James has a desk job and would like to become more fit, so he purchases a tread walker and a standing desk which will allow him to walk at a slow pace as he works. However, he is concerned that standing and walking while working may cause his productivity to decline. After working this way for 6 months he takes a simple random sample of 15 days. He records how long he walked that day (in hours) as recorded by his fitness watch as well as his billable hours for that day as recorded by a work app on his computer. Assuming that all conditions for inference are met, which of the following is a 95 percent confidence interval for the average change in the number of billable hours for each increase of 1 hour spent walking?

Answer:

cost of paint set  =$19.5

cost of Sketchbook = $13

cost of brush =  $3..25

Step-by-step explanation:

Total money with Nate = $37.75

Let the cost of paint set be $x

As the  Sketchbook cost 2/3 the cost of the paint set

Thus cost of Sketchbook = $(2/3)x

Cost of brush is 1/4 of Sketchbook

Thus cost of brush = (1/4)*(2/3)x =$ 1/6x

Total cost of all the three item in terms of x  is

x + (2/3)x + ( 1/6)x

=>(6x+4x+x)/6 = 11x/6

Given that after money spent on buying all the three thing Nate has left $2

subtracting money spent on buying three things from total money is equal to $2

Mathematically it can be written as

$37.75 -  11x/6 = $2

=> $37.75  - $2  11x/6

=>$35.75 =  11x/6

=> $35.75*6 = 11 x

=> $214.5 = 11x

=> $214.5/11 = x  

=> x = 19.5

Thus,

cost of paint set  = x = $19.5

cost of Sketchbook = $(2/3)x =$(2/3)*19.5 = $13

cost of brush = $ 1/6x = $ (1/6)*19.5 = $3.25

Answer:

  area: 144.5 cm^2

Step-by-step explanation:

Maybe you want the area of this figure.

The area of a trapezoid is given by the formula ...

  A = (1/2)(b1 +b2)h

Using the given dimensions, the area is ...

  A = (1/2)(9.7 cm +24.3 cm)(8.5 cm)

  A = (1/2)(34 cm)(8.5 cm) = 144.5 cm^2

Answer:

add x

Step-by-step explanation:

get the constants on one side, and the variables on the other for easiest solving.

Answer:

Correct

Step-by-step explanation:

Amount of granular of 10 batch of raisin nut = 28 cups

To find raisin nut 30 batches = 28 x 3 = 84

Amount of granula of 10 batch of honey almond energy = 42

To find honey almond 15 batches = 42 + 21 = 63

Answer:

Step-by-step explanation:

Since you did not post answer choices, there's not too much I can tell you. One thing for sure is that the equation must have 1/2x. This represents the slope at which the equation is increasing. To find which equation passes through (5,1), all you have to do is plug in 5 into the x in your equation. After you solve, if the y you get is equal to the y value of 1, you know that is the line that alsses through (5,1). I hope this helps.

Answer b

Step-by-step explanation:

It’s fast

Answer:

14

Step-by-step explanation:

all i did was divided 42 by 3 and got 14

Answer:D)36

Step-by-step explanation:

Took the test

Answer:

the area is 30 you have to muiltly the two together

Step-by-step explanation:

Answer:

Step-by-step explanation:

Identify:      Hypothesized π = 0.22 n =1189 X = 230  

Estimate the sample proportion, p, of defective items. p= X/n = 230/1189 = 0.1934

List the formula for the standard error of a proportion.   [tex]\sqrt{PQ/n}[/tex]

Estimate the standard error of a proportion.  [tex]\sqrt{PQ/n} = \sqrt{0.22\times 0.78/1189} = 0.0120[/tex]

State the null and alternative hypotheses below.

H0: P = 0.22

H1: P<0.22

Illustrate the acceptance and rejection regions of the diagram to the right.

check the attached image below for the diagram

Identify the critical Z , -1.645

Fornulate the decision rule and list below.

If Z calculated is less than Z critical we reject null hypothesis

Calculate your test statistic.

[tex]Z= \frac{p-P}{\sqrt{PQ/n}} = \frac{0.1934-0.22}{0.0120}= -2.217[/tex]

Do you accept or reject the null hypothesis at 0.05 level of significance? Reject

State your conclusion. Should the quality control manage accept the shipment or return it?

WE have sufficient evidence that the population proportion of "like the ads a lot" for the company's ads is less than 0.22 at a 0.05 level of significance.

