java given that the variables x and y have already been declared and assigned values, write an expression that evaluates to true if x is non-negative and y is negative.

Step-by-step explanation:

college level question ???? what the ...

oh my.

16 : 20 = 16 / 20 = 16 ÷ 20

16/20 = 4/5 = 0.8

Answer: $ 5.90 is the the cost of 2 panes of glass

In order to solve this we must divide the number of panes, by the cost spent on the panes. 20.65 divided by 7 is 2.95. This means that each pane is $ 2.95. If there are two panes that were also broken, we have to add 2.95 twice, which is $5.90. This means that the nursey owner must spend another $5.90 on two panes.

I hope this helps & Good Luck <3 !!!

With placing positive integers around the circle. Yes, there exist three integers in consecutive locations around the circle that have a sum greater than or equal to 17.

What exactly is a circle?

A circle is a kind of ellipse with zero eccentricity and two foci that are coincident. A circle is also known as the locus of points drawn at equal distances from the center. The radius of a circle is the distance from its center to its outside line. The diameter of a circle is the line that divides it into two equal sections and is equal to twice the radius.

The equation for a circle in the plane is:

(x-h)^²+ (y-k)² = r²

When the coordinate points are (x, y)

(h, k) is the coordinate of a circle's center.

where r is the circumference of a circle.

where circle area = πr²

Circle circumference=2πr

Now,

First 10 positive integers

that are 1,2,3,4,5,6,7,8,9,10

after putting these in circle 1 and 10 will be adjacent

and

To prove :-there exist three integers in consecutive locations around the circle that have a sum greater than or equal to 17 .

Now as sum of =5+6+7=18

6+7+8=21

7+8+9=24

Hence,

           There exist three integers in consecutive locations around the circle that have a sum greater than or equal to 17.

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Answer:

a= 4

Step-by-step explanation:

Rearrange terms

Multiply all terms by the same value to eliminate fraction denominators

Cancel multiplied terms that are in the denominator

Multiply the numbers

than subastraract form both by 25

Simplify the expression

Subtract the numbers

Subtract the numbers

You will find the solution

Answer:

x = 17.2 oz of substance A and C

x = 3.7 oz of substance B

Step-by-step explanation:

This is a word problem in mathematical optimization, which involves finding the values that maximize or minimize some objective function. To solve this problem, we need to find the optimal number of ounces of each substance to provide 100% of the required nutrition.

Let x be the number of ounces of substance A and C. Then the amount of substance B is 1 1/5 times either of these, or 1 1/5 x.

Since each ounce of substance A supplies 3% of the nutrition, the total contribution from A is 3x%. Similarly, the total contribution from B is 10 * 1 1/5 x = 11 x/5% and from C is 15x%.

The objective is to find x such that the total contribution from all three substances is 100%, or 3x + 11 x/5 + 15x = 100.

Solving for x, we have

29x/5 = 100

x = 100 * 5 / 29 = 17.24 oz

So, 17.24 oz of substance A and C, and 1 1/5 * 17.24 oz = 3.65 oz of substance B should be in the meal. Rounding to the nearest tenth, we have:

x = 17.2 oz of substance A and C

x = 3.7 oz of substance B

The answers to each part is given below.

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.

Given is a charitable organization.

{ a } -

Assume that the annual salary of the baseball player is ${x}. The amount donated would be -

10% of {x} = ${x/10}

In $120, you can send 1 child to school.

In $1, you can send (1/120) childrens to school.

In ${x/10}, you can send {x/1200} childrens to school.

{ b } -

Same answer as in the case of part {a}.

Therefore, the answers to each part is given above.

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The correct option on this statistics topic is (c) To determine if a significant X-Y relationship exists.

Statistics is a science and perhaps also the art of learning from data. As a discipline, it deals with the collection, analysis, and interpretation of data, and the effective communication and presentation of data-based results. 

In statistics correlation coefficient is a single number that represents the strength and direction of the relationship between variables.

