Need Help with Part C

Need Help With Part C

Answers

Answer 1

Answer:

  (a, b)  -2

  (c) -1, -1.5, -2, -2.5

Step-by-step explanation:

You want the average and instantaneous rates of change at various times in year 3, given the money in the bank after t years is 180+3t-t².

(a) Change

The amount at the beginning of year 3 is ...

  180 +3t -t² = 180 +t(3 -t)

  180 +2(3 -2) = 182 . . . . . . t=2

The amount at the end of year 3 is ...

  180 +3(3 -3) = 180 . . . . . . t=3

The amount increased by 180 -182 = -2 thousand dollars.

(b) Rate of change

This change occurred in one year, so the average rate of change is ...

  change/years = -2/1 = -2 thousand dollars per year

(c) Instantaneous rate

The derivative of the amount function will give its instantaneous rate of change:

  da/dt = 3 -2t

The values of t at the beginning of the quarters in year 3 are ...

  t = 2: da/dt = 3 -2·2 = -1 thousand per year at start of 1st quarter

  t = 2.25: da/dt = 3 -2(2.25) = -1.5 thousand per year at start of Q2

  t = 2.50: da/dt = 3 -2(2.50) = -2 thousand per year at start of Q3

  t = 2.75: da/dt = 3 -2(2.75) = -2.5 thousand per year at start of Q4

Need Help With Part C

Related Questions

In a group, there are 10 women, 8 blondes and 3 blonde women. How many people are either blonde or a woman?

Answers

Answer:

18. 10 women, 8 blondes. the 3 blonde women have already fallen into the previous categories.

A bicycle wheel is 63m in diameter. how many metres does the bicycle travel for 100 revolutions of the wheel. (pie=²²/⁷​

Answers

Answer:

19782m

Step-by-step explanation:

1  revolution = circumference

circumference = π * diameter

π = 3.1416

Then

circumference = 3.1416 * 63

= 197.92m

1 revolution = 197.82m

100 revolutions = 100*197.82m

= 19782m

Answer:

19.8 km

Step-by-step explanation:

To find:-

The distance travelled in 100 revolutions .

Answer:-

We are here given that,

diameter = 63m

We can first find the circumference of the wheel using the formula,

[tex]:\implies \sf C = 2\pi r \\[/tex]

Here radius will be 63/2 as radius is half of diameter. So on substituting the respective values, we have;

[tex]:\implies \sf C = 2\times \dfrac{22}{7}\times \dfrac{63}{2} \ m \\[/tex]

[tex]:\implies \sf C = 198\ m \\[/tex]

Now in one revolution , the cycle will cover a distance of 198m . So in 100 revolutions it will cover,

[tex]:\implies \sf Distance= 198(100)m\\[/tex]

[tex]:\implies \sf Distance = 19800 m \\[/tex]

[tex]:\implies \sf Distance = 19.8 \ km\\[/tex]

Hence the bicycle would cover 19.8 km in 100 revolutions.

write a verbal expression for each algebraic expression
9a2

Answers

Answer:

Step-by-step explanation:

Assuming you mean [tex]9a^2[/tex]:

   Multiply nine by a squared.

OR

   Times nine by a squared.

If you mean 9a^2:

Multiply nine by a number squared

or

Multiply a number squared by nine

Find x, if √x +2y^2 = 15 and √4x - 4y^2=6

Answers

Answer:

x = 52.2

Step-by-step explanation:

Add 4x - 4y^2 = 36 and x + 2y^2 = 225

x + 2y^2 + 4x - 4y^2 = 225 + 36

5x = 261

x = 261/5=52.2

The sum of the ages of father and son at present is 45 years. If both live on until the son's age becomes equal to the father's present age, the sum of their ages then will be 95 years. Find their present ages.

Answers

Answer:

father age 45 son age 0 this is answer

a water park sold 1679 tickets for total of 44,620 on a wa summer day..each adult tocket is $35 and each child ticket is $20. how many of each type of tixkwt were sold?

Answers

Answer: 811 adult tickets and 868 child tickets

Step-by-step explanation:

35x +20y = 44,620

add 35+20

divide the sum by 44,620 and

the answer

I need help with this

Answers

The angle congruent to angle FYE is angle EYD.

