Third quadrant the complex plane is where the number -14 - 5i is situated.
-14-5i is located in which quadrant?Based on the common knowledge, the complex number's real and imaginary components are considered as the x- and y- coordinates of an ordered pair in a 2-D plane.
first quadrant a+bi =(a,b)
second quadrant -a+bi= (-a,b)
third quadrant -a-bi=(-a,-b)
fourth quadrant a,-b=(a,-b)
According to the question,-14-5i is located in third quadrant(-14,-5)
As a result, the complex plane's third quadrant is where the number -14 - 5i is situated.
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Which point is the solution to the inequality shown in this graph?? Help pls
a.(0,5)
b.(-3,-1)
c.(0,0)
d.(3,3).
Answer:
only (0,5)
Step-by-step explanation:
(0,5) is in the shaded region on the graph, so it is a solution.
One other point is in the unshaded region so it is NOT a solution. The other two points are on the dashed line, so they are NOT solutions. If the line was solid (not dashed) they would work, but since the line is dashed they are NOT solutions.
Answer:
A. (0,5)
Step-by-step explanation:
Which is a function?
look at pic
Answer:
option 2 {(12, 3), (11,2), ...}
Step-by-step explanation:
For functions, multiple x-values can have the same y-value but each y-value must have a unique x-value. The second option matches this criterion.
Someone please help me
Step-by-step explanation:
Part A: [tex]u^6[/tex] can be written as the square of u³, or [tex](u^3)^2[/tex]. Similarly, [tex]v^6=(v^3)^2[/tex]. Hence, we can write this as a difference of two squares by writing it as
[tex](u^3)^2-(v^3)^2[/tex]
Part B:
Difference of Two SquaresWe can first factor a difference of two squares a² - b² into (a+b)(a-b). Here, a would be u³ and b would be v³.
[tex](u^3+v^3)(u^3-v^3)[/tex]
Sum and Difference of Two CubesWe can factor this further by the use of two special formulas to factor a sum of two cubes and a difference of two cubes. These formulas are as follows:
[tex]a^3+b^3=(a+b)(a^2-ab+b^2)\\a^3-b^3=(a-b)(a^2+ab+b^2)[/tex]
Since u³ + v³ is a sum of two cubes, let's rewrite it.
[tex]u^3+v^3=(u+v)(u^2-uv+v^2)[/tex]
Since u³ - v³ is a difference of two cubes, we can rewrite it as well.
[tex]u^3-v^3=(u-v)(u^2+uv+v^2)[/tex]
Now, let's multiply them together again to get the final factored form.
[tex]u^6-v^6=(u+v)(u^2-uv+v^2)(u-v)(u^2+uv+v^2)[/tex]
Part C:
If we want to factor [tex]x^6-1[/tex] completely, we can just see that x to the sixth power is just [tex]x^6[/tex] and 1 to the sixth power is just 1. Hence, x can substitute for u and 1 can substitute for v.
[tex]x^6-1=(x+1)(x^2-x(1)+1^2)(x-1)(x^2+x(1)+1^2)\\x^6-1=(x+1)(x^2-x+1)(x-1)(x^2+x+1)[/tex]
We can repeat this for [tex]x^6-64[/tex], as 64 is just 2 to the sixth power.
[tex]x^6-64=(x+2)(x^2-x(2)+2^2)(x-2)(x^2+x(2)+2^2)\\x^6-64=(x+2)(x^2-2x+4)(x-2)(x^2+2x+4)[/tex]
3) angle of an isosceles triangle is 70°, find the value of If one remaining angles. a) 40°, 40° b) 45°, 45° c) 40°70° d)50⁰, 50⁰
The remaining two angles of the given isosceles triangle is Option(C) 40°,70° .
What are the remaining two angles in the isosceles triangle ?For an isosceles triangle, the two sides of the triangle are congruent and equal in length . Also the angles subtending the adjacent equal sides of the isosceles triangle are of same measure.
We also know that the sum of the three interior angles of any triangle is always equal to 180° .
In the options given, in Option(C) the angles measure 40° and 70° .
