The limiting reagents are potassium superoxide, carbon dioxide, nitrogen , Sulphur dioxide and oxygen respectively
What are the limiting reagent1.
Potassium superoxide reaction:
4KO2(s) + 2H2O(l) → 4KOH(s) + 3O2(g)
Given: 0.150 mol KO2 and 0.100 mol water
We can start by calculating the amount of moles of oxygen that can be produced from each reactant.
From 0.150 mol of KO2, we can produce:
0.150 mol KO2 * (3 moles O2 / 4 moles KO2) = 0.113 mol O2
From 0.100 mol of water, we can produce:
0.100 mol H2O * (3 moles O2 / 2 moles H2O) = 0.150 mol O2
Since the amount of moles of oxygen that can be produced from the water is larger, we have a surplus of water. Therefore, potassium superoxide is the limiting reagent, and we can produce 0.113 moles of O2.
2.
C2H2 and O2 reaction:
2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(l)
Given: 13.7 g of C2H2 and 18.5 g of O2
We can start by calculating the amount of moles of each reactant:
C2H2: 13.7 g / 26.04 g/mol = 0.522 mol
O2: 18.5 g / 32.00 g/mol = 0.580 mol
We can then calculate the amount of moles of CO2 produced from each reactant:
From 0.522 mol of C2H2, we can produce:
0.522 mol C2H2 * (2 moles CO2 / 2 moles C2H2) = 0.522 mol CO2
From 0.580 mol of O2, we can produce:
0.580 mol O2 * (2 moles CO2 / 5 moles O2) = 0.232 mol CO2
Since the amount of moles of CO2 that can be produced from O2 is smaller, we have a surplus of O2. Therefore, C2H2 is the limiting reagent, and we can produce 0.522 moles of CO2. To find the mass, we can multiply the amount of moles by the molar mass of CO2:
0.522 mol * (44.01 g/mol) = 23.0 g CO2
3.
Nitrogen gas can react with hydrogen gas to form gaseous ammonia. If 4.7 g of nitrogen reacts with 9.8 g of hydrogen, how much ammonia is formed? What is the limiting reagent?
We can balance the reaction equation first:
N2(g) + 3H2(g) → 2NH3(g)
Next, we need to convert the masses of nitrogen and hydrogen to moles.
For nitrogen:
moles = mass / molar mass
moles = 4.7 g / 28.0 g/mol = 0.168 mol
For hydrogen:
moles = mass / molar mass
moles = 9.8 g / 2.0 g/mol = 4.9 mol
Since the reaction requires 3 moles of hydrogen for every 1 mole of nitrogen, the limiting reagent will be nitrogen.
The amount of ammonia that can be formed can be calculated using the moles of the limiting reagent.
moles of NH3 = moles of N2 * 2
moles of NH3 = 0.168 mol * 2 = 0.336 mol
Mass of NH3 = moles of NH3 * molar mass of NH3
Mass of NH3 = 0.336 mol * 17.0 g/mol = 5.7 g
So, 5.7 g of ammonia can be formed and nitrogen is the limiting reagent.
4.
One of the most common acids found in acid rain is sulfuric acid. Sulfuric acid is formed when gaseous sulfur dioxide reacts with ozone (O3) in the atmosphere to form gaseous sulfur trioxide and oxygen. The sulfur trioxide forms sulfuric acid when it comes in contact with water. If 5.13 g of sulfur dioxide reacts with 6.18 g of ozone, how much sulfur trioxide is formed? What is the limiting reagent?
We can balance the reaction equation first:
2SO2(g) + O3(g) → 2SO3(g)
Next, we need to convert the masses of sulfur dioxide and ozone to moles.
For sulfur dioxide:
moles = mass / molar mass
moles = 5.13 g / 64.0 g/mol = 0.0801 mol
For ozone:
moles = mass / molar mass
moles = 6.18 g / 48.0 g/mol = 0.1288 mol
Since the reaction requires equal moles of sulfur dioxide and ozone, the limiting reagent will be whichever has the smaller amount, in this case, sulfur dioxide.