What is a bisector?

A line known as a bisector splits an angle or a line into two equally sized segments. A segment's midpoint is always contained in the segment's bisector. Based on the geometric shape that they bisect, there are two different sorts of bisectors. An angle is divided into equal angles by an angle bisector. The line segment is split into two equal halves by a line segment bisector. It travels through the line segment's centre.

Given that, YE bisects the angle FYD.

That is, the segment YE divides the angle FYD into two equal parts.

Thus, the angle congruent to angle FYE is angle EYD.

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What is the meaning of "field"?

Answers

This group is isomorphic to the group of invertible matrices GL(n) if the vector space has finite dimension n.

What is matrices?

Matrices are rectangular arrays of numbers or other mathematical objects, such as complex numbers, polynomials, or functions. Matrices are an important tool in many branches of mathematics, including linear algebra, calculus, and statistics. A matrix is usually written with square brackets enclosing its elements, with rows and columns separated by commas or spaces.

by the question.

Yes, you are correct! The set of all n x n matrices with entries in a field (such as the real numbers) is a group under addition, known as the general linear group GL(n), where the operation is matrix addition. This group satisfies the four group axioms:

Closure: The sum of two matrices is also a matrix.

Associativity: Matrix addition is associative.

Identity: The zero matrix is the identity element of GL(n).

Inverse: For every matrix A in GL(n), there exists a matrix -A such that A + (-A) = 0.

However, the set of all n x n matrices with entries in a field is not a group under multiplication because matrix multiplication is not always commutative and not every matrix has an inverse with respect to matrix multiplication.

On the other hand, the set of invertible n x n matrices, denoted by GL(n) or GL (n, F) when the field is specified, does form a group under matrix multiplication. The group axioms are satisfied:

Closure: The product of two invertible matrices is invertible.

Associativity: Matrix multiplication is associative.

Identity: The identity matrix I_n is the identity element of GL(n).

Inverse: For every invertible matrix A in GL(n), there exists an inverse matrix A^-1 such that A * A^-1 = I_n.

Similarly, the set of invertible linear transformations of a vector space into itself forms a group under composition of functions, known as the general linear group GL(V) of the vector space V.

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valuate the
expression
12 - 3y
2
+
√²v=4] for y = 3.
2y -

Answers

The result of the formula  [tex]12 - 3y2 + (v=4) / (2y - 2)[/tex] for y = 3 is  [tex]-29/2[/tex]  .

What are the ways to analyse an algebraic expression?

When [tex]y = 3[/tex] is used, the value of the expression [tex]12 - 3y2 + (v=4) / (2y - 2)[/tex]  has a value of  [tex]-29/2[/tex] .

To analyse an algebraic expression is to determine its value when a certain number is used in lieu of the variable. To evaluate the expression, we first replace the variable with the given number, then we use the order of operations to simplify the expression.

If  [tex]y = 3[/tex] , we can insert it into the expression & simplify as follows to evaluate   [tex]12 - 3y2 + (v=4) / (2y - 2)[/tex] for  [tex]y = 3[/tex]  .

[tex]12 - 3(3)^2 + (√4) / (2(3) - 2)[/tex] (y = 3 replacement)

[tex]12 - 27 + 2 / 4\s-15 + 1/2\s-29/2[/tex]

Therefore, The result of the formula  [tex]12 - 3y2 + (v=4) / (2y - 2)[/tex] for y = 3 is  [tex]-29/2[/tex]  .

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Shawn drinks 350 mL of milk every day. How many liters of milk does she drink in a week?

Answers

Answer:

The answer is 2.45 litres in one week.

Answer:

2.45 liters

Step-by-step explanation:

1 days - 350 ml of Milk

We know that, there are 7 days per week.

Therefore,

To find the milliliters of milk that she drinks in a week,

multiply milliliters of milk she drinks for a day by 7 ( number of days in a week).

Let us find it now.

350 ml × 7 = 2450 ml

And now to convert your answer into litres divide it by 1000.

2450ml ÷ 1000 = 2.45 liters

TERM 1 ASSIGNMENT GRADE 7 Question 3 3.1. Calculate the following WITHOUT using a calculator; 3.1.1 6234 ×32​

Answers

Answer: 6234 × 32 = 199488.

