Answer:
mass (gram), volume (litre) and length (metre)
Explanation:
Matter is usually defined as anything that has mass and can occupy space. Matter exists primarily in three forms; solid, liquid or as a gas. Some of the properties of matter and there corresponding metric units are listed below
Properties ⇒ Metric unit
Mass ⇒ gram
Volume ⇒ litre
length ⇒ metre
If 12.8 g lead(II) sulfate (303.3 g/mol) precipitates when excess potassium chloride is added to 1.65 L of a water sample, what is molar concentration of Pb2+ in the sample?
Answer:
[tex]M=0.0256M[/tex]
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
[tex]PbSO_4(aq)+2KCl(aq)\rightarrow PbCl_2(s)+K_2SO_4(aq)[/tex]
In such a way, since all the lead (II) is converted due to the excess of potassium chloride, the moles of lead (II) in the sample are computed from the mass of lead (II) sulfate:
[tex]n_{Pb^{2+}}=12.8gPbSO_4*\frac{1molPbSO_4}{303.3gPbSO_4} *\frac{1molPb^{2+}}{1molPbSO_4} \\\\n_{Pb^{2+}}=0.0422molPb^{2+}[/tex]
Thus, since volume of the solution is 1.65 due to the fact that the addition of the reactants is not enough to significantly modify the reaction's volume, the resulting molar concentration of the lead (II) ions is:
[tex]M=\frac{n_{Pb^{2+}}}{V}=\frac{0.0422molPb^{2+}}{1.65L}\\ \\M=0.0256M[/tex]
Regards.
Calculate the pH of a buffer solution that contains 0.25 M benzoic acid (C 6H 5CO 2H) and 0.15M sodium benzoate (C
Answer:
[tex]pH=3.97[/tex]
Explanation:
Hello,
In this case, for the calculation of the pH of the given buffer we need to use the Henderson-Hasselbach equation:
[tex]pH=pKa+log(\frac{[base]}{[acid]} )[/tex]
Whereas the pKa for benzoic acid is 4.19, the concentration of the base is 0.15 M (sodium benzoate) and the concentration of the acid is 0.25 M (benzoic acid), therefore, the pH turns out:
[tex]pH=4.19+log(\frac{0.15M}{0.25M} )\\\\pH=3.97[/tex]
Regards.
The term electron capture best fits which of the following descriptions?
A. Electron capture is a phenomenon exhibited by an unstable nucleon that spontaneously converts into a more stable nuclei.
B. Electron capture is the combination of a core electron with a proton to yield a neutron within the nucleus.
C. Electron capture is the addition of an electron to a neutral atom to form an anion.
D. None of the above.
Answer:
Option B:
Electron capture is the combination of a core electron with a proton to yield a neutron within the nucleus.
Explanation:
The electron capture is a nuclear process whereby a neutral atom absorbs an electron from its closest shell (which is usually the K shell of the atom).
This capture phenomenon, causes one of the protons within the nucleus of the atom to convert into a neutron because of the merging of the positive and negative charges. Once they merge, a light particle called the electron neutrino is emitted from the nucleus of the atom.
This phenomenon occurs mostly in atoms that have a proton-rich nucleus. This provides the positive charge that pulls the electron from its shell into the nucleus of the atom.
10g = __________ mg? *
Answer:
Explanation:
as we know that
1g =1000mg
so
10g=10*1000
10g=10000
A compound has an M-/M-2 ratio of 75:25. Which of the following could be the molecular formula of this compound? a) CH2Br2 b) CH2Cl2 c) CHCI d) CH:Bre) CHF
Answer:
c) CH₃Cl
Explanation:
Due the relative abundance of chlorine and bromine. It is possible to determine which of the halogens is present in a mass spectrum of a organic compound:
The Cl-35, Cl-37 have a relative abundance of 75/25; Br-79 and Br-81 of 50/50.
For that reason, if a compound has a M/M+2 ratio of 75:25 you can be sure the compound has 1 Cl in its structure. Thus, the only possible structure is:
c) CH₃ClIn general, which of the following gases would you expect to behave the most ideally even under extreme conditions? View Available Hint(s) In general, which of the following gases would you expect to behave the most ideally even under extreme conditions? N2 CO H2
Answer:
The correct option is H₂
Explanation:
An ideal gas is the gas that obeys the gas laws perfectly. There molecules occupy little/negligible space with no interaction. Since they occupy negligible space, it can be said that the smaller the molecule of a gas, the more it behaves like an ideal gas. There size also accounts for there weak intermolecular force between it's molecules.
From the explanation above, H₂ has the smallest molecule and hence will behave the most like an ideal gas.