Different types of correlation coefficients may be appropriate for your data, depending on the measurement level and distribution. Pearson's product-moment correlation coefficient (Pearson's r) is commonly used to assess the linear relationship between two quantitative variables. 

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The coordinate of the quadrilateral DEFG after trnaslation, reflection and dilation is mention on the graph.

A spatial transformation is each mapping of feature space to itself and it maintains some spatial correlation between figures.

The vertices of the quadrilateral DEFG (Red) is given as,

D(2, 2), E(6, 2), F(8, 4), G(2, 4)

The vertices of the quadrilateral D'E'F'G' after translation (Green) is given as,

D'(2, -4), E'(6, -4), F'(8, -2), G'(2, -2)

The vertices of the quadrilateral D"E"F"G" after reflection (Purple) is given as,

D"(-2, -4), E"(-6, -4), F"(-8, -2), G"(-2, -4)

The vertices of the quadrilateral D'''E'''F'''G''' after reflection (Black) is given as,

D'''(-1, -2), E'''(-3, -2), F'''(-4, -1), G'''(-1, -2)

The coordinate of the quadrilateral DEFG after trnaslation, reflection and dilation is mention on the graph.

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The value for differential equation is found as -

[tex]\frac{dP}{dt} =\frac{d}{dt} (\frac{c_1e^t}{1+c_1e^t})\\[/tex]

[tex]\frac{dP}{dt} - (\frac{c_1e^t}{(1+c_1e^t)} )(1-\frac{c_1e^t}{(1+c_1e^t)^2})\\ =(\frac{c_1e^t}{(1+c_1e^t)^2} )-(\frac{c_1e^t}{1+c_1e^t})(1-\frac{c_1e^t}{1+c_1e^t})=0[/tex]

What is differential equation?

Any equation with one or more terms and one or more derivatives of the dependent variable with respect to the independent variable is referred to as a differential equation.

The equation given is - [tex]P=\frac{c_1e^t}{1+c_1e^t}[/tex]

Take derivative with respect to t -

[tex]\frac{dP}{dt} =\frac{d}{dt} (\frac{c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =\frac{d}{dt}c_1 (\frac{e^t}{1+c_1e^t})[/tex]

By Quotient rule [tex]\frac{d}{dt} \frac{u}{v} =\frac{v\frac{du}{dt}- u\frac{dv}{dt}}{v^2}[/tex] -

[tex]\frac{dP}{dt} =c_1 (\frac{(1+c_1e^t)\frac{d}{dt}(e^t)-(e^t)\frac{d}{dt}(1+c_1e^t)}{(1+c_1e^t)} )\\\frac{dP}{dt} =c_1 (\frac{(1+c_1e^t)(e^t)-(e^t)(0+c_1e^t)}{(1+c_1e^t)} )[/tex]

([tex]\frac{d}{dx} e^t=e^t[/tex] and [tex]\frac{d}{dx} c_1=0[/tex] here [tex]c_1=[/tex]constant)

[tex]\frac{dP}{dt} =c_1e^t (\frac{(1+c_1e^t-c_1e^t)}{(1+c_1e^t)^2} )\\\frac{dP}{dt} = (\frac{(c_1e^t)}{(1+c_1e^t)^2} )[/tex]

Now, [tex]\frac{dP}{dt} =P(1-P)[/tex] -

[tex]\frac{dP}{dt} - (\frac{c_1e^t}{(1+c_1e^t)} )(1-\frac{c_1e^t}{(1+c_1e^t)^2})\\ =(\frac{c_1e^t}{(1+c_1e^t)^2} )-(\frac{c_1e^t}{1+c_1e^t})(1-\frac{c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{1}{1+c_1e^t}-1+\frac{c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{1-(1+c_1e^t)+c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{1-1-c_1e^t+c_1e^t}{1+c_1e^t})\\[/tex]

[tex]\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{0}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(0)\\\frac{dP}{dt} =0[/tex]

Therefore, the value is [tex]\frac{dP}{dt} =0[/tex].

