Is AABC-ADEP? If so, identify the similarity postulate or theorem that
applies.
B
16
105°
5-105
4
36
A
C
D
9
F
I

Is AABC-ADEP? If So, Identify The Similarity Postulate Or Theorem Thatapplies.B161055-105436ACD9FI

Answers

Answer 1

Answer:

D. cannot be determined

Step-by-step explanation:

that is kind of a trick question.

right based on the given information none of the 3 methods can be applied.

we don't have all 3 sides for SSS

we don't have 2 angles for AA

and we don't have 2 sides with their included angle for SAS.

but it can still be determined (they ARE similar), as this is a special case of SSA, where it is clear that the corresponding congruent angles are located at the same position relatively to the corresponding similar lines.

you can discuss this with your teacher, if you are interested.

AND - we can easily determine any of the other missing pieces (side and angles). these missing pieces then will correspond exactly to their counterparts in the other triangle (the 2 angles in ABC are equal to the 2 angles in DEF, the missing sides file the same scaling factor as the other known sides). and then any of the 3 methods can be applied.

so, this is actually tricky ...


Related Questions

Write the rational number as a decimal.

−11/5

Answers

-11/5 = -11 ÷ 5 = -2.2

Answer:

-2.2

Why should people conserve energy? (Please don’t get the answer form the internet)

Answers

People should conserve energy because it produces a higher quality of life. Reduced emissions result in cleaner air quality. It also helps create a healthier planet and helps sustain resources we have.

What is the value of h(2)?

-2

-1

0

3

Answers

It should be 0 and BECAREFUL not 3
I think 0. I think so

Help me pleassseeeee

Answers

Answer:

8x+(-20x)

Step-by-step explanation:

I don’t understand how to do this.

Answers

Answer:

46degrees

Step-by-step explanation:

From the question, we are told that both triangles are similar, hence;

<E = <S

<D = <R

<F = <T

From triangle DEF

<D + <F + <E = 180

Since <D = <F = 67

67 + 67 + <E = 180

134 + <E = 180

<E = 180 - 134

<E = 46degrees

Since <E = <S, hence the measure of <S  is 46degrees

Question 13
<
Given the function C(t) = (t – 6)(t + 1)(t – 7)
its C-intercept is=
I
its t-intercepts are =

Answers

Answer:

The c intercept is 42

The t intercepts are: 6, -1 and 7

Step-by-step explanation:

Given

[tex]c(t) = (t - 6)(t +1)(t-7)[/tex]

Solving (a): The c intercept

Simply set t to 0

[tex]c(t) = (t - 6)(t +1)(t-7)[/tex]

[tex]c(0) = (0 - 6)(0 +1)(0-7)[/tex]

[tex]c(0) = (- 6)(1)(-7)[/tex]

[tex]c(0) = 42[/tex]

Solving (b): The t intercept

Simply set c(t) to 0

[tex]c(t) = (t - 6)(t +1)(t-7)[/tex]

[tex](t - 6)(t +1)(t-7) = 0[/tex]

Split

[tex]t - 6= 0,\ \ t +1= 0,\ \ t-7 = 0[/tex]

Solve for t

[tex]t = 6,\ \ t =-1,\ \ t=7[/tex]

help plsss it’s timed i need to passss plsss

Answers

Answer:

65°

Step-by-step explanation:

To obtain Angle A, we use the cosine rule ;

Cos A = (b² + c² - a²) / 2bc

Cos A = (12² + 14² - 14²) / 2(12)(14)

Cos A = 144 / 336

A = Cos^-1(144/336)

A = 64.62°

A = 65°

Bryan is sitting on a bench in the mall. He noticed that 18 out of the last 60 men who walked by had a beard . Considering this data how many of the next 90 men who walk by should Bryan expect to have a beard?

Answers

Answer:

27

Step-by-step explanation:

every 30 men = 9 men with beards

you have 30 3 times in 90 so you get 27

60÷2=30

18÷2=9

30 men normal = 9 men with beards

90÷30=3

3×9=27

can we say ((-16)÷4) ÷ (-2) is the same as (-16)÷ (4÷(-2)?

Answers

Answer:

no we can't

Step-by-step explanation:

(-4)÷(-2). (-16÷(-2)

2. 8

[tex]\longrightarrow{\blue{[( - 16)\div 4) \div ( - 2)] \:is\:not\:equal\:to\:( - 16) \div [4 \div( - 2) ] }}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex][( - 16 )\div 4) \div ( - 2)] = ( - 16) \div [4 \div( - 2) ][/tex]

Let us first solve for L. H. S.

