In July 2014 one Mexican peso was worth 0.075 U.S. dollars. How many Mexican pesos was $133.00 U.S. dollars worth?

Answer:

So im pretty sure it is just adding each side

Step-by-step explanation:

Add 10 + 5 + 3 + 5 + 7

This question is incomplete, the complete question is;

A given population proportion is .25. What is the probability of getting each of the following sample proportions

a) n = 110 and = p^ ≤ 0.21, prob = ?

b) n = 33 and p^ > 0.24, prob = ?

Round all z values to 2 decimal places. Round all intermediate calculation and answers to 4 decimal places.)

Answer:

a) the probability of getting the sample proportion is 0.1660

b) the probability of getting the sample proportion is 0.5517

Step-by-step explanation:

Given the data in the questions

a)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 110

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 110 ) √( 0.1875 / 110 ) = 0.0413

Now, P( p^ ≤ 0.21 )

= P[ (( p^ - μ ) /S.D) < (( 0.21 - μ ) / S.D)

= P[ Z < ( 0.21 - 0.25 ) / 0.0413)

= P[ Z < -0.04 / 0.0413]

= P[ Z < -0.97 ]

from z-score table

P( X ≤ 0.21 ) = 0.1660

Therefore, the probability of getting the sample proportion is 0.1660

b)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 33

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 33 ) = √( 0.1875 / 33 ) = 0.0754

Now, P( p^ > 0.24 )  

= P[ (( p^ - μ ) /S.D) > (( 0.24 - μ ) / S.D)

= P[ Z > ( 0.24 - 0.25 ) / 0.0754 )

= P[ Z > -0.01 / 0.0754  ]

= P[ Z > -0.13 ]

= 1 - P[ Z < -0.13 ]

from z-score table

{P[ Z < -0.13 ] = 0.4483}

1 - 0.4483

P( p^ > 0.24 )  = 0.5517

Therefore, the probability of getting the sample proportion is 0.5517

Answer:

[tex]Q(a+h)-Q(a-h)=8ah+10h[/tex]

Step-by-step explanation:

We are given the function:

[tex]Q(x)=2x^2+5x-3[/tex]

And we want to find and simplify:

[tex]Q(a+h)-Q(a-h)[/tex]

Substitute:

[tex]=[2(a+h)^2+5(a+h)-3]-[2(a-h)^2+5(a-h)-3][/tex]

Expand:

[tex]\displaystyle =[2(a^2+2ah+h^2)+5a+5h-3]-[2(a^2-2ah+h^2)+5a-5h-3][/tex]

Distribute:

[tex]=[2a^2+4ah+2h^2+5a+5h-3]-[2a^2-4ah+h^2+5a-5h-3][/tex]

Distribute:

[tex]=(2a^2+4ah+2h^2+5a+5h-3)+(-2a^2+4ah-2h^2-5a+5h+3)[/tex]

Rewrite:

[tex]=(2a^2-2a^2)+(4ah+4ah)+(2h^2-2h^2)+(5a-5a)+(5h+5h)+(-3+3)[/tex]

Combine like terms:

[tex]=8ah+10h[/tex]

Hence:

[tex]Q(a+h)-Q(a-h)=8ah+10h[/tex]

Answer:

The z-score for an ACT score of 16 is -1.23.

His ACT score was of [tex]X = 22.5 + 5.3Z[/tex], considering that Z is his z-score.

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

ACT:

Mean of 22.5, standard deviation of 5.3, so [tex]\mu = 22.5, \sigma = 5.3[/tex]

The z-score for an ACT score of 16 is

Z when x = 16. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{16 - 22.5}{5.3}[/tex]

[tex]Z = -1.23[/tex]

The z-score for an ACT score of 16 is -1.23.

Jose's ACT score had a Z-score of Z. What was his ACT score?

This is X, considering Z his z-score. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{X - 22.5}{5.3}[/tex]

[tex]X - 22.5 = 5.3Z[/tex]

[tex]X = 22.5 + 5.3Z[/tex]

His ACT score was of [tex]X = 22.5 + 5.3Z[/tex], considering that Z is his z-score.

Answer:

-2y + 10

Step-by-step explanation:

Substitution method:

On the second equation of the system, we have to find x as a function of y.

