Mention four importance of writing the physical quantities as vectors.​

Answer:

y = 1.75 cm

Explanation:

In the double-slit experiment the equation for destructive interference is

           d sin tea = (m + ½)

λ

let's use trigonometry to find the angle

         tan θ = y / L

as all the experiment does not occur at small angles

          tan θ = sin θ / cos θ = sin θ = y / L

we substitute

        y = (m + 1/2 ) λ  L / d

we calculate

         y = (3 + ½) 500 10⁻⁹ 5.00 / 0.5 10⁻³

         y = 1.75 10⁻² m

         y = 1.75 cm

Complete Question

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Answer:

[tex]v = 3.4 \ m/s[/tex]

Explanation:

From the question we are told that

   The mass of the collar is  [tex]m = 2 \ kg[/tex]

    The original length is  [tex]L = 3.0 \ m[/tex]

     The spring constant is  [tex]k = 3.0 \ N/m[/tex]

Generally the extension of the spring  is  mathematically evaluated as

        [tex]e = 4 -3 = 1 \ m[/tex]

Now with Pythagoras theorem we can obtain the length from A to B as

        [tex]AB = \sqrt{5 ^2 + 4^2}[/tex]

       [tex]AB = 6.4 \ m[/tex]

The  extension of the spring at B is  

     [tex]e_b = 6.4 - 3 = 3.4 \ m[/tex]

According to the law of energy conservation

   The energy stored in the spring at point A +  the kinetic energy of the  spring =  The  energy stored on the spring at B

So

     [tex]\frac{1}{2} * k * e + \frac{1}{2} * m* v^2 = \frac{1}{2} * k * e_b[/tex]

substituting values

    [tex]\frac{1}{2} * 3 * 1^2 + \frac{1}{2} * 2* v^2 = \frac{1}{2} * 3 * 3.4^2[/tex]

=>   [tex]v = 3.4 \ m/s[/tex]

Answer:

The  pressure difference is  [tex]\Delta P = 1.46 *10^{5}\ Pa[/tex]

Explanation:

From the question we are told that

   The  density is  [tex]\rho = 1250 \ kg/m^3[/tex]

   The  speed at location 1  is  [tex]v_1 = 9.93 \ m/s[/tex]

    The  diameter at location 1 is  [tex]d_1 = 11.1\ cm = 0.111 \ m[/tex]

     The  diameter at location 2 is  [tex]d_1 = 16.7\ cm = 0.167 \ m[/tex]

     The  height at location 1 is  [tex]h_1 = 8.89 \ m[/tex]

       The  height at location 2  is  [tex]h_2 = 1 \ m[/tex]

Generally the cross- sectional area at location 1 is mathematically represented as

       [tex]A_1 = \pi * \frac{d^2}{4}[/tex]

=>     [tex]A_1 = 3.142 * \frac{ 0.111^2}{4}[/tex]

=>     [tex]A_1 = 0.0097 \ m^2[/tex]

Generally the cross- sectional area at location 2 is mathematically represented as

           [tex]A_2 = \pi * \frac{d_1^2}{4}[/tex]

=>     [tex]A_2= 3.142 * \frac{ 0.167^2}{4}[/tex]

=>     [tex]A_2 =0.0219 \ m^2[/tex]

From continuity formula

       [tex]v_1 * A_1 = v_2 * A_2[/tex]

=>     [tex]v_2 = \frac{A_1 * v_1}{A_2 }[/tex]

=>      [tex]v_2 = \frac{0.0097 * 9.93}{0.0219 }[/tex]

=>      [tex]v_2 = 4.398 \ m/s[/tex]

Generally according to Bernoulli's theorem

     [tex]P_1 + \rho * g * h_1 + \frac{1}{2} \rho * v_1^2 = P_2 + \rho * g * h_2 + \frac{1}{2} \rho * v_2^2[/tex]

=>   [tex]P_2 - P_1 = \frac{1}{2} \rho (v_1 ^2 - v_2^2 ) + \rho* g (h_1 - h_2)[/tex]

=> [tex]\Delta P = \frac{1}{2}* 1250* (9.93 ^2 - 4.398^2 ) + 1250* 9.8 (8.89- 1)[/tex]

=> [tex]\Delta P = 1.46 *10^{5}\ Pa[/tex]

Answer:

a) The planet experiences a centripetal force towards its star

b) The universal attractive force (Gravitational force)

c)None of these choices are true.