[tex] = [( - 16 )\div 4) \div ( - 2)][/tex]

[tex] = [ (\frac{ - 16}{4} )\div ( - 2)][/tex]

[tex] = \frac{( - 4)}{( - 2)} [/tex]

[tex] = 2[/tex]

Now, R. H S.

[tex]( - 16) \div [4 \div ( - 2)][/tex]

[tex] = \frac{ - 16}{ - 2} [/tex]

[tex] = 8[/tex]

[tex]\sf\purple{L. H. S.\: ≠ \:R. H. S. }[/tex]

Hence, [tex][( - 16) \div 4) \div( - 2)] ≠(-16)\div [4 \div( - 2) ][/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

What is the least common denominator of rational expressions with the given denominators? 4a^2, 6a, and 10b
( please do not respond to this if you are going to spam my question)

Answers

Iondont know sorryy

ang tamang yunit para masukat sng area ng panyo ay​

Answers

Answer:

ang sentimeter ay ang tamang yunit ng pagsukat para sa pagsukat sa lugar ng isang panyo

Q23. Find the value of k, if x = 2, y = 1 is a solution of the equation 2x + 3y = k.​

Answers

Answer:

k=7

Step-by-step explanation:

2x+3y=k

2(2)+3(1)=k

4+3=k

k=7

Answer:

7.

Step-by-step explanation:

Substitute x = 2 and y = 1 into the given equation:

2(2) + 3(1) = k

4 + 3 = k

k = 7.

Can someone help I forgot what formal to use?

Answers

Answer:

1) V = 336mm

2) V = 64.33ft

Step-by-step explanation:

1) V = lwh + lwh

V = 4(6)(5) + 9(6)(4)

V = 120 + 216

V = 336mm

2) V = [tex]\frac{1}{3}[/tex][tex]\pi[/tex][tex]r^{2}[/tex]h +  

Cone = [tex]\frac{1}{3}[/tex][tex]\pi[/tex][tex]r^{2}[/tex]h

Cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h

V = [tex]\frac{1}{3}[/tex][tex]\pi[/tex][tex](1.5)^{2}[/tex](3) +

V = [tex]\pi[/tex][tex](1.5)^{2}[/tex] +

V = 7.07 + 57.26

V = 64.33ft

PLEASE HELP!!!
-Graphing Linear Inequalities
What is the difference between solid and dashed lines?

Answers

Inequalities that use < or > symbols are plotted with a dashed line to show that the line is not included in the region. Inequalities that use ≤ or ≥ symbols are plotted with a solid line to show that the line is included in the region. For example, this graph shows the inequality .

Which expression is equivalent to 4p^-4 10q -3? Assume ​

Answers

Step-by-step explanation:

Derive an expression for the equivalent width in a saturated line. Assume a Voigt profile, with the difference in optical depth between the center of the line and the wings being ~104. The wings of the line can be ignored. Define a frequency x1 = (v1 − v0)/ΔvD, where the optical depth τv = 1. Inside of x1 the line is fully saturated, and outside x1 the line is optically thin. Show that the equivalent width is

Note that the equivalent width is practically insensitive to the number density of absorbing material.

Which of these graphs represents a function?

Answers

Answer:

[tex]{ \tt{graph \: y \:and \:graph\: z}}[/tex]

Help me pls this is hard

Answers

Answer:

I guess it is the Answer C

Answer:

C

The distance around the edge of the circle

1.What are the coordinates of the vertices of ABC? Use the coordinates to find the lengths of AC and AB .
2.Use the distance formula to find BC. Show your work.

Answers

Answer/Step-by-step explanation:

1.

✔️Coordinates of vertices ABC:

A(2, 2)

B(6, 2)

C(2, -1)

✔️AC = |2 - (-1)| = 3 units

AB = |2 - 6| = 4 units

2. Distance formula => [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Distance between B(6, 2) and C(2, -1):

[tex] BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Where,

[tex] B(6, 2) = (x_1, y_1) [/tex]

[tex] C(2, -1) = (x_2, y_2) [/tex]

[tex] BC = \sqrt{(2 - 6)^2 + (-1 - 2)^2} [/tex]

[tex] BC = \sqrt{(-4)^2 + (-3)^2} [/tex]

[tex] BC = \sqrt{16 + 9} = \sqrt{25} [/tex]

[tex] BC = 5 units [/tex]

Answer:

The person above me has the correct answer and solves it in the correct way.

Step-by-step explanation:

This is what I used as my answer though.

