Answer:
Its A
Explanation:
To reduce the strength of an electromagnet, Juan must reduced the number of loops in the wire.
What is electromagnetic field strength?
The strength of an electromagnetic is the effect or force that an electromagnet exerts in a given field.
The strength of an induced emf in a given magnetic field is given by;
emf = NBA/t
where;
N is number of turns of the magnetB is magnetic field strengthA is area of the coilDecrease in number of turns of the wire, reduces the strength of the magnetic field.
Thus, to reduce the strength of an electromagnet, Juan must reduced the number of loops in the wire.
Learn more about electromagnet here: https://brainly.com/question/12555869
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What is the correct interpretation of this diagram?
Forces from the left and the right are unbalanced. The object moves left.
Up and down forces are balanced. The force toward the right is greater than the force toward the left. The object will move toward the right.
Up and down forces are balanced. The object does not move.
Up and down forces are balanced. The force toward the right is greater than the force toward the left. The object will move toward the left.
Answer:
where is the diagram?
Explanation:
here is the diagram
hope this helps a little cuz i cant paste pictures here
Four directional arrows with labels five hundred seventy-nine Newtons, four hundred eighty-seven Newtons, five hundred seventy-nine Newtons and six hundred thirty-two Newtons
How does mass affect acceleration during free fall?
Pick a hypothesis below now.
If an object falls freely, then heavy objects accelerate more than light objects.
If an object falls freely, then heavy objects accelerate less than light objects.
If an object falls freely, then heavy objects accelerate nearly the same as light objects.
Answer:
it is the 3rd one
Explanation:
If an object falls freely, then heavy objects accelerate nearly the same as light objects.
Two identical spheres (of equal mass) a distance of 10 meters apart exert a force of gravity of 0.00050 N on each other. What are their masses?
Answer:
From the following statements about mechanical waves, identify those that are true for transverse mechanical waves only, those that are true for longitudinal mechanical waves only, and those that are true for both types of waves.
Explanation:
You are interested in space travel and want to learn more facts about space travel.
Which would be the best source of information? (2 points)
The Star Wars web page NASA web page
A book about planets
A magazine article
Answer:
A Book about Planets
Explanation:
Answer:
Nasa web page
Explanation:
If a 40 kg pumpkin is thrown through your neighbors window with an acceleration rate of 2 m/s, what’s the force you through it with?
Answer:
[tex]\boxed {\boxed {\sf 80 \ Newtons}}[/tex]
Explanation:
Force can be found by multiplying the mass by the acceleration.
[tex]F=m*a[/tex]
The mass of the pumpkin is 40 kilograms.
The acceleration of the pumpkin is 2 meters per second squared.
[tex]m= 40 \ kg \\a= 2 \ m/s^2[/tex]
Substitute the values into the formula.
[tex]F= 40 \ kg *2 \ m/s^2[/tex]
Multiply.
[tex]F= 80 \ kg*m/s^2[/tex]
A kilogram meter per second squared is equal to 1 Newton. Therefore, our answer of 80 kg*m/s² is also equal to 80 Newtons (N).
[tex]F=80 \ N[/tex]
The force is 80 Newtons.
Answer:
80 newton
Explanation:
F=ma so we now substitute our values I. E 40kg*2m/s=80 Newton
how we will gonna solve this question?
0.05cm=_______=mm
Answer:
It would be 0.5 millimeter !
Explanation:
1 cm is equal to 10 mm. You'll just need to move the decimal point over ! :))
A hole is punched at A in a plastic sheet by applying a 660-N force P to end D of lever CD, which is rigidly attached to the solid cylindrical shaft BC. Design specifications require that the displacement of D should not exceed 15 mm from the time the punch first touches the plastic sheet to the time it actually penetrates it. Determine the required diameter of shaft BC if the shaft is made of a steel with G.
Answer:
hello your question lacks some data and required diagram
G = 77 GPa, т all = 80 MPa
answer : required diameter = 252.65 * 10-^3 m
Explanation:
Given data :
force ( P ) = 660 -N force
displacement = 15 mm
G = 77 GPa
т all = 80 MPa
i) Determine the required diameter of shaft BC
considering the vertical displacement ( looking at handle DC from free body diagram )
D' = 0.3 sin∅ , where D = 0.015
hence ∅ = 2.8659°
calculate the torque acting at angle ∅ of CD on the shaft BC
Torque = 660 * 0.3 cos∅
= 660 * 0.3 * cos 2.8659 = 198 * -0.9622 = 190.5156 N
hello attached is the remaining part of the solution
The required diameter of shaft BC will be 252.65 ×10⁻³A shaft's diameter is the line that goes through its center and splits it into two equal halves.