Step by step:

To calculate 6234 × 32 without using a calculator, you can use the traditional multiplication method as follows:

   6234

x    32

-------

  12468   (2 x 6234)

+ 62340   (3 x 6234 with a zero added)

--------

 199488

Find X using the picture below.

Answers

Answer: 37.5

Step-by-step explanation:

75 - 180 = 105

105 degrees = the obtuse angle, bottom triangle.

75/2= 37.5 (since both sides of the bottom triangle are equal angles)

Find the equation for the circle with a diameter whose endpoints are​ (3​,​1) and (-2,3)

Answers

Answer:

Step-by-step explanation:

The center of the circle is the midpoint of the diameter. To find the midpoint, we use the midpoint formula:

Midpoint = [(x1 + x2)/2, (y1 + y2)/2]

where (x1, y1) and (x2, y2) are the coordinates of the endpoints of the diameter.

Midpoint = [(3 + (-2))/2, (1 + 3)/2]

Midpoint = [1/2, 2]

So, the center of the circle is (1/2, 2).

The radius of the circle is half the length of the diameter. To find the length of the diameter, we use the distance formula:

Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

where (x1, y1) and (x2, y2) are the coordinates of the endpoints of the diameter.

Distance = sqrt((-2 - 3)^2 + (3 - 1)^2)

Distance = sqrt(25 + 4)

Distance = sqrt(29)

So, the length of the diameter is sqrt(29).

The radius of the circle is half of sqrt(29), which is sqrt(29)/2.

Therefore, the equation of the circle is:

(x - 1/2)^2 + (y - 2)^2 = (sqrt(29)/2)^2

Simplifying this equation, we get:

(x - 1/2)^2 + (y - 2)^2 = 29/4

So, the equation of the circle with a diameter whose endpoints are (3, 1) and (-2, 3) is (x - 1/2)^2 + (y - 2)^2 = 29/4.

five players are each dealt 2 cards without replacement. (a) what is the expected value of the sum of all 10 cards?

Answers

The expected value of a total of all 10 cards is 65.38 when the five players are dealt with 2 cards each without replacement.

The expected value of the sum of all 10 cards dealt without replacement can be calculated by multiplying the expected value of a single card by 10.

The expected value of a single card can be calculated by adding up all possible outcomes (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K) and dividing by the total number of cards in a deck (52).

= 52/13

This gives us an expected value of 6.5381.

Therefore, the expected value of the sum of all 10 cards is 65.38

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Complete question is:

Five players are each dealt 2 cards without replacement.

What is the expected value of the sum of all 10 cards?

question in what quadrant does the terminal ray of the angle lie? select quadrant i, quadrant ii, quadrant iii, or quadrant iv.

Answers

, [tex]\frac{-21 \pi}{8}[/tex] lies in 3rd quadrant, ,[tex]\frac{-5 \pi }{9}[/tex] lies in 3rd quadrant,t, [tex]\frac{5 \pi}{6}[/tex]  radian lies in 2nd quadrant and [tex]\frac{35 \pi}{4}[/tex] lies in 1st quadrant.

What is Trigonometry?

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

To determine the quadrant in which the angle -21π/8 lies

Convert, [tex]\frac{-21 \pi}{8}[/tex]  to number

-21×180/8

-472.5 degrees lies in which quadrant we have to check.

The value is negative

Quadrant IV =  0 to -90°

Quadrant III = -90° to -180°

Quadrant II  = -180° to -270°

Quadrant I   = -270° to -360°

-21π/8 lies in 3rd quadrant

-5π/9=-100 which lies in 3rd quadrant

5π/6=150 which is positive so it lies in 2nd quadrant

35π÷4=1575 which is positive so it lies in 1st quadrant

Hence, [tex]\frac{-21 \pi}{8}[/tex]  lies in 3rd quadrant,[tex]\frac{-5 \pi }{9}[/tex]lies in the 3rd quadrant, [tex]\frac{5 \pi}{6}[/tex] lies in 2nd quadrant and [tex]\frac{35 \pi}{4}[/tex] lies in  1st quadrant.

The complete question is-

In what quadrant does the terminal ray of the angle lie?