If a 0.01 level of significance had been used in the test, would you have accepted or rejected the null hypothesis?  

at 0.01 level of significance the critical value of Z is -2.33

Since Z calculated is greater than Z critical value we accept the null hypothesis

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: motor skills of a sober subject.

n= 20

X[bar]= 37.1

S= 3.7

The claim is that the average score for all sober subjects is equal to 35.0, symbolically: μ= 35.0

The hypotheses are:

H₀: μ = 35.0

H₁: μ ≠ 35.0

α: 0.01

The statistic to use, assuming all conditions are met, is a one sample t- test

[tex]t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}[/tex]

[tex]t_{H_0}= \frac{37.1-35.0}{\frac{3.7}{\sqrt{20} } } = 2.34[/tex]

This test is two-tailed, meaning, the rejection region is divided in two and you'll reject the null hypothesis to low values of t or to high values of t:

[tex]t_{n-1;\alpha /2}= t_{19; 0.005}=-2.861[/tex]

[tex]t_{n-1;1-\alpha /2}= t_{19; 0.995}= 2.861[/tex]

The decision rule using this approach is:

If [tex]t_{H_0}[/tex] ≤ -2.861 or if [tex]t_{H_0}[/tex] ≥ 2.861, you reject the null hypothesis.

If -2.861 < [tex]t_{H_0}[/tex] < 2.861, you do not reject the null hypothesis.

The value is within the non rejection region, the decision is to not reject the null hypothesis.

I hope this helps!

Answer:

[tex]9\sqrt{15}*cis(\dfrac{19\pi}{24})[/tex]

Step-by-step explanation:

To multiplying complex numbers in polar form, follow these steps:

Given the two complex number in polar form

[tex]3\sqrt{3}\:cis(\dfrac{\pi}{8})\:\:and\:\:3\sqrt{5}\:cis(\dfrac{2\pi}{3})\\\\3\sqrt{3}\:cis(\dfrac{\pi}{8})*3\sqrt{5}\:cis(\dfrac{2\pi}{3})=(3\sqrt{3}*3\sqrt{5})*cis(\dfrac{\pi}{8}+\dfrac{2\pi}{3})[/tex]

[tex]=9\sqrt{15}*cis(\dfrac{3\pi+8*2\pi}{24})\\\\=9\sqrt{15}*cis(\dfrac{19\pi}{24})[/tex]

Answer: 34.86cis (2.49)

Step-by-step explanation: I took the quiz.

Answer: 90/8=11.25

Step-by-step explanation:

Answer:

The aquarium contains [tex]\frac{x}{2}[/tex] cubic inches of water

Step-by-step explanation:

Given: A local aquarium is filled halfway with water.

To find: Volume of water in the aquarium

Solution:

Volume refers to the three-dimensional space enclosed by a boundary. S.I. unit of volume is [tex]m^3[/tex]

Let x cubic inches denotes volume of an aquarium.

As a local aquarium is filled halfway with water,

the aquarium contains [tex]\frac{x}{2}[/tex] cubic inches of water.

Answer:

Step-by-step explanation:

Showing results for The aquarium contains cubic inches of waterStep-by-step explanation:Given: A local aquarium is filled halfway with water.To find: Volume of water in the aquarium Solution:Volume refers to the three-dimensional space enclosed by a boundary. S.I. unit of volume is Let x cubic inches denotes volume of an aquarium.As a local aquarium is filled halfway with water,the aquarium contains cubic inches of water.

Answer:

84 square inches

Step-by-step explanation:

First, separate this shape into two shapes you can easily find the area of. You can do this by turning it into a rectangle and a rhombus.

Say the rectangle has measurements of 5 by 6 inches. The area of that rectangle will be 30 square inches. Save this value to add on later.

The rhombus now has a height of 4 (because the side length 10 minus the side length 6 equals 4), and two bases by the values of 12 and 15. The area of a rhombus can be found with the equation:

a = 1/2(b1 + b2) x h

Simply plug in those values to find the area of the rhombus, 54. Now add the area of the rhombus and the area of the rectangle to get 84 square inches as your final area.

Answer:

As E is right angle , CD is hypotenuse , and ED is perpendicular and CE is the base .

Thus sinC = Perpendicular/ Hypotenuse

sinC = ED/CD

sinC = 3/5

The sine of an angle in a right triangle is the ratio of the side opposite to

the angle to the hypotenuse side.

