Answer:
False
Explanation:
Im pretty sure the answer is false
A light bulb uses 1.2 A when connected across a 120 V source. What is the resistance by the bulb?
A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°.
a. What is the horizontal component of the velocity?
b. What is the vertical component of the velocity?
c. How long does it take the ball to reach its highest point?
d. What is the maximum height of the ball?
e. What is the total amount of time that the ball is in the air?
f. How far is the ball from the football player when it lands?
I would appreciate any help :)
Answer:
see explanation
Explanation:
Answer:
a. 13.22 m/s
b. 16.32
c. 1.664 s
d. 13.58
e. 3.328
f. 40.0m
Explanation:
This is basically what the guy said, i dunno if you saw the letters, but he added some at the end of every answer.
If one person is applying an upward force equal to 60 N at one end, at what location on the board is the other person applying an upward force
Answer:
When one person applies force f1 = 60 N at one end, the other person applies f2 = 160 - 60 = 100 N. The torques about the center must balance. Thus the distances from the center d1 and d2 must be such that f1*d1 = f2*d2, or 60*1.5 = 100*d2, so d2=0.9. Thus f2 must be applied at a point 1.5 + 0.9 = 2.4 m from the end where f1 is applied.
What are the two main regions of the body?
cranial and spinal
axial and appendicular
trunk and limbs
muscular and skeletal
Answer: Your correct answer would be the second option; axial and appendicular. The axial region makes up the axis of the human body, this includes your head, neck, etc. The appendicular region makes up the parts of the human body that connects to the axial region, for example limbs and appendages.
Have you ever written a bio-data or an application letter? Share your experience in the
space below. (e.g. How did you find the experience? What was hard? What was easy?)
Leave the space blank if you have never written any of these.
Answer:
I found the experience tasking
Explanation:
I wouldn't say it was hard, neither was it easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously. Of course I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way.
I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn
The experience of writing a bio-data or an application letter was quite a tasking goal, where proper structure is required.
The given problem is based on the fundamentals of bio-data. Biodata is a document that is used to display the biographical data about the work experience in any organization.
As per my experience it was neither hard nor easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously. I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way. I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn.Thus, it is concluded that writing a bio-data or an application letter was quite a tasking goal, where proper structure is required.
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Suppose that a brass rod 2.0 m long expands 0.2 cm when its temperature is increased a certain amount. By how much will a brass rod 80 m long expand with the same change in temperature?
Answer:
0.08 m
Explanation:
Linear expansivity brass = 2 * 10^-5 C
Linear expansivity = change in length / (initial length * θ)
Change in length = 0.2cm = 0.002m
Initial length = 2m
2 * 10^-5 = 0.002 / (2 * θ)
(2 * 10^-5 * 2θ) = 0.002
4 * 10^-5θ = 0.002
θ = 0.002 / 4 * 10^-5
θ = 2 * 10^-3 / 4 * 10^-5
θ = 0.5 * 10^2
θ = 50°C
For a rod of original length 80m at the same temperature of 50°C
Linear expansivity = change in length / (initial length * θ)
Change in length = dL
2 * 10^-5 = dL / (80 * 50)
2 * 10^-5 * 80 * 50 = dL
160 * 10^-5 * 50 = dL
8000 * 10^-5 = dL
0.08 m = dL
Hence, change in length = 0.08m
A 10-turn ideal solenoid has an inductance of 3.5 mH. When the solenoid carries a current of 2.0 A the magnetic flux through each turn is:
Answer:
7 * 10^-4Wb
Explanation:
The magnetic flux is the product of the inductance and current
Magnetic flux = LI
L is the inductance = 3.5mH
I is the current = 2.0A
Number of turns N = 2A
Since for a 10-turn solenoid, L = 3.5mH
For a one-turn solenoid, L = 3.5/10 = 0.35mH
magnetic flux = 0.35mH * 2
magnetic flux = 0.35 * 10^-3 * 2
magnetic flux = 0.7* 10^-3
Magnetic flux = 7 * 10^-4Wb
Hence the magnetic flux through each turn is 7 * 10^-4Wb
The magnetic flux through each turn is 7 ×10⁻⁴ Wb. The magnetic flux is the product of the inductance and current.
What is megnetic flux?
The surface integral of the normal component of the magnetic field B across a surface is the magnetic flux through that surface. It is commonly indicated by the letters B.
The weber is the SI unit for magnetic flux, while the maxwell is the CGS unit.
The given data in the problem is;
[tex]\rm \phi[/tex] is the magnetic flux =?
