Answer:
The first scenario!
Explanation:
W=F*d
a) 55*8= 440J
b) 60*6= 360J
c) 50*5= 250J
d) 40*10= 400J
The scenario with the greatest amount of work done on a wagon is "A force of 55 N moves it 8 m" and the Work done is 440N.m.
What is Work done?Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;
W = F × d
Where F is force applied and d is distance travelled.
From the question;
A force of 55 N moves it 8 m
W = 55N×8m = 440N.m
A force of 60 N moves it 6 m.
W = 60N×6m = 360N.m
A force of 50 N moves it 5 m.
W = 50N×5m = 250N
A force of 40 N moves it 10 m.
W = 40N×10m = 400N.m
Therefore, the scenario with the greatest amount of work done on a wagon is "A force of 55 N moves it 8 m" and the Work done is 440N.m.
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You pull with a force of 295 N on a rope that is attached to a block of mass 22 kg, and the block slides across the floor at a constant speed of 1.6 m/s. The rope makes an angle of 35 degrees with the horizontal. What is the net force on the block
Answer:
Fnet = 0
Explanation:
Since the block slides across the floor at constant speed, this means that it's not accelerated.According Newton's 2nd Law, if the acceleration is zero, the net force on the sliding mass must be zero.This means that there must be a friction force opposing to the horizontal component of the applied force, equal in magnitude to it:[tex]F_{appx} = F_{app} * cos \theta = 295 N * cos 35 = 242 N (1)[/tex]
In the vertical direction, the block is not accelerated either, so the sum of the normal force and the vertical component of the applied force, must be equal in magnitude to the force of gravity on the block:[tex]F_{appy} = F_{app} * cos \theta = 295 N * sin 35 = 169 N (2)[/tex]
⇒ 169 N + Fn = Fg = 216 N (3)
This means that there must be a normal force equal to the difference between Fappy and Fg, as follows:Fn = 216 N - 169 N = 47 N (4)Each vertical line on the graph is 1 millisecond (0.001 s) of time. What is the period and
frequency of the sound waves?
Explanation:
Given that,
Each vertical line on the graph is 1 millisecond (0.001 s) of time.
We need to find the period and the frequency of the sound wave. The period of a wave is equal to the each vertical line on graph i.e. 0.001 s.
Let f be the frequency of the sound wave. So,
f = 1/T
i.e.
[tex]f=\dfrac{1}{0.001 }\\\\f=1000\ Hz[/tex]
So, the period and the frequency of the sound waves is 1 milliseond and 1000 Hz respectively.
explain briefly where the energy come from when a liquid Rises against Gravity in a capillary tube
Answer:
Surface tension
Explanation:
When liquid rises against gravity in a capillary tube, the energy comes from surface tension.
This is because surface tension is the energy that's needed to increase the liquid surface area.
As a result of hydrogen bonding present in Water, it usually has high surface tension which makes it to possess a tough skin that can make it not to break despite high forces applied to it.
The liquid will be in contact with the capillary tube and as such experiences surface tension which in turn makes the capillary tube to experience an upward force that makes the liquid begin to rise up.
The more the liquid keeps rising, the more it gets to the point where the surface tension becomes balanced from the weight of the liquid.
We intend to measure the open-loop gain (LaTeX: A_{open}A o p e n ) of an actual operational amplifier. The magnitude of LaTeX: A_{open}A o p e n is in the range of 106 V/V. However, the signal generator in measurement setup can supply minimal voltage of 1 mV, and the oscilloscope used at amplifier output can measure maximal voltage level of 10 V. Can you design a simple measurement setup using this signal generator and oscilloscope, and accurately measure the LaTeX: A_{open}A o p e n
Answer:
voltage divider, R₂ = 1000 R₁
measuring the output in the resistance R₁
Explanation:
Let's analyze the situation, in an op amp in open gain loop, the gain is maximum G = 10⁶ V / V
in this case the signal generator gives a minimum wave of 1 10⁻³ V, after passing through the amplified it becomes 10³ V which saturates the oscilloscope.
