It’s not really that hard but I am just busy so please do this for me.

Its Not Really That Hard But I Am Just Busy So Please Do This For Me.
Its Not Really That Hard But I Am Just Busy So Please Do This For Me.

Answers

Answer 1

The Surface area are shown below.

What is Surface Area?

The total area of an object's external facing surfaces is its surface area. The base, top, and lateral surfaces (sides) of the object's surface are added together to get the object's overall surface area.

1. The measure of sides are

A = 3

B = 15

C= 17

D= 8

So, the Lateral Surface Area

= ( 15+17+8) x 3

= 117 mm²

and, the total surface Area

= Area of two triangles + Area of rectangle

= 2 x 1/2 x 8 x 15 + 117

= 120 + 117

= 237 mm²

2. The measure of sides are

A = 5

B = 2

C= 9

D= 2

So, the Lateral Surface Area

= 2 x (5 x 9) + 2 (2 x 5)

= 110 m²

and, the total surface Area

= 110 + 2 (2 x 9)

= 146 m²

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Related Questions

TRUE/FALSE. if january has 31 days, then 7 is an even number.

Answers

Answer: False

Step-by-step explanation:

7 is not an even number, and it never will be.

Even though january has 31 days, 7 is an odd number.

False. 7 is an odd number. This is because an even number is a number which can be divided by 2 without a remainder. 7 cannot be divided by 2 without a remainder, so it is an odd number.

To calculate this, we can use the remainder operator. This operator is represented by the percentage sign (%). When using this operator, the result is the remainder of a division operation. For example, if we divide 7 by 2, the result is 3 with a remainder of 1. If we write this as an equation, it will be 7 % 2 = 1. This means that 7 is not evenly divisible by 2, and is thus an odd number.

Therefore, even though january has 31 days, 7 is an odd number.

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Exponential Functions

Answers

In the exponential function y = 3 × q⁵ the starting value is 3.

What is an exponential function?

The formula for an exponential function is f(x) = aˣ, where x is a variable and a is a constant that serves as the function's base and must be bigger than 0.

Given is an exponential function is -

y = 3 × q⁵

The exponential function is written in the form abˣ.

Here, a is considered to be the initial value, b is considered to be the base and x represents the growth factor.

So, the initial or starting value in function y = 3 × q⁵ is -

a = 3

Hence, the starting value is 3.

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Office Bargains sells 150 pens for $7.50. What is the price per pen? $ per pen

Answers

Answer:

5 cents each

Step-by-step explanation:

to find out how much each pen costs, you would divide the total price(7.50) by the number of pens(150) to get to the price for each pen ($0.05)

Answer:

To find this, you just want to divide 7.50 by 150.

Take note that since were looking for how much each individual pen costs, 7.50 with come first in the equation, as shown:

7.50/150 = 0.05

Each Pen Costs 5 cents each!

Step-by-step explanation:

Hope it helps! =D

a shoe sells 200 pairs at $60. for each $1 increase, sales decrease by 2. determine maximum (vertex) PLS HELP I NEED THE ANSWERRRR WILL MARK BRAINLIEST

Answers

Answer: The maximum number of pairs of shoes sold occurs at a price of $30 and the vertex of the parabolic equation is (30, 200).

Explanation: The equation for the number of pairs of shoes sold as a function of price is given by:

y = 200 - 2x

where x is the price in dollars and y is the number of pairs sold. The maximum (vertex) can be found by taking the derivative of the function and setting it equal to zero:

dy/dx = -2

0 = -2

x = 60/2 = 30

So the maximum number of pairs of shoes sold occurs at a price of $30 and the vertex of the parabolic equation is (30, 200).

g-filling machines at jelly belly. the variance in a production process is an important measure of the quality of the process. a large variance often signals an opportunity for improvement in the process by finding ways to reduce the process variance. jelly belly candy company is testing two machines that use different technologies to fill three pound bags of jelly beans. the file bags contains a sample of data on the weights of bags (in pounds) filled by each machine. conduct a statistical test to determine whether there is a significant difference between the variances in the bag weights for two machines. use a .05 level of significance. what is your conclusion? which machine, if either, provides the greater opportunity for quality improvements?

Answers

There is sufficient evidence to support the claim of a greater variance for machine 1

Given two data sets, n1=25 and n2=22, their means are calculated as x1=3.3284 and x2=3.2782 respectively. The variance for each data set is calculated as s1=0.2211 and s2=0.0768 respectively.

The null hypothesis is that the variance of data set 1 (s1) is less than or equal to the variance of data set 2 (s2), while the alternative hypothesis is that the variance of data set 1 is greater than the variance of data set 2.

The test statistic F is calculated as the ratio of the variance of data set 1 squared to the variance of data set 2 squared, resulting in a value of 8.288.

The P-value is calculated as the probability of obtaining the value of the test statistic, or a more extreme value, which is less than 0.01.

Therefore, based on the significance level, the null hypothesis is rejected and the alternative hypothesis is accepted.
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There is sufficient evidence to support the claim of a greater variance for machine 1

Given two data sets, n1=25 and n2=22, their means are calculated as x1=3.3284 and x2=3.2782 respectively. The variance for each data set is calculated as s1=0.2211 and s2=0.0768 respectively.

The null hypothesis is that the variance of data set 1 (s1) is less than or equal to the variance of data set 2 (s2), while the alternative hypothesis is that the variance of data set 1 is greater than the variance of data set 2.

The test statistic F is calculated as the ratio of the variance of data set 1 squared to the variance of data set 2 squared, resulting in a value of 8.288.

The P-value is calculated as the probability of obtaining the value of the test statistic, or a more extreme value, which is less than 0.01.

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The Los Angeles Times regularly reports the air quality index for various areas of Southern California. A sample of air quality index values for Pomona provided the following data: , , , , , , , , and. A. Compute the range and interquartile range. Range Interquartile range b. Compute the sample mean, sample variance, and sample standard deviation (to 2 decimals). Sample mean Sample variance Sample standard deviation c. A sample of air quality index readings for Anaheim provided a sample mean of , a sample variance of , and a sample standard deviation of. What comparisons can you make between the air quality in Pomona and that in Anaheim on the basis of these descriptive statistics

Answers

The values mean, variance and standard deviation for Pomona and Anaheim are compared to identify the deviation in the air quality level.

The air quality index values for various area of southern California. Here the random variable (X) represents the air quality index values for Pomona.

From the given information the data values are 28, 42, 58, 48, 45, 55, 60, 49 and 50

Range = max. value - min.value

           = 60 - 28 = 32

mean for air quality index for Pomona = x'

                                            = sum of the values/total no.of samples

                                            = (∑Xi )/ (n)

                                            = 435/9 = 48.33

sample variance , ∑(Xi - x')/ n-1 = 92.75

standard deviation is the sq.root of variance , i.e √92.75

                                            = 11.66

Use mean 48.3, variance 136 and standard deviation 11.66 to compare with the air quality in Pomona and Anaheim.

The air quality index reading for Pomona mean is equal to Anaheim. That is, The Pomona mean (48.3) is equal to the Anaheim mean (48.3).

The variance and sample standard deviation for Anaheim are 136 and 11.66, respectively.

The variance and sample standard deviation for Pomona are 92.75 and 9.63, respectively.

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what is the percent change of the data set? if your answer

Answers

The percent change of the data set is 10%.

Percentage change is a way to describe the difference between an old value and a new value, expressed as a ratio and then multiplied by 100.

If the price of a product was $5 last month and it increased to $5.50 this month, we can calculate the percentage change as

=> (5.50 - 5) / 5 x 100 = 10%.

This means that the price of the product has increased by 10% compared to last month. If the price had gone down, we would have a negative percentage change.

Percentage change is a useful tool to compare data sets, especially when dealing with large numbers.

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Find the volume of the cylinder shown. Use 3.14
3.14
for pi. Round your answer to the nearest tenth.

Answers

1021.02 is the correct volume

Let y (x) be the solution of the differential equation xlogxdydx+y=2xlogx
, x≥1
. Then y (e) is equal to,
(a). e
(b). 0
(c).2
(d). 2e

Answers

y = 2 is the solution of  differential equation .

What exactly does differential equation mean?

An equation that connects one or more unknown functions and their derivatives is known as a differential equation in mathematics.

                               Applications typically use functions to describe physical quantities, derivatives to indicate the rates at which those quantities change, and differential equations to define a relationship between the two.

( x logx )dy/dx + y = 2xlogx

dividing by xlogx, we get

  dy/dx + y/xlogx  = 2

   d(IF × Y ) = 2logx dx

  IF  =  e∫1/xlogx dx

        = [tex]e^{log(logx)} = logx[/tex]

rightarrow Multiplying by IF, we get

      d(IF * Y ) = 2logx dx

   By integrating, we get

y logx = ∫2 logx dx

 By using Product Rule on RHS, we get

   ylogx = 2[logx ∫ 1 - ∫((∫1) d/dx(logx)) dx

  ylogx =  2[x(logx - 1 )] + c

  Put x = 1, we get

   0 = 2[1(0 - 1 )] + c

    c = 2

ylogx = 2[x[logx - 1 )] + 2

  at x = e

 y = 2

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find the horizontal and vertical asymptotes of the curve. y = 3ex ex − 5

Answers

The graph of y = 3ex ex − 5 has a horizontal asymptote of y = 3 and a vertical asymptote of x = -3/5.

The equation y = 3ex ex − 5 can be rewritten as y = 3x2ex − 5. In order to find the horizontal and vertical asymptotes of this function, we must first find its degree of the numerator and denominator. The numerator is a second degree polynomial while the denominator is a first degree polynomial.

The horizontal asymptote will be the line y = b/a, where b and a are the coefficients of the highest degree terms in the numerator and denominator, respectively. In this case, b = 3 and a = 1, so the horizontal asymptote is y = 3.

The vertical asymptote of a function is the line x = a/b, where a and b are the coefficients of the highest degree terms in the numerator and denominator, respectively. In this case, a = 3 and b = -5, so the vertical asymptote is x = -3/5.

Therefore, the graph of y = 3ex ex − 5 has a horizontal asymptote of y = 3 and a vertical asymptote of x = -3/5.

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PLEASE HELP ASAPP!!!

Answers

The value of investment at maturity is $15094.

what is compound interest?

Interest that is added to a loan or deposit sum is known as compound interest. In our daily lives, it is the notion that is employed the most frequently. Compound interest is calculated for a sum using the principal and interest accrued over time. Compound interest and simple interest differ primarily in this way.

a=9000

r= 0.09

t=6

y=a(1+r)ᵗ

=> y=9000(1+0.09)⁶

=> y= 9000(1.09)⁶

=> y= 15093.900

Rounded to whole number : $15094

The value of investment at maturity is $15094

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Using the Law of Sines to solve the triangle if ∠ A = 43 ∘ , ∠ C = 75 ∘ , b = 15 : ∠ B is degrees; a = ; c = ; Round to two decimal places if needed. Assume ∠ A is opposite side a , ∠ B is opposite side b , and ∠ C is opposite side c .

Answers

The values using Law of Sines are:

∠ B = 62∘; b = 11.58 and c = 16.40.

Explain the Law of Sines?

The relationship between a triangle's sides and angles is demonstrated using the sine rule. It is specified as:

A/Sin(A) = B/Sin(B) = C/Sin(C)

Where A, B, and C are indeed the angles and A, B, and C are the angles' opposing sides.

∠ A = 43 ∘ , ∠ C = 75 ∘ , b = 15 ;

Part a:

∠ B = 180 -  ∠ A  -  ∠ C

∠ B = 180 - 43 ∘  - 75∘

∠ B = 62∘

Part b: the value of a.

a/Sin(A) = b/Sin(B)

a =  b/Sin(B) * Sin(A)

a = 15/Sin(62) * Sin(43)

b = 11.58

Part c: the value of c

b/Sin(B) = c/Sin(C)

c = b/Sin(B) * Sin(C)

c = 15/Sin(62) * Sin(75)

c = 16.40

Thus, the values using Law of Sines are obtained.

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A math test has 40 questions. A student answers 85% of the questions correctly. How many questions did the student answer correctly? Enter your answer in the box. questions

Answers

34 questions was answered correctly by the student, while 6 questions were incorrect

What is an equation?

An equation is an expression showing the relationship between two or more numbers and variables. An equation can either be linear, quadratic, cubic and so on depending on the degree.

A math test has 40 questions. A student answers 85% of the questions correctly.

Number of questions answered correctly = 85% of total questions = 0.85 * 40 questions = 34 questions

Number of questions not answered correctly = 40 - 34 = 6 questions

34 questions was answered correctly by the student.

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Baldwin drew a cale drawing of an apartment. In real life, a rug by the door i 4 feet long. It i 5 inche long in the drawing. What i the cale factor of the drawing?

Answers

The scale factor is 1/5 inch per foot.

Apartment Rug Scale Factor

The scale factor of the drawing can be found by dividing the length of the rug in real life by the length of the rug in the drawing.

4 feet / (5 inches/12 inches/foot) = 4 * 12 / 5 = 9.6 inches

So the scale factor is 9.6 inches / 4 feet = 1/5 inch per foot.

The method used to find the scale factor is applicable to any drawing or model where the size of an object is known in both the real-life version and the drawing or model. As long as the ratio of the size of the object in the real-life version to the size of the object in the drawing or model is constant, the scale factor can be found using the same method.

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Let f be the function defined by f(x) = Inx/x. What is the absolute maximum value of f?(A) 1(B) 1/e(C) 0(D) -e(E) f does not have an absolute maximum value

Answers

The absolute maximum value of f is 1.

The function f(x) is defined as the natural logarithm of x (lnx) divided by x. This function is undefined when x is equal to 0, but for positive x values, the maximum value of f(x) is 1. To prove this, we need to take the derivative of f(x) and set it equal to 0. We can calculate the derivative of f(x) by using the quotient rule.

The quotient rule states that for two functions u(x) and v(x), the derivative of their quotient can be calculated by taking the derivative of u(x) times v(x) minus the derivative of v(x) times u(x), all divided by v(x)2. After taking the derivative of f(x) = lnx/x, we get f'(x) = (1/x) – (lnx/x2).

Now we set f'(x) = 0 and solve for x. This gives us x = 1, so when x = 1, we get the maximum value of f(x) = ln1/1 = 1. Therefore, the absolute maximum value of f is 1.

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what conic section is described by the equation 4x2 3xy 5y2 x y = 0?

Answers

An ellipse is described by this equation. It is a conic section because it has two variables, x and y, that are squared and multiplied together. The conic's shape is fixed because the equation also contains a constant.

An ellipse is described by this equation. It is a conic section because it has two variables, x and y, that are squared and multiplied together. A constant in the equation, 4x2 + 3xy + 5y2 - x - y = 0, shows that the conic's shape is fixed.  The equation is neither a parabola nor a hyperbola because it lacks any x or y terms. The equation therefore describes an ellipse. An oval-shaped closed curve known as an ellipse is produced when a plane and a cone intersect. The foci, or the two places at which the ellipse is symmetric, serve as its two defining points. The standard form of an ellipse, which is centred at the origin and contains the equation A(x2) + B(xy) + C(y2) + D(x) + E(y) + F = 0, is described by the equation provided. In this case, the constants are A=4, B=3, C=5, D=1, and E=1, and F=0. The major axis to minor axis ratio in the equation is 4:5, describing a moderately flattened ellipse. The equation can be used to determine the ellipse's area, circumference, and other parameters because it is symmetrical.

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Tony rounded each of the numbers and to the nearest hundred. Which choice correctly compares the rounded numbers?.

Answers

To the nearest hundred, Tony rounded the figures 1183 and 1145.

What is meant by place values?

Our entire number system is built on place value. In this system, a digit's position within a number affects its value. The placements of the digits make the numbers 42,316 and 61,432 distinct from one another.

Place value is the value that a digit in a number represents based on where it appears in the number.

In order to round the number to the nearest hundred, look at the digit after the tens place.

In the hundreds place, we add one if the number in the tens place is greater than or equal to 5.

We replace the remaining digits with 0 if the number in the tens place is less than 5.

1200 is the result of rounding 1183 to the nearest tenth (8 in this case).

1145 is rounded to 1100 because there are four tens places in it.

The complete question is;

Tony rounded each of the numbers 1183 and 1145 to the nearest hundred. Which choice correctly compares the rounded numbers

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Let R be the region bounded by the parabola y=x^2 and the line y=4
(a) What is the volume of the solid generated when R is rotated about the line y=4 ?
V=
(b) What is the volume of the solid generated when R is rotated about the line y=5 ?
V=

Answers

So, when R is rotated along the line y = 4, the volume of the solid formed is roughly 12.57 cubic units. So, when R is rotated about the line y = 5, the volume of the solid formed is roughly 81.34 cubic units.

What is volume?

Every three-dimensional item requires some amount of space. The volume of this space is measured. Volume is defined as the space occupied by an item inside the confines of three-dimensional space. It is also known as the object's capacity.

Here,

The volume of the solid generated when R is rotated about the line y = 4 is given by the formula:

V = π * ∫[a,b] (x² - 4)² dx

where a and b are the x-coordinates of the points where the parabola y = x² intersects the line y = 4. To find these points, we set y = x² and y = 4 and solve for x:

x²= 4

x = ±2

So the points of intersection are (2, 4) and (-2, 4). The region R is the part of the parabola between these points, so a = -2 and b = 2.

Substituting these values into the formula for V, we have:

V = π * ∫[-2,2] (x² - 4)² dx

Evaluating the definite integral, we obtain:

V = π * [x⁵/5 - 4x³/3 + 16x] evaluated from -2 to 2

= π * (16/5 - 16/3 + 16 - (-16/5 + 16/3 - 16))

= π * (32/5)

= 12.57 ≈ 12.57 (rounded to 4 decimal places)

For the volume of the solid generated when R is rotated about the line y = 5, we can use the same formula:

V = π * ∫[a,b] (x² - 5)² dx

where a and b are the x-coordinates of the points where the parabola y = x² intersects the line y = 5. These can be found in the same way as before:

x² = 5

x = ±√5

So the points of intersection are (√5, 5) and (-√5, 5). The region R is the part of the parabola between these points, so a = -√5 and b = √5.

Substituting these values into the formula for V, we have:

V = π * ∫[-√5,√5] (x² - 5)² dx

Evaluating the definite integral, we obtain:

V = π * [x⁵/5 - 5x³/3 + 25x] evaluated from -√5 to √5

= π * (25/5 - 25/3 + 25√5/2 - (-25/5 + 25/3 - 25√5/2))

= π * (50/3 + 25√5)

= 50.97 + 25√5 ≈ 50.97 + 25 * 2.236 = 81.34 (rounded to 2 decimal places)

So the volume of the solid generated when R is rotated about the line y = 4 is approximately 12.57 cubic units. So the volume of the solid generated when R is rotated about the line y = 5 is approximately 81.34 cubic units.

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a particle is moving along the x-axis with position function x ( t ) = t 3 − 5 t 2 3 t 2 for t ≥ 0 . over which of the following time intervals is the particle speeding up?

Answers

The particle is speeding up over the time interval (10/6, ∞).

The particle is speeding up when its acceleration is positive, which occurs when its second derivative is greater than 0. The second derivative of x (t) is 6t - 10, so the particle is speeding up when t > 10/6. Therefore, the particle is speeding up over the time interval (10/6, ∞).