What is the diameter?A diameter is a line that travels through the center of a sphere and intersects the circumference at opposing ends. It measures twice as long as the sphere's radius
The given data in the problem is;
P is the force = 660 N
d is the displacement = 15 mm
G is the constant= 77 GPa
τ is the shear stress= 80 MPa
From the torsional equation;
[tex]\frac{\tau}{R} =\frac{T}{j} \\\\ \frac{\pi}{32} \times d^4=\\\\ \tau =\frac{T \times R}{J} \\\\\ \tau =\frac{T \times (\frac{d}{2} )}{J} \\\\ 80= \frac{32 \times 190 \times \frac{d}{2} }{\pi} \\\\\\d=252.65 \times 10^{-3}[/tex]
Hence the required diameter of shaft BC will be 252.65 ×10⁻³.
To learn more about the diameter refer to the link;
https://brainly.com/question/5501950
Is this physically plausible?
Answer:
stop useing my awnsers just to deleate them
Explanation:
Why is the car industry a good example of energy efficiency and human technology over time?
Answer:
Fortunately, the potential for higher energy efficiency is great. ... For example, landlords of rental residential buildings are not motivated to pay for ... it over time, and the timeframes in which specific technologies can be expected to ... especially for small firms, and many industries prefer to expend their human and financial.
4 Energy Efficiency | America's Energy Future: Technology. this is a site
Explanation:
Answer:
the car industry is one of the most important industry in the world as it aid easy transportation of goods and man.
Explanation:
cars and other automobiles have aid easy movement of people and goods from one place to another as it is more efficient (does not waste time as compared to traditional means of transportation.)and reliable.
Determine the activity of the sample of cerium when the sample was 20 seconds old
Answer:
There are [tex]3.779\times 10^{23}[/tex] atoms when the sample of cerium is 20 seconds old.
Explanation:
The decay of isotopes is modelled after the following exponential expression:
[tex]N(t) = N_{o}\cdot e^{-\left(\frac{\ln 2}{t_{1/2}}\right)\cdot t }[/tex] (1)
Where:
[tex]N_{o}[/tex] - Initial number of atoms, dimensionless.
[tex]N(t)[/tex] - Current number of atoms, dimensionless.
[tex]t[/tex] - Time, measured in seconds.
[tex]t_{1/2}[/tex] - Half-time, measured in seconds.
Now we clear the half-time within (1):
[tex]\ln \frac{N(t)}{N_{o}} = -\frac{t\cdot \ln 2}{t_{1/2}}[/tex]
[tex]t_{1/2} = -\frac{t\cdot \ln 2}{\ln \frac{N(t)}{N_{o}} }[/tex]
If we know that [tex]N_{o} = 5\times 10^{23}[/tex], [tex]N(t) = 2\times 10^{23}[/tex] and [tex]t = 66\,s[/tex], then the half-life of the isotope is:
[tex]t_{1/2}=-\frac{(66\,s)\cdot \ln 2}{\ln \frac{2}{5} }[/tex]
[tex]t_{1/2}\approx 49.927\,s[/tex]
And the decay equation for the sample is described by:
[tex]N(t) = (5\times 10^{23})\cdot e^{-0.014\cdot t}[/tex]
Lastly, if we get that [tex]t = 20\,s[/tex], then the activity of the sample of cerium is:
[tex]N(20) = (5\times 10^{23})\cdot e^{(-0.014)\cdot (20)}[/tex]
[tex]N (20) \approx 3.779\times 10^{23}[/tex]
There are [tex]3.779\times 10^{23}[/tex] atoms when the sample of cerium is 20 seconds old.
Energy is
A) conserved
OB) created only
OC) destroyed only
OD) created or destroyed
Answer:
A
Explanation:
Conserving energy produces a higher quality of life. Reduced emissions result in cleaner air quality. In addition, it helps create a healthier planet, or at least helps sustain the resources we already have
car 1 is traveling south at 18 m/s and has a full load, giving it a total mass of 14,650 kg. Car 2 is traveling north at 11 m/s and has a mass of 3,825 kg. After the collision, car 1 has a final velocity of 6 m/s south. What is the velocity of car 2
Answer:
v_{4}= 80.92[m/s] (Heading south)
Explanation:
In order to calculate this problem, we must use the linear moment conservation principle, which tells us that the linear moment is conserved before and after the collision. In this way, we can propose an equation for the solution of the unknown.
ΣPbefore = ΣPafter
where:
P = linear momentum [kg*m/s]
Let's take the southward movement as negative and the northward movement as positive.
[tex]-(m_{1}*v_{1})+(m_{2}*v_{2})=-(m_{1}*v_{3})+(m_{2}*v_{4})[/tex]
where:
m₁ = mass of car 1 = 14650 [kg]
v₁ = velocity of car 1 = 18 [m/s]
m₂ = mass of car 2 = 3825 [kg]
v₂ = velocity of car 2 = 11 [m/s]
v₃ = velocity of car 1 after the collison = 6 [m/s]
v₄ = velocity of car 2 after the collision [m/s]
[tex]-(14650*18)+(3825*11)=(14650*6)-(3825*v_{4})\\v_{4}=80.92[m/s][/tex]
Answer the following questions
Answer:
9 - 10N to the left
10 - There is no change on the object
Explanation:
Can I have brainliest answer pls?
