Answer:
C. Maximal Flow Method
Explanation:
When it comes to optimization theory, Maximal Flow Method or problems have to do with finding a possible or viable flow through a flow network that obtains the maximum potential flow rate. The maximum flow problem can be viewed as an exceptional case of more complex and complicated network flow problems, such as that of the circulation problem.
Use computer software packages, such as Minitab or Excel, to solve this problem. The owner of Showtime Movie Theaters, Inc., used multiple regression analysis to predict gross revenue () as a function of television advertising () and newspaper advertising (). Values of , , and are expressed in thousands of dollars. Weekly Gross Revenue ($1000vs) Television Advertising ($1000in) Newspaper Advertising ($1000s) 96 5 1.5 90 2 2 95 4 1.5 92 2.5 2.5 95 3 3.3 94 3.5 2.3 94 2.5 4.2 94 3 2.5 The estimated regression equation was a. What is the estimated gross revenue for a week where thousand is spent on television and thousand is spent on newspaper advertising (to 3 decimals)
Answer:
a. Gross revenue
b. 95% P.I ( 91.774, 95.400)
Explanation:
Please check the file attached below to see the solution to given question using minitab
Given the following Java code:
public static boolean f(int [] arr) {
for (int i = 0; i < arr.length - 1; i++) {
for (int j = i + 1; j < arr.length; j++) {
if (arr[i] < arr[j]) // *HERE*
return false;}
return true;}
(i) Find the number of times the comparison marked by *HERE* will be evaluated for each input:
{1, 2}
{10, 20, 30}
{30, 20, 10}
{-4, 7, 1}
(ii) For an array of size ????, what is the big-oh runtime of this code in the worst case?
Answer:
See explaination
Explanation:
{1, 2}
Runs only once for 1 < 2
{10, 20, 30}
Runs 1 for 10 < 20
Runs 1 for 10 < 30
Runs 1 for 20 < 30
Total 3 times
{30, 20, 10}
Runs 1 for 30 < 20
Runs 1 for 30 < 10
Runs 1 for 20 < 10
Total 3 times
{-4, 7, 1}
Runs 1 for -4 < 7
Runs 1 for -4 < 1
Runs 1 for -7 < 1
Total 3 times
Generalizing it will run for n*(n-1)/2 so for 2 element it will run for 2*1/2 = 1
For 3 element it will run for 3*2/2 = 3 times
(ii) (3 points) For an array of size , what is the big-oh runtime of this code in the worst case?
Time complexity in Worst case is O(n^2). Reason being it uses two for loop where first loop runs for n time and the second loop runs for n*n time in worst case hence its O(n^2)
short notes on Supply chain Management System (SCMS)
Answer: Its the is the centralized management of the flow of goods and services and includes all processes that transform raw materials into final products. By managing the supply chain, companies are able to cut excess costs and deliver products to the consumer faster.
It is a management of the flow of goods, data, and finances related to a product or service, from the procurement of raw materials to the delivery of the product at its final destination.
Explanation: ik its long but hope it helps
Write a loop that continually asks the user what pets the user has, until the user enters "rock", in which case the loop ends. It should acknowledge the user in the following format. For the first pet, it should say "You have a dog with a total of 1 pet(s)" if they enter dog, and so on.
Sample Run:
User enters:
lemur parrot cat rock
Outputs:
You have a lemur with a total of 1 pet(s)
You have a parrot with a total of 2 pet(s)
You have a cat with a total of 3 pet(s)
Answer:
Check the explanation
Explanation:
The Python program that frequently asks the user what pets the user has,
until the user enters "rock", in which case the loop ends can be analysed in the written codes below.
'''
# count of pets
count = 0
# read the user input
pet = input()
# loop that continues till the user enters rock
# strip is used to remove the whitespace
while pet.strip() != 'rock':
# increment the count of pets
count += 1
# output the pet name and number of pets read till now
print('You have a %s with a total of %d pet(s)' %(pet.strip(),count))
pet = input() # input the next pet
#end of program
Following are the python program to use the loop to count the number of pets until the user enters the "rock":
Program:c = 0#defining a variable c that initilzes with 0
p = input()#defining a variable p that input value
while p != 'rock':#defining a loop that check p value not equal to rock
c += 1#using c variable for counts total number of pets
print('You have a %s with a total of %d pet(s)' %(p,c))#print total number of pet
p = input() #input value
Output:
Please find the attached file.
