Explanation:
Antinodes are not the same thing as the amplitude , but they are very closely related. The amplitude is the distance from the rest position of the wave to the antinode . The antinode is just a point along the wave that has the greatest maximum velocity in the y-direction.
The amplitude of a standing wave doesn't remain the same throughout the wave. It keeps on changing as it is a function of x.
Where the amplitude is minimum is called?
The locations at which the absolute value of the amplitude is minimum are called nodes, and the locations where the absolute value of the amplitude is maximum are called antinodes.
Explanation:
Antinodes are not the same thing as the amplitude , but they are very closely related. The amplitude is the distance from the rest position of the wave to the antinode . The antinode is just a point along the wave that has the greatest maximum velocity in the y-direction .
intro urself please
If 300j of energy is available for every 75c of charge what is the potential difference
Answer: 4V
Explanation:
If 300j of energy is available for every 75c of charge, the voltage will be calculated by dividing the available energy by the charge. This will be:
= 300 / 75
= 4v
Therefore, the potential Difference will be 4V.
what is the correct answer?
Answer:
Option (4)
Explanation:
Given polynomial is,
P(x) = 1x³ - 7x² + 2x + 40
If (x - 5) is a factor of the given polynomial,
Synthetic division by x = 5,
5 | 1 -7 2 40
↓ 5 -10 -40
1 -2 -8 0
Therefore, factored form of the polynomial will be,
P(x) = (x - 5)(x²- 2x - 8)
Now we further factorize the expression (x² - 2x - 8),
(x² - 2x - 8) = x²- 4x + 2x - 8
= x(x - 4) + 2(x - 4)
= (x + 2)(x - 4)
Now fully factored form of the polynomial will be,
P(x) = (x - 5)(x + 2)(x - 4)
Therefore, remaining factors of the polynomial other than (x - 5) are (x - 4)(x + 2)
Option (4) will be the correct option.
Clarissa has a credit card with a limit of $1,000 and pays her balance in full each month. If Clarissa needs a short-term loan, can she use her credit card as collateral at a pawn shop? Why or why not? Select the best answer from the choices provided. A. She cannot use it because a credit card is not collateral. B. If the balance on the credit card is zero, she can use it. C. If the balance on the credit card is $1,000, she cannot use it. D. She can use it if she increases the credit limit.
Answer:
B.she cannot use it because the credit card is not collareral
Explanation:
sorry if am wrong
The pitch of a sound is most closely related to what ?
A 43 kg box is being pushed and pulled by
three forces. The first force is 155 N to the
right. The second force is 227 N to the left.
The third force is 113 N to the right. What is
the acceleration of the box?
Answer:
a = - 0.209 [m/s²]
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
We will take the positive forces to the right and the negative forces to the left.
[tex]155-277+113=43*a\\-9=43*a\\a = - 0.209[m/s^{2} ][/tex]
The negative sign means that the box accelerates in a negative direction to the left.
a skier starts at rest at the top of a hill with 350 J of gravitational potential energy. Assuming energy is conserved, what is her final kinetic energy at the lowest point
Answer:
350Joules
Explanation:
According to law of Conservation of energy, the amount of energy at the used up at the start is equal to that at the end.
The initial energy used up is gravitational potential energy
Final energy at the lowest point is kinetic energy.
If the energy is conserved then it means energy is not used up during the process hence;
Initial Potential energy = Final kinetic energy
If the gravitational potential energy is 350Joules then her final kinetic energy at the lowest point will also be 350Joules
The ball as launched horizontally off a 200m cliff. The initial velocity is 40m/s.
Find the time it takes to hit the ground.
Find the RANGE, distance traveled horizontally.
Find the final vertical velocity.
Answer:
a. 6.39 s b. 255.6 m c. 62.6 m/s
Explanation:
a. Find the time it takes to hit the ground.
Using y = ut + 1/2gt² where y = height of cliff = 200 m, u = initial vertical velocity of ball = 0 m/s, g = acceleration due to gravity = 9.8 m/s² and t = time taken for ball to hit the ground.
So, substituting the values of the variables into the equation, we have
200 m = 0 m/s × t + 1/2 × 9.8 m/s² × t²
200 m = 0 + (4.9 m/s²)t²
200 m = (4.9 m/s²)t²
dividing both sides by 4.9 m/s², we have
t² = 200 m ÷ 4.9 m/s²
t² = 40.82 s²
taking square root of both sides, we have
t = √(40.82 s²)
t = 6.39 s
b. Find the RANGE, distance traveled horizontally.