The amount of sulfur trioxide that can be formed can be calculated using the moles of the limiting reagent.
moles of SO3 = moles of SO2 * 2
moles of SO3 = 0.0801 mol * 2 = 0.1602 mol
Mass of SO3 = moles of SO3 * molar mass of SO3
Mass of SO3 = 0.1602 mol * 80.0 g/mol = 12.8 g
So, 12.8 g of sulfur trioxide can be formed and sulfur dioxide is the limiting reagent.
5.
Sulfur trioxide is formed when sulfur dioxide reacts with oxygen:
SO2 + 1/2 O2 → SO3
From the given amounts of sulfur dioxide and oxygen, we can calculate the amount of sulfur trioxide that can form:
7.99 g SO2 * (1 mol SO2 / 64.06 g SO2) = 0.1251 mol SO2
2.18 g O2 * (1 mol O2 / 32.00 g O2) = 0.0681 mol O2
We need equal amounts of sulfur dioxide and oxygen for complete reaction, so the limiting reagent is the one with the smaller amount, which is oxygen. The maximum amount of sulfur trioxide that can form is determined by the amount of oxygen:
0.0681 mol O2 * (1 mol SO3 / 0.5 mol O2) = 0.1362 mol SO3
0.1362 mol SO3 * (80.06 g SO3 / 1 mol SO3) = 10.93 g SO3
So, 10.93 g of sulfur trioxide can form from the given amounts of sulfur dioxide and oxygen. The limiting reagent is oxygen.
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Please help with the problem attached:
Answer:
the one with cars is false I think
how do we open a business that is cheaper
Answer:dont sell as much stuff and name it something like the doller treestore LOL
Explanation:
A major component of gasoline is octane (C3H18). When liquid octane is burned in air it reacts with oxygen (O₂) gas to produce carbon dioxide gas and water
vapor. Calculate the moles of octane needed to produce 2.10 mol of water. Be sure your answer has a unit symbol, if necessary, and round it to the correct
number of significant digits.
The amount of octane produced by a reaction involving 2.10 mole of water is 18.9 mole.
What is a mole?We'll start by writing the reaction's balanced equation. This is as follows:
2C8H18 + 25O2 → 16CO2 + 18H2O
Based on the above-mentioned balanced equation,
2 moles of octane were converted into 18 moles of water.
Using the above data, we can calculate the number of moles of octane produced by the reaction of 2.10 mole of water. This can be obtained by doing the following:
Based on the above-mentioned balanced equation,
2 moles of octane were converted into 18 moles of water.
Therefore,
When x mole of octane will react to produce 18 moles of water
x = 2x / 18 x 2.10
2x = 37.8
x = 37.8/2
x = 18.9
As a result, the number of moles of octane produced by the reaction is 18.9 mole.
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the bjerrum plot shows the relative concentrations of each carbonate species in seawater at different ph's. please select the relative concentrations of carbonate species in seawater at ph of 7.
Relative concentrations of carbonate species in seawater at pH of 7 is [HCO3-]= 4.1 Mmol, [H2CO3]=0.91 Mmol-1, [CO3 2-]= 1.9x 10-3 Mmol.
Find attached Bjerrum plot shows the relative concentrations of each Carbonate species in seawater at different pHs.
The reactions between carbon dioxide, hydrogen ions, bicarbonate and Carbonate ions, all dissolved in water, are as follows:
CO2 + H2O ⇌ H+ + HCO−3
(1) HCO−3 ⇌ H+ + CO2−3
Reaction 1 is actually the combination of two elementary reactions:
CO2 + H2O ⇌ H2CO3 ⇌ H+ + HCO−3
Sea-water reactions.
H+ has very little final role in the seawater reactions. We can express Them as:
CO2 + CO3-- + H2O ⇌ 2HCO3-
Ca++ + CO3-- ⇌ CaCO3 (aragonite).
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Based on relative bond strengths, classify these reactions as endothermic (energy absorbed) or exothermic (energy released).AB+C --> AC+BA+ BC --> AB + CA2+C2 --> 2ACB2+C2 --> 2BCA2+B2 --> 2ABStrongest BondA-BA-AB-BC-CB-CA-CWeakest Bond
The answer is 1) Endothermic, 2) Exothermic, 3) Endothermic, 4) Endothermic, 5) Exothermic.
The stronger the bond, the more energy is required to break it, and the stronger the bond formed, the more energy is released.
