La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?

Answers

Answer 1

Answer:

Falso.

Step-by-step explanation:

Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]

[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.

(c) El exponente es un negativo par.

Si [tex]n[/tex] es par, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' = c'[/tex], la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]

[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.


Related Questions

Review your answers to Question 4. What happens to the coordinates of a shape when the shape reflects about the line y = x? Explain.

Answers

Answer:

The x and y coordinates swap position

Step-by-step explanation:

Given

Reflection across: [tex]y = x[/tex]

Required

What happens to the coordinate

When a point is reflected about [tex]y = x[/tex], the x and y coordinates swap position

i.e.

[tex](x,y) \to (y,x)[/tex]

Answer:

When the shape reflects about the line y = x, the x-coordinate and the y-coordinate of each point are swapped.

Step-by-step explanation:

Solve the system of equations.
5x – 4y = -10
y = 2 x – 5
x =
y =

Answers

Answer:

6x2+3y2=12,x+y=2,2x-y=-1x+y=4,x-y=2

Step-by-step explanation:

I just know.

Answer:

Step-by-step explanation:

5x – 4y = -10

y = 2 x – 5

Rearrage the equation:

5x – 4y = -10 (1)

-2 x +y =  5.  (2)

pluging variable y equation2 in 1

5x - 4•(2x-5) = -10

 -3x = -30

Solve equation [1] for the variable  x  

3x = 30

x = 10

x = 10

y = 2x-5

Use the  x  value to solve for  y  

y = 2(10)-5 = 15

x= 10

y= 15

I need some one to help me!!

Is (7, 0) a solution to the equation y = x − 7?

Answers

Answer:

Yes

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Coordinates (x, y)

Step-by-step explanation:

Step 1: Define

Identify

Point (7, 0)

Equation y = x - 7

Step 2: Find

Substitute in point [Equation]:                                                                         0 = 7 - 7Subtract:                                                                                                            0 = 0

Since 0 = 0 is true, then it would be a solution to the equation.

How many triangles are there in the picture?
Clue, there are more than 30.

Answers

Answer:

36?

Step-by-step explanation:

Answer:

42 Triangles

Step-by-step explanation:

Count all the triangles one by one and determine the # of triangles.

If f(x) = [tex]\frac{1}{9}[/tex] x-2, what is [tex]F^{-1}[/tex](x)

Answers

Answer:

Solution given:

f(x) = [tex]\frac{1}{9}[/tex] x-2

let f(x)=y

y = [tex]\frac{1}{9}[/tex] x-2

interchanging role of x and y

x= [tex]\frac{1}{9}[/tex] y-2

x+2= [tex]\frac{1}{9}[/tex] y

y=9(x+2)

y=9x+18

So

F-¹(x)=9x+18

and

F-¹(-1)=9*-1+18=-9+18=9

help me right now pls ?!

Answers

Answer:

B) =−7j−k−1

Step-by-step explanation:

10k+17-7j-18-11k what we have

=(−7j)+(10k+−11k)+(17+−18) combine like terms

=−7j−k−1

Answer:

-7j-k-1

Step-by-step explanation:

for this problem you have to subtract the like terms while following the order of the equation (start with the terms on the left and move terms)

Step 1:

-7j has no like terms

= -7j

Step 2:

10k and -11k are like terms

10k-11k

= -1k

Step 3:

17 and -18 are like terms

17-18

= -1

Step 4:

put all simplified terms together

=-7j-k-1

Adya and Ashley complete a work separately in 20 and 25 days respectively. After 10 days of their working together, they both left then Amber came and completed the remaining work in 3 days. If Amber alone would do the work, calculate how many days he would take to complete the work.?​

Answers

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

Number of days Adya took to complete the work = 20

Work done by Adya in 1 day = [tex]\frac{1}{20}[/tex]

Number of days Ashley took to complete the work = 25

Work done by Ashley in 1 day = [tex]\frac{1}{25}[/tex]

So,

Total work by Adya & Ashley in 1 day =

[tex] \frac{1}{20} + \frac{1}{20} \\ = \frac{5 + 4}{100} \\ = \frac{9}{100} [/tex]

•°• Their total work in 10 days =

[tex] \frac{9 \times 10}{100} \\ = \frac{90}{100} \\ = \frac{9}{10} [/tex]

Now,

The work left to be completed =

[tex]1 - \frac{9}{10} \\ = \frac{10}{10} - \frac{9}{10} \\ = \frac{1}{10} [/tex]

From this we know that,

Amber completes [tex]\frac{1}{10}[/tex] of the work in 3 days.

