is it possible to roll a six sided number cube to generate a set of ten ordered pairs and have it graph a function?

Answers

Answer 1

Answer:

  maybe

Step-by-step explanation:

It depends on your strategy for determining ordered pairs.

A straightforward interpretation of the problem would say 1 roll gives an x-value, and the next roll gives the corresponding y-value. If that is the strategy, in 10 rolls, there will be repeats of the x-value. So, the pairs cannot represent a function.

__

If you adopt a different strategy, such as using the rolled number as the tens digit of the x-value, and sequentially assigning the numbers 0 to 9 to the units digit of the x-value, then all of the x-values will be different. Regardless of how you arrive at the y-values, the result will always be a function when graphed.

__

Basically, any strategy that makes it likely that the x-values will be different makes it likely that the relation will be a function. Otherwise, it is unlikely (or impossible) that the relation will be a function.


Related Questions

Six-four million, one hundred eighty-six thousand, three hundred square miles in standard form

Answers

Answer:

64,186,300 square miles

I'm sorry if I misunderstood.

Good luck mate! :)

Please add Brainliest if you'd like, not that it matters.

Remember to try your best every day!

Consider the following repeating decimal. 0.619
(a) Write the repeating decimal as a geometric series.
0.619 = _______ + n=0 summation infinity _______
(b) Write the sum of the series as the ratio of two integers

Answers

Answer:

a.  0.6[tex]\overline {19}[/tex] = [tex]0.6 + \ \sum \limits ^{\infty}_{n=0} \ 0.019 \ ( \dfrac{1}{100})^n[/tex]

b. 0.6[tex]\overline {19}[/tex]  = [tex]\mathbf{\dfrac{613}{990}}[/tex]  

Step-by-step explanation:

Consider the following repeating decimal. 0.6[tex]\overline {19}[/tex]

a) Write the repeating decimal as a geometric series.

0.6[tex]\overline {19}[/tex] is being expressed as 0.6191919...

0.6[tex]\overline {19}[/tex] = 0.6 + 0.019 + 0.00019+ 0.0000019 + ...

0.6[tex]\overline {19}[/tex] =[tex]0.6 + \dfrac{19}{1000}+ \dfrac{19}{100000}+ \dfrac{19}{10000000}+ ...[/tex]

0.6[tex]\overline {19}[/tex] = [tex]0.6+ \dfrac{19}{1000} \begin {bmatrix} 1 + \dfrac{1}{100} + \dfrac{1}{10000}+ ... \end {bmatrix}[/tex]

0.6[tex]\overline {19}[/tex] = [tex]0.6 + \ \sum \limits ^{\infty}_{n=0} \ 0.019 \ ( \dfrac{1}{100})^n[/tex]

(b) Write the sum of the series as the ratio of two integers

0.6[tex]\overline {19}[/tex]  = [tex]0.6 + 0.019 ( \dfrac{1}{1-0.01})[/tex]

0.6[tex]\overline {19}[/tex]  =[tex]0.6 + \dfrac{19}{1000}\times \dfrac{100}{99}[/tex]

0.6[tex]\overline {19}[/tex]  = [tex]0.6 + \dfrac{19}{990}[/tex]

0.6[tex]\overline {19}[/tex]  = [tex]\dfrac{594+19}{990}[/tex]

0.6[tex]\overline {19}[/tex]  = [tex]\mathbf{\dfrac{613}{990}}[/tex]  

A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 9 phones from the manufacturer had a mean range of 1260 feet with a standard deviation of 24 feet. A sample of 12 similar phones from its competitor had a mean range of 1230 feet with a standard deviation of 37 feet. Do the results support the manufacturer's claim? Let μ1 be the true mean range of the manufacturer's cordless telephone and μ2 be the true mean range of the competitor's cordless telephone. Use a significance level of α=0.1 for the test. Assume that the population variances are equal and that the two populations are normally distributed.
a. State the null and alternative hypotheses for the test.
b. Compute the value of the t test statistic. Round your answer to three decimal places.
c. Determine the decision rule for rejecting the null hypothesis H0. Round your answer to three decimal places.
d. State the test's conclusion.