AB is a strong bond and requires more energy to break it, forming a weak AC bond that releases very little energy, so the reaction is relatively endothermic since more energy is absorbed than given off. Similar logic can be applied to all 5.
Endothermic reactions consume energy in the form of heat. Endothermic reactions occur when molecules absorb energy from surroundings, causing them to break and form new bonds with other molecules.
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Describe the situations when Greek prefixes are used:
a) To specify the number of hydrogen atoms in the formula of simple nonmetal hydrogen compounds.
b) To specify the number of water molecules in a hydrate.
c) To specify the number of atoms of each element in molecular compounds.
d) To specify the charge of elements in the names of polyatomic compounds.
e) To specify the number of atoms of each element in ionic
compounds.
**YOU CAN CHOOSE MULTIPLE
The situations when Greek prefixes are used to specify the charge of elements in the names of polyatomic compounds. Therefore, option D is correct.
When and why are prefixes used when naming compounds?Because molecular compounds can form compounds with different element ratios, prefixes are used to specify the number of atoms of each element in a compound molecule. SF₆, sulfur hexafluoride, and N₂O₄, dinitrogen tetroxide are two examples.
Greek prefixes are used to indicate the number of atoms of each nonmetal element in the compound's chemical formula. The prefix "mono-" is not used if the compound contains only one atom of the element listed first in the name.
Thus, option D is correct.
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8. A cashier at Whole Foods measures the weight (mass) of fruit with an electronic scale at the register.
If the cashier accidentally leaves a pen on the scale for each measurement, would this contribute to
random error or systematic error? Explain.
Leaving a pen on the scale for each measurement would contribute to systematic error.
The term "systematic error" describes a predictable and repeatable deviation in measurement results that takes place in the same direction every time the measurement is taken. In this instance, each measurement is consistently and repeatedly deviated by the pen on the scale, systematically elevating all of the readings above the actual weight of the fruit.
What is a systematic error with an example?
A systematic error is one that consistently changes in the same manner. For instance, if something consistently or frequently raised the blood pressure right before the measurements, this might happen when taking blood pressure.
What is the random error?
Each measurement varies slightly from the next because of random error. Unexpected outcomes of an experiment are where it comes from.
What are 3 systematic errors?
Environmental Errors.
Observational Errors.
Instrumental Errors.
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A nutritionist suspected that her company's clients had below average cholesterol. They obtained a random sample of 8 clients of the same age and gender. These clients had a mean cholesterol level of xˉ=4.28 mmol/L (millimoles per liter).To see how likely a sample like this was to happen by random chance alone, the nutritionist performed a simulation. They simulated 60 samples of n=8 cholesterol levels from a normal population with a mean of 4.6 mmol/L and a standard deviation of 0.5 mmol/L (these are generally accepted values for people with the same age and gender of those in the sample). They recorded the mean of the cholesterol levels in each sample. Here are the sample means from their 60 samples:They want to test H0:μ=4.6 mmol/L vs. Ha:μ<4.6 mmol/L where μ is the mean cholesterol level for all clients like those sampled.Based on these simulated results, what is the approximate p-value of the test?Note: The sample result was xˉ=4.28 mmol/L.
The nutritionist can deduce that the mean cholesterol level for all clients is less than 4.6 mmol/L (Ha:4.6 mmol/L) because this p-value is less than 0.05, rejecting the null hypothesis.
Calculating the likelihood that a sample mean will be equally extreme or more extreme than the observed mean if the null hypothesis is correct will yield the p-value.
Using the observed sample mean as a foundation, calculate the Z-score:
[tex]Z = \frac{4.28 - 4.6}{0.5 / \sqrt{8}}[/tex]
To ascertain the likelihood of encountering a Z-score, look up the Z-score in a typical normal table. The Z-score in this case is around -2.56, with a probability of 0.0039.
The p-value is the chance of encountering a sample mean that is as severe or more extreme than the observed mean, given that the null hypothesis is true. The p-value for this test is hence close to 0.0039.
There is a 0.0039 possibility of seeing a sample mean that is as high or more severe than the observed mean (4.28 mmol/L) if the average cholesterol level for all customers is 4.6 mmol/L.
