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HELPPP ​

Answer:

-x-9

Step-by-step explanation:

-(x+9)

The "-" at the beginning can be rewritten as -1

=-1(x+9)

To distribute -1 into the parentheses, multiply each value inside by -1

=(-1)(x)+(-1)(9)

=(-x)+(-9)

= -x-9

I hope this helps!

Answer: here u go and can u give me brainliest

Step-by-step explanation:

Answer:

The answer should be C....

Answer:

3 -2x^2 -6x= -18

Step-by-step explanation:

that's what got

Answer:

30

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

:P

Answer:

1400 ft.

Step-by-step explanation:

It is a simple problem you just need to take the rate (30 ft. per second) and multiply it times the number of seconds it traveled (20) so you're equation would be 20x30 which results in 600. This means the ship has traveled 600 ft. in 20 seconds meaning it is 600 ft. close to you. To get the final answer 1400 you take it's original distance (2000) and subtract how far it has traveled since then (600) so you would get 2000-600=1400 ft. away

Answer:

Y-Intercept

Step-by-step explanation:

Your question is not that clear to answer. If you are asking what number -1 called its y-intercept

Answer:

37

Step-by-step explanation:

Answer:

4/1/5=20 because when you divide by a fraction u keep change the divison into multiplaicton and flip the 1/5 to 5/1 so 4x5

Step-by-step explanation:

Answer:

0.37

Step-by-step explanation:

Answer:

Step-by-step explanation:

The fraction 8/8 is an improper fraction. A proper fraction is one in which the numerator is less than the denominator.

1/1, 2/2, 3/3, 4/4, 5/5, 6/6, 7/7, 8/8, 9/9, 10/10, 11/11, 12/12, 13/13, 14/14, 15/15 ...

Answer:

r = -2

Step-by-step explanation:

Hope this helps :)

Answer:

6pi meters

Step-by-step explanation:

The formula for area of a circle is

A = pi r^2

9 pi  = pi r^2

Divide each side by pi

9 = r^2

Take the square root of each side

sqrt(9) = sqrt(r^2)

3 =r

Now we can find the circumference

C = 2 * pi *r

C = 2 * pi *3

C = 6pi meters

Answer:

6pi meters

Step-by-step explanation:

give the person above brainliest

have a good one!

Answer: 224

Step-by-step explanation: Subtract the terms and term number to find the common difference, 168/42=4. 112-29×4=-4=first term. 57×4+-4=224!

Answer:

free

Step-by-step explanation:

Answer:

x = 3

Step-by-step explanation:

ok then, firstly, lets make line CB into y

sin45 / y = sin 90 / 6[tex]\sqrt{2}[/tex]

in other words, as sin 90 = 1

y / sin45 = 6[tex]\sqrt{2}[/tex]

y = sin 45 * 6[tex]\sqrt{2}[/tex] = 6 as sin 45 = root2/2, and root2 * root 2 = 2, so

6*2/2 = 6

we also know BCD is 30*, as angles in a tri add up to 180*

so, x/sin30 = 6/sin90 = 6

x/sin30 = 6

6*sin30 = x

x = 3 as sin 30 = 1/2

Answer:

y = mx + b

Step-by-step explanation:

Answer:

The answer is B) 152

Step-by-step explanation:

Answer:

0.98 = 98% probability that the average midterm score of these students is at most 75 points.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The average midterm score of students in a certain course is 70 points.

This means that [tex]\mu = 70[/tex]

29 students are randomly selected and the standard deviation of their scores is found to be 13.15 points.

This means that [tex]\sigma = 13.15, n = 29, s = \frac{13.15}{\sqrt{29}} = 2.44[/tex]

Find the probability that the average midterm score of these students is at most 75 points.

This is the pvalue of Z when X = 75. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{75 - 70}{2.44}[/tex]

[tex]Z = 2.05[/tex]

[tex]Z = 2.05[/tex] has a pvalue of 0.98.

0.98 = 98% probability that the average midterm score of these students is at most 75 points.

Answer:

I believe it is 3

Step-by-step explanation:

Answer:

the answer is 3 brainlest plz

Step-by-step explanation:

Answer:

$1.25

Step-by-step explanation:

There is a lot of unnecessary extra information we can ignore here. Simply divide the amount collected on any given day by the number of snacks sold.

53.75 / 43 = $1.25

Double check via another day:

45 / 36 = $1.25 ~ yup!

The price per snack is $1.25.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

From the table,

We see that,

43 snacks = $53.75

This means,

1 snack = 53.75/43 = 1.25

Similarly,

36 snacks = 45

1 snack = 45/36 = 1.25

Thus,

The price per snack is $1.25.

Learn more about expressions here:

https://brainly.com/question/3118662

#SPJ3

Subtracting 3 from all measurements, it is found that:

From this, we have that:

More can be learned about the standard deviation of a data-set at https://brainly.com/question/12180602

#SPJ1

Answer:

27 problems are remaining to solve

I assume the given plane has equation

x + 3y + 4z = d

for some constant d ≠ 0.

