Answer:
No a rhombus is not a rectangle
Step-by-step explanation:
How do you find the x-intercept of a parabola?
Please help me! How much would you expect gas to cost in 2030. Show your work.
Answer:World Bank expects the natural gas price at Henry Hub to increase to $4 per MMBtuStep-by-step explanation:
- The two rectangles shown have equal areas. Find the value of x.
9 ft
4 ft
(6x + 6) ft
4x ft
The percentage of obese children aged 12-19 years in the United States is approximately P(t) = 0.04t + 4.6 if 0 ≤ t < 10 −0.01005t2 + 0.945t − 3.4 if 10 ≤ t ≤ 30 where t is measured in years, with t = 0 corresponding to the beginning of 1970. What was the percentage of obese children aged 12-19 at the beginning of 1975? At the beginning of 1985? At the beginning of 1990?† (Round your answers to two decimal places.) 1975 % 1985 % 1990 %
Answer:
1975------ 4.8%
1990 ------ 11.48%
1985 ------ 8.51%
Step-by-step explanation:
Given
[tex]P(t) = 0.04t + 4.6[/tex] if 0 ≤ t < 10
[tex]P(t) = -0.01005t^2 + 0.945t - 3.4[/tex] if 10 ≤ t ≤ 30
Where
t:=0 implies year = 1970
Solving (a): Beginning of 1975.
First, we calculate the value of t
[tex]t = 1975 - 1970[/tex]
[tex]t = 5[/tex]
This falls in the range: 0 ≤ t < 10
So:
[tex]P(t) = 0.04t + 4.6[/tex]
[tex]P(5) = 0.04 * 5 + 4.6[/tex]
[tex]P(5) = 4.80[/tex]
Solving (b): Beginning of 1990.
[tex]t = 1990 - 1970[/tex]
[tex]t = 20[/tex]
This falls in the range: 10 ≤ t ≤ 30
So:
[tex]P(t) = -0.01005t^2 + 0.945t - 3.4[/tex]
[tex]P(20) = -0.01005*20^2 + 0.945*20 - 3.4[/tex]
[tex]P(20) = 11.48[/tex]
Solving (c): Beginning of 1985
[tex]t = 1985 - 1970[/tex]
[tex]t = 15[/tex]
This falls in the range: 10 ≤ t ≤ 30
So:
[tex]P(t) = -0.01005t^2 + 0.945t - 3.4[/tex]
[tex]P(15) = -0.01005*15^2 + 0.945*15 - 3.4[/tex]
[tex]P(15) = 8.51375[/tex]
[tex]P(15) = 8.51[/tex]
Axis of sym: x =
Vertex: (
,
)
Do not do the domain
Range: Pick one: A. y≥4 B. y<4 C. y≤4 D. y≤−2 E. y<−2
The Range is
Zeros:
and
Equation:
Answer:
SEE BELOWStep-by-step explanation:
to understand thisyou need to know about:quadratic functionPEMDASlet's solve:vertex:(h,k)
therefore
vertex:(-1,4)
axis of symmetry:x=h
therefore
axis of symmetry:x=-1
to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0vertex form of quadratic equation:
y=a(x-h)²+ktherefore
y=a(x-(-1))²+4y=a(x+1)²+4it's to notice that we don't know what a is
therefore we have to figure it out
the graph crosses y-asix at (0,3) coordinates
so,
3=a(0+1)²+4
simplify parentheses:
[tex]3 = a(1 {)}^{2} + 4[/tex]
simplify exponent:
[tex]3 = a + 4[/tex]
therefore
[tex]a = - 1[/tex]
our vertex form of quadratic equation is
y=-(x+1)²+4let's simplify it to standard form
simplify square:
[tex]y = - ( {x}^{2} + 2x + 1) + 4[/tex]
simplify parentheses:
[tex]y = - {x}^{2} - 2x - 1 + 4[/tex]
simplify addition:
[tex]y = - {x}^{2} - 2x + 3[/tex]
therefore our answer is D)y=-x²-2x+3
the domain of the function
[tex]x\in \mathbb{R}[/tex]
and the range of the function is
[tex]y\leqslant 4[/tex]
zeroes of the function:
[tex] - {x}^{2} - 2x + 3 = 0[/tex]
[tex] \sf divide \: both \: sides \: by \: - 1[/tex]
[tex] {x}^{2} + 2x - 3 = 0[/tex]
[tex] \implies \: {x}^{2} + 3x - x + 3 = 0[/tex]
factor out x and -1 respectively:
[tex] \sf \implies \: x(x + 3) - 1(x + 3 )= 0[/tex]
group:
[tex] \implies \: (x - 1)(x + 3) = 0[/tex]
therefore
[tex] \begin{cases} x_{1} = 1 \\ x_{2} = - 3\end{cases}[/tex]
QR has a midpoint at M(8,8). Point R is at (10, 10). Find the coordinates of point Q. Write the coordinates as decimals or integers.