Program Explanation:
Defining a variable "c" that is initialized with 0, which is used to count input values.In the next line, a "p" variable is declared as the input value from the user end.A while loop is declared to check that the p-value is not equal to 'rock'.Inside this loop, the "c" variable is used for counting the total number of pets, and a print method is used to print the total number of pets.Another input method is used that works until the user inputs the value that is "rock".Find out more about the loop here:
brainly.com/question/17067964
For this problem, use a formula from this chapter, but first state the formula. Frames arrive randomly at a 100-Mbps channel for transmission. If the channel is busy when a frame arrives, it waits its turn in a queue. Frame length is exponentially distributed with a mean of 10,000 bits/frame. For each of the following frame arrival rates, give the delay experienced by the average frame, including both queueing time and transmission time.
a. 90 frames/ sec.
b. 900 frames/ sec.
c. 9000 frames/ sec
Answer:
(a). 0.1 × 10^-3 = 0.1 msec.
(b). 0.11 × 10^-3 = 0.11 msec.
(c). 1 × 10^-3. = 1 msec.
Explanation:
So, in order to solve this problem or question there is the need to use the Markov queuing formula which is represented mathematically as below;
Mean time delay, t = /(mean frame length,L) × channel capacity, C - frame arrival rate, F. ---------------------------------(1).
(a). Using equation (1) above, the delay experience by 90 frames/sec.
=> 1/(10^-4× 10^8 - 90). = 0.1 × 10^-3= 0.1 msec.
(b). Using equation (1) above, the delay experience by 900 frames/sec.
=> 1/(10^-4× 10^8 - 900). = 0.11 × 10^-3= 0.11 msec.
(c). Using equation (1) above, the delay experience by 90 frames/sec.
=> 1/(10^-4× 10^8 - 9000). = 1 × 10^-3= 1 msec.
Hence, the operating queuing system is; 900/10^-4 × 10^8 = 0.9.
This assignment deals with Logical Equivalences. Review section 1.7 of the text before completing the assignment. The assignment may be handed in twice before it is graded. Consider the statements in the left column of the tables below. Translate each into a propositional statement. In the box below, indicate which two statements are logically equivalent. The gray shaded box is the Equation editor that should be used to enter the propositional expression.
Question 1
Statement Reason
Whenever there is a puppy in the house, I feel happy
If I am happy, then there is a puppy in the house
If there is not a puppy in the house, then I am not happy.
If I am not happy, then there is no puppy in the house
Question 2
Statement Reason
If I am in school today, then I am in CSC231 class
If I am not in school today, then I am not civics class
If I am not in CSC231 class, then I am not in school today
If I am in CSC231 class, then I am in school today
Answer:
Question (1) the statements (i) and( iv) are logically equivalent and statements (ii) and (iii) are logically equivalent. Question (2) the statements (i) and (iii) are logically equivalent.
Explanation:
Solution
Question (1)
Now,
Lets us p as puppy in the house, and q as i am happy
So,
p : puppy in the house, and q : i am happy
Thus,
The Statements
(i) so if there is a puppy in the house, I feel happy : p -> q
(ii) If I am happy, then there is a puppy in the house : q -> p
(iii) If there is no puppy in the house, then I am not happy. : ~ p -> ~q
(iv) If I am not happy, then there is no puppy in the house : ~q -> ~p
Hence, the statements (i) and( iv) are logically equivalent and statements (ii) and (iii) are logically equivalent.
Question (2)
Let us denote p as i am in school today, and q as i am in CSC231 class, and r as i am in civics class,
So,
p: i am in school today, q: i am in CSC231 class, r: i am in civics class,
Now,
(i) if I am in school today, then I am in CSC231 class :p -> q
(ii) If I am not in school today, then I am not civics class :~p -> ~r
(iii) If I am not in CSC231 class, then I am not in school today :~q -> ~p
(iv) If I am in CSC231 class, then I am in school today : q -> p
Therefore, the statements i) and iii) are logically equivalent.
Translate We get up at 8 o'clock into Spanish in the box below:
Answer:
nos despertamos a las ocho
Explanation:
A company with a large number of hosts creates three subdomains under a main domain. For easier management of the host records, how many zones should be used
Answer:
4
Explanation:
For easier management of the host records of the company 4 zones should be used because
subdomain is part of a larger domain and the main domain which is the primary domain is the name which the company have decide to use which will represent the company website address and in a situation where the company
have different domain names in which they had registered, they will need to choose one among the domain which will inturn be their main domain.
