Answer: All forms of distraction.
Mr Chichester is driving his dark blue camaro to a REO Speedwagon concert. He is driving 15 m/s when he realizes he is going to be late to his favorite band so he slams on the gas for 10s and reaches a final velocity of 45 m/s. How far did Mr. Chichesters travel during this 10s?
Answer:
300m
Explanation:
step one
given data
initial speed u= 15m/s
final speed v= 45m/s
time taken to attain final speed= 10seconds
Step two:
Let us first solve for the acceleration
a= Δv/t
a= 45-15/10
a=30/10
a= 3m/s
applying the equation of motion
[tex]v^2=u^2+2as[/tex]
substituting our given data
[tex]45^2+15^2+2*3*s\\\\2025=225+6s\\\\[/tex]
collect like terms
2025-225=6s
1800=6s
divide both sides by 6
s=1800/6
s=300m
Please help I will send pics in return or I will mark brainliest (depending on what u want) for a good attempt and explanation.
The answer would have to be 8.47 m/s/s because the backwards pull + the rate of speed it is going would have to be added to get the answer to compensate for the backwards pull
A steel bridge is 5.5m long. If the linear expansivity of steel is 0.000011/℃, how much will it expand when temperature rise by 10 ℃? Give your answer in cm
Answer:
The expansion of the steel bridge is 0.0605 cm
Explanation:
The given length of the steel bridge, L = 5.5 m
The linear expansivity of the steel bridge, [tex]\alpha_ L[/tex] = 0.000011/°C
The rise (change) in the temperature, ΔT = 10°C
Let, ΔL, represent the expansion of the steel bridge
Given that the linear expansivity, [tex]\alpha_ L[/tex], of a material is the change in the length of a material per unit length of the material per unit change in the temperature, we have;
[tex]\alpha_ L[/tex] = ΔL/(L × ΔT)
∴ ΔL = [tex]\alpha_ L[/tex] × L × ΔT = 0.000011 /°C × 5.5 m × 10 °C = 0.000605 meters
ΔL = 0.000605 meters
The expansion of the steel bridge, ΔL = 0.000605 meters = 0.000605 m × 100 cm/m = 0.0605 cm
what does the area under a speed-time graph represent
Answer: It represents the whole distance traveled. Hope this helps!
Explanation:
Where could we use a light bulb that has 12V written on it
Answer:
Explanation:
In a battery charger (for an auto).
As a replacement for any bulb in an auto.
As a lamp in an emergency exit where the power must be shut off.
As a light that illuminates the back of a truck, turned on when loading the truck.
Why is it difficult to use the law of conservation of energy to calculate the
effects of a collision?
Answer:
B
Explanation:
In a collision some of the kinetic energy of the object convert into thermal energy and sound. It's not so easy to measure thermal and sound energy. That's why it's difficult to use law of conservation of energy.
Alert: Energy is always conserved.
HELP ASAP!!!! WILL GIVE BRAINLIEST!
What are the functions of ribosomes, the endoplasmic reticulum, vesicles, and the Golgi apparatus?
Ribosomes, endoplasmic reticulum, vesicles, and the Golgi apparatus are the organelles present in the eukaryotic cell. They are involved in various roles and functions involving proteins.
What are the functions of the organelles?Ribosomes are the organelles involved in the transcription and translation process to synthesize proteins and transport them from ER to the vesicles. The endoplasmic reticulum (ER) is a membraneous structure that along with ribosomes is involved in lipid and protein synthesis.
The proteins synthesized from ER are transported to the Golgi body through the vesicles. They even eliminate the waste from the cell. The Golgi apparatus receives proteins from ER and then packs, modifies, and transports them to the target location.
Therefore, the ER, ribosomes, Golgi, and vesicles are involved in protein synthesis and transportation.
