Answer:
LX = WI
I = L
A = G
W = X
I = L
LAX = WIG
solve for x^3+y^3+z^3=k, with k being all numbers from 1-100
The equation x^3+y^3+z^3=k has no general algebraic solution
How to solve the equationFrom the question, we have the following parameters that can be used in our computation:
x^3+y^3+z^3=k
Where
k = 1, 2, ...., 99, 100
There is no general solution to the equation, and it can only be solved by assumptions
Take for instance: k = 1
The solutions for k = 1 are (1, 0, 0), (0, 1, 0) and (0, 0, 1)
There are multiple solutions for other values too
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If 20% of a length is 23km.what is the complete length?
The total length is 115 km.
Step-by-step explanation:1. Create an equation.Let "x" be the complete lengh. So, in order to find 20% of that length we need to multiply by 0.2, which equals 20%. And it needs to equal 23 km. Hence the equation should be the following:
[tex]0.2x=23[/tex]
2. Divide by "0.2" on both sides of the equation.[tex]\frac{0.2x}{0.2} =\frac{23}{0.2} \\ \\x=115[/tex]
3. Verify the answer.To verify the answer, calculate 20% of the result (115), and it should equal 23 km. Let's see!
[tex]115*0.2=\\ \\23[/tex]
4. Conclude.The total length is 115 km.
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work out an estmate of the mean age in this table
a)
The class modal interval is 24 ≤ a < 26.
b)
The Mean age of the employee is 23.
What is a mean?It is the average value of the set given.
It is calculated as:
Mean = Sum of all the values of the set given / Number of values in the set
We have,
Age Frequency (f) Midpoint (x) fx
18 ≤ a < 20 3 19 57
20 ≤ a < 22 2 21 42
22 ≤ a < 24 7 23 161
24 ≤ a < 26 8 25 200
26 ≤ a 0
Now,
Sum of all the frequencies.
N = 3 + 2 + 7 + 8 = 20
Sum of fx.
= 57 + 42 + 161 + 200
= 460
Now,
Mean = 460/20
Mean = 23
Now,
Class modal interval.
= 24 ≤ a < 26
Because in the class interval, the frequency is the highest.
Thus,
The class modal interval is 24 ≤ a < 26.
The Mean is 23.
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While sitting on her balcony, Natalie saw a helicopter flying 1,200 feet above her and the top of a tree 14 feet below her. On a number line, let 0 represent Natalie’s location and the positive side of 0 represent a higher position.
Which number sentence correctly compares the distances of the helicopter and the top of the tree to Natalie?
A. |-1,220| > |14|
B. |-1,220| < |14|
C. |1,220| < |-14|
D. |1,220| > |-14|
Answer:
the awnser is C
Step-by-step explanation:
The equations that represent the balance in three different savings accounts x years after 2012,
A
=
900
(
1.05
)
x
A
=
900
(
1.05
)
x
B
=
1100
(
1.038
)
x
B
=
1100
(
1.038
)
x
C
=
5000
(
0.85
)
x
C
=
5000
(
0.85
)
x
Which of the following statements are TRUE? Check all that apply.
Account C had the largest balance in the year 2012.
The balance of Account A is growing at a rate of 5% per year.
The balance of Account C is decreasing at a rate of 85% per year.
Account A is growing faster than account B.
all the applications are true.
What is simple interest?
A quick and simple way to figure out interest on money is to use the simple interest technique, which adds interest at the same rate for each time cycle and always to the initial principal amount. Any bank where we deposit our funds will pay us interest on our investment. One of the different types of interest charged by banks is simple interest. Now, before exploring the idea of basic curiosity in further detail,
Solution: Start by using:
2012 indicates that x=1
So A = 900 (1.05) = 900 × 1,05=945
B = 1100 (1.038) = 1100 × 1038 = 1141.8 \sC = 5000 (0,85) = 5000 x0.85 = 4250 \s4250 1141.8945
So, Ture is the first applicant.
Applying the second: 1.05-1=0.055% Ture
The third application is 1-0.85=0.15=15%. False
Applying the fourth: A 1.05+=0.05=5%
B: \s11038-1=0.038=3.8% \s5% > 3.8% Ture
Hence all the apply are true.
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.10. for each of the gcd(a, b) values in exercise 1.9, use the extended euclidean algorithm (theorem 1.11) to find integers u and v such that au bv
The equation is satisfied for the gcd(30, 21) and it is: -30 + 21 = 3.