The range is the horizontal distance traveled by the ball, R = vt where v = horizontal velocity of ball = 40 m/s and t = time taken for ball to hit the ground = 6.39 s
So, R = vt
= 40 m/s × 6.39 s
= 255.6 m
c. Find the final vertical velocity.
Using v = u - gt where u = initial vertical velocity of ball = 0 m/s, v = final velocity of ball, g = g = acceleration due to gravity = 9.8 m/s² and t = time taken for ball to hit the ground = 6.39 s.
So, substituting the values into the equation, we have
v = 0 m/s - 9.8 m/s² × 6.39 s
v = -62.62 m/s
v ≅ -62.6 m/s
Two objects, one 4 times as massive as the other, are approaching each other under their mutual gravitational
attraction. When the separation between the objects is 100 km, the acceleration of the lighter object is 1 m/
s2. When the separation between them is 25 km, the acceleration of the heavier object is
To Find :
The acceleration of the heavier object.
Solution :
Force of gravitation on lighter object by heavier object is :
[tex]F = \dfrac{Gm(4m)}{100^2}[/tex]
Acceleration of lighter object is given by :
[tex]a_s = \dfrac{4Gm}{100^2}\\\\m = \dfrac{50^2}{G}[/tex] .....1)
Now, acceleration of heavier object when separation between them is 25 km :
[tex]4ma_h = \dfrac{Gm(4m)}{25}\\\\a_h = \dfrac{Gm}{25}[/tex].....2)
Putting value of m in equation 2, we get :
[tex]a_h = \dfrac{G\times 50^2}{G \times 25}\\\\a_h = \dfrac{2500}{25}\\\\a_h = 100\ m/s^2[/tex]
Therefore, the acceleration of the heavier object is 100 m/s².
Please help me on this!!!
Le manque de sommeil peut réduire la production d'insuline par le pancréas. L'insuline est responsable de métaboliser le sucre dans le sang. De quel ordre peut être la réduction d'insuline?Lecteur immersif
Answer:
Very big.
Explanation:
Very big reduction occurs in insulin production when a person did not sleep in 24 hours. Due to lack of sleep, reduction occurs in the production of insulin by the pancreas. Insulin is a hormone that is responsible for metabolizing sugar in the blood and if insulin is not secreted by the pancreas in normal concentration so the person get diabetes disease due to increasing amount of glucose in the blood.
Water boiling
Which one is shown? (Look at pic)
Answer:
conduction.
Explanation:
Hoped I helped! Im Eve btw have a great day and consider marking this brainliest if you do thank you in advanced!
Which term below best matches this definition - a period in European history when many educated people stressed the importance of learning and reasoning; education was considered the key to understanding and solving society's problems
Answer:
The Enlightenment.
Explanation:
The Enlightenment took place during the eighteen century and it typically involved a period of philosophical, cultural and intellectual movement in which ideas on nature, reason, humanity and God were emphasized on greatly over science and superstition through meetings that were held at coffeeshops, scientific academies, literary salons, masonic lodges, etc. Some of the influential philosophers of the enlightenment were Adam Smith, John Locke, Jean Jacques Rousseau, David Hume, Baruch Spinoza, Montesquieu, Hugo Grotius, Denis Diderot, Gottfried Wilhelm, Cesare Beccaria, Immanuel Kant etc. The enlightenment was also known as the age of reason or the age of enlightenment.
Hence, the enlightenment was a period in European history when many educated people stressed the importance of learning and reasoning; education was considered the key to understanding and solving society's problems.
An unknown material, m1 = 0.41 kg, at a temperature of T1 = 86 degrees C is added to a Dewer (an insulated container) which contains m2 = 1.7 kg of water at T2 = 22 degrees C. Water has a specific heat of cw = 4186 J/(kg⋅K). After the system comes to equilibrium the final temperature is T = 30.3 degrees C.
Complete Question
An unknown material, m1 = 0.41 kg, at a temperature of T1 = 86 degrees C is added to a Dewer (an insulated container) which contains m2 = 1.7 kg of water at T2 = 22 degrees C. Water has a specific heat of cw = 4186 J/(kg⋅K). After the system comes to equilibrium the final temperature is T = 30.3 degrees C.
Part (a) Input an expression for the specific heat of the unknown material.
