Answer:
Explanation:
SI unit of
length=meter
volume =dm^3
mass =kilogram
time=second
energy= joule
temperature =kelvin
A 40-turn coil has a diameter of 19 cm. The coil is placed in a spatially uniform magnetic field of magnitude 0.40 T so that the face of the coil and the magnetic field are perpendicular. Find the magnitude of the emf induced in the coil (in V) if the magnetic field is reduced to zero uniformly in the following times.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
[tex]\epsilon = 7.57 \ V[/tex]
b
[tex]\epsilon =0.0757 \ V[/tex]
c
[tex]\epsilon =0.00699 \ V[/tex]
Explanation:
From the question we are told that
The number of turns is N = 40 turns
The diameter is [tex]d = 19 \ cm = 0.19 \ m[/tex]
The initial magnetic field is [tex]B_i = 0.40 \ T[/tex]
The final magnetic field is [tex]B_f = 0 \ T[/tex]
Generally the cross-sectional area of the coil is mathematically represented as
[tex]A = \pi \frac{d^2}{4}[/tex]
=> [tex]A = 3.142 * \frac{0.19^2}{4}[/tex]
=> [tex]A = 0.0284 \ m^2[/tex]
At [tex]\delta t = 0.60 \ s[/tex]
The induced emf is
[tex]\epsilon = - N * \frac{[B_f - B_i ] * A }{\delta t }[/tex]
=> [tex]\epsilon = - 40 * \frac{[- 0.40 ] * 0.0284 }{0.06}[/tex]
=> [tex]\epsilon = 7.57 \ V[/tex]
At [tex]\delta t = 6 \ s[/tex]
The induced emf is
[tex]\epsilon = - N * \frac{[B_f - B_i ] * A }{\delta t }[/tex]
=> [tex]\epsilon = - 40 * \frac{[- 0.40 ] * 0.0284 }{6}[/tex]
=> [tex]\epsilon =0.0757 \ V[/tex]
At [tex]\delta t = 65 \ s[/tex]
The induced emf is
[tex]\epsilon = - N * \frac{[B_f - B_i ] * A }{\delta t }[/tex]
=> [tex]\epsilon = - 40 * \frac{[- 0.40 ] * 0.0284 }{65}[/tex]
=> [tex]\epsilon =0.00699 \ V[/tex]
During the class prize-giving ceremony, Anand clapped his hands hard while Kumar clapped his hands softly. Everybody could hear Anand's clapping while only a few could hear Kumar's clapping. This was because the sound produced by Anand was of____________.
A - higher pitch
B - lower frequency
C - higher volume
D- lower pitch
Answer:
C - higher volume
Explanation:
The pitch or frequency of sound that an object can produce depends upon its size and configuration . The shape of hand of all are same so the frequency of sound produced by hands of all will be almost same . Hence frequency of sound produced by the hands of Anand and Kumar would have been almost the same .
But the intensity of sound produced by them would have been different . Intensity represents energy a sound carries . Hard hitting clap will produce sound of higher intensity . Intensity of sound is also called high volume sound . So Kumar's clap will carry greater energy and hence greater volume of sound .
Calculate the momentum of at 1500 kg car traveling at 6 m/s?
Answer:
Explanation:
momentum =mass*speed
p=1500 kg*6 m/s
p=9000 kgm/s
If you push a 20-kg box with a net force of 10 N, what is the acceleration of the box? A) 20 m/s^2 B) 2 m/s^2 C) 0.5 m/s^2 INTEGRATED SCIENCE to the person who keeps deleting my questions ':(
Answer:
C) 0.5 m/s^2
Explanation:
[tex]Mass = 20kg\\Force = 10 N\\Acceleration = ?\\\\Force = Mass \times Acceleration \\\\Acceleration = \frac{Force}{Mass}\\\\ Acceleration = \frac{10}{20}\\ \\Acceleration = 1/2 = 0.5m/s^2[/tex]
A Georgia water worker accidentally strikes a water pipe with the end of his pickaxe while trying to dig a whole. If the pickaxe strikes with a force of 3,600N and the end of the pickaxe measures 15mm by 13mm, how much pressure is exerted on the pipe by the pickaxe
Answer:
Pressure, [tex]P=1.84\times 10^7\ Pa[/tex]
Explanation:
Given that,
Force with which pickaxe strikes is 3600 N
The end of the pickaxe measure 15mm by 13mm.