For the gcd(a, b) values in exercise 1.9, the extended Euclidean algorithm (Theorem 1.11) can be used to find integers u and v such that au + bv = gcd(a, b).
We start by using the Euclidean algorithm to calculate the gcd(a, b). We then iteratively calculate the remainder, quotient, and coefficients for each step. We use the equation a = qb + r, where q is the quotient and r is the remainder. We then use the equation r = a - qb to find the value of u and v.
For example, consider gcd(30, 21). We use the Euclidean algorithm to calculate the gcd. We get that gcd(30, 21) = 3. We then use the equation a = qb + r to calculate the remainder, quotient, and coefficients. We get that 30 = 1(21) + 9. We then use the equation r = a - qb to find the values of u and v. So, 9 = 30 - 1(21), which gives us that u = -1 and v = 1. This means that the equation is satisfied for the gcd(30, 21) and it is: -30 + 21 = 3.
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an article reported the following data on oxidation-induction time (min) for various commercial oils: 86 102 130 160 180 195 135 145 214 105 145 154 153 135 87 99 94 119 129 (a) calculate the sample variance and standard deviation. (round your answers to four decimal places.)
The sample variance is 2482.6375 and the sample standard deviation is 49.79 (rounded to four decimal places). The sample variance and standard deviation can be calculated using the following formula:
Sample variance:
s^2 = (1 / (n-1)) * ∑ (x_i - x)^2
Sample standard deviation:
s = √(s^2)
Where:
x_i is each data point,
x is the sample mean,
n is the number of data points,
∑ represents the sum of all terms.
First, we need to calculate the sample mean:
x = (86 + 102 + 130 + 160 + 180 + 195 + 135 + 145 + 214 + 105 + 145 + 154 + 153 + 135 + 87 + 99 + 94 + 119 + 129) / 20 = 140.95
Next, we can use the sample mean to calculate the sample variance:
s^2 = (1 / (20-1)) * ( (86-140.95)^2 + (102-140.95)^2 + (130-140.95)^2 + (160-140.95)^2 + (180-140.95)^2 + (195-140.95)^2 + (135-140.95)^2 + (145-140.95)^2 + (214-140.95)^2 + (105-140.95)^2 + (145-140.95)^2 + (154-140.95)^2 + (153-140.95)^2 + (135-140.95)^2 + (87-140.95)^2 + (99-140.95)^2 + (94-140.95)^2 + (119-140.95)^2 + (129-140.95)^2)
Finally, we can take the square root of the sample variance to find the sample standard deviation:
s = √(s^2) = √(2482.6375) = 49.79
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grade 4 standard based practice compare two fractions jasmine cut 3/8 yard of blue ribbon and 1/3 yard of red ribbon to decorate
Hence, Reese would need 2/5 yards of blue ribbon for every yard of gold ribbon. Thus, the correct option will be (c)
A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other. For example, if there is 1 boy and 3 girls you could write the ratio as:
1 : 3 (for every one boy there are 3 girls)
and if there is 2 pen and 4 copy in your bag the the ratio is
1 : 2 (for every 1 pen there is 2 copy)
We know that
Reese needs 1/4 yards of blue ribbon for every 5/8 yards of gold ribbon.
To know the total blue ribbon she would need for each yard of gold ribbon, we use the following proportion.
(1/4)/x=(5/8)
the x = 5/8 = 4x
x = 2/5
Reese needs 1/4 yards of blue ribbon for every 5/8 yards of gold ribbon.
To know the total blue ribbon she would need for each yard of gold ribbon, we use the following proportion.
Then, we solve for x.
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The question is incomplete, the complete question is:
Standard based practice compare two fractions jasmine cut 3/8 yard of blue ribbon and 1/3 yard of red ribbon to decorate will be:
a) 0
b) 4/7
c) 2/5
d) 3/9
truth table for (P^Q)
In the attachment......
Jesse freelance landscapes for $20 an hour. Denisse has a landscaping business, but charges $40 for an appointment and $15 dollar an hour. How many hours would they need to work to make the same amount of money? If you need someone to do a 9-hour job, who would cost less?
Answer:
Denise will cost less.
Step-by-step explanation:
20×9=180.
therefore Jesse will cost $180 for the 9hour job whereas denise:
15×9=135.
135+40=175.
denise will cost $175.
This shows denise is $5 cheaper.
Answer:
Step-by-step explanation:
1. multiply 15x9 and then add 40
2. 20x9
now which one cost less jesse or denisse?
The figure shown below contains two similar triangles. Find the unknown measure indicated by a variable. Answer to the nearest tenth.
