The position of John at time of 4.35 s is -1.13 m
we know that,
at time, t = 0, the initial velocity, u = - 2 m/s
at time, t = 5 s, the final velocity, v = 2 m/s
The average acceleration can be calculated as follows;Acceleration = Δ velocity/ Δ time
Acceleration = v₂-v₁/ t₂-t₁
Acceleration = 2- (-2)/ 5-0 = 4/5= 0.8 m/s²
The position of John at time, t = 4.35 s can be calculated as followsx(t) = ut +1/2 at²
u is velocity
t is time
a is acceleration
x(t) = ut +1/2 at²
x(4.35) = (-2 x 4.35) +0.5 x0.8x(4.35)²
x(4.35) = -8.7 +7.569
x(4.35) = - 1.13 m
Thus, the position of John at time of 4.35 s is -1.13 m
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gravity on the surface of the Moon is only 1/6 as strong as gravity on Earth.
Answer:
True,
Explanation:
Over the entire surface, the variation in gravitational acceleration is about 0.0253 m/s2 (1.6% of the acceleration due to gravity). Because weight is directly dependent upon gravitational acceleration, things on the Moon will weigh only 16.6% (= 1/6) of what they weigh on the Earth.
A meteoroid (small piece of rock) is initially at rest in deep space far from our Sun.
When the meteoroid just comes into contact with the Sun's gravitational field it begins to fall
toward the Sun along a radial straight line. With what speed does it strike the Sun? The Sun has
a mass of 2 x 1030 kg and a radius of 6.96 x 10° m.
The speed of the meteoroid when it strikes the Sun can be calculated using the formula for the escape velocity, which is the minimum speed an object must have in order to escape from the gravitational pull of a planet or star.
The formula for escape velocity is:
v_escape = (2GM/R)^(1/2)
where G is the gravitational constant (6.67 x 10^-11 N m^2/kg^2), M is the mass of the Sun, and R is its radius.
Plugging in the values, we get:
v_escape = (2 * 6.67 x 10^-11 * 2 x 10^30 / 6.96 x 10^8)^(1/2)
v_escape = 617.7 km/s
So the meteoroid strikes the Sun with a speed of approximately 617.7 km/s.
of a big spherical cushion, stuffed with furniture padding. The egg has a mass of 85-g. If the egg greater than 28 N, it breaks f the cushion hits the ground at 12 m/s ,what is the minimum distance that it must compress on impact to ensure that the egg is unscathed? Note The acceleration associated with stopping the egg is so great that you can neglect gravity while the cushion is slowing due to contact with the ground dValue Units
The minimum distance that the cushion must compress on impact to ensure that the egg is unscathed is 0.2184m or about 22 cm.
To find the minimum distance that the cushion must compress on impact to ensure that the egg is unscathed, we can use the impulse-momentum theorem. The impulse-momentum theorem states that the change in momentum of an object is equal to the impulse applied to it. In this case, the change in momentum of the egg is equal to the impulse applied by the cushion.
The change in momentum of the egg is given by:
Δp = mvf - mvi
where m is the mass of the egg, vf is the final velocity of the egg, and vi is the initial velocity of the egg.
The impulse applied by the cushion is given by:
I = FΔt
where F is the average force applied by the cushion and Δt is the time over which the force is applied.
Since the egg comes to a stop after hitting the cushion, vf = 0. Therefore, the change in momentum of the egg is:
Δp = -mvi
Setting the change in momentum is equal to the impulse applied by the cushion and rearranging gives:
FΔt = mvi
F = mvi/Δt
We are given that the initial velocity of the cushion is 12 m/s and the mass of the egg is 85-g or 0.085-kg. We are also given that the force applied by the cushion must be less than 28 N to prevent the egg from breaking. Substituting these values into the equation for F gives:
28 N = (0.085-kg)(12 m/s)/Δt
Solving for Δt gives:
Δt = (0.085-kg)(12 m/s)/(28 N) = 0.0364 s
Now, we can use the equation d = vavgΔt to find the minimum distance that the cushion must compress. The average velocity of the cushion during the compression is given by:
vavg = (vi + vf)/2 = (12 m/s + 0 m/s)/2 = 6 m/s
Substituting the values for vavg and Δt into the equation for d gives:
d = (6 m/s)(0.0364 s) = 0.2184 m
Therefore, the minimum distance that the cushion must compress on impact to ensure that the egg is unscathed is 0.2184m or about 22 cm.