We need to find the pressure exerted on the pipe by the pickaxe. Pressure exerted is equal to the force acting per unit area. So,
[tex]P=\dfrac{F}{A}[/tex]
A = 15 mm × 13 mm = 195 mm² = 0.000195 m²
So,
[tex]P=\dfrac{3600\ N}{0.000195\ m^2}\\\\P=18461538.46\ Pa\\\\\text{or}\\\\P=1.84\times 10^7\ Pa[/tex]
So, the pressure of [tex]1.84\times 10^7\ Pa[/tex] is exerted on the pipe by the pickaxe.What is the term for when the positive side of a battery is connected to the acceptor side and the negative side is connected to the donor side of the p-n rectifying junction?
Answer:
It is called Reverse biased
Explanation:
It is reverse bias because the voltage potential side of the battery is connected negative to the donor side or p type material and it is connected positive to the N type material or acceptor side across the diode which increases the diode width of the PN junction.
If you travel 5 miles north then turn and travel 5 miles south, you have traveled ______ miles
Answer: 10 miles
Explanation:
5 miles +5 miles= 10 miles (despite the directions)
This is the distance traveled
-------------------------------------
EXTRA STUFF ( you can literally ignore this part)
If you are asked for displacement instead for distance, then it will be 0 miles because you went 5 miles north and 5 miles south, which at the end, you are still at where you originally were.
Hope this helps!! :)
A box at rest on a ramp at an incline of 22°. The normal force on the box is 538 N
Answer:
F = 580.25 N
Explanation:
It is given that,
A box at rest on a ramp at an incline of 22°
The normal force on the box is 538 N
We need to find the gravitational force on the box.
The force of gravity acting on an object is equal to its weight. So,
F = mg
But here the box is incline at an angle of 22 degrees
It means that mg will resolve in rectangular components such that, normal force is :
[tex]N=mg\cos\theta\\\\mg=F=\dfrac{N}{\cos\theta}\\\\F=\dfrac{538}{\cos22}\\\\F=580.25\ N[/tex]
So, the gravitational force on the box is 580.25 N.
A constant force of 5KN pulls a crate along a distance of 15 m in 75s.What is the power
Explanation:
We know,
1KN = 1000N
Then, Force(F) = 5*1000N
=5000N
Here,
Power (P)=Work(W)/Time(T)
=Force * distance/ Time (W = F*s)
= 5000*15/75
=1000
So, The power of body or object is 1000Watt.
I hope this will be helpful for you.
You have a 100-kg object sitting on a frictionless tabletop. The object is connected to a spring with k = 1000 N/m and a natural length of 1 m with the other end of the spring connected to the wall. You pull the object 50 cm from the equilibrium position of the spring and hold it in place, and then release it.
Required:
a. How hard were you pulling on the object to hold it in place?
b. How much work did you do to move the object to that spot?
c. How close to the wall will the object get?
d. What is the fastest that the object moves and where is that location?
Answer:
a) 500 N
b) 250 J
c) 0.87 m
d) 1.58 m/s, at 0.6 m from the wall
Explanation:
The mass of the object m = 100 kg
the spring constant k = 1000 N/m
length of the the spring = 1 m
extension of the string = 50 cm = 0.5 m
a) Force used to pull the mass is gotten from Hooke's law equation
F = -kx
where F is the force used to pull = ?