Answers

Answer:

a

The null hypothesis is  [tex]H_o : \mu_1 - \mu_2 \le 0[/tex]

The  alternative hypothesis is [tex]H_a : \mu_1 - \mu_2 > 0[/tex]   (Manufacturers claim)

b

 [tex]t = 2.114[/tex]

c

Decision rule

    Reject the null hypothesis

d

There is sufficient evidence to support the claim that the calling range (in feet) of Manufacturers 900-MHz cordless telephone is greater than that of its leading competitor

Step-by-step explanation:

From the question we are told that

   The first sample  size is  [tex]n_1 = 9[/tex]

    The second sample size is [tex]n_2 = 12[/tex]

    The first sample mean is  [tex]\= x_1 = 1260 \ feet[/tex]

     The  second sample mean is  [tex]\= x_2 = 1230[/tex]

     The  first standard deviation is  [tex]\sigma_1 = 24[/tex]

     The second standard deviation is  [tex]\sigma_2 = 37[/tex]

      The significance level is [tex]\alpha = 0.10[/tex]

The null hypothesis is  [tex]H_o : \mu_1 - \mu_2 \le 0[/tex]

The  alternative hypothesis is [tex]H_a : \mu_1 - \mu_2 > 0[/tex]   (Manufacturers claim)

Generally the degree of freedom is mathematically represented as

       [tex]df = n_1 + n_2 -2[/tex]

       [tex]df = 9 + 12 - 2[/tex]

       [tex]df = 19[/tex]

Generally the pooled standard deviation  is mathematically represented as

      [tex]\sigma_p = \sqrt{ \frac{(n_1 - 1)\sigma_1^2 + (n_2-1 )\sigma_2^2 }{ (n_1 - 1 ) + (n_2 - 1 )} }[/tex]

      [tex]\sigma_p = \sqrt{ \frac{(9 - 1)24^2 + (12-1 )37^2 }{ (9 - 1 ) + (12 - 1 )} }[/tex]

      [tex]\sigma_p =32.17[/tex]

Generally the test statistics is mathematically represented as

      [tex]t = \frac{\= x_1 - \= x_2 }{\sqrt{\frac{\sigma_p^2}{n_1 } +\frac{\sigma_p^2}{n_2 } } }[/tex]

    [tex]t = \frac{1260 - 1230 }{\sqrt{\frac{32.17^2}{9 } +\frac{32.17^2}{12 } } }[/tex]

    [tex]t = 2.114[/tex]

Generally the p-value is obtained from the student t distribution table and the value is

    [tex]p-value = P(t > 2.11) = t_{2.11 , 19} = 0.024173[/tex]

Given that the  [tex]p-value < \alpha[/tex]

The null hypothesis is rejected

Hence we can conclude that there is sufficient evidence to support the claim that the calling range (in feet) of Manufacturers 900-MHz cordless telephone is greater than that of its leading competitor

A candy box is to be made out of a piece of cardboard that measures 8 by 12 inches. Squares of equal size will be cut out of each corner, and then the ends and sides will be folded up to form a rectangular box. What size square should be cut from each corner to obtain a maximum volume

Answers

Answer:

Length of square cut = 1.569 inches

Step-by-step explanation:

given data

Length of cardboard = 12 inches

Breadth of cardboard = 8 inches

solution

we will consider here side of the square = x

when we cutting out the square then there Length and breadth of candy box will be

Length of box = (12 - x - x)

Length of box = (12 - 2x) inches.

and

Breadth of box = (8 - x - x)

Breadth of box = (8 - 2x) inches.

and Height of candy box  wil be = x inches

so

Volume of a cuboid = L × b × h    .....................1

Volume of a cuboid = (12 - 2x) × (8 - 2x) × x

Volume of a cuboid = 96x - 40x² + 4x³

now we Differentiate with respect to x

V' = 96 - 80x + 12x²

and for maximum volume we put V' = 0

0 = 96 - 80x + 12x²

solve it we get

x = 5.097

x = 1.569

when x = 5.097 inches

Breadth of candy box = 8 - 10.194 = -2.194 inches

but we know breadth never be negative,

so we take

Length of square cut = 1.569 inches


If 3s = t + 5 and s
= 4, then t = ?