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Which of the following reactions
is BALANCED and shows
COMPLETE combustion?
A. 2C,H, +70,- 4CO₂ + 6H₂O
B. 2C,H, +40,5CO + 6H₂O
C. 2C,H, +40, 7CO₂ + 6H₂O
D. 2C,H, +50,- 4CO + 6H₂O
1
The balance of the reaction equation occurs when the number of atoms of each element is the same on both sides of the equation.
How do you know a balanced combustion equation of hydrocarbons?The question is incomplete but the reaction equation of the hydrocarbons for a combustion reaction can be known to be balanced in the following ways;
To write a balanced combustion equation of hydrocarbons, you need to follow these steps:
Write the chemical formula for the hydrocarbon, which has the general form CxHy.
Write the balanced chemical equation for the combustion of the hydrocarbon, which is typically written as:
CxHy + (x + y/4) O2 → x CO2 + (y/2) H2O
where O2 is the oxygen required for complete combustion, CO2 is carbon dioxide, and H2O is water. The factor of (x + y/4) in front of the O2 represents the stoichiometric coefficient required to balance the equation.
Balance the equation by adjusting the stoichiometric coefficients of the reactants and products so that the number of atoms of each element is the same on both sides of the equation.
Check that the equation is balanced by counting the number of atoms of each element on both sides of the equation.
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which of the following elements (p, na, o, n) is most likely to form a compound involving an expanded valence shell of electrons? explain.
The element most likely to form a compound involving an expanded valence shell of electrons is oxygen (O).
Oxygen has a valence shell of 6 electrons and it is able to form a variety of compounds with other elements by sharing its electrons with them. This gives oxygen the ability to form compounds with expanded valence shell, and is one of the reasons why it is such a versatile element.Oxygen is an essential element in the air that humans and other animals need to survive. It is the most abundant element on Earth and makes up 21% of the atmosphere. Oxygen is a colorless, odorless gas that is essential for the respiration of living organisms. It is also used in a variety of industrial processes, such as the production of steel, plastics
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Choose the words that correctly complete the paragraph. Susan ran the 400-m sprint at the track meet, and her final time was 65 s. She reported that her velocity in the race was 6.15 m/s. Susan’s statement was an inaccurate report of velocity because she mentioned only Choose... . She did not include Choose... , which is also a part of velocity.
Susan ran the 400-m sprint at the track meet, and her final time was 65 s. She reported that her velocity in the race was 6.15 m/s. Susan’s statement was an inaccurate because she mentioned only speed.
What is velocity?Velocity is a vector measure of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.
For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below. Susan’s statement was inaccurate because she mentioned only speed.
Therefore, susan’s statement was inaccurate because she mentioned only speed.
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draw three glucose molecules joined by a,1, 4 linkages. you only need to show o's and the h's attached to o's. you may draw ring or chair forms of glucose?
Glucose (C6H12O6, molecular weight 180.18) is a hexose—a monosaccharide containing six carbon atoms. Glucose is an aldehyde (contains -CHO group).
Glucose is an aldehyde (contains -CHO group). Its five carbons and one oxygen form a ring called a "pyranose ring", the most stable form for six-carbon aldoses. In this ring, each carbon is attached to a hydroxyl and hydrogen side group except for the fifth atom, which is attached to the sixth carbon on the outside of the ring, forming the CH2OH group. This ring structure is in equilibrium with the more reactive form.
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A sample of oxygen gas initially at 0.760 atm is cooled from 27°C to −93°C at constant volume.
What is its final pressure (in atm)?