The gases that one would expect to behave the most ideally even under extreme conditions is H2.
An ideal gas is commonly described to as gases that are present i gas molecules that do not encounter any kind of interaction with the neighboring molecules.H2 is simply known as a molecule of hydrogen that has two hydrogen atoms which are bonded to each other by covalent bond.
Due to the fact that the hydrogen atom has a smaller size and lesser electronegativity the hydrogen molecule is thus regarded to be the least polar.
N2 is known to have greater polarizability than hydrogen molecule and thus cannot be the answer.
Note that for a gas to behave ideally, the attractive and repulsive intermolecular forces need to be negligible. When looking at the three molecules
H2,N2,CO, the molecule which is most polar will behave least ideally.
Therefore, hydrogen molecule will have the least intermolecular forces and will be most ideal.
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A) For the following reaction, K > 1. Classify each of the reactants and products based on their strength as Bronsted-Lowry acids or bases.
C9H7N + HNO2Doublearrow.GIFC9H7NH+ + NO2-
a) HNO2 1) stronger acid
b) NO2- 2) weaker acid
c) C9H7NH+ 3) stronger base
d) C9H7N 4) weaker base
B)
For the following reaction, K < 1. Classify each of the reactants and products based on their strength as Bronsted-Lowry acids or bases.
C5H11NH+ + C6H5COO-Doublearrow.GIFC5H11N + C6H5COOH
a) C5H11NH+ 1) strongest acid
b) C6H5COO- 2) stongest base
c) C5H11N 3) weakest acid
d) C6H5COOH 4) weakest base
Answer:
Explanation:
According to Bronsted-Lowry acids or base theory , the reagent capable of giving hydrogen ion or proton will be acid and that which accepts hydrogen ion or proton will be base .
C₉H₇N + HNO₂ ⇄ C₉H₇NH⁺ + NO₂⁻
If K > 1 , reaction is proceeding from left to right .
Hence HNO₂ is giving H⁺ or proton and C₉H₇N is accepting proton to form
C₉H₇NH⁺ .
Hence HNO₂ is bronsted acid and C₉H₇N is bronsted base .
B )
when K < 1 , reaction above proceeds from right to left . That means
C₉H₇NH⁺ is giving H⁺ so it is a bronsted acid and NO₂⁻ is accepting H⁺ so it is a bronsted base .
Hence , NO₂⁻ is a bronsted base and C₉H₇NH⁺ is a bronsted acid .
If you spill a chemical on a balance and continue to weigh, do you think it will affect your reading
Answer:
It shouldn't, but it might there is a chance. Liquid doesn't really weigh that much but it still can add slight weight.
Explanation:
The chemical could maybe make the balancer move a bit. But not a lot.
3. A balloon is filled with a mystery fluid that has a mass of 1000 kg and a volume of
of |
500 mL.
A. What is the density of the fluid?
B. Will the balloon sink or float in water?
(Helpppp ppls)
limitations of bohr
Answer:
Bohr's Atomic model
Explanation:
The limitations of Bohr’s model are Bohr’s model of an atom that could not explain the line spectra of atoms containing more than one electron called multi-electron atoms.
Which species functions as the oxidizing agent in the following reduction-oxidation reaction?
Which one the reducing agent?
Which one is oxidized?
Which one is reduced?
Which one loses electrons?
Which one gains electrons?
Zn(s) + Cu2+(aq) ? Cu(s) + Zn2+(aq).
Answer:
See explanation
Explanation:
In this case, we can start with the half-reactions. If the total reaction is:
[tex]Zn_(_s_)~+~Cu^2^+~_(_a_q_)~->~Cu_(_s_)~+~Zn^2^+_(_a_q_)[/tex]
If we split the reaction we will have:
Half-reaction 1:
[tex]Zn_(_s_)~->~Zn^2^+_(_a_q_)[/tex]
Half-reaction 2:
[tex]Cu^2^+~_(_a_q_)~->~Cu_(_s_)[/tex]
Now we can add the electrons, keeping in mind that we have to obtain zero charge in both sides of each half-reaction:
Half-reaction 1:
[tex]Zn_(_s_)~->~Zn^2^+_(_a_q_)~+~2e^-[/tex]
Half-reaction 2:
[tex]Cu^2^+~_(_a_q_)~+~2e^-~->~Cu_(_s_)[/tex]
With this in mind, we can solve the questions:
Which one loses electrons?
In half-reaction number 1 we have the electrons in the products side, therefore this half-reaction is the one that loses electrons.
Which one gains electrons
In half-reaction number 2 we have the electrons in the reagent side, therefore this half-reaction is the one that gains electrons.