Answers

3s=t+5

s=4

we substitute 4 for s in the equation

3*4=t+5

12=t+5

t=12-5

t=7

Answer:

Brainliest!

Step-by-step explanation:

3s = t+5

s = 4

so...

3 (4) = t+5

12 = t+5

t = 7

What is 0.000345 expressed in scientific notation?
O 3.45 x 102
O 3.45 x 10
0 3.45 x 102
0 3.45 x 10 4

Answers

Answer:

The answer is D 10 to the power of -4.

Step-by-step explanation:

When the decimal point moves left, the power of becomes negative. Therefor the answer is D.

Have a good day.

What is the solution set of the equation 2z+6z+2=3−1z


Note: z≠0,−2

Answers

Answer:

z = 1/9

Step-by-step explanation:

2z + 6z + 2 = 3 - 1z

2z + 6z + 1z = 3 - 2 (on rearranging)

9z = 1 (on solving)

z = 1/9

HOPE IT HELPS (✿^‿^)

For the diagram, calculate; the radius of the smaller section and the perimeter of the shape of the and;

Answers

Answer:

a). Radius r of the small sector= 12cm

b). Perimeter of the shape= 68 cm

c). Angle= 47.7°

Step-by-step explanation:

a). Radius of the big sector= 24 cm

Arc if the big sector= 20 cm

Arc of the small sector= 10 cm

For the radius r of the small sector

r/10 = 24/20

r=(10*24)/20

r= 24/2

r= 12 cm

Radius r of the small sector= 12cm

b). Perimeter of the shape

= Total length of the shape

Let's note that the other side of the sector is also the radius= 24 cm

Perimeter= 20+24+24

Perimeter of the shape= 68 cm

c) the angle

Length of arc = 2πr*(angle/360)

Let angle = b

Length of arc = 20cm

20= 2*3.14*24*(b/360)

(20*360)/(2*3.14*24)= b

47.7°= b

Angle= 47.7°

If you roll a die 100 times, what is the approximate probability that you will roll between 9 and 16 ones, inclusive? (Round your answer to two decimal places.) HINT [See Example 4.]

Answers

Answer: 0.47

Step-by-step explanation:

Given that

n = 100, probability of rolling 1 = 1/6

binomial approximation

np = 100 ( 1/6) = 16.667

standard deviation = √ 100 × 1/6 ×5/6 = 3.7627

P ( 9 ≤ X ≤ 16 )

= P ( 8.5 < X < 16.5 )

so,

= P ((8.5 - 16.6667) / 3.7627 < Z < (16.5 - 16.6667) / 3.7627

= P ( -2.17 < Z < -0.04 )

= 0.484 - 0.015

= 0.47

Therefore the approximate probability that you will roll between 9 and 16 ones is 0.47

Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are independent simple random samples selected from normally distributed populations. Assume that the population standard deviations are equal.

Answers

Answer:

See the attachment for formatted formulas

Step-by-step explanation:

Let X11, X12, ……,X1n  and X21 , X22……., X2n be two small independent random samples from two normal populations with means u1 and u2  and the standard deviations σ1 and σ2 respectively. If σ1= σ2 (=σ) but unknown then the unbiased pooled or combined estimate of the common variance σ2 (the term variance means that each population has the same variance) is given by

Sp2  = ((n_1-1)  s_(1^2 )+ (n_2-1) s_2^2)/(n_1+n_2-2)

Where

S12 = 1/(n_1- 1) ∑▒〖 (X_1i- X`_1)〗^2  and

S22 = 1/(n_2- 1) ∑▒〖 (X_2j- X`_2)〗^2

The test statistic

t = ((X_1`-X_2`)- (μ_1- μ_2))/(√(s_p&1/n_1 )+ 1/n_2 )

Has t distribution with v= n1 + n2 – 2 degrees of freedom.

It is used as a test statistic for testing hypotheses about the difference between two population means.

The procedure for testing hypothesis H0: μ_1- μ_2= ∆_0 in case of small independent samples when σ_1= σ_2 is as follows.

Formulate the null and alternative hypotheses given  σ_1= σ_2= σ unknown.

H0: μ_1- μ_2= ∆_0  against the appropriate alternative.

