John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

a 30 m/s
b 0 m/s
c 25.9 m/s
d 15 m/s

Answers

Answer 1

The horizontal component of the velocity is equal to: D. 15 m/s.

Given the following data:

Velocity = 30 m/sAngle = 60°

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity  in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

[tex]V_x = Vcos(\theta)[/tex]

Substituting the given parameters into the formula, we have;

[tex]\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5[/tex]

Horizontal component, Vx = 15 m/s

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Related Questions

the purpose of many scientific investigations is to test a {n}

Answers

Hypothesis , I believe the answer is hypothesis

Answer:

Scientific investigation is a quest to find the answer to a question using the scientific method.

Explanation:

the scientific method is a systematic process that involves using measurable observations to formulate, test or modify a hypothesis.

what is the velocity of a 50 kg dog with 3000 j of kinetic energy

Answers

Answer:

KE = 225000000 J

Explanation:

Answer:

10.954. from equation. KE=1/2m(v^2)

2KE=m(v^2) 6000=50(v^2) (v^2)=6000/50

(v^2)=120. square root for all v=10.954 m/s

Connor rode an inner tube down a river. For 4.6 minutes, he moved downriver at 15 meters per minute. During this time, how far did he move?
answers:
3.26 meters

3.26 minutes

69 meters

69 minutes

Answers

Answer:

69 meters

Explanation:

stella is driving down a steep hill. she should keep her car __________ to help _________.

Answers

Answer:

Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.

Explanation:

Block A has a mass of 2kg and a speed of 50 m/s along the positive x axis.

Block B has a mass of 4 kg and a speed of 25 m/s along the negative x axis.



The two blocks collide head-on in a perfectly elastic collision.

Determine the velocity of each mass after the collision.

Answers

Momentum is conserved, so

(2 kg) (50 m/s) + (4 kg) (-25 m/s) = (2 kg) v₁' + (4 kg) v₂'

where v₁' and v₂' are the velocities of the two blocks after the collision. Simplifying this gives

100 kg•m/s - 100 kg•m/s = (2 kg) v₁' + (4 kg) v₂'

0 = (2 kg) v₁' + (4 kg) v₂'

v₁' = -2v₂'

Energy is also conserved, so

1/2 (2 kg) (50 m/s)² + 1/2 (4 kg) (-25 m/s)² = 1/2 (2 kg) (v₁')² + 1/2 (4 kg) (v₂')²

Simplifying yields

2500 J + 1250 J = (1 kg) (v₁')² + (2 kg) (v₂')²

3750 J = (1 kg) (v₁')² + (2 kg) (v₂')²

Substitute v₁' = -2v₂' and solve for v₂' :

3750 J = (1 kg) (-2v₂')² + (2 kg) (v₂')²

3750 J = (6 kg) (v₂')²

(v₂')² = 625 J/kg = 625 m²/s²

v₂' = 25 m/s

Then the first block has final velocity

v₁' = -2 (25 m/s)

v₁' = -50 m/s

Draw a nitrogen cycle and explain in short.
please help me ​

Answers

Answer:   biogeochemical process

Explanation:

hi my name is coolboy123hillok

Answers

Answer:

you should change that name

please change your name

according to newton's third law, of a sledgehammer hits a wall with a force of 1000 n, how much force does the wall hit the sledgehammer? a - 1000 n b 1000 n c 0 n d 500 n

Answers

The correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

Newton's third law

Newton's third law of motion states that for every action or force, there is an equal but oppositely directed force.

Application of the newton's third law

Force with which the sledgehammer hits the wall = 1000 N

From the Newton's third law, an equal but oppositely directed force is exerted on the sledgehammer by the wall.

Thus, the force exerted by the sledgehammer on the wall = -1000 N

The negative sign indicates that the force acts in a direction opposite to that of the sledgehammer.

Thus, the correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

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An object with a mass of 13.2 kg is accelerating at 9.4 m/s? What force is being applied on the object?
Round your answer to the appropriate number of significant figures and use the following formula:
force = mass x acceleration

Answers

Force = mass x acceleration:

Force = 13.2 kg x 9.4 m/s

Force = 124.08

Force = 124 Newtons

The force will be  = 124 N              

What is newton's second law of motion?

Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

according to newton's second law of motion

Force = mass * acceleration

given

mass = 13.2 kg

acceleration = 9.4 m/s

force = 13.2 * 9.4

        = 124.08 N

Rounding off answer to  the appropriate number of significant figures

force = 124 N

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can someone explain why is the answer 3.1?​

Answers

i dont know  Im sorry but why Im messaging is because when more people respond it usually is the first to pop up so someone else will see this and be able to help you            Explanation:

29) A cheetah can accelerate from rest to 25
m/s in 6 s. Assuming that the cheetah moves
with constant acceleration, what distance does
it cover in the first 3 s

Answers

Answer:

[tex]\huge\boxed{\sf S = 18.75 \ meters}[/tex]

Explanation:

Given Data:

Initial Velocity = Vi = 0 m/s (rest)

Final Velocity for 6 seconds = Vf = 25 m/s

Time (1) = T1 = 6 seconds

Time (2) = T2 = 3 seconds

Required:

Distance for 3 seconds = S = ?

Solution:

For 6 seconds, the acceleration will be:

[tex]\displaystyle a = \frac{Vf-Vi}{t} \\\\a = \frac{25 - 0}{6} \\\\a = 25 / 6\\\\\boxed{a = 4.167 \ m/s^2}[/tex]

Since, acceleration is constant, it will be the same at 3 seconds as well.

Using second equation of motion to find Distance (S) with time being 3 seconds:

[tex]\displaystyle S= Vit+\frac{1}{2} at^2\\\\S = (0)(3)+ \frac{1}{2} (4.167)(3)^2\\\\S = \frac{1}{2} (4.167)(9)\\\\S = \frac{37.5}{2} \\\\\boxed{S = 18.75 \ meters}\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

Which image shows an example of the electromagnetic force in action?

Answers

Answer:

Where are the images?

Explanation:

I can't help if there is no image(s) to this question.

A book with a. mass of 1 kg is sliding on a table. If the frictional force on the book is 5 N, calculate the book’s acceleration. Is it speeding up or slowing down?

Answers

Force = mass x acceleration:

5N = 1kg x acceleration

Acceleration = 5N / 1 kg

Acceleration  = 5 m/s^2

Acceleration is a positive value so it is speeding up

If the density of gold is 19.3 g/mL, what is the mass of 5mL of gold?​

Answers

Answer:

96.5 mL

Explanation:

A single covalent bond is stronger than a single hydrogen bond so why does a group of polar molecules tend to have a higher boiling point than a group of non polar molecules

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this question makes no sense

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like how do you get this question

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Explanation:

you serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has how much energy

Answers

Answer:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

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