Chemistry High School

Name the type of reaction shown:2C4H10+13O2=8CO2+10H2O

Answers

Answer 1

Answer: It is AN combustion

reaction.

Explanation:

Related Questions

calculating kinetic energy 1200kg car moving at 10​

Answers

Answer:

60000J

Explanation:

Given parameters:

Mass of car  = 1200kg

Speed  = 10m/s

Unknown:

Kinetic energy  = ?

Solution:

The kinetic energy is given as:

   Kinetic energy  = [tex]\frac{1}{2}[/tex]  m v²  

Now insert the parameters and solve;

   m is the mass

    v is the velocity  

 Kinetic energy  =  [tex]\frac{1}{2}[/tex] x 1200 x 10²   = 60000J

When KOH dissolved in ethanol, what is the intermolecular
attraction between OH ions and C2H5OH molecules?

a. Dipole-dipole
b. ionic attraction
c. London dispersion forces
d. lon-dipole
e. Covalent bonds

Answers

Answer: d. Ion-dipole

Explanation:

I NEED HELPPPP

Samantha can do 6 back handsprings in 18 seconds. How many back handsprings can she do per second?

Answers

Answer:

3 Handsprings

Explanation:

18 divided by 6 is 3

A stone weighs 105 lb in air. When submerged in water, it weighs 67.0 lb. Find the volume and specific gravity of the stone.

Answers

Don’t knowwwwwwwwwww?

Explain what happens as a puddle dries after a rainstorm.

Answers

After a Rainstorm the puddle than starts to evaporate. Going into the air as the water vapor turns from liquid to gas as they begin to form a cloud it repeats the cycle again but there is more to the water cycle but that’s a simple answer for your question.

The process by which a cell takes in a large particle is called

A
endocytosis.

B
diffusion.

C
active transport.

D
exocytosis.

Answers

Answer:

A endocytosis

Explanation:

The process by which a cell takes in a large particle is called endocytosis. Therefore, the correct option is option A.

What is endocytosis?

Endocytosis is the procedure by which molecules are actively transported into the cell by being engulfed by its membrane. All cells use endocytosis and exocytosis to transport substances that cannot passively cross the membrane. Exocytosis serves the opposite purpose by ejecting molecules from the cell.

The requirement for homeostasis ensures an equal flow all molecules into and out of a cell, like all of the body's systems. This indicates that the number of molecules exocytosis and endocytosis both equal the number of molecules into the cell. The two systems work together to maintain a balance between nutrients and waste that is necessary for normal cell growth and function. The process by which a cell takes in a large particle is called endocytosis.

Therefore, the correct option is option A.

To know more about endocytosis, here:

https://brainly.com/question/185008

#SPJ3

PLZ ANSWER REALLY FAST NO JOKES

A piece of nickel at 25 °C is dropped into a glass of water at 25 °C. Which statement is correct?

Heat will flow from the nickel to the water in the glass.
Heat will flow from the water in the glass to the nickel.
There will be no transfer of heat from the nickel to the water in the glass.
The final temperature of water and nickel will be 0 °C.

Answers

Answer:

The temperature of the water in both beakers will decrease

Explanation:

Answer:

I believe it's C. "There will be no transfer of heat from the nickel to the water in the glass."

Explanation:

there won't be any transfer of heat from the nickel to the water in the glass because both the nickel and the glass of water are at the same temperature.

Please help I’m confused

Answers

answer: i believe it’s the second one !


Which part of the wave is the arrow pointing to?
A. Rarefaction
B. Compression
C. Wavelength
D. Crest

Answers

B I am pretty sure.

Answer:

A. Rarefaction

Explanation:

4Al + 3O2 —> 2Al2 O3
10.7g of powdered Al is placed into a container containing 10.7g O2. What is the limiting reactant? How many grams of aluminum oxide can be produced? Calculate the mass of excess reactant that remains after the reaction is complete

Answers

Limiting reactant : Al

Al2O3 produced = 18.36 g

mass O2 remains = 11.904 g

Further explanation

Given

Reaction

4Al + 3O2 —> 2Al2O3

10.7 g O2

Required

Limiting reactant

mass Al2O3

Mass of excess reactant remains

Solution

mol Al : 10.7 : 27 = 0.396

mol O2 = 10.7 : 32 = 0.334

1. limiting reactant

mol : coefficient of Al : O2 = 0.396/4 : 0.334/3 = 0.099 : 0.111

Al as a limitng reactant(smaller ratio)

2. mass Al2O3

mol Al2O3 based on Al : 2/4 x 0.396 = 0.18

mass Al2O3(MW=102 g/mol) = 0.18 x 102 = 18.36 g

3. mass O2 remains

mol O2 reacted : 3/4 x 0.396 = 0.297

mol O2 remains = 0.669 - 0.297 =0.372

mass O2 remains = 0.372 x 32 = 11.904 g

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