Z=
Answer:
36.4
Step-by-step explanation:
1. rule is
[tex]\frac{AB}{BH} =\frac{BC}{BD}; \ or \ \frac{z}{BH} =\frac{BC}{BD};[/tex]
2. according to the rule above
[tex]z=\frac{BH*BC}{BD}; \ = > \ z=\frac{15(20+14)}{14}=\frac{15*34}{14}=36.42857.[/tex]
3. finally, z=36.4
PS. additional details are in the attachment.
1. Bargain Deli's 1.5 pound package of sliced
ham sells for $4.80. Deli Market's 2 pound
package of sliced ham sells for $5.80. Which
brand of ham is the better buy? What is the
cost per pound of the cheaper brand?
Step-by-step explanation:
The better buy is Bargain Deli's sliced ham as it is cheaper per pound. The cost per pound of Bargain Deli's sliced ham is $4.80/1.5 = $3.20 per pound.
Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−7t cos(6t), y = e−7t sin(6t), z = e−7t; (1, 0, 1)
The parametric equations for the tangent line to the curve at the given point are x = 1 - 7e−7cos(6)t + 6e−7sin(6)t, y = -7e−7sin(6)t - 6e−7cos(6)t, and z = 1 - 7e−7t.
The given parametric equations are x = e−7t cos(6t), y = e−7t sin(6t), z = e−7t, and the point is (1, 0, 1).
We can find the tangent line in two steps. First, we'll find the slope at the given point (1, 0, 1). Second, we'll use the point-slope form of a line equation to find the equation of the tangent line.
At the given location, determine the slope.
We can find the slope by taking the partial derivative of each coordinate with respect to t.
∂x/∂t = -7e−7tcos(6t) + 6e−7tsin(6t)
∂y/∂t = -7e−7tsin(6t) - 6e−7tcos(6t)
∂z/∂t = -7e−7t
Evaluating these derivatives at t = 1, we find:
∂x/∂t = -7e−7cos(6) + 6e−7sin(6)
∂y/∂t = -7e−7sin(6) - 6e−7cos(6)
∂z/∂t = -7e−7
At the given point, x = 1, y = 0, and z = 1.
Thus, the slope of the tangent line is:
m = (∂x/∂t, ∂y/∂t, ∂z/∂t) = (-7e−7cos(6) + 6e−7sin(6), -7e−7sin(6) - 6e−7cos(6), -7e−7)
Use the point-slope form of a line equation to find the equation of the tangent line.
The point-slope form of a line equation is:
r(t) = r₀ + m*t
Where r₀ is the point and m is the slope.
Thus, the equation of the tangent line is:
r(t) = (1, 0, 1) + (-7e−7cos(6) + 6e−7sin(6), -7e−7sin(6) - 6e−7cos(6), -7e−7)*t
Simplifying, we find:
x = 1 - 7e−7cos(6)t + 6e−7sin(6)t
y = -7e−7sin(6)t - 6e−7cos(6)t
z = 1 - 7e−7t
Therefore, the parametric equations for the tangent line to the curve at the given point are x = 1 - 7e−7cos(6)t + 6e−7sin(6)t, y = -7e−7sin(6)t - 6e−7cos(6)t, and z = 1 - 7e−7t.
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The parametric equations for the tangent line to the curve with the given parametric equations at the point (1,0,1) are:
x = 1 + e^-7t * (-7cos(6t) + 6sin(6t))
y = e^-7t * (-7sin(6t) - 6cos(6t))
z = e^-7t
The tangent line at a given point on a curve is a line that is locally closest to the curve at that point. To find the tangent line, we need to first find the derivative of the curve at the given point and then use it to find the slope of the tangent line. In this case, the given curve is a parametric equation and we can find the partial derivatives with respect to the parameter t.
Next, we use the partial derivatives to calculate the slope of the tangent line at the given point. Finally, we use the slope and the given point to write the parametric equations of the tangent line.
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How would you classify 6x power of 2
Answer:
Step-by-step explanation:
The expression "6x power of 2" represents a polynomial expression in the variable x. The term "6x" is a linear term, and the term "2" is a constant term. So, the expression "6x power of 2" can be classified as a degree 1 polynomial with one variable.
Answer:
monomial of degree 2 with one variable
Step-by-step explanation:
You want to classify 6x².
PolynomialA polynomial is a sum of terms consisting of the product of a constant and one or more variables raised to non-negative integer powers. Special names are given to polynomials consisting of one, two, or three terms.
