In the diagram AB/BC = AD/DE
Substitute the known values into the proportion and solve for DE

The probability that the first winner randomly selects the card for the pizza topped with ham, artichoke hearts, and pepperoni is 1/560 given that there are 16 toppings to choose from. This can be obtained by finding the total number of all possible three-topping pizzas (3 distinct toppings) using combination formula and finding the probability.

Given that there are 16 toppings,

the total number of all possible three-topping pizzas,

ⁿCₓ = [tex]\frac{n!}{x!(n-x)!}[/tex] = 16!/[3!(16-3)!] = 16!/[3!(13)!] = 14×15×16/3×2 =560

Probability of choosing pizza topped with ham, artichoke hearts, and pepperoni,

P(ham, artichoke hearts, pepperoni) = 1/560

Hence the probability that the first winner randomly selects the card for the pizza topped with ham, artichoke hearts, and pepperoni is 1/560 given that there are 16 toppings to choose from.

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Answer:

Step-by-step explanation:

dddfykb

The area of the shaded part in figure A and B are 2m² and 49 m² respectively.

To determine the area, we must know the shape of the shaded part.

After identifying the shape, we move further to know the formula for such shape

From the figures given in A, we can see that the shaded region is in form of a triangle

a. The area of a right angle is given as;

The base multiplied by the half the height and vice versa

It is written mathematically as;

Area = 1/ 2 × base × height

Where

base = 2m

height = 2m

Substitute into the formula

Area = 1/ 2 × 2 × 2

Area = 2m²

For figure B, the shaded part is a rectangle

The formula for area of a rectangle is given as;

the width multiplied by the length

Area = width × length

Where width = 7m

length = 7m

Area = 7 × 7

Area = 49m ²

Thus, the area of the shaded part in figure A and B are 2m² and 49 m² respectively.

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The distance between the two stations is 360km.

Speed is the rate of change of distance.

Rate is a measure of one quantity against another in this case distance and time.

Analysis:

time at station A = 12:24

time at station B = 14:12

time spent = 14:12 - 12:24 = 1 hour 48 minutes = convert 48 minutes to hour

we divide 48 by 60 = 0.8

Total time = 1.8 hours

Distance = speed x time = 200 x 1.8 = 360 km

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

27.068

28.08

28.15

29.94

Answer: x² + 4x +3=0

Step-by-step explanation:

Add 4x to both sides.

The value of t based on the information about the sphere is 1.3π.

It should be noted that the volume of a sphere is 4/3πr³. In this case, it's divided into 8 equal parts.

Volume of each part = 1/8 × 4/3πr³

= 1/8 × 4/3 × π × 8

= 4/3π

= 1.3πin³

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Answer:

Step-by-step explanation:

So, we’re probably looking at a n9-m0 cusp, since adding 0 to a number gives a sum lower than adding 9 to a slightly smaller number, something that isn’t true elsewhere in the cycle.

We need a n9 where the sum n+9 is divisible by 3. 9 is divisible by 3 already, so n must be divisible by 3 as well. So, it’s 0, 3, 6, or 9.

Taking as the most likely 3 (because a 39 year old is more likely than a 9 year old, 69 year old, or 99 year old to have a child who doesn’t already know their father’s age) we’ll try 39, 40. 3+9=12, 4+0=4, 12/3=4, this is a possible solution.

Do the others work?

0+9=9, 1+0=1, 9/4=/=1

6+9=15, 7+0=7, 15/4=/=7

9+9=18, 1+0+0=1, 18/4=/=1

1+2+9=12, 1+3+0=4, 12/3=4

there are at least two possibles. the father was correct, the father cannot determine his age from what she has been told, she must guess. From what she knows of him, is it more likely that he’s 39, or 129, or even older?

The linear inequality of the given graph is: D. y < -2x + 3.

First, using two points on the line, (0, 3) and (1.5, 0), find the slope (m).

Slope (m) = change in y / change in x = (3 - 0) / (0 - 1.5)

Slope (m) = 3/-1.5 = -2.

Next, substitute (x, y) = (0, 3) and m = -2 into y = mx + b to find the value of b.

3 = -2(0) + b

3 = 0 + b

b = 3

Substitute m = -2 and b = 3 into y < mx + b (the shaded part is at the left, so we use the "<" sign)

y < -2x + 3

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The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

In this problem, the function is:

[tex]g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}[/tex]

The horizontal asymptote is given as follows:

[tex]y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6[/tex]

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

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The correct option is A. hot water moving through a pipe.