Distance Formula: d = √(x2-x1)^2 + (y2-y1)^2 

BC = √(x2-x1)^2 + (y2-y1)^2 

B = (6,2)

C = (2,-1)

BC = √(2-6)^2 + (-1-2)^2 

BC = √(-4)^2 + (-3)^2 

BC = √16+9

BC = √25

BC = 5

ok and again i just dont understand well so this is why i am asking so many times and u guys and girls are getting alot of points

Answers

Answer:

The answer is A

Step-by-step explanation:

The right answer is A

How do I solve this problem in 8th grade math
X - (-25) = -50

Answers

Answer:

try the meeting was a good friend of mine for the first person in my family who has been a great friend for any

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: x = - 75}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex]x - ( - 25) = - 50[/tex]

➺ [tex] \: x + 25 = - 50[/tex]

➺ [tex] \: x = - 50 - 25[/tex]

➺ [tex] \: x = - 75[/tex]

Therefore, the value of [tex]x[/tex] is -75.

[tex]\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}[/tex]

[tex]x - ( - 25) = - 50[/tex]

➺ [tex] \: - 75 + 25 = 50[/tex]

➺ [tex] \: - 50 = - 50[/tex]

➺ L. H. S. = R. H. S.

Hence verified.

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Out of 90 civil servants, 65 were working in the office, 50 were working in the field and 35 were working in both the premises (sites). How many civil servants were absent? How many civil servants were working in the field only? Represent the above information in the Venn diagram. 1​

Answers

Answers:

10 people absent15 people working in the field onlySee the below image for the venn diagram

=======================================================

Explanation:

35 people are working in both places. 50 work in the field or both, so 50-35 = 15 people work solely in the field. 65 work in the office or both, so 65-35 = 30 people work solely in the office

So far that accounts for 15+30+35 = 80 people who work in the field, the office, or both.

The remaining 90-80 = 10 people are absent.

The venn diagram is below.

You work for a company in the marketing department. Your manager has tasked you with forecasting sales by month for the next year. You notice that over the past 12 months sales have consistently gone up in a linear fashion, so you decide to find a regression equation for the company's sales history. You find that the regression equation for the data is (sales) = 25.614*(time) + 5.499. Interpret the slope.

a. When sales increases by 1 unit, time increases by 5.499 months.
b. We are not given the dataset, so we cannot make an interpretation.
c. When sales increases by 1 unit, time increases by 25.614 months.
d. When time increases by 1 month, sales increases by 5.499 units.
e. When time increases by 1 month, sales increases by 25.614 units.

Answers

It’s A. when sales increases by 1 unit,

Orla weighed 3.77kg when she was born.
On Orla's second birthday she weighed 12.8kg.
Calculate the percentage increase in her weight.

Answers

Answer :

70.5% weight increase

(Show full work please) Carter spots an airplane on radar that is currently approaching in a straight line, and
that will fly directly overhead. The plane maintains a constant altitude of 7250 feet.
Carter initially measures an angle of elevation of 16 to the plane at point A. At some
later time, he measures an angle of elevation of 26° to the plane at point B. Find the
distance the plane traveled from point A to point B. Round your answer to the
nearest foot if necessary

Answers

Consult the attached diagram.

In the larger triangle,

tan(16°) = (7250 ft) / (x + y)

and in the smaller triangle,

tan(26°) = (7250 ft) / y

You want to solve for x.

From the first equation (I'm ignoring units from here on, all distances are measured in ft), you have

(x + y) tan(16°) = 7250

x tan(16°) + y tan(16°) = 7250

x tan(16°) = 7250 - y tan(16°)

x = 7250 cot(16°) - y

From the second equation,

y = 7250 cot(26°)

Solving for x gives

x = 7250 cot(16°) - 7250 cot(26°)

x = 7250 (cot(16°) - cot(26°))

x ≈ 10,433 ft

The distance the plane traveled from point A to point B is 10,433 ft.

We have given that,

Carter spots an airplane on the radar that is currently approaching in a straight line, and that will fly directly overhead.

The plane maintains a constant altitude of 7250 feet.

In the larger triangle,tan(16°) = (7250 ft) / (x + y)and in the smaller triangle,

What is the tan ratio?

[tex]tan(\ theta)=\frac{\\opposite \side }{hypotenouse}[/tex]tan(26°) = (7250 ft) / y

we have to solve for x.

From the first equation (I'm ignoring units from here on, all distances are measured in ft),

you have

(x + y) tan(16°) = 7250

x tan(16°) + y tan(16°) = 7250

x tan(16°) = 7250 - y tan(16°)

x = 7250 cot(16°) - y

From the second equation,

y = 7250 cot(26°)

Solving for x gives

x = 7250 cot(16°) - 7250 cot(26°)

x = 7250 (cot(16°) - cot(26°))x ≈ 10,433 ft

Therefore the distance the plane traveled from point A to point B is 10,433 ft.

To learn more about altitude visit:

https://brainly.com/question/22736499

#SPJ2

Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)

Answers

Answer : 424.875 miles

The problem states that Brian can travel ‘27.5’ miles per gallon, and his tank can only hold ‘15.45’ gallons of fuel.

