Answer:
solid molecules are packed closely and liquid molecules are losely packed
What is gibbs free energy.
Answer:
It’s a
Explanation:
what causes us to perceive objects in three dimensions?
a. objects in 3-D appear to have width and height, but no depth
b. light bouncing or reflecting off an object in different ways
c. The curvature of space-time relative to objects solar mass
d. The rate of time dilation as we approach objects
Answer:
Light bouncing or reflecting off an object in different ways.
I just took a quiz and this was the answer
(k12 answer)
Light bouncing or reflecting off an object in different ways causes us to perceive objects in three-dimensions. Thus, the correct option is B.
How do we perceive objects in three dimension?Binocular fusion permits the perception of a single clear image and it also provides extra cues for the depth perception. That is, the binocular disparity between the two images is used by the nervous system of an individual to allow the perception of a three-dimensional world where the approximate distance of an object can be determined.
The depth perception is the ability to perceive the distance to objects using the visual system and visual perception.
Therefore, the correct option is B.
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Explanation:
The rod can be in equilibrium only if the resultant force is 0 and the moment around any point of the rod must be equal to 0.
We have to take moments around the pivoted point.
Moment = Force × Perpendicular distance to the force
For the rod to be in equilibrium,
Clockwise moment - Anticlockwise moment = 0
Clockwise moment = Anticlockwise moment
The distance between pivoted point and the weight of rod = 50 cm - 30 cm = 20 cm
So 20 cm× 1.2 N produces a Clockwise moment
If Perpendicular distance between pivoted point and 2N load is x,
Anticlockwise moment = x × 2N
20 cm× 1.2N = 2N × x
x = 12 cm
So 2 N load is at 12 from the pivoted point.
From the left edge of the meter ruler, 2N load is at 30-12 cm distance
= 18 cm
Answer: 18 cm
Explanation:
what is cheetah speed and strength?
Answer:
Speed: 109.4–120.7 km/h (68.0–75.0 mph)
Strength: Couldn't find out.
Explanation:
A ball is thrown from ground level at an angle of 0 and the initial velocity components are 7.5m/s and 13m/s. Ignoring air resistance, calculate each of:
1- The initial velocity is vi
2- The value of the angle at which the ball was thrown
3 - The horizontal range of the ball R
I assume you mean an angle of θ, and not 0. I also assume the given components of the initial velocity are horizontal and vertical, respectively, so that
1. the initial velocity vector is
[tex]\boxed{\vec v_i = (7.5\,\vec\imath + 13\,\vec\jmath) \dfrac{\rm m}{\rm s}}[/tex]
which means the ball is thrown with an initial speed of
√((7.5 m/s)² + (13 m/s)²) ≈ 15 m/s,
and
2. the angle made by [tex]\vec v_i[/tex] with the positive horizontal axis is θ such that
[tex]\tan(\theta) = \dfrac{13}{7.5} \implies \theta \approx \arctan(1.7) \approx \boxed{60^\circ}[/tex]
3. At time t, the ball attains a height y and horizontal range x according to
y = (13 m/s) t - g/2 t²
x = (7.5 m/s) t
where g = 9.8 m/s². When the ball reaches the ground (y = 0) for t > 0, we have
(13 m/s) t - g/2 t² = 0
13 m/s - g/2 t = 0
t = 2 (13 m/s)/g = (26 m/s)/g
Plugging this time into the x equation gives a horizontal range of
x = (7.5 m/s) (26 m/s)/g ≈ 20. m
A potted plant falls from the window of an apartment building. It falls for 2.0
s and then hits the ground. What is the speed of the plant just before it hits
the ground? Assume only gravity is acting on it.
A)20 m/s
B) 9.8 m/s
C) 2.0 m/s
D) 4.9 m/s
Answer:
D) 4.9 m/s
Explanation:
Speed of Object in Free Fall
s = Rate of Acceleration, Due to Gravity × Length of Time
s = 9.8 × 2.0
s = m/s (Round Up to The Nearest Whole Number)
--
m/s = 9.8 ÷ 2.0 = 4.9 m/s
Where does the energy released in a nuclear decay reaction come from
A. Electrons
B. Chemical bonds
C. Positrons
D. The binding energy of the nucleus
. Which of the following are forces that push upward on an indoor skydiver? Choose all that apply. *
gravity
acceleration
air resistance
lift
WILL GIVE BRAINLIST
The forces that push upward on an indoor skydiver are lift force and air resistance.
The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.