Which one is oxidized?
If half-reaction number 1 loses electrons will be the oxidation reaction.
Which one is reduced?
If half-reaction number 2 gains electrons will be the reduction reaction.
Which species functions as the oxidizing agent in the following reduction-oxidation reaction?
If half-reaction number 2 is the reduction will be a oxidizing agent.
Which one the reducing agent?
If half-reaction number 1 is the oxidation will be a reducing agent.
I hope it helps!
Identify the major factor affecting reaction rates that accounts for the following observations:
a. Tadpoles grow more rapidly near the cooling water discharged from a power plant. 尤mpeca
b. Enzymes facilitate certain biochemical reactions but are not onsumed
c. Hydrogen peroxide antiseptic rapidly decomposes when applied to an open wound.
Answer:
a. Tadpoles possess the tendency to grow more rapidly close to the cooling water released from the power plant as the temperature is greater in these waters, permitting them to acquire more nutrients. Thus, in the given case, the factor is the temperature of the system.
b. In the given case, the factor is the catalyst, and in the given case enzymes are the biological catalyst. An enzyme increases the rate of the reaction as they lower the activation energy.
c. In the given case, the factor is the enzyme, as the blood comprises an enzyme, peroxidase, which catalyzes the decomposition of hydrogen peroxide.
The carbon atoms in saturated hydrocarbons ________. Group of answer choices contain a benzene ring contain at least one double bond contain both a double and a triple bond have only single bonds contain at least one double bond
Answer:
Have only single bonds.
Explanation:
Hello,
In this case, we need to remember that saturation is a state at which a carbon chain contains no insaturations, that is neither double nor triple bonds such case are alkenes and alkynes, but saturations only which are characterized by the presence of single bonds between adjacent carbon atoms. Such is the case of ethane (CH₃-CH₃), propane (CH₃-CH₂-CH₃), butane (CH₃-CH₂-CH₂-CH₃) and so on.
Best regards.
The value of ΔG° (kJ/mol) at 25°C for the formation of phosphorous trichloride from its constituent elements: Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) A) –59.2 B) +59.2 C) –642 D) +75.6 E) –373 F) –29.4
Answer:
F. [tex]\mathsf{\Delta G^0 \simeq -29.4 \ kJ}[/tex]
Explanation:
GIven that:
The chemical equation for the reaction is:
[tex]\mathtt{Fe_2O_{3(s)} + 3CO_{(g)} \to 2Fe _{(s)} + 3CO_{2(g)}}[/tex]
The value of the ΔG° (kJ/mol) at 25 °C
[tex]\Delta G^0 = \begin {pmatrix} 2( \Delta G_f^0 \ Fe_{(s)} )+ 3 ( \Delta G_f^0 \ CO_{2(g)} ) - 1 ( \Delta G_f^0 \ Fe_2CO_3_{(s)} + 3 ( ( \Delta G_f^0 \ CO _{(g)} ) \end {pmatrix}[/tex]
where;
[tex]\Delta G_f^0 \ Fe_{(s)} = 0[/tex]
[tex]\Delta G_f^0 \ CO_{2(g)} = -394.359 \ kJ/mole[/tex]
[tex]\Delta G_f^0 \ Fe_2CO_3_{(s)} = -742.2 \ kJ/mole[/tex]
[tex]\Delta G_f^0 \ CO _{(g)}= -137.168\ kJ/mole[/tex]
Replacing the values ; we have
[tex]\Delta G^0 = \begin {pmatrix} 2(0 )+ 3 ( -394.359 ) ) -( 1 (-742.2) + 3 (-137.168 ) \end {pmatrix}[/tex]
[tex]\Delta G^0 = \begin {pmatrix} 0 -1183.077 ) -(-742.2- 411.504 \end {pmatrix}[/tex]
[tex]\Delta G^0 = \begin {pmatrix} -1183.077 +742.2+ 411.504 \end {pmatrix}[/tex]
[tex]\mathtt{\Delta G^0 = -29.373 \ kJ}[/tex]
[tex]\mathsf{\Delta G^0 \simeq -29.4 \ kJ}[/tex]
Which of the following is a characteristic of a good roasting pan?
Answer:
i can't understand the question
On the basis of intermolecular forces of attraction, rank the following three compounds in terms of increasing boiling point.