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1. for both r = 10 cm, and r = 1.4 cm calculate the value for the electrostatic force. show work. (10 points)
For r = 10 cm, electrostatic force is -[tex]5.4 * 10^-5 N[/tex] and for r - 1.4 cm, it is [tex]-3.9 * 10^-3[/tex] N. We use Coulomb's law. Work is shown.
To calculate the electrostatic force between two point charges, we use Coulomb's law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, this can be expressed as:
F =[tex]k * q1 * q2 / r^2[/tex]
where F: force, q1 and q2: charges, r : charges distance, and k: Coulomb constant.
Let's assume we have two point charges, q1 and q2, and we want to calculate the electrostatic force between them for two different distances, r = 10 cm and r = 1.4 cm.
For the distance r = 10 cm, assuming the charges are q1 = +2 C and q2 = -3 C, the force can be calculated as follows:
F =[tex]k * q1 * q2 / r^2[/tex]
F = [tex](9 * 10^9 N*m^2/C^2) * (2 C) * (-3 C) / (0.1 m)^2[/tex]
F =[tex]-5.4 * 10^(-5) N[/tex]
For the distance r = 1.4 cm, assuming the same charges, the force can be calculated as follows:
F =[tex]k * q1 * q2 / r^2[/tex]
F = [tex](9 x 10^9 N*m^2/C^2) * (2 C) * (-3 C) / (0.014 m)^2[/tex]
F =[tex]-3.9 * 10^-3 N[/tex]
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Pulleys A and B are mounted on bracket CDEF. The tension on each side of the two belts is given as TA1 = 120 lb, TA2 = 160 lb, T81 = 210 lb, and TB2 = 150 lb. Replace the four forces with a single equivalent force, and determine where its line of action intersects the bottom edge of the bracket. T81 lb 2 in. r=2 in. r= lin. 125° T82 lb С D 25° TA A B F E 1 in. 6 in- - 6 in. 4 in. TA1 lb TA2 lb The resultant force R is Тb 8 The point d where the resultant force intersects the line EF is in.
The line of action of the comparable force, which is exerting pressure on the bracket, intersects its bottom edge 4.19 inches from point C.
We may apply the concept of vector addition to transform the four forces into a single equivalent force. We begin by creating a schematic and assigning names to the forces:
T81 lb T82 lb
| |
| |
| |
---C-------------D--
TA1 lb | TA2 lb
| |
| |
| |
F E
We can represent each force as a vector, with its magnitude and direction. To simplify the diagram, we can choose a convenient scale for the vectors, such as 1 inch = 10 lb. Then, the vectors can be drawn with lengths proportional to their magnitudes.
Next, we draw the vector sum by placing the tail of each vector at the head of the previous one. The resulting vector represents the equivalent force:
T81 lb T82 lb
| |
| |
| |
---C-------------D--
TA1 lb | TA2 lb
| |
| |
| |
F E
\ /
\ /
\ /
\ /
\ /
\ /
\ /
X
You can calculate the intersection of the bottom edge of the bracket and the line of the comparable force by taking moments around any point on the edge. Since point C is on the force's path, we can pick it as a convenient choice. The moment formula is:
TA1(4) + T81(2) - TB2(dC) - TA2(10) - T82(dD) = 0
where dC and dD are the distances from points C and D to the line of action of the force, respectively. Solving for dC, we get:
dC = (TA1(4) + T81(2) - TA2(10) - T82(dD)) / TB2
We can substitute the given values and solve for dD:
dD = (TA1(4) + T81(2) - TA2(10) - T82(125°)) / TB2
= (-480) / 150
= -3.2 inches
The negative sign indicates that the point of intersection is to the left of point D. To find the distance from point C, we can use the moment equation again:
TA1(4) + T81(2) - TB2(dC) - TA2(10) - T82(dD) = 0
solving for dC, we get:
dC = (TA1(4) + T81(2) - TA2(10) - T82(dD)) / TB2
= (480 + 210 + 160 - 150(3.2)) / 150
= 4.19 inches
Therefore, the point of intersection is 4.19 inches from point C.
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(Note that the strain in this case is uniform.) Also calculate change in distance using geometrically non-linear strain, and compare. [For those with the 1st edition of the text, the last sentence of Prob. 2.3 should be replaced by the following; " Calculate the strain components corresponding to the given displacement field. Use the definition of εxx to estimate the change of distance between the two points. Compare the two results.]
We can estimate the change in distance between the two points: ΔL = εxxL0 = 0.002500mm = 1mm for given displacement field.
