Kira studied data collected on the school basketball team for 1 season she noticed that a player on the team had 13 succesful free throws out of a total of 20

Answer:

9

Step-by-step explanation:

we just replace n with 15

A(n) =16 + (N - 1) (-0.5)

      =16 + (15 - 1) (-0.5)

      =16-7.5+0.5

       =9

hope it helps

Answer:

Janet uses less than 4 cups of flour because is less than 4.

Step-by-step explanation:

She is using 3/8 of 4 so less than. Then you use 4 not 1 because there is 4 cups.

Answer:

She uses less than four cups because 3/8 (1.5) is less than 4.

Step-by-step explanation:

Answer:

Yes, he got the correct quotient

Step-by-step explanation:

1.5 divided by 1/3 is 4.5, and 4.5 is equal to 4 1/2

Answer:

Sage did it right.

your work:

1 1/2 ÷ 1/3

3/2 ÷ 1/3

3/2 × 3/1

9/2

4 1/2

Step-by-step explanation:

first convert 1 1/2 into an improper fraction:

multiply the 2 and 1, you get 2, than add that to the current numerator to get a new one. You get 3/2 as your improper fraction

you now have: 3/2 ÷ 1/3

then turn the division sign into a multiplication sign by flipping the divisor:

you get 3/2 × 3/1

solve this:

multiply the numerators together, you get 9 as a new numerator

multiply your denominators, you get 2 as your new denominator

so now you have 9/2

next turn this into a mixed fraction, you get 4 1/2

so Sage did it right.

Answer:

-3.82

Step-by-step explanation:

You are going up the line of negative numbers so you have to add o.o2 to 3.8 (3.80).

Answer:

2√3/3

Step-by-step explanation:

Sec(330°)

=1/cos(330°)

=1/√3/2 (since Cos (330°)=√3/2

=1×2/√3

=2/√3×√3/√3

=2√3/3

Answer:

[tex]\implies \sec 330^o = \dfrac{2}{\sqrt3}=\dfrac{2\sqrt{3}}{3}[/tex]

Step-by-step explanation:

Given :-

And we need to find out its value . Firstly we know that 330° lies in 4th quadrant . And In fourth quadrant , cosine and secant are positive . Therefore , the result will be positive. Now we know that ,

[tex]\implies \sec (360^o-\theta)= \sec\theta [/tex]

Using this ,

[tex]\implies \sec (330^o) \\\\\rm\implies sec(360^o-30^o) \\\\\rm\implies \sec 30^o [/tex]

And the value of sec 30° is ,

[tex]\implies \sec 30^o = \dfrac{2}{\sqrt3}[/tex]

And by question we need to write it with a rational denominator .So on rationalising the denominator , we have ,

[tex]\implies \sec 30^o = \dfrac{2}{\sqrt3}=\boxed{\red{\dfrac{2\sqrt3}{3}}}[/tex]

Hence the required answer is 2√3/3.

Answer:

1164 are the total number of miles he rode in 6 months.

Step-by-step explanation:

It means:

Thus,

Thus, the number of miles he rode in 6 months would be = 194×6 = 1164 miles

Therefore, 1164 are the total number of miles he rode in 6 months.

Answer:

ΔABD is an obtuse triangle

Step-by-step explanation:

The type of a triangle according to its angle measures

In triangle ABD

∵ m∠ABD = 100°

∵ m∠BAD = 50°

→ The sum of the interior angles of a triangle is 180°

∴ m∠ABD + m∠BAD + m∠BDA = 180°

∴ 100 + 50 + m∠BDA = 180

∴ 150 + m∠BDA = 180

→ Subtract 150 from both sides

∴ m∠BDA = 30°

∵ m∠ABD = 100°

∴ ∠ABD is an obtuse angle

∵ m∠BAD = 50° and m∠BDA = 30°

∴ ∠BAD and ∠BDA are acute angles

∵ ΔABD has 1 obtuse angle and 2 acute angles

∴ ΔABD is an obtuse triangle

Answer:

The type of function the equation represents is "directly proportional" ⇒ B

Step-by-step explanation:

Let us solve the question using the rules above

∵ The equation of the function is y = -8x

→ Compare it with the two forms above

∵ The equation is in the form of y = kx, where k = -8

∴ The equation represents directly proportional

∴ The type of function the equation represents is "directly proportional"

Answer:

y=79/73x+644/73

theres the equation, enjoy <3

Step-by-step explanation:

2.6% b/c 1820×2.6/100

Answer:

a) The class interval containing the median is the interval 2 ≤ h <  3

b) The mean number of hours the children spent on their tablets is 2.2 hours.

Step-by-step explanation:

a) The given parameters are;

The number of students that spent 0 ≤ h < 1 hour = 4

The number of students that spent 1 ≤ h < 2 hours = 8

The number of students that spent 2 ≤ h < 3 hours = 11

The number of students that spent 3 ≤ h < 4 hours = 7

The median is given by the location of the 15th child which is located in the interval given as follows;

We note that the total number of children is obtained by adding the  frequencies of the intervals together, as follows;

The number of children = 4 + 8 + 11 + 7 = 30

The frequency of the first interval = 4

The sum of the first + Second intervals = 4 + 8 = 12

The sum of the first + Second + Third intervals = 4 + 8 + 11 = 23

Therefore, the class interval containing the median is the interval 2 ≤ h <  3

b) We use the midpoint of each class interval to find the mean as follows;

The mean = ∑fh/∑h

∴ The mean = (4 × 0.5 + 8 × 1.5 + 11 × 2.5 + 7 × 3.5)/(4 + 8 + 11 + 7) = 2.2

The mean number of hours the children spent on their tablets = 2.2 hours.