Part (b) What is the specific heat in J/(kg⋅K)?
Answer:
a
[tex]c = \frac{m_2 * c_w (T - T_2)}{m_1 * (T_1 - T) }[/tex]
b
[tex]c = 2587.14 \ J /(kg \cdot K)[/tex]
Explanation:
From the question we are told that
The mass of the material is [tex]m_1 = 0.41 \ kg[/tex]
The temperature is [tex]T_1 = 86 ^oC[/tex]
The mass of water is [tex]m_2 = 1.7 \ kg[/tex]
The temperature of water is [tex]T_2 = 22^oC[/tex]
The specific heat of water is [tex]c_w = 4186 \ J/(kg\cdot K)[/tex]
The temperature of the system is [tex]T= 30 .3^o C[/tex]
Generally heat lost by the unknown material = heat gained by water
Generally the heat gained by water is mathematically represented as
[tex]Q_2= m_2 * c_w (T - T_2)[/tex]
=> [tex]Q_2= 1.7 * 4186 (30.3 - 22)[/tex]
=> [tex]Q_2= 59064.46 \ J[/tex]
Generally the heat lost by the unknown material is mathematically represented as
[tex]Q_1= m_1 * c* (T_1 - T)[/tex]
[tex]m_2 * c_w (T - T_2) = m_1 * c* (T_1 - T)[/tex]
=> [tex]c = \frac{m_2 * c_w (T - T_2)}{m_1 * (T_1 - T) }[/tex]
Here c is the specific heat capacity of the unknown material
=> [tex]Q_1= 0.41 * c (86 - 30.3)[/tex]
=> [tex]Q_1= 22.83 c[/tex]
So
[tex]59064.46 = 22.83 c[/tex]
=> [tex]c = \frac{59064.46 }{ 22.83}[/tex]
=> [tex]c = 2587.14 \ J /(kg \cdot K)[/tex]
Where could we use a light bulb that has 12V written on it
Answer:
Explanation:
In a battery charger (for an auto).
As a replacement for any bulb in an auto.
As a lamp in an emergency exit where the power must be shut off.
As a light that illuminates the back of a truck, turned on when loading the truck.
Please help I will send pics in return or I will mark brainliest (depending on what u want) for a good attempt and explanation.
The answer would have to be 8.47 m/s/s because the backwards pull + the rate of speed it is going would have to be added to get the answer to compensate for the backwards pull
A 0.2 kg baseball is pitched with a velocity of 40 m/s and is then batted to the pitcher with a velocity of 60 m/s. What is the magnitude of change in the ball's momentum?
Answer:
The magnitude of change in the ball's momentum is 4 kgm/s
Explanation:
Given;
mass of the ball, m = 0.2 kg
initial velocity of the ball, u = 40 m/s
final velocity experienced by the ball, v = 60 m/s
Therefore, the change in momentum of the ball is given as final momentum minus initial mometum;
ΔP = mv - mu
ΔP = m(v-u)
ΔP = 0.2 (60 - 40)
ΔP = 4 kgm/s
Therefore, the magnitude of change in the ball's momentum is 4 kgm/s
The magnitude of the change in the momentum of the baseball is 4 kgm/s.
To solve the problem above we need to use the formula of change in momentum
Change in momentum: This can be defined as the product of the mass and the change in velocity of a body.
The formula of change in momentum is
M = m(v-u).................. Equation 1
Where M = change in momentum, m = mass of the baseball, v = final velocity of the baseball, u = initial velocity of the baseball.
From the question
Given:
m = 0.2 kg v = 60 m/s u = 40 m/sSubstitute these values into equation 1
M = 0.2(60-40) M = 0.2(20) M = 4 kgm/sHence, The magnitude of the change in the momentum of the baseball is 4 kgm/s
Learn more about change in momentum here: https://brainly.com/question/11789105
PLZ HELP IM REALLY CONFUSED a boy is playing catch with his friend. He throws the ball straight up. When it leaves his hand, the ball (2kg) is traveling 10m/s. Whats the ball's kinetic energy just as it leaves the boy's hand? What is the potential energy of the ball when it reaches the highest point
Answer:
K.E = 100 J
Final P.E = 100 J
Explanation:
The kinetic energy of any object can be given by the following formula:
[tex]K.E = (\frac{1}{2})mv^{2}[/tex]
where,
K.E = Kinetic Energy
m = mass of ball = 2 kg
v = speed of ball
Initially, v = 10 m/s. Therefore, the initial K.E is given as:
[tex]K.E = (\frac{1}{2})(2\ kg)(10\ m/s)^{2}[/tex]
K.E = 100 J
Now, at the highest point the K.E of the ball becomes zero. because the ball stops for a moment at the highest point and its velocity becomes zero. So, from Law of Conservation of energy:
Initial K.E + Initial P.E = Final K.E + Final P.E
Initial P.E is also zero due to zero height initially.
