Mr. Patel bought lunch at a restaurant for $7.35. If he paid with a $10.00 bill, how much change did he get back?

A.
$2.55

B.
$2.65

C.
$3.35

D.
$3.65

Answer:

95km

Step-by-step explanation:

5 days = 375km

4 days = 67km + 78km + 46km + 89km= 280km

5 days - 4days = the 5th day

375km - 280km = 95km

Answer:

no solution

Step-by-step explanation:

when you distribute, the 6x on each side cancel out leaving there to be no solution to the problem. I attached a photo of my work as well.

Answer:

The answer is False meaning it's no solution

Step-by-step explanation:

1. Distribute 3 through the parentheses which will be 6x+12=6x+10

2.Cancel equal terms on both sides of the equation and you will get 12=10 which isn't a true statement.

Step-by-step explanation:

Answered 1 year, 9 months ago

Given,

Principal, P =Rs.10000,  Rate, R = 8% per annum compounded half yearly for 1 year. 

Now, There are two half years in a year. Therefore compounding has to be 2 times. 

And rate = half of 10% = 5% half yearly.

Therefore, the required amount =   = Rs. 10816

And Compound Interest, C.I. = Amount - Principal = Rs. (10816 - 10000) = Rs. 816.

hope it helps you

Answer:

B or D, I can't tell from these answer choices.  X-8

Step-by-step explanation:

Shanique has 8 less questions than John (X).

Answer:

[tex]A_1 = 24m^2[/tex] -- Swing set

[tex]A_2 = 16m^2[/tex] -- Slide

[tex]A_3 = 5m^2[/tex] --- Pathway

Step-by-step explanation:

Missing part of the question:

Fill in the table above to show the area of each section (see attachment for table)

The area of each section is calculated as:

[tex]Area = Length * Width[/tex]

For the Swing set

[tex]A_1 = 8m * 3m[/tex]

[tex]A_1 = 24m^2[/tex]

For the Slide

[tex]A_2 = 8m * 2m[/tex]

[tex]A_2 = 16m^2[/tex]

For the Pathway

[tex]A_3 = 5m * 1m[/tex]

[tex]A_3 = 5m^2[/tex]

The total area is:

[tex]Area=A_1 + A_2 + A_3[/tex]

[tex]Area = 24m^2 + 16m^2 + 5m^2[/tex]

[tex]Area = 45m^2[/tex]

Answer:

another one ayy ok let me think

Step-by-step explanation:

b

Answer:

I believe is A

Step-by-step explanation:

20/4=5

4/4=1

because the ratio is friends to fluid ounces the answer would be 1:5

Answer: The ratio of eggs, eggs, to two cups of flour. Let me write two cups of flour. Cups of flour. In either case is, is four eggs for every three cups of flour 5/2

Step-by-step explanation: Im not sure through

Answer:0.028

Step-by-step explanation: 0.07 x 0.4= 0.028

Answer:

I DONT KNOW!!

Step-by-step explanation:

Answer:

First option is the correct answer.

[tex] (m + n - 1) \sqrt{p} [/tex]

Step-by-step explanation:

[tex]m\sqrt{p} + n\sqrt{p} - \sqrt{p} \\ \\ = (m + n - 1) \sqrt{p} [/tex]

Answer:

its 4.8

Step-by-step explanation:

i divided 7.5 by 12.5 and got 0.6 and added 4.2 and got 4.8

Equation is formed of two expressions. The amount of water that is used by Sofia to make the slime is 4.8 fl oz.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Let the amount of salt solution used by Sofia be x, and the amount of water used by Sofia be y.

As it is given that the amount of glue used is 12.5 times the amount of salt solution used, and the amount of glue used is 7.5 fl oz. Therefore, the equation can be written as,

Amount of glue = 12.5 x Amount of salt solution

[tex]7.5 = 12.5 \times x\\\\x = \dfrac{7.5}{12.5}\\\\x = 0.6[/tex]

Also, it is given that the amount of water used is 4.2 fl oz. less than the amount of salt solution used, since we know the amount of salt solution used, therefore, the equation can be written as,

Amount of salt solution = Amount of water - 4.2 oz

[tex]x = y -4.2\\\\(0.6)=y-4.2\\\\y = 4.8[/tex]

Hence, the amount of water that is used by Sofia to make the slime is 4.8 fl oz.