To solve this problem we must use a simple voltage divider, for this we use the fact that in a series circuit the voltage is the sum of the voltages of each element.
If we use two resistors whose relationship is
R₂ / R₁ = 10³
R₂ = 1000 R₁
When measuring the output in the resistance R₁ we have the desired divider, with a tolerance range, for the minimum output of the generator (1 10⁻³V) we have a reading of V = 1 V in the oscilloscope, for which we can use voltage up to 10V on the generator
1. Describe how unequal heating and rotation of the Earth causes atmospheric and oceanic circulation patterns that determine the regional and global climate.
6)
A 50 kg bike and rider accelerate from 4 to 8 m Determine how much kinetic energy must be added to make this occur?
S
S
A)
200
B)
400)
800)
D)
1200
Answer:
A.) 200 in my opinion so I hope this helps
Answer: 1200 j
Explanation:
I just took it
an object is found to have weight of 16.7N on moon
what is it's
weight on earth where g= 10N/kg
Answer:
167 kg
Explanation:
On Earth it is 167 kg. We have to multiply the weight in the Moon by 10 because 1 kg on Earth, is nearly 10 N. 1 kg is 9,8 N in fact, but we get it as 10 N in general.
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Select True or False for the following statements about electromagnetic waves. A vertical automobile antenna is sensitive to electric fields polarized horizontally. Ultraviolet radiation causes common sunburn. Radio waves travel in vacuum at a lower speed than the visible light. The sun's radiation is most intense in the visible region. Gamma rays can be produced in transitions of an atomic nucleus from one state to another. Radio waves have wavelengths longer than 1 m. X-rays travel in vacuum at a higher speed than the visible light.
Answer:
a) False, b) True, c) true, d) true, e) True, g) False
Explanation:
Se pide que analicemos cada expresión, f) true
a) False. La antena vertical tiene cargas eléctricas que se pueden mover en la direccion vertical, una onda electromagnética polarizada horizontal el campo eléctrico esta en la dirección horizontal por lo cual no puede mover los electrones que están en direccional vertical
be) True. La radiación ultravioleta es absorvidad por la melanina del la piel y crea las quemaduras comunes de insolación.
C) False. Todas la ondas electromagnetismo viajan en la misma velocidad c
d) True. La Temperatura del sol es 5800K por lo cual la radiación mas intensa esta en el rango visible
e) True. Los rayos gamma son de muy alta energía, por lo cual se producen en ransicio0n de los núcleos atmicos.
f) True. El rango de frecuencia para las onda de radio va desde 500 Kahoy hasta 110 MHz, por lo tanto el rango de longitudes de onda es
c= lam f
lam = c/f
lam = 3 108/500 103
lam = 6 102 m
lam = 3 108 / 110 106
lam = 2,72 m
los lo ttnato en todo el rango de las frecuecias de radio la lambda> 1 m
g) False. Todas las ondas electromagnéticas viajan a la misma velocidad c( 3 108m/s)
200 Coulombs of charge passes through a point in a circuit for 0.6 minutes. what is the magnitude of the current flowing
Answer:
5.56 A
Explanation:
From the question,
Q = it.............. Equation 1
Where Q = charges, i = current, t = time.
Make i the subject of the equation
i = Q/t.............. Equation 2
Given: Q = 200 coulombs, t = 0.6 minutes = (0.6×60) seconds
Substitite these values into equation 2
i = 200/(0.6×60)
i = 5.56 A
Hence the magnitude of the current flowing through the circuit is 5.56 A
An inclined plane consists of a 25 m length that raises an object 5 m above the ground. When pushing a 4500 N crate to the top of the ramp you exert 1000 N. What is the ideal Mechanical Advantage of this machine?
The IDEAL mechanical advantage of this ramp is (25m / 5m) = 5 .
But it's only giving you a real MA of (4500N/1000N) = 4.5 .
The friction between the crate and the surface of the ramp is robbing some of the work you do as you slide the crate up the ramp, which degrades the mechanical advantage.