The given term has a coefficient of 6, and one variable, x, raised to the power of 2. The "degree" of the term is the sum of powers of all of the variables in the term, so the degree of x² is 2.
A single-term polynomial is called a "monomial."
6x² is a monomial of degree 2
What is the surface area?
9 m
Submit
4 m
3 m
square meters
Answer:
108 m^2
Step-by-step explanation:
9*4*3= 108 m^2
find the volume V of the solid generated by revolving the region bounded by the given lines and curves about x axis for y = x^2, y =0, x =2.
The volume of the solid generated is V=8π and 32/5π
Given functions are x=y², x=2 and y=0
The equation y=x² is a parabola opening to right and has a vertex at O(0,0)
and another y=0 is the x-axis and x=2 is a line parallel to the y-axis
The region bounded by the above will be formed once their intersection points are known.
y²=2⟹y=±√2
OFB is bounded by O(0,0), F(2,0) and B(2,√2)
Let V be the volume of solid generated when the region OFB is revolved around line x=2.
[tex]V=\pi \int\limits^2_0 {x^4} \, dx \\[/tex]
V=π[x⁵/5]²₀
V=π[(2)⁵/5]
V=32/5 π.
[tex]V=\pi \int\limits^4_0 {(2^2)_2-(\sqrt{y}^2)_3 } \, dy\\\\ V=\int\limits^4_0 {(4-y)} \, dx[/tex]
V=8π.
when the shaded region revolves the bout x-axis:
[tex]V=\pi \int\limits^b_a {y^2} \, dx \\\\V=\pi \int\limits^2_0 {y^2} \, dx =\pi \int\limits^2_0 {x^4} \, dx =\pi [\frac{1}{5}.x^5]_0^2\\\\ V=\pi [\frac{32}{5}-0][/tex]
V=32/5
when the shaded region revolves the bout y-axis:
[tex]V=\pi \int\limits^c_d [(x^2)_2-(x^2)_1} \, dx \\V=\pi \int\limits^4_0 [(2^2)_2-(\sqrt{y} ^2)_1} \, dy \\V=\pi \int\limits^4_0 {(4-y)} \, dy =\pi [4y-\frac{1}{2}y^2]_0^4[/tex]
V=π[16-8]
V=8π
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Keshawn is selling lollipops and candy bars for the PHS football team fundraiser this year. The lollipops are $2, and the candy bars are $4. He is hoping to raise $180 on his own. Define the variables. Write an Inequality to represent the situation.
Answer:
Variables:
x = number of lollipops sold
y = number of candy bars sold
Inequality: 2x + 4y ≥ 180
Stefan borrowed twice as much on his 8 % car loan as on his 7% student loan. The annual interest
on the car loan is $360 more than the interest on the student loan. How much did Stefan borrow on
each loan?
a. Write an equation about the principals on the loans, using for the amount of money he borrowed
for his car and y for the amount of money he borrowed for his student loan.
b. Write another equation about the interest on the loans.
c. Solve your system and answer the question for much he borrowed at each rate.
Car: $
Student: $
Answer:
Stefan borrowed $8000 on his car loan and $4000 on his student loan.
Step-by-step explanation:
a. Let x be the amount of money Stefan borrowed on his car loan and y be the amount he borrowed on his student loan. According to the problem, Stefan borrowed twice as much on his car loan as on his student loan, so x = 2y.
b. The annual interest on the car loan is $360 more than the interest on the student loan. We can set up an equation as follows:
0.08x - 0.07y = 360
c. Substituting x = 2y from equation (a) into equation (b), we get:
0.08(2y) - 0.07y = 360
0.16y - 0.07y = 360
0.09y = 360
y = 4000
So, Stefan borrowed $4000 on his student loan. Using equation (a), we can find the amount he borrowed on his car loan:
x = 2y = 2(4000) = 8000
Therefore, Stefan borrowed $8000 on his car loan and $4000 on his student loan.
PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!
The translation applied is:
(x, y) → (x - 1, y - 5)
It is a translation of 1 unit to the left and 5 units down.
Which is the translation applied?To find the translation from MNOP to M'N'O'P' we just need to take the difference between any two correspondent vertices.
For example, we can see that:
M = (-1, 3)
M' = (-2, -2)
Taking the difference we will geT:
(-2, -2) - (-1, 3) = (-2 + 1, -2 - 3) = (-1, -5)
Sothat the translation is:
(x, y) → (x - 1, y - 5)
The translation one unit to the left and 5 units down.
