..............is a piece of hardware used to provide data and instructions to a computer used for interaction and control. *
Output device.
Processing.
input device.
All of above. ​

Answer:

Explanation:

so this is what "format" is about,   it's saying what do the ones and zeros represent.   b/c the bits can represent lots of different things ,  like letters with ascii code ,   and that's got several types.  some are 8 bits,  some are 16 bits,  the questions  you've shown are in groups of 5 which is really not a "thing" in binary,  it's always by twos,   without some type of  "frame work"  around the bits, we won't know what they represent,  if that is helping?   the important part is what is the "frame work"   that these bits are in.

all of your questions seem to have some  "art"  thing going on,  they make some kinda of binary artwork,  for what they are saying, that's not what's important.  Other than if they form  palindromes,   maybe that's what the questions are really about, how these do from palindromes, that is, they read the same backwards as forwards... I know.. why would anyone read backwards.. but a computer can do that pretty quickly,  sooo sometimes to check,  it will read  forwards and backwards.. but when there is a palindrome,  the computer is "confused"  

this is also a big big part of  "typing"  not like on a keyboard but when you program, and you say that  your variables are of a certain type,  like a char, or a string, or a double, you are specifying how many bits will be used to represent your data.  so then when you put the ones and zeros into the memory ,  ( think RAM)  then it's stored in groups of what ever size you've determined.    hmmmm   does this help?

Answer:

The Open Software Foundation (OSF) was a not-for-profit industry consortium for creating an open standard for an implementation of the operating system Unix. It was formed in 1988 and merged with X/Open in 1996, to become The Open Group.

Explanation:

YOUR PROFILE PIC IS CUTE :)

Answer:

The function in C++ is as follows:

int isSorted(int ar[], int n){

if ([tex]n == 1[/tex] || [tex]n == 0[/tex]){

 return 1;}

if ([tex]ar[n - 1][/tex] < [tex]ar[n - 2][/tex]){

 return 0;}

return isSorted(ar, n - 1);}

Explanation:

This defines the function

int isSorted(int ar[], int n){

This represents the base case; n = 1 or 0 will return 1 (i.e. the array is sorted)

if ([tex]n == 1[/tex] || [tex]n == 0[/tex]){

 return 1;}

This checks if the current element is less than the previous array element; If yes, the array is not sorted

if ([tex]ar[n - 1][/tex] < [tex]ar[n - 2][/tex]){

 return 0;}

This calls the function, recursively

return isSorted(ar, n - 1);

}

Answer:

A class may be a structured diagram that describes the structure of the system.  

It consists of sophistication name, attributes, methods, and responsibilities.  

A mailbox and an email message have certain attributes like, compose, reply, draft, inbox, etc.

Software architecture affects:

Performance, Robustness, Distributability, Maintainability.  

Explanation:

See attachment for the Model object classes which may be utilized in the system implementation to represent a mailbox and an email message.

Advantages:

Large-scale reuse Software architecture is vital because it affects the performance, robustness, distributability, and maintainability of a system.

Individual components implement the functional system requirements, but the dominant influence on the non-functional system characteristics is that the system's architecture.

Three advantages of System architecture:

• Stakeholder communication: The architecture may be a high-level presentation of the system which will be used as attention for discussion by a variety of various stakeholders.

• System analysis: making the system architecture explicit at an early stage within the system development requires some analysis.

• Large-scale reuse:

An architectural model may be a compact, manageable description of how a system is organized and the way the components interoperate.

The system architecture is usually an equivalent for systems with similar requirements then can support large-scale software reuse..

Answer:

This is worth 50 dollars.

Explanation:

١ - one

٢ - two

٣ - three

٤ - four

٥ - five

٦ - six

٧ - seven

٨ - eight

٩ - nine

٠ - zero

What you see above is the ten digits in Arabic.

Both 5 (٥) and 0 (٠) appear here, thus representing 50.

Answer: False

Explanation:

The statement that "you fail a course as a MAIN (residency) course, you can repeat that course as either a MAIN (residency) or an online (IG or IIG) course" is false.