So,

Time taken by Amber to complete the whole work =

[tex]3 \times 10 \\ = 30 \: \: days[/tex]

↦ If Amber alone would do the whole work, he would take [tex]\boxed{30 \ \ days}[/tex] to complete it.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

IM AM SO CONFUSED
Find the solution set.
8x2 - 2x – 1=0
Separate the two values with a comma.

Answers

Hello,

Answer (1/2,-1/4)

[tex]8x^2-2x-1=0\\\\8x^2-4x+2x-1=0\\\\4x(2x-1)+2x-1=0\\\\(2x-1)(4x+1)=0\\\\sol=\{\dfrac{1}{2} ,-\dfrac{1}{4} \}\\[/tex]

Integrate with respect to x

1/√(1-2x)

Answers

Answer:

-√(1 - 2x) + C

Step-by-step explanation:

1/√(1-2x)

We want to integrate it. Thus;

∫1/√(1 - 2x) dx

Let u = 1 - 2x

Thus;

du/dx = -2

Thus, dx = -½du

Thus,we now have;

-½∫1/√(u) du

By application of power rule, we will now have;

-½∫1/√(u) du = -√(u) + C

Plugging in the value of u, we will have;

-√(1 - 2x) + C

How do angles inside a polygon affect the sides of the polygon?

Answers

Hello,

Let 's  n the number of sides,

R the radius of the circonscrit circle,

c the side of the polygon (c like côté)

Angle in the center is 360/n and its half is 180/n

(c/2)/R=sin(180/n)

Inside angles are (180-360/n)/2 = 90-180/n (°)

Find the highest common factor (HCF) for 36, 84 and 108 ​

Answers

Answer:

Check your question one time

For f(x) = 6x + 20, what is the value of x for which f(x)= -4 ?

Answers

Answer:

x = -4

Step-by-step explanation:

Plug in -4 into the function and solve for x:

f(x) = 6x + 20

-4 = 6x + 20

-24 = 6x

-4 = x

So, the answer is x = -4


PLEASE HELP.
if v1….

Answers

I believe the answer is 4.4

which of the following is the equation of a line that passes through the points (1,6) and(2,1)

Answers

Answer:

y=1x-5

Step-by-step explanation:

it goes over to the right 1 time and down 5

(1+1,6-5)=(2,1)

40 points if helped question is in the picture

Answers

Answer:

15 9 3

Step-by-step explanation:

15 9 3

sorry i guessed on this one

but it does work

when they said 3 in the first sentence i helped me guess

Answer:

first term = 15

second term = 9

Third term = 3

Step-by-step explanation:

Let the first term be 3x

Let the second term be = 3x - 6       [ 6 less than first term]

Let the third term be = 1/5 of 3x

                                 [tex]=\frac{1}{5} \times 3x\\\\=\frac{3}{5}x[/tex]

Difference between first and third term = 12

That is ,

           [tex]3x - \frac{3}{5}x = 12\\\\\frac{(3x \times 5) - 3x }{5} = 12\\\\15x - 3x = 12 \times 5\\\\12x = 60\\\\x = \frac{60}{12} = 5\\\\Therefore , \ first \ term = 3x = 3 \times 5 = 15\\\\second \term = 3x - 6 = 3( 5) - 6 = 15 - 6 = 9\\\\Third \ term = \frac{1}{5} \times 3x = \frac{1}{5} \times (3 \times 5) = 3[/tex]

Will mark brainlest help me please​

Answers

Answer:

no le entiendo por qué estás en inglés

Which of the following values is closest to the standard deviation for the set
of data shown below?
23, 64, 73, 47, 22, 46, 34, 48, 67, 89, 83, 12, 23, 44, 16

Answers

It’s A thinks for the time

What is the value of (3/10)^3?

