mai poured 2.6 of water into a partially-filled pitcher. the pitcher now contains 10.4.mai wants to know how many liters of water was originally in the pitcher.

The zeros of the function f(x) = x² - 4x - 5 are given as follows:

x = -1 and x = 5.

The quadratic function for this problem is defined as follows:

f(x) = x² - 4x - 5

The coefficients are given as follows:

a = 1, b = -4, c = -5.

Then the discriminant is given as follows:

D = b² - 4ac

D = (-4)² - 4(1)(-5)

D = 36

Hence the zeros are given as follows:

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Since [tex]1 - \sin^{2}{\theta} = \cos^{2}{\theta}[/tex], the trigonometric expression [tex]\frac{\sin{\theta}}{\sqrt{1 - \sin^{2}{\theta}}} = \tan{\theta}[/tex] is proven.

The trigonometric expression for this problem is defined as follows:

[tex]\frac{\sin{\theta}}{\sqrt{1 - \sin^{2}{\theta}}} = \tan{\theta}[/tex]

The identity used for the proof is given as follows:

[tex]\sin^{2}{\theta} + \cos^{2}{\theta} = 1[/tex]

Hence:

[tex]1 - \sin^{2}{\theta} = \cos^{2}{\theta}[/tex]

Replacing on the left side of the expression, we have that:

[tex]\frac{\sin{\theta}}{\sqrt{1 - \sin^{2}{\theta}}} = \frac{\sin{\theta}}{\sqrt{cos^{2}{\theta}}}[/tex]

Taking the square root:

[tex]\frac{\sin{\theta}}{\sqrt{1 - \sin^{2}{\theta}}} = \frac{\sin{\theta}}{\cos{\theta}}[/tex]

The tangent is given as the division of the sine by the cosine, hence:

[tex]\frac{\sin{\theta}}{\cos{\theta}} = \tan{\theta}[/tex]

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Answer:-117

Step-by-step explanation:

-13x-143+12x=-26

-x=-26+143=117

x=-117

The terminal value formula helps estimate the value of a business beyond the explicit forecast period,

the terminal value formula = FCFF 6 / (WACC – Growth Rate)

We can say that in a DCF model with a five-year free cash flow projection, the terminal value formula = FCFF 6 / (WACC – Growth Rate)

It could be accountable that in finance, the terminal value (also known as “continuing value” or “horizon value” or "TV") of a security is the present value at a future point in time of all future cash flows when we expect stable growth rate forever. It is most likely often used in multi-stage discounted cash flow analysis and also allows for the limitation of cash flow projections to a several-year period; see Forecast period (finance). Forecasting results beyond such a period is impractical and exposes such projections to a variety of risks limiting their validity, primarily the great uncertainty involved in predicting industry and macroeconomic conditions beyond a few years.

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Answer:

a) [tex]W(x) = 0.50 (3^x)[/tex]

W = tickets worth in $
x  = number of balloons popped

b) For 8 balloons popped, number of tickets = 6,561

Tickets worth = [tex]\$ 3,280.50[/tex]

Step-by-step explanation:

The relation between number of balloons popped(x) and the number of tickets is  
[tex]f(x) =3 ^ x\\\\f(1) = 3^1 = 3\\\\f(2) = 3^2 = 9\\\\f(3) = 3^3 = 27\\\\f(4) = 3^4 = 81[/tex]

each ticket is worth 50 cents

So for x  tickets

[tex]W(x) = 0.50 (3^x)[/tex]

Number of tickets for 8 balloons popped
f(x) = 3^8

= [tex]f(x) = 3^8 = 6,561[/tex]

Ticket worth = [tex]0.5 \times 6,561 = \$ 3,280.50[/tex]

In this equation, the value of x is fixed at 2, which means that every point on the graph will have the same x-coordinate value of 2. This creates a vertical line that passes through the point (2, y), where y can be any real number.

Therefore, the proper equation for the graph presented is:

[tex]x=2[/tex]

The lac curve, also known as the envelope curve, is a curve that shows the maximum amount of work that can be done in a given period of time.

It is defined by the equation: W = min {W1 + W2, W3, W4, ..., Wn}, where W1, W2, W3, W4, ..., and Wn are the individual work tasks. The envelope curve is called such because it forms an envelope that encompasses all of the individual tasks on the graph, visually representing the maximum amount of work that can be done within the given timeline. This curve can be used to assess the efficiency of a task or project, as well as to analyze the impact of changes in the workload, deadlines, and resources.

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The Hypothesis test of probability of the type I error is True.

The Hypothesis test probability of the type II error is False.

The notion of the significance level of a hypothesis test is best described by the probability of observing a sample statistic more extreme than the one actually obtained, assuming the null hypothesis is true. This is also known as the "p-value." A significance level is often set beforehand, such as alpha (α) = 0.05, and if the p-value is less than alpha, the null hypothesis is rejected.

