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A magnesium ribbon is cleaned to remove the protective layer of basic magnesium carbonate from its surface, so that it may readily combine with the oxygen in air (on heating).

Answer:

Magnesium gets covered with a layer of magnesium oxide when kept in air for a long time. This layer hinders the burning of magnesium. Hence, it is to be cleaned before burning.

Answer:

Explanation:

Indira point is the southern most point of India and is situated on great nicobar island in the nicobar island.

Answer:

Your Ans Is

(A) Indra point.

8g + 65g = 73g

24g + 38g = 62g

Answer:

1)Na + O2 = > 2NaO

8 g + 65 g = > 73g

2) 2H2 + O2 → 2H2O

24 g + 38g→ 62 g

An atom is neutral as it has the same number of electrons that of protons. So, if an atom has 32 protons i.e. the atomic number of it is 32, then it will have 32 electrons revolving the nucleus.

Answer:

0.302M

Explanation:

Molarity, which is the molar concentration of a solution can be calculated as follows:

Molarity = number of moles (n) ÷ volume (V)

According to this question, 19.5 grams of Be(OH)2 is dissolved in enough water to make a 1.5 L solution.

Using mole = mass/molar mass to calculate the number of moles in 19.5g of Be(OH)2

Molar mass of Be(OH)2 = 9 + (16 + 1)2

= 9 + (17)2

= 9 + 34

= 43g/mol

mole = 19.5/43

mole = 0.453moles

Molarity = n/V

Molarity = 0.453/1.5

Molarity = 0.302M

Answer:

2Na + 2H2O → 2NaOH + H2

Explanation:

This is the balanced equation of,

Sodium + water → sodium hydroxide + hydrogen

Answer:

The balanced equation would be:

3AgNO3+Al→3Ag+Al(NO3)3

Explanation:

Answer:

The chloroplasts form a spiral around the vacuole and have specialized bodies known as pyrenoids that store starch. The cell wall consists of an inner layer of cellulose and an outer layer of pectin, which is responsible for the slippery texture of the algae.

Explanation:

hope it is helpful to you

Answer:

Explanation:The equation for this is F = -GmM/R^2 where the minus sign says the force is attractive m is 10 kg, M is 20 kg and R is 5 meters. If you crunch the numbers you get an answer of:

Answer:

[tex]V=795.26L[/tex]

Explanation:

From the question we are told that:

Volume [tex]V=1dm^3=>1L[/tex]

Density [tex]\rho=70.8g/L[/tex]

Generally the equation for Density is mathematically given by

[tex]\rho =\frac{Mass}{Volume}[/tex]

Therefore

[tex]M=\rho*V[/tex]

[tex]M=70.8*1[/tex]

[tex]M=70.8g[/tex]

Since at STP

[tex]T=273K[/tex]

[tex]P=1atm[/tex]

[tex]Mass =70.8g[/tex]

Therefore

[tex]Moles\ of\ Hydrogen=\frac{Mass}{2g}[/tex]

[tex]Moles\ of\ Hydrogen=\frac{70.8}{2g}[/tex]

[tex]Moles\ of\ Hydrogen=35.4moles[/tex]

Generally the equation for Ideal gas is mathematically given by

[tex]PV=nRT[/tex]

Therefore

[tex]V=\frac{nRT}{P}[/tex]

[tex]V=\frac{35.4*0.0826*273}{1}[/tex]

[tex]V=795.3L[/tex]

Answer:

because they are high reactive to the air thats why we keep them in paroffin oil

Answer:

ΔH = -746.6kJ

Explanation:

Using Hess's law we can find the ΔH of a reaction from the sum of similar reactions. From the reactions:

1. 2CO(g) + O2(g) → 2CO2 ΔH = -566.0kJ

2. N2(g) + O2(g) → 2NO(g) ΔH = 180.6kJ

The negative reaction of 2:

-2. 2NO(g) → N2(g) + O2(g) ΔH = -180.6kJ

The sum of 1 - 2:

2CO(g) + O2(g) + 2NO(g) → 2CO2  N2(g) + O2(g) ΔH = -566.0kJ + (-180.6kJ) =

ΔH = -746.6kJ

Subtracting the molecules that don't change:

2CO(g) + 2NO(g) → 2CO2  + N2(g) ΔH = -746.6kJ

Answer:

a group of electrochemical cells that can be recharged

Answer:

Thus, the element containing the greatest number of atoms is 12 g He. Thus, the correct option is (4) 12 g He. Note: The number of atoms of a compound is Avogadro's number for 1 mole of compound. The number 6.022×1023 is known as Avogadro's number.

Explanation:

(4)✔️ 12 g He

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Answer:

120gram I think so this is the answer if the answer is correct plz mark me as brainliest.

Answer:

10 m

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 14 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

Next, we shall determine the energy. This can be obtained as follow:

Velocity (v) = 14 m/s

Kinetic Energy (KE) =?