Learn more about cell organelles, here:
https://brainly.com/question/14798609
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Ya sabes que los materiales se utilizan dependiendo de la fun- ción que deben tener: transparentes (cristales), conductores de la electricidad (cables de tendidos eléctricos), muy resistentes (vigas), inoxidables (cuberterías), etc. Pero, ¿interesarán materiales de densidad grande o pequeña? ¿Por qué? Busca ejemplos de tres materiales que justifiquen tu respuesta (por ejemplo, el hilo conductor de las líneas de alta tensión, los colchones de espuma de alta densidad, la fibra de carbono, etc). ¿Qué características tiene la fibra de carbono en cuanto a resis- tencia y densidad? Busca objetos que se elaboren con fibra de carbono.
1.
Asthenosphere
a. the liquid layer located between the mantle and the inner
core
2.
Continental crust
b. the inner most solid layer of Earth
3.
Convection currents
the parts of Earth's crust located beneath the ocean that
make up the seafloor
4.
Crust
5.
Density
d. a transition zone beneath the lithosphere that is semi-
fluid, sometimes referred to as the plastic layer
6.
Inner core
e. the hard, rigid outermost layer of Earth
7
Lithosphere
f. all the parts of the Earth's crust that are not beneath the
ocean
8
Mantle
9.
Mesosphere
g the layer that is directly below Earth's crust and is divided
into 3 parts: lithosphere, asthenosphere, and mesosphere
h. the amount of force on a substance
10.
Oceanic crust
1. the solid lower layer of the mantle
11.
Outer core
j. the rigid, solid upper mantle connected to Earth's crust
12
Pressure
ki instrument used to measure earthquake waves
13.
Seismograph
1. the layer of Earth that is split into larger pieces: it floats on
the asthenosphere and moves due to convection currents
14.
Tectonic plates
m. the measure of mass per volume; the number of particles
in a given space
in movement of liquid and gaseous matter in a circular
motion caused by a difference in temperature; warm rises
and cool sinks, causing a circular current
Answer:
dsfghrtykuyjfcjuktj,ilyk
Explanation:
jgbnm,g bcm
John wants a new video tape and a new shirt, but he only has $12.00. He buys the video tape and gets $0.52 change. What was his opportunity cost?
Answer:
You have the answer in your comments. I will be copying it so your question doesn't get deleted.
The answers is $0.58
$11.48
the video tape
the new shirt
a skier starts at rest at the top of a hill with 350 J of gravitational potential energy. Assuming energy is conserved, what is her final kinetic energy at the lowest point
Answer:
350Joules
Explanation:
According to law of Conservation of energy, the amount of energy at the used up at the start is equal to that at the end.
The initial energy used up is gravitational potential energy
Final energy at the lowest point is kinetic energy.
If the energy is conserved then it means energy is not used up during the process hence;
Initial Potential energy = Final kinetic energy
If the gravitational potential energy is 350Joules then her final kinetic energy at the lowest point will also be 350Joules
How many kilometers in 487,320 meters? If there are 1,000 meters in one kilometer?
Answer:
48.732
Explanation:
Just move the denominator 3 times for the 0s in 1000.
No machine have 100% efficiency. Why?
[tex]\huge\fcolorbox{black}{pink}{Answer}[/tex]
Because said machines have to operate in the physical world with constraints caused by the laws of physics. It’s not possible to do useful work without encountering some of these issues. The mains ones are:
Heat lost from the systemFriction (including air resistance)Electrical resistance[tex]\sf\blue{hope\:it\:helps}[/tex]
A rocket is fired vertically upwards starting frkm rest. It accelerates at 30m/s for 4secs. At the end of 4secs it runs out of fuel but continues to rise. How long does it rise with reference to firing position?