Martina travels from her house to her moms office building, From there she walks to school. After school, she walks to the library and then to a friends house before finally ending back at home. Fine Martina's totoal distance traveld
Answer:
it matters how far she traveled
Explanation:
Analyze the chemical reaction below
16 g CH4 + 64 g O2 → 44 g CO2 + 36g H2O
Explain the law of conservation of mass and describe how the equation represents the law of conservation of mass.
Answer:
Explanation:
The law of conservation of mass states that the mass of the elements at the beginning of the reaction(reactants) will equal the mass at the end of the reaction (product) .
In the chemical equation above,the total mass of the reactants is 80g(16+64) and the total mass of the products is also 80g(44+36).therefore the mass remained constant and that's how the equation represents the law of conservation of mass
Which phrase best describes Osorno?
shield volcano
active volcano
dormant volcano
explosive volcano
Answer:
dormant
Explanation:
Answer:
dormant
Explanation:
Hi i need help. thNKS
Answer:
8
Explanation:
Groups go down, periods go across :)
Suppose a cart of mass 0.5 kg is placed on the table and connected to a mass hanging mass over the edge. If the hanging mass is 0.2 kg, when what would be the acceleration of the cart?
Explanation:
0.10kg
0.5kg×0.2kg=
0.10
how does the index of refraction of an unknown substance compare to the index of refraction of a vacuum? explain how the speed and the refraction of light would behave in both?
Answer:
By measuring the speed of light in both in space and that unknown substance
Explanation:
Refractive Index (Index of Refraction) is a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density.
By measuring the speed of light in that medium and dividing it by speed of light 3*10^8 we can measure the refractive index of any medium
To determine a waves' frequency, you must know the (2 points)
Select one:
a. distance it travels
b. number of oscillations in a given period of time
c. distance between the crest and trough
d. height of the wave
Answer:
b
to determine the frequency you must know oscillations and the given time
During a thunderstorm a tornado lift a car to a height of 300 m above the ground increasing and strength the tornado flings the car horizontally with the speed of 80.0 m/s how long does the car take to reach the ground how far horizontally does the car travel before hitting the ground
Answer:
Explanation:
To calculate the time it took the car to hit the ground, we use the formula
speed = distance/time
80 m/s = 300 m/time
time = 300/80
time = 3.75 secs
It must have taken the car 3.75 seconds to hit the ground
To determine the horizontal distance of the car before hitting the ground, the same formula will also be used but with the time obtained above (since that was the time it took before hitting the ground)
speed = distance/time
80 = distance/3.75
distance = 3.75 x 80
distance = 300 meters
A student is helping his teacher move a 40.0 kg aquarium. What net sideways force must he exert on the aquarium to slide it across the floor so that it accelerates at 0.50 m/s2?
Answer:
20 N
Explanation:
From the question given above, the following data were obtained:
Mass (m) of aquarium = 40 kg
Acceleration (a) = 0.50 m/s²
Force (F) =?
Force is simply defined as the product of mass and acceleration. Mathematically, it is expressed as:
Force (F) = mass (m) × acceleration (a)
F = m × a
With the above, we can obtain the force needed to slide the aquarium as follow:
Mass (m) of aquarium = 40 kg
Acceleration (a) = 0.50 m/s²
Force (F) =?
F = m × a
F = 40 × 0.5
F = 20 N
Therefore, a force of 20 N is needed to slide the aquarium.
I can’t figure it out my question is:
--- are complex and may be change when new information is available or new technologies are developed.
My choices to choose from are:
Laws
Hypothesis
Theories
Procedures
A block slides down a 30.0 degree inclined plane at an acceleration of 2.0 m/s^2. What is the coefficient of friction between the block and the inclined plane? Use g=10.0 m/s^2
A) .20
B) .25
C) .30
D) .35
Answer:
D) .35
Explanation:
m = Mass of block
g = Acceleration due to gravity = [tex]10\ \text{m/s}^2[/tex]
[tex]\theta[/tex] = Angle of inclination = [tex]30^{\circ}[/tex]
a = Acceleration of block = [tex]2\ \text{m/s}^2[/tex]
[tex]\mu[/tex] = Coefficient of friction between the block and the inclined plane
f = Frictional force = [tex]\mu mg\cos\theta[/tex]
As the forces are conserved in the system we have
[tex]mg\sin\theta-f=ma\\\Rightarrow mg\sin\theta-\mu mg\cos\theta=ma\\\Rightarrow g(\sin\theta-\mu\cos\theta)=a\\\Rightarrow \sin30^{\circ}-\mu\cos30^{\circ}=\dfrac{2}{10}\\\Rightarrow \dfrac{1}{2}-\mu\dfrac{\sqrt{3}}{2}=0.2\\\Rightarrow \mu=\dfrac{\dfrac{1}{2}-0.2}{\dfrac{\sqrt{3}}{2}}\\\Rightarrow \mu=\dfrac{0.3\times 2}{\sqrt{3}}\\\Rightarrow \mu=0.3464\approx 0.35[/tex]
The coefficient of friction between the block and the inclined plane is 0.35
Calculate the kinetic energy of a 1 kg object moving at 4.5 ms. Round to the first decimal.