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Answer:

The number to use are 10, 7, 20 and 3.

Step-by-step explanation:

Given

[tex]17 * 23[/tex]

Required

Which numbers would be used using the area model or partial products

The number to use are 10, 7, 20 and 3.

This is shown below:

[tex]\begin{array}{ccc}{ } & {10} & {7} & {20} & { } & { } \ \\ {3} & { } & { } \ \end{array}[/tex]

When the numbers are multiplied, we get:

[tex]\begin{array}{cccc}{ } & {10} & {7} & {} & {20} & {200} &{140} &{=340}\ \\ {3} & {30 } & {21 } &{=51} \ \end{array}[/tex]

[tex]Total = 340 + 51[/tex]

[tex]Total = 391[/tex]

Answer:

1 and 7/10 pounds?

Step-by-step explanation:

because if its 4/10 more you add 3/10 and 4/10 im pretty sure

Answer:

PLEASE MARK BRAInliest

Step-by-step explanation:

tweety weighed 17/10 pounds last year.

Answer:

1 i know its one hope it help

Step-by-step explanation:

List all prime factors for each number.

Prime Factorization of 2 shows:

2 is prime  =>  21

Prime Factorization of 7 shows:

7 is prime  =>  71

Prime Factorization of 8 is:

2 x 2 x 2  =>  23

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is

2, 2, 2, 7

Multiply these factors together to find the LCM.

LCM = 2 x 2 x 2 x 7 = 56

In exponential form:

LCM = 2^3 x 7^1 = 56

LCM = 56

Therefore,

LCM(2, 7, 8) = 56

Given:

The equation is

[tex]y=5x^3-6x^2-4x+8[/tex]

To find:

The coordinates of the turning point.

Solution:

We have,

[tex]y=5x^3-6x^2-4x+8[/tex]

Differentiate with respect to x.

[tex]\dfrac{dy}{dx}=5(3x^2)-6(2x)-4(1)+(0)[/tex]

[tex]\dfrac{dy}{dx}=15x^2-12x-4[/tex]

For the turning points [tex]\dfrac{dy}{dx}=0[/tex].

[tex]15x^2-12x-4=0[/tex]

Using quadratic formula:

[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\dfrac{-(-12)\pm \sqrt{(-12)^2-4(15)(-4)}}{2(15)}[/tex]

[tex]x=\dfrac{12\pm \sqrt{144+240}}{30}[/tex]

[tex]x=\dfrac{12\pm \sqrt{384}}{30}[/tex]

Now,

[tex]x=\dfrac{12+\sqrt{384}}{30}\text{ and }x=\dfrac{12-\sqrt{384}}{30}[/tex]

[tex]x\approx 1.053\text{ and }x\approx-0.253[/tex]

Putting x=1.053 in the given equation, we get

[tex]y=5(1.053)^3-6(1.053)^2-4(1.053)+8[/tex]

[tex]y\approx 2.973[/tex]

Putting x=−0.253 in the given equation, we get

[tex]y=5(-0.253)^3-6(-0.253)^2-4(-0.253)+8[/tex]

[tex]y\approx 8.547[/tex]

Therefore, the turning points are (1.053,2.973) and (-0.253, 8.547).

Answer:

120 deg

Step-by-step explanation:

There is an angle symbol in the equilateral triangle and another symbol in half of the vertex angle. Those two angles are congruent.

The measure of the vertex angle is 2 * 60 deg = 120 deg

Answer: 120 deg

Answer:

1. A=πr2=π·4.62≈66.4761

A≈66.48

2. A=πr2=π·22≈12.56637

A≈12.57

please mark as brainiest

Answer:

1. 66.48

2. 12.57

Step-by-step explanation:

Formula is A = ㅠr^2

The radius is that half line :))

Answer:

Step-by-step explanation:

Since there are four aces and 52 total cards.

P(A)=4/52=1/13

Answer:

The probability that you would draw an ace in a deck of cards would be 8%

Answer:

b my

Step-by-step explanation:

valentines

bbg

In the kitchen triangle,  the largest angle will be at counter

A triangle is a three-sided polygon that consists of three edges and three vertices.

Given that kitchens have a working triangle between the sink (S), the counter (C), and the oven (O).