Answer:
t = 16.5 s
Explanation:
First we apply first equation of motion to the accelerated motion of the rocket:
[tex]v_{f1} = v_{i1} + at_{1}[/tex]
where,
vf₁ = final speed of rocket during accelerated motion = ?
vi₁ = initial speed of rocket during accelerated motion = 0 m/s
a = acceleration of rocket during accelerated motion = 30 m/s²
t₁ = time taken during accelerated motion = 4 s
Therefore,
[tex]v_{f} = 0\ m/s + (30\ m/s^2)(4\ s)\\\\v_{f} = 120\ m/s[/tex]
Now, we analyze the motion rocket when engine turns off. So, the rocket is now in free fall motion. Applying 1st equation of motion:
[tex]v_{f2} = v_{i2} + g t_{2}[/tex]
where,
vf₂ = final speed of rocket after engine is off = 0 m/s
vi₂ = initial speed of rocket after engine is off = Vf₁ = 120 m/s
g = acceleration of rocket after engine is off = - 9.8 m/s² (negative sign for upward motion)
t₂ = time taken after engine is off = ?
Therefore,
[tex]0\ m/s = 120\ m/s + (- 9.8\ m/s^2)(t_{2})\\\\t_{2} = \frac{120\ m/s}{9.8\ m/s^2}\\\\t_{2} = 12.25\ s[/tex]
So, the time taken from the firing position till the stopping position is:
[tex]t = t_{1} + t_{2}\\\\t = 4 s + 12.5 s[/tex]
t = 16.5 s
Le manque de sommeil peut réduire la production d'insuline par le pancréas. L'insuline est responsable de métaboliser le sucre dans le sang. De quel ordre peut être la réduction d'insuline?Lecteur immersif
Answer:
Very big.
Explanation:
Very big reduction occurs in insulin production when a person did not sleep in 24 hours. Due to lack of sleep, reduction occurs in the production of insulin by the pancreas. Insulin is a hormone that is responsible for metabolizing sugar in the blood and if insulin is not secreted by the pancreas in normal concentration so the person get diabetes disease due to increasing amount of glucose in the blood.
say something random cuz i already answered my own question
Answer:
The experimental setup, with car 1 is at the top of a ramp and car 2 at the bottom of the ramp is explained below in details.
Explanation:
The meter pole should be located at the opening location of car second at the bottom of the ramp so that it regulates the portion of car second that will finish up the most distant away from the bottom of the ramp.
So, I think now you got your answer which is absolutely correct and it will help you.
Answer:
hello my good friend
Explanation:
Which has greater kinetic energy: a bowling ball that has a mass of 5 kg travelling at 6 m/s, or a ship that has a mass of 120000 kg and is moving at 0.02 m/s?
Answer:
The bowling ball has greater kinetic energy.
Explanation:
Kinetic energy is given by:
[tex] K = \frac{1}{2}mv^{2} [/tex]
Where:
m: is the mass
v: is the speed
For the bowling ball we have:
[tex]K = \frac{1}{2}mv^{2} = \frac{1}{2}5 kg*(6 m/s)^{2} = 90 J[/tex]
And for the ship:
[tex]K = \frac{1}{2}mv^{2} = \frac{1}{2}120000 kg*(0.02 m/s)^{2} = 24 J[/tex]
Therefore, the bowling ball has greater kinetic energy.
I hope it helps you!
A 0.2 kg baseball is pitched with a velocity of 40 m/s and is then batted to the pitcher with a velocity of 60 m/s. What is the magnitude of change in the ball's momentum?
Answer:
The magnitude of change in the ball's momentum is 4 kgm/s
Explanation:
Given;
mass of the ball, m = 0.2 kg
initial velocity of the ball, u = 40 m/s
final velocity experienced by the ball, v = 60 m/s
Therefore, the change in momentum of the ball is given as final momentum minus initial mometum;
ΔP = mv - mu
ΔP = m(v-u)
ΔP = 0.2 (60 - 40)
ΔP = 4 kgm/s
Therefore, the magnitude of change in the ball's momentum is 4 kgm/s
The magnitude of the change in the momentum of the baseball is 4 kgm/s.