♡ 3/1000
♡27/1000
♡9/10
♡27/10

Answers

Answer:

27/10 is the value of (3/10)^3.

Step-by-step explanation:

It is also written as 0.027

The equation for the circle below is x2 + y2 = 100. What is the length of the
circle's radius?

Answers

Answer:

Step-by-step explanation:

x²+y² =(Radius)²

x²+y² =10². So the radius is 10

Answer:

radius = 10

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ( where r is the radius )

x² + y² = 100 ← is in this form

with r² = 100 ( take the square root of both sides )

r = [tex]\sqrt{100}[/tex] = 10

Select the correct answer from each drop-down menu.
The equation of a line is 3/5x+1/3y=1/15
The x-intercept of the line is
and its y-intercept is


Answers

Answer:x intercept is where the line is crossing the x axis or where y=0

y intercept is where the line crosses the y axis or where x=0

to find them, set other ting to zero

3/5x+1/3y=1/15

xintercept, set y=0

3/5x+1/3(0)=1/15

3/5x+0=1/15

3/5x=1/15

times 5/3 both sides

x=1/9

xintercept is x=1/9

yintercet

set x=0

3/5(0)+1/3y=1/15

0+1/3y=1/15

1/3y=1/15

times 3/1 both sides

y=1/5

yintercept is y=1/5

xint is x=1/9

yint is y=1/5

Step-by-step explanation:

The equation of line is ( 3/5 )x+ ( 1/3)y = ( 1/15 ) , where x-intercept of the line is ( 1/9 , 0 ) and the y-intercept of the line is ( 0 , 1/5 )

What is an Equation of a line?

The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept

And y - y₁ = m ( x - x₁ )

y = y-coordinate of second point

y₁ = y-coordinate of point one

m = slope

x = x-coordinate of second point

x₁ = x-coordinate of point one

The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given data ,

Let the equation of line be represented as A

( 3/5 )x+ ( 1/3)y = ( 1/15 )

To find the x-intercept of the line, we set y = 0 and solve for x:

3/5x + 1/3(0) = 1/15

3/5x = 1/15

x = (1/15) ÷ (3/5) = 1/9

So the x-intercept of the line is (1/9, 0)

To find the y-intercept of the line, we set x = 0 and solve for y:

3/5(0) + 1/3y = 1/15

1/3y = 1/15

y = (1/15) ÷ (1/3) = 1/5

So the y-intercept of the line is (0, 1/5)

Hence , the equation of line is solved

To learn more about equation of line click :

https://brainly.com/question/14200719

#SPJ2

One number is 9 times another. Their product is 27 times their sum. Find the numbers.


the answer is not 3 btw

Answers

Answer:

270 & 30

Step-by-step explanation:

let the number is n,

the equation :

n× 1/9 n= 27(n +1/9 n)

1/9 n² = 27n + 3n

1/9 n² = 30n

1/9n²- 30n = 0

n(1/9n -30)= 0

n = 0 or

1/9n = 30 => n = 30×9 = 270

270 is a number,

the other : 270/9 = 30

Find the length of side xx in simplest radical form with a rational denominator.

Answers

Answer:

2/3.

Step-by-step explanation:

.

Answer:

Solution given:

the relationship between perpendicular and base is given by tan angle

Tan 60=opposite/Adjacent

[tex]\sqrt{3}[/tex]=x/3

x=[tex]3\sqrt{3}[/tex]

The value of x is [tex]3\sqrt{3}[/tex]

Can someone help me with this math homework please!

Answers

うsじょうぉじょあそlざ

ありおdごうおの

Answer:

First drop box: 40x + 18(x - 3) = 468

Second drop box: $6

Step-by-step explanation:

Explanation in progress! Enjoy your answer first then come back for the explanation once you've done it (●'◡'●)

PLEASE PLEASE HELP ILL GIVE BRAINLY

Answers

Answer:

In this case, we can do substitution.