The distance between the sink in the oven is 8 feet.

The distance between the sink and the counter is 6 feet,

The distance between the oven and the counter at 7 feet.

we need to find in the kitchen triangle, where is the largest angle

SO=8

SC=6

OC=7

Hence, in the kitchen triangle,  the largest angle will be at counter

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Answer:

[tex]\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}= \frac{(x+3)}{x}[/tex]

[tex]\frac{3x^2 - 5x - 2}{x^3 - 2x^2} = \frac{3x + 1}{x^2}[/tex]

[tex]\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}=-\frac{5}{2x}[/tex]

[tex]\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x} = \frac{-(x-3)^2}{25}[/tex]

[tex]\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}= x +1[/tex]

[tex]\frac{9x^2 + 3x}{6x^2} = \frac{3x + 1}{2x}[/tex]

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x} = 3x[/tex]

Step-by-step explanation:

Required

Simplify

Solving (1):

[tex]\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}[/tex]

Factorize the numerator and the denominator

[tex]\frac{x^2(x + 2) -9(x+2)}{x(x^2-x-6)}[/tex]

Factor out x+2 at the numerator

[tex]\frac{(x^2 -9)(x+2)}{x(x^2-x-6)}[/tex]

Express x^2 - 9 as difference of two squares

[tex]\frac{(x^2 -3^2)(x+2)}{x(x^2-x-6)}[/tex]

[tex]\frac{(x -3)(x+3)(x+2)}{x(x^2-x-6)}[/tex]

Expand the denominator

[tex]\frac{(x -3)(x+3)(x+2)}{x(x^2-3x+2x-6)}[/tex]

Factorize

[tex]\frac{(x -3)(x+3)(x+2)}{x(x(x-3)+2(x-3))}[/tex]

[tex]\frac{(x -3)(x+3)(x+2)}{x(x+2)(x-3)}[/tex]

Cancel out same factors

[tex]\frac{(x+3)}{x}[/tex]

Hence:

[tex]\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}= \frac{(x+3)}{x}[/tex]

Solving (2):

[tex]\frac{3x^2 - 5x - 2}{x^3 - 2x^2}[/tex]

Expand the numerator and factorize the denominator

[tex]\frac{3x^2 - 6x + x - 2}{x^2(x- 2)}[/tex]

Factorize the numerator

[tex]\frac{3x(x - 2) + 1(x - 2)}{x^2(x- 2)}[/tex]

Factor out x - 2

[tex]\frac{(3x + 1)(x - 2)}{x^2(x- 2)}[/tex]

Cancel out x - 2

[tex]\frac{3x + 1}{x^2}[/tex]

Hence:

[tex]\frac{3x^2 - 5x - 2}{x^3 - 2x^2} = \frac{3x + 1}{x^2}[/tex]

Solving (3):

[tex]\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}[/tex]

Express x^2 - 9 as difference of two squares

[tex]\frac{6 - 2x}{x^2 - 3^2} * \frac{15 + 5x}{4x}[/tex]

Factorize all:

[tex]\frac{2(3 - x)}{(x- 3)(x+3)} * \frac{5(3 + x)}{2(2x)}[/tex]

Cancel out x + 3 and 3 + x

[tex]\frac{2(3 - x)}{(x- 3)} * \frac{5}{2(2x)}[/tex]

[tex]\frac{3 - x}{x- 3} * \frac{5}{2x}[/tex]

Express [tex]3 - x[/tex] as [tex]-(x - 3)[/tex]

[tex]\frac{-(x-3)}{x- 3} * \frac{5}{2x}\\[/tex]

[tex]-1 * \frac{5}{2x}[/tex]

[tex]-\frac{5}{2x}[/tex]

Hence:

[tex]\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}=-\frac{5}{2x}[/tex]

Solving (4):

[tex]\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x}[/tex]

Expand x^2 - 6x + 9 and factorize 5x - 15

[tex]\frac{x^2 -3x -3x+ 9}{5(x - 3)} / \frac{5}{3-x}[/tex]

Factorize

[tex]\frac{x(x -3) -3(x-3)}{5(x - 3)} / \frac{5}{3-x}[/tex]

[tex]\frac{(x -3)(x-3)}{5(x - 3)} / \frac{5}{3-x}[/tex]