Answer:
91.21
Explanation:
Kinetic energy =1/2 mv2 substitute the values I. E 1/2 *1 *4.5^2= 91.21
Use the computational model of a cannon and cannonball shown to answer the question below.
If the mass of the cannonball increases, and all other initial conditions stay the same, what would happen to the velocity and kinetic energy of the cannonball?
A. The velocity decreases, and the kinetic energy decreases.
B. The velocity decreases, and the kinetic energy increases.
C. The velocity increases, and the kinetic energy decreases.
D. The velocity increases, and the kinetic energy increases.
Answer:
It would be option B.
Explanation:
Option B. is the right answer because as the mass of the canon increases the kinetic energy will increase as well, but the will decrease due to its greater mass.
If the mass of the cannonball increases, and all other initial conditions stay the same, the velocity decreases, and the kinetic energy increases.
The kinetic energy of an object is the energy possessed by the object due to its motion.
[tex]K.E = \frac{1}{2} mv^2[/tex]
where;
m is the mass of the objectv is the velocity of the objectK.E is the kinetic energy of the objectWhen the mass increases, the kinetic energy will increase.
[tex]v^2 = \frac{2K.E }{m}\\\\v=\sqrt{\frac{2K.E }{m}}[/tex]
when the mass increases, the velocity of the cannonball will decrease.
Thus, we can conclude that if the mass of the cannonball increases, and all other initial conditions stay the same, the velocity decreases, and the kinetic energy increases.
Learn more here:https://brainly.com/question/6498875
A 0.050 kg toy truck moving right at 0.20 m/s collided with a toy car weighing 0.015 kg initially at rest, on a frictionless track. The truck keeps moving right at 0.15 m/s after the collision,
what is the final speed of the race car?
Answer:
0.1667 m/s
Explanation:
m1V1 + m2V2 = m1V3 + m2V4
0.01 = ( 0.0075) + (0.015 * V4)
V4 = (0.01 - 0.0075) / (0.015)
V4= 0.1667
Answer:
0.167 m/s
Explanation:
A 1000-kg car is travelling at 30 m/s (about 67 mph, for context). What is the car's momentum? If the driver then slams on the brakes, applying a force of 7,500 N, how long will it take the car to stop?
it will take the car 5 seconds to stop
A cartoon shows two friends watching an unoccupied car in free fall after it has rolled off a diff. One friend says to the other, "It goes from zero to sixty mphin about three seconds." Is this statement correct? (Note that 60 mph converts to 26.8 m/s.)
Answer:
The statement is not correct.
Explanation:
To know if the statement is correct, we shall determine the velocity of the car after 3 s. This is illustrated below.
Data obtained from the question include:
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 3 s
Final velocity (v) =?
v = u + gt
v = 0 + (9.8 × 3)
v = 0 + 29.4
v = 29.4 m/s
Thus, the velocity of the car after 3 s is 29.4 m/s.
Hence, the statement made by the friend is not correct as the car has a falling velocity of 29.4 m/s after 3 s.
help me please I can't get the final step
Answer:
[tex]\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}[/tex]
Explanation:
Dimensional Analysis
It's given the relation between quantities A, B, and C as follows:
[tex]\displaystyle A=\frac{3}{2}B^mC^n[/tex]
and the dimensions of each variable is:
[tex]A=L^2T^2[/tex]
[tex]B=LT^{-1}[/tex]
[tex]C=LT^2[/tex]
Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):
[tex]\displaystyle L^2T^2=\left(LT^{-1}\right)^m\left(LT^2\right)^n[/tex]
Operating:
[tex]L^2T^2=\left(L^mT^{-m}\right)\left(L^nT^{2n}\right)[/tex]
[tex]L^2T^2=L^{m+m}T^{-m+2n}[/tex]
Equating the exponents:
[tex]m+n=2[/tex]
[tex]-m+2n=2[/tex]
Adding both equations:
[tex]3n=4[/tex]
Solving:
[tex]n=4/3[/tex]
[tex]m=2-4/3=2/3[/tex]
Answer:
[tex]\mathbf{\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}}[/tex]