Lisette wrote the following algebraic expression to represent “4 times as large as the product of w and 11.”

A) The dresses for films set in the 1700s would be 60%.

B) The percentage of dresses that are not for films set in the 1700s is 40%.

C) The percentage of dresses that can be used for films set in the 1700s or during the civil war era is 75%.

D) The percentage of dresses that are not for films set during the civil war era is 85%.

What is a percentage?

The percentage is a way of expressing a number as a fraction of 100. It is often denoted using the symbol "%". It is used to express a proportion of a number out of 100. It is useful in many applications such as finance, statistics, and other fields.

A. Three-fifths of the dresses can be used for movies that take place in the 1700s, which is 3/5 * 100 = 60%.

B. The percent of the dresses that are not for films set in the 1700s is 100% - 60% = 40%. This is found by subtracting the percentage of dresses that are used for 1700s movies from 100%.

C. The percent of the dresses that can be used for films set in the 1700s or during the civil war era is 60% + 15% = 75%. This is found by adding the percentage of dresses that can be used for 1700s movies and the percentage of dresses that can be used for civil war era movies.

D. The percent of the dresses that are not for films set during the civil war era is 100% - 15% = 85%. This is found by subtracting the percentage of dresses that are used for civil war era movies from 100%.

Hence,

A) The dresses for films set in the 1700s would be 60%.

B) The percentage of dresses that are not for films set in the 1700s is 40%.

C) The percentage of dresses that can be used for films set in the 1700s or during the civil war era is 75%.

D) The percentage of dresses that are not for films set during the civil war era is 85%.

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7/100% can be written as a fraction as 7/100, and as a decimal as 0.07.

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{\dfrac{7}{100}\%}[/tex]

[tex]\mathsf{= \dfrac{7}{100} \div 100}[/tex]

[tex]\mathsf{= \dfrac{7}{100}\times \dfrac{1}{100}}[/tex]

[tex]\mathsf{= \dfrac{7(1)}{100(100)}}[/tex]

[tex]\mathsf{= \dfrac{7}{1,000}}[/tex]

[tex]\mathsf{= 0.0007}[/tex]

[tex]\huge\text{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{\dfrac{7}{1,000} \ \& \ 0.0007}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

10

I wish you luck in your assignments.

Answer:

Given that Figure A and Figure B are similar polygons, the scale factor of Figure A to Figure B = 5/2.

Recall:

Similar Polygons have corresponding side lengths whose ratio are equal. That is, their pairs of corresponding sides are proportional.

The ratio of any of their corresponding side length = scale factor

Given the two pairs of similar polygons, the scale factor of figure A to figure B will be calculated as follows:

A side length of Figure A = 10

Corresponding side length of Figure B = 4

Scale factor of Figure A to Figure B = 10/4 = 5/2

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

fffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff

Answer:51x900/100

Step-by-step explanation:

So you’ll do 51 x 900

And then at the denominator when there is no number it is automatically 1 so the denominator will be 100.

Answer:

288

Step-by-step explanation:

1 pound is equal to 16 ounces

if Itzel purchases 18 pounds, to convert to ounces simply multiply 18 by 16.

Answer:

288

I wish you luck in your assignments.

(I just noticed someone got here in before me and answered WAY better. So I edited this to tell you to give them brainliest.)

The common denominator of the given expression is 5y+6.

Division is the process of splitting a number or an amount into equal parts.

here, we have,

Given expression,

(y+(y-3)/3)/(5/9+2/3y)

We have to find the common denominator.

On solving the numerator and denominator of the  given expression,

=3y(4y-3)/5y+6

Hence the common denominator of the above expression is given by 5y+6

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Answer:

  x = 7

Step-by-step explanation:

You want to know the value of x when the base of a triangle measures 5x+35, and its midsegment measures 35.

The base of the triangle is twice the length of the midsegment, so you have ...

  5x +35 = 2(35)

  5x = 35 . . . . . . . . . . subtract 35

  x = 7 . . . . . . . . . . divide by 5

__

Additional comment

The midsegment joins the midpoints of the sides of the triangle.

In more formal terms, the smaller triangle is similar to the larger one with a scale factor of 1/2. That means the parallel segments are related by that scale factor of 1/2: (1/2)(5x +35) = 35.

Answer:£21.00

Step-by-step explanation:

One pizza: (£35/5) =£7

Three pizza's: (£7x3)=£21

Answer:

2.5

Step-by-step explanation:

Decimeter is 0.1 meter (10 centimeters). That means 25 decimeters is 2.5 meters.

Answer:

Steps for How to Transform the Graph of a Cubic Function

Step 1: The standard form of a cubic function is y=a(x−h)3+k y = a ( x − h ) 3 + k , where a indicates a stretch or a shrink, h indicates a vertical shift, and k indicates a horizontal shift.