Therefore for easier , efficient and effective management of the host records 4 zones will be the best zones to be used.
Example of sub domain is north.example.com
For easier management of the host records, 4 zones should be used
Host record or a DNS host, is simply known as record in one's domain's DNS zone file that is said to create the connection between one's domain and its matching IP address.
It is also called an A or Address record. It is said to links a domain to the physical IP address of a computer hosting that has the domain's services.
4 zones in the subdomain is good because a subdomain is part of a larger domain and the main domain and therefore having four will cater for all.
Its gives a creative approach to the management of DNS, DHCP, and IPAM data.
Conclusively, the use of host records helps to manage multiple DNS records, DHCP and IPAM data.
Learn more from
https://brainly.com/question/19281141
It is only likely for a guest to receive outstanding service at luxury brands. That's why Ritz-Carlton, Mandarin Oriental, Four Seasons, and others are the best at what they do.
Answer:
FALSE
Explanation:
A potential danger of social media is that
Answer: information can be viewed my strangers
Explanation:
Apex
What kind of testing is basically checking whether a game or feature works as expected by the developers?
acceptance
functional
compatibility
load
Create a single list that contains the following collection of data in the order provided:
[1121, "Jackie Grainger", 22.22,
1122, "Jignesh Thrakkar", 25.25,
1127, "Dion Green", 28.75, False,
24.32, 1132, "Jacob Gerber",
"Sarah Sanderson", 23.45, 1137, True,
"Brandon Heck", 1138, 25.84, True,
1152, "David Toma", 22.65,
23.75, 1157, "Charles King", False,
"Jackie Grainger", 1121, 22.22, False,
22.65, 1152, "David Toma"]
The data above represents employee information exported from an Excel spreadsheet. Whomever typed the data in originally didn't give much care to how the information was formatted, unfortunately. Each line of data has in it employee information (the whole number), the name of the employee (the string), and the employee's hourly wage (the decimal number). Some rows have extra information in them from a column in the spreadsheet that no one can remember what its purpose was.
Note that the presence of a couple of new data types in the above - "float" values (the numbers with the decimals in them) and "bool" [short for boolean] values (True and False).
Assume that the above information is a small sample of the company's data. Programmatically sort the information into three different lists: one for employee numbers, one for employee names, and one for employee salary information.
No duplicate data should make its way into the new lists.
For each value in the list containing hourly wage information, multiply the current value by 1.3 (since benefits are about 30% of a person's salary) and store each value in a list called total_hourly_rate. Programmatically determine the maximum value in the list and if it's over over 37.30, throw a warning message that someone's salary may be a budget concern.
Determine if anyone's total hourly rate is between 28.15 and 30.65. If they are, add the hourly rate a new list called underpaid_salaries.
For each value in the list that contains unmodified salary information, calculate a raise in dollars according to the following rules:
If the hourly rate is between 22 and 24 dollars per hour, apply a 5% raise to the current rate. If the hourly rate is between 24 and 26 dollars per hour, apply a 4% raise to the current rate. If the hourly rate is between 26 and 28 dollars per hour, apply a 3% raise to the current rate. All other salary ranges should get a standard 2% raise to the current rate.
Add each new value you calculate to a new list called company_raises.
Design your own complex condition with no fewer than four different truth tests in it (all conditions must be on one line, in other words). Above your condition, write out in comments the exact behavior you are implementing with Python.
