Answer:
$50.08
Step-by-step explanation:
Let's use x to represent the lesser expensive hat and 2x to represent the more expensive hat since the more expensive hat is twice the price.
So, our equation would be 2x + x = 75.12
We can combine them together to make 3x.
Then, we make the 3x equal to 75.12
3x = 75.12
Now, we solve it.
Divide both sides by 3 to solve for x.
75.12/3 = 25.04
x = 25.04
Lastly, plug it in for 2x to get the price of the more expensive hat.
2(25.04) = ?
2(25.04) = 50.08
Therefore, the price of the more expensive hat is $50.08
division concepts
how many times can 9 go into .7632 ?
Answer:
None! .7632 is smaller than 9.
Step-by-step explanation:
3y + 6 = 18y
- What does the ( y ) variable stand for and how exactly do you find it?
Answer:
y=2/5 or 0.4
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
3y + 6 = 18y -->
subtract 3y from both sides to get rid of it.
6 = 15y -->
isolate the variable by dividing it by 15.
6/15 = 15y/15 -->
simplify.
2/5 = y
Enter the solution (x, y) to the system of equations shown. y=2x+1 3y=4x+7
Answer:
Step-by-step explanation:
3(2x + 1) = 4x + 7
6x + 3 = 4x + 7
2x = 4
x = 2
y = 2(2) + 1
y = 4 + 1
y = 5
(2,5)
Answer:
2,5
Step-by-step explanation:
PLEASE HELP ME with an explanation. Thanks in advance
Answer:
3) 0.30
The probability a randomly selected student plays a sport given they work part time = 0.30
Step-by-step explanation:
Step(i):-
Given 'A' plays a sport
B work part time
Given P(A) = 0.48
P(B) = 0.40
P(A∩B) =0.12
P(A∪B)¹ =0.24
Step(ii):-
By using conditional probability
[tex]P(B/A) = \frac{P(BnA}{P(A)}[/tex]
and similarly [tex]P(A/B) = \frac{P(AnB}{P(B)}[/tex]
The probability a randomly selected student plays a sport given they work part time
Now [tex]P(A/B) = \frac{P(AnB}{P(B)}[/tex]
[tex]P(A/B) = \frac{0.12}{0.40}= 0.30[/tex]
Final answer:-
The probability a randomly selected student plays a sport given they work part time = 0.30
Which geometric series converges?
CO
Σ(-3) 2-1
Η =1
O
Σ5-1) 2-1
CO
Ο Σ4(-02 - 1
H=1
CO
Σ06(-2) 2-1
h=1
Answer:
its C
Step-by-step explanation:
i just did it on edge and plus its really not cool to post answers when you dont actually know the answer bc people that actually want to help cant bc there only two answers allowed per question. so please dont answer if your not trying to help.
The geometric series [tex]\sum_{n=1}^{\infty} 5(-1)^{n-1}[/tex] converges to zero.
What is convergent and divergent geometric series?A mathematical term denoting an endless series of the form
a + ar + ar² + ar³ + ⋯, where r is referred to as the common ratio. The geometric series for a = 1 and r = 1/2, or 1 + 1/2 + 1/4 + 1/8 +, is a straightforward example.
A series is considered to be convergent if the partial sums gravitate to a certain value, also known as a limit.
In contrast, a divergent series is one whose partial sums do not reach a limit. The Divergent series usually approaches infinity.
From the given options let us try with [tex]\sum_{n=1}^{\infty} 5(-1)^{n-1}[/tex].
[tex]= 5\sum_{n=1}^{\infty} (-1)^{n-1}.[/tex]
[tex]= 5\sum_{n=1}^{\infty} (-1)^{n}.\frac{1}{-1}[/tex].
[tex]= -5\sum_{n=1}^{\infty} (-1)^{n}.[/tex]
= - 5[- 1 + 1 - 1 + 1 ...+ 1].
= - 5[0].
= 0.
learn more about geometric sequences here :
https://brainly.com/question/19235539
#SPJ7
Which are equations? CHECK all that apply.
X+3=12
Z/7+1
25-q
6g=18
2/3m
P/3.5=2.25
9=100-f
K divided by 5.8
Answer:
X + 3 = 12
6g = 18
P/3.5 = 2.25
9 = 100 - f
Step-by-step explanation:
Equations have equal signs.