Thus as one angle of the isosceles triangle is given to be 70°, the other angle of its adjacent side is also 70° .
The sum of the interior angles of the triangle is equal to -
70° + 40° + 70° = 180° which satisfies the property.
Therefore, the remaining two angles of the given isosceles triangle is Option(C) 40°,70° .
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A rectangle measures 3.5 ft by 7 ft. It is enlarged by a scale factor of two. What is the area of the enlarged rectangle? T a m a
Answer:
98
Step-by-step explanation:
Solution 1, (quick)
When enlarging by a scale factor, the shape's area is multiplied by the scale factor squared.
3.5*7*2^2=98
This works because for a rectangle width x and length y, width 2x and length is 2y, area is 4xy compared to area xy originally.
Solution 2, (technical)
Scale factor of 2 means multiplying by 2
3.5^2=7
7*2=14
7*14=98
PLEASE HELP QUICKLY️️️
Answer:
first option x = 7
Step-by-step explanation:
"x" is the cathetus opposite the angle of 30°
14 is the hypotenuse
use the sine function
[tex]sin30^{0} =\frac{x}{14}[/tex]
[tex]x=14sen30^{0} =14(0.5)=7[/tex]
Hope this helps
A firm offers routine physical examinations as part of a health service program for its employees. The exams showed that 16% of the employees needed corrective shoes, 23% needed major dental work, and 3% needed both corrective shoes and major dental work. What is the probability that an employee selected at random will need either corrective shoes or major dental work
Probability of people needing corrective shoes or dental work is 0.36.
What is probability?The proportion of favorable cases to all possible cases used to determine how likely an event is to occur.
What are mutually exclusive events?A statistical term used to describe events that cannot occur concurrently is "mutually exclusive".
Here, the two events getting corrective shoes and getting dental work are not mutually exclusive events.
P(corrective shoes or dental work) = P(corrective shoes) + P(dental work) - P(corrective shoes and dental work)
P(corrective shoes or dental work) = 0.16 + 0.23 - 0.03
P(corrective shoes or dental work) = 0.36
Hence, the probability of people needing corrective shoes or dental work is 0.36.
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Janice bought 30 items each priced at 30 cents, 2 dollars, or 3 dollars. If her total purchase price was $\$$30.00, how many 30-cent items did she purchase
she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.
According to the statement
Janice bought total items = 30
Price of items are 30 cents, 2 dollars, or 3 dollars.
Total purchase price of Janice = 30$
If we let she bought 10 items at price of 3$, Then it is not possible
So, Number of items which are bought by her at price of $3 is less than 10. Similarly Number of items which are bought by her at price of $2 is less than 10.
we know that 1 CENT = 0.01 $
We also know that 10 30-cents will worth 3 dollars, so the number of cents which are bought by her at price of $0.01 is greater than 10.
Now, Let she bought 20 items at price of 0.01$
Then 20*0.3 = 6$
It means 30$-6$ = 24$
24$ are left to purchase the things which are at price of 2$ and 3$.
If we let she purchase 4 items at cost $3 then
Then 4*$3 = 12$
It means 24$-12$ = 12$
Now, with remaining money she bought 6 items at cost $2.
So, she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.
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she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.
According to the statement
Janice bought total items = 30
Price of items are 30 cents, 2 dollars, or 3 dollars.
Total purchase price of Janice = 30$
If we let she bought 10 items at price of 3$, Then it is not possible
So, Number of items which are bought by her at price of $3 is less than 10. Similarly Number of items which are bought by her at price of $2 is less than 10.
we know that 1 CENT = 0.01 $
We also know that 10 30-cents will worth 3 dollars, so the number of cents which are bought by her at price of $0.01 is greater than 10.
Now, Let she bought 20 items at price of 0.01$
Then 20*0.3 = 6$
It means 30$-6$ = 24$
24$ are left to purchase the things which are at price of 2$ and 3$.
If we let she purchase 4 items at cost $3 then
Then 4*$3 = 12$
It means 24$-12$ = 12$
Now, with remaining money she bought 6 items at cost $2.