The downward forces on the indoor skydiver include the following;
gravity due to its weightdownward force due its accelerationThe upward force on the indoor skydiver include the following;
lift forceair resistanceThus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.
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A car starts from rest and accelerates at 2.5m/s^2 for 2s. What is the final velocity of the car
Answer:
5m/s ez
Explanation:
plz make me brainliest
The main goal of every defense is to __________. A. stop the ball B. regain possession of the ball C. protect the goal or basket D. all of the above
Answer:
D.
Explanation:
I believe it is D. Because in defense you are to stop others from scoring, while trying to score. But also while trying to protect the Goal or basket. I hope this helps you out.
Answer:
d
Explanation:
Tommy does 45 Joules of work to push the pencil over 3 meter. How much force did he use?
Answer:
Work = Force × Distance
Therefore Force = Work/Distance
= 45 joules/3 metres
= 15 newton
Explanation:
Answer:
15
Explanation:
15
How do energy transformations occur in a hydroelectric plant?
The potential energy of water is converted to mechanical energy by a turbine.
The kinetic energy of water is converted by a dam into potential energy.
The kinetic energy of water is converted by a generator into electric energy.
The potential energy of water is converted by a transformer into electric energy.
Answer:
The answer is #3: The kinetic energy of water is converted by a generator into electric energy.
Explanation:
Hydropower plants capture the energy of falling water to generate electricity. A turbine converts the kinetic energy of falling water into mechanical energy. Then a generator converts the mechanical energy from the turbine into electrical energy.
4. symbol for the gravitational force ?
Answer: G
Explanation:
differential rotation is when a planet's equator and polar regions rotate at different rates. True False
Two towers of height 40 m and 30 m respectively support a transmission line conductor at water crossing. The horizontal distance between the towers is 300 m. If the tension in the conductor is 1590 kg, find the clearance of the conductor at a point mid-way between the supports. Weight of conductor is 0·8 kg/m. Bases of the towers can be considered to be at the water level.
The sag in the tensioned cable depends on the weight of the cable and
the applied tension.
The clearance midway between the support is approximately 29.34 metersReasons:
The given parameters are;
Height of the towers are; h₁ = 40 m and h₂ = 30 m
Horizontal distance between the towers, l = 300 m
The tension in the conductor, T = 1,590 kg
Weight of the conductor, w = 0.8 kg/m
Required:
The clearance space of the conductor mid-way between the support
Solution:
The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;
[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]
Where;
h = h₂ - h₁ = 40 m - 30 m = 10 m
Which gives;
[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]
The sag at the lowest point is give by the formula;
[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]
Therefore;
[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]
The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m
The distance of the midpoint from the lowest point, x, is therefore;
[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]
Which gives;
[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]
The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34
The clearance midway between the support ≈ 29.34 m
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Heat rising in a hot-air balloon is an example of __________.
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Medicine in Western cultures has not focused on the energy in the body as much as cultures in Asia have.
A.
True
B.
False
PLEASE NO LINKS
Answer:
A
Explanation:
This is true because culture in Asia focus more on energy that is why we see kung fu and taekwondo etc.
Answer:
A
Explanation:
Got it right.
I’m not sure what this is… help please
Answer:
A) Slower
Explanation:
Less / low energy means less / slower speed.
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Ten seconds after starting from rest, a freely-falling object will have a speed of about ________________________
Answer:
100 m/s
Explanation:
Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.
A toy car travels down a sloping ramp at constant speed. toy car Which statement about
the forces acting on the car is correct?
A There are no forces acting on the car vertically.
B There is no resultant force acting on the car.
C There is no gravitational force acting on the car.
D There is no frictional force acting on the car.
Answer:
D There is no frictional force acting on the car.
Explanation:
There isnt any friction acting on the car while its going down.
an acorn falls from a tree. ignoring air resistance, what forces are on the acorn while it’s falling?
Answer: gravity
Explanation:
a girl on a bridge throws a rock straight down at -12.5 m/s. it hits the ground 38.4 m below. How much time did it take?
The acceleration of both the rocks is only due to the gravitational force acting on them. Even though the speed of thrown rock would be greater than that of dropped rock, the acceleration of both the rocks would be g downwards.
Answer:
1.80
Explanation:
38.4=-12.5(a)-1/2(-9.80)(a)^2
a= acceleration
^2 is the exponent
Which is larger, the sun's pull on earth or earth's pull on the sun?.
Answer:
the suns pull
Explanation:
The Sun's pull on Earth is twice as large as Earth's pull on the much larger Sun.