Expressions do not.
Therefore, any expression with an equal sign is an equation, making it one of the correct answers.
Answer:
X + 3 = 12
6g = 18
P/3.5 = 2.25
9 = 100 - f
Step-by-step explanation:
Just did it!
Which are the center and radius of the circle with equation (x + 5)2 + (y − 4)2 = 9?
A. (−5, −4); r = 3
B. (5, −4); r = 9
C. (−5, 4); r = 3
D. (5, 4); r = 9
Answer:
C)
Step-by-step explanation:
*Look at the picture*
(60 POINTS) The figure is transformed as shown in the diagram. Describe the transformation.
A) dilation, then reflection
B) reflection, then rotation
C) rotation, then translation
D) translation, then reflection
Answer:
The solution is rotation, then translation. The figure has been rotated about the origin by 90° and then translated 6 units to the right.
think your a pro at riddles?
Mr. and Mrs. Mustard have six daughters and each daughter has one brother. How many people are in the Mustard family?
Answer:
nine
Step-by-step explanation:
Please answer quick
Taylor is playing a board game with two friends. Using a single dice, one friend rolled a one, and the other friend rolled a three. Taylor need to roll a number higher than both friends in order to win the game, and she wants to calculate her probability of winning m. What is the probability that Taylor will win the game?
A. P(winning)= 4/6=66%
B.P(winning)= 3/6=50%
C. P(winning)= 5/6=83%
D. P(winning)= 2/6=33%
Answer:
It would be 2/6.
Step-by-step explanation:
2/6 simplified is 1/3 and she is going against two of her friends in which makes three.
The probability that Taylor will win the game is 3/6 or 50% option (B) is correct.
What is probability?It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
Taylor is playing a board game with two friends. Using a single dice, one friend rolled a one, and the other friend rolled a three.
To win, Taylor needs to roll a 4, a 5, or a 6.
Total number in a standard roll = 6
Favorable outcomes = 3
Probability = 3/6 or
= (3/6)×100
= 50 %
Thus, the probability that Taylor will win the game is 3/6 or 50% option (B) is correct.
Learn more about the probability here:
brainly.com/question/11234923
#SPJ5
A football team scored fewer than 16 points in Saturday’s game. Than wants to write an inequality for the number of points. He uses the variable s in his inequality. What does s represent? A - the number of fans of the team
B - the number of games played by the team
C - the number of points scored by the team
D - the number of players on the team
Which statement is true regarding the graphed functions? On a coordinate plane, a straight red line with a positive slope, labeled g of x, crosses the x-axis at (negative 6, 0) and the y-axis at (0, 6). A straight blue line with a negative slope, labeled f of x, crosses the x-axis at (negative 0.75, 0) and the y-axis at (0, negative 2). f(4) = g(4) f(4) = g(–2) f(2) = g(–2) f(–2) = g(–2)
Answer:
none of the above
Step-by-step explanation:
The attached graph shows that none of f(-2), f(2), or f(4) matches any of g(-2) or g(4).
None of the offered statements is true.
___
Please report this problem to your teacher.
Answer:
The answer is not C
Step-by-step explanation:
I think the answer is D sooooo Pray it will be
UPDATE IT IS D
HOPE THIS HELP STAY SAFE
Consider a vat that at time t contains a volume V (t) of salt solution containing an amount Q(t) of salt, evenly distributed throughout the vat with a concentration c(t), where c(t) = Q(t) / V(t). Assume that water containing a concentration k of salt enters the vat at a rate rin, and that water is drained from the vat at a rate rout > rin.
(a) If V (0) = V0, find an expression for the amount of solution in the vat at time t. At what time T will the vat become empty? Find an initial value problem that describes the amount of salt in the vat at time t <= T. You may assume that Q(0) = Q0.