K.E + 0 = 0 + Final P.E
Final P.E = 100 J
what does the area under a speed-time graph represent
Answer: It represents the whole distance traveled. Hope this helps!
Explanation:
PLEASE HELP ME this is due in 20 mins!!!!!
See how a block and tackle system can increase your mechanical advantage. You will need two broomsticks, a rope, and two helpers.
A. Give each helper a broom stick and have them stand facing each other holding the broomstick firmly in both hands in a horizontal position. The broomsticks should be at the same level, about two feet apart.
B. Tie one end of the rope to one of the broomsticks. (You may need to have one of your helpers hold the knot firmly in one hand as he or she holds the broomstick to help anchor it.)
C. Wrap the rope around the other broomstick, as in a simple pulley system, and pull on the free end of the rope. Your helpers should resist your pulling. What happens? Can you pull the broomsticks together?
D. Now weave the rope back over the first broomstick, so you have a double pulley. Pull on the free end. What happens now? Can you pull the broomsticks together? What is your mechanical advantage?
E. Try weaving the rope over the broomsticks one or two more times. Describe what happens, and state the mechanical advantage of each situation.
F. Write a summary of what happened and an explanation using the terms:
force
distance
work
mechanical advantage
A steel bridge is 5.5m long. If the linear expansivity of steel is 0.000011/℃, how much will it expand when temperature rise by 10 ℃? Give your answer in cm
Answer:
The expansion of the steel bridge is 0.0605 cm
Explanation:
The given length of the steel bridge, L = 5.5 m
The linear expansivity of the steel bridge, [tex]\alpha_ L[/tex] = 0.000011/°C
The rise (change) in the temperature, ΔT = 10°C
Let, ΔL, represent the expansion of the steel bridge
Given that the linear expansivity, [tex]\alpha_ L[/tex], of a material is the change in the length of a material per unit length of the material per unit change in the temperature, we have;
[tex]\alpha_ L[/tex] = ΔL/(L × ΔT)
∴ ΔL = [tex]\alpha_ L[/tex] × L × ΔT = 0.000011 /°C × 5.5 m × 10 °C = 0.000605 meters
ΔL = 0.000605 meters
The expansion of the steel bridge, ΔL = 0.000605 meters = 0.000605 m × 100 cm/m = 0.0605 cm
two Force one of 12 Newton and another 24 Newton acts at 90 degree with each other find the resultant of two force and its direction
Answer:
Fr = 26.83 [N]
Explanation:
To solve this problem we must use the Pythagorean theorem, since the forces are vector quantities, that is, they have magnitude and density. Therefore the Pythagorean theorem is suitable for the solution of this problem.
[tex]F_{r}=\sqrt{(12)^{2}+(24)^{2} } \\F_{r}=26.83[N][/tex]
say something random cuz i already answered my own question
Answer:
The experimental setup, with car 1 is at the top of a ramp and car 2 at the bottom of the ramp is explained below in details.
Explanation:
The meter pole should be located at the opening location of car second at the bottom of the ramp so that it regulates the portion of car second that will finish up the most distant away from the bottom of the ramp.
So, I think now you got your answer which is absolutely correct and it will help you.
Answer:
hello my good friend
Explanation:
HELP ASAP!!!! WILL GIVE BRAINLIEST!
What are the functions of ribosomes, the endoplasmic reticulum, vesicles, and the Golgi apparatus?
Ribosomes, endoplasmic reticulum, vesicles, and the Golgi apparatus are the organelles present in the eukaryotic cell. They are involved in various roles and functions involving proteins.
What are the functions of the organelles?Ribosomes are the organelles involved in the transcription and translation process to synthesize proteins and transport them from ER to the vesicles. The endoplasmic reticulum (ER) is a membraneous structure that along with ribosomes is involved in lipid and protein synthesis.