Answer:
Point Q: ( 6, 6)
Step-by-step explanation:
(10, 10)
- 2 (8, 8)
( 6, 6)
Answer:
Point Q is at (6, 6).
Step-by-step explanation:
Segment QR has a midpoint M at (8, 8).
Point R is at (10, 10), and we want to determine the location of Point Q.
First, recall that the midpoint is given by the formula:
[tex]\displaystyle M=\Big(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\Big)[/tex]
We will let R(10, 10) be (x₁, y₁). We are also given that M is at (8, 8). Therefore:
[tex]\displaystyle (8, 8)=\Big(\frac{10+x}{2}, \frac{10+y}{2}\Big)[/tex]
This gives us two cases:
[tex]\displaystyle \frac{10+x}{2}=8\text{ and } \frac{10+y}{2}=8[/tex]
Solve for each case. Multiply both sides by 2:
[tex]10+x=16\text{ and } 10+y=16[/tex]
And we can subtract 10 from both sides:
[tex]x=6\text{ and } y=6[/tex]
Therefore, Point Q is at (6, 6).
Rewrite the number in Standard form
1.37 x 10-7
*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆
Answer: 0.000000137
Explanation:
I hope this helped!
<!> Brainliest is appreciated! <!>
- Zack Slocum
*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆
Is KLMN below a rectangle?
Algebra 2
Could u help me pls
Answer:
log150=2.1716091259
Step-by-step explanation:
Press it on your calculator
what is the difference in hours and minutes between these times 10:35 2:40
Answer:
10:35
11:35
12:35
1:35
2:35
=Thats 4 hours
and then 40-35=5
So 4hours 5 minutes
Answer:
yeah
Step-by-step explanation:
im reply cause I want to ask a questionbx
Write the polynomial in standard form: I need help with this
Write the polynomial in standard form:
18
Help plssss!!!!!!! 10 points
Answer:
16 every 2 years, or 8 more per year
a rectangular prism has a lenth of 2/3,a width of 1/2 and a height of 1/3 find the volume
Answer:
2/18 = 1/9
Step-by-step explanation:
2/3 x 1/3 = 2/9
2/9 x 1/2 = 1/9
What is the mean?
1 2 1 3 6 3 6 2
What ratio is not equivalent to the ratio 10:35 please help
Step-by-step explanation:
Personally I think the answer is 2:7
I might be wrong but that is my opinion
Plz I really need help
Answer:
.. it's 30 or 50
Step-by-step explanation:
3
A Rubik's Cube has a volume of 10 cm
1) Write an equation to find the length of the sides.
2) Find the length of the side to the nearest tenth.
Answer:
The formula to find the value of the side is X ^ 3 = 10, and the side measures 2.15 cm.
Step-by-step explanation:
Given that a Rubik's Cube has a volume of 10 cm, to write an equation to find the length of the sides and find the length of the side to the nearest tenth, the following calculations must be performed, knowing that the volume of a cube is obtained to enhance one of its sides to the third:
X ^ 3 = 10
X = 3√ 10
X = 2.15
Thus, the formula to find the value of the side is X ^ 3 = 10, and the side measures 2.15 cm.
Select the correct answer.
Which pair of statements correctly compares the two data sets?
O
0
1
2
3
4
5
6
7
8
9
10
11
12
13
0
1
2
3
4
5
6
7
8
9
10
11
12
13
OA. The difference of the means is 1. This value is less than half of the mean absolute deviation of either data set.
