Answer:
, Nervous tissue is composed of two types of cells, neurons and glial cells. Neurons are the primary type of cell that most anyone associates with the nervous system. They are responsible for the computation and communication that the nervous system provides.
what is an example of an involuntary muscle?
Answer:
the cardiac muscle is an example
Answer:
your heart
Explanation:
it keeps beating all day and all night
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If you know that your average speed on road trips in 47 mph, how much time should you plan for a road trip to Atlanta, which is 715 miles away?
Answer:
about 15 hours and 13 minutes
Explanation:
If the average speed on road trips is 47 mph, then we use the formula for speed to estimate the time it would take to cover a distance of 715 miles:
speed = distance / time
solve for "time" by cross-multiplication:
time = distance / speed
time = 715 / 47 = 15.212 hours
Which is about 15 hours and 13 minutes
slader A barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer). On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion). (a) Determine the barometric pressure in psia. If the ambient temperature increased to 85oF and the barometric pressure did not change, (b) would the mercury column be longer, be shorter, or remain the same length
Answer:
Explanation:
vapour pressure at 70⁰F = .36 psi
pressure of 6.5 inch water column
6.5 inch = 6.5 x 2.54 cm =.165 m
pressure = .165 x 10³ x 9.8 = 1617 Pa
= 1617 x .000145 psi
= .23 psi
28.35 inch = 28.35 x 2.54 cm = .72 m
pressure = .72 x 13.6 x 10³ x 9.8
= 95961.6 Pa
= 95961.6 x .000145 psi
= 13.91 psi
a ) Barometric pressure at 70⁰F
= pressure due to mercury column of 28.35 inch + water column of 6.5 inch + vapour pressure at 70⁰F
= 13.91 + .23 + .36 psi
= 14.5 psi
b )
If pressure is measured at 85⁰F
vapour pressure will be increased and pressure of dry gas will also be increased . This pressure will force down the column of mercury . So column of mercury will go down .
A 250 kg motorcycle starts at rest at a stoplight. When the light turns green the motorcycle accelerates to 20 m/s in 4 seconds. Calculate the force applied by the motorcycle if there is also 200 N of friction. Please show work. Any help would be appreciated
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A 1125 kg car was traveling at 20 m/s toward a traffic signal when the light suddenly turned red. The driver stomped on her accelerator, clearing the intersection in 1.7 seconds and coming to a speed of 24.6 m/s . What was the acceleration of the car?
Answer:
a = 3.88 m/s^2 (3.88 meters per second squared)
Explanation:
The acceleration of the car can be obtained based of the change of velocities (from initial velocity "vi" to final velocity "vf") in the given amount of time:
In our case:
a = (26.6 - 20) / 1.7 = 3.88 m/s^2
An airplane is traveling at 250 m/s in level flight. If the airplane is to make a change in direction, it must travel is a horizontal curved path. To fly in the curved path, the pilot banks the airplane at an angle such that the lift has a horizontal component that provides the horizontal centripetal acceleration to move in a horizontal circular path. If the airplane is banked at an angle of 15.0 degrees, then the radius of curvature of the curved path of the airplane is
Answer:
The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).
Explanation:
We assume that airplane can be represented as a particle. The free body diagram of the vehicle is presented below as attachment, whose variables are:
[tex]W[/tex] - Weight of the airplane, measured in newtons.
[tex]F[/tex] - Lift, measured in newtons.
[tex]\theta[/tex] - Banking angle, measured in sexagesimal degrees.
The equations of equilibrium associated with the airplane are, respectively:
[tex]\Sigma F_{r} = F\cdot \sin \theta = m\cdot \frac{v^{2}}{R}[/tex] (Eq. 1)
[tex]\Sigma F_{z} = F\cdot \cos \theta - W = 0[/tex] (Eq. 2)
From (Eq. 2):
[tex]F = \frac{W}{\cos \theta}[/tex]
In (Eq. 1):
[tex]W\cdot \tan \theta = m\cdot \frac{v^{2}}{R}[/tex]
By using the definition of weight, we eliminate the mass of the airplane:
[tex]g\cdot \tan \theta = \frac{v^{2}}{R}[/tex]
Where:
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v[/tex] - Speed, measured in meters per second.
[tex]R[/tex] - Radius of curvature, measured in meters.