Answer:
0.38 atm
Explanation:
Gay-Lussac's Law states:
[tex]\frac{P_1}{T_1} =\frac{P_2}{T_2}[/tex]
p = pressure
T = temperature
Change temps from Celcus to Kelvin:
27+273 = 360
-93+273 = 180
plugging the information in we have:
[tex]\frac{0.760 atm}{360K} = \frac{x}{180K}[/tex]
Cross multiply:
136.8 = 360x
divide 136.8 by 360 = .38 atm
Part 1: Read the following information on elements, compounds and mixtures. Fill in the blanks where necessary Elements: A pure substance containing only one kind of • An element is always uniform all the way through (homogeneous). An element be separated into simpler materials (except during nuclear reactions). • Over 100 existing elements are listed and classified on the Compounds: A pure substance containing two or more kinds of The atoms are __combined in some way. Often times (but not always) they come together to form groups of atoms called molecules • A compound is always homogeneous (uniform). Compounds _ be separated by physical means. Separating a compound requires a chemical reaction The properties of a compound are usually different than the properties of the elements it contains. Mixtures: • Two or more NOT chemically combined. • No reaction between substances. • Mixtures can be uniform (called ) and are known as solutions. • Mixtures can also be non-uniform (called • Mixtures can be separated into their components by chemical or physical means. • The properties of a mixture are similar to the properties of its components. Part 2: Classify each of the following as elements (E), compounds (C) or Mixtures (M). Write the letter X if it is none of these. Diamond (C) Sugar (C.H.O.) Milk Air Sulfuric Acid (H:50.) Gasoline Krypton (K) Bismuth (B1) Uranium (U) Water (H20) Alcohol (CH,OH) Pail of Garbage Ammonia (NH3)_ Salt (NaCl) Energy Wood Bronze Dry Ice (CO) _Baking Soda (NaHCO)_Titanium (T1) Iron (Fe) Electricity Popcorn A dog Gold (Au) Pizza Concrete Ink CHEM 1101 AY 2019-2020 SEM 2
A pure substance containing two or more kinds of the atoms are elements combined in some way. Compounds can be separated by physical means.
A physical approach cannot separate the components of a substance. Chemical or electrochemical methods must be used to separate the elements from compounds because they are chemically bonded together.
A compound is anything created when two or more separate chemical elements are mixed together in a specific proportion. Chemical connections that are challenging to break are created when the elements interact with one another. These bonds develop as a result of atoms sharing or trading electrons.
A mixture is a substance composed of two or more unrelated chemical components. A mixture is a physical combination of two or more distinct substances that can take the form of solutions, suspensions, or colloids.
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For the following reaction, 8.10 grams of silicon tetrafluoride are allowed to react with 5.90 grams of water.
Silicon tetrafluoride(s) + water(l) → hydrofluoric acid(aq) + silicon dioxide(s)
What is the maximum amount of hydrofluoric acid that can be formed?
What is the FORMULA for the limiting reagent?
What amount of the excess reagent remains after the reaction is complete?
The maximum amount of HF that can be formed is 0.312 mol. The formula for the limiting reagent is SiF4. The amount of excess H2O that was consumed is: n(H2O excess consumed) = 0.
What is limiting reagent?Limiting reagent is the reactant that is completely used up in reaction and hence determines when the reaction stops.
SiF4(s) + 2 H2O(l) → 4 HF(aq) + SiO2(s)
Molar masses of SiF4 and H2O are:
SiF4: 28.09 + 4 x 19.00 = 104.09 g/mol
H2O: 2 x 1.01 + 16.00 = 18.02 g/mol
Number of moles of each reactant is:
n(SiF4) = 8.10 g / 104.09 g/mol = 0.0779 mol
n(H2O) = 5.90 g / 18.02 g/mol = 0.327 mol
For SiF4: n(HF) = 0.0779 mol SiF4 × (4 mol HF / 1 mol SiF4) = 0.312 mol HF
For H2O: n(HF) = 0.327 mol H2O × (4 mol HF / 2 mol H2O) = 0.654 mol HF
We see that H2O produces a larger amount of HF than SiF4, indicating that SiF4 is limiting reagent. Therefore, the maximum amount of HF that can be formed is 0.312 mol.
The formula for the limiting reagent is SiF4.
From the balanced equation, we see that 1 mol of SiF4 reacts with 2 mol of H2O to produce 4 mol of HF. Therefore, the amount of H2O required to react with 0.0779 mol of SiF4 is:
n(H2O) = 0.0779 mol SiF4 × (2 mol H2O / 1 mol SiF4) = 0.1558 mol H2O
The amount of excess H2O that was consumed is: n(H2O excess consumed) = 0.
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need help i need it quick
Answer:
A
Explanation:
I would expect a sandwich to look like A
For a certain ideal gas, the temperature is
increased from 200 K to 602 K allowing pres-
sure, which is initially 1 atm, to vary while
the volume and number of moles of gas are
held constant. What is the new pressure?