In a geometrically linear analysis, the strain is assumed to be proportional to the displacement, which means that the strain is uniform throughout the material. However, in reality, the strain is not always linearly related to the displacement, and a more accurate analysis would take into account the non-linear strain behavior.
To calculate the change in distance using geometrically linear strain, we can use the definition of strain: ε = ΔL/L0, where ΔL is the change in length and L0 is the original length. In this case, we are given that εxx = 0.002, which means that the strain in the x-direction is 0.2%. Using this equation, we can estimate the change in distance between the two points: ΔL = εxxL0 = 0.002500mm = 1mm.
To calculate the change in distance using geometrically non-linear strain, we would need to use a more complex strain-displacement relationship. However, we can expect that the non-linear strain analysis would predict a slightly different change in distance compared to the linear analysis, since the strain would not be assumed to be uniform throughout the material.
Comparing the results from the two analyses, we see that the change in distance predicted by the geometrically linear strain analysis is 1mm. While we cannot accurately predict the change in distance using the non-linear strain analysis without further information, we can expect the difference between the two results to be small. Nonetheless, in situations where more accurate predictions are necessary, a geometrically non-linear analysis may be required.
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At the instant shown in Figure, car A has a speed of 15 km/h, which is being increased at the rate of 300 km/h 2 as the car enters the expressway. At the same instant, car B is decelerating at 250 km/h 2 while traveling forward at 100 km/h.
(a) Determine the magnitude of the velocity of A with respect to B.
(b) Determine the direction angle of the velocity of A with respect to B, measured counterclockwise from the positive x-axis
(a) The magnitude of the velocity of A with respect to B is √(23.61 - 13.89t)².
(b) The direction angle of the velocity of A with respect to B is 0° counterclockwise from the positive x-axis.
What is the velocity of A with respect to B?We can use relative velocity formula to find the velocity of A with respect to B.
VrA = Vr + Ar(t)
where;
Vr is the relative speedAr is the relative accelerationt is the timeRelative speed = speed of A - speed of B
= 4.17 m/s - 27.78 m/s
= -23.61 m/s
Relative acceleration = acceleration of A - deceleration of B
= 83.33 m/s² - 69.44 m/s²
= 13.89 m/s²
Relative velocity = -23.61 m/s + 13.89 m/s² (t)
The magnitude of the velocity of A with respect to B is calculated as follows;
|Vrel| = √(-23.61 + 13.89t)² + 0^2
= √(23.61 - 13.89t)²
The direction angle of the velocity of A with respect to B can be found using the arctangent function.
θ = arctan(0 / (23.61 - 13.89t))
= arctan(0) = 0°
The magnitude of velocity of A with respect to B is calculated as;
|Vrel| = √(23.61 - 13.89t)²
Direction angle of velocity of A with respect to B = θ = 0° counterclockwise from the positive x-axis.
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A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 Times 10^-19 C, mproton = 1.67 Times 10^-27 kg)
The acceleration of the proton is 7.6×10¹⁰ m/s² in the direction of the electric field.
Electrostatic forces are both attractive and repulsive forces caused by charged particles. Also known as Columbus Power. The Colombes attraction is named after French scientist Charles Augustin de Coulomb. However, his one of his four fundamental forces of nature is the electrostatic force.
- The force on a charged particle due to an electric field is given by: F = qE
where q is the charge = 1.6×10⁻¹⁹C
and E is the electric field = 800N/C
Also, from Newton's laws of motion;
F = ma
where m is mass = 1.67×10⁻²⁷kg and a is acceleration
ma = qE
a = qE/m
a = (1.60 x10^-19x800)/(1.67 x 10^-27 )
a = 7.6x10^10
towards the direction of the electric field.
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the motion of the molecules reflect the kinetic enregy of molecules or is ordered and predictable reflects the potential energy of moecules and is random and erratic
The motion of molecules is best described as being random and erratic. Option d is correct answer.
The movement of molecules is a reflection of the kinetic energy they possess. The molecules in a substance are always moving, even in solid objects, but the motion is typically less than in liquids or gases. The kinetic energy of a molecule is related to its speed and mass. The faster and heavier the molecule, the more kinetic energy it has.
The motion of molecules is not ordered or predictable, meaning that they do not follow a specific path or pattern. Instead, the molecules move randomly, colliding with one another and bouncing off surfaces. This random motion is due to the thermal energy that is present in all objects. Thermal energy is the energy that causes objects to become hotter, and it is related to the potential energy of molecules.