Cancel out x - 3

[tex]\frac{(x -3)}{5} / \frac{5}{3-x}[/tex]

Change / to *

[tex]\frac{(x -3)}{5} * \frac{3-x}{5}[/tex]

Express [tex]3 - x[/tex] as [tex]-(x - 3)[/tex]

[tex]\frac{(x -3)}{5} * \frac{-(x-3)}{5}[/tex]

[tex]\frac{-(x-3)(x -3)}{5*5}[/tex]

[tex]\frac{-(x-3)^2}{25}[/tex]

Hence:

[tex]\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x} = \frac{-(x-3)^2}{25}[/tex]

Solving (5):

[tex]\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}[/tex]

Factorize the numerator and expand the denominator

[tex]\frac{x^2(x - 1) -1(x - 1)}{x^2 - x-x+1}[/tex]

Factor out x - 1 at the numerator and factorize the denominator

[tex]\frac{(x^2 - 1)(x - 1)}{x(x -1)- 1(x-1)}[/tex]

Express x^2 - 1 as difference of two squares and factor out x - 1 at the denominator

[tex]\frac{(x +1)(x-1)(x - 1)}{(x -1)(x-1)}[/tex]

[tex]x +1[/tex]

Hence:

[tex]\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}= x +1[/tex]

Solving (6):

[tex]\frac{9x^2 + 3x}{6x^2}[/tex]

Factorize:

[tex]\frac{3x(3x + 1)}{3x(2x)}[/tex]

Divide by 3x

[tex]\frac{3x + 1}{2x}[/tex]

Hence:

[tex]\frac{9x^2 + 3x}{6x^2} = \frac{3x + 1}{2x}[/tex]

Solving (7):

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x}[/tex]

Change / to *

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} * \frac{x}{x-1}[/tex]

Expand

[tex]\frac{x^2-2x-x+2}{4x} * \frac{12x^2}{x^2 - 2x} * \frac{x}{x-1}[/tex]

Factorize

[tex]\frac{x(x-2)-1(x-2)}{4x} * \frac{12x^2}{x(x - 2)} * \frac{x}{x-1}[/tex]

[tex]\frac{(x-1)(x-2)}{4x} * \frac{12x^2}{x(x - 2)} * \frac{x}{x-1}[/tex]

Cancel out x - 2 and x - 1

[tex]\frac{1}{4x} * \frac{12x^2}{x} * \frac{x}{1}[/tex]

Cancel out x

[tex]\frac{1}{4x} * \frac{12x^2}{1} * \frac{1}{1}[/tex]

[tex]\frac{12x^2}{4x}[/tex]

[tex]3x[/tex]

Hence:

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x} = 3x[/tex]

Answer:

[tex]c. \\ x(x+3)[/tex]

Step-by-step explanation:

Answer:

C)

Step-by-step explanation:

Answer:

The constant is 2.50

I believe the equation would look like 2.5x=17.5

and x would equal 7

Answer:

$900

Step-by-step explanation:

Given that:

Principal, p = 5000

Interest, r = 6%

Period, t = 3 years

Using the relation :

Simple interest = Principal * Rate * Time

Simple interest = $5000 * 0.06 * 3

Simple interest = $900

Hence, amount of interest earned = $900

Answer: The answer is 9a^2 - 3a + 1/4

Step-by-step explanation:

Hope this helpfull.

But Im so sorry if this not helpfully

Answer:

What is the area, in square inches, of the trapezoid below? 15.7 in 8 in 6.6 in​-by-step explanation:

The area, in square inches, of the trapezoid, is 89.2 in².

We have given that,

A = 89.2 in²

The area (A) of a trapezoid is calculated as,

A = 1/2 h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 8, b₁ = 6.6, b₂ = 15.7 , then

A = 1/2 × 8 × (6.6 + 15.7)

A= 4 × 22.3

A= 89.2 in²

The area, in square inches, of the trapezoid, is 89.2 in².

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Answer:

V = pi x radius x 2 x height OR pi x diameter x height

Hope that helps!

Answer:

the formula for the volume of a cylinder is V=πr²h

Answer:

Step-by-step explanation:

Answer:

54 inches

Step-by-step explanation:

6/18=7/x

6x=7(18)

6x=126

x=21

21+15=18=54