To find the miles he can travel, all you have to do is multiply the miles he can travel per gallon (27.5) by the gallons he has in the tank (15.45).

This gives you the answer of 424.875 miles.

Answer:

27.5 miles per gallon

1 full tank = 15.45 gallons

27.5 x 15.45 = 424.875 miles

rounded to the nearest 100th: 424.88 miles

nearest 10th: 424.9 miles

nearest whole #: 425 miles

2.) Find the zeros of the quadratic function y = x2 – 3x + 2 by factoring method. ​

Answers

Problem:-

2.) Find the zeros of the quadratic function y = x2 – 3x + 2 by factoring method.

Solution:-

[tex]\sf{Set\:y = 0. Thus, }[/tex]

[tex]\sf\rightarrow{0 = x2 – 3x + 2} [/tex]

[tex]\sf\rightarrow{0 = ( x – 2) ( x – 1)}[/tex]

[tex]\sf\rightarrow{x – 2 = 0 or x – 1 = 0} [/tex]

[tex]\sf{Then\:x = 2\:and\:x = 1}[/tex]

Answer:-The zeros of y = x² – 3x + 2 are 2 and 1.=====================

#CarryOnLearning

(ノ^_^)ノ

Let V be the set of all 3x3 matrices with Real number entries, with the usual definitions of scalar multiplication and vector addition. Consider whether V is a vector space over C. Mark all true statements (there may be more than one).

a. The scalar closure axiom is satisfied
b. The additive inverse axiom is not satisfied
c The additive inverse axiom is satisfied
d. The additive closure axiom is not satisfied
e. The scalar closure axiom is not satisfied
f. The additive closure axiom is satsified
g. V is not a vector space over C
h. V is a vector space over C
i. The zero axiom is satisfied
j. The zero axiom is not satisfied

Answers

Answer:

the Scalar Closure axiom is not satisfiedV is not a Vector Space of CThe Additive Closure axiom is satisfied.

Step-by-step explanation:

According to the Question,

Given That, Let V be the set of all 3x3 matrices with Real number entries, with the usual definitions of scalar multiplication and vector addition. Consider whether V is a vector space over C.For V is a vector space over C and V is Set of 3x3 Matrices with Real entries.

Then, For any u,w ∈ V ⇒ u+w ∈ V

And u∈V and z∈C ⇒ z u ∈ V

So, If we take any z= i ∈ C

and V be any 3x3 matrices with Real entrices.

then, z,v ∉ V  ∴z,v Has Complex entries

So, the Scalar Closure axiom is not satisfied

Hence, V is not a Vector Space of C

Any u,w ∈ W ⇒ u+w ∈ V

So, The Additive Closure axiom is satisfied.

Một hộp đựng 10 phong bì bốc thư trúng thưởng trong đó 3 phong bì đựng 500 nghìn 7 phong bì đựng 100 nghìn. Bốc ngẫu nhiên liên tiếp hai phong bì. Nếu biết phong bì thứ hai có 500 nghìn, tìm xác xuất để phong bì đầu tiên cũng có 500 nghìn?

Answers

I can't understand tell me in english

Given f(x) = x2 + 24 - 12, find f(3)

Answers

Answer:

f(3) = 12

Step-by-step explanation:

f(3) = (3 x 2) + 24 - 12

     = 6 + 24 - 12

f(3) = 12

If this helps you, please give brainliest!

Answer:

Step-by-step explanation:

f(x) = [tex]x^{2}[/tex] + 24 - 12

substitute 3 inplace of x

f(3) = [tex]3^{2}[/tex] + 24 - 12

=9 + 24 - 12

21

If the question is f(x) = x2 + 24 - 12     {x*2 + 24 - 12}

now substitute 3 in place of x

f(3) = 3*2 + 24 - 12

=6 + 24 - 12

18

please helpppppppppp

Answers

Answer:

Step-by-step explanation:

b = sqrt(2 * L)                 Given

L = 4.5                            Given

b = sqrt(2 * 4.5)

b = sqrt(9)

b = 3

Answer:

b = 9

Step-by-step explanation:

Given :-

[tex] \small \sf \: b = \sqrt{2 \it \: l} [/tex]

[tex] \small \: l = 4.5[/tex]

Solution :-

[tex] \small \sf \: b = \sqrt{2 \it \: l} [/tex]

plug the values of l in the equation

[tex] \small \sf \leadsto \: b = \sqrt{2 × 4.5} [/tex]

[tex] \small \sf \leadsto \: b = \sqrt{9} [/tex]

[tex] \small \sf \leadsto \: b = 9 [/tex]

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