Decide the significance level α. The test statistic under H0 is

t = ((X_1`-X_2`)- ∆_0  )/(√(s_p&1/n_1 )+ 1/n_2 )

Which has t distribution with v= n1 + n2 – 2 degrees of freedom.

Identify the critical region Compute the t- value from the given data Reject H0 if t falls in the critical region, accept H0 otherwise.

pls someone help me

Answers

Answer:

C

Step-by-step explanation:

Starting at zero, it went back 2/5 to negative 2/5.  Then it went forward 4/5 to positive 2/5, which is the answer.

If half of a box of candy weighs 3/5 of a pound, how much would 4 full boxes weigh?

Answers

So we want to know what a full box is. We have the weight of half a box. So we can use the formula: (2 x 3/5) and you want to know the outcome of four full boxes. So (2x3/5)4
Or: 6/5 x 4

And the answer is 24/5. But if you want to simplify it, it’s 4 4/5

Dione has 3 rolls of pennies containing 50 coins each, 4 rolls of nickels
containing 40 coins each, 5 rolls of dimes containing 50 coins each, and 6
rolls of quarters containing 40 coins each. How much money does she have?

Answers

Answer:

$94.50

Step-by-step explanation:

3(50)=150 $1.50

4(40)=160 160(5)=800 $8.00

5(50)=250 250(10)=2500 $25.00

6(40)=240 240(25)=6000  $60.00

60+25+8+1.5=$94.50

How can the decimal –70.73 be written as a mixed number? ​ ​

Answers

Answer:

-70[tex]\frac{73}{100}[/tex]

Hope It Help

What is the difference between 4 and 62
2.

Answers

Answer:

6214

Step-by-step explanation:

you round up 62 and 4 20 times and that is your answer but for give me if this answer wrong

Find the product. (3p–2)(2p^2–p+3)

Answers

Answer:

6p^3−7p^2+11p−6

Step-by-step explanation:

1. You would want to foil it, which means multiplying one number from each parentheses to the next parentheses, like so:

3p * 2p ^ 2 = 6p^3

3p * -p = -3p

3p * 3 = 9p

-2 * 2p^2 = -4p^2

-2 * -p = 2p

-2 * 3 = - 6

2. Now add all of the numbers we foiled together, thus getting you:

6p^3−7p^2+11p−6

Which option shows the correct hypotheses for the test that the explanatory variables jointly significantly predict engine overhaul time?

Answers

Unclear question. However, I inferred you want to know about hypotehsis test.

Step-by-step explanation:

Remember, any hypothesis test is divided into two types. They are:

the null hypothesis andthe alternate hypothesis.

Using this question example, here's the hypothesis statements ma sound:

Null hypothesis; There is a significant impact by the explanatory variables on engine overhaul time.

Alternate hypotheses; There is no impact by impact by the explanatory variables on engine overhaul time.

Amy deposited $750 in a saving account that pays 6.75% Interest compounded monthly. Calculate the total amount in the account after 10 years.

Answers

Answer:

Amount after 10 years is $1472.775

Step-by-step explanation:

Amy deposited $750 in a saving account that pays 6.75% Interest compounded monthly for 10 years.

Principal amount= $750

Rate of interest= 6.75%

Time= 10 years

Number of times compounded= 10*12

Number of times compounded= 120

A= p(1+r/n)^(nt)

A= 750(1+0.0675/120)^(120*10)

A= 750(1+0.0005625)^(1200)

A= 750(1.0005625)^(1200)

A= 750(1.9637)

A= 1472.775

Amount after 10 years is $1472.775

Many smoke detectors contain:
A. Carbon-14
B. Americium-241
C. Strontium-90
D. Iodine

Answers

Answer:

Option B, Americium-241, is the right answer.

Step-by-step explanation:

A device which senses smoke usually as an indicator of fire is known as a smoke detector.The two most common types of smoke detectors are the Ionization chamber and photoelectric smoke indicators. Many of these smoke detectors comprise some amount of americium-241, which is a radioactive substance. These smoke detectors respond immediately to fires that give off some smoke.