k is the spring constant = 1000 N/m
x is the extension = 0.5 m
substituting, we have
F = 1000 x 0.5 = 500 N this force is used to pull the mass
b) The work done in moving the mass = Fx
==> 500 x 0.5 = 250 J
c) The energy stored up in the spring U = [tex]\frac{1}{2}kx^{2}[/tex]
U = [tex]\frac{1}{2}*1000*0.5^{2}[/tex] = 125 J
energy available for the mass from its equilibrium position = 250 - 125 = 125 J
this energy is equivalent to the work done by the spring on the mass by moving it closer to the wall
Work W = (weigh of the mass) x distance moved
weight = mg
where m is the mass = 100 kg
g is acceleration due to gravity = 9.81 m/s^2
substituting, we have
W = mgd
where d is the distance the mass moves closer to the wall
W = 100 x 9.81 x d
but W = 125 J
125 = 981d
d = 125/981 = 0.13 m
closeness to the wall = L - d
where L is the natural length of the spring = 1 m
closeness to the wall = 1 - 0.13 = 0.87 m
d) The maximum kinetic energy of the object will be halfway between the extended length and the final resting place.
extended length = 1 + 0.5 m = 1.5 m
distance from resting place = 1.5 - 0.87 = 0.63 m from the wall
At this point, all the mechanical energy on the mass and spring system is converted to kinetic energy of motion.
KE = [tex]\frac{1}{2}mv^{2}[/tex]
substituting,
125 = [tex]\frac{1}{2}*100*v^{2}[/tex] = [tex]50v^{2}[/tex]
[tex]v^{2}[/tex] = 125/50 = 2.5
v = [tex]\sqrt{2.5}[/tex] = 1.58 m/s
Maria was returning from her work when, when entering a street, she came across two unknown boys, who began to give praise to the girl:
_ You are the most beautiful girl seen in this world, said the first young man.
_ The moon is jealous of you! Said the second young man.
The girl went on her way and left.
What's wrong with this situation?
Answer:
Sexual harassment.
Explanation:
It is illegal to harass an individual on account of the sex of that person. sexual harassment includes inappropriate sexual advances, sexual favor demands, and other physical or verbal sexual misconduct. Nevertheless, harassment should necessarily not be of a sexual nature and may make derogatory comments about a person's sex. As per the question, it is unlawful to harass Maria by making offensive remarks and comments.
a burning piece of wood converts ____ energy into ____ energy
Answer:
a burning piece of converts Chemical energy into Heat(Thermal) and Light energy
How many (whole number of) 87 kg people
can safely occupy an elevator that can hold a
maximum mass of exactly 1 metric ton? A
metric ton is 1.000 x 103 kg.
Answer in units of people.
Answer:
11
Explanation:
1. You are going to be rounding down.
2. change the metric ton to kg.
1.000 * 10^3 kg = 1000 kg
1000 / 87 = 11.49 = 11 people
while you are in class, your iclicker falls off your desk to the floor. what forces are acting on your iclicker as it falls to the floor?
Answer:
Gravitational forces and drag forces
Explanation:
All objects that are above a certain distance above the ground has gravitational force acting on them. A falling body like the iclicker has gravitational force pulling it down with a magnitude proportional to its mass and the acceleration due to gravity. As the iclicker fall, it experiences air resistance due to the drag forces on it from the air molecules around. This drag force acts upwards so as to oppose the motion of the iclicker downwards, and the magnitude is minimal when compared to the gravitational force. The resultant force is therefore downwards
A bungee cord stretches 25 meters and has a spring constant of 140 N/m. How much energy is stored in the bungee
Answer:
87.5 kJExplanation:
The potential energy stored in a stretch spring is given by the expression below
PE = Work = force * distance
So:
[tex]PE = (kx) * x[/tex]
This then simplifies to:
[tex]PE = kx^2[/tex]
where k is the spring constant= 140 N/m
Given that x= 25 m
Substituting our data into the expression for P.E stored we have
[tex]PE = 140*25^2\\\\PE= 140*625\\\\PE= 87500 J[/tex]
Hence the energy stored in the spring is 87.5kJ
how high off the ground is a a book that has 120 J of potential energy and a 4-kg mass
A ball is rolling down a hill. At one point near the top of the hill, it’s velocity is 2 m/s. Further down the hill, it’s velocity is 9 m/s what is tringlev?