(b) Solve the initial value problem in part (a). What is the amount of salt in the vat at time t? What is the concentration of the last drop that leaves the vat at time t = T
Answer:
a.i [tex]\frac{dQ(t)}{dt} = kr_{in} - \frac{Q(t)r_{out} }{V_{0} + (r_{in} - r_{out} )t}\\\frac{dQ(t)}{dt} + \frac{Q(t)r_{out} }{V_{0} + (r_{in} - r_{out} )t} = kr_{in}[/tex]
ii. time at which vat will be empty
[tex]T = \frac{Q(T)r_{out} }{[V_{0} + (r_{in} - r_{out} )]kr_{in}}[/tex] when dQ/dt = 0
b. i Amount of salt at time t
Q(t) = [[exp(rout/(rin - rout)]krin[V(0)t + [exp(rout/(rin - rout)](rin - rout)t²/2 + Q(0)V(0)]/[V(0) + [exp(rout/(rin - rout)](rin - rout)t]
ii. Concentration at t = T
c(T) = [krin[(V(0)T + (rin - rout)T²/2)exp(rout/(rin - rout) + Q(0)V(0)]/([V(0) + exp(rout/(rin - rout)[(rin - rout)T]][V₀ + (rin - rout)T])
Step-by-step explanation:
a.
i. We determine the differential equation for the solution in the vat at time,t.
Let Q be the quantity of salt in the vat at any time,t.
So, dQ/dt = rate of change of quantity of salt in the vat. = rate of change of quantity of salt into the vat - rate of change of quantity of salt out of the vat.
Now, since a concentration of salt, k enter the vat at a rate of rin, rate of change of quantity of salt into the vat = krin.
Let V(0) = V₀ be the volume of water int the vat at time t = 0. Now, the volume of water in the vat increases at a rate of (rin - rout). The increase in volume after a time t is (rin - rout)t. So the volume after a time, t is V(t) = V₀ + (rin - rout)t. The concentration of this liquid is thus Q(t)/V(t) = Q(t)/V₀ + (rin - rout)t. Now, the rate of change of quantity of salt out of the vat is thus [Q(t)/V₀ + (rin - rout)t]rin = Q(t)rout/[V₀ + (rin - rout)t].
So, dQ(t)/dt = krin - Q(t)rout/[V₀ + (rin - rout)t].
[tex]\frac{dQ(t)}{dt} = kr_{in} - \frac{Q(t)r_{out} }{V_{0} + (r_{in} - r_{out} )t}\\\frac{dQ(t)}{dt} + \frac{Q(t)r_{out} }{V_{0} + (r_{in} - r_{out} )t} = kr_{in}[/tex]
ii Time T at which vat will be empty
At time T, when the vat is empty, dQ(T)/dt = 0.
So
[tex]\\\frac{dQ(T)}{dt} + \frac{Q(T)r_{out} }{V_{0} + (r_{in} - r_{out} )T} = kr_{in}\\0 + \frac{Q(T)r_{out} }{V_{0} + (r_{in} - r_{out} )T} = kr_{in}\\T = \frac{Q(T)r_{out} }{[V_{0} + (r_{in} - r_{out} )]kr_{in}}[/tex]
b. i
i. We solve the differential equation to find the amount of salt at time,t
The integrating factor is ex
[tex]exp(\int\limits {\frac{r_{out} }{V_{0} + (r_{in} - r_{out})t} } \, dt ) = exp(\frac{r_{out}}{(r_{in} - r_{out})} \int\limits {\frac{ (r_{in} - r_{out})}{V_{0} + (r_{in} - r_{out})t} } \, dt )\\= exp(\frac{r_{out}}{(r_{in} - r_{out})} ln [V_{0} + (r_{in} - r_{out})t} ]) \\\= [V_{0} + (r_{in} - r_{out})t} ]exp(\frac{r_{out}}{(r_{in} - r_{out})})[/tex]
Multiplying both side of the equation by the integrating factor, we have
[tex][V_{0} + (r_{in} - r_{out})t} ]exp(\frac{r_{out}}{(r_{in} - r_{out})})\frac{dQ(t)}{dt} + [V_{0} + (r_{in} - r_{out})t} ]exp(\frac{r_{out}}{(r_{in} - r_{out})})\frac{Q(t)r_{out} }{V_{0} + (r_{in} - r_{out} )t} = kr_{in}[V_{0} + (r_{in} - r_{out})t} ]exp(\frac{r_{out}}{(r_{in} - r_{out})})[/tex]dQ(t)[V(0) + (rin - rout)texp(rout/(rin - rout))]/dt = krin[V(0) + (rin - rout)texp(rout/(rin - rout))]
Integrating both sides we have
∫(dQ(t)[V(0) + (rin - rout)texp(rout/(rin - rout))]/dt)dt = ∫(krin[V(0) + (rin - rout)texp(rout/(rin - rout))])dt
Let exp(rout/(rin - rout) = A
Q(t)[V(0) + A(rin - rout)t] = Akrin[V(0)t + A(rin - rout)t²/2 + C
At t = 0, Q(t) = Q(0),
So,
Q(0)[V(0) + A(rin - rout)×0] = AkrinV(0)t + A(rin - rout)×0²/2 + C
C = Q(0)V(0)
Q(t)[V(0) + A(rin - rout)t] = Akrin[V(0)t + A(rin - rout)t²/2 + Q(0)V(0)
Q(t) = [[exp(rout/(rin - rout)]krin[V(0)t + [exp(rout/(rin - rout)](rin - rout)t²/2 + Q(0)V(0)]/[V(0) + [exp(rout/(rin - rout)](rin - rout)t]
The above is the amount of salt at time ,t.