A piece of gold aluminum alloy weighs 49N. When suspended from a balance and submerged in water it weighs 39.2. What is the weight of gold in the alloy of relative density of gold if 19.3 and aluminum is 2.5
Answer:20.8
Explanation:
Which of the following is true about an object that travels 5 meters to the left, then 2
meters up, then another 5 meters to the right?
A Displacement of the object is equal to 12 meters.
B. Displacement of the object is equal to 12 meters down.
C: Total distance travelled by the object is equal to 12 meters.
D. Total distance travelled by the object is equal to 12 meters down.
Answer:
Total distance travelled by the object is equal to 12 meters.
Explanation:
Given that,
An object that travels 5 meters to the left, then 2 meters up, then another 5 meters to the right.
Displacement is equal to the shortest path covered and the distance is equal to the total path covered.
Displacement = -5+2+5
= 2 m down
Distance = 5+5+2
= 12 m
Hence, the correct option is (c) "Total distance traveled by the object is equal to 12 meters."
The option that is true about an object that travels 5 meters to the left, then 2 meters up, then another 5 meters to the right is C. Total distance traveled by the object is equal to 12 meters.
Displacement simply means the overall change in the position of an object. It's a vector quantity. On the other hand, distance is a scalar quantity and it represents how much ground that an object has been able to cover.
Therefore, the distance will be:
= 5m + 2m + 5m
= 12m
The distance is 12 meters.
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An amusement park ride called the Rotor debuted in 1955 in Germany. Passengers stand in the cylindrical drum of the Rotor as it rotates around its axis. Once the Rotor reaches its operating speed, the floor drops but the riders remain pinned against the wall of the cylinder. Suppose the cylinder makes 26.0 rev/min and has a radius of 3.70 m. 1) What is the coefficient of static friction between the wall of the cylinder and the backs of the riders
Answer:
μs = 0.36
Explanation:
While the drum is rotating, the riders, in order to keep in a circular movement, are accelerated towards the center of the drum.This acceleration is produced by the centripetal force.Now, this force is not a different type of force, is the net force acting on the riders in this direction.Since the riders have their backs against the wall, and the normal force between the riders and the wall is perpendicular to the wall and aiming out of it, it is easily seen that this normal force is the same centripetal force.In the vertical direction, we have two forces acting on the riders: the force of gravity (which we call weight) downward, and the friction force, that will oppose to the relative movement between the riders and the wall, going upward.When this force be equal to the weight, it will have the maximum possible value, which can be written as follows:[tex]F_{frmax} = \mu_{s}* F_{n} = m * g (1)[/tex]
where μs= coefficient of static friction (our unknown)As we have already said Fn = Fc.The value of the centripetal force, is related with the angular velocity ω and the radius of the drum r, as follows:[tex]F_{n} = m* \omega^{2} * r (2)[/tex]
Replacing (2) in (1), simplifying and rearranging terms, we can solve for μs, as follows:[tex]\mu_{s} = \frac{g}{\omega^{2} r} (3)[/tex]
Prior to replace ω for its value, is convenient to convert it from rev/min to rad/sec, as follows:[tex]\omega = 26.0 \frac{rev}{min} * \frac{1min}{60 sec} *\frac{2*\pi rad }{1 rev} = 2.72 rad/sec (4)[/tex]
Replacing g, ω and r in (3):[tex]\mu_{s} = \frac{g}{\omega^{2} r} = \frac{9.8m/s2}{(2.72rad/sec)^{2} *3.7 m} = 0.36 (5)[/tex]A physics student sits in a chair. The chair pushes up on the student's body. Identify the other force of the interaction force pair.
Answer:
gravity pulls down on student the chair pushes up on the student's body with the same force gravity is pulling down on the student
I need help!!!!!!!!!!!pleaseeeeeee
TRUE OR FLASE
12. During sleep the pituitary gland shuts down for the rest of the night.
13. When a person has a nightmare they wake up in a sweat and don't remember
the content of their dream.
