Answer:
70km/h
Explanation:
speed = distance /time
= 35/0.5
=70km/h
An illustration to show the respective wavelengths of electromagnetic waves. There is a transverse wave with really small wavelengths to really long and are listed from smallest to largest are gamma ray, x-rays, ultraviolet, visible, infrared, microwave and radio. Which has the longest wavelength? Which has the highest frequency?
The wave which has the longest frequency if, listed from smallest to largest are gamma ray, x-rays, ultraviolet, visible, infrared, microwave, and radio is radio waves and gamma rays have the highest frequency.
What is an electromagnetic wave?The oscillations between an electric field and a magnetic field produce waves known as electromagnetic waves or EM waves. In other words, magnetic and electric fields oscillate to form electromagnetic (EM) waves.
The term "electromagnetic spectrum" (EMS) refers to the entire range of electromagnetic radiation that is now understood. Wavelengths rise from roughly 10⁻¹⁸ m to 100 km, and frequencies fall from 3 × 10²⁶ Hz to 3 × 10³ Hz in this range.
The following list of the seven electromagnetic waves is organized by decreasing wavelength and increasing frequency and energy: X-rays, gamma rays, UV rays, visible light, radio waves, microwaves, and infrared waves.
Thus, radio waves have the longest frequency and gamma rays have the highest frequency.
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2. Look at the table of typical densities. You have a 1 cm volume of each of the materials.
a List them in order of smallest mass to biggest mass.
b Which is the odd one out? Why?
Answer:
um were is it
Explanation:
Answer:
i think its b
Explanation:
Need help with question 1) and 2) please ASAP ??? 15 points ?
A 20.0 g rubber bullet traveling with a velocity of 60.0 m/s hits a stationary
3.00 kg wood block resting on a frictionless surface. The rubber bullet
ricochets off the wood block with a velocity of 40.0 m/s in the opposite
direction.
A. Find the velocity of the wood block.
Answer:
0.667 m/s
Explanation:
Given that,
Mass of a rubber bullet, m₁ = 20 g = 0.02 kg
Initial speed of rubber bullet, u₁ = 60 m/s
Mass of the wood block, m₂ = 3 kg
Initial speed of the wooden block, u₂ = 0
A rubber bullet hits the stationary wood block. The rubber bullet ricochets off the wood block with a velocity of 40.0 m/s in the opposite direction.
Final speed of rubber bullet, v₁ = -40 m/s
Using the conservation of momentum. It will remains conserved. Let v₂ is the velocity of the wood block.
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\0.02 \times 60+3\times 0=0.02 \times (-40)+3\times v_2\\\\1.2=-0.8+3v_2\\\\2=3v_2\\\\v_2=0.667\ m/s[/tex]
So, the velocity of the wood block is 0.667 m/s.
Create a flexibility workout using the 'Principle of Progression' over a four week period.
Answer:
You can go to youtub and search 4 week flexibility programs and use that and add the principle of progression.
Answer:
r
Explanation:
the compound sodium sulfide consists of a ratio of two sodium ions (Na^+) to one sulfide ion (s^2-). Wrote a chemical formula for this compound.
Answer:Na2S
Explanation:
Doing assignment
A bowling ball with a mass of 7.0kg strikes a pin that had a mass of 2.0kg the pin flies forward with a velocity of 6.0m/s, and the ball continues forward at 4.0 m/s. What was the original velocity of the ball?
The conservation of momentum P states that the amount of momentum remains constant when there are not external forces.
We don't have external forces, so:
[tex]P_0 = P_1\\m_bv_{0b}+m_pv_{0p}=m_bv_{1b}+m_pv_{1p}\\[/tex]
Where:
mb is the mass of the bowling ball mp the mass of the pin[tex]v_{0b}\quad and\quad v_{0p}[/tex] the initial velocities of the bowling ball and the pin.[tex]v_{1b}\quad and\quad v_{1p}[/tex] the final velocities of the bowling ball and the pin.Solving for v0b:
[tex]v_{0b} =\dfrac{m_bv_{1b}+m_pv_{1p}- m_pv_{0p}}{m_{b}}\\\\v_{0b} =\dfrac{(7\;kg)(4\;m/s)+(2\;kg)(6\;m/s)- (2\;kg)(0 \;m/s)}{7\;kg}\\v_{0b}=\dfrac{40}{7}\;m/s\\\\\boxed{v_{0b}\approx5.71\;m/s}[/tex]
R/ The original velocity of the ball was 5.71 m/s.The original velocity of the ball is 5.71 m/s.