Electrical current passing through a metal wire is similar to hot water moving through a pipe.

Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I is a typical way to represent current. The ampere, denoted by the letter A, is the common unit.

The method of flowing of electrical current in metal wire is-

Comparison of flow of electricity with flow of water in pipe-

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The complete question is-

which of the following situations would be mist similar to an electrical current passing through a metal wire in a closed circuit?

A. hot water moving through a pipe

B. an automobile traveling through a tunnel

C. an airplane flying through clouds

D. a flying pan heating up on a hot plate

E. a bird building a nest

The two odd numbers are 43 and 37.

Whole numbers are positive numbers belonging to the set W ∈ {1, 2,3, 4, ...}

The two odd numbers can be represented as (2m-1) and (2n-1) respectively sum=80 and difference = 6

Let m and n be two whole numbers

Therefore

,[tex]2m-1) + (2n-1)= 80\\(2m-1) - (2n-1)= 6\\\\2(m+n-1)=80\\2(m-n)=6\\\\m+n = 41\\m-n=3\\[/tex]

Adding the two equations

[tex](m+n)+(m-n)=2m=44\\m=22\\n=m-3=19\\[/tex]

so m=22 ad n=19. our two odd numbers are 2m-1 = 43 and 2n-1 = 37

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Using an exponential function, it is found that Mary's initial investment was of $3,030.

An exponential function is modeled by:

[tex]y = ab^x[/tex].

In which:

Her investment model, in thousands of dollars, is:

[tex]M(x) = 3.03(1.28)^{2x}[/tex]

Then a = 3.03, since we measure the amount in thousands of dollars, Mary's initial investment was of $3,030.

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Length of each side is 176 feet ² .

each side of house = 22 feet long

Perimeter of octagon = 8 × sides

Length of each side of house = 8 × 22 ⇒ 176 feet²

Therefore, length of each side is 176 feet ² .

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Answer:

0

Step-by-step explanation:

The y values are the same so this line is a straight line with a slop of 0

To check:

To find the slope we use y1-y2/x1-x2

Plug in the numbers: 4-4/-9-7 = 0/-16 = 0

The probablity that the sample's mean length is greate than 6.3 inches is0.8446.

Given mean of 6.5 inches,standard deviation of 0.5 inches and sample size of 46.

We have to calculate the probability that the sample's mean length is greater than 6.3 inches is 0.8446.

Probability is the likeliness of happening an event. It lies between 0 and 1.

Probability is the number of items divided by the total number of items.

We have to use z statistic in this question because the sample size is greater than 30.

μ=6.5

σ=0.5

n=46

z=X-μ/σ

where μ is mean and

σ is standard deviation.

First we have to find the p value from 6.3 to 6.5 and then we have to add 0.5 to it to find the required probability.

z=6.3-6.5/0.5

=-0.2/0.5

=-0.4

p value from z table is 0.3446

Probability that the mean length is greater than 6.3inches is 0.3446+0.5=0.8446.

Hence the probability that the mean length is greater than 6.3 inches is 0.8446.

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Answer:

31

Step-by-step explanation:

C= 2πr  We will used 3.14 for pi and the radius is 5

C = 2(3.14)(5)

C =31.4 Then round to the nearest whole number which would be 31.  31.4 is closer to 31 than 32

20 years is the answer.

A= R(1+r)^ t

A-415    

R=230

r=3%

415=230 (1+3%)^ t

t=log1.03  315/230

t=19.89 (use calculator)

David will invest at least 20 years.

An investment is a dedication of an asset to achieve an increase in value over a period of time. Investing requires the sacrifice of current assets such as time, money and effort. In finance, the purpose of an investment is to generate a profit on the invested asset

The most common example of an investment type. Investment is generally what you want to use in the future with the aim of generating regular cash flow or increasing the value of something over time so that you can sell it at a higher price than you purchased.

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https://brainly.com/question/68367When two lines intersect at a point, angles are formed. Some of these angles formed are vertically opposite and thus are equal.