L is the inductance = 3.5mH
I is the current = 2.0A
N number of turns of solenoid = 2A
The inductance for the one turn is found by;
For a 10-turn solenoid, L = 3.5mH
For a one-turn solenoid, L = 3.5/10 = 0.35mH
The megnetic flux through each turn is found by;
[tex]\rm \phi = L \times I \\\\ \rm \phi = 0.35 \times 10^{-3}\times 2\\\\ \rm \phi =7 \times 10^{-4}[/tex]
Hence the magnetic flux through each turn is 7 ×10⁻⁴ Wb.
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In an RC parallel circuit, Et = 480 V, R = 50ko, and XC = 47 ko. What is the reactive power?
Correct question is;
In an RC parallel circuit, Et = 480 V, R = 50kΩ, and XC = 47 kΩ. What is the reactive power?
Answer:
P_r = 4.9 VARs
Explanation:
We are given;
Total voltage: Et = 480 V
Resistance; R = 50kΩ = 50000 Ω
Capacitive reactance; XC = 47 kΩ = 47000 Ω
Formula for current across the capacitor is;
Et = I_c • XC
I_c = Et/XC
l_c = 480/47000
I_c = 0.01021 A
Formula for reactive power is;
P_r = (I_c)² × XC
P_r = 0.01021² × 47000
P_r = 4.9 VARs
according to newton's first law of motion what is the reason for a ball throwing up in the airfall back to earth
A bird perched in a tree is balanced or unbalanced
Answer: Balanced
Explanation: When a bird is perched on a tree it is sitting still will stay still if the forces acting on it are balanced.
Did the energy you used to lift the notebook get stored in the book as potential energy? Explain your answer with reasons.
Answer:
Because when you move a object the energy stored in moving objects. As the object moves faster, more energy is stored. Motion energy is the sum of potential and kinetic energy in an object that is used to do work.
Explanation:
answer it please
What is the Central Idea of "Shelter Dog Protects Owner with Epilepsy“
What is the author’s viewpoint?
Do you agree or disagree with that viewpoint?
Why? Explain your answer.
parpgraph 1-2
Answer:
Yes, the energy used to lift the book was stored in the book as potential energy. The book moved when it was let go.
Explanation:
This is what edmentum sample answer says so I hope this helps out!
Only 35 % of the intensity of a polarized light wave passes through a polarizing filter. What is the angle between the electric field and the axis of the filter
Answer:
The angle between the electric field and the axis of the filter is 54⁰
Explanation:
Apply the equation for intensity of light through a polarizer.
[tex]I = I_oCos^2 \theta[/tex]
where;
I is the intensity of the transmitted light
I₀ is the intensity of the incident light
θ is the incident angle
If only 35 % of the intensity of a polarized light wave passes through a polarizing filter, then the ratio of the intensity of the transmitted light to that of the intensity of the incident light is given by;
[tex]\frac{I}{I_o} = Cos^2 \theta\\\\\frac{35}{100} = Cos^2 \theta\\\\Cos^2 \theta = 0.35\\\\Cos\theta = \sqrt{0.35} \\\\Cos\theta = 0.5916\\\\\theta = Cos^{-1}(0.5916)\\\\\theta = 54 ^0[/tex]
Therefore, the angle between the electric field and the axis of the filter is 54⁰
The angle between the electric field and the axis of the filter for the polarized light wave which passes through a polarizing filter is 54°.
What is electric field?The electric field is the field, which is surrounded by the electric charged. The electric field is the electric force per unit charge.
From the Malus's law, the intensity of the polarized beam can be calculated with the following formula.
[tex]I=I_o\cos^2\theta[/tex]
Here, (I₀) is the intensity of the polarized beam incident on the observer θ is the angle of incident.
It is given that only 35 % of the intensity of a polarized light wave passes through a polarizing filter.
The angle between the electric field and the axis of the filter can be found out using the above formula as,
[tex]35\%=(100\%)\cos^2\theta\\\theta=\cos^{-1}\sqrt{\left(\dfrac{35}{100}\right)}\\\theta=54^o[/tex]
Hence, the angle between the electric field and the axis of the filter for the polarized light wave which passes through a polarizing filter is 54°.
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A student drops a 2.4-kg ball. It’s speed right before hitting the ground is 5 m/s. If 15 J of energy was transferred to the environment as the ball fell, what was the total initial energy of the ball?
21 J
30 J
45 J
6 J
The answer is 45J
Don’t know how to explain sorry
what are the characteristics of image when object is between f1 and 2f1 for concave lense?
Answer:
The required diagram is shown in the figure. When an object is placed in front of the convex lens, i.e., between 2F
1
and F
1
, its image is formed beyond 2F
2
on the other side of the lens. The image is real, inverted and enlarged.
solution
A carriage of 20 kg is pulled with a force of 35 N. How far the carriage will go
doing 95 J work?