KE = ½mv²

KE = ½ × m × 14²

KE = ½ × m × 196

KE = m × 98

Finally, we shall determine the height. This can be obtained as follow:

Kinetic energy (KE) = m × 98

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

Since the object is falling from a particular height,

Potential energy (PE) = kinetic energy (KE)

PE = mgh

KE = m × 98

m × 9.8 × h = m × 98

Divide both side by m × 9.8

h = m × 98 / m × 9.8

h = 10 m

Thus, the bottle was dropped from a height of 10 m

Answer:

D. Zn²⁺ + 2Ag → Zn + 2Ag⁺

Explanation:

On the reduction potential chart, we have that silver ion Ag⁺ is a stronger oxidizing agent than, zinc, Zn, which is a reducing reducing agent the compared to silver

Therefore, the redox reaction that will occur is that the zinc, Zn, will be oxidized to Zn²⁺ ion, while the silver, Ag²⁺ ion will be reduced to silver deposits Ag, therefore, the zinc will displace the silver in the solution containing silver and zinc ions because zinc is higher than silver in the reactivity series

The reduction potential Zn → Zn²⁺ + 2e⁻ = +0.76

The reduction potential for Ag⁺ + e⁻ → Ag = +0.8

Therefore, given that redox reactions are reversible, we get the following likely redux reaction;

Zn(s) + 2Ag⁺(aq) ⇄ 2Ag(s) + Zn²⁺(aq)

Therefore, from the given options;

Zn²⁺(aq) + 2Ag(s) → Zn(s) + 2Ag⁺(aq) is the reaction most likely to occur.

Answer:

I don't know I don't know about question but I can try to find it

Explanation:

I don't know about question but I can try to find it

Answer:

C.faste-moving lava flows and explosion of cinder

Answer:

Todas son correctas

Explanation:

I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc. VERDADERO. La mayoría de los compuestos de carbono son apolares, y basados en la regla: Similar disuelve similar, podemos presumir que la mayoría de compuestos de carbono se disuelven en solventes no polares.

II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos. VERDADERO. Al ser sustancias apolares, sus fuerzas electrostáticas son bajas. De la misma manera, como su masa atómica es pequeña, las fuerzas de Van der Waals son despreciables haciendo que sus puntos de fusión y ebullición sean bajos respecto a sustancias de estrucutra similar.

III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos. VERDADERO. Los gases (Como el gas natural) son combustibles usados para cocina. Los líquidos (Como la gasolina) son combustibles y bastante inflamables. Los sólidos (Como la madera) se usan como combustibles para hacer asados o son el combustible en incendios forestales.

IV) El enlace covalente es característico de los compuestos del carbono. VERDADERO. La polaridad del carbono es neutral haciendo que la mayoría de los enlaces que forma sean covalentes.

Answer:

Unicellular organisms consist of only one cell and multicellular organisms consist of many cell.

Explanation:

Living things made up of a cell are called unicellular beings. They are very small and simple. In other words, unicellular organisms are those that are formed only by a single cell in which all the vital functions necessary for life are produced. For this reason, they are mostly microscopic organisms. Examples of unicellular organisms are viruses or bacteria.

Multicellular organisms are made up of a large number of cells. They present, therefore, a greater complexity than unicellular organisms in terms of the functions they develop. All current multicellular organisms come from a single cell, that is, they begin their life being unicellular. That is, they are formed from a zygote. Some examples of multicellular organisms are mammals, fungi, and mosses.

So, unicellular organisms consist of only one cell and multicellular organisms consist of many cell.

Answer:

NO. 10.

performed experiments

NO. 11.

Inference

Explanation:

No 10.

in order to prove that Mary Mellon was in fact infected by typhoid proper experiments needs to be carried out.

No. 11

inference means an assumption due to the situation.

Answer:

6.40 is the answer to your question

The number of moles of oxygen in 1.60 moles of sodium hydrogen phosphate is 6.4 moles

Let's represent the chemical formula of the compound. The chemical formula of sodium hydrogen phosphate is as follows:

The chemical formula of a compound is a symbolic expression use to signify the number of atoms present in a molecular substance. Therefore,

sodium hydrogen phosphate  = Na₃PO₄

Therefore,

1 mole of Na₃PO₄ = 4 moles of oxygen

1.60 moles of Na₃PO₄  = ? moles of oxygen

cross multiply

number of moles of oxygen = 1.60 × 4

number of moles of oxygen = 6.4 moles

learn more on moles here: https://brainly.com/question/18395277

Answer: 4.93

Explanation:

Answer:

51.6058

Explanation:

The percentage of abundance is changed to decimal by dividing 100

Fluorine (F) and iodine(I) are the halogen elements that belong to group 17. They differ from each other as fluorine has 3 fewer energy shells than iodine. Thus, option D is correct.

Halogen is a nonmetallic element that belongs to group 17 and consists of six elements namely fluorine, bromine, tennessine, chlorine, astatine, and iodine.

They are diatomic and have 7 valence electrons in the outer shell, which makes them highly reactive and electronegative. The shielding effect is less in F than I due to the closer placement and attraction of the valence electron to the nucleus.

Fluorine differs from iodine as it has a smaller size with fewer energy shells than iodine. Iodine has five energy shells,  whereas fluorine has two energy shells that make the difference of three shells between them.

Therefore, F and I differ from each other.

Learn more about fluorine and iodine here:

https://brainly.com/question/2005537

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Answer:

1) The percentage of oxygen in dry air is _______

C. 21

2) The composition of the Earth’s earliest atmosphere was different to that of the present atmosphere. Which of these gases was present in large amounts in the Earth’s earliest atmosphere?

B. CARBON DIOXIDE

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Answer: The percentage of oxygen in dry air is .  21

Explanation:  Ammonia gases was present in large amounts  in the easth7s earliest atmosphere

Hope it will help you