To solve the problem above we need to use the formula of change in momentum
Change in momentum: This can be defined as the product of the mass and the change in velocity of a body.
The formula of change in momentum is
M = m(v-u).................. Equation 1
Where M = change in momentum, m = mass of the baseball, v = final velocity of the baseball, u = initial velocity of the baseball.
From the question
Given:
m = 0.2 kg v = 60 m/s u = 40 m/sSubstitute these values into equation 1
M = 0.2(60-40) M = 0.2(20) M = 4 kgm/sHence, The magnitude of the change in the momentum of the baseball is 4 kgm/s
Learn more about change in momentum here: https://brainly.com/question/11789105
what is the correct answer?
Answer:
i cant explain well but the answer is letter b
x-5
Explanation:
dont report me or i will report you too
Answer:
x-5 is the answer
Explanation:
pick her as the brainliest
A 0.3 kg bird flies south with a speed of 5 m/s. What is its kinetic energy?
A. 1.5 J
B. 2.5 J
C. 3.8 J
D. 8.3 J
Answer:
right answer is number C that is 3.8J since KE=1/2mv²
Two objects, one 4 times as massive as the other, are approaching each other under their mutual gravitational
attraction. When the separation between the objects is 100 km, the acceleration of the lighter object is 1 m/
s2. When the separation between them is 25 km, the acceleration of the heavier object is
To Find :
The acceleration of the heavier object.
Solution :
Force of gravitation on lighter object by heavier object is :
[tex]F = \dfrac{Gm(4m)}{100^2}[/tex]
Acceleration of lighter object is given by :
[tex]a_s = \dfrac{4Gm}{100^2}\\\\m = \dfrac{50^2}{G}[/tex] .....1)
Now, acceleration of heavier object when separation between them is 25 km :
[tex]4ma_h = \dfrac{Gm(4m)}{25}\\\\a_h = \dfrac{Gm}{25}[/tex].....2)
Putting value of m in equation 2, we get :
[tex]a_h = \dfrac{G\times 50^2}{G \times 25}\\\\a_h = \dfrac{2500}{25}\\\\a_h = 100\ m/s^2[/tex]
Therefore, the acceleration of the heavier object is 100 m/s².
Water boiling
Which one is shown? (Look at pic)
Answer:
conduction.
Explanation:
Hoped I helped! Im Eve btw have a great day and consider marking this brainliest if you do thank you in advanced!
Clarissa has a credit card with a limit of $1,000 and pays her balance in full each month. If Clarissa needs a short-term loan, can she use her credit card as collateral at a pawn shop? Why or why not? Select the best answer from the choices provided. A. She cannot use it because a credit card is not collateral. B. If the balance on the credit card is zero, she can use it. C. If the balance on the credit card is $1,000, she cannot use it. D. She can use it if she increases the credit limit.
Answer:
B.she cannot use it because the credit card is not collareral
Explanation:
sorry if am wrong
a student tries to produce notes of higher frequency by blowing a trumpet harder. he will succeed?
Answer:
Please mark as Brainliest!!
Explanation:
He will not succeed as it blows the trumpet harder that only increase the amplitude of the sound wave that means the intensity of the sound will increase but the frequency remains the same.
Answer:
he wont
Explanation:
a crowbar 2 metres long is used to lift a rock weighing 800 newtons .If the fulcrum is 0.25 metre,from where the bar touches the rock, how much effort must be applied to move the rock
Answer:
??
Explanation:
It is not possible to accurately calculate instantaneous velocity.
TRUE
FALSE
You’ve been in a car traveling at 80 km/hr. How many hours will it take to travel 640 km?
An unknown material, m1 = 0.41 kg, at a temperature of T1 = 86 degrees C is added to a Dewer (an insulated container) which contains m2 = 1.7 kg of water at T2 = 22 degrees C. Water has a specific heat of cw = 4186 J/(kg⋅K). After the system comes to equilibrium the final temperature is T = 30.3 degrees C.