So, she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.
find the equation of the line y=mx+b form with the slope 3 that passes through the point (5,19)
The equation of the line that has a slope of 3 and that passes through the point (5,19) is y = 3x + 4
Equation of a straight lineFrom the question, we are to determine the equation of the line that has a slope of 3 and that passes through the point (5,19)
Using the point-slope form of an equation of a line
y - y₁ = m(x - x₁)
Where m is the slope
and (x₁, y₁) is a point on the line
From the given information
m = 3
x₁ = 5
y₁ = 19
Putting the parameters into the equation, we get
y - 19 = 3(x - 5)
y - 19 = 3x - 15
y = 3x -15 + 19
y = 3x +4
Hence, the equation of the line that has a slope of 3 and that passes through the point (5,19) is y = 3x + 4
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Help please you don’t know how much this means to me
[tex]a(0) = 1 \: \: \: \: \: \: b(0) = 2 \: \: \: \: \: c(0) = 3 \\ a(1) = b(0) + c(0) = 2 + 3 = 5 \\ b(1) = a(0) + c(0) = 1 + 3 = 4 \\ c(1) = a(0) + b(0) = 1 + 2 = 3 \\ \\ a(2) = b(1) + c(1) = 4 + 3 = 7 \\ b(2) = a(1) + c(1) = 5 + 3 = 8 \\ c(2) = a(1) + b(1) = 5 + 4 = 9[/tex]
[tex]a(3) = b(2) + c(2) = 8 + 9 = 17\\ b(3) = a(2) + c(2) =7 + 9 = 16 \\ c(3) = a(2) + b(2) = 7 + 8 = 15 \\ \\ a(4) = b(3) + c(3) = 16 + 15 = 31 \\ b(4) = a(3) + c(3) = 17 + 15 = 32 \\ c(4) = a(3) + b(3) = 17 + 16 = 33[/tex]
[tex]a(5) = 32 + 33 = 65 \\ b(5) = 31 + 33 = 64 \\ c(5) =31 + 32 = 63 \\ \\ a(6) = 64 + 63 = 127 \\ b(6) = 65 + 63 = 128 \\ c(6) = 65 + 64 = 129 \\ [/tex]
[tex]a(7) = 128 + 129 = 257 \\ b(7) = 127 + 129 = 256 \\c (7) = 127 + 128 = 255 \\ \\ a(8) = 256 + 255 = 511 \\ b(8) = 257 + 255 = 512 \\ c(8) = 257 + 256 = 513[/tex]
[tex]a(9) = 512 + 513 = 1025 \\ b(9) = 511 + 513 = 1024 \\ c(9) = 511 + 512 = 1023 \\ \\ a(10) = 1024 + 1023 = 2047 \\ b(10) = 1025 + 1023 = 2048 \\ c(10) = 1025 + 1024 = 2049[/tex]
b)[tex]a(n) + b(n) + c(n) = \\ 2(a(n - 1) + b(n - 1) + c(n - 1)) \\ 6 \times 2 {}^{n } [/tex]
c)[tex]6 \times 2 {}^{n} > 100 \: 000 \\ 2 {}^{n} > \frac{100 \: 000}{6} \\ n > log {}^{2} ( \frac{100 \: 000}{6} ) \\ n > 14.02468 \\ n = 15[/tex]
Using the quadratic formula, solve the
equation below to find the two possible
values of t.
6x^2-35=-11x
Give each value as a fraction in its
simplest form.
The two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2
What are the two possible solution to the equation?
