Janice buys 74 packs of gum in a variety flavors. She chooses twice as many packs of green apple gun as packs of spearmint gum and 6 fewer packs of cinnamon gun than packs of green apple gum. How many packs of spearmint gum does Janice buy?

Answer:

slide A= 6

slide B= 8

perimeter= 36

Area = 80

Step-by-step explanation:

Answer:

slide A= 6

slide B= 8

perimeter= 36

Area = 80

Step-by-step explanation:

Answer:

thanks have a nice day can you please mark me brainliest im trying to rank up and i  need 2 more brainlys

Step-by-step explanation:

Answer:

First: 105

Second: 65

Third: 133

Fourth: 129

Fifth: 60

Answer:

2000 minutes on 16 miles

Answer:

168.75 minutes

Step-by-step explanation:

Francine's speed (the unit rate) is (16 miles) / (45 minutes), or 16/45 miles/min.

Recalling that distance = speed times time, we recognize that

time = distance / speed

which here is  

(60 miles) / (16/45) miles/min = 168.75 minutes, or 168 min 45 sec

Answer:20 dollars.

not sure

Step-by-step explanation:

Answer:

( x + 8 ) ^2+ y^2= 36

Step-by-step explanation:

Answer: 1.25 minutes per lap

Step-by-step explanation:

Her total time divided by total laps is 15 divided by 12, which is 1.25

Answer:

Kenith runs 0.8 laps a minute

Step-by-step explanation:

Step-by-step explanation:

K=12 if you want explanation i will

Answer:

0.20

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

(2, 6) is not a solution to the given system of linear equations.

y = 5x - 4 = 5*2 - 4 = 10 - 4 = 6

y = - 1/2x + 8 = - 1/2 * 2 + 8 = - 1 + 8 = 7

Since, point (2, 6) does not satisfy to equation 2.

Therefore, (2, 6) is not a solution to the given system of linear equations.

Answer:

no

Step-by-step explanation:

This it the test please do as fast as posible and show work. thank you and sorry

Answer:

x=1 and y=10 (1,10)

Step-by-step explanation:

2+30=32

10=1+9

Answer:

Step-by-step explanation:

First box: (0,1)

Second box: (0,-3)

Third box: (0,-4)

The number of bags that would be collected in the second week is 6 7/8 bags.

A mixed number is a number that is made up of an integer and a proper fraction. A proper fraction is a fraction that has a numerator that is less than the denominator. An example of a mixed number is 2 3/4.

In order to determine the number of bags that would be collected in the second week, multiply 2 3/4 by 2 1/2. Multiplication is the mathematical operation that is used to determine the product of two or more numbers.

Number of bags collected in the second week = 2 3/4 x 2 1/2

11/4 x 5/2 = 55/8 = 6 7/8 bags

To learn more about multiplication of fractions, please check: https://brainly.com/question/1114498

#SPJ1

Answer:

6

Step-by-step explanation:

14/2 - 3 + 6/3

Divide 14 by 2 to get 7.

7−3+6/3

Subtract 3 from 7 to get 4.

4+6/3

Divide 6 by 3 to get 2.

4+2

Add 4 and 2 to get 6.

6

Answer: $200

Step-by-step explanation:

On the X axis, it shows the kilograms. Since the problem asks for how much money she makes for 60 kg, go to the point on the X axis that represents 60 kg and then go up to the corresponding y or dollar value, which is 200.

the answer is 3p

hope it helps!

Answer: 3p

Step-by-step explanation:

5 − 3 + =

3

Answer: 3y + 5 cm

Step-by-step explanation: The perimeter of a triangle

is just the distance around the outside of the figure.

So just add up all the sides.

So we have y + y + y + 5 and we get 3y + 5.

Answer:

5 inches

Step-by-step explanation:

Hope I helped

Answer:

Annual $54,624.85

Semiannual $54,787.62

Monthly $54,927.75

Daily $54,955.35

Continuously $54,955.35

Step-by-step explanation:

If 42,800 dollars are invested at an interest rate of 5 percent per year, to find the value of the investment at the end of 5 years for the following compounding methods, the following calculations must be performed:

Annual $54,624.85

42,800 (1 + 0.05 / 1)^5x1 = X = 54,624.85

Semiannual $54,787.62

42,800 (1 + 0.05 / 2)^5x2 = X = 54,787.62

Monthly $54,927.75

42,800 (1 + 0.05 / 12)^5x12 = X = 54,927.75

Daily $54,955.35

42,800 (1 + 0.05 / 365)^5x365 = X = 54,955.35

Continuously $54,955.35

42,800 (1 + 0.05 / 365)^5x365 = X = 54,955.35

Answer:

18n+9

Step-by-step explanation:

9(2n+1)

18n+9

Answer:

2

Step-by-step explanation:

Reduce the numbers with the greatest common factor which is 3

So.. 2

Answer:

2

Step-by-step explanation:

I did 8 divided by 4 which is 2.

I hope this helps.

Answer:

a) 0.1151 = 11.51% probability that an individual distance is greater than 210.00 cm.

b) 0.883 = 88.3% probability that the mean for 20 randomly selected distances is greater than 197.80 cm.

c) The distribution of the population is normal, which means that the sample size does not need to exceed 30.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a standard deviation of 8.3 cm.

This means that [tex]\mu = 200, \sigma = 8.3[/tex]

a. Find the probability that an individual distance is greater than 210.00 cm.

This is 1 subtracted by the pvalue of Z when X = 210. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{210 - 200}{8.3}[/tex]

[tex]Z = 1.2[/tex]

[tex]Z = 1.2[/tex] has a pvalue of 0.8849

1 - 0.8849 = 0.1151

0.1151 = 11.51% probability that an individual distance is greater than 210.00 cm.

b. Find the probability that the mean for 20 randomly selected distances is greater than 197.80 cm

Now [tex]n = 20, s = \frac{8.3}{\sqrt{20}} = 1.8559[/tex]

This probability is 1 subtracted by the pvalue of Z when X = 197.8. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{197.8 - 200}{1.8559}[/tex]

[tex]Z = -1.19[/tex]

[tex]Z = -1.19[/tex] has a pvalue of 0.117

1 - 0.117 = 0.883

0.883 = 88.3% probability that the mean for 20 randomly selected distances is greater than 197.80 cm.

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The distribution of the population is normal, which means that the sample size does not need to exceed 30.