Answer:
A code was created to single list that contains the following collection of data in the order provided
Explanation:
Solution
#list that stores employee numbers
employeee_numbers=[1121,1122,1127,1132,1137,1138,1152,1157]
#list that stores employee names
employee_name=["Jackie Grainger","Jignesh Thrakkar","Dion Green","Jacob Gerber","Sarah Sanderson","Brandon Heck","David Toma","Charles King"]
#list that stores wages per hour employee
hourly_rate=[22.22,25.25,28.75,24.32,23.45,25.84,22.65,23.75]
#list that stores salary employee
company_raises=[]
max_value=0
#list used to store total_hourly_rate
total_hourly_rate=[]
underpaid_salaries=[]
#loop used to musltiply values in hourly_wages with 1.3
#and store in new list called total_hourly_rate
#len() is used to get length of list
for i in range(0,len(hourly_rate)):
#append value to the list total_hourly_rate
total_hourly_rate.append(hourly_rate[i]*1.3)
for i in range(0,len(total_hourly_rate)):
#finds the maximum value
if(total_hourly_rate[i]>max_value):
max_value=total_hourly_rate[i] #stores the maximum value
if(max_value>37.30):
print("\nSomeone's salary may be a budget concern.\n")
for i in range(0,len(total_hourly_rate)):
#check anyone's total_hourly_rate is between 28.15 and 30.65
if(total_hourly_rate[i]>=28.15 and total_hourly_rate[i]<=28.15):
underpaid_salaries.append(total_hourly_rate[i])
for i in range(0,len(hourly_rate)):
#check anyone's hourly_rate is between 22 and 24
if(hourly_rate[i]>22 and hourly_rate[i]<24):
#adding 5%
hourly_rate[i]+=((hourly_rate[i]/100)*5)
elif(hourly_rate[i]>24 and hourly_rate[i]<26):
#adding 4%
hourly_rate[i]+=((hourly_rate[i]/100)*4)
elif(hourly_rate[i]>26 and hourly_rate[i]<28):
#adding 3%
hourly_rate[i]+=((hourly_rate[i]/100)*3)
else:
#adding 2% for all other salaries
hourly_rate[i]+=((hourly_rate[i]/100)*2)
#adding all raised value to company_raises
company_raises.extend(hourly_rate)
#The comparison in single line
for i in range(0,len(hourly_rate)):
For this exercise i used ternary
operator hourly_rate[i]= (hourly_rate[i]+((hourly_rate[i]/100)*5)) if (hourly_rate[i]>22 and hourly_rate[i]<24) else (hourly_rate[i]+((hourly_rate[i]/100)*4)) if (hourly_rate[i]>24 and hourly_rate[i]<26) else hourly_rate[i]+((hourly_rate[i]/100)*2)
In this lab, you will design a die game called 15. The object of the game is to score exactly 15 points in as few rolls of the die as possible. After each roll, the player can choose to add the current die value to his or her score or not, unless the die value is six, in which case it is automatically added to the player’s score. If the player’s score exceeds 15, the player loses. If the player’s score is equal to 15, the player wins. Play continues until the player reaches or exceeds 15 points.
Description:
To start the game, the player presses the reset switch. The score will be set to zero and both the Win and Lose LEDs will be turned off. The player then rolls the die by toggling the Rb switch to the Roll position. The die counter should operate with a clock frequency of 27 MHz or 50 MHz so that the player cannot control the outcome of a roll. After about a second or more, the player toggles the Rb switch back to the Off position to end the roll. The Turn Counter should be incremented to indicate that the player has taken a roll. If the player rolled a six, it is automatically added to his or her score. Otherwise, the player can press the Add button to add the die value to his or her score or the player can press the Pass button to leave the score unchanged. After each roll, the score will be greater than, less than or equal to 15. If the score is equal to 15, the player wins – the Win LED should be turned on and remain on until the system is reset for a new game. If the score is greater than 15, the player loses – the Lose LED should be turned on and remain on until the system is reset. Once the player has won or lost, the player cannot roll the die again until the system is reset. (The Rb switch will not have any effect in these states.) If the score is less than 15, the player will roll again. After each roll, the player presses either the Add button or the Pass button (unless a six is rolled) before the die can be rolled again. Play continues until the player’s score equals or exceeds 15.
1) Draw a state diagram for the game as a Moore finite state machine.
2) Draw a state diagram for the game as a Mealy finite state machine.
Answer:
Explanation:
Check the file attached below to see the diagram that is drawn for the question being answered
what term defines inventiveness uncertainty and futuristic ideas typically deals with science and technology
Answer:
Innovation.
Explanation:
Innovation can be considered the ideal term, because an innovative idea arises from the set of a new technique, method or invention that aims to improve an existing method, standard, or product.
However, added to an innovative idea is the risk, since innovation breaks an already established standard, so it is through science and technology that an invention will gain greater foundation and recognition, which increases its credibility and acceptance.