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The revenue function (Rx) when x is 1, 4, 8, 12,16, 20 are 72,252,468,432, and 300 respectively.

Revenue function is a formula or equation representing the way in which particular items of income behave when plotted on a graph. For example, the most common revenue function is that for total revenue in the equation y = bx, where y is the total revenue, b is the selling price per unit of sales, and x is the number of units sold.

R(x) = x × P(x)

When x = 1

R(x) = 1(75-3)

R(x) = 72

when x = 4

R(x) = 4( 75-12)

= 252

when x = 12

R(x) = 12(75-36)

R(x) = 468

when x = 16

R(x) = 16( 75-48)

= 432

when x = 20

R(x) = 20( 75-60)

= 300

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The values of the compositions of the functions are.

Here we have two graphs for functions f(x) and g(x), and we need to use these to find the values of some compositions.

First, we want to find the value of:

f(g(5))

Using the second graph we can see that g(5) = 0, then:

f(g(5)) = f(0)

and using the first graph we can see that f(0) = 4, then

f(g(5)) = 4.

The second expression is:

g(f(1))

And we cans ee that f(1) = 3, then:

g(f(1)) = g(3) = 1

So:

g(f(1)) = 1

And so on, for the next two we have:

f(f(4)) = f(2) = 0

g(g(3)) = g(1) = 5

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It should be noted that the area model method is based on the simple equation that is used to find the area of a rectangle:

the length times the width equals the total area (LxW=A).

The area of a shape simply means the total space that is taken by the shape. It simply expresses the extent of the region on a particular plane as well as a curved surface.

For example, the area of a rectangle with the length of 48 units and a width of 21 units can be measured by multiplying 48 by 21. This will be 1008 units².

A overview was given as your information is incomplete

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The solution is, EF = 4√3

Area of a rectangle (A) is the product of its length (l) and width (w).

A= l. w

here, we have,

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A = 48 cm^2

The area of the triangle is 1/4 of this. Therefore:

A = 12 cm^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

12 = 1/2 * DF *DE

Since DE = DF:

24 = DF^2

Thus:

DF = 2√6 = DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

DF^2 + DE^2 = EF^2

Therefore:

now, Squaring & Adding , we get,

FE^2 = 48

And finally, we can take the square root of both sides:

EF =  4√3

Hence, The solution is, EF = 4√3

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The coordinates of the image of quadrilateral DEFG after being reflected about the origin include the following:

D' = (9, 5).

E' = (-5, -4).

F' = (6, 2).

G' = (-4, -2).

In Geometry, a reflection can be defined as a type of transformation which moves every point of the object by producing a flipped but mirror image of the geometric figure.

Generally speaking, reflecting a point about the origin is a a type of transformation which causes both the x-coordinate and the y-coordinate to become negated (the signs are changed);

(x, y)                              →               (-x, -y)

Ordered pair D  = (-9, -5) →   Ordered pair D' = (9, 5).

Ordered pair E  = (5, 4) →   Ordered pair E' = (-5, -4).

Ordered pair F  = (-6, -2) →   Ordered pair F' = (6, 2).

Ordered pair G  = (4, 2) →   Ordered pair G' = (-4, -2).

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the total area of the figure will be 53.13 unit square.

The area is the entire amount of space occupied by a flat (2-D) surface or an object's form. On a sheet of paper, draw a square using a pencil. It has two dimensions. The area of a form on paper is the area that it occupies.

Given a figure that we will transform into three parts A, B, and C as shown in the attached figure

Where A is a semicircle with a radius of 3 unit

b is a triangle with a height of 6 and a base of 3 units

and C is a rectangle with a length of 6 and a width of 5 units

From the general formulas of area,

area of semicircle = pi/2 radius * radius

Area of rectangle = length * width

Area of triangle = 1/2 height * base

in our case,

area of semicircle = pi/2 3* 3

Area of semicircle = 14. 13 unit square

Area of rectangle = 6* 5

Area of rectangle = 30 unit square

Area of triangle = 1/2 6* 3

Area of triangle = 9

Thus, the total area of the figure will be = 14. 13 + 30 +9

Therefore, the total area of the figure will be 53.13 unit square.