The principle of conservation of momentum: In a closed system, The total momentum before collision is equal to total momentum after collision.
From the principle of conservation of momentum,
MU+mu = MV+mv.................... Equation 1
Where M = mass of the bowling ball, m = mass of the pin, U = initial velocity of the bowling ball, u = initial velocity of the pin, V = final velocity of the bowling ball, v = final velocity of the pin.
From the question,
Given: M = 7 kg, m = 2 kg, u = 0 m/s (at rest), v = 6.0 m/s, V = 4 m/s.
Substitute these values into equation 1 and solve for U
7(U)+2(0) = 7(4)+2(6)
7U = 28+12
7U = 40
U = 40/7
U = 5.71 m/s.
Hence, The original velocity of the ball is 5.71 m/s.
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Differences in water temperature in the ocean create movement because
Is block b speeding up or slowing down once it is set into downward motion and the cat is on block a?
Answer:
The answer is "Slowing down ".
Explanation:
please find the complete question in the attached file.
In this question, if the block B weight were accounted for by kinetic the friction of frame A, because the blocks pushed at a consistent speed throughout the beginning.
Afterward, on block A, the resistance intensity rises, which allows frames to also be negative, which is defined in the graph, that's why the answer Slowing down is correct.
Why is gravity so weird? .
Answer:
Why is gravity so weird? No force is more familiar than gravity — it's what keeps our feet on the ground, after all. And Einstein's theory of general relativity gives a mathematical formulation for gravity, describing it as a “warping” of space.
Answer:
Because it pulls us down to the centre the earth
Sugar is a compound. Its formula is represented below. Use the periodic table to determine which elements are in sugar. Write the elements down.
What is a force ?????
Answer:
A force is a push or pull upon an object resulting from the objects interaction with another object
A 1800 kg car moves along a horizontal road at speed v₀ = 18.4 m/s. The road is wet, so the static friction coefficient between the tires and the road is only µ static = 0.188 and the kinetic friction coefficient is even lower, µ kinetic = 0.1316. The acceleration of gravity is 9.8 m/s². What is the shortest possible stopping distance for the car under such conditions? (neglect the reaction time of the driver and round your answer to 4 decimal places)
Answer:
The shortest possible distance is [tex]|s| = 91.9 \ m[/tex]
Explanation:
From the question we are told that
The mass of the car is [tex]m = 1800 \ kg[/tex]
The speed along the horizontal road is [tex]v_o =u = 18.4 \ m/s[/tex]
The static friction coefficient is [tex]\mu_s = 0.188[/tex]
The kinetic friction coefficient is [tex]\mu_k = 0.1316[/tex]
Generally the static frictional force acting on the car is mathematically represented as
[tex]F_f = m * g * \mu_s[/tex]
Generally the force propelling the car is mathematically represented as
[tex]F = m * a[/tex]
Here a is the maximum acceleration
at the point which the car stops ,
[tex]F = F_f[/tex]
=> [tex]m * g * \mu_s = ma[/tex]
=> [tex]g * \mu_s =a[/tex]
=> [tex]a = 9.8 * 0.188[/tex]
=> [tex]a = 1.8424 \ m/s^2[/tex]
Generally from kinematic equation
[tex]v^2 = u^2 + 2as[/tex]
Here v is the final velocity of the car and the value is zero given that the car comes to rest
So
[tex]0^2 = 18.4^2 + 2* 1.8424 s[/tex]
=> [tex]s = - \frac{18.4^2}{2 * 1.8424}[/tex]
=> [tex]|s| = 91.9 \ m[/tex]
Compared to the range of a bullet shot horizontally just above horizontal ground, a bullet shot from the same position at an angle of 30 degrees with the same initial velocity as the first bullet, would travel a horizontal distance that is-
a) the same
b) farther
c) not as far
d) the same, but will remain in the air longer
Answer:
b) farther
Explanation:
The range of the bullet shot horizontally just above the horizontal ground is given as;
[tex]R_1 = \frac{u^2sin(2\theta)}{g}[/tex]
where;
θ is the angle of projection with the horizontal ground = 0
R₁ = 0
The range of the bullet shot at an angle of 30 degrees with the same initial velocity as the first bullet is given as;
[tex]R_2 = \frac{u^2sin(2 \theta)}{g} \\\\R_2 = \frac{u^2sin(2*30)}{9.8}\\\\R_2 = 0.088u^2[/tex]
Therefore, the second bullet will travel a horizontal distance that is farther
Help!!!!!!!!!!!!