Create a simple program that calls a function call gradeCalculated, in the main area the user is asked to enter their grade from 0-100. (Python)
Answer:
def gradeCalculated(score):
if score < 60:
letter = 'F'
elif score < 70:
letter = 'D'
elif score < 80:
letter = 'C'
elif score < 90:
letter = 'B'
else:
letter = 'A'
return letter
def main():
grade = int(input("enter your grade from 0-100: "))
print("Letter grade for ",grade,"is:",gradeCalculated(grade))
if(grade>80):
print("You are doing good! keep it up!!")
else:
print("You have to get work hard")
main()
Explanation:
See attached image for output
Which three statements about RSTP edge ports are true? (Choose three.) Group of answer choices If an edge port receives a BPDU, it becomes a normal spanning-tree port. Edge ports never generate topology change notifications (TCNs) when the port transitions to a disabled or enabled status. Edge ports can have another switch connected to them as long as the link is operating in full duplex. Edge ports immediately transition to learning mode and then forwarding mode when enabled. Edge ports function similarly to UplinkFast ports. Edge ports should never connect to another switch.
Answer:
Edge ports should never connect to another switch. If an edge port receives a BPDU, it becomes a normal spanning-tree port. Edge ports never generate topology change notifications (TCNs) when the port transitions to a disabled or enabled status.Must be completed in JAVA
Complete SortedTableMap. The SortedTreeMap from the final lecture uses an AVLTree to implement the SortedMap interface so that the essential methods run in O(log n) time, which is relatively quite good. For this problem, complete the empty SortedTableMap class by using an ArrayList to implement the SortedMap interface. It will not be possible to implement all of the essential methods so that they run in O(log n) time, but your implementation should be as runtime efficient as possible. Specifically, the get method can be done in O(log n) time; some other methods can be done in O(n), some can be done in O(1).
package Class;
/*
* This file should not be modified
*/
public interface SortedMap extends Map {
Entry firstEntry();
Entry lastEntry();
Entry floorEntry(K key);
Entry ceilingEntry(K key);
Entry lowerEntry(K key);
Entry higherEntry(K key);
Iterable> subMap(K fromKey, K toKey);
}
package Class;
import java.util.ArrayList;
import java.util.Comparator;
/*
* Complete this file for part 3 of the assignment
*
* No additional classes should be imported
*/
public class SortedTableMap extends AbstractMap implements SortedMap {
}
Answer:
What is your question?
Consider the code fragment below. Show the values stored at each location in memory and as they change while the code executes. Use the memory addresses given in the comments following each statement. Assume all integer and pointer sizes are four bytes and each box in the memory representation is 4 bytes.
int x; // x is at memory address 5000
int *y; // *y is at memory address 5004
int *z; // *z is at memory address 5008
int *a; // a is at memory address 5012
z=&x;
y=malloc(5 * sizeof(int)); // malloc returns
// address 6000
X = 10;
y[1] = 15;
y[2] = *z; x=*(y + 1);
a = malloc(sizeof(int)); // malloc returns // address 6020
*a = *y; a = z; *z= 25; *a = 12; y[3] = *z; y[4] = x; y[0] = x;
Answer:
see explaination
Explanation:
Final value :-
Memory => value = reference in code
5000 => 12 = x
5004 => 6000 = *y
5008 => 5000 = *z
5012 => 5000 = *a
6000 => 12 = y[0]
6004 => 15 = y[1]
6008 => 10 = y[2]
6012 => 12 = y[3]
6016 => 12 = y[4]
6020 =>
What happens in the process represented by the flowchart ?
A) The person drinks water if the answer to “Thirsty?” is no.
B) The person always drinks water.
C) The person drinks water if the answer to “Thirsty?” is yes.
D) The person never drinks water.
CORRECT ANSWER: C!!!
Answer:
the person drinks water if the answer to “thirsty?” is yes
Answer:
C
Explanation:
Computer security experts devote their time and energy to the protection of sensitive data and the prevention of an outside attack on the internal network. They specialize in building secure firewalls as well as complex intrusion detection systems designed to keep intruders out. They watch and monitor the incoming message traffic very closely. But no matter how well they protect the private network from outside access without proper authority, they do not help prevent an attack by a malicious or disgruntled employee from the inside. And they cannot prevent breaches due to a simple lack of understanding of security policy by internal employees.When do YOU think an organization needs information systems security policies? Why?
Answer:
Information security policy are used for the prevention of intruders hacking a network when an organization start getting IT related attacks.
Explanation:
Information security policy are used for the prevention of intruders hacking a network when an organization start getting IT related attacks.