Reasons:

The given parameters of ΔCDE are;

∠E = 90°, DC = 5, CE = 4, ED = 3

Required: The ratio that represents the sine of ∠C

Solution:

Given that ∠E = 90° therefore;

ΔCDE is a right triangle

DC = The hypotenuse side = 5

ED = 3 = The side opposite ∠C

[tex]sin\angle C = \mathbf{\dfrac{Opposite \ leg \ length}{Hypotenuse \ length}}[/tex]

Therefore;

[tex]\underline{sin\angle C \ is \ \dfrac{3}{5}}[/tex]

Learn more about trigonometric ratios here:

https://brainly.com/question/4232719

Answer:

The radius is 5 cm

Step-by-step explanation:

The formula for the area of a circle is :  [tex]\p*radius^2[/tex]

To work out the length of the radius you would first need to divide the area of  78.5 cm by pi (pi=3.14), this gives you [tex]25cm^2\\[/tex]. This is because by dividing the area by pi we are isolating the value of the radius squared.

The final step is to work out the radius. You can do this by finding the square root of the radius squared which is 25, this gives you 5 cm. This means that the radius is 5 cm. This is because the square root is a number that when squared equals that number.

1) Divide 78.5 by pi.

[tex]78.5/\pi=25cm^2[/tex]

2) Find the square root of 25 cm squared.

[tex]\sqrt{25} =5 cm[/tex]

In this question pi is 3.14

There are 7 rows of 9 people then there will be 63 people in all.

Multiplication refers to the product of two numbers or more than two numbers. It states the result when a number is taken times.

There are 7 rows of 9 people.

This means in each row, there are 9 people.

Then the number of people in 7 rows will be 7 multiplied by 9 i.e.,

[tex]7\times9=63[/tex]

So, the number of people will be 63.

Learn more about multiplication here- https://brainly.com/question/10590363

#SPJ2

Answer:

b means one of the sides of a square it doesn't matter because all sides are the same

Formula for a square is

b^2 or b*b

Answer:

  126 in^2

Step-by-step explanation:

The surface area can be found from the surface area formula:

  SA = 2(LW +LH +WH)

I like to rearrange it slightly to ...

  SA = 2(LW +H(L +W))

For the given dimensions, the area is ...

  SA = 2(6·3 + 5(6 +3)) = 2(18 +45) = 126 . . . . square inches

Answer:

y = [tex]-3x^2+12x-12[/tex]

Step-by-step explanation:

(x-2)^2 = (x-2)(x-2) => [tex]x^2-4x+4[/tex]

now, multiple every term by negative 3 and you get...

-3x^2+12x-12

Answer:

Answer is the first one :)

Step-by-step explanation:

√(-7-5)² + (-7-9)²

answer is 20

hope this helps

Answer:

A.

Step-by-step explanation:

In the attached file

Step-by-step explanation:

y4 - 2y3 = 0

y3(y - 2) = 0

y3 = 0

y = 0

Y - 2 = 0

Y = 2

Answer:

a= 14

b= 111

Step-by-step explanation:

just took it

Answer:

1.56% probability that the student gets all three questions right

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the student guesses the answer correctly, or he does not. The probability of the student guessing the answer of a question correctly is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Each question has 4 possible answers, one of which is correct.

So [tex]p = \frac{1}[4} = 0.25[/tex]

Three questions.

This means that [tex]n = 3[/tex]

What is the probability that the student gets all three questions right?

This is [tex]P(X = 3)[/tex]

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156[/tex]

1.56% probability that the student gets all three questions right

Answer:

(a) We conclude that there is a significant association between prenatal exposure to antidepressant medicine and the risk of autism at 5% significance level.

(b) Yes, we can conclude that prenatal exposure to antidepressant medicine increases the risk of autism in the child.

Step-by-step explanation:

We are given that Autism and Maternal Antidepressant Use A recent study 41 compared 298 children with Autism Spectrum Disorder to 1507 randomly selected control children without the disorder.

Of the children with autism, 20 of the mothers had used antidepressant drugs. Of the control children, 50 of the mothers had used the drugs.

Let [tex]p_1[/tex] = proportion of mothers who had used drugs having Autism Spectrum Disorder in their children.

[tex]p_2[/tex] = proportion of mothers who had used drugs not having Autism Spectrum Disorder in their children.