Given the equation; 6x² - 35 = -11x
The quadratic formula is expressed as;
x = [ -b±√( b² - 4(ac) ]/2a
First, we re-arrange our equation in the form of ax² + bx + c = 0
6x² + 11x - 35 = 0
a = 6b = 11c = -35We substitute into the formula.
x = [ -b±√( b² - 4(ac) ]/2a
x = [ -11±√( 11² - 4( 6 × -35 ) ]/2×6
x = [ -11±√( 121 + 840 ]/12
x = [ -11±√961 ]/12
x = [ -11 ± 31 ]/12
x = (-11 + 31)/12, (-11 + 31 )/12
x = 20/12, -42/12
x = 5/3, -7/2
Therefore, the two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2
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Initially, there were only 86 weeds in the garden. The weeds grew at a rate of 8% each week. The following function represents the weekly weed growth: f(x) = 86(1.08)x. Rewrite the function to show how quickly the weeds grow each day.
f(x) = 86(1.08)7x; grows approximately at a rate of 5.6% daily
f(x) = 86(1.087)x; grows approximately at a rate of 0.56% daily
f(x) = 86(1.01)x; grows approximately at a rate of 0.1% daily
f(x) = 86(1.01)7x; grows approximately at a rate of 1% daily
The function is f(x) = 86(1.01)^7x; grows approximately at a rate of 1% daily
How to rewrite the function?The function is given as:
f(x) = 86(1.08)^x
There are 7 days in a week.
This means that:
1 day = 1/7 week
So, x days is
x day = x/7 week
Substitute x/7 for x in
f(x) = 86(1.08)^(x/7)
Rewrite as:
f(x) = 86(1.08^1/7)^x
Evaluate
f(x) = 86(1.01)^x
In the above, we have:
r = 1.01 - 1
Evaluate
r = 0.01
Express as percentage
r = 1%
Hence, the function is f(x) = 86(1.01)^7x; grows approximately at a rate of 1% daily
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Answer: the answer is d
Step-by-step explanation:
Can someone please help me with this? I'll give brainliest :)
Based on the information given find the slope from [2,5] Is interval notation and means from x=2 to x=5.
16. y = 3x - 4
17. y = 2x^2-4x - 2
The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
How to determine the slope?The interval is given as:
x = 2 to x = 5
The slope is calculated as:
[tex]m = \frac{y_2 -y_1}{x_2-x_1}[/tex]
16. y = 3x - 4
Substitute 2 and 5 for x
y = 3*2 - 4 = 2
y = 3*5 - 4 = 11
So, we have:
[tex]m = \frac{11 - 2}{5 - 2}[/tex]
[tex]m = \frac{9}{3}[/tex]
Divide
m = 3
Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3
17. y = 2x^2-4x - 2
Substitute 2 and 5 for x
y = 2 * 2^2 - 4 * 2 - 2 = -2
y = 2 * 5^2 - 4 * 5 - 2 = 28
So, we have:
[tex]m = \frac{28 + 2}{5 - 2}[/tex]
[tex]m = \frac{30}{3}[/tex]
Divide
m = 10
Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
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Find the midpoint of a and b when a has coordinates (2,3) and b has coordinates (8,9)
The midpoint of co-ordinate is (5, 6)
Add both "x" coordinates, and divide by 2.
Add both "y" coordinates, and divide by 2.
Given that;
Coordinates of A = (2,3)
Coordinates of B = (8,9)
Find:
Midpoint of co-ordinate
Computation:
Midpoint of co-ordinate = [(x1 + x2) / 2], [(y1 + y2) / 2]
Midpoint of co-ordinate = [(2 + 8) / 2], [(3 + 9) / 2]
Midpoint of co-ordinate = [10 / 2], [12 / 2]
Midpoint of co-ordinate = (5, 6)
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What is the sum of the 12th square number and the 9th square number
Answer: 225
Step-by-step explanation:
What is a square number?
A square number is a product of a number times itself
So, the 12th square number would be 12 * 12, or 12²
The 9th square number would be 9 * 9, or 9²
The equation would be 12² + 9²
So:
12² + 9²
= 144 + 81
= 225
So, the answer is 225
Which search method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line
The wide-area search method employs the use of markers such as knots at regular intervals along the search line.
Given the method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line.
In order to locate, relieve distress, and preserve the life of a person who has been reported missing or is believed to be lost, stranded, or is considered a high-risk missing person, wide area search and rescue refers to activities occurring within large geographic areas. It also refers to the removal of any survivors to a safe location.