Lastly, we clear the radius of curvature with the expression:
[tex]R = \frac{v^{2}}{g\cdot \tan \theta}[/tex]
If we know that [tex]v = 250\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\theta = 15^{\circ}[/tex], the radius of curvature is:
[tex]R = \frac{\left(250\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot \tan 15^{\circ}}[/tex]
[tex]R = 23784.356\,m[/tex]
The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).
If the forces on an object are balanced, the object will do what?
If an object starts out at rest and accelerates to 100 m/s what is its initial speed?
Answer:0m/s
Explanation.
The initial velocity is 0 because when the object starts moving its speed is zero
HELP PLZ HURRY :((( I NEED IT BY TONIGHT
Answer:
Please see attached image
Explanation:
On his fishing trip Justin takes the boat 4 km south. The fish aren’t biting so he goes 4 km back east. He follows a school of fish 4 km further north and then 3 km west. What distance did he cover? What was his displacement?
Answer:
Distance = 15km
Displacement = 1km
Explanation:
the total distance covered is how far Justin has travelled = 4km + 4km + 4km + 3km
Total distance covered = 15km
To get the displacement, we will use the Pythagoras theorem. Find the diagram attached.
From the diagram, the displacement D is expressed as:
D = AC - BC
From the diagram
AC = 4km
BC = 3km
D = 4km - 3km
D = 1km
Hence his displacement is 1km
A man is pulling a box with the force of 10N. There is nobody else on the other side of the box. What is the total amount of force on the box? *
15. An astronaut on the moon has a 110 kg crate and a 230 kg crate. How do the forces required to liftyihe crates straight up on the moon compare with the forces required to lift them on Earth?
Explanation:
Mass of carte 1 is 110 kg and that of crate 2 is 230 kg
Force required to lift crates is equal to its crate i.e. W = mg
On Moon, a = 1.625 m/s²
Weight of crate 1, W = 110 kg × 1.625 m/s² = 178.75 N
Weight of crate 2, W = 230 kg × 1.625 m/s² = 373.75 N
On Earth, g = 9.8 m/s²
Weight of crate 1, W = 110 kg × 9.8 m/s² = 1078 N
Weight of crate 2, W = 230 kg × 9.8 m/s² = 2254 N
Hence, this is the required solution.
The forces required to lift the crates straight up on the Moon is lesser than the forces required to lift them on Earth.
Given the following data:
Mass A = 110 kgMass B = 230 kgScientific data:
Acceleration due to gravity on Earth = 9.8 [tex]m/s^2[/tex]Acceleration due to gravity on Moon = 1.6 [tex]m/s^2[/tex]The formula for weight.Mathematically, the weight of an object is given by the formula;
[tex]Weight = mg[/tex]
Where;
m is the mass of the object.g is the acceleration due to gravity.For the weight on Moon:[tex]Weight \;A= 110 \times 1.6[/tex]
Weight A = 176 Newton.
[tex]Weight \;B=230 \times 1.6[/tex]
Weight B = 368 Newton.
For the weight on Earth:[tex]Weight \;A= 110 \times 9.8[/tex]
Weight A = 1,078 Newton.
[tex]Weight \;B=230 \times 9.8[/tex]
Weight B = 2,254 Newton.
In conclusion, the forces required to lift the crates straight up on the Moon is lesser than the forces required to lift them on Earth.
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5
2. When you keep the mass the same and decrease the unbalanced force how does the acceleration change?
Answer:
The acceleration will decrease due to less force acting on the object.
Explanation:
Can someone who knows how to do physics please answer this
Answer:
about 3.17647 hours
Explanation:
The appropriate relation is ...
time = distance/speed
time = (270 km)/(85 km/h) = 3 3/17 h ≈ 3.17647 h
It will take Derek about 3.17647 hours to drive the distance.
Arctic sea ice has declined over the past few decades causing water levels to increase. This is an interaction of which two spheres? A)Biosphere and geosphere
B)Cryosphere and hydrosphere
C)Geosphere and atmosphere
D)Hydrosphere and geosphere
Answer:
B
Explanation:
Answer:
Its B)Cryosphere and hydrosphere! I took the test and got that question correct!
Explanation:
You drive 200 miles in 3 hours before stopping
for 30 minutes for lunch and gas. After lunch,
you travel 150 miles in an hour and a half. What
was your average speed for the trip?