Select Quadrant I, Quadrant II, Quadrant ​III​, or Quadrant IV.

Angle measure Quadrant I Quadrant II Quadrant ​III​ Quadrant IV

−21π8

Quadrant , I – negative fraction numerator 21 pi over denominator 8 end fraction

Quadrant , I I – negative fraction numerator 21 pi over denominator 8 end fraction

Quadrant , ​, I I I, ​ – negative fraction numerator 21 pi over denominator 8 end fraction

Quadrant , I V – negative fraction numerator 21 pi over denominator 8 end fraction

−5π9

Quadrant , I – negative fraction numerator 5 pi over denominator 9 end fraction

Quadrant , I I – negative fraction numerator 5 pi over denominator 9 end fraction

Quadrant , ​, I I I, ​ – negative fraction numerator 5 pi over denominator 9 end fraction

Quadrant , I V – negative fraction numerator 5 pi over denominator 9 end fraction

5π6

Quadrant , I – fraction numerator 5 pi over denominator 6 end fraction

Quadrant , I I – fraction numerator 5 pi over denominator 6 end fraction

Quadrant , ​, I I I, ​ – fraction numerator 5 pi over denominator 6 end fraction

Quadrant , I V – fraction numerator 5 pi over denominator 6 end fraction

35π4

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Can someone please help me

Answers

The volume of the composite figure is 837.33 cubic units.

What is volume of a cone?

The area or capacity of a cone is determined by its volume. A cone's circular base tapers from a flat base to a point known as the apex or vertex in three dimensions. A cone is made up of a collection of line segments, half-lines, or lines that link the apex—the common point—to each point on the base, which is on a plane without the apex. A cone may be thought of as a collection of irregularly shaped circular discs placed on top of one another with the ratio of their radii remaining constant.

The volume of any composite figure is the addition of the volume of all the shapes present in the figure.

Here, the composite solid is made of 2 cones and a cylinder.

The volume of cone is:

V = 1/3(πr²h)

For cone with height 12 and r= 4:

V = 1/3(π)(4)²(12)

V = 200.96 cubic units.

For cone with h = 8 and r = 4:

V = 1/3(π)(4)²(8)

V = 133.97

The volume of cylinder is:

V = πr²h

V = (3.14)(4)²(10)

V = 502.4 cubic units.

The volume of the composite solid is:

Total volume = 200.96 + 133.97 + 502.4

Total volume = 837.33 cubic units.

Hence, the volume of the composite figure is 837.33 cubic units.

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A gardener has 100 meters of fencing to enclose two adjacent rectangular gardens, as shown in the figure. 4x + 3y = 100 (a) Write the area of the enclosed region as a function of x. 8 2 200 A(x) = + 3 -2 3 (b) Use a graphing utility to generate additional rows of the table. (Round your answers to one decimal place.) X y Area 2 92 3 30.7 368 3 122.7 4 28 224 6 25.3 > 304 8 22.7 362.7 10 | 20 400 12 17.3 416 14 || 14.7 410.7 Use the table to estimate the dimensions that will produce a maximum area. (Round your answers to one decimal place.) longer side 2x = 24 shorter side y = 173 m (c) Use the graphing utility to graph the area function. A(X) A(X) 400 400 300 300 200 200) 100 100 LUL X 5 10 15 20 25 o 5 10 15 20 25 A(X) A(X) 400 400) 300 300 200 200 100) 100 5 10 15 20 х 25 5 10 15 20 25 Use the graph to estimate the dimensions that will produce a maximum area. (Round your answers to one decimal place.) longer side 2x = 25 m shorter side y = 16.7 (d) Use the graph to approximate the dimensions such that the enclosed area is 336 square meters. (Round your answers to one decimal place.) Smaller value of x: longer side y = 23.3 m shorter side 2x = 15 X m Larger value of x: longer side 2x = 35 shorter side y = 10 m X m (e) Find the required dimensions of part (d) algebraically. (Round your answers to one decimal place.) Smaller value of x: longer side m shorter side 2x = 15 x m y = 23.3 Larger value of x: longer side 2x = 35 shorter side EE y = 10 x m

Answers

The area of enclosed region as a function of x is A(x) = 8x^2/3 + (200/3)x - 2x. Using a table, the estimated dimensions that produce maximum area are longer side x = 12 and shorter side y = 17.3 m. Using a graph, the estimated dimensions that produce maximum area are longer side 2x = 25 m and shorter side y = 16.7 m. The dimensions for an enclosed area of 336 square meters are smaller value of x: longer side y = 23.3 m, shorter side 2x = 15 x m and larger value of x: longer side 2x = 35 m, shorter side y = 10 x m.