Therefore, the required proof and answer to the question are stated below:

a) m< TRV = 60° (given)

   m<TRS = 4x° (given)

Thus, it can be concluded from the diagram that:

<TRV ≅ m<BRW  (vertically opposite angle property)

Also,

m<TRS ≅ m<VRW (vertically opposite angle property)

But,

m<VRW = m<VRZ + m<ZRW

Thus,

m<TRV ≅ m<BRW = 60°

m<TRV + m<BRW + m<TRS + m<VRW = [tex]360^{o}[/tex]

60° + 60° + m<TRS + m<VRW = [tex]360^{o}[/tex]

m<TRS + m<VRW =   [tex]360^{o}[/tex] - [tex]120^{o}[/tex]

                             = [tex]240^{o}[/tex]

2m<TRS = [tex]240^{o}[/tex] (since m<TRB = m<VRW )

m<TRS = 120

4x = 120

x = [tex]\frac{120}{4}[/tex]

  = [tex]30^{o}[/tex]

Thus, x = [tex]30^{o}[/tex]

b) The missing reason in step 3 is the angle addition postulate.

jhgvbiluhliuhnhl

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The value of the angle will be C. 20°

From the information given, it was stated that the protractor showed an angle going through the tenth tick mark after ten degrees.

This means the value of the angle will be:

= 10° + 10°

= 20°

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Range of values of the variable p is  [tex]0\leq p\leq \frac{10}{3}[/tex]

Step-by-step explanation:

From general quadratic equation [tex]ax^{2} +bx+c[/tex], for imaginary case-

[tex]D\leq 0\\b^2-4ac\leq 0[/tex]

In given question, [tex]a= p+2[/tex], [tex]b=2p[/tex], [tex]c= 5-p[/tex]

using above condition-

[tex]b^2-4ac = 4p^2-4(2p)(5-p)\leq 0\\4p^2 - 40p+8p^2\leq 0\\12p^2-40p\leq 0\\4p(3p-10)\leq 0[/tex]

Here, [tex]4p\leq 0, p\leq 0[/tex]

and

[tex]3p-10\leq 0\\p\leq \frac{10}{3}[/tex]

Therefore, range of values of the variable p is  [tex]0\leq p\leq \frac{10}{3}[/tex].

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The total amount of manufacturing overhead cost is closest to $ 29,500.

In business, overhead or overhead rate refers to an ongoing fee for working in a commercial enterprise. Overheads are the expenditure that can not be quite simply traced to or recognized with any unique revenue unit, not like running fees which include uncooked cloth and exertions.

Overhead fees, frequently referred to as overhead or working prices, confer with those expenses associated with running a commercial enterprise that cannot be connected to creating or producing a product or service. they're the prices the business incurs to live in the enterprise, irrespective of its success degree.

Examples of overhead encompass hire, administrative expenses, or worker salaries. Overhead fees may be observed on a business enterprise's income assertion, wherein they are subtracted from its profits to reach at the internet profits discern.

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Answer:

b, 20 hours

Step-by-step explanation:

First, find out how many times 66 (what Vinny made) goes into 165. (what Vinny wants to make) the answer is 2.5. Then, multiply 8 by 2.5 as well. You get 20. The answer is b, 20.

I hope this helps!

Answer:

14.35 ft

Step-by-step explanation:

We can use the pythagorean theorem to find the distance between the poles since both triangles are right triangles.

a^2 + b^2 = c^2

a^2 + 12^2 = 14^2

a^2 + 144 = 196

a^2 = 52

a = 7.21 ft

a^2 + b^2 = c^2

a^2 + 7^2 = 10^2

a^2 + 49 = 100

a^2 = 51

a = 7.14 ft

7.21 + 7.14 = 14.35 ft

Brainliest, please :)

Answer: c; 14.35

Step-by-step explanation: I need help on this and i saw this guy asked for brainlist and i think two people need to anser so please give him brainlist.

The resulted integral is [tex]I=\frac{8}{3} \times \frac{5 \pi}{16}=\frac{5 \pi}{6}[/tex].

In mathematics, an integral is either a number representing the region under a function's graph for a certain interval or just an added to the initial, the derivative of which is initial function (indefinite integral).

Computation of the integrals:

Step 1: We employ the equations in cylindrical coordinates.

[tex]x=r \cos \theta, y=r \sin \theta, z=z[/tex]

Thus, in cylindrical coordinate system,

E lies above the paraboloid [tex]z=r^{2}[/tex] and below the plane [tex]z=2 r \sin \theta[/tex] .

Therefore, the top part E is  [tex]z=2 r \sin \theta[/tex] is the cross-section between paraboloid and the plane.

Now, at the cross-section use, [tex]r^{2}=2 r \sin \theta[/tex] and  [tex]z=2 r \sin \theta[/tex] .