Explanation:

This problem raise several claims, let's review some aspects of circular motion

            F = m a

the centripetal acceleration is

            a = v² / r

where v is the speed (modulus of velocity) that is constant and r is the radius

The direction of the acceleration is perpendicular to the motion.

Let's review the different claims

Part a) the orbital velocity is constant

The correct statement is: The planet experiences a centripetal force towards its star

Part b) what is the centripetal force

The correct statement: The universal attractive force (Gravitational force)

Part c) which statement is true

1) False. There can be no tangential force

2) False. There is a centripetal force that creates the movement, but there is no centrifugal force because the system is accelerated and there is no tangential force because the movement is circular.

3) False. There is no tangential force

4) True none is true

5) False. There is a force because movement has acceleration

Answer:

To find out the area of the hot filament of a light bulb, you would need to know the temperature, the power input, the Stefan-Boltzmann constant and Emissivity of the Filament.

Explanation:

The emissive power of a light bulb can be given by the following formula:

E = σεAT⁴

where,

E = Power Input or Emissive Power

σ = Stefan-Boltzmann constant

ε = Emissivity

A = Area

T = Absolute Temperature

Therefore,

A = E/σεT⁴

So, to find out the area of the hot filament of a light bulb, you would need to know the temperature, the power input, the Stefan-Boltzmann constant and Emissivity of the Filament.

Answer:

3.1 × 10^- 7 m and 2.1 × 10^-7 m

Explanation:

First we must convert each value of energy to Joules by multiplying its value by 1.6 ×10^-19. After that, we can now obtain the wavelength from E= hc/λ

Where;

h= planks constant

c= speed of light

λ= wavelength of light

For 6.0ev;

E= 6.0 × 1.6 ×10^-19

E= 9.6 × 10^-19 J

From

E= hc/λ

λ= hc/E

λ= 6.6 × 10^-34 × 3 × 10^8/9.6 × 10^-19

λ= 2.1 × 10^-7 m

For 4.0 eV

4.0 × 1.6 × 10^-19 = 6.4 × 10^-19 J

E= hc/λ

λ= hc/E

λ= 6.6 × 10^-34 × 3 × 10^8/6.4 × 10^-19

λ= 3.1 × 10^- 7 m

(a) The wavelength of the atom's emission spectrum when the energy is 4 eV is [tex]3.1 \times 10^{-7} \ m[/tex]

(b) The wavelength of the atom's emission spectrum when the energy is 6 eV is

[tex]2.1 \times 10^{-7} \ m[/tex]

The wavelength of the atom's emission spectrum is calculated as follows;

[tex]E = hf\\\\E = \frac{hc}{\lambda}[/tex]

where;

For 4 eV;

[tex]\lambda = \frac{hc}{E} \\\\\lambda = \frac{(6.626 \times 10^{-34}) \times 3\times 10^8}{4 \times 1.602 \times 10^{-19}} \\\\\lambda = 3.1 \times 10^{-7} \ m[/tex]

For 6 eV;

[tex]\lambda = \frac{hc}{E} \\\\\lambda = \frac{(6.626 \times 10^{-34}) \times 3\times 10^8}{6 \times 1.602 \times 10^{-19}} \\\\\lambda = 2.1 \times 10^{-7} \ m[/tex]

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Answer:

yes it was a constant speed and the car traveled 10 meters in 20 seconds.

Explanation:

Answer:

It's a constant speed and the car traveled 10 meters in 20 seconds.

hope this helps!