--The given question is incomplete, the complete question is
"The motion of the molecules reflect
a. the kinetic energy of molecules
b. is ordered and predictable
c. reflects the potential energy of molecules
d. is random and erratic" --
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The block then moves up a hill that is not frictionless. Determine what height the block reaches if 430 J of thermal energy is produced. On a frictionless horizontal surface, a 9.61 kg block is pushed up against a 34,596 N/m spring and compresses it 0.23 m. The block is then released. A.) Determine the block's speed after it leaves the spring. V = 13.8 m/s B.) The block then moves up a hill that is not frictionless. Determine what height the block reaches if 430 J of thermal energy is produced. h =
Answer:
51
Explanation:
you will settle down and calculate it well
An electron is placed at point A in a uniform electric field of magnitude Edirected to the right, as shown above. A short time later, the electron is at point B. Which of the following statements describes the relationship between the electric field and the motion of the electron? The electron experiences a force of magnitude F =qE at point A, which accelerates the electron in the direction of the electric field The electric potential energy of the electron-field system at point A is converted into kinetic energy, causing the electron to move along the field lines. The electron moves through the electric field from a higher electric potential at point A to a lower electric potential at point B D) The electron is accelerated by the electric field in a direction perpendicular to the field lines, causing it to move from point A to point B (E) A force not associated with the electric field moves the electron from point A to point B. The electric field does negative work on the electron in the process.
The correct statement describing the relationship between the electric field and the motion of the electron is (A) - The electron experiences a force of magnitude F=qE at point A, which accelerates the electron in the direction of the electric field.
As the electron is placed in a uniform electric field of magnitude E directed to the right, it experiences a force of magnitude F=qE in the same direction. This force accelerates the electron in the direction of the electric field.
Hence, the electron moves from point A to point B due to the force exerted on it by the electric field. Therefore, option (A) is the correct statement that describes the relationship between the electric field and the motion of the electron.
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true/false. parallel bands of magnetized rock that show alternating polarities stripe the floor of the atlantic ocean; the pattern is symmetrical and parallel with the spreading center.
The Doppler shift of a star is most easily detected in A. its absorption lines B. its continuous spectrum C. its sound waves D. its size
The Doppler shift of a star is most easily detected in B. its continuous spectrum.
The relationship between the Doppler effectThe Doppler effect occurs whenever there is a proximity or separation between a source of mechanical or electromagnetic waves and an observer. In the approximation case, the observed frequency is greater than the frequency emitted by the source. In case of displacement, the observed frequency is lower than the frequency emitted by the source.
How important is the Doppler effect for astronomyThe Doppler effect is used to measure the speed of objects by means of waves emitted by radio frequency or laser based devices, such as radar. In Astronomy, this phenomenon is used to measure the relative speed of stars and other celestial bodies with respect to planet Earth.
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The arc length formula says the length s of arc subtended by angle Θ in a circle of radius r is given by the equation s = rΘ. What are the dimensions of (a) s, (b) r, and (c) Θ?
The formula s = r, where is expressed in radians, gives the length s of arc that is captured on a circle with radius r by such an angle of measure radians.
What is the arc's length that subtends?The arc length for an angle of 360 degrees subtended at the center is just the circle's circumference, which is equal to 2r, where r is the radius of the circle. The arc length momentum for an aspect of will be 360 2 r = 180 r.
What is the angle's measurement?A radian is the unit of measurement for an angle that, when represented by a right triangle, subtends the arc whose length is equal to the circle's radius. One radian is the length of the angle, or m. (Hence the naming.)
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choose the best description of kinetic energy. a. the energy an object has due to its motion b. the energy an object has due to its position c. heat that is lost or gained in a reaction d. energy that spontaneously becomes more ordered
The best description of kinetic energy is a. the energy an object has due to its motion.
What is kinetic motion based energy?Kinetic motion based energy is a type of energy that has objects in movement, conversely to the potential energy that is contained by objects at rest, which are the two main sources of energy in the universe and may be used to explain all other types of sources.
Therefore, with this data, we can see that kinetic motion based energy is a type of energy in movement that can be used when performing work.
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(e) suppose that sam reads about f' in this study and draws the following conclusion: if sam increases his average calorie intake from 2700 to 2720 calories per day, then his weight will increase by approximately 0.2 pounds. fill in the blanks below so that the equation supports his conclusion.
