Answer:
A longitudinal wave is a wave where the displacement of the medium is in the same direction than the propagation of the wave.
This means that as a P wave travels through the Earth, the relative motion between the p wave and the particles is near zero, as the motion of the particles is parallel to the motion of the wave.
An example of this would be the waves generated when you throw a rock in water, you can see how the water particles move along the waves in the water.
The relative motion between the p wave and the particles is almost negligible.
In case of a longitudinal wave, the displacement of the medium is in the same direction as the direction of the propagation of the wave. This property suggests that as a P wave travels through the Earth, the particles also move along in the same direction. The relative motion between the p wave and the particles is almost negligible. In case of transverse waves, the displacement of particles of the medium and the direction of the propagation of the wave is perpendicular to each otherLearn more:
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you throw a ball toward a wall at a speed 25.0 m/s and at an angle 40° above the horizontal. the wall is distance d = 22.0 m from
4.80m/s
(d) Since v y >0 when the ball hits the wall, it has not reached the highest point yet.
Mark walked 2 miles east than 1 mile north how would you determine his total displacement
They could determine it by counting their total amount of miles mark went by the directions he went to walk those miles.
A slanted surface used to raise an object is a(n)
Answer:
Inclined Plane
Explanation:
What is the magnitude of the velocity after it hits the
ground?
9.3 m/s
12 m/s
41 m/s
73 m/s
Answer: 9.3m/s
Explanation:
Your question isn't complete but let me help out:
A 0.060 kg ball hits the ground with a speed of –32 m/s. The ball is in contact with the ground for 45 milliseconds and the ground exerts a +55 N force on the ball. What is the magnitude of the velocity after it hits the ground?
We would use Newton's law of motion to solve this which goes thus:
F = ma
f = m(v-u)/t
Cross multiply
ft = m(v-u)
where,
f = 55
t = 45/1000 = 0.045
m = 0.0060
u = -32
v = Unknown
Therefore,
55 × 45/1000 = 0.060(v - -32)
55 × 0.045 = 0.060(v + 32)
2.475 = 0.06(v + 32)
2.475 = 0.06v + 1.92
0.06v = 2.475 - 1.92
0.06v = 0.555
v = 0.555/0.06
v = 9.25m/s
v = 9.3m/s Approximately
Answer:
A.9.3 m/s
Explanation:
A source emits sound with a frequency of 18,002 Hz. Both it and an observer are moving toward each other, each with a speed of 130 m/s. What frequency (in Hz) does the observer hear
Answer:
The frequency heard by the observer is 24,830.35 Hz.
Explanation:
Given;
frequency of the source, Fs = 18,002 Hz
speed of the source, Vs = 130
speed of sound in air, V = 343 m/s
Apply Doppler effect, as the source and the observer move closer to each other, the frequency heard by the observer increases because of decrease in distance.
[tex]f_s = f_o[\frac{v}{v + v_s} ]\\\\[/tex]
where;
f₀ is the frequency heard by the observer
[tex]f_s = f_o[\frac{v}{v + v_s} ]\\\\18,002 = f_o[\frac{343}{343 + 130} ]\\\\18,002 = f_o(0.725)\\\\f_o = \frac{18,002}{0.725} \\\\f_o = 24,830.35 \ Hz[/tex]
Therefore, the frequency heard by the observer is 24,830.35 Hz.
A spring with a spring constant of 1730 N/m is compressed 0.136 m from its equilibrium position with an object having a mass of 1.72 kg. The spring is released and the object moves along a frictionless surface when it reaches a small embankment. If the speed of the object is 2.45 m/s at location A, what is the embankment height h
Given :
A spring with a spring constant of 1730 N/m is compressed 0.136 m from its equilibrium position with an object having a mass of 1.72 kg.
To Find :
The embankment in the height.
Solution :
Since no external force is acting in the system, therefore total energy will be conserved.
Initial kinetic energy of the object = Energy stored in spring
[tex]K.E _i = \dfrac{kx^2}{2}\\\\K.E_i = \dfrac{1730\times 0.136^2}{2}\\\\K.E_i = 16\ J[/tex]
Also, initial potential energy is 0.
Now,
[tex]K.E_i + P.E_i = K.E_f + P.E_f\\\\16 + 0 = \dfrac{1.72\times 2.45^2}{2}+ mgh\\\\mgh =16 - 5.16\\\\h = \dfrac{16 - 5.16}{1.72 \times 9.8}\\\\h = 0.64\ m[/tex]
Therefore, the embankment height is 0.64 m.
How does radiation transfer thermal energy from the Sun to Earth?
Answer:
The thermal energy is carried by electromagnetic waves
Explanation:
There are three types of transfer of heat (thermal energy):
- Conduction: conduction occurs when two objects/two substances are in contact with each other. The heat is transferred from the hotter object to the colder object by the collisions between the molecules of the two mediums.