Explanation:

Answer:

32.13 N

Explanation:

Given that

mass of the crate, m = 3 kg

angle of inclination, = 35°

coefficient of static friction, = 0.3

To solve this, we can assume that the minimum force is F Newton, then use the formula

mgsinA = coefficient of static friction * [F + mgcosA]

=>3 * 9.8 * sin35 = 0.3 * [F + 3 * 9.8 * cos35]

=> 29.4 * 0.5736 = 0.3 * [F + 29.4 * 0.8192]

=> 16.86 = 0.3 [F + 24.08]

=> 16.86 = 0.3F + 7.22

=> 16.86 - 7.22 = 0.3F

=> 0.3F = 9.64

=> F = 9.64/0.3

=> F = 32.13 N

Therefore, the Force that must be applied is 32.13 N

The  net force that must be applied is  9.8 N.

The minimum force required is Fnet.

Fnet = -Ff + mgsinθ

But Ff = μN = μmgcosθ

Fnet = - μmgcosθ + mgsinθ

Where;

m = 3.00 kg

μ =  0.300

θ = 35.0o

Substituting values;

Fnet = mgsinθ - μmgcosθ

Fnet = (3 × 10 × sin 35.0o) - (3 × 0.300  × 10 × cos  35.0o)

= 17.2 - 7.4

Fnet = 9.8 N

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Answer:

a. d.

Explanation:

isotopes have a diff number of neutrons

Answer:

See the explanation

Explanation:

Given:

Distance of Firecrackers A and B = 600 m

Event 1 = firecracker 1 explodes

Event 2 = firecracker 2 explodes

Distance of lab partner from cracker A = 300 m

You observe the explosions at the same time

to find:

does event 1 occur before, after, or at the same time as event 2?

Solution:

Since the lab partner is at 300 m distance from the firecracker A and Firecrackers A and B are 600 m apart

So the distance of fire cracker B from the lab partner is:

600 m  + 300 m = 900 m

It takes longer for the light from the more distant firecracker to reach so

Let T1 represents the time taken for light from firecracker A to reach lab partner

T1 = 300/c

It is 300 because lab partner is 300 m on other side of firecracker A

Let T2 represents the time taken for light from firecracker B to reach lab partner

T2 = 900/c

It is 900 because lab partner is 900 m on other side of firecracker B

T2 = T1

900 = 300

900 = 3(300)

T2 = 3(T1)

Hence lab partner observes the explosion of the firecracker A before the explosion of firecracker B.

Since event 1 = firecracker 1 explodes and event 2 = firecracker 2 explodes

So this concludes that lab partner sees event 1 occur first and lab partner is smart enough to correct for the travel time of light and conclude that the events occur at the same time.

Answer:

mA=2,mB=4

mA=2,mB=4 and

mA=3,mB=6

Explanation:

First of all we need to write the equation of the networks

sin θ = mA λ / dA

sin θ = mB λ / dB

Equating we have

mA λ/ dA = mB λ / dB

We are given the ratio as

dB / dA = 2

So

mA 2 = mB

Finally overlapping orders

We have

mA=2,mB=4

mA=2,mB=4

and mA=3,mB=6

Answer:

Transverse

Explanation:

It's tranverse because the water molecules are moving repeatedly up and down vertically when the waves move horizontally across the waters surface.