The probability of a type I error is related to the significance level. A type I error occurs when the null hypothesis is rejected when it is actually true. The probability of a type I error is represented by alpha (α) and is the level of significance that was set for the test.

The probability of a type II error is the probability of failing to reject a false null hypothesis. It is represented by beta (β) and depends on the sample size, the true value of the parameter being tested, and the level of significance set for the test.

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Answer:

Step-by-step explanation:

=  5 /100  * 78 =  39 /10  = 3.9

$3.90

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

The required formula is :

[tex] \qquad \dashrightarrow \sf \: A = P \times \dfrac{{\bigg(1 + \dfrac{APR}{n} \bigg) }^{ny} - 1}{\dfrac{APR}{n}}[/tex]

Now, plug in the values ~

[tex] \qquad \dashrightarrow \sf \: A = 250 \times \dfrac{{\bigg(1 + \dfrac{0.04}{12} \bigg) }^{(12 \times 10)} - 1}{\dfrac{0.04}{12}}[/tex]

[tex] \qquad \dashrightarrow \sf \: A = 250 \times \dfrac{{\bigg(1 + 0.0033 \bigg) }^{(12 0)} - 1}{0.0033}[/tex]

[tex] \qquad \dashrightarrow \sf \: A = 250 \times \dfrac{{\bigg(1.0033 \bigg) }^{(12 0)} - 1}{0.0033}[/tex]

[tex] \qquad \dashrightarrow \sf \: A = 250 \times \dfrac{1.4908- 1}{0.0033}[/tex]

[tex] \qquad \dashrightarrow \sf \: A = 250 \times \dfrac{0.4908}{0.0033}[/tex]

[tex] \qquad \dashrightarrow \sf \: A = 250 \times 147.249[/tex]

[tex] \qquad \dashrightarrow \sf \: A = 250 \times 147.2498[/tex]

[tex] \qquad \dashrightarrow \sf \: A = 250 \times 147.2498[/tex]

[tex] \qquad \dashrightarrow \sf \: A =\$ 36812.45[/tex]

That's the required value ~

The value of the x in the given triangle is 7.5 units.

Proportion definition, comparative relation between things or magnitudes as to size, quantity, number.

Given is a triangle having sides, 12, 4 and 10 there is a missing side x we need to find is value,

Using the concept of parallel lines crest a proportion,

x / 10 = 12 / 16

x = 120 / 16

x = 7.5

Hence, the  value of the x in the given triangle is 7.5 units.

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The simplification of the given expression

[tex]3 \frac{1}{5} x + 10 \frac{7}{9} - 2 \frac{2}{5} x - 10 \frac{8}{9} [/tex]

is

[tex]\frac{4}{5}x - \frac{1}{9}x[/tex]

[tex]3 \frac{1}{5} x + 10 \frac{7}{9} - 2 \frac{2}{5} x - 10 \frac{8}{9} [/tex]

Change into improper fraction

[tex] = \frac{16}{5} x + \frac{97}{9} - \frac{12}{5}x - \frac{98}{9} [/tex]

[tex] [/tex]

Collect like terms

[tex]= \frac{16}{5}x - \frac{12}{5}x + \frac{97}{9} - \frac{98}{9} [/tex]

Subtract

[tex] = \frac{4}{5}x - \frac{1}{9}x [/tex]

Consequently, the solution to the expression is

[tex] = \frac{4}{5}x - \frac{1}{9}x [/tex]

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Answer:

= 36x - 5.

Step-by-step explanation:

Sorry for my cancellation

76 degrees Fahrenheit was found to be equal to approximately 24.4 degrees Celsius using the formula of conversion.

To convert Fahrenheit to Celsius, you can use the following formula:

Celsius = (Fahrenheit - 32) x 5/9

Plugging in 76 degrees Fahrenheit, we get:

Celsius = (76 - 32) x 5/9

Celsius = 44 x 5/9

Celsius = 220/9

Celsius ≈ 24.4

Therefore, 76 degrees Fahrenheit is approximately 24.4 degrees Celsius.

On the Fahrenheit scale, water freezes at 32 degrees Fahrenheit (°F) and boils at 212 °F, at standard atmospheric pressure.

On the Celsius scale, the freezing point of water is defined as 0 degrees Celsius (°C), and the boiling point of water is defined as 100 °C, at standard atmospheric pressure.

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Answer:

Step-by-step explanation:

The expressions 1/3(36m+12) and 12m+4  are equivalent

Equivalent expressions are defined as algebraic expressions that have the same solution but differ in the mode of the arrangement of values.

These expressions are known to have variables, constants, terms, coefficients, and factors.

They are also made up of mathematical operations.