ii. The concentration of the last drop of salt at time, t = T
To find the concentration of the last drop of salt at time t = T, we insert T into Q(t) to find its quantity and insert t = T into V(t) = V₀ + (rin - rout)t.
So
Q(T) = [Akrin[V(0)T + A(rin - rout)T²/2 + Q(0)V(0)]/[V(0) + A(rin - rout)T]
Q(T) = [[exp(rout/(rin - rout)]krin[V(0)T + [exp(rout/(rin - rout)](rin - rout)T²/2 + Q(0)V(0)]/[V(0) + [exp(rout/(rin - rout)](rin - rout)T]
the volume at t = T is
V(T) = V₀ + (rin - rout)T.
The concentration at t = T is c(T) = Q(T)/V(T) = [Akrin[V(0)T + A(rin - rout)T²/2 + Q(0)V(0)]/[V(0) + A(rin - rout)T]/V₀ + (rin - rout)T.
= [Akrin[V(0)T + A(rin - rout)T²/2 + Q(0)V(0)]/([V(0) + A(rin - rout)T][V₀ + (rin - rout)T])
= [krin[(V(0)T + (rin - rout)T²/2)exp(rout/(rin - rout) + Q(0)V(0)]/([V(0) + exp(rout/(rin - rout)[(rin - rout)T]][V₀ + (rin - rout)T])
Juan spins two different fair spinners. One spinner has numbers 1 through 8. The other has letters A through F. What is the probaility that one spinner will land on 3 and the other will land on C?
Answer:
...
Step-by-step explanation:
16x^4-25 Which pattern can we use to factor the expression?
Step-by-step explanation:
Hope this helps you... Lemme know if you don't understand
Instructions : integrate the following
You can simplify the integrand:
[tex]\dfrac{3x^2+4x+1}{2x}=\dfrac{3x}2+2+\dfrac1{2x}[/tex]
Then integrate term-by-term:
[tex]\displaystyle\int\frac{3x^2+4x+1}{2x}\,\mathrm dx=\frac32\int x\,\mathrm dx+2\int\mathrm dx+\frac12\int\frac{\mathrm dx}x[/tex]
[tex]=\dfrac{3x^2}4+2x+\dfrac12\ln|x|+C[/tex]
solve each of the equations below and classify them based on their solution.
1.) -8x - 3x= -11x
2.) 6x = -6y - 12
3.) -3z = 8 -z
4.) -5n = 3 - 5n
No Solution, Unique Solution, Infinitely many Solution
Answer:
Answers are below
Step-by-step explanation:
1.) No solution
2.) Unique solution
3.) Unique solution
4.) No solution
I graphed the equation that had a unique solution on the graph below.
If these answers are correct, please make me Brainliest!
I need help!!! And fast!!!!
Kim's business earns $10,000 per month. Kim's non-employee expenses are $3,000 per month. If Kim wants $2,000 in profit per month, how many employees can Kim have if each employee costs $1,000 per month?
Answer:
Kim's business earns $10,000 per month.
Kim's non-employee expenses are $3,000 per month.