Complete Question
An unknown material, m1 = 0.41 kg, at a temperature of T1 = 86 degrees C is added to a Dewer (an insulated container) which contains m2 = 1.7 kg of water at T2 = 22 degrees C. Water has a specific heat of cw = 4186 J/(kg⋅K). After the system comes to equilibrium the final temperature is T = 30.3 degrees C.
Part (a) Input an expression for the specific heat of the unknown material.
Part (b) What is the specific heat in J/(kg⋅K)?
Answer:
a
[tex]c = \frac{m_2 * c_w (T - T_2)}{m_1 * (T_1 - T) }[/tex]
b
[tex]c = 2587.14 \ J /(kg \cdot K)[/tex]
Explanation:
From the question we are told that
The mass of the material is [tex]m_1 = 0.41 \ kg[/tex]
The temperature is [tex]T_1 = 86 ^oC[/tex]
The mass of water is [tex]m_2 = 1.7 \ kg[/tex]
The temperature of water is [tex]T_2 = 22^oC[/tex]
The specific heat of water is [tex]c_w = 4186 \ J/(kg\cdot K)[/tex]
The temperature of the system is [tex]T= 30 .3^o C[/tex]
Generally heat lost by the unknown material = heat gained by water
Generally the heat gained by water is mathematically represented as
[tex]Q_2= m_2 * c_w (T - T_2)[/tex]
=> [tex]Q_2= 1.7 * 4186 (30.3 - 22)[/tex]
=> [tex]Q_2= 59064.46 \ J[/tex]
Generally the heat lost by the unknown material is mathematically represented as
[tex]Q_1= m_1 * c* (T_1 - T)[/tex]
[tex]m_2 * c_w (T - T_2) = m_1 * c* (T_1 - T)[/tex]
=> [tex]c = \frac{m_2 * c_w (T - T_2)}{m_1 * (T_1 - T) }[/tex]
Here c is the specific heat capacity of the unknown material
=> [tex]Q_1= 0.41 * c (86 - 30.3)[/tex]
=> [tex]Q_1= 22.83 c[/tex]
So
[tex]59064.46 = 22.83 c[/tex]
=> [tex]c = \frac{59064.46 }{ 22.83}[/tex]
=> [tex]c = 2587.14 \ J /(kg \cdot K)[/tex]
A ball is thrown vertically upward with a speed v. An identical second ball is thrown upward with a speed of 1/2 v (half as fast). What is the ratio of the maximum height of the second ball to that of the first ball
Answer:
1:4
Explanation:
The formula for calculating the maximum height of the ball is expressed as;
H = u²sin²theta/2g
If a ball is thrown vertically upward with a speed v, its maximum height is expressed as;
H = v²sin²90/2g
Since sin90 = 1
H = v²/2g.... 1
If an identical second ball is thrown upward with a speed of 1/2 v, then the maximum height will be expressed as;
H1 = (1/2v)²sin²90/2g
H1 = (v²/4)(1)/2g
H1 = v²/8g ...... 2
Divide both equations
H/H1 = (v²/2g)/(v²/8g)
H/H1 = v²/2g × 8g/v²
H/H1 = 8g/2g
H/H1 = 4
Reciprocate both sides
H1/H = 1/4
H1:H = 1:4
Hence the ratio of the maximum height of the second ball to that of the first ball is 1:4
Calculate the time needed to drive a car 100 kilometers if the car is traveling at a speed of 70 km/hr.
A.14 hours
B. 7 hours
C. .7 hours
D.1.4 hours
Answer:
D.1.4 hours
Explanation:
[tex]d\ =\ vt[/tex]
[tex]t\ =\ \frac{d}{v}[/tex]
[tex]t\ =\ \frac{100}{70}[/tex]
[tex]t\ =\ 1.42857142857[/tex]
Therefore, the answer is D 1.4 hours