NEED ANSWER ASAP GIVING BRAINLIEST

Answer:

let's find the zeros of the divisor

x+2=0

x=-2

let x²-3x+2k =f(x)

Now f(-2)=(-2)²-3(-2)+2k=7

4+6+2k=7

2k=7-10

2k=-3

k=-3/2

jeez that looks really hard

Step-by-step explanation:

Answer:

-72

Step-by-step explanation:

-8×-9

=-72

hope it helps you..

Answer:

I think its 56 = 56

Step-by-step explanation:

Answer:

8 and 48

Step-by-step explanation:

This can be written as a system of equations. X will be the smaller number and y will be the larger:

6x = y

x + y = 56

Then substitute y in the second equation for 6x(seen in first equation) and solve.

x + 6x = 56

7x = 56

x = 8

So one number is 8. To find the other plug in 8 for x in either of the original equations (both get the same answer for y).

6x = y

6 * 8 = y

48 = y

Then double check by seeing if they fit the requirements of the problem.

Hope this helps!

Answer:

a). 6:51

b). 6:30 am

c). 34 minutes

Step-by-step explanation:

a). Train leaves Westchester at 6:30.

   From the arrival - departure table in column (2),

   Arrival time of the train at middlewich = 6:51

b). Kate has to reach Southam before 9:00 am

   Therefore, time of the latest train that she can catch to get to work on time is 6:30 am

    By this train she can reach at 07:19 at Southam.

c). Duration of journey from Westchester to Eastwick = 06:34 - 06:00

                                                                                        = 00:34

                                                                                        ≈ 34 minutes

9514 1404 393

Answer:

  y = 6^x -3

Step-by-step explanation:

The graph is that of an exponential function that has been translated downward. We notice the horizontal asymptote is -3, and a couple of points on the graph are (0, -2) and (1, 3).

The shifted parent function will look like ...

  y = a·b^x +c

where c is the horizontal asymptote. Using the two points we found, we have ...

  -2 = a·b^0 -3 . . . . . using (x, y) = (0, -2)

  1 = a . . . . . . . . . . add 3 and simplify

Then using (x, y) = (1, 3), we have ...

  3 = b^1 -3

  6 = b . . . . . . . . . add 3 and simplify

So, the equation is ...

  y = 6^x -3

Answer:

The equation of the line is, y = x

Step-by-step explanation:

The constraints of the required linear equation are;

The point through which the line passes = (2, 2)

The line to which the required line is parallel = y = x + 4

Two lines are parallel if they have the same slope, therefore, we have;

The slope of the line, y = x + 4 is m = 1

Therefore, the slope of the required line = 1

The equation of the required lime in point and slope form becomes;

y - 2 = 1 × (x - 2)

∴ y = x - 2 + 2 = x

The equation of the required line is therefore, y = x

Answer:

is 512

Step-by-step explanation:

Step-by-step explanation:

[tex] \frac{2}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } = \frac{2(2 - \sqrt{3} )}{1} = 4 - 2 \sqrt{3} [/tex]

Step-by-step explanation:

Given that,

The positions of the first particle,[tex]s_1=4t-t^2[/tex]

Velocity,

[tex]v_1=\dfrac{ds_1}{dt}\\\\v_1=\dfrac{d(4t-t^2)}{dt}\\\\v_1=4-2t[/tex]

Position,

[tex]s_2=5t^2-t^3[/tex]

[tex]v_2=\dfrac{ds_2}{dt}\\\\v_2=\dfrac{d(5t^2-t^3)}{dt}\\\\v_2=10t-3t^2[/tex]

Hence, this is the required solution.

Answer:

0.7

Step-by-step explanation:

.

Answer:  b) 0.7

Just copy that into mathswatch :>

Hi there!

[tex]\large\boxed{(3x - 2)(2x + 1) }[/tex]

6x² - x - 2

To solve, we must factor into the following format:

(ax - b)(cx - d)

The following conditions must be met:

a · c = 6

da + bd = -1

b · d = -2

By guessing and checking, we get:

(3x - 2)(2x + 1)

Answer for Acellus:

(2 x + 1) (3 x - 2)

Step-by-step explanation:

i checked the equation on an online calculator, and it came up with it switched (compared to the other answer that is posted) like so...