It should be noted that if one fail a course as a residency course, the course can only be repeated as a main (residency) course and not an online course. When a course is failed, such course has to be repeated the following semester and this will give the person the chance to improve their GPA.

Answer:

Answer:In this context sound data is stored and transmitted in an analog form. Since computers represent data in digital form, (as bits and bytes) the

Answer:

it would have to be flow control which would be C.

Explanation:

Flow Control is restricts the ability for individuals to reveal information present in some part of the database. Hence, option C is correct.

The management of data flow between computers, devices, or network nodes is known as flow control. This allows the data to be processed at an effective rate. Data overflow, which occurs when a device receives too much data before it can handle it, results in data loss or retransmission.

A design concern at the data link layer is flow control. It is a method that typically monitors the correct data flow from sender to recipient. It is very important because it allows the transmitter to convey data or information at a very quick rate, which allows the receiver to receive it and process it.

The amount of data transmitted to the receiver side without any acknowledgement is dealt with by flow control.

Thus, option C is correct.

For more information about Flow Control, click here:

https://brainly.com/question/28271160

#SPJ5

Answer: Users expect to see a certain pattern in the data

Explanation:

Confirmatory Data Analysis occurs when the evidence is being evaluated through the use of traditional statistical tools like confidence, significance, and inference.

In this case, there's an hypothesis and the aim is to determine if the hypothesis is true. In this case, we want to know if a particular pattern on the data visualization conforms to what we have.

Answer:

The program in C++ is as follows:

#include <iostream>

#include <iomanip>

using namespace std;

int* sortArray(int temp [], int n){

   int tmp;

   for(int i = 0;i < n-1;i++){

 for (int j = i + 1;j < n;j++){

  if (temp[i] > temp[j]){

   tmp  = temp[i];

   temp[i] = temp[j];

   temp[j] = tmp;   }  } }

return temp;

}

float average(int temp [], int n){

   float sum = 0;

   for(int i = 0; i<n;i++){

       sum+=temp[i];    }

   return sum/n;

}

int main(){

   int n;

   cout<<"Number of temperatures: ";    cin>>n;

   while(n>10){

       cout<<"Number of temperatures: ";    cin>>n;    }

   int temp[n];

   for(int i = 0; i<n;i++){

       cout<<"Input temperature "<<i+1<<": ";

       cin>>temp[i];    }

   int *sorted = sortArray(temp, n);

   cout<<"The sorted temperature in ascending order: ";

   for( int i = 0; i < n; i++ ) {  cout << *(sorted + i) << " ";   }

   cout<<endl;

   float ave = average(temp,n);

   cout<<"Average Temperature: "<<setprecision(2)<<ave<<endl;

   cout<<"Highest Temperature: "<<*(sorted + n - 1)<<endl;

   cout<<"Lowest Temperature: "<<*(sorted + 0)<<endl;

   return 0;

}

Explanation:

See attachment for complete source file with explanation

Answer and Explanation:

I and II answered

Interruption: interruption occurs when network is tampered with or communication between systems in a network is obstructed for illegitimate purposes.

Interception: interception occurs when data sent between systems is intercepted such that the message sent to another system is seen by an unauthorized user before it reaches destination. Interception violates confidentiality of a message.

Modification: modification occurs when data sent from a system to another system on the network is altered by an authorized user before it reaches it's destination. Modification attacks violate integrity, confidentiality and authenticity of a message.

Fabrication: fabrication occurs when an unauthorized user poses as a valid user and sends a fake message to a system in the network. Fabrication violates confidentiality, integrity and authenticity.

Complete Question:

A technician needs to manage a Linux-based system from the GUI remotely.  Which of the following technologies should the technician deploy?