Hence, the wide-area search method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line
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Write the equation of the sinusoidal function shown.
A) y = cos x - 1
B)y=sin x - 1
C) y=2 sin x - 1
D) y = 2 cos x - 1
Answer:
A. y= cos x - 1
Step-by-step explanation:
short answer: this is basically the parent graph cos(x), just vertically shifted down 1 unit.
longer answer:
standard form is y = a cos(bx-c) +d
a = amplitude
b = 2pi/period
c = horizontal shift
d = vertical shift (also equal to midline)
for this graph
a=1
period is 2pi, so b=1
there is no horizontal shift so c=0
d= -1 because it is shifted down one unit from axis (midline is at -1)
BRAINLIEST TO CORRECT ANSWER
There is a pair of parallel sides in the following shape.
what is the area
The area of the given figure is 38 square units
Area of a trapezoidThe area of the given trapezoid is expressed as:
A = 0.5(a+b)h
where
a and b are the sides
h is the height
Substitute
A = 0.5(9+10) * 4
A = 19 * 2
A = 38 square units
Hence the area of the given figure is 38 square units
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PLEASE HELP ME AS SOON AS POSSIBLE
a) The linear function that models the population in t years after 2004 is: P(t) = -200t + 29600.
b) Using the function, the estimate for the population in 2020 is of 26,400.
What is a linear function?A linear function is modeled by:
y = mx + b
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.The initial population in 2004, of 29600, is the y-intercept. In 12 years, the population decayed 2400, hence the slope is:
m = -2400/12 = -200.
Hence the equation is:
P(t) = -200t + 29600.
2020 is 16 years after 2004, hence the estimate is:
P(16) = -200(16) + 29600 = 26,400.
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How many solutions does this nonlinear system of equations have? NEED HELP ASAP!
Answer:
Step-by-step explanation:
two
Can u guys pls help me with this homework
The value of √(7 * 23 - 1)/8 is 4.47, the values of a, b and c are -14/11, -10/11 and 3, respectively and the area of the shape is 5√5 + 5 square meters
How to evaluate the radical expression?The question goes thus:
If √5 = 2.236, evaluate √(7 * 23 - 1)/8
We have:
√(7 * 23 - 1)/8
Evaluate the product of 7 and 23
√(7 * 23 - 1)/8 = √(161 - 1)/8
Evaluate the difference of 161 and 1
√(7 * 23 - 1)/8 = √160/8
Evaluate the quotient of 160 and 8
√(7 * 23 - 1)/8 = √20
Express 20 as the product 4 and 5
√(7 * 23 - 1)/8 = √(4 * 5)
Expand the product
√(7 * 23 - 1)/8 = √4 * √5
Express √4 as 2
√(7 * 23 - 1)/8 = 2 * √5
Substitute √5 = 2.236
√(7 * 23 - 1)/8 = 2 * 2.236
Evaluate the product
√(7 * 23 - 1)/8 = 4.472
Approximate
√(7 * 23 - 1)/8 = 4.47
Hence, the value of √(7 * 23 - 1)/8 is 4.47
How to simplify the radical expression?The expression is given as:
(3√2 + 5√6)/(3√2 - 5√6)
Rationalize the above expression
(3√2 + 5√6)/(3√2 - 5√6) * (3√2 + 5√6)/(3√2 + 5√6)
Evaluate the product
(3√2 + 5√6)²/((3√2)² - (5√6)²)
Simplify the denominator
(3√2 + 5√6)²/(18 - 150)
This gives
[(3√2)² + (5√6)² + 2 *(3√2) * (5√6)]/(-132)
Simplify the numerator
[168 + 120√3]/(-132)
Simplify the fraction
-14/11 - 10√3/11
Hence, the values of a, b and c are -14/11, -10/11 and 3, respectively
How to determine the area?The area is calculated as:
A = 1/2 * (Sum of parallel bases) * Height
So, we have:
A = 1/2 * (4 + 3√5 + 6 - √5) * √5
Evaluate the like terms
A = 1/2 * (10 + 2√5) * √5
Evaluate the product
A = (5 + √5) * √5
Evaluate the product
A = 5√5 + 5
Hence, the area of the shape is 5√5 + 5 square meters
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What is the slope of a line that is parallel to the line y = 3/4x+2?