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Answer:

Exact Form:

x=15/8

Decimal Form:

x=1.875

Mixed Number Form:

x=1 7/8

Step-by-step explanation:

Answer: [-3, 13)

A square bracket [] means it includes the number, and a round bracket () means that value is not included.

The formula to calculate the number of books donated by Hannah would be: bbb/150150150 = 333.

Essentially, we are taking the total number of books that were donated, bbb, and dividing it by the total number of students at Hannah's school, 150150150. The result of this equation is 333, which represents the number of books Hannah donated. To calculate this number we would first divide bbb by 150150150. Then, we would multiply the result by 333 to get the total number of books Hannah donated. For example, if the total number of books donated was 300,000, the number of books Hannah donated would be 49,950. This can be calculated by dividing 300,000 by 150150150 and then multiplying the result by 333.

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The solution is, the value of x= 12.4.

Pythagorean theorem, the well-known geometric theorem that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle)—or, in familiar algebraic notation, a2 + b2 = c2.

here, we have,

radius = 22

so, from the given diagram we get,

height of the right angle triangle = √22²-19.8²

                                                      =9.59

so, x = 22- 9.59

       = 12.41

Hence, The solution is, the value of x= 12.4.

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The maximum area is 900 square meters

Given that

Perimeter, P = 120

So, we have

P = 2(l + w) = 120

This gives

l + w = 60

Make l the subject

l = 60 - w

The area is

A = lw

So, we have

A =w(60 - w)

Expand

A = 60w - w^2

Differentiate and set to 0

60 - 2w = 0

So, we have

w = 30

Recall that

A =w(60 - w)

So, we have

A = 30(60 - 30)

Evaluate

A = 900

See attachment

This is represented as follows

Length (l) | Width (w) | Area (A)

30 | 30 | 900

35 | 25 | 875

40 | 20 | 800

45 | 15 | 675

50 | 10 | 500

55 | 5 | 275

See attachment

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Answer:

900 m²

Step-by-step explanation:

The maximum possible area of a rectangle is when the width and length are equal, i.e. it is a square.

To find the side length of a square, divide its perimeter by 4. Therefore, the width and length of a rectangle with perimeter 120 m is:

[tex]\implies \sf \dfrac{120}{4}=30\;m[/tex]

The area of a square is the square of its side length, so the maximum area for a rectangle with perimeter of 120 m is:

[tex]\implies \sf Area=30^2=900\;m^2[/tex]

The formula for the perimeter of a rectangle is:

[tex]\boxed{\sf Perimeter=2(width+length)}[/tex]

Therefore, if the perimeter is 120 m:

[tex]\implies \sf 120=2(width+length)[/tex]

[tex]\implies \sf width+length=60[/tex]

So the width and length must sum to 60 m.

Sketch various rectangles where the sum of their width and length is 60 m.  For example:

The formula for the area of a rectangle is:

[tex]\boxed{\sf Area=width \times length}[/tex]

A table with the width, length and areas (in increments of 5 m for the lengths) is as follows:

[tex]\begin{array}{c|c|c}\vphantom{\dfrac12} \sf width\;(m)&\sf length\;(m)& \sf area\;(m$^2$)\\\cline{1-3}\vphantom{\dfrac12}5&55&275\\\vphantom{\dfrac12}10&50&500\\\vphantom{\dfrac12}15&45&675\\\vphantom{\dfrac12}20&40&800\\\vphantom{\dfrac12}25&35&875\\\vphantom{\dfrac12}30&30&900\\\vphantom{\dfrac12}35&25&875\\\vphantom{\dfrac12}40&20&800\\\vphantom{\dfrac12}45&15&675\\\vphantom{\dfrac12}50&10&500\\\vphantom{\dfrac12}55&5&275\end{array}[/tex]

Let x be the length of the rectangle (in meters).

Let y be the area of the rectangle (in meters squared).