Answer:

24.7°C

Explanation:

Heat lost by brass = heat gained by aluminum and water

-q = q

-mCΔT = mCΔT + mCΔT

-(50 g) (0.380 J/g/°C) (T − 200°C) = (50 g) (0.900 J/g/°C) (T − 20°C) + (160 g) (4.186 J/g/°C) (T − 20°C)

-(19 J/°C) (T − 200°C) = (45 J/°C) (T − 20°C) + (670 J/°C) (T − 20°C)

-(19 J/°C) (T − 200°C) = (715 J/°C) (T − 20°C)

-19 (T − 200°C) = 715 (T − 20°C)

-19T + 3800°C = 715T − 14300°C

18100°C = 734T

T = 24.7°C

Answer:

98 N.

Explanation:

Given data: mass= 10 kg,      gravity= 9.8 m/s2

required: tension in the cord=  ?

solution:

formula of tension= mass x gravity

by putting values of mass and gravity, we get

tension= 10 x 9.8

tension= 98 N.  Ans

If the mass of the object which is attached with both ends of cord is 10 kg, so the tension which is a opposite force of weight is 98 N.

Answer:

OB.It has definite shape and definite volume

Mass of fish is 5.09Kg

Explanation:

First to find the spring constant K using

k = F/s

= 220/0.15 = 1466.7 N/m

So using the formula

T = 2π√(m/k)

f = 1/T = 1/2πx √(k/m)

f² x 4π²= k/m

So

m = k/(f² x π²)

m = 1466.7/(2.7² x 4π²)

m = 5.09 kg

Answer:

10⁻¹² W / m²

Explanation:

The feeble sound that a man can hear is of the vale which measures 0 on decibel scale . The intensity of sound in terms of J / m² .s is 10⁻¹² W / m² .

So the intensity of sound of monkey at 2.5 km must be 10⁻¹² W / m² .

Answer:

5 hours

Explanation:

Given that

Speed of the airplane, v = 400 mile/hr

Distance of the airport, s = 2000 miles

This is quite a straightforward question that deals with one of the basic formulas in physics.

Speed.

speed is said to the the ratio of distance covered with respect to the time taken. This can be mathematically expressed as

Speed, v = distance covered, d / time taken, t

v = d / t

In the question above, we're looking for the time taken. So, so make t, subject of formula.

t = d / v, now we proceed to substituting the earlier given values into this equation.

t = 2000 / 400

t = 5 hrs,

therefore we can conclude that the airplane was airborne for 5 hours

Answer:

What is the intensity is 1.3349 × 10⁻⁷ w/m²

Explanation:

Given that;

λ = 582 nm = 582 × 10⁻⁹

R = 75.0 cm = 0.75 m

d = 0.640 mm = 0.000640 m

a = 0.434 mm = 0.000434 m

I₀ =  4.40×10⁻⁴ W/m²

y = 0.710 mm  = 0.00071 m

Now to get our tanФ we say

tanФ = y/R =  0.00071 / 0.75 = 0.0009466  

Ф is so small

∴ tanФ ≈ sinФ

So

∅ = 2πdsinФ / λ

we substitute

∅ = ( 2π × 0.000640 × 0.0009466  ) /  582 × 10⁻⁹

=  6.54 rad

Now

β = 2πasinФ / λ

we substitute

β = ( 2π × 0.000434 × 0.0009466  ) /  582 × 10⁻⁹

β = 4.435 rad

I = I₀ cos²(∅/2) [(sin(β/2))/(β/2)]²

we substitute

I = 4.40×10⁻⁴ cos(3.27)² [ (sin(2.2175)) / (2.2175) ]²  

= 4.40×10⁻⁴ × 0.9967 × 0.0003044

= 1.3349 × 10⁻⁷ w/m²

Answer:

Explanation:

With the help of expression of  time period of pendulum we can calculate the height of the branch . The swinging tire can be considered equivalent to swinging bob of a pendulum . Here length of pendulum will be equal to height of branch .

Let it be h . Let the time period of swing of tire be T then from the formula of time period of pendulum

[tex]T = 2\pi\sqrt{\frac{l}{g} }[/tex]  where l is length of pendulum .

here l = h so

[tex]T = 2\pi\sqrt{\frac{h}{g} }[/tex]  

[tex]h = \frac{T^2g}{4\pi^2}[/tex]

If we calculate the time period of swing of tire , we can calculate the height of branch .