Answer: 3/4
Step-by-step explanation:
Parallel lines have the same slope.
From the top of a 16 m tall building, the angle of depression to a car on the road is 35°. To the nearest metre, how far is the car from the base of the building?
The distance of the car to the base of the building is 23 metres.
How to find the distance of the car from the building using angle of depression?The situation will form a right angle triangle.
Therefore, the distance of the car to the base of the building is the adjacent side of the right angle triangle formed.
Therefore,
tan 35 = opposite / adjacent
tan 35 = 16 / x
x tan 35 = 16
x = 16 / tan 35
Therefore,
x = 16 / 0.70020753821
x = 22.8506141103
x = 23 meters
Therefore, the distance of the car to the base of the building is 23 metres.
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The temperature was -20.5°F at 5 A.M. and rose 5 degrees per hour for the next 5 hours. Melissa says the temperature at 10 A.M. was -5.5°F. Which statement identifies Melissa’s error and the correct answer?A.Melissa multiplied incorrectly. The correct answer is -0.5°F.B.Melissa multiplied incorrectly. The correct answer is 9.5°F.C.Melissa added incorrectly. The correct answer is 4.5°F.D.Melissa added incorrectly. The correct answer is 5.5°F.
The statement which identifies Melissa’s error and the correct answer is; Melissa added incorrectly. The correct answer is 4.5°F
TemperatureInitial temperature = -20.5°FChange in temperature per hour = 5°FNumber of hours = 5New temperature = Initial temperature + (Change in temperature per × Number of hours)
= -20.5°F + (5°F × 5)
= -20.5°F + (25°F)
= 4.5°F
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Answer:
C
Step-by-step explanation:
In the diagram AB/BC = AD/DE
Substitute the known values into the proportion and solve for DE
Answer:
[tex]\huge\boxed{\sf DE = 9}[/tex]
Step-by-step explanation:
From the figure,
AB = 2
BC = 3
AD = 6
Substitute in the given formula
[tex]\displaystyle \frac{AB}{BC} =\frac{AD}{DE} \\\\\frac{2}{3} = \frac{6}{DE} \\\\Cross \ Multiply \\\\2 \times DE = 6 \times 3\\\\2DE = 18\\\\Divide \ 2 \ to \ both \ sides\\\\DE = 18/2\\\\DE = 9\\\\\rule[225]{225}{2}[/tex]
Half of a set of the parts are manufactured by machine A and half by machine B. Eight percent of all the parts are defective. Two percent of the parts manufactured on machine A are defective. Find the probability that a part was manufactured on machine A, given that the part is defective. (Round your answer to 4 decimal places.)
The probability that a part was manufactured on machine A, given that the part is defective is P ( A | D ) = 0.024.
What is probability?Probability is the branch of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely it is that a claim is true. The probability of an event is a number between 0 and 1, with 0 indicating impossibility and 1 indicating certainty.To find the probability that a part was manufactured on machine A, given that the part is defective:
The probability that a part was manufactured on machine A given that part is defective:
P ( A | D )
P ( A | D ) = [P (A) * P ( D | A )]/ P ( D )
Where: P (A) is the probability that the part is manufactured in machine A which is 0.2 (half of the parts are manufactured in machine A)
P (D/A) is the probability of a defective part given that the part was manufactured in machine A which is 2% or 0.02
And finally, the probability of defective part in the production is 8% or 0.08 hence :
P ( A | D ) = [ ( 0.2 ) * 0.02 ] / 0.08
P ( A | D ) = 0.024
Therefore, the probability that a part was manufactured on machine A, given that the part is defective is P ( A | D ) = 0.024.
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Solution
We can start with the pythagorean theorem:
(leg 1)² + (leg 2)² = (hypotenuse)²
Substitute the values we know.
15² + x² = 32²
Solve for x.