An information security policy are set of rules/policies designed to guide employees for the protection of the security of company information and IT systems. The reasons for these policies are:
It defines what is required from organization’s employees for the security of the IT systemsInformation security policies provide a means to secure the organization against external and internal threats Information security policies are a mechanism to for ensuring an organization’s legal and ethical responsibilities Information security policies are created to hold each employee responsible with regard to information securityJoe, Kate and Jody are members of the same family. Kate is 5 years older than Joe. Jody is 6 years older than Kate . The sum of their ages squared is 961 years. What are their ages?
Answer:
5, 10 and 16
Explanation:
The sum of their ages is √961 = 31
If Joe is x years old, the equation that follows is:
x + (x+5) + (x+5+6) = 31
This simplifies to
3x = 31 - 11 - 5 = 15
so x=5
From that you can find
Joe = x = 5
Kate = x+5 = 10
Jody = x+5+6 = 16
can a +2 management studnet from nepal study computer engineer in UK?
Answer: The UK government offers a global scholarship programme called “Chevening”. It is open to all international students who meet the Chevening eligibility criteria, which states you must have applied for at least three degree courses in the UK, usually one-year Master's courses
Explanation: So yes that should be fine
What process is used to convert numbers between the binary system and the decimal system?
ANSWER: D) Look up the number on a binary-to-decimal conversion table
Answer:
The method is easy . Divide the binary number by 2 and write the remainder . Again divide by 2 and write remainder and continue till remainder becomes 1 . Then write all the remainders (0 , 1) in the order . The decimal is converted into binary
If you wanna convert binary into decimal , number the digits of a binary number from right to left and from 0 to how much digits are there. Then the digit 1 or 0 is multiplied by the corresponding power of 2 , which comes after numbering . Add all them and you get them into decimal
Answer:
The answer is D) Look up the number on a binary-to-decimal conversion table.
Explanation:
Consider the following relational schema, where the primary keys are Bold,
Students(sid, sname, address, dept_id)
Courses(cid, cname, dept_id)
Departments(dept_id, dname, college)
Grades(sid, cid, year, semester, grade)
Write the following queries in SQL. Only use the tables that are absolutely needed for the corresponding query.
1. Find the sids and snames of students who took "Database" course (i.e., cname = ‘Database’) in Fall 2019.
2. Find the average grade of all the students who took "CS327" (i.e., cid=‘CS327’) in Fall 2019. You can assume grade is a numerical attribute.
3. Find the number of distinct courses offered by each department in Fall 2019.
4. Find the sids of students who have taken at least 10 different courses offered by "Computer Science" department (i.e., dname = ‘Computer Science’).
Answer:
The queries for each question are explained.
1. Find the sids and snames of students who took "Database" course (i.e., cname = ‘Database’) in Fall 2019.
The columns sid and sname are taken from students table.
The course name belong to the courses table.
The semester and year belong to the grades table.
To get the final query, all these tables need to be joined in the FROM clause using JOIN ON keywords.
select s.sid, sname
from students s join grades g on g.sid = s.sid
join courses c on g.cid = c.cid
where cname like 'database%'
and semester like 'Fall'
and year=2019
2. Find the average grade of all the students who took "CS327" (i.e., cid=‘CS327’) in Fall 2019. You can assume grade is a numerical attribute.
The grade column is taken from grades table.
The course id belongs to the grades table.
The semester and year also belong to the grades table.
The final query is formed using the grades table only.
select avg(grade)
from grades
where cid like 'CS327'
and semester like 'Fall'
and year=2019
3. Find the number of distinct courses offered by each department in Fall 2019.
The department id belongs to the courses table.
The course id belongs to the grades table.
The semester and year also belong to the grades table.
To get the final query, the courses and the grades tables are joined in the FROM clause using JOIN ON keywords.