Answer in units of atm.
Answer:
3.01 atmospheres
Step by step explanation:
The pressure of an ideal gas is directly proportional to its temperature and directly inversely proportional to its volume. Since the volume and number of moles are held constant, the pressure will be directly proportional to the temperature.
So, using the ideal gas law, P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, respectively, and P2 and T2 are the new pressure and temperature, respectively.
Substituting the initial values, P1 = 1 atm and T1 = 200 K, and the new temperature T2 = 602 K, we can solve for P2:
P2 = (P1 x T2) / T1 = (1 atm x 602 K) / 200 K = 3.01 atm
Therefore, the new pressure is 3.01 atm.
How much volume of the above stock solution you will need to prepare the riboflavin solutions of following concentrations: (a) 0.059 mM in 25 ml (b) 14 uM in 25 ml
0.013 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 14 μM solution.
To prepare a 0.059 mM riboflavin solution in 25 ml, we need to calculate the amount of riboflavin to add to 25 ml of water.
First, we need to convert the concentration from mM to μM:
0.059 mM × 1000 μM/1 mM = 59 μM
Next, we need to calculate the amount of riboflavin required to prepare a 25 ml solution with a concentration of 59 μM:
59 μM × 25 ml = 1475 μmol
Finally, we need to convert μmol to milligrams:
1475 μmol × (375.2 g/mol) / (10⁻⁶ μmol/mol) = 0.055 g
So, 0.055 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 0.059 mM solution.
To prepare a 14 μM riboflavin solution in 25 ml, we need to calculate the amount of riboflavin to add to 25 ml of water:
14 μM × 25 ml = 350 μmol
Finally, we need to convert μmol to milligrams:
350 μmol × (375.2 g/mol) / (10⁻⁶ μmol/mol) = 0.013 g
So, 0.013 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 14 μM solution.
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How many grams of KCL are needed to prepare 200.0mL of 0.900% (m/v) KCL solution?
Answer:
To prepare 200.0 mL of 0.900% (m/v) KCl solution, 91.4 grams of KCl are required. [1] This can be calculated by first converting the molarity to moles, then using the atomic mass of KCl to convert the number of moles to grams. For example, 2.45 moles of KCl is required to make 0.5 L of 2.45 M solution. [2] This calculation can also be applied to other salts, such as CuSO4.6H2O, to find the required mass to make a given 0.300 M solution. [3]
Explanation:
In order to prepare a 200.0 mL solution of 0.900% (m/v) KCL, you will need 1.8 grams of KCL.
Explanation:To resolve the question of 'How many grams of KCL are needed to prepare 200.0mL of 0.900% (m/v) KCL solution?', first we need to understand that the %(m/v) here means grams of solute per 100 mL of solution. Hence, for a 0.900% (m/v) KCL solution, there would be 0.900 grams of KCL per 100 mL of solution.
For preparing 200.0mL (which is double of 100mL), simply double the amount of KCL needed. So, 0.900 grams x 2 = 1.8 grams.
So, you therefore need 1.8 grams of KCL to prepare 200.0mL of 0.900% (m/v) KCL solution.
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an acid ___ .is a solution where the water molecules are intact accepts h and removes them from a solutionreleases h in a solution
An acid is a solution where the water molecules release H+ ions (hydrogen ions) into the solution.
An acid is characterized by its ability to release hydrogen ions (H+) into a solution. When an acid is dissolved in water, it donates hydrogen ions (H+) to the water molecules, making the solution acidic. This is why an acid is often described as a solution that releases H+ ions into the solution.
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Be sure to answer all parts.
Calculate the mass in grams of 16.8 mol of copper(I) carbonate. Enter your answer in scientific notation
with the correct number of significant figures.
Solving the Question
[tex]n=\dfrac{m}{M}[/tex]
m = massM = molar massRearrange for m:
[tex]m=nM[/tex]
Plug in given:
[tex]m=(16.8)M[/tex]
⇒ The molar mass of copper (1) carbonate is 187.1 g/mol:
[tex]m=(16.8)(187.1)\\m=3143.28[/tex]
Round to significant figures:
⇒ The given value has 3 significant figures:
[tex]m= 3140[/tex]
Convert to scientific notation:
3.14 × 10³ g
Answer3.14 × 10³ g
if the concentration of chloride is higher inside the cell what does that mean for the nernst potential
Inside the cell, the potassium concentration is higher than outside, whereas the sodium and chloride ion concentrations are lower.