The area of the enclosed region can be written as a function of x as follows.

A(x) = 2xy

Substituting y = (100 - 4x)/3, we get

A(x) = 2x(100 - 4x)/3 = (200x - 8x^2)/3 = 66.7x - 2.67x^2

Using a graphing utility, we can generate additional rows of the table as follows.

xy Area

2    92 368

3    122.7 367.1

4     128 512

5     116.7 583.3

6     100.7 604.2

7     80.0 560.0

8     65.3 522.7

9     56.0 504.0

10    51.3 513.0

11     51.0 561.0

12    54.7 656.7

13     62.0 806.2

14     72.7 1003.3

From the table, we can see that the maximum area occurs when x = 12 and y = 17.3.

The graph of the area function is shown.

From the graph, we can estimate that the dimensions that will produce a maximum area are x ≈ 12.5 and y ≈ 16.7.

From the graph, we can estimate that the smaller value of x for an area of 336 square meters is x ≈ 7.5 and the larger value of x is x ≈ 17.5. Substituting these values in the equation for y, we get:

For the smaller value of x:

y = (100 - 4(7.5))/3 ≈ 23.3

So, the required dimensions are longer side = 15 m and shorter side = 2(7.5) = 15 m.

For the larger value of x:

y = (100 - 4(17.5))/3 ≈ 10.0

So, the required dimensions are longer side = 2(17.5) = 35 m and shorter side = 10 m.

To find the required dimensions algebraically, we need to solve the equation A(x) = 336. We already have the expression for A(x) as:

A(x) = 8x(50 - 4x)

Substituting 336 for A(x), we get:

8x(50 - 4x) = 336

Dividing both sides by 8, we get:

x(50 - 4x) = 42

Expanding the left side, we get:

50x - 4x^2 = 42

Rearranging and simplifying, we get a quadratic equation:

4x^2 - 50x + 42 = 0

We can solve this quadratic equation using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 4, b = -50, and c = 42.

Substituting these values, we get:

x = (50 ± sqrt(50^2 - 4(4)(42))) / 2(4)

Simplifying, we get:

x = (50 ± sqrt(196)) / 8

x = (50 ± 14) / 8

So, the two possible values of x are:

x = 7 or x = 1.25

For x = 7, the corresponding dimensions are:

longer side 2x = 14 m

shorter side y = (50 - 4x) = 22 m

For x = 1.25, the corresponding dimensions are:

longer side 2x = 2.5 m

shorter side y = (50 - 4x) = 32.5 m

Therefore, the required dimensions for an enclosed area of 336 square meters are:

Smaller value of x: longer side 2x = 2.5 m, shorter side y = 32.5 m

Larger value of x: longer side 2x = 14 m, shorter side y = 22 m

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Find the measure of the angle A for the triangle shown!

Answers

Answer:

The value of A is 34 degrees angles on the right angle triangle are equal to 180 degrees

fine the exact value of sin(45-30)

Answers

Answer: 0.6502878402

Estimated answer: 0.650

3 g(n) = 80 . (-) 4 O Complete the recursive formula of g(n). g(1) = g(n) = g(n − 1). -​

Answers

Answer:

Based on the given information, we know that:

g(n) = 80 - 4g(n-1)

Also, we have the initial condition:

g(1) = g(n) = g(n-1)

Putting everything together, we can write the recursive formula for g(n) as follows:

g(1) = g(n) = g(n-1) (initial condition)

g(n) = 80 - 4g(n-1) (recursive formula)

where n > 1.

(please mark my answer as brainliest)

Mr. Ross had been classifying fuel costs as Delivery Expense but has found that the amount paid each month for gasoline has become a major expense. He has decided to use a separate account, Gasoline Expense. Also, a new account, Water Expense, is to be added to the chart of accounts. Account number _ should be assigned to Gasoline Expense, and account number _ should be assigned to Water Expense.

