\pi(\cos(0)-\sin(0))\\&=2\pi((1)-(0))\\&=2\pi \text{ m/s}\end{aligned}[/tex]

And the acceleration at t = 0 will be:

[tex]\displaystyle \begin{aligned} a(0) &= -2\pi ^2(2\sin(2\pi(0))+\cos(\pi(0)) \\ & = -2\pi ^2(2\sin(0)+\cos(0)) \\ &= -2\pi ^2(2(0)+(1)) \\ &= -2\pi^2(1) \\ &= -2\pi^2\text{ m/s$^2$} \end{aligned}[/tex]

Which expression is equivalent to ?
x ^-5/3

Answers

Answer:

[tex] {x}^{ - \frac{5}{3} } \\ \frac{1}{ {x}^{ \frac{5}{3} } } [/tex]

In how many ways can a committee of 3 men and 2 women be formed from a group of 9 men and 10 ​women?

Answers

Answer:

first you have to find the number of ways 3 men can be chosen, then the number of ways 2 women can be chosen, and then you need to multiply these numbers together to get the number of ways because multiplication will show the total arrangements possibilities. use combination since order does not matter.

number ways for 2 out of 10 women total: 10 choose 2= 45

number of ways for 3 out of 9 men total: 9 choose 3= 84

84x45= 3780

3780 total ways

number of ways

công thức đạo hàm của ln(u) = ?

Answers

Answer:

U'/U

Step-by-step explanation:

Find the value of k, if (x - 2) is a factor of the polynomial p(x) = 2x2 + 3x - k​

Answers

Answer:

The value of k is 14.

Step-by-step explanation:

(x - 2) is a factor of the polynomial

[tex]x - 2 = 0 \rightarrow x = 2[/tex]

This means that [tex]p(2) = 0[/tex]

p(x) = 2x² + 3x - k​

[tex]p(2) = 2(2)^2 + 3(2) - k[/tex]

[tex]0 = 8 + 6 - k[/tex]

[tex]14 - k = 0[/tex]

[tex]k = 14[/tex]

The value of k is 14.

A baseball is hit and its height at different one-second intervals is recorded (See attachment)

Answers

Answer:

[tex]h(t)[/tex] is likely a quadratic function.

Based on values in the table, domain of [tex]h(t)[/tex] : [tex]\lbrace 0,\, 1,\, 2,\, 3,\, 4,\, 5,\, 6,\, 7,\, 8\rbrace[/tex]; range of [tex]h(t)\![/tex]: [tex]\lbrace 0,\, 35.1,\, 60.1\, 75.2,\, 80.3,\, 75.3,\, 60.2,\, 35.0 \rbrace[/tex].

Step-by-step explanation:

By the power rule, [tex]h(t)[/tex] is a quadratic function if and only if its first derivative, [tex]h^\prime(t)[/tex], is linear.

In other words, [tex]h(t)[/tex] is quadratic if and only if [tex]h^\prime(t)[/tex] is of the form [tex]a\, x + b[/tex] for some constants [tex]a[/tex] and [tex]b[/tex]. Tables of differences of [tex]h(t)\![/tex] could help approximate  whether [tex]h^\prime(t)\![/tex] is indeed linear.

Make sure that values of [tex]t[/tex] in the first row of the table are equally spaced. Calculate the change in [tex]h(t)[/tex] over each interval:

[tex]h(1) - h(0) = 35.1[/tex].[tex]h(2) - h(1) = 25.0[/tex].[tex]h(3) - h(2) = 15.1[/tex].[tex]h(4) - h(3) = 5.1[/tex].[tex]h(5) - h(4) = -5.0[/tex].[tex]h(6) - h(5) = -15.1[/tex].[tex]h(7) - h(6) = -25.2[/tex].[tex]h(8) - h(7) = -35.0[/tex].

Consecutive changes to the value of [tex]h(t)[/tex] appears to resemble a line with slope [tex](-10)[/tex] within a margin of [tex]0.2[/tex]. Hence, it is likely that [tex]h(t)\![/tex] is indeed a quadratic function of [tex]t[/tex].

The domain of a function is the set of input values that it accepts. For the [tex]h(t)[/tex] of this question, the domain of [tex]h(t)\![/tex] is the set of values that [tex]t[/tex] could take. These are listed in the first row of this table.

On the other hand, the range of a function is the set of values that it outputs. For the [tex]h(t)[/tex] of this question, these are the values in the second row of the table.

Since both the domain and range of a function are sets, their members are supposed to be unique. For example, the number "[tex]0[/tex]" appears twice in the second row of this table: one for [tex]t = 0[/tex] and the other for [tex]t = 8[/tex]. However, since the range of [tex]h(t)[/tex] is a set, it should include the number [tex]0\![/tex] only once.

> Next question Get a similar question You this question below Find the distance between the points (-3,-3) and (-5,-1) Distance vo Х Submit Question​

Answers

Answer:

The answer is the square root of 8, or 2root2.

Step-by-step explanation:

Use the distance formula.

d = sqrt((-3-(-5))^2 + (-3-(-1)))

d = sqrt(2^2 + 2^2)

d = sqrt(4 + 4)

d = sqrt8

d = sqrt4 * sqrt2

d = 2 * sqrt2

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