Step-by-step explanation:

The first 100 terms of a series add up to 4950, and the first 21 terms of a series where a = 20 and t21 = 400 add up to 4410

An arithmetic progression is when the difference between each phrase that follows another in a sequence is always the same. For instance, the sequence 5, 7, 9, 11, 13, and 15 is an example of an arithmetic progression with a 2 tolerance. A progression having a set tolerance between any two consecutive numbers is known as a "arithmetic progression" (A.P.). Two alternative types of mathematical progression exist: finite-length mathematical series A series that has a limited number of terms is a finite geometric progression. One may calculate the early, late, tolerance, and number of terms in a series using the terms in the series.

given

1) n6 = 6  where a = 5 and d = 5 = 105

2)n6 =6 where a = 9 and d = 12 = 234

3) n5= 5 where a = 5.7 and d = 1.4 = 42.5

4) a = 20 and  t₂₁ = 400 ,

= 380

Therefore, Sum of 21 terms =  4410

5) In series  a = 0 and t₁₀₀ =  99  = 4950

The first 100 terms of a series add up to 4950, and the first 21 terms of a series where a = 20 and t21 = 400 add up to 4410

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Answer: Both Rick and Jenny could be correct because we do not know what "x" is.

Step-by-step explanation:

The purpose of the variable "x" is to substitute it for an unknown number. Since we do not know what "x" is we can not solve the equation. We can only add like terms.

I hope this helps :)

if functions  f(x) = 2x²-4x-6 and g(x)= 2x+7 then f(g(x)) is 8(x+2)(x+4)

A relation is a function if it has only One y-value for each x-value.

Given functions are f(x)= 2x²-4x-6

g(x)=2x+7

We need to find expression of f(g(x))

f(g(x))=f(2x+7)

Now replace x with 2x+7 in f(x)

f(2x+7)=2(2x+7)²-4(2x+7)-6

=2(4x²+49+28x)-8x-28-6

Apply distributive property

=8x²+98+56x-8x-28-6

Add the like terms

=8x²+48x+64

f(g(x))=8(x+2)(x+4)

Hence, if functions f(x) = 2x²-4x-6 and g(x)= 2x+7 then f(g(x)) is 8(x+2)(x+4)

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For 2 weeks tony will spent time for practice basketball is 10 hours.

Given data :

1st week

= Tuesday = 2 hours

= Wednesday = 1 hour

= Friday = 2 hours

same for 2nd week

so total hours = 1st week + 2nd week

                       =  2 + 1 + 2 + 2 + 1 + 2

                       = 10 hours

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According to the findings, 40 of the adults who were not parents and 150 of the adults who were parents believed that the park should be expanded.

250 adults, 180 of whom are parents, leaving 70 adults who are not parents (250 - 180). According to the findings, 40 adults without children and 150 adults with children said the park should be expanded. Thus, 180 – 150 = 30 parents.

Parents: YES OR NO Not parents: 40 | 30 of 150

In this exercise, we must determine the values of the voters who supported expanding the parking lot, which requires that we:

In fact, parents will be 150, not 40.

Parents won't be 30 in total; they'll be 40. Instead, a park should be built to accommodate 250 persons, 180 of whom were parents.

The park should be extended, according to 40 of the people who weren't parents.

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The length of x of a diagonal support is 13.8 feet.

The hypotenuse of a triangle is the length of the longest side of the triangle. So that it is always opposite to the measure of the largest angle of a triangle.

In the question given, divide the length of the footbridge into 2 parts.

So that,

Half of the footbridge = 25/ 2

                     = 12.5 ft

So that applying the appropriate trigonometric function to determine the value of x using any of the congruent triangles. We have;

Sin θ = opposite/ hypotenuse

Sin 65 = 12.5/ x

x = 12.5/ Sin 65

  = 12.5/ 0.90631

x = 13.792 feet

The length x of a diagonal support is 13.8 feet.

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The Chinese yuan you can buy for a dollar is 6.86483 Chinese yuan

From the question, we have the following parameters that can be used in our computation:

1 Chinese yuan= $0.14567

Divide both sides of the equation by 0.14567

So, we have the following representation

1/0.14567 Chinese yuan= $0.14567/0.14567

Evaluate the quotient

1/0.14567 Chinese yuan= $1

Evaluate the other quotient

6.86483 Chinese yuan= $1

This means that

$1 = 6.86483 Chinese yuan

Hence, you can buy 6.86483 Chinese yuan for $1

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There was 4 dollar of discount on the total amount.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value. Unitary method is a technique by which we find the value of a single unit from the value of multiple devices and the value of more than one unit from the value of a single unit. It is a method that we use for most of the calculations in math.