Explanation:
The change in velocity is the final velocity minus the initial velocity.
Δv = v − v₀
Δv = 9 m/s − 2 m/s
Δv = 7 m/s
What is the direction of the electric field at a point a distance d = 34.00 cm directly to the right of the positive charge?
Answer:
s the charge is positive, the electric field lines leave it at the point a d = 0.034 cm, the electric field lines go to the right.
Explanation:
The electric field around the cagases oisitvi, field leaving this means that the field lines move away from
If the charge is negative the lines of the field are directed towards the charge
Let's apply this to our case, as the charge is positive, the electric field lines leave it at the point a d = 0.034 cm, the electric field lines go to the right.
A coil has an inductance of 7.00 mH, and the current in it changes from 0.200 A to 1.50 A in a time interval of 0.250 s. Find the magnitude of the average induced emf in the coil during this time interval.
Answer:
Magnitude of the average induced emf = 36.4 mv
Explanation:
Given:
inductance of the coil (L) = 7 mH
Initial current (Ci) = 0.200 A
Final current (Cf) = 1.50 A
Interval = 0.250 s
Find:
Magnitude of the average induced emf
Computation:
E = L(di/dt)
E = 7 [(1.5-0.20) / 0.250]
E = 7[5.2]
Magnitude of the average induced emf = 36.4 mv
A rocket train car that is 30 m long is traveling from Los Angeles to New York at v=0.5c when a light at the center of the car flashes. When the light reaches the front of the car, it immediately rings a bell. Light reaching the back of the car immediately sounds a siren. A bicyclist waiting to cross the tracks sees the light in front of her at the instant when it flashes. Choose frame S' so that its origin is located at the center of the train. Take the direction of motion of the train (eastward) to be the positive direction of x'. Let the instant when the light flashes be t′=0s.
Required:
What are (x′A,t′A) and (x′B,t′B), the spacetime coordinates of event A and B in S'?
Answer: The reference frame of a passenger in a seat near the center of the train
Explanation:
the speed of light is the same for the passenger and the bicyclist
then the avents are simultaneous fo the passenger not for the bicyclist
the delay between the two events for the bicyclist is
Δt=Δd/vs
where
Δd= lenght of train
vs=speed of sound
the reference frame of a passenger in a seat near the center of the train
Solution:
The space and time transformations are:
x' = γ(x - vt)
t' = γ(t - vx/c²).
In the primed frame the two events are simultaneous, so that Δt' = 0. Also here Δx' = 30. In the unprimed frame Δx' = 30 = γ(Δx - v Δt).......(*)
We also have Δt' = 0 = γ(Δt - vΔx/c²)→Δx = c²Δt/v......(**)
Substituting (**) in (*): 30 = γ(c²Δt/v - vΔt))→Δt = 30/(c²/v - v) =
30/(2c - 0.5c) = 6.7 x 10^(-8)s
A spring with force constant of 59 N/m is compressed by 1.3 cm in a hockey game machine. The compressed spring is used to accelerate a small metal "puck" with mass 39.2 grams which will then slide up an inclined surface inside the machine. Assume friction is so tiny it may be ignored in this problem. How high in cm above its initial vertical position will the puck rise before stopping (momentarily at least)? Note: Convert units as necessary.
Answer:
The puck moves a vertical height of 2.6 cm before stopping
Explanation:
As the puck is accelerated by the spring, the kinetic energy of the puck equals the elastic potential energy of the spring.
So, 1/2mv² = 1/2kx² where m = mass of puck = 39.2 g = 0.0392 g, v = velocity of puck, k = spring constant = 59 N/m and x = compression of spring = 1.3 cm = 0.013 cm.
Now, since the puck has an initial velocity, v before it slides up the inclined surface, its loss in kinetic energy equals its gain in potential energy before it stops. So
1/2mv² = mgh where h = vertical height puck moves and g = acceleration due to gravity = 9.8 m/s².