How does chloride impact the potential of resting membranes?Since chloride is a negative ion, it must exit the cell in order for the membrane potential to change from -70 mV to -65 mV by making the cell more positive.
How does concentration affect the potential of the cell?The larger concentration enables the rise in voltage difference in an electrochemical cell. Increased voltage is seen as a result of the reaction moving more quickly in a forward direction due to the higher reactant concentration.
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A chemist measures the amount of iodine solid produced during an experiment. She finds that of iodine solid is produced. Calculate the number of moles of iodine solid produced.
The number of moles of iodine solid produced is 1.6 g.
What are moles?Moles are a standard scientific unit for measuring large quantities of very small entities, such as atoms.
Mass of iodine solid produced = 1.6 g
Iodine solid has a molecular formula: I2
Atomic mass of iodine = 126.904 g/mol
Therefore, molar mass of I2 solid = 2 x 126.904 = 253.808 g/mol
The number of moles of a given substance is the ratio of its mass to the molar mass
moles of I2 solid = mass of I2 solid/molar mass = 1.6 g/253.808 = 0.00630 moles
Hence, the moles of iodine solid produced are 0.00630 moles.
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S + 6 HNO3 --> H₂SO4 + 6 NO2 + 2H₂O
In the above equation how many grams of water can be made when 6 grams of HNO3 are
consumed?
Taking into account the reaction stoichiometry,50.57 grams of H₂O are formed when 6 grams of HNO₃ are consumed.
Reaction stoichiometryThe balanced reaction is:
S + 6 HNO₃ → H₂SO₄ + 6 NO₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
S: 1 moleHNO₃: 6 molesH₂SO₄: 1 moleNO₂: 6 molesH₂O: 2 molesThe molar mass of the compounds is:
S: 32 g/moleHNO₃: 63 g/moleH₂SO₄: 98 g/moleNO₂: 46 g/moleH₂O: 18 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
S: 1 mole ×32 g/mole= 32 gramsHNO₃: 6 moles ×63 g/mole= 378 gramsH₂SO₄: 1 mole ×98 g/mole= 98 gramsNO₂: 6 moles ×46 g/mole= 276 gramsH₂O: 2 moles× 18 g/mole= 36 gramsMass of H₂O formedThe following rule of three can be applied: if by reaction stoichiometry 378 grams of HNO₃ form 36 grams of H₂O, 6 grams of HNO₃ form how much mass of H₂O?
mass of H₂O= (6 grams of HNO₃×36 grams of H₂O)÷378 grams of HNO₃
mass of H₂O= 0.57 grams
Finally, 50.57 grams of H₂O are made.
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within atoms, there is an ongoing relationship between the nucleus and the electrons. categorize the characteristics by whether they describe the nucleus or electrons.
Within atoms, there is an ongoing relationship between the nucleus and the electrons. Characteristics describe the nucleus are:
Positively chargedAttracts the negatively charged particles into the space surrounding itCharacteristic describe electrons :
Negatively chargedCan gain or lose energyCan move from one atom to anotherCan bond two atoms into a molecule when shared between two atomsOn the basis of the 1909 Geiger-Marsden gold foil experiment, Ernest Rutherford identified the atomic nucleus in 1911, which is the compact, dense region made up of protons and neutrons at the heart of an atom. Positively charged nucleus draws negatively charged particles into the area around it.
The elementary electric charge of the electron is a negative one, making it a subatomic particle. Due to their lack of components or substructure, electrons, which are part of the lepton particle family's first generation, are typically regarded to be elementary particles.
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An aqueous solution at 25°C has a H3O+ concentration of ×8.810−12M . Calculate the OH− concentration. Be sure your answer has the correct number of significant digits.
The OH⁻ concentration will be 10^2.9031
The amount of hydrogen ions present in a solution or substance is first and foremost indicated by the pH scale, which measures acidity or alkalinity.