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graph the function f(x)= cos (2x) +1
Graph the trigonometric function using the amplitude, period, phase shift, and vertical shift.
Amp= 1
Period=pi
Vertical shift= 1
Phase shift= none
Using MATLAB, plot Bode diagrams of G1(s) and G2(s) given below: G1(s)=1+s/1+2s G(s) = 1-s/1-2s Note that the second transfer function is a non-minimum phase system; meaning it has a zero on the right-half plane. Note how the phase plot is affected.
Bode plots depict the frequency response, or the magnitude and phase changes as a function of frequency. This is accomplished using two semi-log scale plots. Using MATLAB, plot Bode diagrams of G1(s) and G2(s) given below.
(a) The first function is:
G1(s) = (1 + s)/(1 + 2s)
MATLAB Code:
%G1(s)
n1 = [1 1] %coefficients of numerator
d1 = [2 1] %coefficients of denominator
sys1 = f(n1,d1) %the transfer function
bode(sys1) %bode plot
grid on
Command Window:
>> Untitled
n1 = 1 1
d1 = 2 1
sys1 = (1 + s)/(1 + 2s)
Continuous-time transfer function.
(b) The second function is:
G(s) = (1 - s)/(1 - 2s)
MATLAB Code:
%G2(s)
n2 = [-1 1] %coefficients of numerator
d2 = [2 1] %coefficients of denominator
sys2 = f(n2, d2) %the transfer function
bode(sys2) %bode plot
grid on
Command Window:
>> Untitled
n2 = -1 1
d2 = 2 1
sys2 = (1 - s)/(1 - 2s)
Continuous-time transfer function.
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The complete question is:
Using MATLAB, plot Bode diagrams of G1(s) and G2(s) given below:
G1(s) = (1 + s)/(1 + 2s)
G2(s) = (1 - s)/(1 - 2s)
Note that the second transfer function is a non-minimum phase system; meaning it has a zero on the right-half plane. Note how the phase plot is affected.
Your aunt sponsors you for a charity walk. she says she will give you $2 per minute. After 20 minutes of walking, you have raised $_____ for charity.
40 dollars. Aunt sponsored me with 2 dollars per minute, and I walked for 20 minutes, so I have raised 40 dollars for charity.
My aunt is a very generous and kind person. She offered to sponser me for a charity walk, telling me that she would give me 2 dollars per minute I walked. I was really excited to get involved in this walk and help out a good cause. I decided to commit to walking 20 minutes, which meant I would be raising 40 dollars for charity. I was really proud of myself for being able to help out, and I was also really thankful for my aunt's generous sponsership. Over the 20 minutes, I was really motivated to keep going, knowing that I was helping out a charity and also earning money. After the 20 minutes were up, I had raised 40 dollars for charity, thanks to my aunt's sponsership. It was a really rewarding experience and I'm glad I got to take part.
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A sine function has the following key features:
Period = 12
Amplitude = 4
Midline: y = 1
y-intercept: (0, 1)
The function is not a reflection of its parent function over the x-axis.
Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.
Answer:
The sine function for the given parameters is y = 4 sin ( pi/2 * x ) + 1. The period is 12, the amplitude is 4, the midline is y = 1 and the y-intercept is (0, 1). The function is not a reflection of its parent function over the x-axis.
Step-by-step explanation:
To solve a sine function with the given features, one must first identify the midline, amplitude, period, and phase shift of the function. The midline is the average of the maximum and minimum values of the graph, while the amplitude is half of the difference between these two values. The period is the length of one cycle in radians, and the phase shift is how much it has been shifted from its parent function over the x-axis.
If tant=74, what is tan(t−π) ?
The tan(t−π) = 74of the given trigonometric function, tan(t−π), is 74
Evaluating trigonometric functionsFrom the question, we are to determine the value of trigonometric function tan(t−π) using the given information.
The given information is tan(t) = 74
We can use the following identity to solve this problem:
tan(t - π) = tan(t) - tan(π) / 1 + tan(t)tan(π)
Since tan(π) = 0
This can be simplified into
tan(t - π) = tan(t) / (1 - 0)
tan(t - π) = tan(t)
Thus,
We just need to find tan(t)
Given that tan(t) = 74.
Hence, tan(t−π) = 74
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A politician's support increases from 32% to 53% Determine the absolute and relative change in this situation.
Absolute Change: The politician's support has increased by percentage points.
Relative Change: The politician's support has increased by %.
Round your answer to the nearest tenth of a percent.