I put the answer in and it said it was right for Acellus.

Hope this helps :))

Answer:

15.87 %

Step-by-step explanation:

z = (.9-1)/.1 = -1

z score of -1 = .1587

The probability that a randomly selected small size package has a weight of less than 0.9 pounds is 15.87 %

We have given that,

A store sells ground meat in small, medium, and large sizes. The weights of the small size packages have a mean weight of 1 pound and a standard deviation of 0.1 pounds. If the distribution of weights for the small-size packages of ground meat is approximately normally distributed

[tex]Z = \frac{x - \mu}{\sigma}[/tex]

Z = standard score

x = observed value

[tex]\mu[/tex] = mean of the sample

[tex]\sigma[/tex] = standard deviation of the sample

z = (0.9-1)/0.1 = -1

z of -1 = 0.1587

Therefore the value of the z-score is 0.1587.

To learn more about the Z-score visit:

https://brainly.com/question/25638875

#SPJ2

Answer:

Dude

Answer: The b-value is the middle number, the number next to the X

Answer:

the answer is 2035.75 cm³

Step-by-step explanation:

comment if you want explanation

Answer:

Q.5

Step-by-step explanation:

(2x)^3+3×(2x)^2×3y+3×2x×(3y)^2+(3y)^3

8x^3+3×4x^2 × 3y + 3×2x×9y^2 + 27y^3

8x^3 + 36x^2 × y + 54xy^2 + 27y^3

Answer:

37500

Step-by-step explanation:

3% of 1250000

That is (3/100)*1250000

The answer is 37500

Answer:

214°

Step-by-step explanation:

The measure of an arc that sees the center angle of the circle is equal to the very same angle that it sees

Since the measure of circle is 360° and arc AB is given as 146° the measure of arc ACB should be 360 - 146 = 214°

Answer:

2/5

Step-by-step explanation:

18x+12x=-4+16

30x=12

x=2/5

Answer:

18x-16=-12x-4

18x+12x=-4+16

30x=12

x=12/30

x=2/5

Given:

Clicks = 50

Impressions = 5000

To find:

The CTR percentage.

Solution:

We know that,

[tex]CTR=\dfrac{\text{Clicks}}{\text{Impressions}}\times 100[/tex]

Substituting the given values, we get

[tex]CTR=\dfrac{50}{5000}\times 100[/tex]

[tex]CTR=\dfrac{1}{100}\times 100[/tex]

[tex]CTR=1\%[/tex]

Therefore, the correct option is A.

Point F

Point E

These lie in the second quadrant.

Answer:

1min = 0.25miles

5.25miles / 0.25miles = 25 = 25minutes

Step-by-step explanation:

Hope this is right I'm not the best at worded time/distance math questions.

9514 1404 393

Answer:

  0 ≤ t < 52.5 minutes

Step-by-step explanation:

Riko will be behind Yuto until her distance traveled matches his. That is, she will be behind for ...

  0.35t < 5.25 +0.25t

  0.10t < 5.25

  t < 52.5

Riko will be behind Yuto on the interval 0 ≤ t < 52.5 minutes.

_____

Additional comment

distance = speed × time

Here, time is measured from when Riko starts riding. In addition to the 5.25 miles that Yuto has already gone, his distance will be the product of his speed (0.25 mi/min) and the travel time (t min). Then Yuto's total distance is 5.25+0.25t miles. The speed×time product is also used to find Riko's distance traveled. In her case, it is 0.35t miles.

Answer:

m=16

Step-by-step explanation:

(6+6)/m=6/8

12/m=6/8

M=16

Answer:

16

Step-by-step explanation:

This triangle has been dialated; ILM is a dialated version of IJK. We know that dialations are by scale factors, and we also know the length of two corresponding sides.

IM is 6 m long, and IMK is 6+6 m long, so 12 m. So using simple ratios, we know the dialation factor from ILM to IJK is 2. The corresponding side for JK (m) is LM, which we know is 8 m. So side m is 16 because of the scale factor (2).