Answer:
2.71 m
Explanation:
Force is the product of mass and acceleration
F=m*a
Work done is the product of force and distance
Work done=F*d
In this case;
F= 35 N
Work done = 95 J
95 =35 * d
95 /35 = d
2.71 m= d
A 1000 kg car and a 2000 kg car are lifted the same distance in a
mechanic's shop. Neglecting friction, raising the more massive car
requires
Answer:
Twice as much work
Explanation:
2. An 85.5 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 12.0 m) and spun at a constant angular velocity of 18.4 rpm. Answer the following:
(a) What is the angular velocity of the centrifuge in ?
(b) What is the linear velocity of the astronaut at the outer edge of the centrifuge?
(c) What is the centripetal acceleration of the astronaut at the end of the centrifuge?
(d) How many g’s does the astronaut experience?
(e) What is the centripetal force experienced by the astronaut?
Answer Expert Verified
Hello here is your answer and also please mark me as brainlest
Since one revolution around a circle is 2 pi radian; hence 1 rpm equals 2 pi radians per minute. And because a minute has 60 seconds, 1 rpm equals 1/60 revolution per second. Therefore, we have 2 pie/60 * 15.3 = 0.2513 rps. The linear velocity v = wr where w is the angular velocity in rad/s and r is the distance. So we have 0.2513 * 10.0 = 2.513 rad/s The centripetal acceleration is given by a = w^2 r = (2.513)^2 * 10 = 63.15 rad/s2 The centripetal force F = mass * centripetal acc = 75 * 63.15 = 4736.25 N The torque = centripetal force * distance = 4736 * 63.15 = 299078.4 Nm Two forces acts on the astronaut. The normal force and acceleration due to gravity.
I hope this help you
brainlest
Rotational kinematics and Newton's second law allow to find the results for the astronaut's movement in the centrifuge are:
a) The angular velocity is: w = 1.927 rad / s
b) The linear velocity is: v = 23.1 m / s
c) The centripetal acceleration is: a = 6.417 10³ m / s²
d) The centripetal acceleration is: a = 6.548 10² g
e) The centripetal force F = 5.49 10⁵ N
given parameters
The mass of the astronaut m = 85.5 kg Centrifuge radii r = 12.0 m Angular velocity w = 18.4 rpm (2prad / 1rev) (1min / 60s) = 1.927 rad / sTo find
a) angular velocity
b) linear velocity
c) centripetal acceleration
d) acceleration in units of gravity (g)
e) the centripetal force
The angular velocity is defined as the rotated angle in the unit of time.
[tex]w = \frac{\Delta \theta}{t}[/tex]
Angular and linear variables are related.
v = w r
Where w is the angular velocity, θ is the angle, t the time, v the lienal velocity and R the radius of the cetnrifuga
Let's answer the questions:
a) The angular velocity of the centrifuge and the astronaut are equal
w = 1.927 rad / s
b) Linear velocity
v = 1.927 12.0
v = 23.1 m / s
c) Centripetal acceleration has the formula:
a = [tex]\frac{v^2}{R}[/tex]
a = [tex]\frac{23.1^2}{12.0}[/tex]
a = 6.417 10³ m / s²
d) The value of this eceleration as a function of gravity
[tex]\frac{a}{g}[/tex] = 6.417 10³ / 9.8
[tex]\frac{a}{g}[/tex] = 6.548 10²
a = 6.548 10² g
e) The centripetal force
F = ma
F = 85.5 6.417 10³
F = 5.49 10⁵ N
In conclusion, using rotational kinematics and Newton's second law we can find the results for the movement of the astronaut in the centrifuge are:
a) The angular velocity is: w = 1.927 rad / s
b) The linear velocity is: v = 23.1 m / s
c) The centripetal acceleration is: a = 6.417 10³ m / s²
d) The centripetal acceleration is: a = 6.548 10² g
e) The centripetal force F = 5.49 10⁵ N
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What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N?
Answer:
What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N? a=2m/s^2 Applying Newton's 2nd law, a=Fnet/m=(400N)/(200kg)=2m/s^2. The acceleration is constant.
Explanation:
The person begins to push a refrigerator with a force of 400 N. So, the acceleration of the refrigerator will be 2 m/s².
What is Acceleration?In mechanics, acceleration is the measure of how rapidly an object's velocity changes over time. It is a vector quantity. An object's acceleration depends on the direction of the net force exerted on it.
A vector quantity, acceleration is something that has both a magnitude and a direction. As a vector quantity, velocity is also. The ratio of the velocity vector change over a time interval to that interval is the definition of acceleration.
There are several types of acceleration :
Uniform AccelerationNon-Uniform AccelerationAverage AccelerationAccording to the question, the given values are :
Force applied to the refrigerator is 400 N.
The mass of the refrigerator is 200 kg.
Use the 2nd law of newton,
[tex]Force= mass*acceleration[/tex]
Acceleration = 400/200
Acceleration = 2 m/s².