CH3CH2OH
CH3OCH3
CH3CH2CH3
a. (lowest bp) CH3CH2CH3 < CH3OCH3 < CH3CH2OH (highest bp)
b. (lowest bp) CH3CH2OH < CH3OCH3 < CH3CH2CH3 (highest bp)
c. (lowest bp) CH3OCH3 < CH3CH2OH < CH3CH2CH3 (highest bp)
d. (lowest bp) CH3CH2OH < CH3CH2CH3 < CH3OCH3 (highest bp)
e. (lowest bp) CH3CH2CH3 < CH3CH2OH < CH3OCH3 (highest bp)
Answer:
a. (lowest bp) CH3CH2CH3 < CH3OCH3 < CH3CH2OH (highest bp
Explanation:
CH3CH2OH is an alkanol. The intermolecular forces present within the molecules include dispersion forces, dipole-dipole attraction as well as hydrogen bonding which is the major intermolecular force of attraction present.
CH3OCH3 is an ether. The intermolecular forces present within the molecules are dispersion forces and dipole-dipole attraction.
CH3CH2CH3 is an alkane. The only intermolecular forces present is dispersion forces.
The order of increasing strength of these intermolecular forces is dispersion forces ,dipole-dipole forces<hydrogen bonding, the alkanol has the highest bioling point, followed by the ether and then the alkane with the lowest boiling point.
The ranking of the compounds in terms of increasing the boiling point is option a.
What is ethanol?Ethanol i.e. (CH3-CH2-O-H) has three types of intermolecular interactions i.e. weak van der Waals interaction, dipole-dipole interaction, and strong intermolecular H-bonding interaction.
While on the other hand, in dimethyl ether (CH3-O-CH3) have two types of interactions - weak van der Waals interaction, and dipole-dipole interaction.
In propane (CH3-CH2-CH3) has only weak van der Waals interaction.
So ethanol needed more energy to overcome this these interactions for the conversion to a liquid state to the gaseous state.
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Radioactive manganese-52 decays with a half-life of 5.6 days. A chemist obtains a fresh sample of manganese-52 and measures its radioactivity. She then determines that to do an experiment, the radioactivity cannot fall below 25% of the initial measured value. How long does she have to perform the experiment?
Answer: 11.2 days
Explanation:
Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]
[tex]k=\frac{0.693}{5.6days}=0.124days^{-1}[/tex]
b) for completion of 75% of reaction
[tex]t=\frac{2.303}{0.124}\log\frac{100}{100-75}[/tex]
[tex]t=\frac{2.303}{0.124}\log\frac{100}{25}[/tex]
[tex]t=11.2days[/tex]
The time for which she has to perform the experiment is 11.2 days
A solution is made by dissolving
3.60g of sodium chloride to a final
volume of 115mL solution.
What is the weight/volume % of the
solute?
Answer:
3.13%
Explanation:
Step 1: Given data
Mass of sodium chloride (solute): 3.60 g
Volume of solution: 115 mL
Step 2: Calculate the weight/volume % of the solute
We will use the following expression.
%w/v = mass of solute / milliliters of solution × 100%
%w/v = 3.60 g / 115 mL × 100%
%w/v = 3.13%
The weight/volume % of the solute is 3.13%
Answer:
3.13
Explanation:
correct
If 28.0% of a sample of gallium-66 decays in 4.46 hours, what is the half-life of this isotope (in hours)?
Answer:
I hope it will work dear,
Explanation:
by simple mathematical rule,
if 28%=4.46 hrthen we know at half life 50% decay occur hence we get
2. 50% = T 1/2
solving the 2 equations by cross multiplication we will get,
T 1/2= 7.96 hr
THANKS FOR ASKING QUESTION:
A match is lit and held under a cold piece of metal. The following observation are made.A) the match burnsB) the metal gets warmerC) water condenses on the metalD) soot (carbon) is deposited on the metal.Which of these occurrences are due to physical changes and which are due chemical changes?
Answer:
A - chemical changes
B - Physical changes
C - Chemical changes
D - Chemical changes
Explanation:
First and foremost, a chemical change is an irreversible change in the chemical properties of a substance leading to the formation of a new substance or substances while a physical change is a reversible change to the properties of a substance.
The burning of a match stick is an irreversible process involving the reaction of the various component of the match head (potassium chlorate, sulfur, glass powder) with that of the side of the box holding the match (phosphorus, binder, glass powder). Hence, it is considered a chemical reaction.
Warming of the metal is a reversible process and hence, a physical reaction. Warming involves a rise in temperature due to the heating. Once the heat source is removed and the metal allowed to stay for a while, its temperature will return back to the original temperature.
Water condensation and deposition of soot on the metal can be considered a chemical reaction. A reaction that leads to the formation of, at least, one new product is definitely a chemical reaction.
How many grams (of mass m) of glucose are in 255 mL of a 5.50% (m/v) glucose solution?