Answer:
true for first and false for second
Explanation:
Cuestions
A radio station is transmitting at a frequency of 15.42 MHz.Calculate the frequency of
the transmission
Answer:
The wavelength of the transmitting waves is 55.35 m
Explanation:
Radio waves are electromagnetic waves, thus travel at the speed of light (3.0 x [tex]10^{8}[/tex] m/s)
The frequency of transmission = 15.42 MHz
= 15.42 x [tex]10^{6}[/tex] Hz
But,
v = fλ
where: v is the velocity of the wave, f is the frequency and λ is the wavelength
The wavelength of the transmitting waves can be determined by,
λ = [tex]\frac{v}{f}[/tex]
= [tex]\frac{3.0 *10^{8} }{5.42 *10^{6} }[/tex]
= 55.3506
λ = 55.35 m
The wavelength of the transmitting waves is 55.35 m.
One molecule of dinitrogen tetroxide contains...
A.
four nitrogen atoms and four oxygen atoms.
B.
two nitrogen atoms and four oxygen atoms.
C.
four nitrogen atoms and two oxygen atoms.
D.
two nitrogen atoms and two oxygen atoms.
Answer:
C
Explanation:
C is correct
Ok!
151617
a sentence that describes how energy is related to work
Answer:
Energy should be transferred to an object in order to move it. ... This amount of energy transferred by the force to move an object is called work or work done. Thus, the relation between Work and Energy is direct. That is, the difference in the Kinetic energy of an object is work done by an object
Which of the following statements about treatment for self-injury (SI) is not true?
Answer:
Its true
Explanation:
1. A Zambeef delivery track travels 18 km north, 10 km east, and 16 km south. What is its final displacement from the origin?
Answer:
2km
Explanation:
Given data
We are told that the direction traveled are
North>>>East>>>South
Hence the displacement is defined as the distance away from the initial position is
Initial position =18km
FInal position = 16km
The displacement = 18-16= 2km
Hence the displacement is 2km
fossil fuel had beeb used more in the existing world.
Answer:Fossil Fuels Still Supply 84 Percent Of World Energy — And Other Eye Openers From BP's Annual Review.
________ is described as the pulling force transmitted by the means of a
string, a cable, chain. (An example would be a pulley)
Please help I need to turn this today!
Answer:
it should be tension for the space
Answer:
tension
Explanation:
I'm not sure if I'm right but if the example is a pulley a pulley applies tension to a belt or rope or chain to keep it tight
Given vector A with magnitude 2N and vector B magnitude 4N, what are the minimum and maximum magnitudes of A+B?
-- If A and B are pointing in exactly opposite directions, then their sum A+B is the minimum possible value. A+B = 2 N in the same direction as B.
-- If A and B are pointing in exactly the same direction, then their sum A+B is the maximum possible value. A+B = 6 N in that same direction.
What did Thomas Edison create that made him most famous today? I know it is something about light, but I do not believe he was first. May someone tell me his most famous accomplishment in easy words to understand? Thanks
Explanation:
Thomas Edison invented the incandescent light bulb which is kind of like the light bulbs we use today. but they have been improved throughout the years.
hope this is simple and understandable
Answer:
One of the most famous and prolific inventors of all time, Thomas Alva Edison exerted a tremendous influence on modern life, contributing inventions such as the incandescent light bulb, the phonograph, and the motion picture camera, as well as improving the telegraph and telephone.
Explanation:
Your well-wisher
HELP ME HOW ARE BLACK HOLES FROMED
Answer:
Stellar black holes form when the center of a very massive star collapses in upon itself.
Answer:
A black hole can be formed by the death of a massive star. When such a star has exhausted the internal thermonuclear fuels in its core at the end of its life, the core becomes unstable and gravitationally collapses inward upon itself, and the star's outer layers are blown away.
Explanation:
A woman pushes a 35.0 kg object at a constant speed for 10.8 m along a level floor, doing 280 J of work by applying a constant horizontal force of magnitude F on the object. (a) Determine the value of F (in N). (Enter the magnitude.) N (b) If the worker now applies a force greater than F, describe the subsequent motion of the object. The object's speed would increase with time. The object's speed would remain constant over time. The object would slow and come to rest. (c) Describe what would happen to the object if the applied force is less than F. The object's speed would increase with time. The object's speed would remain constant over time. The object would slow and come to rest.