A. RDP  

B. SSH  

C. VNC  

D. Telnet

Answer:

Managing a Linux-based System from the GUI Remotely

The technology that the technician should deploy to manage the Graphic User Interface (GUI) remotely is:

C. VNC

Explanation:

VNC stands for Virtual Network Computing. This computing technology enables a remote user to access and control another computer to execute commands. It acts as a cross-platform screen-sharing system and is used to remotely access and control another computer. VNC makes a computer screen, keyboard, and mouse available to be seen and used from a remote distance.  The remote user does everything from a secondary device without being in front of the primary computer or device.  An example of a good VNC is TeamViewer.

the technique used is Data Validation

Answer:

the word processing

Explanation:

the word is a good word

Answer:

Explanation:

Using the main() and Instrument class which can be found online. We can create the following StringInstrument class that extends the Instrument class itself. The only seperate variables that the StringInstrument class posses' would be the number of Strings (numStrings) and the number of frets (numFrets). Due to technical difficulties I have added the code as a seperate text file below.

Answer:

This can be done by a greedy solution. The algorithm does the following:  

Put song 1 on CD1.

For song 1, if there's space left on the present CD, then put the song on the present CD. If not, use a replacement CD.

If there are not any CDs left, output "no solution".

Explanation:  

The main thing is prove the correctness, do that by the "greedy stays ahead argument". For the primary song, the greedy solution is perfect trivially.  

Now, let the optimal solution match the greedy solution upto song i. Then, if the present CD has space and optimal solution puts song (i+1) on an equivalent CD, then the greedy and optimal match, hence greedy is not any worse than the optimal.Else, optimal puts song (i + 1) on subsequent CD. Consider an answer during which only song (i + 1) is moved to the present CD and zip else is modified. Clearly this is often another valid solution and no worse than the optimal, hence greedy is not any worse than the optimal solution during this case either. This proves the correctness of the algorithm. As for every song, there are constantly many operations to try to do, the complexity is O(n).

Answer:

Explanation:

The statement solution was added to the code and then the code was repeated in order to create the second test case with 9 nickels and 0 dimes. The outputs for both test cases can be seen in the attached image below.

import java.util.Scanner;

class AssigningSum {

    public static void main(String[] args) {

        int numCoins;

        int numNickels;

        int numDimes;

        numNickels = 5;

        numDimes = 6;

        /* Your solution goes here */

        numCoins = numNickels + numDimes;

       System.out.print("There are ");

       System.out.print(numCoins);

       System.out.println(" coins");

//        TEST CASE 2

        numNickels = 9;

        numDimes = 0;

        /* Your solution goes here */

        numCoins = numNickels + numDimes;

        System.out.print("There are ");

        System.out.print(numCoins);

        System.out.println(" coins");

}

}

Answer:

Answer:Data Types. Computer systems work with different types of digital data. In the early days of computing, data consisted primarily of text and ...

Answer:

All flags are On ( c, z , N  )

Explanation:

Given data:

4-bit operation

Assuming 2's complement representation

Determine status flags that are on after performing 1010+0110

    1   1

    1  0   1  0

    0  1   1  0

  1  0 0 0 0

we will carry bit = 1 over

hence C = 1

given that: carry in = carry out there will be zero ( 0 ) overflow

hence V = 0

also Z = 1      

But the most significant bit is  N = 1

(c) 4

The function strpos() is a function in php that returns the position of the first occurrence of a particular substring in a string. Positions are counted from 0. The function receives two arguments. The first argument is the string from which the occurrence is to be checked. The second argument is the substring to be checked.

In this case, the string is "Get Well Soon!" while the substring is "Well"

Starting from 0, the substring "Well" can be found to begin at position 4 of the string "Get Well Soon!".

Therefore, the function strpos("Get Well Soon!", "Well") will return 4.

Then, with the echo statement, which is used for printing, value 4 will be printed as output of the code.

Answer:

The output is:

1 2 3 4 5

Explanation:

Given

See attachment for code segment

Required

The output of rec2(5)

From the attached code segment, we have the following:

The base case: if (x==0){ return;}

The above implies that, the recursion ends when the value of x gets reduced to 0

The recursion:

rec2(x-1); ---- This continually reduces x by 1 and passes the value to the function

printf("%d ", x); This prints the passed value of x

Hence, the output of rec2(5) is: 1 2 3 4 5

Answer:

Hmm, I think it is true

Explanation:

Answer:

The answer would be A: Random

Explanation:

The random() function returns a generated random number (a pseudorandom number)