From inspection of the values of area from the table from part (b), the function is quadratic, since the second differences between the y-values is constant.  The maximum point (vertex) is (30, 900).  Therefore, the graph is a parabola that opens downwards.

[tex]\boxed{\begin{minipage}{5.6 cm}\underline{Vertex form of a quadratic equation}\\\\$y=a(x-h)^2+k$\\\\where:\\ \phantom{ww}$\bullet$ $(h,k)$ is the vertex. \\ \phantom{ww}$\bullet$ $a$ is some constant.\\\end{minipage}}[/tex]

As the vertex is (30, 900) and the parabola opens downwards (so the value of "a" is negative):

[tex]\implies y=-a(x-30)^2+900[/tex]

To find the value of a, substitute one of the other points into the equation:

[tex]\implies -a(10-30)^2+900=500[/tex]

[tex]\implies -a(-20)^2=-400[/tex]

[tex]\implies -400a=-400[/tex]

[tex]\implies a=1[/tex]

Therefore, the equation of the parabola is:

[tex]y=-(x-30)^2+900\qquad \{x|\;0 < x < 60\}[/tex]

Note: If the measure of one side of the rectangle is 60 m, then the measure of the adjacent side will be 0 cm, which is impossible. Therefore, the domain of the function must be set to (0, 60).

From inspection of the table, the maximum area of a rectangle that has a perimeter of 120 m is when its width and length are both 30 m.

From the graph of the relationship between length and area of a rectangle with a perimeter of 120 m, the maximum area is when the length is 30 m ⇒ max area = 900 m².

Therefore, the maximum area of the rectangle is 900 m².

Answer:

Step-by-step explanation:

To calculate the amount of interest earned by Amelia's investment, we can use the formula for compound interest:

A = P * (1 + r/n)^(nt), where

A = amount after t years

P = principal amount ($9810)

r = annual interest rate (2.7%)

n = number of times the interest is compounded per year (quarterly, so n = 4)

t = number of years (13)

Plugging in the values, we get:

A = $9810 * (1 + (0.027/4))^(4 * 13)

A = $9810 * (1.00675)^52

A = $9810 * 1.8972436

A = $18561.61 (rounded to nearest cent)

Therefore, the interest earned by Amelia's investment is $18561.61 - $9810 = $8751.61.

The Area of the given triangle is 1146.27 sq. units.

An important plane geometry theorem also referred to as Hero's formula.

By dividing the quadrilateral into two triangles along its diagonal, this formula is also used to determine the quadrilateral's surface area.

Given the semiperimeter and the lengths of the sides a, b, and c

[tex]p=\frac{a+b+c}{2}[/tex]

of a triangle, Heron's formula gives the area of the triangle as

[tex]A=\sqrt{p(p-a)(p-b)(p-c)}[/tex].

Now in the given question,

a = 57

b = 43

c = 58

Hence, the semi-perimeter,

[tex]p=\frac{a+b+c}{2}[/tex]

[tex]p=\frac{57+43+58}{2} =79[/tex]

Now we calculate the area,

[tex]A=\sqrt{p(p-a)(p-b)(p-c)} \\A=\sqrt{79(79-47)(79-43)(79-58)} \\A=\sqrt{79(22*36*21)} \\A=\sqrt{79*16632} \\A=\sqrt{1313928} \\A=1146.266[/tex]

Hence, the area of triangle is 1146.27 sq. units.

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Answer: P'(50) = -200 means that the derivative of P(t) with respect to t, evaluated at t = 50, is equal to -200. The derivative of a function represents the rate of change of the function. In this case, P'(50) = -200 represents the rate of change of the number of individuals infected by the disease 50 days after it was first detected.

Since P'(50) = -200, this means that the number of individuals infected by the disease is decreasing at a rate of 200 individuals per day when t = 50. In other words, 200 individuals are recovering or being treated each day, so the total number of infected individuals is decreasing.

Step-by-step explanation:

Answer:

Yes, Uncle Sonny is correct.