Skill-related fitness goals include __________. A. cardiovascular fitness B. reaction time C. muscular endurance D. flexibility
Answer:
B. Reaction time
Explanation:
Don't have an explanation. Sorry!
An artery with a 3 cm radius carries blood away from the heart. In a constricted region that is partially blocked with plaque, the radius shrinks to 2 cm and the blood's velocity is 5 m/s. What is the bloods velocity in the 3 cm radius unconstricted region?
Answer:
2.32m/sExplanation:
What is flow rate?
Flow rate is the volume of fluid per unit time flowing past a point through the area
the formula is Q=Av
where A= area
v= flow velocity
step one:
given data
radius r1= 3cm= 0.03m
radius r2=2cm= 0.02m
velocity v1=?
velocity v2=5m/s
The area A1
[tex]Area= \pi r^2\\\\Area- A1= 3.142*0.03^2\\\\A1= 0.0028m^2[/tex]
The area A2
[tex]Area= \pi r^2\\\\Area- A2= 3.142*0.02^2\\\\A1= 0.0013m^2[/tex]
Step two:
For the continuous flow
Q1=Q2
A1v1=A2v2
0.0028*v1=0.0013*5
v1=0.0065/0.0028
v1=2.32m/s
The bloods velocity in the 3 cm radius unconstricted region is 2.32m/s
Hiking with 10-15 lb backpack can increase your calorie burn by how much
Explanation:
Just one 60 minute walk through tiny hills, with a 10 pound backpack, can consume over 600 calories because you weigh about 100 lbs. Lead to increasing the slope of such hills, and it would be equal to 800 calories for calorie burning.
Which term best explains why you hear an echo?
Answer:
reflection
Explanation:
Answer:
reflection
Explanation:
A p e x
Which arrow is the action and which arrow is the reaction?
whos still awake???
Answer:
definitely not me
Explanation:
why would I?
A car travels for 10 seconds at 5 m/s. How much distance does it travel?
Question 19 of 20
8 44%
Look at the diagram. To overcome the friction force, the man could use a slippery
substance like oil or graphite spray on the floor. These substances are examples of
what?
Enter your answer
Substances like oil or graphite spray are examples of - lubricants.
Lubrication is the control of friction and a friction-reducing film between moving surfaces such as the given diagram. The lubricant used can be a fluid, solid, or plastic substance.
Oil reduces the amount of friction by introducing a layer of a smooth and slippery substance that makes the surface smooth and slippery as well.Graphite Spray is a Lubricant that contains high purity graphite along with an organic binder that will adhere the coating to most surfaces.This leaves a dry, clean film of highly lubricous graphite.It lubricates and reduces friction in parts so they slide or rotate easily.Thus, oil or graphite spray are examples of - lubricants.
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Cold air is more dense than hot air. When I filled a 9 centimeter diameter balloon with cold air the mass was 1 gram and when I measured the mass of the same size balloon with hot air it was 0.5 grams. When molecules are cooled they move closer together and when they are heated up they move farther apart. Because of this more molecules can fit into a balloon when the air going in is cold than when the air going in is warm. (Please explain this to me)
Two objects with the same mass move with the same speed but in opposite directions. Compare their kinetic energies.
A.
Kinetic energies are equal.
B.
Kinetic energies are opposite in magnitude.
C.
Kinetic energy of the higher object is greater.
D.
Kinetic energy of the lower object is greater.
Answer:
A. Kinetic energies are equal.
Explanation:
The kinetic energy of the bodies will be equal since the mass and speed are the same.
Kinetic energy is the energy due to the motion of a body.
Mathematically;
K.E = [tex]\frac{1}{2}[/tex] m v²
m is the mass
v is the speed
The kinetic energy is a scalar quantity with no regard for direction.
Answer:kinetic energies are equal
Explanation:
A sound source produces 85 sound wave compressions in 5 seconds. the wave length of the sound is 20m. calculate the
a)frequency of the sound waves
b)the speed of the wave
Answer: it would be 14.1 mm
Explanation: Sound is a wave. More specifically, sound is defined to be a disturbance of matter that is transmitted from its source outward. A disturbance is anything that is moved from its state of equilibrium. Some sound waves can be characterized as periodic waves, which means that the atoms that make up the matter experience simple harmonic motion.