The equation supports his conclusion is about calories
[tex](2720 calories - 2700 calories) * f'[/tex][tex]=0.2[/tex]
Calories are a unit of measurement used to measure the energy value of food. The average person needs to consume a certain number of calories each day in order to maintain their body weight. Eating too many calories can lead to weight gain, while eating too few can lead to weight loss.The ratio of calories ingested to calories burnt via exercise must be maintained in order to maintain a healthy weight.
Assuming Sam's current daily calorie intake is 2700 calories, the equation that supports his conclusion is:
Weight (in pounds) = [tex](2720 calories - 2700 calories) * f'[/tex]
Weight (in pounds) = [tex]0.2 * f'[/tex]
Weight (in pounds) = [tex]0.2[/tex]
Therefore,The equation supports his conclusion is
[tex](2720 calories - 2700 calories) * f'[/tex][tex]=0.2[/tex]
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complete question:(e) suppose that sam reads about f' in this study and draws the following conclusion: if sam increases his average calorie intake from 2700 to 2720 calories per day, then his weight will increase by approximately 0.2 pounds. fill in the blanks below so that the equation supports his conclusion.
f' ( )=( )
Consider the LTI (linear time invariant) dis- crete time systems with the following impulse re- sponses, h[n]. For each system, determine whether or not the system is causal or noncausal and whether or not the system is FIR (finite impulse response) or IIR (infinite impulse response). Give a brief justification. A. h[n] = (0.8j)n-2 u[n+2]
B. h[n] = (0.8j)n-2 u[n-2]
C. h[n] = (0.8j)n-2 (u[n+1] – u[n-5])
D. h[n] = (0.8j)n u[n-3] – (0.8j)n u[n-10]
E. h[n] = (0.8j)n u[n] – (0.8j)n-10 u[n-10]
The response of a FIR filter is based on a mathematical formula that derives the output signal from the input samples acquired both in the present and in the past.
What is the finite impulse response?A. The causal and FIR system given by h[n] = (0.8j)n-2 u[n+2] exists. Since the impulse reaction solely depends on the input's current and future values, it is causal.
B. The h[n] = (0.8j)n-2 u[n-2] system is noncausal and FIR. Because the impulse reaction is dependent on the input's future values, it is not causal.
C. The causal and FIR nature of the system described by h[n] = (0.8j)n-2 (u[n+1] – u[n-5]). Since the impulse reaction solely depends on the input's current and future values, it is causal. The impulse response h[n] is zero for n 0 and for n 0, which is another reason why it is FIR.
D. The causal and IIR nature of the system depicted by h[n] = (0.8j)n u[n-3] – (0.8j)n u[n-10] is established. The impulse response is causal since it only depends on the input's recent and previous values, and it is IIR because the impulse response, h[n], is non-zero for all n.
D. The causal and IIR nature of the system described by h[n] = (0.8j)n u[n] – (0.8j)n-10 u[n-10] is shown. The impulse response is causal since it only depends on the input's recent and previous values, and it is IIR because the impulse response, h[n], is non-zero for all n.
Therefore, They are easy to design, having a linear phase response, and good precision and control over the output signal.
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a physics student skiis down a slope with a constant acceleration of 2.0 m/s^2 for 15 seconds What’s the final speed of the physics student
The final speed of the student will be 30 m/s.
What is Speed?speed is described as. the pace at which an object's location changes in any direction. Speed is defined as the distance traveled divided by the travel time. Speed is a scalar quantity because it just has a direction and no magnitude.
Given, a physics student skis down a slope with a constant acceleration of 2.0 m/s² for 15 seconds.
So,
a = 2 m/s²
t = 15 Second
u(initial velocity) = 0
Thus, from the equations of motion
v = u + at
v = 0 + 15 *2
v = 30 m/s
Therefore, the final speed of the student will be 30 m/s.
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The troubleshooting of a parallel circuit that contains three dimly lit bulbs is being discussed. A voltmeter that is placed across each of the bulbs indicates 7 2 volts.
Technician A says that the power supply that is common to all three bulbs may be faulty.
Technician B says that the ground terminal that is common to all three bulbs may have excessive resistance.
Who is correct?
A. A only
B. B only
C. Both A and B
D. Neither A nor B
The correct answer is C. Both A and B are correct, as the dimly lit bulbs could be due to either a faulty power supply or excessive resistance in the ground terminal.
Both technician A and technician B are correct when a voltmeter is placed across each of the bulbs indicates 7 2 volts during the troubleshooting of a parallel circuit that contains three dimly lit bulbs. Technician A says that the power supply that is common to all three bulbs may be faulty. Technician B says that the ground terminal that is common to all three bulbs may have excessive resistance.