Answer:

Explanation:

The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.

import java.io.*;

import java.util.*;

class Rainfall

{

   Scanner in = new Scanner(System.in);

   private int month = 12;

   private double total = 0;

   private double average;

   private double standard_deviation;

   private double largest;

   private double smallest;

   private double months[];

   public Rainfall()

   {

       months = new double[12];

   }

   public void setMonths()

   {

       for(int n=1; n <= month; n++)

       {

           int answer = 0;

           while (true) {

               System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );

               answer = in.nextInt();

               if (answer > 0) {

                   months[n-1] = answer;

                   break;

               }

           }

       }

   }

   public void getTotal()

   {

       total = 0;

       for(int i = 0; i < 12; i++)

       {

           total = total + months[i];

       }

       System.out.println("The total rainfall for the year is " + total);

   }

   public void getAverage()

   {

       average = total/12;

       System.out.println("The average monthly rainfall is " + average);

   }

   public void getLargest()

   {

       double largest = 0;

       int largeind = 0;

       for(int i = 0; i < 12; i++)

       {

           if (months[i] > largest)

           {

               largest = months[i];

               largeind = i;

           }

       }

       System.out.println("The largest amount of rainfall was " + largest +

               " inches in month " + (largeind + 1));

   }

   public void getSmallest()

   {

       double smallest = Double.MAX_VALUE;

       int smallind = 0;

       for(int n = 0; n < month; n++)

       {

           if (months[n] < smallest)

           {

               smallest = months[n];

               smallind = n;

           }

       }

       System.out.println("The smallest amount of rainfall was " + smallest +

               " inches in month " + (smallind + 1));

   }

   public static void main(String[] args)

   {

       Rainfall r = new Rainfall();

       r.setMonths();

       r.getTotal();

       r.getSmallest();

       r.getLargest();

       r.getAverage();

   }

}

Answer:

I'm unsure of what language you are referring to, but the explanation below is in Python.

Explanation:

a = int(input("Input your first number: "))

b = int(input("Input your second number: "))  

c = int(input("Input your third number: "))

maximum = max(a, b, c)

print("The largest value: ", maximum)

Answer:

Explanation:

The following code is written in Java. It creates the raiseToPower method that takes in two int parameters. It then uses recursion to calculate the value of the first parameter raised to the power of the second parameter. Three test cases have been provided in the main method of the program and the output can be seen in the attached image below.

class Brainly {

   public static void main(String[] args) {

       System.out.println("Base 5, Exponent 3: " + raiseToPower(5,3));

       System.out.println("Base 2, Exponent 7: " + raiseToPower(2,7));

       System.out.println("Base 5, Exponent 9: " + raiseToPower(5,9));

   }

   public static int raiseToPower(int base, int exponent) {

       if (exponent == 0) {

           return 1;

       } else if (exponent == 1) {

           return base;

       } else {

           return (base * raiseToPower(base, exponent-1));

       }

   }

}

Answer:

Explanation:

/* From the information provided, For now will consider the name of table as TRIPGUIDES*/

/*In all the answers below, the syntax is based on Oracle SQL. In case of usage of other database queries, answer may vary to some extent*/

1.

Select R.Reservation_ID, R.Trip_ID , C.Customer_Num,C.Last_Name from Reservation R, Customer C where C.Customer_Num=R.Customer_Num ORDER BY C.Last_Name

/*idea is to select the join the two tables by comparing customer_id field in two tables as it is the only field which is common and then print the desired result later ordering by last name to get the results in sorted order*/

2.

Select R.Reservation_ID, R.Trip_ID , R.NUM_PERSONS from Reservation R, Customer C where C.Customer_Num=R.Customer_Num and C.LAST_NAME='Goff' and C.FIRST_NAME='Ryan'

/*Here, the explaination will be similar to the first query. Choose the desired columns from the tables, and join the two tables by equating the common field

*/

3.