Step-by-step explanation:

For the first one, (s - t)(x) = ((x - 5) - 4x^2)(x) = x^2 - 21x

For the second one, (s*t)(x) = ((x - 5) *4x^2)(x) = 4x^4 - 20x^3

And for the last one,  (s+t)(-2) = ((x - 5) + 4x^2)(-2) = -8x^2 - 2x + 10

Hope your happy with the answer :)

Three less than 3 times a number, n, is
19 more than twice the number. What
is the number?
А
17
B
19
21
D 22

Answers

The equation is:

3n - 3 = 2n + 19

=> 3n - 2n = 19 + 3

=> n = 22

So, the answer is 22.

The table shows information about water used in a household.
The value for April is missing.



The mean monthly water used for the six months is 18 m

Work out the value for April.

Answers

Answer:

is there is no value of April

Step-by-step explanation:

so the value of the month April is zero

Juan compró un led TV en cuotas que costó $ 76.000=. Si le falta pagar 3 cuotas y ya pagó $ 47.000, ¿Cuál es el valor de cada cuota fija?

Answers

Respuesta:

$ 9666. 67

Explicación paso a paso:

Costo de TV = $ 76,000

Número de cuotas = 3

Monto ya pagado = $ 47000

Amontof cada cuota fija = Cantidad que queda por pagar / 3

Cantidad que queda por pagar = Costo de TV - Cantidad ya pagada

Cantidad que queda por pagar = $ (76000 - 47000) = $ 29000

Monto de cada cuota fija = $ 29000/3 = $ 9666. 67

What is the result of converting 60 ounces to punds remember there are 16 ounces in a pound pleasdnsjjsjs

Answers

Answer:

A. 3.75 pounds

Step-by-step explanation:

16 ounces = 1 pound

converting 60 ounces to pounds

Let x = number of pounds

60 ounces = x pounds

Find the proportion

16 / 1 = 60 / x

Cross product

16 * x = 1 * 60

16x = 60

Divide both sides by 16

x = 60/16

x = 3.75

Therefore,

60 ounces = 3.75 pounds

The cost of having a window fixed is $175 plus $30 per hour of labor. Using h for the number of hours of labor, write an expression that represents the total cost.

Answers

Answer:

175 + 30h

Step-by-step explanation:

Hope this helps

Answer:

total cost = 175+30h

Step-by-step explanation:

Total cost = fixed cost + cost per hour * hours

total cost = 175+30h  where h is the number of hours

Write the equation for a parabola with a focus at (6,-4) and a directrix at y= -7

Answers

Given:

The focus of the parabola is at (6,-4).

Directrix at y=-7.

To find:

The equation of the parabola.

Solution:

The general equation of a parabola is:

[tex]y=\dfrac{1}{4p}(x-h)^2+k[/tex]                  ...(i)

Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.

The focus of the parabola is at (6,-4).

[tex](h,k+p)=(6,-4)[/tex]

On comparing both sides, we get

[tex]h=6[/tex]

[tex]k+p=-4[/tex]                            ...(ii)

Directrix at y=-7. So,

[tex]k-p=-7[/tex]                            ...(iii)

Adding (ii) and (iii), we get

[tex]2k=-11[/tex]

[tex]k=\dfrac{-11}{2}[/tex]

[tex]k=-5.5[/tex]

Putting [tex]k=-5.5[/tex] in (ii), we get

[tex]-5.5+p=-4[/tex]

[tex]p=-4+5.5[/tex]

[tex]p=1.5[/tex]

Putting [tex]h=6, k=-5.5,p=1.5[/tex] in (i), we get

[tex]y=\dfrac{1}{4(1.5)}(x-6)^2+(-5.5)[/tex]

[tex]y=\dfrac{1}{6}(x-6)^2-5.5[/tex]

Therefore, the equation of the parabola is [tex]y=\dfrac{1}{6}(x-6)^2-5.5[/tex].

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