Answer:
Step-by-step explanation:
Absolute Change:
The absolute change in the politician's support is calculated as the difference between the final support percentage (53%) and the initial support percentage (32%):
53% - 32% = 21 percentage points
So, the absolute change in the politician's support is 21 percentage points.
Relative Change:
The relative change in the politician's support is calculated as the absolute change divided by the initial support percentage, multiplied by 100 to express it as a percentage:
(21 / 32) * 100 = 65.625%
Rounding to the nearest tenth of a percent, the relative change in the politician's support is 65.6%.
So, the absolute change in the politician's support is 21 percentage points, and the relative change is 65.6%.
In this case, the absolute change in the politician's support is an increase of 21 percentage points, and the relative change is an increase of 65.6%.
Explanation:In this situation, the absolute change in the politician's support can be calculated by subtracting the original value from the new value. So, 53% (new value) - 32% (original value) = 21%. Thus, the absolute change in support is 21 percentage points.
The relative change is the absolute change divided by the original value. So, 21% (absolute change) ÷ 32% (original value) = 0.65625. To get the relative change as a percentage, we need to multiply this decimal by 100, and round to the nearest tenth of a percent, which gives us 65.6%.
Therefore, the politician's support has increased by an absolute change of 21 percentage points, and a relative change of 65.6%.
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In an encyclopedia of language, the author presents five sentences that make a reasonable paragraph regardless of their
order.
The sentences are listed below.
Mark had told him about the foxes.
John looked out of the window.
Could it be a fox?
However, nobody had seen one for months.
He thought he saw a shape in the bushes.
In how many different orders can the five sentences be arranged?
There are 120 different ways to the five sentences be arranged.
What is mean by Multiplication?Multiplication means to add number to itself a particular number of times. Multiply will be viewed as a process of repeated addition.
Given that;
In an encyclopedia of language, the author presents five sentences that make a reasonable paragraph regardless of their order.
And, The sentences are listed below.
1) Mark had told him about the foxes.
2) John looked out of the window.
3) Could it be a fox?
4) However, nobody had seen one for months.
5) He thought he saw a shape in the bushes.
Since, There are 5 sentence.
Hence, Number of different ways to the five sentences be arranged is,
⇒ 5!
⇒ 5 × 4 × 3 × 2 × 1
⇒ 120
Thus, There are 120 different ways to the five sentences be arranged.
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PLEASE ANSWER THIS ILL GIVE BRAINLIEST
Answer:
sorry
Step-by-step explanation:
Solve these 2 equations (picture attached.)
1. g(x)=1/5x
2. g(x)=-1/5x
No proof is needed.
The transformations for each function are given as follows:
1) Vertical compression by a factor of 5.
2) Vertical compression by a factor of 5 and a reflection over the x-axis.
What are the transformations?The parent function for this problem is given as follows:
f(x) = 1/x.
For item 1, we have that x was multiplied by five, as the multiplication was in the domain, the transformation was a vertical compression by a factor of 5.
For item 1, along with the multiplication of x by 5, the function was also multiplied by -1, meaning that the function was reflected over the x-axis.
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Can anyone help me? Find m
Answer:
m∠Y = 60
WY = 7 in
Step-by-step explanation:
It's an isosceles triangle (2 sides are equal), therefore m∠W = m∠Y because the base angles of an isosceles triangle are equal.
Sum of interior angles of a triangle is 180.
let x = m∠W = m∠Y
2x + 60 = 180
2x = 180 - 60 = 120
x = 120/2 = 60
m∠Y = 60
Since all 3 angles = 60, now we know it's an equilateral triangle, therefore WY = 7 in
consider the following elementary reactions: (i): 2 a b c (slow) (ii): b d e (fast) (iii): e c f (fast) the rate law is
The rate law for the overall reaction is:[tex]rate = k[A]^2[B][C][/tex]
The rate law describes the relationship between the rate of a reaction and the concentrations of the reactants. In this case, the overall reaction is the combination of three elementary reactions: (i): 2 a b c (slow), (ii): b d e (fast), and (iii): e c f (fast).
We can determine the rate law for the overall reaction by combining the rate laws from each of the elementary reactions. The rate law for reaction (i) is[tex]rate = k[A]^2[B][C],[/tex] since it is a second order reaction with respect to A and first order with respect to B and C. Reaction (ii) is first order with respect to B, and reaction (iii) is first order with respect to E and C.
Combining the rate laws, we get: [tex]rate = k[A]^2[B][C][/tex]. This is the rate law for the overall reaction.
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