-x - 2y = -10

We have to find x as a function of y, so:

[tex]-x = -10 + 2y[/tex]

Multiplying both sides of the equality by -1:

[tex]x = -2y + 10[/tex]

So -2y + 10 is the answer to this question.

sinh(ln(4)) = (exp(ln(4)) - exp(-ln(4)))/2 = (4 - 1/4)/2 = 15/8 = 1.875

sinh(4) = (exp(4) - exp(-4))/2 ≈ 27.28992

Value of the expression in which each variable was swapped out with a number from its corresponding domain sinh⁡ (l5)

sinh (5)

=sinh(1.6094) =2.39990 rad

=sinh⁡(1.6094) =2.3

By doing the following, you may determine the numerical value of an algebraic expression: Replace each variable with the specified number. Then, enter your score in your team's table.

Value of the expression in which each variable was swapped out with a number from its corresponding domain. In the case of a number with only one digit, referring to the numerical value associated with a digit by its "value" is a convenient shorthand.

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Answer:

0.9021 = 90.21% probability that 10 or fewer customers choose the leading brand

Step-by-step explanation:

For each customer, there are only two possible outcomes. Either they choose the leading brand, or they do not. The probability of a customer choosing the leading brand is independent of any other customer, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The leading brand of dishwasher detergent has a 30% market share.

This means that [tex]p = 0.3[/tex]

A sample of 25 dishwasher detergent customers was taken.

This means that [tex]n = 25[/tex]

a. What is the probability that 10 or fewer customers choose the leading brand?

This is:

[tex]P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{25,0}.(0.3)^{0}.(0.7)^{25} = 0.0001[/tex]

[tex]P(X = 1) = C_{25,1}.(0.3)^{1}.(0.7)^{24} = 0.0014[/tex]

[tex]P(X = 2) = C_{25,2}.(0.3)^{2}.(0.7)^{23} = 0.0074[/tex]

[tex]P(X = 3) = C_{25,3}.(0.3)^{3}.(0.7)^{22} = 0.0243[/tex]

[tex]P(X = 4) = C_{25,4}.(0.3)^{4}.(0.7)^{21} = 0.0572[/tex]

[tex]P(X = 5) = C_{25,5}.(0.3)^{5}.(0.7)^{20} = 0.1030[/tex]

[tex]P(X = 6) = C_{25,6}.(0.3)^{6}.(0.7)^{19} = 0.1472[/tex]

[tex]P(X = 7) = C_{25,7}.(0.3)^{7}.(0.7)^{18} = 0.1712[/tex]

[tex]P(X = 8) = C_{25,8}.(0.3)^{8}.(0.7)^{17} = 0.1651[/tex]

[tex]P(X = 9) = C_{25,9}.(0.3)^{9}.(0.7)^{16} = 0.1336[/tex]

[tex]P(X = 10) = C_{25,10}.(0.3)^{10}.(0.7)^{15} = 0.0916[/tex]

Then

[tex]P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0001 + 0.0014 + 0.0074 + 0.0243 + 0.0572 + 0.1030 + 0.1472 + 0.1712 + 0.1651 + 0.1336 + 0.0916 = 0.9021[/tex]

0.9021 = 90.21% probability that 10 or fewer customers choose the leading brand

Answer:

M = 84 , r = 32

Step-by-step explanation:

Given M is directly proportional to r then the equation relating them is

M = kr ← k is the constant of proportion

To find k use the condition when r = 2, M = 14 , then

14 = 2k ( divide both sides by 2 )

7 = k

M = 7r ← equation of proportion

(a)

When r = 12

M = 7 × 12 = 84

(b)

When M = 224 , then

224 = 7r ( divide both sides by 7 )

32 = r

Answer:

yes

Step-by-step explanation:

if you change it to standard form, it would be

y=1/2x

because it's in the format of y=ax then it is direct variation

x − 2 out of 5n ( x −2 ) + 8 ( x − 2) . ( x − 2 ) ( 5 n + 8 )

I hope this is correct and helps!

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{5n(x - 2) + 8(x - 2) =}[/tex]

[tex]\large\text{DISTRIBUTE 5 and 8 WITHIN the PARENTHESES}[/tex]

[tex]\large\textsf{= 5n(x) + 5(-2) + 8(x) + 8(-2)}[/tex]

[tex]\large\textsf{= 5nx - 10n + 8x - 16}[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: \bf (x - 2)(5n + 8)}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

The area of the shed=[tex]64m^2[/tex]

Step-by-step explanation:

We are given that

Side of square =8m

We have to find the area of the shed.