If Kim wants $2,000 in profit per month, then the maximum amount Kim can spend for employee:
10000 - 3000 - 2000 =5000
If each employee costs $1,000 per month, Kim can recruit 5000/1000 = 5 as the maximum number of employees.
Hope this helps
:)
Answer:
5
Step-by-step explanation:
Revenue - profit = expense
10000 - 2000 = 8000
8000 = 3000 + 1000n
1000n = 5000
n = 5
In the following shape, two semicircles have been placed at the end of a rectangle whose length is twice its height. Which of the following gives the length around this figure in terms of the semicircle's radius, r?
Answer:
Perimeter of the figure is 2r([tex]\pi[/tex] + 6)
Step-by-step explanation:
Perimeter of a shape is total length of the boundaries of the shape. In the given question, we have two semicircles and a rectangle.
The circumference of a circle = 2[tex]\pi[/tex]r, thus the length of the arc of a semicircle = [tex]\pi[/tex]r.
The height of the rectangle is h, radius 'r' of the semicircle = [tex]\frac{h}{2}[/tex]
⇒ h = 2r
The perimeter of a rectangle = 2(l +b).
Given that: the length is twice its height, so that:
length = 2h
Perimeter of the rectangle = 2 (2h + h)
= 6h
But, h = 2r
Perimeter of the rectangle = 6 × 2r
= 12r
Perimeter of the figure in terms of the semicircle's radius = [tex]\pi[/tex]r + 12r + [tex]\pi[/tex]r
= 2[tex]\pi[/tex]r + 12r
= 2r([tex]\pi[/tex] + 6)
Calculate CDEFtrapezium
｡☆✼★ ━━━━━━━━━━━━━━ ☾
You need to find the length of A F and BC first
Lets call BC --> 'x'
Lets form an equation
9 + 9 + x + x = 28
18 + 2x = 28
- 18
2x = 10
/ 2
x = 5
So now we have the length BC
We can subtract this length from the 11cm to find the vertical height of the trapezium
11 - 5 = 6
Now we have all we need to work it out.
area = (a + b) / 2 x h
area = (5 + 9) / 2 x 6
area = 42 cm^2
Have A Nice Day ❤
Stay Brainly! ヅ
- Ally ✧
｡☆✼★ ━━━━━━━━━━━━━━ ☾
Answer:
42 cm²
Step-by-step explanation:
We can see this shape is made of 2 shapes that we are familiar with which are a rectangle and a trapezium.
⇒ The first step in working out the area of the trapezium is working out the length of CB and then working out the height of trapezium. We are given that the perimeter of the rectangle is 28 cm and we know that opposite sides of a rectangle are equal so we will call the length we want to work out x
→ x + x + 9 + 9 = 28
⇒ Simplify
→ 2x + 18 = 28
⇒ Minus 18 from both sides to isolate 2x
→ 2x = 10
⇒ Divide both sides by 5 to isolate x
→ x = 5
5 cm is the length of CB, we will need to minus that from 11 to find the height of the trapezium so,
11 - 5 = 6. The height of the trapezium is 6
Now we have the height of the trapezium (6), we have the base (9) and we have the top length (5). All we do now is substitute these numbers into the trapezium formula which is
→ 0.5 × ( a + b ) × h
Where 'a' and 'b' are the parallel sides and 'h' is the height
Now we begin to substitute in the values,
→ 0.5 × ( a + b ) × h
⇒ Substitute in the values
→ 0.5 × ( 5 + 9 ) × 6
⇒ Simplify
→ 0.5 × ( 14 ) × 6
⇒ Simplify further
→ 42
The area of the trapezium is 42 cm²
helpp me nowwwwwww dew Help Marshmello i wasn't born yesterday. xd
Answer: A) DE = 24 yd and EF = 10 yd
Step-by-step explanation:
Shape EFD is just a dilate of 2, meaning BCA x 2.
13 x 2 = 26
12 x 2 = 24
5 x 2 = 10
Therefore, DE = 24 yd and EF = 10 yd
I hope this helps!
Answer:
DE = 24, EF = 10
Step-by-step explanation:
We can use ratios to solve
13 ft 12 ft
---------- = -----------
26 ft x ft
Using cross products
13x = 12*26
Divide each side by 13
13x/13 = 12*26/13
x = 24
13 ft 5 ft
---------- = -----------
26 ft y ft
Using cross products
13y = 5*26
Divide each side by 13
13y/13 = 5*26/13
y = 10
A row of tiny red beads is placed at the beginning and at the end of a 20‐centimeter bookmark.