Answer:
14.0 g
Explanation:
Step 1: Given data
Volume of solution (%w/v): 255 mL
Weight/volume % of glucose (solute): 5.50% (m/v)
Step 2: Calculate the mass of glucose
We can calculate the mass of glucose using the following expression.
%w/v = mass of glucose / milliters of solution × 100%
mass of glucose = %w/v × milliters of solution / 100%
mass of glucose = 5.50% (m/v) × 255 mL / 100%
mass of glucose = 14.0 g
A student in a chemistry lab is conducting an experiment using chemicals. Several violations were observed by the instructor. Which of the following methods below would best prevent a contamination of chemicals in the eyes?
Answer:
I would suggest wearing safety glasses as it minimizes the chance of harmful chemicals entering the eyes
Explanation:
Why does hot air rise and cold air sink?
A. Cold air has more kinetic energy than hot air.
B. Hot air has more potential energy than cold air.
C. Cold air is more dense than hot air.
D. Hot air is more dense than cold air.
Answer: C. Cold air is more dense than hot air.
Explanation: Took the test on edmentum
Light energy from the sun is converted by plants into
A electricity
B mechanical energy
C leaves
D chemical energy
How many atom are in 5fes2, 6c2h4o2 and 2cah2po42
Answer:
83 atoms
Explanation:
5*(1 fe + 2 S) + 6(2 C + 4H + 2O) + 2*2(1 Ca + 2 H + 1 P + 4 O) = 15 + 36 + 32 = 83 atoms
The 488 nm laser is shine on a lithium metal whose work function is 2.9 eV will you be able to see any photoelectrons? if yes what is the kinetic energy of the electrons if no what wavelength of light should be used to see the photoelectrons
Answer:
There will not be any ejection of photoelectrons
Explanation:
Energy of the photon= hc/λ
Where;
h= Plank's constant
c= speed of light
λ= wavelength of the incident photon
E= 6.6×10^-34 × 3 ×10^8/488 × 10^-9
E= 4.1 ×10^-19 J
Work function of the metal (Wo)= 2.9 eV × 1.6 × 10^-19 = 4.64 × 10^-19 J
There can only be ejected photoelectrons when E>Wo but in this case, E<Wo hence there will not be any ejection of photoelectrons.
For a concentration cell, the standard cell potential is always:________.
a. positive
b. negative
c. zero
d. need more information
Answer:
C. Zero
Explanation:
A concentration cell is defined as a type of galvanic cell which has two equivalent half-cells of the same constituent in the electrodes but different concentration in the electrolytes.
For a concentration cell, the standard cell potential is always Zero and the cell potential is usually measured with the use of the Nernst equation.
The MSDS for benzene indicates that it is a clear liquid that has a substantial vapor pressure. It has a health rating of 2, a fire rating of 3, and a reactivity rating of 0. It is a cancer-causing agent. Based on this information, which statement about benzene is accurate?
Answer:
Benzene must be kept away from flames.
Explanation:
Edguenuity 2020
The most accurate statement about Benzene is : Keep Benzene away from flames.
Although your question is incomplete a general answer is provided based on the MSDS provided in the question
Benzene is a colorless gas that exhibits a high level of flammability, it also has a sweet odor just like gasoline, it is a cancer-causing agent when humans are exposed to it for too long. based on its flammability it is advisable to keep flammable materials and flammable sources ( flames ) away from Benzene. and to also reduce the rate of human exposure to benzene as well.
Therefore we can conclude that based on the MSDS provided in the question the most accurate statement about benzene is Benzene should be kept away from flames.
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When a 235 92U 92235U nucleus is bombarded by neutrons (10n01n) it undergoes a fission reaction, resulting in the formation of two new nuclei and neutrons. The following equation is an example of one such fission process: 235 92U+10n→AZBa+9436Kr+310n 92235U+01n→ZABa+3694Kr+301n Enter the isotope symbol for the barium (BaBa) nucleus in this reaction. Express your answer as an isotope.
Answer:
139/56 Ba
Explanation:
In writing nuclear equations, there must be a balance of the mass and charge on both sides of the reaction equation. That is, the sum of masses on the lefthand side of the nuclear reaction equation must equal the sum of masses on the righthand side of the nuclear reaction equation. Similarly, the charges on the lefthand side of the nuclear reaction equation must equal the sum of the charges on the right hand side of the nuclear reaction equation.
Hence, the isotope of barium formed in the equation mentioned in the question is 139/56 Ba.
What do viceroy butterflies use to look like poisonous Monarch butterflies?
They use something called Mullerian mimic so they will be protected from predators
Explanation: