it is estimated that 50% of emails are spam emails. Some software has been applied to filter these spam emails before they reach your inbox. A certain brand of software claims that it can detect 99% of spam emails and the probability for a flase positive is 5%. What is the probability that an email is detected as spam

Answer:

c

Step-by-step explanation:

Answer:

[tex]\frac{p-2l}{2}[/tex]

Step-by-step explanation:

move the 2l to the other side by subtracting 2l on both sides. you get P - 2l = 2w. now divide both sides by 2 to get the answer.

Answer: false

Step-by-step explanation:

Surface Area Formula Surface Area Meaning

SA=2B+Ph Find the area of each face. Add up all areas.

SA=B+12sP Find the area of each face. Add up all areas.

SA=2B+2πrh Find the area of the base, times 2, then add the areas to the areas of the rectangle, which is the circumference times the height.

9514 1404 393

Answer:

  x = 30 2/3

Step-by-step explanation:

Angles 4 and 5 are complementary, so we have ...

  m∠4 +m∠5 = 90°

  (2x +4) +(x -6) = 90

  3x -2 = 90 . . . . . . . . . collect terms

  3x = 92 . . . . . . . . . . add 2; next, divide by 3

  x = 92/3 = 30 2/3

Answer:

y= (-6/5)x+3

Step-by-step explanation:

6x+5y=15

Divide everything by 5

(6/5)x + y = 3

Move (6/5)x to the other side of the = sign by subtracting

y= (-6/5)x + 3

That's your answer!

Hope it helps!

Answer:

Im going to guess the second one

Step-by-step explanation:

It's the only one that does not have more than one negative fraction.

Answer:

0.1587

Step-by-step explanation:

Applying,

P(μ>40) = P(μ-(x-μ)/σ)............. Equation 1

Where P(μ>40) =  probability of the age of the random subscriber more than 40 years   μ = mean, σ = standard deviation, x = random subscriber

From the question,

Given: μ = 35 years, σ = 5 years, x = 40 years.

Therefore,

P(μ>40) = P(35-(40-35)/5) = P(35-(5/5)

P(μ>40) = 1-φ(1)

From the norminal probabilty table,

P(μ>40) = 1-0.8413

P(μ>40) = 0.1587

Answer:

162 t-shirts, 324 posters

Step-by-step explanation:

Assuming they only sold t-shirts and posters, you can find the amount of t-shirts sold by dividing 486 by 3, or multiplying it by 1/3. This equals 162. This is because one third were t-shirts. To find the rest you just subtract 162 from the total of 486, or multiply 162 by 2. (since you already know the amount of 1/3, 2/3 is double that.)

Answer:

[tex]\displaystyle y' = 20x^3 + 6x^2 + 70x + 9[/tex]

General Formulas and Concepts:

Pre-Algebra

Algebra I

Calculus

Derivatives

Derivative Notation

Derivative Property [Multiplied Constant]:                                                              [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                            [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

Derivative Rule [Product Rule]:                                                                                [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle y = (x^3 + 7x - 1)(5x + 2)[/tex]

Step 2: Differentiate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

Answer:

The standard error of the distribution of sample proportions is of 0.014.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Consider random samples of size 1200 from a population with proportion 0.65 .

This means that [tex]n = 1200, p = 0.65[/tex]

Find the standard error of the distribution of sample proportions.

This is s. So

[tex]s = \sqrt{\frac{0.65*0.35}{1200}} = 0.014[/tex]

The standard error of the distribution of sample proportions is of 0.014.

Answer:

24/145

Step-by-step explanation:

Trigonometric identities are equalities involving trigonometric functions and remains true for entire values of the variables involved in the equation.

Some trigonometric identities are:

sin(a + b) = sinacosb + cosasinb; sin(a - b) = sinacosb - cosasinb

cos(a + b) = cosacosb - sinasinb; cos(a - b) = cosacosb + sinasinb

Given that sin a = 3/5. sin a = opposite/hypotenuse.

Hence opposite = 3, hypotenuse = 5. using Pythagoras:

hypotenuse² = opposite² + adjacent²

5² = 3² + adjacent²

adjacent² = 16

adjacent = 4

Given that sin a = 3/5. a = sin⁻¹(3/5) = 36.86

cos a = cos 36.86 = 4/5

cos b = -20/29; b = cos⁻¹(-20/29) = 133.6

sinb = sin(133.6) = 21/29

sin(a + b) = sinacosb + cosasinb = (3/5 * -20/29) + (4/5 * 21/29) = -12/29 + 84/145

sin(a + b) = 24/145

Answer:

This problem has not solution

Step-by-step explanation:

lets the  integers be:

x

x+1

x+2

x+3

so:

x+(x+1)+(x+2)+(x+3)=2021

x+x+x+x+1+2+3=2021

4x+6=2021

4x=2021-6=2015

x=2015/4=503.75

x is not a integer

Step-by-step explanation:

If

[tex]V=\dfrac{4\pi}{3}r^3[/tex]

then we can solve for r as

[tex]r = \sqrt[3]{\dfrac{3V}{4\pi}}[/tex]

If the volume of the sphere is 150 ft^3, then the radius is

[tex]r = \sqrt[3]{\dfrac{3(150\:\text{ft}^3)}{4\pi}} = 3.30\:\text{ft}[/tex]

The radius of the given sphere with a volume of 150 cubic feet is 2.29 feet, correct to two decimal places.

Given that

the volume of a sphere = 150 cubic feet.

the radius of the sphere=????

a round solid figure, or its surface, with every point on its surface equidistant from its center.

as we know,

the volume of a sphere

[tex]V=\frac{4}{3} *\pi *r^3[/tex]

[tex]r = \sqrt[3]{\frac{3V}{4\pi } }[/tex][tex]r = \sqrt[3]{\frac{3*150}{4\pi } }[/tex][tex]=2.29 feet[/tex]

therefore, the radius of the given sphere is 2.29feet

to get more about sphere refer to the link,

https://brainly.com/question/22807400

Step-by-step explanation:

You look for the common factor of both of them which in this case is 5, therefore it's

5(x+7)..just divide 5 in 5x and in 35

Answer:

Point D

Step-by-step explanation:

The intersection(s) of lines represents where they cross or intersect. We can see that lines AD and DE cross or intersect as Point D, hence the answer being Point D.

Answer: Point D

Step-by-step explanation: The intersection of two figures is the set of points that is contained in both figures. In the diagram shown, D is the intersection of lines AD and DE because D is the point contained by both line AD and DE.

Answer:

B = 25

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Distributive Property

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

4(9y - 5) = 10(3y + 17) - 40

Step 2: Solve for y

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{4(9y - 5) = 10(3y + 17) - 40}\\\\\large\textsf{4(9y) + 4(-5) = 10(3y) + 10(17) - 10(40)}\\\\\large\textsf{36y - 20 = 30y + 170 - 40}\\\\\large\textsf{COMBINE the LIKE TERMS}\\\\\large\textsf{36y - 20 = (30 y)+ (170 - 40)}\\\\\large\textsf{36y - 20 = 30y + 130}\\\\\large\textsf{SUBTRACT 30y to BOTH SIDES}\\\\\large\textsf{36y - 20 - 30y = 30y + 130 - 30}}\\\\\large\textsf{Cancel out: 30y - 30y because that gives you 0}\\\\\large\textsf{Keep: 20 - 30y because helps solve for the y-value}[/tex]

[tex]\large\textsf{NEW EQUATION: 6y - 20 = 130}\\\\\large\textsf{ADD 20 to BOTH SIDES}\\\\\large\textsf{6y - 20 + 20 = 130 + 20}\\\\\large\textsf{Cancel out: -20 + 20 because that gives you 0}\\\\\large\textsf{Keep: 130 + 20 because that helps solve for the y-value}\\\\\large\textsf{130 + 20 = \bf 150}\\\\\large\textsf{NEW EQUATION: 6y = 150}\\\\\large\textsf{DIVIDE 6 to BOTH SIDES}\\\\\mathsf{\dfrac{6y}{6}= \dfrac{150}{6}}\\\\\large\textsf{Cancel: }\mathsf{\dfrac{6}{6}\large\textsf{ because that gives you 1}}[/tex]