select dept_id, count(distinct g.cid)
from courses c join grades g on c.cid = g.cid
where semester like 'Fall'
and year=2019
group by dept_id
Write a program that will ask for the user to input a filename of a text file that contains an unknown number of integers. And also an output filename to display results. You will read all of the integers from the input file, and store them in an array. (You may need to read all the values in the file once just to get the total count) Using this array you will find the max number, min number, average value, and standard deviation. These results will be reported to both the screen and placed into the output file that the user choose. Output to screen and file could look like this: Read from file: 12 values Maximum value
Answer: Provided in the explanation section
Explanation:
Code provided below in a well arranged format
inputNos.txt
70
95
62
88
90
85
75
79
50
80
82
88
81
93
75
78
62
55
89
94
73
82
___________________
StandardDev.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class StandardDev {
public static void main(String[] args) {
//Declaring variables
String filename;
int count = 0, i = 0;
Scanner sc1 = null;
int min, max;
double mean, stdDev;
int nos[] = null;
/*
* Creating an Scanner class object which is used to get the inputs
* entered by the user
*/
Scanner sc = new Scanner(System.in);
//Getting the input entered by the user
System.out.print("Enter the name of the filename :");
filename = sc.next();
try {
//Opening the file
sc1 = new Scanner(new File(filename));
//counting no of numbers in the file
while (sc1.hasNext()) {
sc1.nextInt();
count++;
}
sc1.close();
sc1 = new Scanner(new File(filename));
//Creating an Integer based on the Count
nos = new int[count];
//Populating the values into an array
while (sc1.hasNext()) {
nos[i] = sc1.nextInt();
i++;
}
sc1.close();
//calling the methods
min = findMinimum(nos);
max = findMaximum(nos);
mean = calMean(nos);
stdDev = calStandardDev(nos, mean);
//Displaying the output
System.out.println("Read from file :" + count + " values");
System.out.println("The Minimum Number is :" + min);
System.out.println("The Maximum Number is :" + max);
System.out.printf("The Mean is :%.2f\n", mean);
System.out.printf("The Standard Deviation is :%.2f\n", stdDev);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
}
//This method will calculate the standard deviation
private static double calStandardDev(int[] nos, double mean) {
//Declaring local variables
double standard_deviation = 0.0, variance = 0.0, sum_of_squares = 0.0;
/* This loop Calculating the sum of
* square of eeach element in the array
*/
for (int i = 0; i < nos.length; i++) {
/* Calculating the sum of square of
* each element in the array
*/
sum_of_squares += Math.pow((nos[i] - mean), 2);
}
//calculating the variance of an array
variance = ((double) sum_of_squares / (nos.length - 1));
//calculating the standard deviation of an array
standard_deviation = Math.sqrt(variance);
return standard_deviation;
}
//This method will calculate the mean
private static double calMean(int[] nos) {
double mean = 0.0, tot = 0.0;
// This for loop will find the minimum and maximum of an array
for (int i = 0; i < nos.length; i++) {
// Calculating the sum of all the elements in the array
tot += nos[i];
}
mean = tot / nos.length;
return mean;
}
//This method will find the Minimum element in the array
private static int findMinimum(int[] nos) {
int min = nos[0];
// This for loop will find the minimum and maximum of an array
for (int i = 0; i < nos.length; i++) {
// Finding minimum element
if (nos[i] < min)
min = nos[i];
}
return min;
}
//This method will find the Maximum element in the array
private static int findMaximum(int[] nos) {
int max = nos[0];
// This for loop will find the minimum and maximum of an array
for (int i = 0; i < nos.length; i++) {
// Finding minimum element
if (nos[i] > max)
max = nos[i];
}
return max;
}
}
_____________________
Output:
Enter the name of the filename :inputNos.txt
Read from file :22 values
The Minimum Number is :50
The Maximum Number is :95
The Mean is :78.45
The Standard Deviation is :12.45
cheers i hope this helped !!!
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and returns the matching position. The input parameters should be a pointer to the source string and a pointer to the target string. If a match is found, the procedure sets the Zero flag and EAX points to the matching position in the target string. Otherwise, the Zero flag is clear and EAX is undefined.
Answer: Provided in the explanation section
Explanation:
Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE
.data
target BYTE "01ABAAAAAABABCC45ABC9012",0
source BYTE "AAABA",0
str1 BYTE "Source string found at position ",0
str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0
str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0
stop DWORD ?
lenTarget DWORD ?
lenSource DWORD ?
position DWORD ?
.code
main PROC
INVOKE Str_find,ADDR target, ADDR source
mov position,eax
jz wasfound ; ZF=1 indicates string found
mov edx,OFFSET str3 ; string not found
call WriteString
jmp quit
wasfound: ; display message
mov edx,OFFSET str1
call WriteString
mov eax,position ; write position value
call WriteDec
mov edx,OFFSET str2
call WriteString
quit:
exit
main ENDP
;--------------------------------------------------------
Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string
pSource:PTR BYTE ;PTR to Source string
;
; Searches for the first matching occurrence of a source
; string inside a target string.