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which of the following statements is correct about the magnitude of the static friction force between an object and a surface?
None of the above statements are correct related to statement about the magnitude of the static friction between an object and surface.
What is meant by static friction?Static friction is a force that opposes the motion of an object that is at rest and in contact with a surface. When an object is placed on a surface, the surface exerts a force on the object in the direction perpendicular to the surface, which is known as the normal force. If a force is applied to the object in a direction parallel to the surface, but the object does not move, the surface exerts an equal and opposite force, known as the static friction force, to prevent the object from sliding.
The magnitude of the static friction force depends on the coefficient of static friction between the two surfaces in contact and the normal force pressing the object and surface together. The coefficient of static friction is a property of the two surfaces and is a measure of the force required to start sliding the object along the surface. If the force applied to the object in a parallel direction is less than the maximum force of static friction, the object will remain at rest. Once the applied force exceeds the maximum force of static friction, the object will start to move, and kinetic friction will take over to oppose the motion.
The magnitude of the static friction force between an object and a surface does not depend on the mass of the object, the shape of the object, or what the object is made of.This means that the force required to start an object moving does not depend on the object's mass, shape, or material. The only things that matter are the coefficient of static friction and the normal force.
It depends on the coefficient of static friction between the object and the surface.The coefficient of static friction is a value that depends on the two surfaces in contact. It represents the force required to start an object moving relative to the surface. The higher the coefficient of static friction, the more force is required to start the object moving.
The normal force is the force that the surface exerts on the object perpendicular to the surface.When an object is resting on a surface, the surface exerts a force on the object perpendicular to the surface. This is called the normal force. The magnitude of the normal force is equal to the weight of the object, which is the force with which the object is pulled downwards by gravity.
If the force applied to the object in a parallel direction is less than the maximum force of static friction, the object will remain at rest.If the force applied to the object is less than the maximum force of static friction, the object will not move. The force of static friction is proportional to the normal force, so the maximum force of static friction is equal to the coefficient of static friction times the normal force.
Once the applied force exceeds the maximum force of static friction, the object will start to move, and kinetic friction will take over to oppose the motion.Once the applied force exceeds the maximum force of static friction, the object will start to move. At this point, the force of static friction is no longer applicable, and kinetic friction takes over. Kinetic friction is the force that opposes the motion of the object and is generally less than the force of static friction.
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Which of the following statements is correct about the magnitude of the static friction force between an object and a surface?
Static friction depends on the mass of the object. Static friction depends on the shape of the object. Static friction depends on what the object is made of but not what the surface is made of. None of the above is correct.which of newton's laws does not apply when considering fictitious forces in a non-inertial reference frame?
Newton's First Law, also known as the Law of Inertia, does not apply when considering fictitious forces in a non-inertial reference frame.
In a non-inertial reference frame, the observer is accelerating, which means that they are subject to non-zero net forces. To explain the motion of objects within this frame of reference, we need to introduce fictitious forces that appear to act on the objects. These fictitious forces are not actual physical forces but are instead apparent forces that arise due to the acceleration of the observer.
Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. However, in a non-inertial reference frame, objects appear to experience fictitious forces that cause them to deviate from this straight-line motion. Therefore, Newton's First Law does not apply in such frames of reference.
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a small sphere carrying 6.5 nc n c of charge is placed 100 mm m m from a small sphere carrying 2.5 nc n c of charge. assume the spheres are tiny relative to the 100-mm m m separation distance. part a at what position from the particle with 6.5 nc n c of charge on the line joining the spheres is the electric field magnitude zero? express your answer with the appropriate units.
At a distance of approximately 0.068 m from the positive charge along the line connecting the two charges, the electric field caused by the positive charge is zero.
What exactly is a "electric field"?Each point in space has an electric field associated with it when there is charge present in any form. The strength and direction of the electric field are expressed by the value of E, also referred to as the electric field strength, electric field intensity, or simply the electric field.
The Coulomb's law determines the electric field caused by a point charge Q at a distance r:
E = kQ/r²
where k is the Coulomb constant, k = 9 × 10⁹ N·m²/C².
Let the distance between the two charges be d = 100 mm = 0.1 m.
kQ1/x² = kQ2/(d-x)²
where x is the distance from the positive charge to the point where the electric field is zero, Q1 = 6.5 nC, and Q2 = -2.5 nC.