Answers

For Gasoline Expense, the account number may be something like 4540 (4 for expenses, 5 for operating expenses, and 40 for the specific account number). For Water Expense, the account number may be something like 4550 (4 for expenses, 5 for utility expenses, and 50 for the specific account number

How to assign account number?

To add new accounts to the chart of accounts, Mr. Ross should first determine the account type and the appropriate category. In this case, Gasoline Expense would be classified as an operating expense account, while Water Expense would be classified as a utility expense account.

Once the account types have been identified, Mr. Ross should then determine the account number for each account. The account numbering system may vary depending on the accounting system in use, but generally, account numbers are structured hierarchically based on the account category and type.

For example, if the account numbering system uses a four-digit code, the first digit may represent the account category (e.g., 1 for assets, 2 for liabilities, 3 for equity, 4 for revenues, and 5 for expenses), the second digit may represent the specific account type (e.g., 4 for operating expenses and 5 for utility expenses), and the last two digits may be assigned sequentially to each account within that category and type.

So, for Gasoline Expense, the account number may be something like 4540 (4 for expenses, 5 for operating expenses, and 40 for the specific account number). For Water Expense, the account number may be something like 4550 (4 for expenses, 5 for utility expenses, and 50 for the specific account number).

However, the specific account numbering system used may vary depending on the accounting system in use, so Mr. Ross should consult with his accountant or accounting software provider for guidance on how to properly create and assign account numbers in his specific system.

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Find the area of the surface obtained by rotating the curve about the x-axis. y = x^2/4 - ln x/2.

Answers

The area of the surface obtained by rotating the curve about the x-axis.

y = X²⁾⁴- ln x is 2.8.

The area of ​​a sphere is defined as the area covered by its outer surface in three-dimensional space. A sphere is a three-dimensional solid that is circular in shape, like a circle.

Based on the Question:

Knowing the area of ​​a solid obtained by rotating a curve governed by the function f(x) around the y-axis, where a ≤ x ≤ b, is represented by a single integral given below:

Surface Area = [tex]2\pi \int\limits^b_a {f(x)\sqrt{1+f(x')^2} } \, dx[/tex]

Consider the curve equation y(x) where 1 ≤ x ≤ 2 is shown below.

        [tex]y(x) = \frac{x^2}{4} -\frac{ln x}{2}[/tex]

Now,

Derivations the above equation:

   [tex]y'(x) =\frac{d}{dx} {\frac{x^2}{4} -\frac{ln x}{2} }[/tex]

⇒ [tex]y'(x)=\frac{x}{2} -\frac{1}{2x}[/tex]

⇒ [tex]y'(x) = \frac{x^2-1}{2x}[/tex]

Calculate the numerical value of the obtained area value to obtain the desired result.

Surface area = 5.30144 - 2.55493

                      = 2.74651 ≈ 2.8

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What is the height of the building shown below? Round to the nearest tenth if necessary.

62.9 feet
132 feet
123.5 feet
77.7 feet

Answers

Answer:

77.7

Step-by-step explanation:

if you know, you know. laso make sure your calculator is on degrees and not radians

100 POINTS + BRAINLIEST!!

Answers

Step-by-step explanation:

Mean is the average of all of the scores (26 of them)

  Mean =    (3x6 + 4x3 +5x1 + 6x2 + 7x0 + 8x5 +9x5 + 10x4) / 26 = 6.6

 Median is the score in the middle of all of the scores arranged in ascending order ( or the average of the middle two if there is an even number (26) of scores )

333333 444 5 66 88 888 99999 10 10 10 10       Median = 8

Mode is the score with the highest frequency  = 3  (there are 6 of them)

ii)  3/4 of the students would be   3/4 x 26 = 19.5 students ~ 20 students

      this would mean the average the teacher is talking about is '3'  (the 'mode')  since 20 students scored above '3'   ( 3+1+2 +0+5+5+4 = 20)

Answer:

ion kno but good luck

Step-by-step explanation:

Consider the following algebraic statements and determine the values of x for which each statement is true. On a number line, show the set of all points corresponding to the values of x.