You want to maximize the function V(x, y, z) = xyz subject to the above constraint. The Lagrangian would be

L(x, y, z, λ) = xyz - λ (x + 3y + 4z - d)

Find its critical points:

∂L/∂x = yz - λ = 0

∂L/∂y = xz - 3λ = 0

∂L/∂z = xy - 4λ = 0

∂L/∂λ = x + 3y + 4z - d = 0

The first three equations tell you that λ = yz = xz/3 = xy/4. Then, for instance,

yz = xz/3   →   3yz - xz = z (3y - x) = 0   →   z = 0   or   3y - x = 0

If z = 0, we get zero volume which is not useful. So 3y = x. Similarly, you would find x = 4z and 3y = 4z, so a critical point occurs when x = 3y = 4z.

In the fourth equation, we get upon substituting

x + 3y + 4z = 3x = d   →   x = d/3, y = d/9, z = d/12

Then the largest volume of this box would be

V(d/3, d/9, d/12) = d ³ / 324

le tienes que sumar 5,400 para que te de el resultado

Answer:

Le tienes que añadir 5400

Step-by-step explanation:

Answer:

[tex]x \ge 0[/tex]  

[tex]y \ge 0[/tex]

[tex]x + y \le 9[/tex]

[tex]8 - x \ge 0[/tex]

[tex]3 - y \ge 0[/tex]

[tex](8 - x) + (3 - y) \le 6[/tex]

Step-by-step explanation:

Given

x = Cars from Baltimore to Trenton

y = Cars from Baltimore to Philadelphia

Required

Write out 6 inequalities

First, 0 or more cars must be shipped to both locations

So:

[tex]x \ge 0[/tex]

[tex]y \ge 0[/tex]

Considering the warehouse in Baltimore.

(1) The warehouse can not ship more than the number of car it has (9).

So:

[tex]x + y \le 9[/tex]

Considering the warehouse in New York.

(1) After shipping cars to Trenton and Philadelphia, the warehouse will have 0 or more cars.

So:

[tex]8 - x \ge 0[/tex] --- To Trenton

[tex]3 - y \ge 0[/tex] --- To Philadelphia

(2) The warehouse cannot send out more than 6.

So:

[tex](8 - x) + (3 - y) \le 6[/tex]

So, the inequalities are:

[tex]x \ge 0[/tex]

[tex]y \ge 0[/tex]

[tex]x + y \le 9[/tex]

[tex]8 - x \ge 0[/tex]

[tex]3 - y \ge 0[/tex]

[tex](8 - x) + (3 - y) \le 6[/tex]

Answer:

73.46 yds ^2

Step-by-step explanation:

triangle = 1/2bh = 1/2(19)(16) = 152

circle= πr^2

π(5)^2 = 25π = 78.54

152 -78.54= 73.46

Answer:

a) P(rolling a number less than 4 on Die 1 and rolling a 5 on Die 2) = [tex]\frac{1}{9}[/tex]

b) P( the sum of both dice adding up to 4) = [tex]\frac{5}{54}[/tex]

Step-by-step explanation:

Given - You roll two six-sided dice. Die 1 is fair. Die 2 is unfair such that the probability of rolling an odd number is [tex]\frac{2}{3}[/tex] and the probability of rolling an even number is [tex]\frac{1}{3}[/tex] , though the probability rolling of each odd number is the same, and the probability of rolling each even number is the same.

To find - What is the probability of:

              a) rolling a number less than 4 on Die 1 and rolling a 5 on Die 2.

              b) the sum of both dice adding up to 4.

Proof -

The sample space , S = { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

                                          (2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

                                          (3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

                                          (4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

                                          (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

                                          (6,1), (6,2), (6,3), (6,4), (6,5), (6,6) }

Now,

Given that , Dice 1 is fair

⇒P₁(1) = P₁(2) = P₁(3) = P₁(4) = P₁(5) = P₁(6) = [tex]\frac{1}{6}[/tex]

Also, Given Dice 2 is unfair

⇒P₂(1) = P₂(3) = P₂(5) = [tex]\frac{2}{3}.\frac{1}{3} = \frac{2}{9}[/tex]

   P₂(2) = P₂(4) = P₂(6) = [tex]\frac{1}{3}.\frac{1}{3} = \frac{1}{9}[/tex]

Now,

a)

P(rolling a number less than 4 on Die 1 and rolling a 5 on Die 2) = P₁(1)P₂(5) + P₁(2)P₂(5) + P₁(3)P₂(5)

= P₂(5) [ P₁(1) + P₁(2) + P₁(3) ]

= [tex]\frac{2}{9}[/tex] [ [tex]\frac{1}{6}[/tex] + [tex]\frac{1}{6}[/tex] + [tex]\frac{1}{6}[/tex] ] = [tex]\frac{2}{9}[ \frac{3}{6}]\\[/tex] = [tex]\frac{1}{9}[/tex]

⇒P(rolling a number less than 4 on Die 1 and rolling a 5 on Die 2) = [tex]\frac{1}{9}[/tex]

b)

P( the sum of both dice adding up to 4) = P₁(1)P₂(3) + P₁(2)P₂(2) + P₁(3)P₂(1)

                                                                  = [tex]\frac{1}{6}[/tex] × [tex]\frac{2}{9}[/tex]  + [tex]\frac{1}{6}[/tex] × [tex]\frac{1}{9}[/tex] + [tex]\frac{1}{6}[/tex] ×[tex]\frac{2}{9}[/tex]   = [tex]\frac{5}{54}[/tex]

⇒P( the sum of both dice adding up to 4) = [tex]\frac{5}{54}[/tex]