In a recent academic year, many public universities in the United States raised tuition and fees due to a decrease in state subsidies. The change in the cost of tuition, a shared dormitory room, and the most popular meal plan from the previous academic year for a sample of 10 public universities were as follows:

$1,589, $593, $1,223, $869, $423, $1,720, $708, $1,425, $922 and $308.

a. What is the mean and median change in the cost? (Explain how you obtain your answer.)
b. What is the five-number summary of the change in the cost? (Explain how you obtain your answer.)
c. What is the standard deviation of the change in the cost? (Explain how you obtain your answer.)
d. The middle 50% of the change in the cost is spread over what value? (Explain how you obtain your answer.)
e. What is the coefficient of variation of the change in cost? (Explain how you obtain your answer.)
f. What are the (absolute values of) the Z scores of the change in cost?

Answers

Answer 1

Answer:

1. mean = 980 median = $895.5

2. 308, 593, 895.5, 1425, 1720

3. 491.7978

4. 895.5

5. 50.28%

Step-by-step explanation:

1. mean $1,589+$593+$1,223+$869+$423+$1,720+$708+$1,425+$922+$308/10

= 9780/10

= $978

median

We first arrange the values in ascending order

308,423,593,708,869,922,1223,1425,1589,1720

number of observation is even so we pick the 2 values in the middle and divide by 2

= 869+922/2

= $1791/2

$895.5

2. five number summary of change

the botom half of th dta set = 308,423,593,708,869

minimum value = 308

n = 5

median = 593 = q1

from 1, q2 = median = $895.5

the upper half of data

922,1223,1425,1589,1720

n = 5

median = $1425

maximum value = $1720

the five number summary of change in cost is therefore

308, 593, 895.5, 1425, 1720

3. standard deviation

[tex]s =[\sqrt{x-barx} ]^{2} \frac{1}{n-1}[/tex]

bar x is the mean = 978

($1,589-978)²+ ($593-978)²+ ($1,223-978)²+ ($869-978)+ ($423-978)²+ $1,720-978)²+($708-978)²+ ($1,425-978)²+ ($922-978)²+ ($308-978)²

= 2176786

=[tex]\sqrt\frac{1}{10-1} {2176786} \\\sqrt{ \frac{2176786}{9}[/tex]

= [tex]\sqrt{241865.1}[/tex]

= 491.7978

4.  middle 50% is spread over the median, which is 895.5

5.  coefficient of variation

= s/bar x * 100

= 491.7978/978 * 100

= 49179.78/978

= 50.28%

6. z score = x - mean/s

x = 1589

= 1589-978/491.7978

= 1.2424

for x = 593

593-978/491.7978

= -0.7828

= 0.7828

for x = 1223

1223-978/491.7978

= 0.4982

for x = 869

869-978/491.7978

= -0.2216

= 0.2216

for x = 423

423-978/491.7978

= -1.1285

= 1.1285

x = 1720

1720-978/491.7978

z = 1.5088

for x = 708

708-978/491.7978

= -0.5490

= 0.5490

for x = 1425

1425-978/491.7978

= 0.9089

for x = 922

922-978/491.7978

= -0.1139

= 0.1139

for x = 308

308-978/491.7978

= -1.3624

= 1.3624


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Answers

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According to the U.S. Census, the proportion of adults in a certain county who owned their own home was 0.71. An SRS of 100 adults in a certain section of the county found that 65 owned their home. What represents the approximate probability of obtaining a sample of 100 adults in which 65 or fewer own their home, assuming that this section of the county has the same overall proportion of adults who own their home as does the entire county?

Answers

Answer:

0.0764 = 7.64% approximate probability of obtaining a sample of 100 adults in which 65 or fewer own their home.

Step-by-step explanation:

To solve this question, we use the normal approximation to the binomial distribution.

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The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

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Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

According to the U.S. Census, the proportion of adults in a certain county who owned their own home was 0.71.

This means that [tex]p = 0.71[/tex]

Sample of 100:

This means that [tex]n = 100[/tex]

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[tex]\mu = E(X) = np = 100*0.71 = 71[/tex]

Standard deviation:

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.71*0.29} = 4.5376[/tex]

What represents the approximate probability of obtaining a sample of 100 adults in which 65 or fewer own their home, assuming that this section of the county has the same overall proportion of adults who own their home as does the entire county?

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[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{64.5 - 71}{4.5376}[/tex]

[tex]Z = -1.43[/tex]

[tex]Z = -1.43[/tex] has a pvalue of 0.0764

0.0764 = 7.64% approximate probability of obtaining a sample of 100 adults in which 65 or fewer own their home.

Rewrite the fraction pairs with common denominators

A. 3/20 and 4/5

B. 8/21 and 6/7

C. 2/8 and 4/9

Answers

Answer:

a) [tex]\frac{3}{20}[/tex] and [tex]\frac{16}{20}[/tex] = [tex]\frac{19}{20}[/tex]

b) [tex]\frac{8}{21}[/tex] and [tex]\frac{18}{21}[/tex] = [tex]1\frac{5}{21}[/tex]

c) [tex]\frac{18}{72}[/tex] and [tex]\frac{32}{72}[/tex] = [tex]\frac{25}{36}[/tex]

Step-by-step explanation:

a) [tex]\frac{3}{20}[/tex] and [tex]\frac{4}{5}[/tex]

[tex]\frac{4}{5}[/tex] x 4 = [tex]\frac{16}{20}[/tex]

[tex]\frac{3}{20}[/tex] and [tex]\frac{16}{20}[/tex] = [tex]\frac{19}{20}[/tex]

b) [tex]\frac{8}{21}[/tex] and [tex]\frac{6}{7}[/tex]

[tex]\frac{6}{7}[/tex] x 3 = [tex]\frac{18}{21}[/tex]

[tex]\frac{8}{21}[/tex] and [tex]\frac{18}{21}[/tex] = [tex]1\frac{5}{21}[/tex]

c) [tex]\frac{2}{8}[/tex] and [tex]\frac{4}{9}[/tex]

[tex]\frac{2}{8}[/tex] x 9 = [tex]\frac{18}{72}[/tex]

[tex]\frac{4}{9}[/tex] x 8 = [tex]\frac{32}{72}[/tex]

[tex]\frac{18}{72}[/tex] and [tex]\frac{32}{72}[/tex] = [tex]\frac{25}{36}[/tex]

2800cm cubed into litres

Answers

Answer: 2.8 liters

Please mark as brainliest

Step-by-step explanation

divide by the volume of 1,000

2,800 divided by 1,000 is 2.8 so it is 2.8 liters

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