We are given that Adrian bought a jacket that costs 11 dollars and a scarf that costs 15 dollars.

At the counter, he received a discount. If he only paid 22 dollars total, then

Total cost 11 + 15 = 26

But 26 - 22 = 4

Therefore, the discount was 4 dollar.

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The value of x = -7 and y = 9 from the system of equations .

A finite collection of equations for which common solutions are sought is referred to as a set of simultaneous equations, often known as a system of equations or an equation system.

simultaneous equations, system of equations Two or more equations in algebra must be solved jointly (i.e., the solution must satisfy all the equations in the system). The number of equations must match the number of unknowns for a system to have a singular solution.

To create an equation in one variable using the elimination approach, you may either add or subtract the equations. To remove a variable, add the equations when the coefficients of one variable are in opposition, and subtract the equations when the coefficients of one variable are in equality.

The equations are :

-x - y = -2          (i)

and

5x + 7y = 28        (ii)

multipling eqation (i) with 5 and then adding both equations we get,

-5x - 5y +5x + 7y = -10 + 28

⇒ 2y = 18

⇒ y = 9

Again, -x -9 = -2

or, x = -7

The value of x = -7 and y = 9 from the system of equations

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The equation that corresponds to fraction   [tex]\frac{7^{-10} }{(7^{4} )(7^{0} )}[/tex] is [tex]\frac{1}{7^{14} }[/tex] . A phrase by itself could contain an action .

It is possible to multiply, divide, add, or subtract in math. An expression has the following structure: Expression: (Math Operator, Number/Variable, Math Operator). A mathematical expression is made up of numbers, variables, and functions (such as addition, subtraction, multiplication or division etc.) It is possible to compare expressions and phrases. In English, a phrase by itself could contain an action, but it doesn't constitute a full sentence.

given

[tex]\frac{7^{-10} }{(7^{4} )(7^{0} )} \\= \frac{1}{7^{4} } *\frac{1}{7^{10} } * 1\\= \frac{1}{7^{14} }[/tex]

The equation that corresponds to fraction   [tex]\frac{7^{-10} }{(7^{4} )(7^{0} )}[/tex] is  [tex]\frac{1}{7^{14} }[/tex] .

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Therefore , the solution to the given problem of equation comes out to be quotient : x² +x+6+ [tex]\frac{2}{x+2}[/tex] and remainder is 2

A mathematical depiction of two equal variables, one on either side of a "equals" sign, is called an equation. Equations can be used to solve common problems. To solve challenges in real life, we frequently turn for pre algebra assistance. Lessons in pre-algebra cover the foundational ideas of mathematics.

Here,

Given : synthetic division for

x³ + 3x² + 8x + 14

------------------------

x + 2

Write the problem in synthetic division format

-2  | 1 3 8 14

         -2 -2  

------------------------

     1   1  6

Carry down the leading coefficient, unchanged, to below the division symbol

-2  |    1 3 8 14

           -2 -2

---------------------------

         1  1   6

Multiply the carry - down value by the zero of the denominator, and carry the result up into the next column:

1(-2)=-2

-2 |  1 3 8 14

        -2 - 2

------------------

     1    1   6

=> We get:

As

x² +x+6+ [tex]\frac{2}{x+2}[/tex]

and remainder is 2

Therefore , the solution to the given problem of equation comes out to be quotient : x² +x+6+ [tex]\frac{2}{x+2}[/tex] and remainder is 2.

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Answer:

9

Step-by-step explanation:

18/5 ÷ 2/5 = 18/5 x 5/2 = 9

Step-by-step explanation:

a) x+20+x+90=180 [sum of 3 angel of triangle]

2x + 110 = 180

2x = 180- 110

2x = 70

x = 70÷2

x = 35

b) 2y + y + y = 180

4y = 180

y = 180÷4

y= 45

c) 4z-30 + 2z = 180

6z = 180 + 30

6z = 210

z = 35

Answer:

  (c)  8 jars

Step-by-step explanation:

You want to know the number of 1.25 quart jars that can be filled from a 2.5 gallon container.

The number of jars can be found from ...

  (2.5 gal) × (4 qt/gal) × (1 jar)/(1.25 qt) = (2.5·4/1.25) jars = 8 jars

Lorraine can fill 8 jars from the 2.5 gallon pot.

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Answer:

Step-by-step explanation:

Triangle JKL is a 51-51-78 triangle, since the angles in a triangle must add up to 180°. Since triangle PQR is similar to triangle JKL, it must also be a 51-51-78 triangle. Since corresponding sides in similar figures are in proportion, we can set up a proportion to find the length of PR:

(PR)/(JK) = (PQ)/(JL) = (36)/(18)

Cross multiplying and solving for PR, we find:

PR = (JK) * (PQ)/(JL) = 18 * 36/18 = 36