We have the expression;

1/3(36m+12)

Now, expand the bracket

36m/3 + 12/3

Divide the values

12m + 4

Hence, the expression is 12m + 4

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By the help of congruent , the measure of angle f g h is 64 degrees and the measure of angle e g d is (4 x + 8) degrees and the value of x is 14

Things that have precisely the same size and shape are said to be congruent. The shapes and sizes need to hold true regardless of how we flip, spin, or rotate the forms. Two triangles that are identical in size and shape are said to be congruent triangles. Even if we flip, turn, or rotate one of two congruent triangles, the other two remain congruent.Two triangles must have the same angles and, as a result, must be congruent if their sides are the same.The equal sides and angles may not be in the same location if there is a turn or flip, but they are still there.

The are congruent So,

4x+8=64

Solve for x

X=14

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The measure of m∠H in the triangle is 85°.

Similar triangles are two triangles that have the same shape but can have different sizes. More specifically, two triangles are similar if their corresponding angles are congruent and their corresponding sides are proportional.

Since ΔABC and ΔFGH are similar, we can say:

m∠A =  m∠F

m∠B =  m∠G

m∠C =  m∠H

m∠A  +  m∠B +  m∠C = 180° (sum of angles in a triangle)

We have m∠A = 50° and m∠B = 45°

50°  +  45°  +  m∠C = 180°

m∠C = 180° - 50° - 45°

m∠C = 85°

Since m∠C =  m∠H

Thus, m∠H =  85°

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Both the equations cut at the point (- 3.125, - 6.25).

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The equations are,

1) 2(1/5)x - 5

2) y = 2x

Now, We can draw the equations by using tool,

Hence, We get the graph of function 2(1/5)x - 5 shows by green line and y = 2x shows by red line.

Clearly, Both the function are cut at the point (- 3.125, - 6.25).

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The required expression that can be used to find the total number of pages of baseball cards in the student's album is P = 72 / 8.

The equation model is defined as the model of the given situation in the form of an equation using variables and constants.

To find the total number of pages of baseball cards in the student's album, we need to divide the total number of cards by the number of cards per page.

Let's call the number of pages "P". Then we have:

P = 72 / 8

So, the number of pages is equal to 9.

So, the expression that can be used to find the total number of pages of baseball cards in the student's album is P = 72 / 8.

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The Exterior Angle Theorem states that the measure of an exterior angle of a triangle is equal to the sum of the measures of the 2 nonadjacent interior angles. That means that the measure of angle DEF is equal to the sum of measure of angle C and measure of angle D. Substituting known values gives you 2y + 9 + 6y + 10 = 115, then you can solve

8y + 19 = 115

8y = 96

y = 12

The measure of angle C is 33 degrees, the measure of angle D is 82 degrees, and because the measure of angle DEF is 115 degrees, its supplement angle (DEC) measures 65 degrees.

Using the fact that the two triangles must be similar, we will see that d = 7.5 ft

To find the distance d we will use the fact that the two triangles must be similar triangles.

That means that the quotients between the legs must be equal.

For the triangle on the left side, the quotient is:

50ft/30ft

For the triangle on the right side, the quotient is:

d/height of the student.

We know that the height of the student is 4.5ft, so that quotient is:

d/4.5ft

Now we can write the equation:

d/4.5ft = 50ft/30ft

Solving this for d, we will get:

d = 4.5ft*(50ft/30ft) = 7.5 ft

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A $1000 cash inflows at the end of each year would have a future value of $8,142.01, $8,922.80 and $11.772012 at the end of the year 7 for interest rates of 5% , 8% and 17% respectively.

Annuities are a financial instrument that generates a regular stream of cash. They have both a present and future value dependent upon the value of the cash payment, the number of payment periods and the interest rate. This question does not specify the cash inflow amount so an answer will be generated that can be scaled on multiples of $1000.

Let C represent the cash inflow at the end of each year. The future value (FV) of this cash inflow is given by:

FV = [tex]C[((1+i)^n-1)/i][/tex]

where i is the annual interest rate and n is the number of years.

(a) For i = 5% and n = 7

FV = [tex]C [((1+0.05)^7-1)/0.05][/tex]

FV= C[(1.047100-1)/0.05]

FV = C [8.142008]

(b) For i = 8% and n = 7

FV = [tex]C [((1+0.08)^7-1)/0.08][/tex]

FV = C[(1.713824 - 1)/0.08]

FV = C[8.922803]

(c) For i = 17% and n = 7

FV = [tex]C [((1+0.17)^7-1)/0.17][/tex]

FV = C[(3.001242 - 1)/ 0.17]

FV = C[11.772012]

Therefore, A $1000 cash inflows at the end of each year would have a future value of $8,142.01, $8,922.80 and $11.772012 at the end of the year 7 for interest rates of 5% , 8% and 17% respectively.