The time period of swing of tire can be estimated with the help of a stop watch . Time period is time that the tire will take in going from one extreme point to the other end and then coming back . We can easily estimate it with the help of stop watch .

Answer:

The speed stays constant after the force stops pushing.

Explanation:

Speed always stays constant when the force stops pushing it.

Answer:

Initial state    Final state

     3           ⇒        2

     3           ⇒        1

     2          ⇒         1

Explanation:

For this exercise we must use Bohr's atomic model

         E = - 13.606 / n²

where is the value of 13.606 eV is the energy of the ground state and n is the integer.

The energy acquired by the electron in units of electron volt (eV)

          E = e V

          E = 12.5 eV

all this energy is used to transfer an electron from the ground state to an excited state

        ΔE = 13.6060 (1 / n₀² - 1 / n²)

the ground state has n₀ = 1

       ΔE = 13.606 (1 -  1/n²)

        1 /n² = 1 - ΔE/13,606

         1 / n² = 1 - 12.5 / 13.606

         1 / n² = 0.08129

          n = √(1 / 0.08129)

          n = 3.5

 since n is an integer, maximun is

         n = 3

because it cannot give more energy than the electron has

From this level there can be transition to reach the base state.

Initial state    Final state

     3           ⇒        2

     3           ⇒        1

     2          ⇒         1

The possible quantum-jump transitions by which the excited atom emits a photon are :

Initial state    Final state

    3          --->       2

    3          ---->      1

    2          ---->      1

Given data :

Potential difference through which an electron accelerates = 12.5 V

Energy acquired by the the electrons = 12.5 eV  ( e * 12.5 )

The Model we will use to determine the possible quantum jump transition is  Bohr's atomic model

 E = - 13.606 / n²    

where ; n = integer

energy at ground state = 13.606 eV

The energy acquired by the electrons ( 12.5 eV )  is used to move the electron from its ground state to an excited state.

Therefore

ΔE = 13.606 * (1 / n₀² - 1 / n²)  ---- ( 1 )  

where n₀ = 1

Back to equation ( 1 )

ΔE = 13.606 (1 -  1/n²)   -- ( 2 )

Resolving equation ( 2 )

1 / n² = 0.08129

n = 3.5 .    Therefore the maximum integer = 3  

Hence The collision between the electron and the hydrogen atom will undergo three ( 3 ) transition to reach the base state.

In Conclusion The possible quantum-jump transitions by which the excited atom emits a photon are :

Initial state    Final state

    3          --->       2

    3          ---->      1

    2          ---->      1

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Answer:

Zoning ordinances detail whether specific geographic zones are acceptable for residential or commercial purposes. Zoning ordinances may also regulate: - size

- placement

- density

- height of structures

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Answer:

B

Explanation:

B on edg.

Answer:

The magnetic force is  [tex]\= F = 400\r j + 2800\r i[/tex]

Explanation:

From the question we are  told that

  The  charge is  [tex]q = -5C[/tex]

  The  velocity is  [tex]v = (1.00\ \r i + 7.00 \ \r j )\ m/s[/tex]

   The  magnetic field is  [tex]B = 80 \r k \ \ T[/tex]

Generally the magnetic force is mathematically represented as

        [tex]\= F = q \= v \ \ X \ \ \= B[/tex]

=>     [tex]\= F = -5 (1.0 \r i + 7.0 \r j ) \ \ X \ \ 80 \r k[/tex]

=>    [tex]\= F = -5.0 \r i + 35\r j \ \ \ X \ \ 80\r k[/tex]

=>  [tex]\= F = 400\r j + 2800\r i[/tex]    N/B - Applied cross - product of unit vector

A father and his son want to play on a seesaw. Due to his larger size than that of the son, the father should outweigh the boy on the opposing sides.

A seesaw is a long, narrow board with a single pivot point, which is often situated in the middle of both ends. As one end rises, the other falls.

Rugby continues to have far more health advantages than hazards.