Step-by-step explanation:

If two figures are related by a dilation, then corresponding lines or line segments in the figures will be congruent. In a dilation, the ratio of the lengths of corresponding lines or line segments remains constant, which means they will have the same length. Therefore, they are congruent.

After analyzing, it can be concluded that the functions f and g are:

A. f(0) is larger than g(0).

B. f(3) is larger than g(3).

To determine which of the two functions is larger at any given point, one must compare the heights of the two functions at the same point on the x-axis. At point x=0, the height of the f(x) function is larger than the height of the g(x) function, so f(0) is larger than g(0).

Similarly, at point x=3, the height of the f(x) function is larger than the height of the g(x) function, so f(3) is larger than g(3).

To compare which of two functions is larger at any given point, we need to compare the heights of the two functions at the same point on the x-axis. For example, at x=0, the height of the f(x) function is larger than the height of the g(x) function, so f(0) is larger than g(0). The same comparison can be made at any other point on the x-axis.

For example, at x=3, the height of the f(x) function is larger than the height of the g(x) function, so f(3) is larger than g(3). This comparison can be done for any point on the x-axis, which will allow us to determine which of the two functions is larger at any given point.

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The solution to the system of equations is 6kg of 15 % chromium and 3kg of 18 % stainless steel

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the amount of chromium be x

Let the amount of stainless steel be y

The percentage of amount of chromium = 15 % of x

The percentage of amount of stainless steel = 18 % of y

Now , the amount of mixture = 9 kg

The percentage of amount of mixture = 17 %

So , the equation will be

x + y = 9   be equation (1)

0.15x + 0.18y = 0.17 ( 9 )

On simplifying the equation , we get

15x + 18y = 153  

Divide by 3 on both sides of the equation , we get

5x + 6y = 51   be equation (2)

Multiply equation (1) by 5 , we get

5x + 5y = 45   be equation (3)

Subtracting equation (3) from equation (2) , we get

y = 6 kg

So , the value of x = 3 kg

Hence , the mixture contains 6kg of 15 % chromium and 3kg of 18 % stainless steel

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The percentage error by calculating by differentials to approximate value of sqrt(99.4) = 0.00045 percentage.

For   percentage error Here first we have to find the value of sqrt(99.4) by  normal calculation and second we will calculate it by differential method then we will find the percentage error .

To approximate sqrt(99.4)  we will  use formula for linear approximation as given below  

f(x) = f(c) + f′(c)(x−c)

and we are dealing with square root so we have to find the f(x) ad here

f(x) = √x

and we will calculate  f'(x)  and here it is

f'(x) = 1/(2√x)

Here, x=99.4 and we choose c =100 because that’s the closest perfect square number to 99.4. so

f(c) = f(100) = √100 = 10

f'(c) = f'(100) =1/(2√100) = 1/20

f(x) =f(c) + f′(c)(x−c)

f(x) = f(99.4)=f(100)+f'(100)(99.4-100)

=10+1/20*(-0.6)

=9.97

Here we find the value by differential = 9.97

and by simple calculation the value is = 9.96995486

ans percentage error = (real value - differential value)/100

= (9.96995486-9.97)/100 = 0.00045 percentage

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The slope of the line through the points is 4/7 and the graph is given below.

Slope of a line is the ratio of the change in y coordinates to the change in the x coordinates of two points given.

Given that, the points ​(14​,8​) and ​(28​,​16) form a proportional relationship.

A proportional relationship will be of the form y = kx, where k is the slope or constant of proportionality.

We have two points ​(14​,8​) and ​(28​,​16).

Slope = (16 - 8) / (28 - 14) = 8/14 = 4/7

Equation of the line is y = 4/7 x

When x = 0, y = 0

When x = 7, y = 4/7 × 7 = 4

When x = 14, y = 4/7 × 14 = 8

When x = 21, y = 4/7 × 21 = 12

and so on.

So the points are (0, 0), (7, 4), (14, 8), (21, 12), (28, 16) and so on.

Hence the slope of the line is 4/7.

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