Select T.TRIP_NAME from TRIP T,GUIDE G,TRIPGUIDES TG where T.TRIP_ID=TG.TRIP_ID and TG.GUIDE_NUM=G.GUIDE_NUM and G.LAST_NAME='Abrams' and G.FIRST_NAME='Miles'

/*

Here,we choose three tables TRIP,GUIDE and TRIPGUIDES. Here we selected those trips where we have guides as Miles Abrms in the GUIDES table and equated Trip_id from TRIPGUIDES to TRIP.TRIP_Name so that can have the desired results

*/

4.

Select T.TRIP_NAME

from TRIP T,TRIPGUIDES TG ,G.GUIDE

where T.TRIP_ID=TG.TRIP_ID and T.TYPE='Biking' and TG.GUIDE_NUM=G.GUIDE_NUM and G.LAST_NAME='Boyers' and G.FIRST_NAME='Rita'

/*

In the above question, we first selected the trip name from trip table. To put the condition we first make sure that all the three tables are connected properly. In order to do so, we have equated Guide_nums in guide and tripguides. and also equated trip_id in tripguides and trip. Then we equated names from guide tables and type from trip table for the desired results.

*/

5.

SELECT C.LAST_NAME , T.TRIP_NAME , T.START_LOCATION FROM CUSTOMER C, TRIP T, RESERVATION R WHERE R.TRIP_DATE='2016-07-23' AND T.TRIP_ID=R.TRIP_ID AND C.CUSTOMER_NUM=R.CUSTOMER_NUM

/*

The explaination for this one will be equivalent to the previous question where we just equated the desired columns where we equiated the desired columns in respective fields and also equated the common entities like trip ids and customer ids so that can join tables properly

*/

/*The comparison of dates in SQL depends on the format in which they are stored. In the upper case if the

dates are stored in the format as YYYY-MM-DD, then the above query mentioned will work. In case dates are stored in the form of a string then the following query will work.

SELECT C.LAST_NAME , T.TRIP_NAME , T.START_LOCATION FROM CUSTOMER C, TRIP T, RESERVATION R WHERE R.TRIP_DATE='7/23/2016' AND T.TRIP_ID=R.TRIP_ID AND C.CUSTOMER_NUM=R.CUSTOMER_NUM

*/

6.

Select R.RESERVATION_ID, R.TRIP_ID,R.TRIP_DATE FROM RESERVATION R WHERE R.TRIP_ID IN

{SELECT TRIP_ID FROM TRIP T WHERE STATE='ME'}

/*

In the above question, we firstly extracted all the trip id's which are having locations as maine. Now we have the list of all the trip_id's that have location maine. Now we just need to extract the reservation ids for the same which can be trivally done by simply using the in clause stating print all the tuples whose id's are there in the list of inner query. Remember, IN always checks in the set of values.

*/

7.

Select R.RESERVATION_ID, R.TRIP_ID,R.TRIP_DATE FROM RESERVATION WHERE

EXISTS {SELECT TRIP_ID FROM TRIP T WHERE STATE='ME' and R.TRIP_ID=T.TRIP_ID}

/*

Unlike IN, Exist returns either true or false based on existance of any tuple in the condition provided. In the question above, firstly we checked for the possibilities if there is a trip in state ME and TRIP_IDs are common. Then we selected reservation ID, trip ID and Trip dates for all queries that returns true for inner query

*/

8.

SELECT G.LAST_NAME,G.FIRST_NAME FROM GUIDE WHERE G.GUIDE_NUM IN

{

SELECT DISTINCT TG.GUIDE_NUM FROM TRIPGUIDES TG WHERE TG.TRIPID IN {

SELECT T.TRIP_ID FROM TRIP T WHERE T.TYPE='Paddling'

}

}

/*

We have used here double nested IN queries. Firstly we selected all the trips which had paddling type (from the inner most queries). Using the same, we get the list of guides,(basically got the list of guide_numbers) of all the guides eds which were on trips with trip id we got from the inner most queries. Now that we have all the guide_Nums that were on trip with type paddling, we can simply use the query select last name and first name of all the guides which are having guide nums in the list returned by middle query.

*/

Explanation:

The taskbar contains app buttons that allow you to quickly run the File Explorer or Microsoft Edge apps.

Hope this helps