A father and his son want to play on a seesaw. Due to his larger size than that of the son, the father should outweigh the boy on the opposing sides.

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Answer:

It can be said to be reliable although it is not valid

Explanation:

This is because Reliability means an indicator of consistency, A measure should produce similar or the same results consistently if it measures the same quantity. So does the thermometer measures over 5days but it is not valid because it deviates from the real value

Answer:

Explanation:

given, work function of Φ = 2.46 eV.

converting the eV to joule, we have

2.45 * 1.6*10^-19 J

The cutoff wavelength is the wavelength where the incoming light does not have enough energy to free an electron, i.e. all of

the photon’s energy will be channeled into trying overcoming the work function barrier.

It is mathematically given as

Φ = hf

f = Φ/h

f = (2.46 * 1.6*10^-19) / 6.63*10^-34

f = 3.936*10^-19 / 6.63*10^-34

f = 5.94*10^14 Hz as our cut off frequency

λf = c,

λ = c/f

λ = 3*10^8 / 5.94*10^14

λ = 5.05*10^-7

λ = 505 nm as our cut off wavelength

K(max) = hf - Φ

K(max) = hc/λ - Φ

K(max) = [(6.63*10^-34 * 3*10^8) / 181*10^-9] - 3.936*10^-19

K(max) = (1.989*10^-25/181*10^-9) - 3.936*10^-19

K(max) = 1.1*10^-18 - 3.936*10^-19

K(max) = 7.064*10^-19 J or 4.415 eV

V(s) = K(max) / e

V(s) = 4.612 V

Complete Question

 An object floats in water with 5/8 of its volume submerged. The ratio of the density of the object to that of water is:

(a) 8/5

(b) 1/2

(c) 3/8

(d) 5/8

(e) 2/1

Answer:

  The correct option is  d

Explanation:

 From the question we are told that

     The ratio of the  volume of the object submerged to the total volume of the object  is  [tex]\frac{V_w}{V_o} = \frac{5}{8}[/tex]

Generally the buoyancy force acting on the object is equal to the weight of the water displaced and this is mathematically represented as

      [tex]F_b = W[/tex]

Now the mass of the water displaced is mathematically represented as

      [tex]m_w = \rho_w * V_w[/tex]

While the mass of the object is mathematically represented as

    [tex]m_o = \rho_o * V_o[/tex]

So  

      [tex]F_b = W \ \equiv \ \rho * V_o * g = \rho * V_w * g[/tex]

   =>    [tex]\frac{V_w}{V_o} = \frac{\rho_o}{\rho_w}[/tex]

From the question that it volume of the water displace (equivalent to the volume of the object in water  ) to the volume of the total object is

        [tex]\frac{V_w}{V_o} = \frac{5}{8}[/tex]

So

     [tex]\frac{\rho_o}{\rho_w} = \frac{5}{8}[/tex]

Answer

The potential energy is  less

Explanation:

From the question we are told that

   The  source of  the emf is  by wires to a resistor.

Now  the potential energy of electron before leaving the source emf will be greater than the potential energy of an electron after leaving the source of emf because the resistor connected to the source emf will reduced the potential energy as it will convert some of the energy to heat

The potential energy of an electron after leaving the source of emf is lesser.

Electro motive force is the voltage or potential difference of an electrical energy device such as battery.

The  source of  the emf is  by wires to a resistor.Now,  the potential energy of an electron before leaving the source emf will be greater than the potential energy of an electron.

After leaving the source of emf because the resistor connected to the source of emf will reduce the potential energy as it will convert some of the energy to heat.

Thus the potential energy of an electron after leaving the source of emf is lesser.

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Answer:

please find the attachment to this question.

Explanation:

In this question, we represent the 100N in the North-East direction, but first, we define the vector representation:

It is generally represented through arrows, whose length and direction reflect the magnitude and direction of the arrow points. In this, both size and direction are necessary because the magnitude of a vector would be a number that can be compared to one vector.

Please find the attachment: