mack is selling beaded necklaces and beaded wristbands at the craft market. a. a necklace requires 40 minutes to make. b. a wristband requires 25 minutes to make. c. mack has 360 minutes to make the necklaces and wristbands. additionally, a. mack wants to make no more than 12 items. b. when mack sells the necklaces and wristbands at the craft market, he will make $3.00 profit per necklace and $2.00 profit per wristband. let x = the number of necklaces mack maker.
Let y = the number of wristbands mack makes.

am going through this and will send me an update tomorrow when you can get back in touch if we have time I would love for a bf of you and I was wondering what I could see for my bad credit cards at least once said that they have no interest and they are not going on the right back side and it doesn't look at the world with me anymore but it will take a little more longer then it might have gone out of there so much more to do it all the

Step-by-step explanation:

Firstly thaj, that's not her. that's not a real picture

Secondly, it's C. The answer is C because all the purple is below the line, making it negative so < since it's all bottom, we use y.

all bottom = y

all top = y

all left = x

all right = x

Answer: 40

Step-by-step explanation:

I rounded to the nearest tens place. The 3 in the tens place rounds up to 4 because the digit to the right in the ones place is 5.

40

When the digit to the right is 5 or greater we round away from 0.

35.7 was rounded up and away from zero to 40

The amount of money that each student has to pay will be $9.61.

An answer to a formula is any variable value that fulfills the equal outcomes, that is, it tends to make the Left Hand Side (LHS) and Right Hand Side (RHS) of the formula equal. To solve an equation, you must locate the feasible solution) to that formula.

Let 'x' be the amount that each student pay. Then the equation is given as,

34x = 326.74

Solve the equation for 'x', then we have

34x = 326.74

x = 326.74 / 34

x = $9.61

The amount of money that each student has to pay will be $9.61.

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Answer: I believe it is the first bubble but it could also be the third one im sorry that is kinda confusing.

The system of transformation used to map ∆RST onto ∆UVW using algebraic notation is (x, y) → (x, y - 4) that is translated down by 4 units and dilation using the scale factor 6.6(x, y).

Translation is the act of moving a form or a figure from one location to another. A figure can move in translation up, down, right, left, or anyplace else in the coordinate system. Just the object's location changes during translation; its size stays the same.

Every point in a form, such as a triangle, rectangle, square, line, circle, and so on, will move by five units in the same direction if one point in the shape moves five units forward. If one point of a triangle travels four units to the left, all three points of the triangle should also move four units to the left.

From the figure we see that the coordinates of the points are:

R = (2, 3)

T = (-1, 0)

U = (1, -2.5)

W = (-0.5, -4)

The first transformation is that the ∆RST is translated down by 4 units.

(x, y) → (x, y - 4)

The second transformation is dilation, since the ∆UVW is smaller in size than the original image.

The distance between RT is:

d = √(-1 -2)² + (0 - 3)²

d = √9 + 9 = √18

The distance between UW is:

d = √(-0.5 - 1)² + (4 + 2.5)²

d = √2.25 + 42.25 = √44.5

The scale factor is:

SF = length of the original figure/ length of new image

SF = √18 / √44.5 = 6.6

Hence, the system of transformation used to map ∆RST onto ∆UVW is (x, y) → (x, y - 4) that is translated down by 4 units and dilation using the scale factor 6.6(x, y).

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The evaluation of the given Boolean expressions are:

a) A && !B =  false              b) B∥C = true

c) B==C = false                   d) A&&!C = true

e) (B∥C)&&(!A) =  false        f) (A!=B)∥(B!=C)  = true

Information available in the problem:

A = true

B = true

C = true

a) Since A and B are both true, !B (which means "not B") is false. Therefore, A && !B evaluates to false, because the logical AND operator returns true only if both of its operands are true.

Hence,

A && !B = true && false = false

b) Since B is true, the result of B∥C will be true, regardless of the value of C. This is because the logical OR operator returns true if at least one of its operands is true.

Hence,

B∥C = true ∥ false = true

c) Since B is true and C is false, B and C have different values, and therefore B==C will evaluate to false. This is because the equality operator returns true only if its operands have the same value.

Hence,

B==C = true == false = false

d) Since A is true and !C (which means "not C") is true, A&&!C evaluates to true. This is because the logical AND operator returns true only if both of its operands are true.

Hence,

A&&!C = true && !false = true && true = true

e) Since B is true, the result of B∥C will be true, regardless of the value of C. This is because the logical OR operator returns true if at least one of its operands is true. Therefore, B∥C evaluates to true.

Since A is true and !A (which means "not A") is false, !A evaluates to false.

Therefore, (B∥C)&&(!A) evaluates to false, because the logical AND operator returns true only if both of its operands are true.

Hence,

(B∥C)&&(!A) = true && false = false

f) Since A is true and B is true, A!=B (which means "A is not equal to B") is false, because A and B have the same value.

Since B is true and C is false, B!=C (which means "B is not equal to C") is true, because B and C have different values.

Therefore, (A!=B)∥(B!=C) evaluates to true, because the logical OR operator returns true if at least one of its operands is true.

Hence,

(A!=B)∥(B!=C) = false ∥ true = true

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The two angels are similar because they have the same magnitude of corresponding angles. The length of x is 6 cm.

For two or more similar triangles, it has two conditions.

The two triangles as shown in the picture, ΔABC and ΔEDC.

Explain why the two triangles are similar! Find the length of x!

We have

The magnitude of ∠BCA and ∠DCE are equal. It is because they are at one point of intersection.

Since, ∠BCA and ∠DCE are equal and m∠A = m∠E, the other angles are also same.

Thus, the two triangle are similar. They have the same magnitude of corresponding angles.

Then, we find x. See the picture in the attachment!

3/10 = 1.8/x

x = (10 × 1.8)/3

x = 18/3

x = 6 cm

Hence, they are similar because they have the same corresponding angles. The x has the length of 6 cm.

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The scaled dimension of a kitchen with the given dimensions is 1.26 cm and 0.96 cm.

Dilation is a type of transformation where the figure is enlarged or made smaller such that it preserves the shape but not size.

Every dilated image are similar figures to the original figure.

Given that,

Actual dimensions of the kitchen = 6.3 m by 4.8 m

Kitchen plan is drawn to a scale of 1 : 500.

This means that, the scale is drawn as 1 unit if the actual unit is 500.

Scaled dimension if actual dimension is 500 = 1

Scaled dimension if actual dimension is 6.3 m = 6.3 / 500

                                                                             = 0.0126 m

                                                                             = 1.26 cm

Scaled dimension if actual dimension is 4.8 m = 4.8 / 500

                                                                             = 0.0096 m

                                                                             = 0.96 cm

Hence the scaled dimensions are 1.26 cm and 0.96 cm.

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The given statement for b is a positive real number and m and n are positive integers, is true.

An integer is a number with no decimal or fractional part, and it includes negative and positive numbers, including zero. A few examples of integers are: -5, 0, 2, -8...

Given that, b is a real number and m and n are positive integers.

According to the above information, the calculation is as follows:

[tex]b^\frac{m}{n} = \sqrt[n]{b^m} = (\sqrt[n]{b} )^m[/tex]

Hence, the statement is true.

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Answer:

The insect population increased at a rate of 20% each month.

Step-by-step explanation:

i looked it up on gogle and it popped up on brainly asked by someone else and already answered

The solution is:

Bigger volume the cylinder wich radius is (L/2) and h = WHow much according to the relation L/W Let´s call L and W the dimensions of the piece of paper

Let´s assume that

 L > WThe Volume (V) of a cylinder is:V(c) = π×r²×h   where r is the radius of the circular base, and h is the height of the cylinderFor the first cylinder (V₁)  (the one which h = w then r = (L/2)V₁ = π×(L/2)²×w

For the second cylinder (V₂) ( the one with h = L and r = (W/2)V₂ = π×(W/2)²×LThe relation

 V₂/V₁  is:V₂/V₁  =  π×(W/2)²×L/π×(L/2)²×wV₂/V₁  = W/LBut   L > W    then       V₂/V₁ < 1     or V₂ < V₁The volume of the first cylinder is bigger than the second one:

n:

Hope this helped :]

[tex] \bf \: {x}^{2} - 2x - 24 = 0[/tex]

[tex] \bf \: {x}^{2} - 6x + 4x- 24 = 0[/tex]

[tex] \bf \: {x}^{}( x- 6) + 4(x- 6) = 0[/tex]

[tex] \bf \: {}^{}( x + 4)(x- 6) = 0[/tex]

[tex]x = - 4 \: \: or \: \: 6[/tex]

The amount of hockey sticks sell for in 2019 will be $22.26.

The amount of any product is given as though it was a proportion of a hundred. The ratio can be expressed as a quarter of 100. The phrase % translates to one hundred percent. It is symbolized by the character '%'.

The percentage is given as,

Percentage (P) = [Final value - Initial value] / Initial value x 100

A certain sporting goods store sold a hockey stick for $20.00 in 2017. The store increased the price by 5% in 2018 and by another 6% in 2019.

Then the amount of hockey sticks sell for in 2019 will be given as,

⇒ $20 x (1 + 0.05) x (1 + 0.06)

⇒ $20 x 1.05 x 1.06

⇒ $22.26

The amount of hockey sticks sell for in 2019 will be $22.26.

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a) The probability that the chosen letter is R is 1/10.

b) The probability mass function of X is P(X = 3) = 1/5, P(X = 4) = 2/5, P(X = 5) = 2/5

c) If k = 3 , then P(X = 3 | X = 3) = 1. Otherwise, P(X = k | X = 3) = 0

d)  The conditional probability P(the chosen letter is R | X > 3) is 1/11.

e) Given that the chosen letter is R, the probability that the word was BROWN is 1/2.

a) The probability that the chosen letter is R is equal to the number of R's divided by the total number of letters in the sentence. There are two R's in the sentence "SOME DOGS ARE BROWN", so the probability of choosing an R is 2/20 = 1/10.

b) To find the probability mass function of X, we need to find the probability of choosing a word of a certain length. There are five words in the sentence, one of length 3, two of length 4, and two of length 5.

The probability of choosing a word of length 3 is 1/5, the probability of choosing a word of length 4 is 2/5, and the probability of choosing a word of length 5 is 2/5. So, the probability mass function of X is:

P(X = 3) = 1/5

P(X = 4) = 2/5

P(X = 5) = 2/5

c) To find the conditional probability P(X = k | X = 3), we need to find the probability of choosing a word of length k given that we know the word has length 3. If X = 3, then the word must be "DOG". So, the only possibility is P(X = 3 | X = 3) = 1.

For all other values of k, P(X = k | X = 3) = 0 because the word must have length 3 given that X = 3.

d) To find the conditional probability P(the chosen letter is R | X > 3), we need to find the probability of choosing an R given that we know the length of the word is greater than 3. The number of R's in words with length greater than 3 is 1, and the number of letters in these words is 11, so the probability is 1/11.

e) Given that the chosen letter is R, the probability that the word was BROWN is equal to the number of R's in the word BROWN (1) divided by the number of R's in the sentence (2). So, the probability is 1/2.

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The power set P(A) is P(A) = { {}, {x}, {y}, {z}, {x,y}, {x,z}, {y,z}, {x,y,z} }

The power set of a set A is the set of all subsets of A, including the empty set and A itself.

For the set A = {x, y, z}, the possible subsets are:

Therefore, the power set of A, denoted P(A), is:

P(A) = { {}, {x}, {y}, {z}, {x,y}, {x,z}, {y,z}, {x,y,z} }

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In geometry, ​8 ft. 3 ft. specifies the dimension of an object. That is the  length and the width.

8 ft. 3 ft. is a dimension, specifically a length and a width. It could refer to the size of a rectangular object, such as a room or a piece of furniture.

In geometry, such a dimension is often used to calculate the area of the rectangle.

The area of a rectangle can be found by multiplying its length by its width.

So, in this case, the area of the rectangle with dimensions 8 ft. * 3 ft. would be 8 ft * 3 ft = 24 ft².

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Answer:

t = 47

Step-by-step explanation:

47 - 38 = 9

As a result of answering the question, we may state that equation In ten attempts, there is a 0.0407 percent chance of getting more than four kings, which is a very little chance.

A mathematical equation is a process that links two statements and indicates equality using the equals symbol (=). A theoretical statement that proves the equality of two formulas is known as an equation in algebra. For instance, the equal sign separates the numbers 3x + 5 and 14 in the equation 3x + 5 = 14.

A. With n=10 and p=4/52, the binomial distribution of the number of kings seen in the 10 trials, K, is followed (since there are 4 kings in a standard deck of 52 cards). K's average is:

mean(K) is equal to[tex]n * p (10 * 4/52 = 0.7692).[/tex]

Meaning: On average, we anticipate seeing 0.77 kings per 10 trials.

B. This is the variance of K:

The formula for var(K) is [tex]n * p * (1 - p) = 10 * 4/52 * (1 - 4/52) = 0.7255.[/tex]

K's standard deviation:

[tex]\sqrt(var(K)) = \sqrt(0.7255) = 0.8524[/tex] where sd(K) =

D. The binomial distribution can be used to calculate the likelihood of receiving more than four kings:

P(K > 4) = 1 - P(K 4) = 1 - 0.0407 for binom.cdf(4, 10, 4/52).

Interpretation: In ten attempts, there is a 0.0407 percent chance of getting more than four kings, which is a very little chance.

D. The binomial distribution can be used to get P(K 3):

Binom.cdf(3, 10, 4/52) = P(K 3) = 0.8789

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37. A possible solution is y(x) = ax + b, where a and b are constants. Taking two derivatives gives y''(x) = 0, which satisfies the differential equation.

38. A possible solution is y(x) = Ce^x, where C is a constant. Taking the derivative of y(x) gives y'(x) = Ce^x, which satisfies the differential equation.

39. A possible solution is y(x) = 3 + 2x^2, which can be checked by taking the derivative and plugging it into the differential equation: xy'(x) + y(x) = x(4x) + (3 + 2x^2) = 3x^2 + 2x^2 + 3 = 5x^2 + 3, which is equal to 3x^2 when x=0.

40. A possible solution is y(x) = sin(x), which can be checked by taking the derivative and plugging it into the differential equation: (y'(x))^2 + (y(x))^2 = cos^2(x) + sin^2(x) = 1.

41. A possible solution is y(x) = ex - 1, which can be checked by taking the derivative and plugging it into the differential equation: y'(x) + y(x) = e^x + e^x - 1 = 2e^x - 1.

42. A possible solution is y(x) = Asin(x) + Bcos(x), where A and B are constants. Taking the second derivative gives y''(x) = -Asin(x) - Bcos(x), which satisfies the differential equation.

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The area of the trapezoid is given as follows:

160 cm².

The area of a trapezoid is obtained adding the bases, multiplying by the height, and dividing by 2.

For the trapezoid in this problem, the parameters are given as follows:

Hence the area is given as follows:

A = 0.5 x (8 + 24) x 10

A = 160 cm².

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The length of the centre pole is approximately 6.29 feet.

What is the Pythagorean Theorem?

Pythagoras Theorem is the way in which you can find the missing length of a right angled triangle.

To find the length of the center pole, we need to use the Pythagorean Theorem to calculate the height of the tent. The height can then be used as one leg of a right triangle with the center pole as the other leg, and we can again use the Pythagorean Theorem to find the length of the center pole.

The height of the tent can be found by using the Pythagorean Theorem on the right triangle formed by one of the triangular faces and the height:

h² = (slant height)² - (base/2)²

h² = 6.75² - 4.5²

h² = 22.5625

h ≈ 4.75 ft

Now we can use the height and the base of the tent to find the length of the center pole using the Pythagorean Theorem:

center pole² = h² + (base/2)²

center pole² = 4.75²+ 4.5²

center pole²= 39.5625

center pole ≈ 6.29 ft

Hence, the length of the center pole is approximately 6.29 feet.

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Answer:

Step-by-step explanation:

We can simplify the left-hand side of the equation using the distributive property of multiplication and combining like terms:

-35 + 4[6x - 12(3x + 5) + 10] = -35 + 4[6x - 36x - 60 + 10] = -35 + 4[-30x - 50] = -35 - 120x - 200 = -120x - 235

Similarly, we can simplify the right-hand side of the equation by combining like terms:

8 + 6x + 9 = 17 + 6x

Substituting these simplified expressions back into the original equation, we get:

-120x - 235 = 17 + 6x

Adding 120x to both sides and subtracting 17 from both sides, we get:

-235 = 126x - 17

Adding 17 to both sides, we get:

-218 = 126x

Dividing both sides by 126, we get:

x = -218/126

Simplifying this fraction, we get:

x = -109/63

Therefore, x is equal to -109/63.

Answer:

  a.  3800

Step-by-step explanation:

You want the product (0.82 +0.042)(4.4×10³) expressed to an appropriate number of significant figures.

The number of significant figures in a product is the least of the numbers of significant figures in the contributors. Here, 4.4×10³ has 2 significant figures, so the result needs to be rounded to 2 significant figures.

  (0.82 +0.042)(4.4×10³) ≈ 3800

__

Additional comment

This is the only answer choice with 2 significant figures, so it can be chosen on that basis alone.

The system has no solution only when h = 3 and k  ≠ 20.

The system has unique solution when h ≠ 3 and k is any real number.

System has many solutions only when h = 3 and k = 20

As per the data given:

[tex]& x_1+h x_2=5 \\[/tex]

[tex]& h x_1+12 x_2=k[/tex]

Consider augmented matrix

[tex]\quad[A \mid b]= & {\left[\begin{array}{cc|c}1 & h & 5 \\h & 12 & k\end{array}\right] } \\[/tex]

[tex]R_2 \rightarrow R_2-4 R_1 & {\left[\begin{array}{cc|c}1 & h & 5 \\0 & 12-4 h & k-20 \\\end{array}\right] }\end{aligned}[/tex]

(a) System has no solution if rank(A) ≠ rank(A|b)

Therefore if 12 - hk = 0 and k - 20 ≠ 0 then

rank(A) ≠ rank(A|b) and system has no solution

12 = 4h and k  ≠ 20

h = 3 and k  ≠ 20

Answer: E. The system has no solution only when h = 3 and k  ≠ 20.

(b) The system has unique solution if rank(A) = rank(A|b)

Number of variables = 2

This is possible only when 12 ≠ 4h and h ≠ 3

The system has unique solution when h ≠ 3 and k is any real number.

(c) The system has many solution when rank(A) = rank(A|b) ≤ (Number of variables = 2)

Therefore this is true only when 12 - 4h = 0 and k - 20 = 0 i.e. h = 3 and  k = 20

System has many solutions only when h = 3 and k = 20

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Choose h and k such that the system has (a) no solution, (b) a unique solution, and (c) many solutions.

[tex]x_1+h x_2=5 \\[/tex]

[tex]4 x_1+12 x_2=k[/tex]

a. Select the correct answer below and fill in the answer box(es) to complete your choice. (Type an integer or simplified fraction.)

A. The system has no solutions only when [tex]$k \neq \square$[/tex] and h is any real number.

B. The system has no solutions only when h = [tex]\square$[/tex] and k=

C. The system has no solutions only when h [tex]\neq \square$[/tex] and [tex]$k \neq$[/tex]

D. The system has no solutions only when [tex]$\mathrm{h}=\square$[/tex] and k is any real number.

E. The system has no solutions only when [tex]$h=\square$[/tex] and [tex]$k \neq$[/tex]

F. The system has no solutions only when [tex]$k=\square$[/tex] and h is any real number.

G. The system has no solutions only when [tex]$h \neq \square$[/tex] and k is any real number.

H. The system has no solutions only when [tex]$h \neq \square$[/tex] and k= ___

Answer:

1. ~ ABC = 180 degrees

2. AB/AD = BC/AC

3. 3/9 = x/6

4. x = 2

5. The scale factor of ADE to ABC is 1:2.

Step-by-step explanation:

1. ~ABC = 180 degrees means that the sum of all the angles of a triangle add up to 180 degrees.

2. AB/AD = BC/AC means that if two sides of a triangle are divided by another side, the ratio will be the same for both sides of the triangle.

3. 3/9 = x/6 means that if you divide 3 by 9, you can find out what x is when it is divided by 6.

4. x = 2 means that when 3 is divided by 9 and the result is divided by 6, the answer is 2.

5. The scale factor of ADE to ABC is 1:2 means that ADE is twice the size of ABC and all related measurements between the two triangles are in a proportion of 1:2.

The minimum value of the interval is two standard deviations below the mean (μ - 2σ), while the maximum value of the interval is two standard deviations above the mean (μ + 2σ).

The range rule of thumb states that the usual measures in an interval are within two standard deviations of the mean.

The parameters you are given to solve this problem are:

Hence the lower bound of the interval is of:

μ - 2σ -> you should subtract two standard deviations from the mean.

The upper bound of the interval is of:

μ + 2σ -> you should add two standard deviations to the mean.

The problem is incomplete, hence the general procedure to obtain the bounds of the interval is presented.

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We can consider $323.53 as near the monthly interest rate on this loan is approximately 0.4974% (or 0.004974 as a decimal). We can use a formula to find the monthly interest where:

P = (r(PV)) / (1 - (1 + r)^(-n))

Where:

P = monthly payment

r = monthly interest rate

PV = present value of the loan (the amount borrowed)

n = total number of months

r (monthly interest)= (1 / n) * ((P / PV) + ((1 / (1 + r)^n) - 1))

we can start by guessing an interest rate of 0.01 (or 1%). putting it into a formula:

r = (1 / 60) * ((323.53 / 10000) + ((1 / (1 + 0.01)^60) - 1))

r = 0.004968

monthly payment is

P can be (0.004968 * 10000) / (1 - (1 + 0.004968)^(-60))

P = $323.52

By using this value we can find the value of the month. Plugging it back into the formula, we get:

r = (1 / 60) * ((323.53 / 10000) + ((1 / (1 + 0.004968)^60) - 1))

r = 0.004974

This new interest rate gives us a monthly payment of:

P can be (0.004974 * 10000) / (1 - (1 + 0.004974)^(-60))

P = $323.53

We can consider $323.53 as near the monthly interest rate on this loan is approximately 0.4974% (or 0.004974 as a decimal).

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The correct question is

Table 33 gives spending data for the football programs at the 10 universities that spent the most money on football in 2012 Click here for the Excel Data File Calculate the population range variance and standard deviation of the ten total football spending figures Do the same for the ten spending per scholarship player figures. (Round your range and variance answers to 2 decimal places and standard deviation answer to 4 decimal places.) Total Spending (Smil) Spending per Scholarship Player (5) Range Variance Std Deviation 7 College Football A B C D 1 Footballs bending Data for 2012's Top Ten College Football Spenders 2 3 Rank School Total Spending (Smil) Spending per Scholarship Player (3) 4 1 The Ohio State University 34.36 5 400,000 2 University of Alabama 37.77 360,000 6 3 Auburn University 33.33 303,000 7 4 University of Wisconsin 24.23 285,000 8 5 University of Arkansas 24.33 9 6 Oklahoma State University 283,000 26.24 10 279,000 7 Virginia Tech 24.72 11 275,000 8 University of Arizona 24.12 12 9 274,000 University of Florida 23.25 13 273,000 University of Michigan 23.64 14 272,000 15 10

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