Maybe you thought we were solving for "m", as in a varriable all the sides are multiplied by, but I think that's just bad labeling. Hope this helps!

Given:

The matrix is:

[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

To show:

[tex](A^{-1})^{-1}=A[/tex]

Solution:

If a matrix is:

[tex]M=\begin{bmatrix}a&b\\c&d\end{bmatrix}[/tex]

Then,

[tex]M^{-1}=\dfrac{1}{ad-bc}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}[/tex]

We have,

[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

Using the above formula, we get

[tex]A^{-1}=\dfrac{1}{(\cos x)(\cos x)-(-\sin x)(\sin x)}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\dfrac{1}{1}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

Now, the inverse of [tex]A^{-1}[/tex] is:

[tex](A^{-1})^{-1}=\dfrac{1}{(\cos x)(\cos x)-(\sin x)(-\sin x)}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

[tex](A^{-1})^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

[tex](A^{-1})^{-1}=\dfrac{1}{1}A[/tex]

[tex](A^{-1})^{-1}=A[/tex]

Hence proved.

Answer:

yes

Step-by-step explanation:

y = 79x - -37

37 = 79(0) - - 37

37 = 0 - - 37

37 = 37

Answer:

Step-by-step explanation:

Given is the isosceles triangle as two sides marked equal.

The missing angles measure the same.

Since the sum of interior angles of a triangle is 180°, we have:

It is an isosceles triangle,

The marked 2 sides of triangle are equal.

Now we have to,

find the measure of indicated angle.

General formula,

→ Sum of all sides of triangle = 180°

Then the value of x is,

→ 2x + 40° = 180°

→ 2x = 140°

→ x = 140/2

→ x = 70°

Therefore, 70° is the value of x.

Given: Given that a citizen have 97 silver coins.

To find : Here we need to find that how many bronze coins would it take to equal this amount.

Solution: We know, 1 silver coin=10 bronze coin

So, 97 silver coin=10×97 bronze coin

=970 bronze coin

Therefore, 970 bronze coins would it take to equal this amount.

Answer:

Question 1: (C) Step 3

Question 2: (B) The 2nd graph from the left

Question 3: (A, B, D)

Question 4: (D) Subtract 1.1j from both sides

Question 5: (C) x <= 3

Question 6: (D) y = 10

Step-by-step explanation:

Question 1:

Step 3 is where Rahul added 1/4 to both sides. This is the only time he used the addition property of equality.

Question 2:

This questions requires you to have knowledge on how to graph lines.

g(x) = -1 is already graphed correctly on all of the answer choices, so we only have to focus on f(x) = -1/2x - 2.

The y-intercept for f(x) is -2, and only answers B & D have that intercept. However, only B has the correct slope of -1/2.

Question 3:

A is correct because they added 3/5x and x, which is still equal to the original equation.

B is correct because they multiplied all the terms to have a denominator of 30, then multiplied both sides by 30 to eliminate the fractions.

C is wrong because it's supposed to 30x, not just a regular x from the original equation.

D is correct because as you solve the equation for x, you end up adding 18x, 6x, and 30x, which is 54x. 24x + 30x in this answer choice also equals 54x.

E is wrong because they subtracted instead of adding the 6x.

Question 4:

All of the answer choices are wrong except for D because the other choices either use a wrong term (like 4j, which doesn't exist) or the wrong property of equality.

Question 5:

Use basic algebra to sovle the inequality:

2(4 + 2x) >= 5x + 5

(distribute 2 to the (4 + 2x))

8 + 4x >= 5x + 5

(subtract 5 from both sides)

3 + 4x >= 5x

(subtract 4x form both sides)

3 >= x

x <= 3

Question 6:

Use basic algebra to solve for y:

2.8y + 6 + 0.2y = 5y - 14

(subtract 6 from both sides)

2.8y + 0.2y = 5y -20

(add like terms)

3y = 5y - 20

(subtract 5y from both sides)

-2y = -20

(divide both sides by -2)

y = 10

Hope it helps (●'◡'●)