Answer 55.5mph
explanation
A motorcycle is stopped at a stop light. When the light turns green it
accelerates at 4.2 m/s^2. How far does it travel during 3 s? *
Answer: 18.9 m
Explanation:
i did the kinematic equation & found the answer.
a blackbody is at temperature of 500°C . What would be its temperature in Kelvin for it to radiate twice as much energy per second?
Answer:
Its temperature in Kelvin for it to radiate twice as much energy = [tex]919.257k[/tex]Explanation:
Energy = [tex]6AT^4[/tex]
therefore,
[tex]\frac{E_1}{E_2} = \frac{T_1^4}{T_2^4}[/tex]
where [tex]E_2 = 2E_1[/tex]
therefore,
[tex]\frac{E_1}{2E_1} = \frac{(500+273)^4}{T_2^4}\\\\T_2 = 919.257k\\\\T_2 = 646.257^oC[/tex]
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What was the instantaneous speed of Bear A at 5 seconds in meters/min? (No unit conversions necessary, no units required for answer. Type your answer.)
Answer: The answer is 40.
Explanation: There is a typo, they mean 5 minutes. Five minutes is the line between zero and 10, and the dot matches up at 5 and 200. 200 divided by 5= 40.
An astronaut weighing 588 N on earth notices that he weighs only 98 N on moon. His mass on moon is blank kg
Answer:
60 kg
Explanation:
An astronaut weighs 588 N on the earth
He also weighs 98 N on the moon
Therefore the the mass of the astronaut on the moon can be calculated as follows
= 588/98
= 6 × 10
= 60 kg
Hence the mass of the astronaut on the moon is 60 kg
The mass of the astronaut on the moon will be equal to 60 kg whereas the gravitational acceleration on the moon is 1.63 [tex]\rm m/s^2[/tex].
Given information:
An astronaut weighing 588 N on the earth notices that he weighs only 98 N on the moon.
The mass of any object in the whole universe doesn't change but the gravitational force or weight can change. This is because the gravitational acceleration can change.
The mass of the object in the earth or anywhere will be,
[tex]w=mg\\588=m\times 9.8\\m=60\rm \; kg[/tex]
So, the astronaut has 60 kg mass which is constant.
The gravitational acceleration on the moon will be,
[tex]98=60a\\a=1.63\rm\; m/s^2[/tex]
Therefore, the mass of the astronaut on the moon will be equal to 60 kg whereas the gravitational acceleration on the moon is 1.63 [tex]\rm m/s^2[/tex].
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Which phrase best describes the path of a light wave
A: parallel to the source
B:Perpendicular to the source
C:Straight away from the source
D:Spiraling around the force
Answer:
C
Explanation:
Straight away from the source
Answer:c
Explanation:
Straight away from the source
The amount of thermal energy transferred between objects depends only on their masses and initial and final temperatures.
Question 17 options:
True
False
Answer:
False
Explanation:
The amount of energy transferred between objects not only depend on their masses, initial and final temperatures but also on their specific heat capacity.
The specific heat capacity plays an important role in ascertaining the amount of thermal energy a body can conduct.
Specific heat capacity is the amount of heat required to raise the temperature of 1kg of a substance by 1kelvin. This property is an intensive property of any matter and it determines to a large extent, how far matter are able to transfer energy.The equation;
H = m c Ф
where H is the amount of heat
m is the mass
c is the specific heat capacity
Ф is the change in temperature;
is used to find the amount of heat of a substance.
Answer:
false
Explanation:
Because the amount of energy is transferred between objects not only depend on their masses, initial and final temperatures but also on their specific heat capacity.
Hopes this helps you and it’s correct because I had this question on edgenuity
mechanical energy defintion
Answer: Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.
(The energy acquired by the objects upon which work is done)
True or False: a projectile accelerates only in the y (vertical) direction. The "x," or
horizontal acceleration is equal to zero.
Answer:
True
Explanation:
Assuming no wind resistance, there will be no horizontal acceleration, because there will be no forces acting on it.
the first outside orbit of Earth planet is
a Jupiter
b Mars
c Saturn
d uranus
Answer:
I believe it would be B, Mars.