A row of the same beads is also placed every 4 millimeters along the bookmark.
How many rows of the beads are used on the bookmark?
Answer:
51 rows
Step-by-step explanation:
Given
Length of bookmark = 20cm
Distance between beads = 4mm
Required
Number of rows of beads
First, the distance between the rows of beads must be converted to cm
if 1mm = 0.1cm
then
4mm = 4*0.1cm
4mm = 0.4 cm
This means that each row of beads is placed at 0.4 cm mark.
The distance between each row follows an arithmetic progression and it can be solved as follows;
[tex]T_n = a + (n-1)d[/tex]
Where [tex]Tn = 20cm[/tex] (The last term)
[tex]a = 0 cm[/tex] (The first term)
[tex]d = 0.4cm[/tex] (The distance between each row of beads)
n = ?? (number of rows)
Solving for n; we have the following;
[tex]T_n = a + (n-1)d[/tex] becomes
[tex]20 = 0 + (n-1)0.4[/tex]
[tex]20 = (n-1)0.4[/tex]
DIvide both sides by 0.4
[tex]\frac{20}{0.4} = \frac{(n-1)0.4}{0.4}[/tex]
[tex]50 = (n-1)[/tex]
[tex]50 = n-1[/tex]
Add 1 to both sides
[tex]50 + 1= n-1 + 1[/tex]
[tex]n = 51[/tex]
Hence, the number of rows of beads is 51
graph y=-2/3x-3 i need help quick
Answer: just get gud at math lol
Step-by-step explanation: no
what is 8 - 3x > -25 because i have been wondering all day
Answer:
[tex]8 - 3x > -25 : \left[\begin{array}{ccc}solution: x < 11\\Interval Notation:(-\infty,11)\end{array}\right][/tex]
Step-by-step explanation:
[tex]8-3x>-25[/tex]
Subtract [tex]8[/tex] from both sides:
[tex]8-3x-8>-25-8[/tex]
Simplify:
[tex]-3x>-33[/tex]
Multiply both sides by [tex]-1[/tex] (reverse the inequality):
[tex]\left(-3x\right)\left(-1\right)<\left(-33\right)\left(-1\right)[/tex]
Simplify:
[tex]3x<33[/tex]
Divide both sides by [tex]3[/tex] :
[tex]\frac{3x}{3}<\frac{33}{3}[/tex]
Simplify:
[tex]x < 11[/tex]
Hope I helped. If so, may I get brainliest and a thanks?
Thank you, have a good day! =)
Of the 34 cars in the parking lot, 12 are blue, 8 are red, 4are white, and 10 are silver. In simplest form, what are the odds in favor that the next car that leaves the lot will be red or white
Answer:
0.3529411765
Step-by-step explanation:
add red and white and divide it by the total
plzzzzzzzz i need help
Michael is cutting a 100-yard ribbon into pieces 3.4 yards long. He says that an inequality that represents his project is 3.4x < 100. Explain what this statement means, in words, and what each part of the inequality represents.
Answer:
Okay well the 3.4 yard pieces are the constant in which Michael will be cuttings that number stays the same an will not change. The (X) represents the unknown number of how many times the ribbon will be cut. As the whole inequality states the unknown number of pieces that are 3.4 yards long are less than 100 yards.
Answer:
The variable, x, is the number of pieces of ribbon Michael cuts. Since each piece is 3.4 yards long, 3.4x is the total length of all the pieces together. This total length cannot be more than the 100 yards of ribbon he has, so 3.4x must be less than or equal to 100.
list down all the prime numbers which are factors of 30
Hey!!
Here's your answer:
prime numbers which are factors of 30 are:
1,2,3 and 5
Hope it helps
Answer:
1, 2, 3, 5
sorry for the confusion i didn't read it correctly
How many 2-letter words can be made from the letters MATH if
Answer:
ham
tam
mat
hat
at
ha
am
ma
Step-by-step explanation:
Use substitution to solve each system of equations:
x=y+6
x+y=10