To find the area of shed we will find the area of square.

We know that

Area of square=[tex]side\times side[/tex]

Using the formula

Area of square=[tex]8\times 8[/tex]

Area of square=[tex]64m^2[/tex]

Area of shed=Area of square

Area of shed=64 square m

Hence, the area of the shed=[tex]64m^2[/tex]

worldwide markets are already established with bis stakeholders like McD, Appe, MS, Aldi Car Manufacturers etc.

so seeing a big corporation emerging from an underdeveloped country would be kind of a suprising thing to happen.

also, economically developed countries are likely to have stable trade relationships with other countries. giving them an edge over outsiders.

Already existing infrastructure might also be a concern to keep in mind when planning your business. It's nice to have mobility, internet, electricity, water at you tap.

I guess there could even be some kind of language barrier for many countries with an insufficient educational system. that might hinder individuals to participate in the global market and community.

Answer:

It's on the next day at 11.45am

Step-by-step explanation:

I hope it helps

Based on the time the plane left, the length of the flight, and the time difference, the plane will arrive at 11 : 45 am the next day.

Because the time is 2 hours ahead, adjust the departure time by 2 hours:

= 22:00 + 2

= 00:00

With the plane leaving by 12 am, the time of arrival is:

= 00:00 + 11 hours 45 mins

= 11 : 45 am

In conclusion, the plane will arrive at 11:45 am.

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Answer:

Answer:

15x(-9)-7

Step-by-step explanation:

it has been translated

Answer:

a speaker receive credibility is a combination of competence trustworthiness and caring

Answer:

P(red and blue) = 1/12

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability of independent events:

If two events, A and B, are independent, the probability of both happening is the multiplication of the probabilities of each event happening, that is:

[tex]P(A \cap B) = P(A)P(B)[/tex]

P (red and blue).

Probability of choosing a red marble, then a blue marble. The marbles are replaced, so the trials are independent.

Probability of a red marble:

3 out of 3 + 5 + 4 = 12. So

[tex]P(A) = \frac{3}{12} = \frac{1}{4}[/tex]

Probability of a blue marble:

4 out of 12, so:

[tex]P(B) = \frac{4}{12} = \frac{1}{3}[/tex]

P (red and blue).

[tex]P(A \cap B) = P(A)P(B) = \frac{1}{4} \times \frac{1}{3} = \frac{1}{4*3} = \frac{1}{12}[/tex]

So

P(red and blue) = 1/12

Answer:

[tex](x,y) = (-3,2)[/tex] is a solution

Step-by-step explanation:

Given

[tex]y \le -4x + 3[/tex]

[tex]x + 8y \ge 7[/tex]

Required

Determine if [tex](x,y) = (-3,2)[/tex] is a solution

[tex]y \le -4x + 3[/tex] becomes

[tex]2 \le -4 * -3 + 3[/tex]

[tex]2 \le 15[/tex] --- this is true

[tex]x + 8y \ge 7[/tex]

[tex]-3+ 8 * 2 \ge 7[/tex]

[tex]13 \ge 7[/tex] --- this is also true

Hence,

[tex](x,y) = (-3,2)[/tex] is a solution

Answer:

Area of ellipse=[tex]\pi ab[/tex]

Step-by-step explanation:

We are given that

[tex]x=acos\theta[/tex]

[tex]y=bsin\theta[/tex]

[tex]0\leq\theta\leq 2\pi[/tex]

We have to find the area enclose by it.

[tex]x/a=cos\theta, y/b=sin\theta[/tex]

[tex]sin^2\theta+cos^2\theta=x^2/a^2+y^2/b^2[/tex]

Using the formula

[tex]sin^2x+cos^2x=1[/tex]

[tex]\frac{x^2}{a^2}+\frac{y^2}{b^2}=1[/tex]

This is the equation of ellipse.