- Convection: convection occurs when a fluid is heated by an external source of heat. The part of the fluid closer to the heat source gets warmer, therefore it becomes less dense and it rises, and it is replaced by the colder part of the fluid, which is colder. Then, this part of fluid is heated as well, so it gets warmer, it rises, etc.. in a cycle.
- Radiation: radiation occurs when thermal energy is carried by electromagnetic waves. Since electromagnetic waves do not need a medium to propagate, this is the only method of heat transfer that can occur through a vacuum (so, in space as well).
Indeed, the Sun emits a lot of electromagnetic radiation, which travels through space and eventually reaches the Earth, heating it.
Explanation:
oo hi granger ru online here i have a doubt in physics .
Answer:
.
Explanation:
Oxygen-15 undergoes beta decay. Which particle correctly completes the
equation to show that the numbers of nucleons on the two sides of the
equation are equal?
150 - 15N+ ?
Answer: [tex]_8^{15}\textrm{O}\rightarrow _{7}^{15}\textrm{N}+_{+1}^0{e}[/tex]
Explanation:
Positron emission: In this process, in which a proton inside a radionuclide nucleus is converted into a neutron while releasing a positron and an electron neutrino. The beta positive particle released is basically a positron with +1 charge and no mass.
General representation of an element is given as:
[tex]_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{+1}^0{e}[/tex]
where,
Z represents Atomic number
A represents Mass number
X and Y represents the symbol of an element
For [tex]_8^{15}\textrm{O}\rightarrow _{7}^{15}\textrm{N}+_{+1}^0{e}[/tex]
A person pushes a box filled with books with a force of 120 newtons a distance of 30 meters within 3 minutes Calculate the work the person did and the amount of power required
120/30-4
I will give brainliest
the tighter the threads of the screw the greater
You did 550 J of work lifting a 220 N backpack. How high did you lift the backpack?
Answer:
0.255 meters
Explanation:
cause formula to calculate work done against gravity is mgh where m refers mass g refers acceleration due to gravity and h refers height
A person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?
Answer:
3.88 × 10^-4 m
Explanation:
Given that a person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?
The total weight = 614 + 85
The total weight = 699N
Let the total area of contact = A
Pressure = Force / A
Substitute all the parameters into the formula
900000 = 699 /A
A = 699 / 900000
A = 7.77 × 10^-4 m
The area of contact between each tire and the ground will be = A/2
That is, 7.77 / 2 = 3.88 × 10^-4 m
Therefore, the area of contact between each tire and the ground is 3.88 × 10^-4 m approximately.
The temperature of the surface of the Sun is 5500°C.
a. What is the average kinetic energy, in joules, of hydrogen atoms on the surface of the Sun?
b. What is the average kinetic energy, in joules, of helium atoms in a region of the solar corona where the temperature is 6.00 times 10^5 K?
Answer:
a. the average kinetic energy of hydrogen atoms is 1.20 × 10^-19J
b. the average kinetic energy of helium atoms is 1.24 × 10^-17J
Explanation:
The computation is shown below;
As we know that
Kinetic energy = 3 ÷ 2 kT
where,
K = Boltzmann constant
And, T = Temperature
a. Now the temperature in kelvin is
T = (5,500 × (°C ÷ K) + 273.15 K)
= 5773.15 K
As
Kinetic energy = 3 ÷ 2 kT
So now 1.38 × 10^-23 J/K for K would be substituted and 5773.15 K for Temperature T
Now Kinetic energy is
= 3 ÷ 2 (1.38 × 10^-23 J/K) ( 5773.15 K)
= 1.20 × 10^-19J
hence, the average kinetic energy of hydrogen atoms is 1.20 × 10^-19J
b. As
Kinetic energy = 3 ÷ 2 kT
now 1.38 × 10^-23 J/K for K would be substituted and 6 × 10^5K for Temperature T
Now Kinetic energy is
= 3 ÷ 2 (1.38 × 10^-23 J/K) (6 × 10^5K )
= 1.24 × 10^-17J
hence, the average kinetic energy of helium atoms is 1.24 × 10^-17J
The river narrows at a rapids from a width of 12 m to a width of only 5.8 m. The depth of the river before the rapids is 2.7 m; the depth in the rapids is 0.85m.Find the speed of water flowing in the rapids, given that its speed before the rapids is 1.2 m/s. Assume the river has a rectangular cross section.
Answer:
7.89 m/s
Explanation:
Given that
Width of the river, b1 = 12 m
Width of the river, b2 = 5.8 m
Depth of the river, d1 = 2.7 m
Depth of the river, d2 = 0.85 m
Speed of the river, v1 = 1.2 m/s
Speed of the river, v2 = ?