Substituting the kinetic energy of the puck for the potential energy of the spring, we have
1/2kx² = mgh
h = kx²/2mg
= 59 N/m × (0.013 m)²/(0.0392 kg × 9.8 m/s²)
= 0.009971 Nm/0.38416 N
= 0.0259 m
= 2.59 cm
≅ 2.6 cm
So the puck moves a vertical height of 2.6 cm before stopping
the linear impulse and momentum equation is obtained by integrating the ______ with respect to time.
Answer:
and the forces acting on the particle as a function of time.
Explanation:
The principle of linear impulse and momentum is obtained by integrating the equation of motion with respect to time. hope this helps you :)
The linear impulse and momentum equation is obtained by integrating the force acting on the object with respect to time.
What is the linear impulse?The Linear Impulse is defined as the momentum exerted by a force during a time interval.
The linear impulse and momentum equation is obtained by integrating the force with respect to time.
From the equation of the impulse-momentum theorem:
∆p = J
where,
∆p is the change in momentum of the object,
J is the impulse applied to it.
The impulse is defined as the product of force and the time over which the force is applied.
Thus, we can write the impulse as:
J = ∫ F dt
where,
F is the force acting on the object,
dt is the time interval during which the force acts.
By substituting this expression for J in the momentum equation,
we get:
∆p = ∫ F dt
which is the linear impulse-momentum equation.
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An object is moving with constant non-zero velocity. Which of the following statements about it must be true?
(A) A constant force is being applied to it in the direction of motion.
(B) A constant force is being applied to it in the direction opposite of motion.
(C) A constant force is being applied to it perpendicular to the direction of motion.
(D) The net force on the object is zero.
(E) Its acceleration is in the same direction as its velocity.
Answer:
The net force on the object is zero.
Explanation:
An object is moving with constant non-zero velocity. If velocity is constant, it means that the change in velocity is equal to 0. As a result, acceleration of the object is equal to 0. Net force is the product of mass and acceleration. Hence, the correct option is (d) "The net force on the object is zero".
For a constant non-zero velocity the net force on the object is zero.
Velocity is defined as the change in displacement per change in time of motion.
[tex]v = \frac{\Delta x}{\Delta t}= \frac{x_2 - x_1}{t_2 - t_1}[/tex]
where;
Δx is the change in displacement
Δt is the change in time motion
When the change in the displacement is same for equal time interval, the resulting velocity will be constant but non-zero in magnitude.
Also, when the net force acting on an object is zero, the object will move with a constant velocity.
[tex]\Sigma F_x = 0[/tex]
Thus, for a constant non-zero velocity the net force on the object is zero.
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An electron is projected with horizontal speed 105m / s in a downwardly directed 304N / C electric field. Find the vertical position (in m) after 2.0 μs.
Answer:
-107 m
Explanation:
Sum of forces in the y direction:
∑F = ma
-qE = ma
a = -qE/m
a = -(1.60×10⁻¹⁹ C) (304 N/C) / (9.11×10⁻³¹ kg)
a = -53.4×10¹² m/s²
Given in the y direction:
v₀ = 0 m/s
a = -53.4×10¹² m/s²
t = 2×10⁻⁶ s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (2×10⁻⁶ s) + ½ (-53.4×10¹² m/s²) (2×10⁻⁶ s)²
Δy = -107 m
What is the charge delivered by a current with an average of 0.54 A over 28.3 minutes?
Answer:
916.9C
Explanation:
Using Q= It
Q= 0.54A x 1698s
= 916.9C
The charge delivered by a current with an average of 0.54 A over 28.3 minutes is 916.9C.
What is Electric Charge?Electric charge is defined as the physical property of matter that causes that matter to experience a force when placed in an electromagnetic field that may be positive or negative such that charges repel each other and unlike charges attract each other. An object with the absence of net charge is said to be neutral.
The SI unit of electric charge is the coulomb which is a derived SI unit and is represented by the symbol C.