To calculate this, we take the second derivative of x (t):

x''(t) = 6t - 10

We then set this equal to 0 and solve for t

6t - 10 = 0

t = 10/6

Therefore, the particle is speeding up over the time interval (10/6, ∞).

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if jacques sells 32,000 baskets at the highest price consumers are willing to pay according to the demand curve, his average revenue will be $ per basket.

Answers

Jacques' average revenue per basket is $ per basket.

Average revenue (AR) is calculated by dividing total revenue (TR) by total quantity sold (Q).

Therefore, AR = TR/Q

Given that Jacques sells 32,000 baskets and the highest price consumers are willing to pay according to the demand curve, his total revenue (TR) is unknown.

However, we can calculate his average revenue (AR) by dividing his total revenue (TR) by the quantity sold (Q).

AR = TR/32,000

Therefore, Jacques' average revenue per basket is $ per basket.

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Complete question:How much average revenue will Jacques make if he sells 32,000 baskets at the highest price consumers are willing to pay according to the demand curve?

item 9 una makes $64 a week, plus 15 percent of the cost of meals that she serves. use the equation y = 0.15x 64 to predict what she makes in a week when she serves $355 worth of meals.

Answers

The amount of money una earns in a week she serves $355 worth of meals including her base earnings is $177.25

How to solve equation?

Amount una makes in a week= $64

Additional amount una earn = 15% of x

Cost of meal she serves = x

Total amount she makes= y

y = 0.15x + 64

If she serves $355 worth of meals.

y = 0.15x + 64

y = 0.15(355) + 64

= 53.25 + 64

y = $177.25

In conclusion, una makes a total of $177.25 in a week.

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In the three topics we have discussed: circle, ellipse, and parabola, choose one of them. Look around your place and look for something that relates to the topic you have chosen. You may draw or capture it and put it on a short size of bond paper. Write 3-5 sentences that serve as your explanation. Make sure your output is creative and the text or words are readable. PLEASE ANSER

Answers

An element around me that has one of the aforementioned shapes is a ball.

What geometric shapes are around us?

One of the geometric shapes around me is a basketball. This has a completely spherical shape that from any perspective looks circular.

This ball is orange in color and due to its circular or sphere shape it can roll on the floor. Additionally, this ball has the property of deforming when it hits the ground and bounces.

Additionally, with this ball we can make parabolic shots to score it on a basketball court.

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What are the types of Discontinuities?

Answers

Three different types of discontinuity exist.

Discontinuous Jump.Continuous Infinity.Displacing Discontinuity.

What is Discontinuities?Discontinuous functions are those parts of the graph that are not connected to one another. If both the left-hand limit and the right-hand limit of a function f(x) exist but are not equal, the function is said to have a first-kind discontinuity at x = a.You need to be familiar with the four different sorts of discontinuities: essential, removable, jump, and point. Factoring the function's numerator and denominator first. When a number is zero in both the numerator and denominator, this is known as a point of discontinuity. There is a point of discontinuity there there is a zero for the numerator and denominator.

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Julia had a bag filled with gumballs. There were 1 watermelon, 2 lemon-lime, and 3 grape gumballs. What is the correct sample space for the gumballs in her bag?

Sample space = watermelon, lemon-lime, lemon-lime, grape, grape, grape
Sample space = lemon-lime, watermelon, grape
Sample space = 1, 2, 3, 4, 5, 6
Sample space = 1, 2, 3

Answers

Option A. is the correct answer.

Sample space = watermelon, lemon-lime, lemon-lime, grape, grape, grape.

What is a sample space?

A sample space is a set of potential results from a random experiment. The letter "S" is used to denote the sample space. Events are the subset of possible experiment results. Depending on the experiment, a sample area could contain a variety of results.

here, we have,

Given that, Julia had a bag filled with gumballs. There were 1 watermelon, 2 lemon-lime, and 3 grape gumballs.

now,

Sample space contains,

2 lemon-lime: Elements in sample space are lemon-lime, lemon-lime,

1 watermelon: Elements in sample space are watermelon,

3 grape: Elements in sample space are grape, grape, grape,

In total there are 13 elements in sample space.