[tex]\large\textsf{Keep: }\mathsf{\dfrac{150}{6}}\large\textsf{ because it helps solve for the y-value}\\\\\large\textsf{\bf y = }\mathsf{\dfrac{150}{6}}\\\\\large\textsf{OR }\\\\\mathsf{\dfrac{150}{6} }\large\textsf{ = \bf y}\\\\\\\large\textsf{SIMPLIFY ABOVE AND TOU YOU HAVE YOUR Y-VALUE}\uparrow\\\\\\\\\boxed{\boxed{\large\textsf{\huge\textsf{Answer: \bf y = 25} (Option B.)}}}\huge\checkmark\\\\\\\\\large\text{Good luck on your assignment and enjoy your day!}\\\\\\\\\\\frak{Amphitrite1040:)}[/tex]

Answer:

11.5

Step-by-step explanation:

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

Answer:

11.5

Step-by-step explanation:

Add all them all together.

7+9+10+12+15+16=69

Divide by the amount of numbers there are

69/6=11.5

11.5

Answer:

3( [tex]\frac{s}{q}[/tex] + r)  

Answer:

0.0264 = 2.64% probability that the proportion of wrong numbers in a sample of 448 phone calls would differ from the population proportion by more than 3%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

A telephone exchange operator assumes that 9% of the phone calls are wrong numbers.

This means that [tex]p = 0.09[/tex]

Sample of 448

This means that [tex]n = 448[/tex]

Mean and standard deviation:

[tex]\mu = p = 0.09[/tex]

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.09*0.91}{448}} = 0.0135[/tex]

What is the probability that the proportion of wrong numbers in a sample of 448 phone calls would differ from the population proportion by more than 3%?

More than 9% + 3% = 12 or less than 9% - 3% = 6%. Since the normal distribution is symmetric, these probabilities are the same, so we find one of them and multiply by 2.

Probability it is less than 6%

P-value of Z when X = 0.06. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.06 - 0.09}{0.0135}[/tex]

[tex]Z = -2.22[/tex]

[tex]Z = -2.22[/tex] has a p-value of 0.0132

2*0.0132 = 0.0264

0.0264 = 2.64% probability that the proportion of wrong numbers in a sample of 448 phone calls would differ from the population proportion by more than 3%

Answer:

[tex]15[/tex]

Step-by-step explanation:

[tex]3\frac{3}{4}\div\frac{2}{8}[/tex]

Turn the mixed number into an improper fraction

[tex]\frac{15}{4} \div\frac{2}{8}[/tex]

keep change flip

[tex]\frac{15}{4} *\frac{8}{2}[/tex]

cancel with GCF

[tex]\frac{15}{1} *\frac{2}{2}[/tex]

simplify

[tex]15*1[/tex]

solve

[tex]15[/tex]

Answer:

1) -[tex]\sqrt{32}[/tex]

2) -[tex]\sqrt{108}[/tex]

3) -[tex]\sqrt{80}[/tex]

4) -[tex]\sqrt{112}[/tex]

5) -[tex]\sqrt{40}[/tex]

6) -[tex]\sqrt{99}[/tex]

7) -[tex]\sqrt{50}[/tex]

8) -[tex]\sqrt{150}[/tex]

Step-by-step explanation:

please mark this answer as brainlist

Answer:

5

Step-by-step explanation:

Answer:

number 1: no

number 2: no

number 3: no

One can observe the midpoint is [tex](-3,1)[/tex].

But in order to verify the observation we must use formula to compute the midpoint of the segment formed by the endpoints.

The formula for such midpoint is [tex](\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})[/tex] where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are endpoints.

Our endpoints are [tex](-5,-3)[/tex] and [tex](-1,5)[/tex], so our midpoint is

[tex](\frac{-5-1}{2}, \frac{-3+5}{2})=\boxed{(-3,1)}[/tex].

Hope this helps.

Answer:

1) C

2) D

3) A

4) B

hope it helps

Answer:

11x-8x+8y

3x+8y SEEESH IN DEEZ NU                           TS

Step-by-step explanation:

If we simplify, both Joe and Hope factored the polynomial correctly but Joe didn't complete it fully.

The first binomial can be further factored:

The quadratic expression needs to have two roots in order to be factored as two binomials.

The discriminant must be positive or zero:

We have a = 3, b = k, c = -8

So we get following inequality:

Since k² is positive for any value of k, the solution is any value of k:

Hope this attachment helps you.