; Receives: pointer to the source string and a pointer
; to the target string.
; Returns: If a match is found, ZF=1 and EAX points to
; the offset of the match in the target string.
; IF ZF=0, no match was found.
;--------------------------------------------------------
INVOKE Str_length,pTarget ; get length of target
mov lenTarget,eax
INVOKE Str_length,pSource ; get length of source
mov lenSource,eax
mov edi,OFFSET target ; point to target
mov esi,OFFSET source ; point to source
; Compute place in target to stop search
mov eax,edi ; stop = (offset target)
add eax,lenTarget ; + (length of target)
sub eax,lenSource ; - (length of source)
inc eax ; + 1
mov stop,eax ; save the stopping position
; Compare source string to current target
cld
mov ecx,lenSource ; length of source string
L1:
pushad
repe cmpsb ; compare all bytes
popad
je found ; if found, exit now
inc edi ; move to next target position
cmp edi,stop ; has EDI reached stop position?
jae notfound ; yes: exit
jmp L1 ; not: continue loop
notfound: ; string not found
or eax,1 ; ZF=0 indicates failure
jmp done
found: ; string found
mov eax,edi ; compute position in target of find
sub eax,pTarget
cmp eax,eax ; ZF=1 indicates success
done:
ret
Str_find ENDP
END main
cheers i hoped this helped !!
Chemical equations of Carbon + water
Answer:
Aqueous carbon dioxide, CO2 (aq), reacts with water forming carbonic acid, H2CO3 (aq). Carbonic acid may loose protons to form bicarbonate, HCO3- , and carbonate, CO32-. In this case the proton is liberated to the water, decreasing pH. The complex chemical equilibria are described using two acid equilibrium equations.
PLS MARK AS BRAINLIEST
Assume variables SimpleWriter out and int n are already declared in each case. Write a while loop that printsA. All squares less than n. For example, if n is 100, print 0 1 4 9 16 25 36 49 64 81.B. All positive numbers that are divisible by 10 and less than n. For example, if n is 100, print 10 20 30 40 50 60 70 80 90C. All powers of two less than n. For example, if n is 100, print 1 2 4 8 16 32 64.
Answer:
This program has been written using JAVA. The code is written beloe:
// import library
import java.util.Scanner;
public category Main operate
public static void main(String[] args)
{
// scanner category
Scanner scan=new Scanner(System.in);
System.out.println("Enter Number:");
int n=scan.nextInt();
//All squares but n
System.out.println("All squares but n are: ");
int temp=0,square=0,i=0;
while(square
range
square=i*i;
if(square>=n)break;
System.out.print(square+" ");
i++;
}
//All positive numbers that are divisible by 10 but less than n
System.out.println(" ");
System.out.println(" ");
System.out.println("All positive numbers are divisible by 10 and less than n are: ");
i=1;
while(i
{
if(i%10==0)
System.out.print(i+" ");
if(i>=n)break;
i++;
}
System.out.println(" ");
System.out.println(" ");
System.out.println("All powers of 2 that are less than n are: ");
//All powers of 2 less than n
i=0;
while(i
mathematics.pow(2, i);
if(num_power
System.out.print(num_power+" ");
i++;
}
}
}
Explanation:
With SimpleWriter out and int n already declared in each case this program makes use of a while loop condition to satisfy the following;
1. All squares less than n
2. positive numbers that are divisible by 10 and less than n.
3. All powers of two less than n.
as a sales person which size hard disc would you recommend a customer who needs to use Microsoft PowerPoint application?
Answer:
Not very big - maybe 64 GB or 128 GB
Explanation:
PPT doesn't take up much space
Exact Target was acquired by Salesforce, which in turn was converted to __________.
Answer:
Salesforce Marketing Cloud.
Explanation:
Exact Target was founded by Peter McCormick, Chris Baggott and Scott Dorsey on the 15th of December, 2000 in Indianapolis, Indiana, United States of America and was later acquired by Salesforce in the year 2013 for $2.5 billion. Salesforce in turn converted Exact Target to Salesforce Marketing Cloud in the year 2014.
The Salesforce Marketing Cloud is a company that provide services such as digital marketing automation and analytics software. Salesforce Marketing Cloud softwares are sold primarily on a multi-year subscription basis and based on number of users, features enabled, and level of customer service. It is a hosted, online subscription model that provides users with services such as, consulting, mobile, implementation, email, social and digital marketing.