Answer:
a) F= 25.9 N
b) The object's speed would increase with time.
c) The object would slow and come to rest.
Explanation:
a)
By definition of work, this is the process through which a force applied on an object, produces a displacement of the object.If the force is constant, and the displacement is parallel to the direction of the force, this work is just the product of the applied force times the distance, as follows:[tex]W = F_{app} * d (1)[/tex]
We can solve for Fapp, replacing W and d by their values:[tex]F_{app} =\frac{W}{d} = \frac{280J}{10.8m} = 25.9 N (2)[/tex]
b)
If the object is moving at constant speed when it is applied a force F, this means that this force must be compensated by an equal opposite force, in this case, the kinetic friction force.Since this force is constant while the object is moving, if we increase the force F making it larger, there will be a net force in the direction of the displacement, which will cause an acceleration that will increase the speed with time.c)
We have already said in b) that if the object is moving at constant speed, there must be an equal and opposite force to the applied force F, the kinetic friction force, which is constant, acting on the object.If we apply a force less than F, there will be a net force in the direction opposite to the displacement, that will cause a acceleration opposite to the displacement, which will make the object to slow down and eventually come to rest.素 Example three
After an airplane takes off, it travels 10.4 km west, 8.7 km north, and 2.1 km up How far is it
from the take off point?
Solution
Answer:
Let R be the total distance
R²=10.4²+(8.7+2.1)²
R²=10.4²+10.8²
R²=224.8
You square root both sides
R=14.99km
If an airplane takes off, it travels 10.4 km west, 8.7 km north, and 2.1 km up, then using the Pythagorean theorem it is 14.99km from its take-off point.
What is Pythagoras' theorem?Pythagoras' theorem is a fundamental theorem in mathematics that relates to the sides of a right-angled triangle. It states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In equation form, the theorem can be written as:
c² = a² + b²
Where
c =the length of the hypotenuse,
a and b = the lengths of the other two sides.
The theorem is named after the ancient Greek mathematician Pythagoras, who is credited with his discovery and proof. Pythagoras' theorem is widely used in mathematics and has many practical applications in fields such as architecture, engineering, and physics.
Here in the question
We can use the Pythagorean theorem to find the distance from the takeoff point:
Distance = √(West)² + (North+Up)²
Plugging in the given values, we get:
Distance = √(10.4)² +( 8.7 + 2.1)²
Distance ≈ 14.99km
Therefore, the airplane is approximately 14.99km away from the takeoff point.
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A plastic ball in a liquid is acted upon by its weight and by a buoyant force. The weight of the ball is 4 N. The buoyant force has a magnitude of 5 N and acts vertically upward. When the ball is released from rest, what is it's acceleration and direction? [2 pts] for a Free Body Diagram correctly labeled.
Answer:
The acceleration is 2.448 meters per square second and is vertically upward.
Explanation:
The Free Body Diagram of the plastic ball in the liquid is presented in the image attached below. By Second Newton's Law, we know that forces acting on the plastic ball is:
[tex]\Sigma F = F - m\cdot g = m\cdot a[/tex] (1)
Where:
[tex]F[/tex] - Buoyant force, measured in newtons.
[tex]m[/tex] - Mass of the plastic ball, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]a[/tex] - Net acceleration, measured in meters per square second.
If we know that [tex]F = 5\,N[/tex], [tex]m = 0.408\,kg[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the net acceleration of the plastic ball is:
[tex]a = \frac{F}{m} - g[/tex]
[tex]a= 2.448\,\frac{m}{s^{2}}[/tex]
The acceleration is 2.448 meters per square second and is vertically upward.
Which of the following is NOT a reason
why gravity is important?
A It holds the planets in
orbit around the sun
B. It causes the ocean tides
C. It guides the growth of plants
D. None of the above
Answer:
I'm gonna say d
Explanation:
bc they all seem very important
hope this helped