The concentration of hydrogen ions, or H₃O⁺, is what is referred to as the pH, which is defined as the negative base 10 logarithm of the activity of hydrogen ions:
pH= - log [H⁺]= - log [H₃O⁺]
An aqueous solution at 25°C has a H₃O⁺ concentration of 8.8 x 10⁻¹²M
pH= - log [H⁺]= - log [H₃O⁺]
pH= - log [8.8 x 10⁻¹²M]
pH = 11.0969
The following relationship can be established between pH and pOH:
pOH + pH= 14
pOH = 14- pH
pOH = 14- 11.0969
pOH = 2.9031
pOH = - log [OH]
2.9031 = - log [OH]
[OH] = 10^2.9031
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Mathematical Representations Quick Check
How does the formation of water from hydrogen and oxygen demonstrate the conservation of mass? (1 point)
Storm
The atomic number of the reactants equals the atomic number of the product, and the product has the same
number of molecules as the reactants.
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same
number of atoms as the reactants.
The atomic number of the reactants equals the atomic number of the product, and the product has the same
number of atoms as the reactants
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same.
number of molecules as the reactants.
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same.
What is the conservation of mass?The conservation of mass is a fundamental principle in physics and chemistry that states that the total mass of a system remains constant, regardless of any changes that take place within the system. In other words, mass cannot be created or destroyed, only transformed from one form to another.
This law applies to both physical and chemical processes, and is a key concept in fields such as thermodynamics, mechanics, and material science. It forms the basis for our understanding of the behavior of matter and energy in the universe, and is widely used in scientific and engineering calculations and experiments.
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Answer:
1. the reactants and the products have the same number of atoms of the same elements
2. the mass of one titanium atom is equal to the mass of four carbon atom
3. The atomic mass of the reactants equals the atomic mass of the product, and the product has the same number of atoms as the reactants.
4. 80amu
5. A molecule with two atoms combined with a molecule with three atoms to produce a molecule with a mass of 84 u.
Explanation: got 100% hope you get the same!
what is the awnser to this
Answer: 2/3
Explanation:
Photoelectron spectroscopy typically measures the binding energy of electrons in units of
MJ/mol
. Use the value for the energy of an electron in a hydrogen atom in the ground state that you just calculated using the Bohr model to predict the binding energy for the electron in hydrogen in units of
MJ/mol
. Note: If you are not sure where to start to answer this question, click on the "Extra Info" button. Binding energy for the electron in hydrogen predicted by the Bohr model
=
MJ/mol
Check your calculated value. To answer this question, remember that
E binding =−E e−
​ . It can also be helpful to think of the units for the energy of the electron as J/electron, while the units for the binding energy are
MJ/mol
of electrons. You will need Avogadro's number and conversion factor for the prefix mega (M).
Previous question
The predicted binding energy for the electron in hydrogen in units of MJ/mol is -13.6 MJ/mol.
Using the value for the energy of an electron in a hydrogen atom in the ground state calculated using the Bohr model, we have:
E_binding = -E_electron = -(13.6 eV) = -2.18 × 10²-18 J/electron
To convert from J/electron to MJ/mol, we can use the following conversions:
1 J/electron * (1 mol/6.022 x 10²23 electrons) = 1.66 x 10²-24 J/mol
1 MJ = 10²6 J
So, putting it all together:
E_binding = (-2.18 x 10²-18 J/electron) * (1 mol/6.022 x 10²23 electrons) * (10²-6 MJ/1 J) = -13.6 MJ/mol
Therefore, the predicted binding energy for the electron in hydrogen in units of MJ/mol is -13.6 MJ/mol.
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Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:
Mg2+, Al3+, F−, O2−
Answer:
Explanation:
Here are four binary ionic compounds that could be formed from the given ions, along with their empirical formulas:
Magnesium fluoride: Mg2+ + 2F- → MgF2 (empirical formula: MF2)
Aluminum oxide: 2Al3+ + 3O2- → Al2O3 (empirical formula: Al2O3)
Magnesium oxide: Mg2+ + O2- → MgO (empirical formula: MO)
Aluminum fluoride: Al3+ + 3F- → AlF3 (empirical formula: AlF3)
In each case, the positive and negative charges balance to give a neutral compound. The empirical formula of each compound shows the simplest ratio of the elements present in the compound.