Therefore, option A . is the correct answer.

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Answer:

Step-by-step explanation:

Option A. is the correct answer.

Sample space = watermelon, lemon-lime, lemon-lime, grape, grape, grape.

in Mrs. Washington's class, there are 2 students in band for every
3 students in chorus. In Mr. Utley's class there are 5 students in band for every 7 students in chorus. Complete the ratio tables. Which class has a greater ratio of students in band to students in chorus?

Answers

Answer:

Here are the completed ratio tables for both classes:

Mrs. Washington's class:

Band: 2

Chorus: 3

Total: 2 + 3 = 5

Band-to-Chorus ratio: 2 : 3

Mr. Utley's class:

Band: 5

Chorus: 7

Total: 5 + 7 = 12

Band-to-Chorus ratio: 5 : 7

Based on the ratios, it appears that Mr. Utley's class has a greater ratio of students in band to students in chorus. The ratio in Mr. Utley's class is 5 : 7, while the ratio in Mrs. Washington's class is 2 : 3.

Step-by-step explanation:

Step-by-step explanation:

radius are a special form of fractions. but they are fractions, and a such all rules of calculation and comparison apply.

mrs. Washington's class has a ratio of 2/3 (or 2:3 or 2÷3).

2/3 = 0.666666666...

mrs. utley's class has a ratio of 5/7.

5/7 = 0.714285714...

so, the class of mrs. Utley had a greater ratio.

to compare the ratios (like any fraction) within calculating their decimal value, we need to bring them to the same denominator :

.../3 and .../7

we need to bring both to .../21 :

2/3 × 7/7 = 14/21

5/7 × 3/3 = 15/21

so, we can clearly see that the ratio of mrs. Utley's class is greater, as 15 is greater than 14.


These tiles represent the expression 2x + x + 6.
&
XX
3x + 6
X
Which expression is equivalent to 2x + x + 6?
Submit
1
1
2x + 8
8x
or
Watch a video
8x + 1
You have

Answers

16y6/x2 is the corresponding formula.The necessary equivalent expression is therefore 16y6/x2.

An expression is defined?

Expressions in mathematics are made up of variables combined with the use of operations and predetermined rules. An equation, some numbers, etc., could be used as examples.

Expressions in mathematics are made up of variables combined with the use of operations and predetermined rules.

Expressions in mathematics are made up of variables combined with the use of operations and predetermined rules. An equation, some numbers, etc., could be used as examples.

There is a phrase that says,

{4xy³/x²}²

Expressed more succinctly,

{4xy³/x²}²

= {4y³/x}²

= 16y⁶/x².

The necessary equivalent expression is therefore 16y6/x2.

The complete question is,

Which of the following expressions is the same as the one given?

(4xy^3/x^2)

^2

A. 16y^6 \sB. 16y

5 x 2, 16 x 2, 5 y, and 16 y.

^6/x^2

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Evaluate the integral. (Use C for the constant of integration.) ∫15sin3(x)cos2(x)dx∫15sin3⁡(x)cos2⁡(x)dx

Answers

The result of the original integral is:

∫15sin3(x)cos2(x)dx = (15/2)(cos(3x + 2x) + cos(3x - 2x)) + 2C

What is the integration?

In mathematics, an integral assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinitesimal data.