Step-by-step explanation:

Let x represent the number.

We have 8x - 6 = 7.

Therefore 8x = 13 and x = 1.625.

Answer:

The slope is 3

The y-intercept is -2

The linear equation is y = 3x - 2

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

∵ A line passes through points (2, 4) and (6, 16)

∴ x1 = 2 and y1 = 4

∴ x2 = 6 and y2 = 16

→ Substitute them in the rule of the slope above to find it

∵ m = [tex]\frac{16-4}{6-2}[/tex] = [tex]\frac{12}{4}[/tex] = 3

∴ m = 3

→ Substitute it in the form of the equation above

∴ y = 3x + b

→ To find b substitute x and y in the equation by the coordinates of

   a point on the line

∵ Point (2, 4) is on the line

∴ x = 2 and y = 4

∵ 4 = 3(2) + b

∴ 4 = 6 + b

→ Subtract 6 from both sides to find b

∵ 4 - 6 = 6 - 6 + b

∴ -2 = b

→ Substitute its value on the equation above

∵ y = 3x + (-2)

∴ y = 3x - 2

→ Let us answer the questions

The slope is 3

The y-intercept is -2

The linear equation is y = 3x - 2

Answer:

I think u kept option incorrect but the correct answer is 1/4

Answer:

f(x)=-[tex]\frac{5}{2}\\[/tex]x+9

Step-by-step explanation:

Use the slope formula and slope intercept formula form y=mx + b to find the equation

Answer:

She practiced a total of 64.5 hours

Step-by-step explanation:

Here, we need to know the number of hours practiced on both per day

Mathematically, that will be;

0.75 + 1.4 = 2.15 hours per day

So in 30 days ; the total number of hours will be

30 * 2.15 = 64.5 hours

Answer:

The stack of blocks is 25.96 inches tall

Step-by-step explanation:

The Volume of a Cube

Given a cube-shaped figure of side length L, the volume is calculated by:

[tex]V=L^3[/tex]

If the volume is known, then the side length can be found by solving for L:

[tex]L=\sqrt[3]{L}[/tex]

We are given three cube-shaped blocks with known volumes. We'll find the individual side lengths and add them up to find the height that results when they stack up vertically.

Block 1, volume 375 cube inches:

[tex]L_1=\sqrt[3]{375}=7.21\ inch[/tex]

Block 2, volume 648 cube inches:

[tex]L_2=\sqrt[3]{648}=8.65\ inch[/tex]

Block 3, volume 1029 cube inches:

[tex]L_3=\sqrt[3]{1029}=10.10\ inch[/tex]

Total height=7.21 inch+8.65 inch+10.10 inch=25.96 inch

The stack of blocks is 25.96 inches tall

Answer:

If Susan bought 12 ounces that would equal to .75 pounds

Step-by-step explanation:

Answer: 45.65 is incorrect.

Step-by-step explanation: it’s a place value problem; right of the decimal is ones, tens, hundredths, thousandths which is 4 place values so 45.065 shows the correct placement

Answer:

Step-by-step explanation:

2/5=40/100 40 out of 100 is 40%

Answer:

A

Step-by-step explanation:

took test on edge

Answer:

A

Step-by-step explanation:

Just took the test

tan(2A) + sin(2A) = sin(2A)/cos(2A) + sin(2A)

• rewrite tan = sin/cos

… = 1/cos(2A) (sin(2A) + sin(2A) cos(2A))

• expand the functions of 2A using the double angle identities

… = 2/(2 cos²(A) - 1) (sin(A) cos(A) + sin(A) cos(A) (cos²(A) - sin²(A)))

• factor out sin(A) cos(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (1 + cos²(A) - sin²(A))

• simplify the last factor using the Pythagorean identity, 1 - sin²(A) = cos²(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (2 cos²(A))

• rearrange terms in the product

… = 2 sin(A) cos(A) (2 cos²(A))/(2 cos²(A) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(A)

… = 4 sin(A) cos(A) / (2 - 1/cos²(A))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(A) cos(A) / (2 - sec²(A))

• divide through again by cos²(A)

… = (4 sin(A)/cos(A)) / (2/cos²(A) - sec²(A)/cos²(A))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(A) / (2 sec²(A) - sec⁴(A))

• factor out sec²(A) in the denominator

… = 4 tan(A) / (sec²(A) (2 - sec²(A)))

• rewrite using the Pythagorean identity, sec²(A) = 1 + tan²(A)

… = 4 tan(A) / ((1 + tan²(A)) (2 - (1 + tan²(A))))

• simplify

… = 4 tan(A) / ((1 + tan²(A)) (1 - tan²(A)))

• condense the denominator as the difference of squares

… = 4 tan(A) / (1 - tan⁴(A))

(Note that some of these steps are optional or can be done simultaneously)

Answer:

C

Step-by-step explanation:

Answer:

what I think this question has mistake