The proteins synthesized from ER are transported to the Golgi body through the vesicles. They even eliminate the waste from the cell. The Golgi apparatus receives proteins from ER and then packs, modifies, and transports them to the target location.
Therefore, the ER, ribosomes, Golgi, and vesicles are involved in protein synthesis and transportation.
Learn more about cell organelles, here:
https://brainly.com/question/14798609
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Why is it difficult to use the law of conservation of energy to calculate the
effects of a collision?
Answer:
B
Explanation:
In a collision some of the kinetic energy of the object convert into thermal energy and sound. It's not so easy to measure thermal and sound energy. That's why it's difficult to use law of conservation of energy.
Alert: Energy is always conserved.
A ball is thrown vertically upward with a speed v. An identical second ball is thrown upward with a speed of 1/2 v (half as fast). What is the ratio of the maximum height of the second ball to that of the first ball
Answer:
1:4
Explanation:
The formula for calculating the maximum height of the ball is expressed as;
H = u²sin²theta/2g
If a ball is thrown vertically upward with a speed v, its maximum height is expressed as;
H = v²sin²90/2g
Since sin90 = 1
H = v²/2g.... 1
If an identical second ball is thrown upward with a speed of 1/2 v, then the maximum height will be expressed as;
H1 = (1/2v)²sin²90/2g
H1 = (v²/4)(1)/2g
H1 = v²/8g ...... 2
Divide both equations
H/H1 = (v²/2g)/(v²/8g)
H/H1 = v²/2g × 8g/v²
H/H1 = 8g/2g
H/H1 = 4
Reciprocate both sides
H1/H = 1/4
H1:H = 1:4
Hence the ratio of the maximum height of the second ball to that of the first ball is 1:4
a student tries to produce notes of higher frequency by blowing a trumpet harder. he will succeed?
Answer:
Please mark as Brainliest!!
Explanation:
He will not succeed as it blows the trumpet harder that only increase the amplitude of the sound wave that means the intensity of the sound will increase but the frequency remains the same.
Answer:
he wont
Explanation:
A rocket is fired vertically upwards starting frkm rest. It accelerates at 30m/s for 4secs. At the end of 4secs it runs out of fuel but continues to rise. How long does it rise with reference to firing position?
Answer:
t = 16.5 s
Explanation:
First we apply first equation of motion to the accelerated motion of the rocket:
[tex]v_{f1} = v_{i1} + at_{1}[/tex]
where,
vf₁ = final speed of rocket during accelerated motion = ?
vi₁ = initial speed of rocket during accelerated motion = 0 m/s
a = acceleration of rocket during accelerated motion = 30 m/s²
t₁ = time taken during accelerated motion = 4 s
Therefore,
[tex]v_{f} = 0\ m/s + (30\ m/s^2)(4\ s)\\\\v_{f} = 120\ m/s[/tex]
Now, we analyze the motion rocket when engine turns off. So, the rocket is now in free fall motion. Applying 1st equation of motion:
[tex]v_{f2} = v_{i2} + g t_{2}[/tex]
where,
vf₂ = final speed of rocket after engine is off = 0 m/s
vi₂ = initial speed of rocket after engine is off = Vf₁ = 120 m/s
g = acceleration of rocket after engine is off = - 9.8 m/s² (negative sign for upward motion)
t₂ = time taken after engine is off = ?
Therefore,
[tex]0\ m/s = 120\ m/s + (- 9.8\ m/s^2)(t_{2})\\\\t_{2} = \frac{120\ m/s}{9.8\ m/s^2}\\\\t_{2} = 12.25\ s[/tex]
So, the time taken from the firing position till the stopping position is:
[tex]t = t_{1} + t_{2}\\\\t = 4 s + 12.5 s[/tex]
t = 16.5 s
if a quarterback applies a 100N force on a football for a distance of .5m, how much work does he do on the ball
PLEASE HELP
Explanation:
Work done = F * d = 100N * 0.5m = 50J.
I NEED THE ANSWER ASAP
A sled accelerates to the right with a value of 10 m/s^2. There is a force acting to the left the is 80 N. If the mass of the sled is 40 kg, what must be the force acting to the right?
Answer:
m/s^-30
Explanation:
John wants a new video tape and a new shirt, but he only has $12.00. He buys the video tape and gets $0.52 change. What was his opportunity cost?
Answer:
You have the answer in your comments. I will be copying it so your question doesn't get deleted.
The answers is $0.58
$11.48
the video tape
the new shirt