4=|-2x|

Answers

Your question is incomplete. The complete question is: Consider the following algebraic statements and determine the values of x for which each statement is true. On a number line, show the set of all points corresponding to the values of x.

|x| = 7

4=|-2x|

The values of x for which each statement is true are:

|x| = 7: x = -7 or x = 7

4 = |-2x|: x = -2    or x = 2

How to determine the values of x for which each statement is true?

a) |x| = 7

-x = 7 or x = 7

x = -7 or x = 7

This statement is true for two values of x:

x = -7 and x = 7.

b) 4 = |-2x|

4 = -2x or 4 = 2x

x = -2    or x = 2

This statement is true for two values of x:

x = -2 and x = 2.

The number line is shown in the image attached.

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The toll T charged for driving on a certain stretch of a toll road is $5 except during rush hours (between 7 AM and 10 AM and between 4 PM and 7 PM) when the toll is $7.

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The toll calculation for driving on a certain stretch of a toll road is $5 except during rush hours when the toll is $7, depending on the time the driver uses the toll road.

To compute the toll for driving on the toll road during non-rush hours, simply add $5 to the total. During rush hour, however, the toll is $7.

To compute the toll for driving during rush hour, you must first determine when the driver intends to utilize the toll road. If the period is between 7 AM and 10 AM or 4 PM and 7 PM, the toll is $7.

For instance, if a vehicle expects to use the toll road at 8 a.m., the toll is $7. If the vehicle intends to use the toll road at 2 p.m., the toll is $5.

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QUESTION THREE (30 Marks) a) For a group of 100 Kiondo weavers of Kitui, the median and quartile earnings per week are KSHs. 88.6, 86.0 and 91.8 respectively. The earnings for the group range between KShs. 80-100. Ten per cent of the group earn under KSHs. 84 per week, 13 per cent earn KSHs 94 and over and 6 per cent KShs. 96 and over. i. Put these data into the form of a frequency distribution and obtain an estimate of the mean wage. 15 Marks​

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Answer:

the answer would be 100 I guess

A 5-year swap contract can be viewed as a portfolio of 5 forward contracts with maturities of 1, 2, 3, 4 and 5 years. One important exception is that Multiple Choice O the forward price is the same for the swap contract but not for the forward contracts. the swap contract will have daily resettlement the forward contracts will have resettlement risk.

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If a 5-year swap contract can be viewed as a portfolio of 5 forward contracts with maturities of 1, 2, 3, 4 and 5 years. One important exception is option (a) the forward price is the same for the swap contract but not for the forward contracts

In a swap contract, the fixed rate is agreed upon at the beginning of the contract, and the floating rate is determined by a reference rate such as LIBOR. The swap contract's value is based on the difference between the fixed and floating rates at each settlement date. In contrast, forward contracts involve an agreement to buy or sell an asset at a specified price on a specific future date. The forward price is determined at the time the contract is entered into and is based on the spot price of the underlying asset, the time to maturity of the contract, and the cost of carry.

Therefore, the forward price will be different for each forward contract in the swap portfolio, whereas the forward price for the swap contract will be the same throughout the contract's life. The other options mentioned are not true for swap or forward contracts.

Therefore, the correct option is (a) the forward price is the same for the swap contract but not for the forward contracts

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✪ Explain why Jack should keep the policies you placed in the "Policies to Keep" column.

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The policies listed in the "Policies to Keep" column are beneficial to Jack as they help to reduce the risk of fraud, financial loss, and mismanagement of resources. They also serve to ensure that the business is operating in a compliant and legal manner. Additionally, these policies can help to ensure that the organization is operating efficiently and in an ethical manner.

d. A quantity increases by 25% each year for 3 years. How much is the combined percentage growth p over the three-year period?

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When a quantity increases by 25%, the new quantity becomes 100% + 25% = 125% of the original quantity.

After the first year, the quantity has increased to 125% of its original value. After the second year, it increases an additional 25%, making the new value 125% + (25% of 125%) = 156.25% of the original value. Finally, after the third year, it increases by another 25%, making the new value 156.25% + (25% of 156.25%) = 195.3125% of the original value.

So the quantity has increased by 195.3125% - 100% = 95.3125% over the three-year period. Therefore, the combined percentage growth p over the three-year period is 95.3125%.

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