A car traveling at 35.6m/s crashes into a concert barrier and comes to a stop in 0.35 seconds. Calculate the average force applied to the 75kg driver.A 3.2kg steel ball traveling at 4.1m/s strikes a second ball of a mass 2.3kg Initially at rest. Calculate the velocity of the second ball when the first one continues traveling in the same direction with a speed of 1.5m/s2 balls of putty are shot towards one another. Ball 1 has a mass of 4.3kg and is moving at 18.6m/s . Ball 2 has a mass of 5.8kg and is moving at 9.5m/s. They collide and stick together. Calculate their final combine velocity.I really appreciate those attempting the problems. I do know the answers but I’m unaware of the steps to get there. Please include all formulas in your response and steps so I can learn and understand.Check your answer:7629N3.6m/s2.46m/sThank you all!
The force on the driver is 7629 N. The velocity of the second ball is 3.6 m/s. The combined velocity of the balls is 13.37 m/s.
We have to find the acceleration using;
v = u - at
v = final velocity = 0 m/s
u = initial velocity = 35.6m/s
a = acceleration = ?
t = time = 0.35 s
u = at
a = u/t = 35.6m/s / 0.35 s
a = 101.7 ms-2
The force on the driver = 75kg × 101.7 ms-2 = 7629 N
Using the principle of conservation of momentum;
Momentum before collision = momentum after collision
m1u1 +m2u2 = m1v1 + m2v2
Hence
(3.2 × 4.1) + 0 = (3.2 × 1.5) + 2.3v2
13.12 = 4.8 + 2.3v2
13.12 - 4.8 = 2.3v2
v2 = 13.12 - 4.8/2.3
v2 = 3.6 m/s
Using the principle of conservation of linear momentum;
m1u1 + m2u2 = m1v1 + m2v2
(4.3 × 18.6) + (5.8 × 9.5) = (4.3 + 5.8) v
v = 79.98 + 55.1/10.1
v = 13.37 m/s
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What feature of a planet's orbit does Kelper's first law of motion describe?
A. the time required for each orbit
B. the shape
C. the distance from the aphelion to the perihelion
D. the distance to the sun
1. A student pushes horizontally on a book with a force of 2 N, which causes the book to slide at a constant velocity. What is the force of friction on the book?
Answer:
The horizontal forces are equal in size and opposite in direction. They are balanced, so the horizontal resultant force is zero. This means that there is no horizontal acceleration just a horizontal constant speed. If a submarine is not moving horizontally, then there are no horizontal forces.
I hope it helps.
Agatha the snake is 50 centimeters long.3 years from now she will be 152 centimeters long and fully grown. If Agatha grows at constant rate, how much does she grow in length each year
Answer: 34cm each year
Explanation:
What is the weight of a 68-kg astronaut in outer space traveling with constant velocity?.
The weight of an astronaut in outer space and traveling with constant velocity is equal to 0 Newton.
Given the following data:
Mass of astronaut = 68 kgTo determine the weight of an astronaut in outer space and traveling with constant velocity:
Mathematically, the weight of an object is calculated by using the following formula;
[tex]Weight = mg[/tex]
Where:
m is the mass of an object.g is the acceleration due to gravity.At a constant velocity, the value of the astronaut's acceleration is equal to zero meter per seconds square ([tex]0\;m/s^2[/tex]).
Substituting the given parameters into the formula, we have;
[tex]Weight = 68 \times 0[/tex]
Weight = 0 Newton
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Reba knows that if she exercises it will help her body, but she is less sure how this will bring positive changes to other aspects of her life. What is the BEST way to explain this connection to Reba?
A.
When you are healthy, everything is automatically better.
B.
Exercise will lead her to meditate, allowing her to improve her mind and body.
C.
She will definitely lose a lot of weight, and thinner people are always happier.
D.
Exercise reduces stress and boosts confidence, which can create positive change.
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D.
Exercise reduces stress and boosts confidence, which can create positive change.
What water pressure must a pump that is located on the first floor supply to have water on the thirteenth of a building with a pressure of 35 lb/in2 Assume that the distance between each floors is 10ft.
The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
The given parameters;
Pressure on the 13 th floor, P₁ = 35 PSIDistance between each floor, d = 10 ftThe vertical pressure of the water is calculated as follows;
[tex]P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\[/tex]
The vertical height of the first floor from the 13th floor = 130 ft
The vertical height of the 13 ft floor = 10 ft
[tex]P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI[/tex]
Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
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