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Answer:

$6.85

Step-by-step explanation:

$2.60 x 4 is 10.4 and that is how much Maria spends. Akio spends $3.55 less than Maria. So, 10.4 - 3.55 which is 6.85 and that is the answer.

The total distance covered by the Ferris wheel after 6 rotations is 2616π feet

An equation is an expression that shows the relationship between two or more numbers and variables using mathematical operations. An equation can be linear, quadratic, cubic and so on, depending on the degree of the variable.

The Ferris wheel has a radius of 218 feet. The total distance covered if the Ferris wheel makes one rotation is the perimeter of the wheel.

Perimeter = 2π * radius = 2π * 218 feet = 436π

For 6 rotations:

Total distance covered = 6 * 436π = 2616π

The total distance is 2616π feet

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The following compositions are shown below:

Case 1

f ° g (x) = x, g ° f (x) = x

The two functions are inverses of each other.

Case 2

f ° g (x) = x, g ° f (x) = x

The two functions are inverses of each other.

In this problem we need to determine the composition between two functions and determine if both functions are inverses of each other. A composition is defined below:

f ° g (x) = f [g (x)]

Where the independent variable of the function f(x) is substituted by function g(x). Two functions are inverses if and only if the following condition is fulfilled:

f[g (x)] = g[f (x)]

Now we proceed to determine the compositions and relationships for each case:

Case 1

f(x) = 3 · x

g(x) = x / 3

f ° g (x) = 3 · (x / 3)

f ° g (x) = x

g ° f (x) = (3 · x) / 3

g ° f (x) = x

Functions f(x) and g(x) are inverses of each other.

Case 2

f(x) = (x - 3) / 2

g(x) = 2 · x + 3

f ° g (x) = [(2 · x + 3) - 3] / 2

f ° g (x) = 2 · x / 2

f ° g (x) = x

g ° f (x) = 2 · [(x - 3) / 2] + 3

g ° f (x) = (x - 3) + 3

g ° f (x) = x

Functions f(x) and g(x) are inverses of each other.

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Anwser : 23.8

Step 1: Subtract 5% from 25.

25 - (5% of 25) = 25 - (0.05 x 25)

Step 2: Simplify the equation.

25 - (0.05 x 25) = 25 - 1.25

Step 3: Subtract 1.25 from 25.

25 - 1.25 = 23.75

The expression whose value is a rational number will be √(4)² and √225+ √169. Then the correct options are A and C.

If the value of a numerical expression is terminating then they are the rational number then they are called a rational number and if the value of a numerical expression is non-terminating then they are called an irrational number.

Let's check all the options, then we have

A. √(4)² = 4, is a rational number.

B. √49 + √7 = 7 + √7, is an irrational number.

C. √225+ √169 = 25 + 13, is a rational number.

D. √2 x √121 = 11√2, is an irrational number.

E. √11 x 16 = 4√11, is an irrational number.

The expression whose value is a rational number will be √(4)² and √225+ √169. Then the correct options are A and C.

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The equation given in the problem is shown below:

[tex]y=-\frac{1}{4} x-3[/tex]

Here are the answer choices:

a) (-8,-1)

b) (0,-3)

c) (-2,-4)

d) (4,-4)

We are asked to choose the coordinate pair that is NOT a solution, so let's just test each option!

To test answer choice "a", plug in [tex]x=-8[/tex] and [tex]y=-1[/tex] into the original equation, then simplify:

Plug in values: [tex]-1=-\frac{1}{4} (-8)-3[/tex]

Multiply: [tex]-1=2-3[/tex]

Subtract: [tex]-1=-1[/tex]

Notice that we now have a true expression, therefore option "a" IS A SOLUTION, and is thus not the correct answer.

Repeat for option "b" (0, -3):

Plug in values: [tex]-3=-\frac{1}{4}(0)-3[/tex]

Multiply: [tex]-3=-3[/tex]

Notice that we now have a true expression, therefore option "b" IS A SOLUTION, and is thus not the correct answer.

Repeat for option "c" (-2, -4):

Plug in values: [tex]-4=-\frac{1}{4}(-2)-3[/tex]

Multiply: [tex]-4=\frac{1}{2} -3[/tex]

Subtract: [tex]-4=-\frac{5}{2}[/tex]

Notice that we now have a false expression, therefore option "c" IS NOT SOLUTION, and is thus the correct answer.

To ensure we have the right option, check option "d" as well (4, -4):

Plug in values:[tex]-4=-\frac{1}{4} (4)-3[/tex]

Multiply: [tex]-4=-1-3[/tex]

Subtract: [tex]-4=-4[/tex]

Notice that we now have a false expression, therefore option "d" IS A SOLUTION, and is thus not the correct answer.

Notice that we have now checked all possible options and only option "c" was evaluated as a false expression, therefore option C is the correct choice in regard to this question.

Let me know if you have any questions!