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A force of 400-N pushes on a 25-kg box horizontally. The box accelerates at 9 m/s? Find the coefficient of kinetic friction between the box and floor.
Answer:
0.69Explanation:
Using the Newtons law of motion;
[tex]\sum Fx = ma_x\\Fm - Ff = ma_x[/tex]
Fm is the moving force = 400N
Ff is the frictional force = μR
μ is the coefficient of kinetic friction
R is the reaction = mg
m is the mass
a is the acceleration
The equation becomes;
[tex]Fm - \mu R = ma_x\\Fm - \mu mg = ma_x\\400- \mu (25)(9.8) = 25(9)\\400 - 254.8 \mu = 225\\- 254.8 \mu = 225 - 400\\- 254.8 \mu = -175\\ \mu = \frac{-175}{- 254.8} \\\mu = 0.69[/tex]
Hence the coefficient of kinetic friction between the box and floor is 0.69
The coefficient of kinetic friction between the box and the floor is 0.714.
Friction: This can be defined as the force that tends to oppose two surfaces in motion.
The question above can be solved using the formula
F-ma = mgμ................. Equation 1
Where F = Force applied to push the box, m = mass of the box, a = acceleration of the box, μ = coefficient of kinetic friction, g = acceleration due to gravity.
make μ the subject of the equation
μ = (F-ma)/mg................ Equation 2
From the question,
Given: F = 400 N, m = 25 kg, a = 9 m/s²,
Constant: g = 9.8 m/s²
Substitute these values into equation 2
μ = [400-(25×9)]/(25×9.8)
μ = (400-225)/245
μ = 175/245
μ = 0.714
Hence, the coefficient of kinetic friction between the box and the floor is 0.714.
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matter can be a solid, lquid or gas. but you cannot see the particles or adoms that make up matter because they are
Answer:
very small...
Explanation:
i guess... but i may be missing something. the question feels too straightforward
sound is faster than light that is why we hear thunder before we see lightning
Answer:
false
Explanation:
sound travels slower than light. that is why we see lightning before we hear the thunder
80g of kerosene was burned to raise the temperature of 3 l of water to 90c ⁰C. What is the efficiency of the burner?
Answer:
363
Explanation:
80g of kerosene was burned to raise the temperature
k = 90+273
= 363
A boy throws a tell ball straight up . disregarding any effects of air resistance, the forces acting 9n the ball untill it returns to the ground is are
What are the 6 uses of electromagnet?
How does the air pressure inside a tennis ball change when you hit it?
WHAT IS CHANGES IN SOLID MATERIALS
Answer: Solid to a Liquid Liquid to a Solid Liquid to a Gas Gas to a Liquid Solid to a Gas Gas to a Solid
Explanation:
What do the skull and vertebrae have in common
Answer: ok
Explanation: ok
A ferry crossed the Potomac River four times in one day. The ferry traveled the same distance for each trip, but it took different amounts of time. The time for each trip is shown in the table below. Time for Ferry to Cross on Different Trips Trip Number Time Trip 1 10 minutes Trip 2 11 minutes Trip 3 9 minutes Trip 4 12 minutes On which trip did the ferry travel the fastest? A. Trip 3 B. Trip 2 C. Trip 4 D. Trip 1
Explanation:
trip 3 ( 9 minutes)
If the ferry is moving at a faster speed, it will travel the same distance in a shorter time. The ferry crossed the river the fastest on Trip 3 because it took the shortest amount of time on that trip.
A black widow spider hangs motionless from a web that extends vertically from the ceiling above. If the spider has a mass of 1.27 g, what is the tension in the web
Answer:
Tension = 0.012 N
Explanation:
If the black widow spider is hanging vertically motionless from the ceiling above. Then, the weight of the spider must be balancing the tension in the spider web. Therefore,
Tension = Weight
Tension = mg
where,
m = mass of spider = 1.27 g = 0.00127 kg
g = acceleration due to gravity = 9.8 m/s²
Therefore,
Tension = (0.00127 kg)(9.8 m/s²)
Tension = 0.012 N
A motobike's tire rotates with a constant angular speed of 62.8 rad/s. The radius of a tire is 30cm. Assuming that no slipping occurs, the number of
revolutions of the tire in one second is:
a.
12.6
b.
20
C.
18.8
d.
10
Answer:
10
Explanation:
Given that :
Angular speed (w) = 62.8 rad/s
Radius of tire (r) = 30 cm
Number of revolutions per second :
s = 2πr
s = 2π * 0.3 = 1.8849555
The number or revolutions per second :
θ = s / r
θ = 1.884955 / 0.3
θ = 6.283185 rad
Number of revolutions per second :
62.8 / 6.283185
= 9.9949309
= 10