Electric Charge is represented as
Q= It
where, Q= Electric charge
I= Electric current
t= time
Q= 0.54A x 1698s
= 916.9C
Thus, the charge delivered by a current with an average of 0.54 A over 28.3 minutes is 916.9C.
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It takes the Earth 24 hours to make a complete rotation around its axis. 33% Part (a) What is the period of rotation of the Earth in seconds? Grade Summary Deductions0 Potential 100 sin cotan) coso asin) atano acotan) sinh0 tan) acoso Attempts remaining per antemp4) detailed vie cosh0 tanhO cotanhO ODegrees O Radians Hint I give up Hints:-% deduction per hint. Hints remaining:- Feedback: dohction per fcedback ▲ 33% Part (b) What is the angular velocity of the Earth in rad/s? 33% Part (c) Given that Earth has a radius of 6.4 x 106 m at its equator, what is the linear velocity at Earth's surface?
Answer:
Explanation:
a )
one rotation per 24 hours
Time period of rotation of the earth T = time / no of rotation
T = 24 x 60 x 60 s / 1
= 86400 s .
b )
angular velocity = angle of rotation in radian / time
in one rotation , angle made at the centre = 2π radian
= 2 x 3.14 radian
angular velocity ω = 2π / T
= 2 x 3.14 / 86400 radian / s
= 72.68 x 10⁻⁶ radian / s
c )
Relation between linear and angular velocity is as follows
v = ω x R where R is radius of the earth and v is linear velocity .
linear velocity = 72.68 x 10⁻⁶ x 6.4 x 10⁶ m /s
= 465.152 m /s
=
Why is it cooler to wear a white shirt than a black shirt on a hot, sunny day?
Answer:
because the colour black absorbs heat which will make you feel much hotter than a white shirt which blocks away heat.
According to the Big Bang Theory, the density and temperature of the Universe is ___________ now than in the past.
Answer:
According to the Big Bang Theory, the density and temperature of the Universe is lower now than in the past.
Hope this answer correct :)
The density and the temperature of the universe should be lower as compared to the past.
What is the big bang theory?According to this theory, it description of the way the universe should be started is provided by the astronomers. The temperature of the universe should be very much hot, the universe size should be small also the universe should be super dense. However, the universe size should be expanded and the temperature should be colder according to the time.
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The magnetic field inside a superconducting solenoid is 4.00 T. The solenoid has an inner diameter of 6.20 cm and a length of 26.0 cm.(a) Determine the magnetic energy density in the field.uB = 1 J / m3(b) Determine the energy stored in the magnetic field within the solenoid.UB = 2 kJ
Answer:
(a) The magnetic energy density in the field is 6.366 J/m³
(b) The energy stored in the magnetic field within the solenoid is 5 kJ
Explanation:
magnitude of magnetic field inside solenoid, B = 4 T
inner diameter of solenoid, d = 6.2 cm
inner radius of the solenoid, r = 3.1 cm = 0.031 m
length of solenoid, L = 26 cm = 0.26 m
(a) The magnetic energy density in the field is given by;
[tex]u _B = \frac{B^2}{2\mu_o} \\\\u _B = \frac{(4)^2}{2(4\pi*10^{-7})}\\\\u_B = 6.366*10^6 \ J/m^3[/tex]
(b) The energy stored in the magnetic field within the solenoid
[tex]U_B = u_B V\\\\U_B = u_B AL[/tex]
[tex]U_B = u_B(A)(L)\\\\U_B = 6.366*10^6(\pi * 0.031^2)(0.26) \\\\U_B = 4997.69 J\\\\U_B = 5 \ KJ\\[/tex]
The acceleration of an object is always in the direction of the net force acting on it.
Answer:
yes
Explanation:
An object which moves in a circle is accelerating. Accelerations are caused by an unbalanced or net force. The net force is always in the same direction as the acceleration. For objects moving in circles at constant speed, the net force is directed towards the center of the circle about which the object moves.