(a) Null Hypothesis, [tex]H_0[/tex] : [tex]p_1=p_2[/tex]      {means that there is no significant association between prenatal exposure to antidepressant medicine and the risk of autism}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1\neq p_2[/tex]     {means that there is a significant association between prenatal exposure to antidepressant medicine and the risk of autism}

The test statistics that would be used here Two-sample z test for proportions;

                         T.S. =  [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex]  ~ N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of mothers who had used drugs having Autism Spectrum Disorder in their children = [tex]\frac{20}{298}[/tex] = 0.067

[tex]\hat p_2[/tex] = sample proportion of mothers who had used drugs not having Autism Spectrum Disorder in their children = [tex]\frac{50}{1507}[/tex] = 0.033

[tex]n_1[/tex] = sample of children with Autism Spectrum Disorder = 298

[tex]n_2[/tex] = sample of children without Autism Spectrum Disorder = 1507

So, the test statistics  =  [tex]\frac{(0.067-0.033)-(0)}{\sqrt{\frac{0.067(1-0.067)}{298}+\frac{0.033(1-0.033)}{1507} } }[/tex]

                                       =  2.281

The value of z test statistics is 2.281.

Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is a significant association between prenatal exposure to antidepressant medicine and the risk of autism.

(b) Yes, we can conclude that prenatal exposure to antidepressant medicine increases the risk of autism in the child because if we reconsider our hypothesis for one-tailed test in which the null hypothesis states that the prenatal exposure to antidepressant medicine does not increases the risk of autism in the child.

For this hypothesis also, our test statistics will be more than the critical value of z and due to which we reject our null hypothesis and conclude that prenatal exposure to antidepressant medicine increases the risk of autism.

Answer:

The answer is ±0.5 or ±1/2

Step-by-step explanation:

When you solve by using the quadratic formula, you get double roots that will solve the equation. Hope this helps!!

The solution of the quadratic equation is 1/2 and 1/2.

We have to find, the solution of the quadratic equation is [tex]4x^2 + 3 = 4x + 2[/tex].

To determine the solution of the quadratic equation following all the steps given below.

Equation; [tex]4x^2 + 3 = 4x + 2[/tex]

        [tex]4x^2 + 3 = 4x + 2\\\\4x^2 + 3 - 4x - 2=0\\\\4x^2 -4x +1 =0[/tex]

                    [tex]\rm 4x^2-4x +1 = 0\\\\4x^2-2x -2x + 1= 0\\\\2x(2x-1) - 1 (2x-1)=0\\\\(2x-1) ( 2x-1) = 0[/tex]

                    [tex]\rm 2x- 1= 0 , \ 2x = 1 , \ x = \dfrac{1}{2}\\\\And \ 2x- 1= 0 , \ 2x = 1 , \ x = \dfrac{1}{2}\\\\[/tex]

Hence, The required solution of the equation is 1/2 and 1/2.

For more details refer to the link given below.

https://brainly.com/question/19776811

Answer:

It is C

Step-by-step explanation:

You have to make a subject to research before your make a question, because you dont know what your looking for then.

I know i might be late but can i have brainliest if its correct so i can level up?

Thank you!

Answer:

cthe therd one

Step-by-step explanation:

you need a subject to research before you make a question,

so you can also begon with your work like assimgments.

Step-by-step explanation:

here,

6x+6x = -35-12

12x= -47

x= -47

[tex] \frac{ - 47}{12} [/tex]

Answer:

[tex]t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236[/tex]    

Now we can find the degrees of freedom:

[tex]df=n-1=80-1=79[/tex]  

Now we can calculate the p value with the alternative hypothesis using the following probability:

[tex]p_v =P(t_{(79)}>2.236)=0.0141[/tex]  

Using a significance level of 0.01 or 1% we have enough evidence to FAIL to reject the null hypothesis and we can conclude that shoppers participating in the loyalty program NOT spent more on average than typical shopper at this significance level assumed

Step-by-step explanation:

Information given

[tex]\bar X=130[/tex] represent the sample mean

[tex]s=40[/tex] represent the sample standard deviation

[tex]n=80[/tex] sample size  

[tex]\mu_o =120[/tex] represent the value to verify

t would represent the statistic  

[tex]p_v[/tex] represent the p value

System of hypothesis

We want to verify if  shoppers participating in the loyalty program spent more on average than typical shoppers (120) , the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 120[/tex]  

Alternative hypothesis:[tex]\mu > 120[/tex]  

The statistic for this case is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

Replacing the info given we got:

[tex]t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236[/tex]    

Now we can find the degrees of freedom:

[tex]df=n-1=80-1=79[/tex]  

Now we can calculate the p value with the alternative hypothesis using the following probability:

[tex]p_v =P(t_{(79)}>2.236)=0.0141[/tex]  

Using a significance level of 0.01 or 1% we have enough evidence to FAIL to reject the null hypothesis and we can conclude that shoppers participating in the loyalty program NOT spent more on average than typical shopper at this significance level assumed