OB .
The difference of the means is 1. This value is more than half of the mean absolute deviation of either data set.
OC The difference of the means is 1. This value is 1 times the mean absolute deviation of either data set.
OD. The difference of the means is 1. This value is 2 times the mean absolute deviation of either data set.
PLZ HELP 44POINTS
Answer:
A.
Step-by-step explanation:
✔️Find the Mean and Mean Absolute Value of the first data set:
Write out the data values:
1, 2, 4, 4, 5, 5, 6, 7, 9, 9, 9, 11
Mean = sum of all data values ÷ number of data values in the data set
Mean = 72 ÷ 12 = 6
M.A.D = sum of |data value - mean| ÷ the number of data values
|1 - 6| = 5
|2 - 6| = 4
|4 - 6| = 2
|4 - 6| = 2
|5 - 6| = 1
|5 - 6| = 1
|6 - 6| = 0
|7 - 6| = 1
|9 - 6| = 3
|9 - 6| = 3
|9 - 6| = 3
|11 - 6| = 5
Sum of |data value - mean| = 30
M.A.D = 30 ÷ 12 ≈ 2.5.
✔️Find the mean and M.A.D of the second data set following the same steps and formula:
Write out the data:
1, 3, 4, 6, 6, 6, 7, 9, 9, 10, 10, 13
Mean = 84 ÷ 12 = 7
Sum of |data value - mean| = 32
M.A.D = 32 ÷ 12 = 2.7
✔️Comparing both data sets,
The difference of the means = 7 - 6 = 1
Thus, the value of this difference, 1, is less than half of the M.A.D of both sets, 2.5 and 2.7.
WILL MARK!! pls help:)
Find x and y so that ABCD will be a parallelogram.
Answer:
your answer will be B. 46
Step-by-step explanation:
hope it helps you...
have a great day!!!
A.63
B.54
C.99
D.126
Answer:
C
Step-by-step explanation:
Area = (8 + 14) x 1/2 x 9
Area = 22 x 1/2 x 9
Area = 11 x 9
Area = 99
Hope that helps!
-Sabrina
If
f(x) = 9x
- 6 and
g(x) = x - 4, which statement is true?
Click on the correct answer.
1 is in the domain of fºg.
1 is not in the domain of fºg.
Answer: 1 is not in the domain of f g.
Step-by-step explanation:
Find the value of x.
The answer would be x=18. First you set it up by setting up an equation;
166=7x+40. Then you subtract 40 from each side. Last, you divide both sides by 7 and you should get x=166 or 166=x.
I need help please.
Step-by-step explanation:
if I had to guess it's probably true
Please help I will give u points
What is the sum?
3(2x + 3) + 2(x + 5)
Answer:
A: 8x + 19
Step-by-step explanation:
3(2x+3) = 6x + 9
2(x+5) = 2x + 10
6x+9 + 2x+10 = 8x + 19
The largest
apple pie has
radius of 20
feet. What was
its area?
WILL MARK! Please help:)
Find x so that this quadrilateral is a parallelogram.
Answer:
46
Step-by-step explanation:
Answer:
46 bc the angles across from each other are the same in a parallelogram
Find x
I got 5 but I don’t know if that’s correct. Please help
Let f be defined by the function f(x) = 1/(x^2+9)
(a) Evaluate the improper integral [tex]\int\limits^{∞}_3 {f(x)} \, dx[/tex] or show that the integral diverges
(b) Determine whether the series ∑n=3∞ f(n) converges or diverges State the conditions of the test used for determining convergence or divergence
(c) Determine whether the series ∑n=1∞(−1)n(en⋅f(n))=∑n=1∞(−1)n(n2+9)en converges absolutely, converges conditionally, or diverges (image put below)
(a)
[tex]\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}[/tex]
Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :
[tex]\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt[/tex]
[tex]=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}[/tex]
(b) The series
[tex]\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}[/tex]
converges by comparison to the convergent p-series,
[tex]\displaystyle\sum_{n=3}^\infty\frac1{n^2}[/tex]
(c) The series
[tex]\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}[/tex]
converges absolutely, since
[tex]\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}[/tex]
That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.
what is a single term algebraic expression is called?