Thus, the limits are given as ;

[tex]r^{2} \leq z \leq 2 r \sin \theta \quad 0 \leq r \leq 2 \sin \theta[/tex]

Apply the limits as compute the integration;

[tex]\begin{aligned}I=\iiint_{E} z d V &=\int_{0}^{\pi} \int_{0}^{2 \sin \theta} \int_{\tau^{2}}^{2 r \sin \theta} z r d r d z d \theta \\&=\int_{0}^{\pi} \int_{0}^{2 \sin \theta}\left[\frac{z^{2}}{2}\right]_{r^{2}}^{2 r \sin \theta} r d r d \theta \\&=\frac{1}{2} \int_{0}^{\pi} \int_{0}^{2 \sin \theta}\left[4 r^{2} \sin ^{2} \theta-r^{4}\right] r d r d \theta\end{aligned}[/tex]

                       [tex]\begin{aligned}&=\frac{1}{2} \int_{0}^{\pi} \int_{0}^{2 \sin \theta}\left[4 r^{3} \sin ^{2} \theta-r^{5}\right] d r d \theta \\&=\frac{1}{2} \int_{0}^{\pi}\left[r^{4} \sin ^{2} \theta-\frac{r^{6}}{6}\right]_{0}^{2 \sin \theta} d \theta \\&=\frac{8}{3} \int_{0}^{\pi} \sin ^{6} \theta d \theta\end{aligned}[/tex]

Step 2: Now, calculate for the [tex]I_{1}=\int_{0}^{\pi} \sin ^{6} \theta d \theta[/tex].

 [tex]\begin{aligned}\sin ^{6} \theta &=\left(\sin ^{2} \theta\right)^{2} \times \sin ^{2} \theta \\&=\left[\frac{1-\cos 2 \theta}{2}\right]^{2} \times\left[\frac{1-\cos 2 \theta}{2}\right] \\&=\frac{1}{8}\left(1-2 \cos 2 \theta+\cos ^{2} 2 \theta\right)(1-2 \cos 2 \theta) \\&=\frac{1}{8}\left(1-2 \cos 2 \theta+\frac{1+\cos 4 \theta}{2}\right)(1-2 \cos 2 \theta)\end{aligned}[/tex]

         [tex]\begin{aligned}&=\frac{1}{16}(3-4 \cos 2 \theta+\cos 4 \theta)(1-2 \cos 2 \theta) \\&=\frac{1}{32}(10-15 \cos 2 \theta+6 \cos 4 \theta-\cos 6 \theta)\end{aligned}[/tex]

Further compute the value of

   [tex]\begin{aligned}I_{1} &=\int_{0}^{\pi} \sin ^{6} \theta d \theta \\&=\frac{1}{32} \int_{0}^{\pi}(10-15 \cos 2 \theta+6 \cos 4 \theta-\cos 6 \theta) d \theta \\&=\frac{1}{32}\left[10 \theta-\frac{15 \sin 2 \theta}{2}+\frac{3 \sin 4 \theta}{2}-\frac{\sin 6 \theta}{6}\right]_{0}^{\pi} \\&=\frac{5 \pi}{16}\end{aligned}[/tex]

Therefore, the obtained integral is  [tex]I=\frac{8}{3} \times \frac{5 \pi}{16}=\frac{5 \pi}{6}[/tex].

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The complete question is -

Use cylindrical or spherical coordinates, whichever seems more appropriate. Evaluate ∫∫∫E z dV, where E lies above the paraboloid

z = x² + y²

and below the plane z = 2y. Use either the Table of Integrals or a computer algebra system to evaluate the integral.

The points on the graph of (-4, 0), (-2.5, -12), and (0, -3), gives;

From the description of the graph, we have;

Furthest point left of the graph = (-4, 0)

The furthest point right on the graph = (0, -3) = The maximum point

The minimum point = (-2.5, -12)

F(x) < 0 at the minimum point

The minimum point is to the right of x = -4

The point the graph crosses the y-axis = (0, -3)

Therefore;

The interval of the graph where F(x) is larger than 0 is to the left of (-4, 0), is the interval (-∞, -4)

The true statement is therefore;

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None of the expressions is an identity

The expressions are given as:

I. y=x

II. 4 = 3x^2 + 2

III. x=x

In algebra, there are three identities; and they are

None of the given expression take the above forms

Hence, none of the expressions is an identity

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