Hope this helps!
a dump truck slowly tilts its bed upward to dispose of a 95 kg steel cabinet. For small angle of tilt the crate stay put,but when the tilt angle exceeds 23.2° the steel cabinet begins to slide.What is the coefficient of static friction between the bed of the truck and the steel cabinet?
Answer:
The value is [tex]\mu =0.4286[/tex]
Explanation:
From the question we are told that
The mass of the steel cabinet is [tex]m = 95 \ kg[/tex]
The threshold angle is [tex]\theta = 23.2^o[/tex]
Generally at the point just before the steel cabinet starts to slide
The horizontal force on the steel cabinet is equal to the frictional force that is
[tex]F_f = F_h[/tex]
Here [tex]F_h[/tex] is the horizontal force which is mathematically represented as
[tex]F_h = m * g cos (theta )[/tex]
and [tex]F_f = \mu N[/tex]
Here N is the normal force acting on the steel cabinet and this is mathematically represented as
[tex]N = mg sin (\theta )[/tex]
=> [tex] m * g cos (theta )= mg sin (\theta ) * \mu [/tex]
=> [tex]\mu = tan (\theta )[/tex]
=> [tex]\mu = tan (23.2)[/tex]
=> [tex]\mu =0.4286[/tex]
The coefficient of static friction between the bed of the truck and steel cabinet is 0.43.
The given parameters;
mass of the steel, m = 95 kgangle of inclination, θ = 23.2⁰The coefficient of static friction between the bed of the truck and steel cabinet is calculated as follows;
[tex]\Sigma F = 0\\\\mg sin(\theta) - \mu mg cos(\theta) = 0\\\\\mu mg cos(\theta ) = mg sin(\theta)\\\\\mu cos(\theta) = sin(\theta)\\\\\mu = \frac{sin(\theta)}{cos(\theta)} \\\\\mu = tan (\theta)\\\\\mu = tan \ (23.2)\\\\\mu = 0.43[/tex]
Thus, the coefficient of static friction between the bed of the truck and steel cabinet is 0.43.
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URGENT!! A 0.057 kg tennis ball and a tennis racket collide. The racket has an initial
momentum of -2.80 kg m/s and a final momentum of -1.97 kg-m/s. The ball
has an initial momentum of 0.02565 kg-m/s. If you assume the collision is
elastic, what is the final velocity of the ball?
O A. -83.26 m/s
O B. -0.80 m/s
O C. -14.11 m/s
O D. -4.75 m/s
Answer:
-14.11
Explanation:
Which choice has the least thermal energy?
A swimming pool full of cool water
b all the water in Earth's oceans
C cup of hot cocoa
d bathtub full of warm water
Answer:it’s c a cup of hot cocoa
Explanation:
Answer:
c, cup of hot cocoa
Explanation:
it might seem like the hot cocoa is the hottest, but because the substance is so small, it has the least thermal energy
is 4x a term? or does it have to remove the 4 to be a term
Answer:
4x is a term oonly
No need to be romoved
A disc with moment of inertia 1.5 kg m2 is rotating with an angular speed of 800 rev/min on a shaft. A second disc, initially at rest and with moment of inertia 5.0 kg m2,is suddenly clamped together to the same shaft.
(a) Determine magnitude of angular momentum of the first disc.
(b) Determine the common angular speed of the combination of the two discs.
Answer:
Explanation:
Angular momentum p = Iw
I is the moment of inertia
w is the angular velocity
a) Angular momentum of the first disc
p1 = I1w1
Given
I1 = 1.5kg/m²
w1 = 800rev/min
Convert to rad/s
1 rev = 6.283rad
1 min = 60secs
800rev/min = 800(6.283)/60
= 83.77rad/s
p1 = 1.5×83.77
p1 = 125.66kgrad/s
Hence the magnitude of angular momentum of the first disc is 125.66kgrad/s
b) according to law of conservation of momentum
I1w1+I2w2 = (I1+I2)w
w is the common angular speed
Given
11w1 = 125.66
w2 = 0rad/s
I1 = 1.5kgm²
I2 = 5kgm²
Substitute
125.66+0 = (1.5+5)w
125.66 = 6.6w
w = 125.66/6.5
w = 19.33rad/s
Since 1rad/s = 9.549tev/min
19.33rad/s = 184.6rev/min
Hence the common angular speed of the combination of the two discs is 184.6rev/min