Solving for x, we get:
x = d Q1 / (Q1 - Q2)(1/2)
Substituting the given values, we get:
x = 0.1 m × 6.5 nC / (6.5 nC + 2.5 nC)(1/2)
x ≈ 0.068 m
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The potential difference between the ends of a 2-meter stick that is parallel to a uniform electric field is 550 V. The magnitude of the electric field is______V/m.
The magnitude of the electric field is 275 V/m.
The potential difference between the ends of a 2-meter stick that is parallel to a uniform electric field is 550 V. To find the magnitude of the electric field, we can use the formula:
Electric field = Potential difference / Distance
In this case, the potential difference is 550 V and the distance is 2 meters. Plugging these values into the formula, we get:
Electric field = 550 V / 2 m
Electric field = 275 V/m
Therefore, the magnitude of the electric field is 275 V/m.
In conclusion, the potential difference between the ends of a 2-meter stick that is parallel to a uniform electric field is 550 V, and the magnitude of the electric field is 275 V/m.
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The actual final pressure of the light bulb will be different than calculated above because the glass bulb will expand. What will the final actual gauge pressure be, taking this into account? The volume expansion coefficient for glass is ?
The pressure changes when the volume is changed.
Why does pressure change with volume?
Your question is incomplete thus I will take a general approach of the relationship of pressure and volume.
Pressure changes with volume because of the relationship between the number of gas molecules, the volume they occupy, and the temperature of the gas.
According to Boyle's Law, which describes the relationship between pressure and volume at a constant temperature, when the volume of a gas is decreased, the gas molecules become more crowded and collide with the container more frequently, resulting in an increase in pressure. Conversely, when the volume of a gas is increased, the gas molecules have more space to move around, resulting in a decrease in pressure.
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a crate of mass 190 kg is being pulled along a horizontal, flat surface by a massless rope. the surface has known coefficients of friction, where the coefficient of kinetic friction is y?
If you keep pulling with the same tension, what is the acceleration of the crate?
The rope's tension, the degree of friction factor, and also the mass of crate all affect the crate's acceleration.
How does friction work in simple physics?Between contacting materials that are sliding or attempting to slide over one another, there's an external force called friction. For illustration, friction makes it challenging to push a book down the floor.
Net force is equal to the sum of the resistive and rope forces.
The applied load is the same as the weight of crate, or mg, with g is the speed from gravity when m is the container's mass because the floor is straight and the object is not moving upwards.
In this case, the amount of contact is given by:
frictional force = y * mg
where y represents the kinetic friction coefficient.
When everything is added, we have:
net force is equal to T-y*mg.
Using Newton ’s second as well:
T-y*mg = ma
where a represents the crate's acceleration.
Solving for a, we get:
a = (T - y * mg) / m
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A particle moving through space has position at time t given by s(t) = 14+20 ( sqrt) t where t is in seconds and s(t) is in meters. What is the acceleration of the object at t = 4 ? A. 5 m/s^2 B. -5/2 m/s^2 C. 15/8 m/s^2 D. -5 8 m/s^2 E. 40 m/s^2
The acceleration of the object at t = 4 is [tex]-5/2 \ m/s^2[/tex]. The correct answer is B.
The acceleration of the object at t = 4 can be found by taking the second derivative of the position function s(t). Acceleration is the rate at which an object changes its velocity with respect to time. It is a vector quantity, meaning that it has both magnitude and direction. The first derivative of s(t) is the velocity function v(t), and the second derivative is the acceleration function a(t).
The first derivative of s(t) is:
[tex]v(t) = d/dt [14 + 20 \sqrt t] \\
= 20/(2\sqrt t)
\\= 10/\sqrt t[/tex]
The second derivative of s(t) is:
a(t) =[tex]d/dt [10\sqrt t][/tex]
=> [tex]-10/(2t^{(3/2)})[/tex]
=>[tex]-5/(t^{(3/2)})[/tex]
Plugging in t = 4 into the acceleration function gives:
a(4) = [tex]-5/(4^{(3/2)})[/tex]
= -5/(8)
= -5/2
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in the winter sport of bobsledding, athletes push their sled along a horizontal ice surface and then hop on the sled as it starts to careen down the steeply sloped track. in one event, the sled reaches a top speed of 9.2 m/s before starting down the initial part of the track, which is sloped downward at an angle of 6.0. What is the sled's speed after it has traveled the first 140 m?
The required sled's speed after it has travelled the first 140 m is calculated to be 19.31 m/s.
The sled's maximum speed is listed as 9.2 m/s.
The angle of the slope is 6 degrees downward.
Distance travelled by the sled is 140 meters.
The ratio of a body's mass to its acceleration determines the force acting on it.