The integral of the product of sine and cosine functions can be evaluated using the identity:

sin(a)cos(b) = (1/2)(sin(a + b) + sin(a - b))

Therefore, we can rewrite the integrand as:

15sin3(x)cos2(x) = (15/2)sin(3x + 2x) + (15/2)sin(3x - 2x)

Now, we can integrate each of the two terms separately:

∫(15/2)sin(3x + 2x)dx = (15/2)cos(3x + 2x) + C

∫(15/2)sin(3x - 2x)dx = (15/2)cos(3x - 2x) + C

Therefore, the result of the original integral is:

∫15sin3(x)cos2(x)dx = (15/2)(cos(3x + 2x) + cos(3x - 2x)) + 2C

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Determine the intervals where the function f(x) = e^(x) Cos(x) (0 less than or equal to X less than equal to 2Pi) is increasing and where it is decreasing ?

Answers

If the function is f(x) = eˣ Cos(x) where (0≤ x ≤2π) , then the function will be increasing in interval (0, π/4) U (7π/4, 2π), and decreasing in interval (π/4, 7π/4) .

In order to find the intervals where function f(x) = eˣ Cos(x) is increasing and where it is decreasing, we find the points where the derivative of the function, f'(x), is positive and negative,

The derivative of function : f(x) = eˣ cos(x) is:

⇒ f'(x) = eˣ cos(x) + eˣ (-sin(x))

⇒ eˣ (cos(x) - sin(x))

So , To find the intervals where f'(x) is positive or negative, we can use the sign of the derivative to determine if the function is increasing or decreasing.

we  know that ;

⇒ When f'(x) > 0, the function is increasing.

⇒ When f'(x) < 0, the function is decreasing.

For function  " eˣ (cos(x) - sin(x)) " ,

we can see that f'(x) is positive when cos(x) > sin(x) and negative when cos(x) < sin(x).

By using a unit circle, we can see that the inequality cos(x) > sin(x) is satisfied for x in the interval (0, π/4) U (7π/4, 2π), and

the inequality cos(x) < sin(x) is satisfied for x in the interval (π/4, 7π/4) .

The given question is incomplete , the complete question is

Determine the intervals where the function f(x) = eˣ Cos(x) where (0≤ x ≤2π) is increasing and where it is decreasing ?

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6. Work The dollar amount d that Julia earns varies directly as the number of hours !

that she works, and d=$116. 25 when 1 = 15 h. Find t when d = $178. 25.

Answers

Work the dollar amount d that Julia earns varies directly as the number of hours is 23 hours is the solution.

What is the time t?

According to the information provided, Julia's earnings correspond closely to the amount of hours she puts in at work.

Also, at t = 15 h, d equals $116.25.

The direct variation's formula is d = kt.

where k is the variational constant.

Find k and replace the known values:

116.25 = k * 15

k = 116.25/15 k = 7.75

Find t now that d is equal to 178.25. In the direct variation equation, swap out d and k, then figure out t:

23 hours are equal to 178.25 = 7.75t t.

t = 23 hours is the solution.

Work the dollar amount d that Julia earns varies directly as the number of hours is 23 hours is the solution.

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Sketch the graph of y = |x + 3| and evaluate the area under the curve y = |x + 3| above x - axis and between x = - 6 to x = 0 .

Answers

The area under the curve y = |x + 3| above the x-axis and between x = -6 and x = 0 is 9 units^2.

What is the area under the curve?

The area under a curve refers to the area between a curve and the -axis. This area could be entirely above the -axis, entirely below the -axis, or a combination of above and below the -axis. In calculus, the area under a curve is a visual representation of an integral.

The graph of y = |x + 3| is a piecewise linear function that starts at (3,0), increases linearly as x decreases to -3, reaches a maximum value of 3 at x = -3, and then decreases linearly as x decreases further to -6. The area under the curve y = |x + 3| above the x-axis and between x = -6 and x = 0 can be calculated by finding the area of two triangular regions. One triangular region is formed by the line y = x + 3 from x = -6 to x = -3 and the x-axis, and the other triangular region is formed by the line y = -(x + 3) from x = -3 to x = 0 and the x-axis. The area of each triangular region can be calculated using the formula 1/2 * base * height, and the total area is the sum of the areas of the two triangular regions.

So, The area under the curve y = |x + 3| above the x-axis and between x = -6 and x = 0 is 9 units^2.

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