Area of the river before the rapid, a1 = 12 * 2.7 = 32.4 m²
Area of the river after the rapid, a2 = 5.8 * 0.85 = 4.93 m²
To solve this question, we use a relation between the speed of the river and the volume of the river. We say,
Area1 * velocity1 = Area2 * velocity2, and when we substitute the values for each other we have
32.4 * 1.2 = 4.93 * v2
38.88 = 4.93v2
v2 = 38.88 / 4.93
v2 = 7.89 m/s
Therefore, the speed of the river after the rapid is 7.89 m/s
A fluid exerts 50 N of force over an area that measures 5 m2. What is the pressure by exerted the fluid?
20 Pa
10 Pa
15 Pa
30 Pa
[tex]\sf{\underline{\underline{\qquad \clubsuit \: Given :\clubsuit\qquad}}} \\ [/tex]
Force = 50 NArea = 5 m²[tex]\sf{\underline{\underline{\qquad \clubsuit \: To \:Find :\clubsuit\qquad}}} \\ [/tex]
The pressure exerted by the fluid = ?[tex]\sf{\underline{\underline{\qquad \clubsuit \: Solution :\clubsuit\qquad}}} \\ [/tex]
[tex]:\implies\sf Pressure = \dfrac{Force}{Area} \\ \\ \\ [/tex]
[tex]:\implies\sf Pressure = \dfrac{50}{5} \\ \\ \\ [/tex]
[tex]:\implies \underline{ \boxed{\sf Pressure = 10 \:pascal }}\\ \\ \\ [/tex]
[tex]\therefore{\underline{\textsf{The pressure exerted by the fluid is \textbf{10 pascal}}}}. \\ [/tex]
In which example would the most transfer of energy take place from Mechanical energy to Thermal (heat) energy?
Question 2 options:
When a feather falls from the sky
When a metal plate is pressing against a fast spinning piece of steel hard enough to stop it
When a skydiver opens her parachute
When a child slides down a waterslide on an innertube
Answer:The answer is when a metal plate is pressed against a fast spinning piece of steel hard enough to stop it. i know this because I just took a test and got this question and got it write
Explanation:
Please help
4. What are the lowest points on a transverse wave called?
a. Crests
b. troughs
C. compressions
d. rarefractions
5. Any substance that a wave moves through is called a
a. medium
b. vibrate
C. crest
d. frequency
Answer:
Explanation:
the lowest points of a transverse wave are called the troughs what is the wavelength of a wave traveling through a rope if the distance from one crest to the next is 1 meter a. 2 m
4. Low points are called troughs
5. Medium: substance through which a wave can travel
Which of these is considered a contact force?
a the force between two magnets.
b the gravitational pull of a planet.
c the friction between an object and air.
d The force between two charged particles.
Answer:
C -) The friction between an object and air.
Explanation:
The frictional force is the force that exists between two surfaces in contact, which is opposed to the movement.
That is, this type of force exists as long as there is physical contact between surfaces.
While the other types of force always act at a separation distance between bodies.
Chemical reactions and nuclear reactions cause matter to change in different
ways. Which two statements describe how matter changes only in a chemical
reaction?
A. The nuclei of the atoms change.
B. Atoms and their electrons are rearranged.
O C. New atoms and elements are formed.
D. The elements stay the same.
Answer:
B. Atoms and their electrons are rearranged.
D. The elements stay the same.
You and your buddy are scuba diving and notice that air bubbles triple in volume as they rise to the surface from where you are in the ocean. Ignoring any temperature changes, how far below the surface of the water (in m) are you when these bubbles are released
Answer:
You and your buddy are scuba diving and notice that air bubbles triple in volume as they rise to the surface from where you are in the ocean. Ignoring any temperature changes, how far below the surface of the water (in m) are you when these bubbles are released? The ocean has a density of 1034 kg/m3
Ist Law: a object continues in a state of
rest or motion unless an external force
applied to it
This image shows an example of
the first law because:
Answer:
Explanation:
This image is the example of Newton's first law of motion because:
As per Newton's first law, football will remain in the state of rest until a player applies an external force by kicking the ball.
And the ball will keep on moving until unless the net of a goal post exerts the external force to stop the ball.
For which object would a geologist use carbon-14 dating to determine age?
The bones of animals
Rocks older than 50,000 years old
Types of Sedimentary rocks
Parts of Volcanic rock
Answer:
B. older than 50,000 years old
hope it helps you
Rocks older than 50,000 years old are objects in which geologists use carbon-14 dating to determine its age.
What is Carbon dating?This is used to determine age by using the decay to nitrogen of radiocarbon (carbon-14).
Older rocks can have its age determined through the use of carbon-14 which is why option B was chosen.
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Two ice skater are at rest, andy and brenda. andy has a mass of 62.5 kg. they push off each other. after, andy moves 1.59 m/s east, while brenda moves 2.22 m/s west. what is brenda's mass?