The inclined plane's acceleration can be expressed as,
a = Fg/m = m g sinθ/m = g sinθ
where,
Fg is force due to gravity
a is acceleration of the body
Put the values as follows in the equation above:
a = 9.81 × sin 6° = 1.03 m/s²
The equation of motion may now be used to get the sled's speed as,
v² - u² = 2 a s
v² - 9.2² = 2 × 1.03 × 140
v² - 9.2² = 288.4
v² = 84.64 + 288.4
v = 19.31 m/s
Thus, the sled's speed after it has travelled the first 140 m is 19.31 m/s.
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The motion of particle is restricted to a plane and analyzed with polar coordinates. Which of the following quantities of the particle's motion does not have a transverse component for any motion? Position Velocity Acceleration None of the above
Position and velocity both have transverse components for motion in polar coordinates. However, acceleration can be expressed as the sum of a radial component and a tangential component, where the tangential component is transverse to the radial direction. Therefore, the answer is Acceleration (Option 3).
An object's acceleration can be defined as the rate at which its velocity changes in relation to the passage of time. Accelerations are vector quantities. The orientation of the net force that is acting on an item is what determines the orientation of the acceleration the object is experiencing.
Particle dynamics studies particle motion and forces. Without a net force, a body has a constant velocity. The net force on a body must be zero to prevent acceleration.
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The 5.00 V battery in (Figure 1) is removed from the circuit and replaced by a 15.00 V battery, with its negative terminal next to point b . The rest of the circuit is as shown in the figure. Figure1 of 1 A closed circuit is made up of three horizontal parallel branches. The top branch contains, from left to right, a 2.00-ohm internal resistor, a 10.00-volt battery, point 'a', and a 3.00-ohm resistor, all connected in series. The middle branch contains, from left to right, a 1.00-ohm internal resistor, a 5.00-volt battery, point b, and a 4.00-ohm resistor, all connected in series. The bottom branch contains a 10.00-ohm resistor. Both batteries have the positive terminal on their left.
(a) Current in the upper branch is -0.4 A
(b) Current in the middle branch is 1.6 A
(c) Current in the lower branch is 1.2 A
What is Kirchhoff's law ?Kirchhoff's current law states that, at a node, the current entering the circuit is equal to the current leaving the circuit. That means the sum of all currents at the node is zero.
Here,
According to Kirchhoff's current law,
I₁ + I₂ = I₃
Taking the clockwise direction from upper loop,
According to Kirchhoff's voltage law,
2I₁ -10 + 3I₁ - 4I₂ + 20 - I₂ = 0
5I₁ - 5I₂ = -10
I₁ - I₂ = -2
Taking clockwise direction from the lower loop,
According to Kirchhoff's voltage law,
-4I₂ + 20 - I₂ + 2I₂ - 10I₃ = 0
-5I₂ - 10I₃ = -20
Dividing by 5,
I₂ + 2I₃ = 4
So we get three equations,
I₁ + I₂ = I₃ (1)
I₁ - I₂ = -2 (2)
I₂ + 2I₃ = 4 (3)
From the above equations,
Adding (2) and (3), we get,
I₂ = 3I₃ - 2
Applying this in eqn(3),
3I₃ - 2 + 2I₃ = 4
5I₃ = 6
I₃ = 1.2 A
So, I₂ = 3I₃ - 2 =3X 1.2 - 2
I₂ = 1.6 A
I₁ = -2 + I₂ = -2 + 1.6
I₁ = -0.4 A
Hence,
(a) Current in the upper branch is -0.4 A
(b) Current in the middle branch is 1.6 A
(c) Current in the lower branch is 1.2 A
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draw the force vectors with their tails at the dot. the location and orientation of your vectors will be graded. the exact length of your vectors will not be graded but the relative length of one to the other will be graded. the black vector is the sum of the vectors in your diagram.
These forces can be seen as a free-body image where we compress the book to a point. The force vectors are then positioned so that their tails are of the vectors point with in plane of the interaction.
What procedures were used to create the Class 11 free-body diagram?Choosing the structure within which the rules of motion will be applied is the first stage. Finding the forces at work on the given software or particle for interest is the second stage. The full body diagram must be drawn in the third phase.
How are a vector's size and direction depicted in a volkswagen vw?The height of the arrow serves as a symbol for a vector's magnitude. An indication of a scale, such as 1 cm = 5 miles, is made, and the arrow is drawn at the appropriate length using the selected scale. The precise direction is shown by the arrow.
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