I need help with the following questions. Help would be very much appreciated! :D

Answers

Step-by-step explanation:

a) 12:40 = 3: 10

b) 40:12 = 10:3

c)

[tex]1. \: \frac{non \: fiction}{graphic \: novels} [/tex]

[tex]2. \: \frac{science \: fiction}{graphic \: novels} \: \: \: \: \: \: \: 3. \frac{science \: fiction}{non \: fiction} [/tex]

d)

Fiction books is 80.

Find the value of x. Picture below

Answers

Answer:

x=6

Step-by-step explanation:

BD is bisecting of <B

x/3=8/4    the theorem of  the bisecting

4*x=3*8

4x=24

x=24/4

x=6

Your friend has prepared his monthly budget and asks you if he has overlooked anything in this planning. which of the following questions points out his most serious omission?

Answers

Answer:

The best and most correct answer among the choices provided by the question is

The statement that points out his most serious omission is "What if the electric bill increases?".

Step-by-step explanation:

A list of the top twenty restaurants in chicago was released. Four of the restaurants specialize in seafood. If five of the restaurants are selected randomly from the list, the standard deviation for the number of restaurants specializing in seafood is_____.

Answers

Answer:

the standard deviation for the number of restaurants specializing in seafood is 0.8944

Step-by-step explanation:

Given that :

Sum total number N of top restaurants in Chicago = 20

Four of the restaurants specialize in seafood,

then , the probability that a randomly selected restaurant from the top 20 in the list will specialize in seafood will be  p = 4/20

p = 0.2

sample size n = 5

Assuming X to be the random variable that follows a Binomial distribution that represent the number of restaurants specializing in seafood.

Then: [tex]X \sim Binomial (n,p)[/tex]

where;

n = 5  and p = 0.2

The standard deviation σ  can be determined by using the formula:

[tex]\sigma = \sqrt{np(1-p)}[/tex]

[tex]\sigma = \sqrt{5\times 0.2(1-0.2)}[/tex]

[tex]\sigma = \sqrt{1.0(0.8)}[/tex]

[tex]\sigma = \sqrt{0.8}[/tex]

σ = 0.894427191

σ [tex]\simeq[/tex] 0.8944

A candle is in the shape of a cylinder with a diameter of 3.5 in and height of 8.5 in. The weight of the candle is 1400 grams.
a. Find the density of the candle.
b. If the candle burns at a rate of 0.75in per hour, find its volume after burning for 3 hours.
c. Compare the volume and surface area of the burned candle to its beginning volume and surface area.
d. What is the weight of the candle after burning for 3 hours?

Answers

Answer:

a

Step-by-step explanation:

Find the sum of the convergent series by using a well-known function. (Round your answer to four decimal places.) [infinity] (−1)n + 1 1 7nn n = 1

Answers

Answer:

Here is the full question:

Find the sum of the convergent series by using a well-known function. (Round your answer to four decimal places.) Σ_(n=1)^∞ (-1)^n+1 1/7^n n

Step-by-step explanation:

Σ_(n=1)^∞ (-1)^n+1 1/7^n n

We will use the function In (1 + x)

We will now give a power series expansion of the function while it is centered at x=0

This will give us In (1 + x) = Σ_(n=1)^∞[tex](-1)^{n+1}[/tex][tex]\frac{x^{n} }{n}[/tex]

Note that x= 1/7

Now let us equate the two equations

Σ_(n=1)^∞[tex](-1)^{n+1}[/tex][tex]\frac{1}{7^{n}n }[/tex] = ㏑(1 + x)|[tex]_{x = \frac{1}{7} }[/tex] = ㏑[tex]\frac{8}{7}[/tex]

Sum of the series will give ㏑[tex]\frac{8}{7}[/tex]

If 3s = t + 5 and se = 4, then t =

Answers

Answer:

t must be 7

Step-by-step explanation:

Replace s with 4 and solve for t in the original equation:

3 s = t + 5

3 (4) = t + 5

12 = t + 5

12 - 5 = t

7 = t

So t must be 7

Let x stand for the length of an individual screw. 100 screws were sampled at a time. The population mean is 2.5 inches and the population standard deviation is 0.2 inches. What is the mean of the sampling distribution of sample means?
a) 0.2
b) 2.5
c) 0.02
d) 2.