Unit=kg
Answer: 44.76 kg
Explanation: There are two options for formulas to use here.
0=(m1)(V1f)+(m2)(V2f)
Or
(m1)(V1f) = —(m2)(V2f)
Both formulas should give you an answer of 44.763514, which can be rounded to the specifications of whatever your curriculum or teacher wants. Most likely 44.76.
Blessings to all of you in the Name of Jesus Christ our Savior!
Mass of egg is 65g and volume is 60cc.The mass of salt dissolved in 100cc of water so that egg just float in water is
Answer:
108.33 grams.
Explanation:
Given that,
Mass of a egg, m = 65 g
Volume of an egg, V = 60 cc
We need to find the mass of the salt dissolved in 100cc of water so that egg just float in water.
The density will remains constant,
[tex]\dfrac{m_1}{V_1}=\dfrac{m_2}{V_2}\\\\m_2=\dfrac{m_1V_2}{V_1}\\\\m_2=\dfrac{65\times 100}{60}\\\\=108.33\ g[/tex]
So, the required mass is 108.33 grams.
The weight of an astronaut plus his space suit on the Moon is only 319 N. How much (in N) do they weigh on Earth?
Answer:
The weight of an astronaut plus his space suit on the Earth is 1,931.69 N.
Explanation:
Newton's second law, called the fundamental law or fundamental principle of dynamics, states that a body accelerates if a force is applied to it. This law indicates that the net force applied on a body is proportional to the acceleration that the body acquires. The constant of proportionality is the mass of the body, so Newton's second law is expressed in the following formula:
F = m*a
Where:
F is the net force. It is expressed in Newton (N) m is the mass of the body. It is expressed in kilograms (Kg). a is the acceleration that the body acquires. It is expressed in meters over second squared (m/s²).The weight of an astronaut plus his space suit on the Moon is only 319 N. Then, being:
F= weight= 319 Nm= ?a = acceleration of the Moon's gravity, whose value is 1.62 m/s²you get:
319 N= m* 1.62 m/s²
Solving:
[tex]m=\frac{319 N}{1.62 \frac{m}{s^{2} } }[/tex]
m=196.91 kg
The mass is an invariable quantity, regardless of the planet in which the astronaut plus his space suit on the Moon is, then you have:
F= weight= ?m= 196.91 kga = acceleration of the Earth's gravity, whose value is 9.81 m/s²replacing in the definition of force:
Weight= 196.91 kg* 9.81 m/s²
Weight= 1,931.69 N
The weight of an astronaut plus his space suit on the Earth is 1,931.69 N.
calculate the number of molecules of hydrogen and carbon present in 4 g of methane?
Answer: 6.022×10²³ molecules of CH4 which consists of 1 mole of C atoms and 4 moles of H atoms.
18
AX
A bicycle rider travels 15 km in 1.25 hours. What is the rider's average speed? v=
At
rage speed [v-ante
10.5 km/h
13.75 km/h
12 km/h
22.5 km/h
The required average speed of bicycle rider is 12 km/h.
Given data:
The distance travelled by the bicycle rider is, d = 15 km.
Time taken to cover the distance is, t = 1.25 h.
Here, we need to use the simple relation between the speed, time and distance. The distance covered covered by any object per unit of time is known as average speed of object. And the mathematical expression for the average speed is given as,
[tex]v = \dfrac{d}{t}[/tex]
Here, v is the average speed.
Solving as,
[tex]v = \dfrac{15}{1.25}\\\\v = 12\;\rm km/h[/tex]
Thus, we can conclude that the required average speed of bicycle rider is 12 km/h.
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Two workers are sliding 500 kg crate across the floor. One worker pushes forward on the crate with a force of 440 N while the other pulls in the same direction with a force of 340 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor
Answer:
0.159
Explanation:
Given that
F1 = 440 N
F2 = 340 N
m = 500 kg
acceleration, a = 0 m/s²
Remember that F = m.a
If F - f(f) = 0, then F = f(f)
N = mg
f(f) = μN, substituting for N, we have
f(f) = μmg
The total force, F = F1 + F2
F = 440 + 340
F = 780 N
Recall that we'd already proven that
F = f(f), so F = 780 N = f(f)
And again, f(f) = μmg, if we substitute for all the values, we have
780 = μ * 500 * 9.81
780 = μ * 4905
μ = 780 / 4905
μ = 0.159
Therefore, the coefficient of static friction of the crate on the floor is 0.159
A rotating space station simulates artificial gravity by means of centripetal acceleration at the rim. The radius of the station is 1156 m and the apparent acceleration of gravity at the rim is 6.13 m/s2. What is the rotation rate of the station in rpm (revolutions per minute).
a= 1156× 6.13= 7086.28
Explanation:
a = m× m/ s^2