X =
Answer:
28.26658805 (I included every digit in case your teacher needs you to round)
Step-by-step explanation:
In order to find x, we need to isolate x by subtracting 15^2 and taking the square root of both sides.
Thus, we have:
[tex]15^2+x^2=32^2\\x^2=32^2-15^2\\\sqrt{x^2} =\sqrt{(32^2-15^2)} \\\sqrt{x^2}=\sqrt{799} \\x=28.26658805[/tex]
When you roll two number cubes, what are the odds in simplest form against getting two numbers greater than 4?
A. 4:1
B. 1:4
C. 1:8
D. 8:1
The odds in simplest form against getting two numbers greater than 4 is 1 : 4.
What are the odds?Probability determines the odds that a random event would happen. The odds the event occurs is 1 and the probability that the event does not occur is 0.
The odds of getting two numbers greater than 4 = 2 x (numbers greater than 3 in a cube / total number of sides in a cube)
2(3/6)
2 x 1/2 = 1 : 4
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In the 1980’s, a clinical trial was conducted to determine if taking an aspirin daily reduced the incidence of heart attacks. Of 22,071 medical doctors participating in the study, 11,037 were randomly assigned to take aspirin and 11,034 were randomly assigned to the placebo group. Doctors in this group were given a sugar pill disguised to look like aspirin. After six months, the proportion of heart attacks in the two groups was compared. Only 104 doctors who took aspirin had a heart attack, whereas 189 who received the placebo had a heart attack. Can we conclude from this study that taking aspirin reduced the chance of having a heart attack? the purpose of this study was to determine whether taking an aspirin daily reduces the proportion of heart attacks.
There is enough evidence to conclude that taking aspirin cannot reduces the chance of cancer.
Given sample size of patients take aspirin 11037, sample size of patients who have assigned placebo group be 11034. 104 doctors who take aspirin had a heart attack, 189 doctors had placebo had heart attacks.
First we have to form hypothesis.
[tex]H_{0} :p{1} -p_{2} =0[/tex]
[tex]H_{1}:p_{1} -p_{2} < 0[/tex]
We have to find the respective probabilities.
[tex]p_{1}[/tex]=104/11037
=0.0094
[tex]p_{2}[/tex]=189/11034
=0.0171
Now their respective margin of errors.
[tex]s_{1}[/tex]=[tex]\sqrt{ {(0.0094*0.9906)/11037}[/tex]
=0.0009
[tex]s_{2}[/tex]=[tex]\sqrt{0.0171*0.9829}[/tex]
=0.0011
Hence the distribution of the differences,they are given by:
p=[tex]p_{1} -p_{2}[/tex]
=0.0094-0.0171
=-0.0077
S=[tex]\sqrt{s_{1} ^{2}+s_{2} ^{2} }[/tex]
=[tex]\sqrt{(0.0009)^{2} +(0.0011)^{2} }[/tex]
=0.00305
z=(p -f)/S (In which f=0 is the value tested at the null hypothesis)
=(-0.0077-0)/0.00305
=-2.52
p value will be 0.005.
p value of 0.05 significance level.
z=1.96.
1.96>0.005
So we will reject the null hypothesis which means it cannot reduce the whole chance of becomming a heart attack.
Hence there is enough evidence to conclude that taking aspirin cannot reduces the chance of cancer.
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If the parabola of equation y=k−x2 is tangent to the line of the equation y=x then what is the value of k ?
The value of k is 1/4.
According to the statement
we have given
The equation of parabola is y=k−x2
And tangent to the line of equation is y = x
and we have to find the value of K.
So, let y=k−x2 -(1)
and let y = x -(2)
(2) is the tangent to the (1) then
therefore they cut at
y=k−x2 -(1)
y = x -(2)
so, put (2) in the (1) then
x = k- (x)^2
(x)^2 + x = k
The above written equation has one real number then for this D =0
so, (x)^2 + x - k = 0
-1 -1*4*k = 0
-1 - 4k = 0
-4k = 1
The value of k is -1/4.
So, The value of k is 1/4.
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