Answers

Answer:

The  correct option is   b

Step-by-step explanation:

From the question we are told that

   The  sample size is  [tex]n = 100[/tex]

    The  population  mean is  [tex]\mu = 2.5[/tex]

   The  sample  standard deviation is  [tex]\sigma = 0.2[/tex]

Generally the mean of the sampling distribution of sample means is mathematically represented as

       [tex]\mu_{\= x } = \mu[/tex]

=>    [tex]\mu_{\= x } = 2.5[/tex]

The weight of an organ in adult males has a bell-shaped distribution with a mean of 310 grams and a standard deviation of 40 grams. Use the empirical rule to determine the following.

a. About 95 % of organs will be between what weights?
b. What percentage of organs weighs between 270 grams and 350 grams?
c. What percentage of organs weighs less than 270 grams or more than 350 grams?
d. What percentage of organs weighs between 230 grams and 430 grams?

Answers

Answer:

Step-by-step explanation:

Given that:

The mean μ = 310

The standard deviation σ =  40

Using the empirical rule to determine the following :

a. About 95 % of organs will be between what weights?

At 95% data values lies within 2 standard deviations of mean.

Thus, the  required range is :

= μ ± 2σ

= ( 310 - 2 (40) ,  310 + 2(40) )  

= (230, 390)

b. What percentage of organs weighs between 270 grams and 350 grams

Here:

μ ± σ = (310 - 40,  310 + 40)

μ ± σ = (270, 350)

Using empirical rule, 68% data values is in the range within 1 standard deviation of mean. This implies that 68% data values lie between (270, 350).

c. What percentage of organs weighs less than 270 grams or more than 350 grams?

The complement theorem can be use to estimate the  percentage of organs that weighs less than 270 grams or more than 350 grams,

This can be illustrated as :

= 100 % - 68 %

= 32 %

d. What percentage of organs weighs between 230 grams and 430 grams?

Using the empirical rule:

The percentage of organs weighs between 230 grams and 430 grams is:

u - 2σ  and  u + 3σ respectively.

How to do ii)
Deduce A^-1 = A^2 based on A^3=I

Answers

Multiply by [tex]A^{-1}[/tex] on the right of both sides of [tex]A^3=I[/tex], then use the fact that matrix multiplication is associative.

If [tex]A^3=I[/tex], then

[tex]A^3A^{-1}=IA^{-1}[/tex]

[tex]A^2(AA^{-1})=A^{-1}[/tex]

[tex]A^2I=A^{-1}[/tex]

[tex]\implies A^2=A^{-1}[/tex]

The following table shows a proportional relationship between xxx and yyy. xxx yyy 222 999 555 22.522.522, point, 5 888 363636 Write an equation to describe the relationship between xxx and yyy.

Answers

Answer:

y=4.5x

Step-by-step explanation:

I got it correct on Khan!

Hope this helps ;)

The equation that describes the proportional relationship between x and y is: y = 4.5x.

How to Write the Equation of a Proportional Relationship?

To write the equation of a proportional relationship between variables x and y, find the constant of proportionality, which is k = y/x, then plug in the value of k into y = kx.

Constant of proportionality (k) = 9/2 = 22.5/5 = 36/8 = 4.5

Substitute k = 4.5 into y = kx.

y = 4.5x.

The equation is: y = 4.5x.

Learn more about the proportional relationship on:

https://brainly.com/question/15618632

#SPJ6

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What is the manufacturing industry Evaluate the expression, when y = 2.4y - 6 + 5y = y x to the second power plus 4equals 40 solve for x When the north pole of a magnet is moved towards the center of a loop of wire containing a galvanometer, the needle of the galvanometer flicks to the right. What would also cause the needle on the galvanometer to move to the right? Hydrogen reacts with oxygen to form a compound called: a. Oxidation b. Oxide c. Metal d. None of the above justice definition in your own words. HELP ASAP PLEASE 10 POINTS beginning in the 1990 Georgia, Alabama and florida entered into a legal battle involving the Chattahoochee River. why did this legal battle take place? (01.02 MC) Read the following passage carefully before you choose your answer. Mrs. Jennings was a widow, with an ample jointure.1 She had only two daughters, both of whom she had lived to see respectably married, and she had now therefore nothing to do but to marry all the rest of the world. In the promotion of this object she was zealously active, as far as her ability reached; and missed no opportunity of projecting weddings among all the young people of her acquaintance. She was remarkably quick in the discovery of attachments, and had enjoyed the advantage of raising the blushes and the vanity of many a young lady by insinuations of her power over such a young man; and this kind of discernment enabled her soon after her arrival at Barton decisively to pronounce that Colonel Brandon was very much in love with Marianne Dashwood. She rather suspected it to be so, on the very first evening of their being together, from his listening so attentively while she sang to them; and when the visit was returned by the Middletons' dining at the cottage, the fact was ascertained by his listening to her again. It must be so. She was perfectly convinced of it. It would be an excellent match, for he was rich and she was handsome. Mrs. Jennings had been anxious to see Colonel Brandon well married, ever since her connection with Sir John first brought him to her knowledge; and she was always anxious to get a good husband for every pretty girl. The immediate advantage to herself was by no means inconsiderable, for it supplied her with endless jokes against them both. At the park she laughed at the colonel, and in the cottage at Marianne. To the former her raillery was probably, as far as it regarded only himself, perfectly indifferent; but to the latter it was at first incomprehensible; and when its object was understood, she hardly knew whether most to laugh at its absurdity, or censure its impertinence, for she considered it as an unfeeling reflection on the colonel's advanced years, and on his forlorn condition as an old bachelor. Mrs. Dashwood, who could not think a man five years younger than herself, so exceedingly ancient as he appeared to the youthful fancy of her daughter, ventured to clear Mrs. Jennings from the probability of wishing to throw ridicule on his age. "But at least, mama, you cannot deny the absurdity of the accusation, though you may not think it intentionally ill-natured. Colonel Brandon is certainly younger than Mrs. Jennings, but he is old enough to be my father; and if he were ever animated enough to be in love, must have long outlived every sensation of the kind. It is too ridiculous! When is a man to be safe from such wit, if age and infirmity will not protect him?" "Infirmity!" said Elinor,2 "do you call Colonel Brandon infirm? I can easily suppose that his age may appear much greater to you than to my mother; but you can hardly deceive yourself as to his having the use of his limbs!" "Did not you hear him complain of the rheumatism? and is not that the commonest infirmity of declining life?" "My dearest child," said her mother laughing, "at this rate you must be in continual terror of my decay; and it must seem to you a miracle that my life has been extended to the advanced age of forty." "Mama, you are not doing me justice. I know very well that Colonel Brandon is not old enough to make his friends yet apprehensive of losing him in the course of nature. He may live twenty years longer. But thirty-five has nothing to do with matrimony." (1811) 1 a financial settlement providing for a wife after her husband's death 2 Marianne's sister The first paragraph characterizes Mrs. Jennings as accommodating and impassioned benevolent and enthusiastic concerned and respectful meddlesome and eager philanthropic and selfless solve the equation by using the quadratic formula. x^2+2x=6 Please help ASAP!!! Plweaseeeeeeeeeeeeeeeeee 2. What is preventive care? In situations where rivals can readily copy the successful features of a company's strategy or duplicate its attempts to attract customers, the only dependable path to competitive advantage is for a company to staff the company's organization with smarter and more talented people. outexecute rivals by developing a collection of resources and capabilities that enables the company to perform certain important value chain activities at lower cost than rivals or with greater effectiveness than rivals (thereby gaining the ability to deliver more value to customers via either a lower price or a more appealing product). do a better job of training, empowering, motivating, and compensating employees than rivals. perform value chain activities quicker or faster than rivals can. outsource more value chain activities than rivals do and thereby achieve lower operating costs. an eraser company needs to ship erasers in bags of 780 plus or minus 9 erasers. what is the minimum and maximum erasers that could be in a bag? 25. Michelle walks into class and yells out that she just got a new Gucci bag for 50% off. If she paid $120 forthe bag, how much was the original price without the discount? Which is true? a. Every meridian is actually a circle rather than a line b. Every meridian is the same length and has the same terminus (beginning and ending points) c. Every parallel begins and ends at the Poles d. Every parallel is the same length