A vibrating string produces a sound wave as illustrated in Figure 14.2, Figure 14.3, and Figure 14.4. As the string oscillates back and forth, part of the string’s energy goes into compressing and expanding the surrounding air. This creates slightly higher and lower pressures. The higher pressure... regions are compressions, and the low pressure regions are rarefactions. The pressure disturbance moves through the air as longitudinal waves with the same frequency as the string. Some of the energy is lost in the form of thermal energy transferred to the air. You may recall from the chapter on waves that areas of compression and rarefaction in longitudinal waves (such as sound) are analogous to crests and troughs in transverse waves.
The frequency of sound waves is 144.1 m.
What is Sound waves?More specifically, sound is defined to be a disturbance of matter that is transmitted from its source outward. A disturbance is anything that is moved from its state of equilibrium.
Some sound waves can be characterized as periodic waves, which means that the atoms that make up the matter experience simple harmonic motion.
This creates slightly higher and lower pressures. The higher pressure... regions are compressions, and the low pressure regions are rarefactions. The pressure disturbance moves through the air as longitudinal waves with the same frequency as the string.
Therefore, The frequency of sound waves is 144.1 m.
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For Valentine’s Day Sally received a helium-filled balloon at a party. On returning home she accidently left the balloon in the car. Later she went to get the balloon and found it was partially deflated. After being in the house for an hour she noticed it was fully inflated again. Explain why this happened.
Answer:
The helium molecules move closer together when it's cold causing the balloon to deflate
Explanation:
The possible reason behind it is: the temperature of outside was low, so the Helium gas inside the balloon compressed and it was partially deflated at the car. When she returned to the house, temperature of the gas of the balloon rises again and it was fully inflated again.
What is Charles' law of gas?The experimental gas law known as Charles' law, commonly referred to as the law of volumes, illustrates how gases tend to expand when heated. Charles's law can now be expressed as follows:
The Kelvin temperature and the volume will be directly proportional when the pressure on a sample of a dry gas is kept constant.
This direct proportional relationship can be expressed as follows:
V∝T.
Hence, as the temperature is low outside the house, the balloon was partially deflated at the car and the temperature rises again when it was inside the house, so it was fully inflated again inside the house.
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Ted Williams drops a ball from 12.7 meter to a desk that is 1.5 meter tall. What is the final speed of the ball right before it hits the desk?
Answer:
Explanation:
Using the equation of motion
V² = u²+2g∆H
v is the final velocity
u is the initial velocity = 0m/s
g = 9.8m/s²
∆H = 12.7-1.5 = 11.2m
Substitute
v² =0²+2(9.8)(11.2)
v² = 219.52
v = √219.52
v = 14.82m/s
Hence the final.speed of the ball is 14.82m/s
How does the size of a bicycle tire affect the distance it will travel when it is pedaled in a certain number of times?
Answer:
No, the size of a bicycle tire will not affect the distance traveled when pedaling, unless you are talking about the limits of the range. ...Proportional, which means that changes in wheel diameter or gear ratio X will cause the bicycle to travel X times.
You throw a ball straight up. You are extra strong feeling today. It takes 11 seconds for the ball to come back down.
a. How high did you throw it?
b. What was the initial speed you threw it at?
Answer:
A. 148.23 m
B. 2.75 m/s
Explanation:
The following data were obtained from the question:
Time of flight (T) = 11 s
Maximum height (h) =?
Initial velocity (u) =?
Next, we shall determine the time taken for the ball to get to the maximum height. This can be obtained as follow:
Time of flight (T) = 11 s
Time (t) to reach the maximum height =.?
T = 2t
11 = 2t
Divide both side by 2
t = 11/2
t = 5.5 s
NOTE: Time to reach the maximum height is the same as the time taken for the ball to fall back to the plane of projection.
A. Determination of the maximum height to which the ball was thrown.
Time (t) to reach maximum height = 5.5 s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =?
h = ½gt²
h = ½ × 9.8 × 5.5²
h = 4.9 × 30.25
h = 148.23 m
B. Determination of the initial velocity.
Maximum height (h) reached = 148.23 m
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) =?
u² = h/2g
u² = 148.23 / (2 × 9.8)
u² = 148.23 / 19.6
Take the square root of both side
u = √(148.23 / 19.6)
u = 2.75 m/s
16.) A person walks 4 meters east, then walks 3 meters north. Determine distance and
displacement.
Answer:
Long question good luck:)
Explanation:
Answer:7
Explanation:
because its the right answer