Area of ellipse

=[tex]4\int_{0}^{a}\frac{b}{a}\sqrt{a^2-x^2}dx[/tex]

When x=0,[tex]\theta=\pi/2[/tex]

When x=a, [tex]\theta=0[/tex]

Using the formula

Area of ellipse

=[tex]\frac{4b}{a}\int_{\pi/2}^{0}\sqrt{a^2-a^2cos^2\theta}(-asin\theta)d\theta[/tex]

Area of ellipse=[tex]-4ba\int_{\pi/2}^{0}\sqrt{1-cos^2\theta}(sin\theta)d\theta[/tex]

Area of ellipse=[tex]-4ba\int_{\pi/2}^{0} sin^2\theta d\theta[/tex]

Area of ellipse=[tex]-2ba\int_{\pi/2}^{0}(2sin^2\theta)d\theta[/tex]

Area of ellipse=[tex]-2ba\int_{\pi/2}^{0}(1-cos2\theta)d\theta[/tex]

Using the formula

[tex]1-cos2\theta=2sin^2\theta[/tex]

Area of ellipse=[tex]-2ba[\theta-1/2sin(2\theta)]^{0}_{\pi/2}[/tex]

Area of ellipse[tex]=-2ba(-\pi/2-0)[/tex]

Area of ellipse=[tex]\pi ab[/tex]

Answer: (8x8x9)/3=192

9514 1404 393

Answer:

  b. No; the domain values are not at regular intervals although the range values have a common factor.

Step-by-step explanation:

The differences between x-values are ...

  -1, -1, -1, -2 . . . . not a constant difference

The ratios of y-values are ...

  2/8 = 0.5/2 = 0.125/0.5 = 0.25 . . . . a constant difference

The fact that the domain values do not have a common difference renders the common factor of the range values irrelevant. The relation is not exponential.

Answer:

100

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(-93 - 3)² + [-37 - (-9)]

√(-96)² + (-28)²

√9216 + 784

√10000

= 100

Answer:

y = 65 + 20x

Step-by-step explanation:

Okay, when you're talking about linear equations try to find the fixed value, and then the changing one.

The fixed value will be by itself

The value that varies will have a variable next to it (x, y, z, whatever)

Then, the answer has to be

y = 65 + 20x

Answer:

hlo how are u?whats ur day is going

Answer:

The correct answer is - 242 ft^2

Step-by-step explanation:

Given:

one door : 3*6.5 => 19.5 ft^2

other door: 3*6.5 => 19.5 ft^2

a window: 2*3.5 => 7 ft^2

total =       46 ft^2

area of all four walls: 2h (l+b)

= 2(8) (10+8)

= 16 (18)

= 288 ft^2

paint required excluding doors and window:

=> area of your wall - (area of doors and window)

=> 288 - 46

= 242 ft^2

The question isn't well stated ; If the question intends to ask the meaning of the inequality :

Answer:

Kindly check explanation

Step-by-step explanation:

Given the inequality : y ≥ 3

This inequality statement or expression means that :

y is true for all values beginning from 3 and beyond

That is values from 3 makes the expression a true statement.

Therefore values of y for which the inequality holds or is true are :

(3,....)

Answer:

[tex]P(x < 3) = 25\%[/tex]

[tex]E(x) = 3[/tex]

Step-by-step explanation:

The given parameters can be represented as:

[tex]\begin{array}{ccccccc}x & {5} & {4} & {3} & {2} & {1}& {0} & P(x) & {25\%} & {30\%} & {20\%} & {15\%} & {5\%} & {5\%} \ \end{array}[/tex]

Solving (a): P(x < 3)

This is calculated as:

[tex]P(x < 3) = P(x = 0) + P(x = 1) + P(x =2)[/tex] ----- i.e. all probabilities less than 3

So, we have:

[tex]P(x < 3) = 5\% + 5\% + 15\%[/tex]

[tex]P(x < 3) = 25\%[/tex]

Solving (b): Expected number of events

This is calculated as:

[tex]E(x) = \sum x * P(x)[/tex]

So, we have:

[tex]E(x) = 5 * 25\% + 4 * 30\% + 3 * 20\% + 2 * 15\% + 1 * 5\% + 0 * 5\%[/tex]

[tex]E(x) = 125\% + 120\% + 60\% + 30\% + 5\% + 0\%[/tex]

[tex]E(x) = 340\%[/tex]

Express as decimal

[tex]E(x) = 3.40[/tex]

Approximate to the nearest integer

[tex]E(x) = 3[/tex]

Answer: the first part is 1.25. The second part is y=1.25x

Step-by-step explanation: edge 2021