In a particular crash test, an automobile of mass 1577 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 17 m/s and 1.5 m/s, respectively. If the collision lasts for 0.18 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s.

Answers

Answer 1

Answer:

Ft=24,443.5 kgm/s

Explanation:

Step one

Given data

Mass of automobile m=1577kg

Initial Velocity u=17m/s

Final Velocity v=1.5m/s

Time t=0.18s

Step two

From the impulse and momentum equation

Ft=mΔv

Substitute

Ft=1577*(17-1.5)

Ft=1577*15.5

Ft=24,443.5 kgm/s


Related Questions

Please help! Will give a lot of points

Answers

Answer:

Chemical and Biological weathering.

Explanation:

Processes that break down and weaken earth minerals are known as weathering. Over time, this can lead to erosion, in which huge sections of rock and stone are carried away, changing landscapes. Physical weathering alters the material structure of rocks, while chemical weathering alters their chemical structure.

A small mass is released from rest at a very great distance from a larger stationary mass. Draw a graphs best represents the gravitational potential energy U of the system of the two masses as a function of time T.

Answers

Answer:

attached below

Explanation:

Gravitational potential

energy = [tex]- \frac{GmM}{r}[/tex] ,

V ∝ [tex]- \frac{1}{r}[/tex]  

attached below is a graph that represents the gravitational potential energy U

Gravitational potential energy is the energy held in an entity as a result of its vertical position or length. This gravitational pull of a planet on an object causes the information to be stored.

This is connected with gravitational pull since it takes work to lift anything against the gravity of the Earth.

Freshwater in a raised lake or kept behind a dam demonstrates gravitational force.

According to the formula:

Gravitational potential energy [tex]\bold{=-\frac{GMm}{r^2}}[/tex]

Therefore

[tex]\to \bold{V \propto -\frac{1}{r}}[/tex]

Therefore, the answer is "Option d"

Learn more about the Gravitational potential :

brainly.com/question/17001724

A speedboat moving at 29.0 m/s approaches a no-wake buoy marker 100 m ahead. The pilot slows the boat with a constant acceleration of -3.4 m/s2 by reducing the throttle. (a) How long does it take the boat to reach the buoy

Answers

Answer:

[tex]t =4.8sec[/tex]

Explanation:

From the question we are told that

Velocity of speed boat [tex]V=29.0m/s[/tex]

Distance to Marker [tex]d=100[/tex]

Acceleration of [tex]a=-3.4m/s^2[/tex]

Generally the Newtons 3rd motion equation is given as

 [tex]v^2 = u^2 + 2 * a* s[/tex]

 [tex]v^2 = 29^2 + 2 * -3.4* 100[/tex]

 [tex]v = \sqrt{161}[/tex]

 [tex]v=12.68m/s[/tex]

Generally the Newton's first equation of motion is given as

 [tex]v = u + a*t[/tex]

 [tex]12.68 = 29 -3.4*t[/tex]

 [tex]12.68-29 = -3.4t[/tex]

 [tex]-16.32 = -3.4t[/tex]

 [tex]t =\frac{-16.32}{-3.4}[/tex]

 [tex]t =4.8sec[/tex] .

Match each term with the appropriate definition​

Answers

Answer:

opaque = 4

malleable = 3

ductile = 2

lustrous (or whatever the bottom word is) = 1

Answer:screenshot

Explanation:

You and your friends are organizing a trip to Europe. Your plan is to rent a car and drive through the major European capitals. By consulting a map you estimate that you will cover a total distance of 5000 kmkm. Consider the euro-dollar exchange rate given in the introduction and use unit conversion to work through these simple problems.

Required:
a. You select a rental package that includes a car with an average consumption of 6.00 liters of fuel per 100 km. Considering that in Europe the average fuel cost is 1.063 euros/liter, how much (in US dollars) will you spend in fuel on your trip?
b. How many gallons of fuel would the rental car consume per mile?
c. What is the average cost, in dollars per gallon, of fuel in Europe?

Answers

Answer:

$383

0.0255

4.83

Explanation:

We're asked to find the total fuel consumed over distance traveled and the cost of given fuel.

To start with, we convert Euro value to USD

Total distance traveled is 5000 km

Average fuel consumption is 6 ltr per 100 km = 0.06 ltr/km

Average fuel cost is 1.063 EUR/ltr

We're going to use a flat rate of 1 EUR to USD = 1.2 USD

To get the total fuel consumption, we use the formula

Total fuel consumption = total distance * average fuel consumption

Total fuel consumption = 5000 km * 0.06 ltr/km

Total fuel consumption = 300 ltr

Finding the total fuel cost, we use the formula

Total fuel cost = total fuel consumption * average fuel cost

Total fuel cost = 300 ltr * 1.063 EUR/ltr

Total fuel cost = 318.9 EUR

Total fuel cost in USD then is, 318.9 EUR × 1.2 USD/EUR

Total fuel cost = 383 USD

b

To convert given fuel consumption to mile per km

Average fuel consumption is 0.06 ltr/km

Conversion rate of Ltr to gal is 1 ltr = 0.264 gal/ltr

Conversion of Km to mile is 1 km = 0.621 mile/km

Going forward, the Average fuel consumption = 0.06 ltr/km * 0.264 gal/ltr ÷ 0.621 mile/km

Average fuel consumption = 0.01584 / 0.621

Average fuel consumption = 0.0255 gal/km

c) to convert given cost of fuel to USD/gal, we say

Average fuel cost is 1.063 EUR/ltr

We'd already stated that the following rates

EUR to USD = 1.2 USD/EUR

Ltr to gal = 0.264 gal/ltr

Average fuel cost = 1.063 EUR/ltr * 1.2 USD/EUR ÷ 0.264 gal/ltr

Average fuel cost = 1.2756 / 0.264

Average fuel cost = 4.83 USD/gal

What is the mass of a reindeer (on earth) that has a weight of 623 N

Answers

Answer: 140 pounds

Explanation:

Weight on an object on Earth is different from other bodies in space due to the gravity acting on the object.

Gravity on Earth is 9.80665 m/s². A kg on earth is therefore 9.80665 newtons (N).

With a weight of 623, the mass of the reindeer is:

= 623 / 9.80665

= 63.52832 kg

Converting to pounds:

A kilogram is about 2.20462 pounds:

= 63.52832 * 2.20462

= 140 pounds

A small car of mass 833 kg is parked behind a small truck of mass 1767 kg on a level road. The brakes of both the car and the truck are off so that they are free to roll with negligible friction. A 41 kg woman sitting on the tailgate of the truck shoves the car away by exerting a constant force on the car with her feet. The car accelerates at 1.5 m/s 2 . What is the acceleration of the truck

Answers

Answer: the acceleration of the truck a_t is 0.6911 m/s²

Explanation:

Given the data in the question;

There is no external force on the system; net force on the system is 0

Mass of the truck with the woman M = 1767 kg + 41 kg = 1808 kg

mass of the car m = 833 kg

car acceleration a_c = 1.5 m/s²

now let a_t be the acceleration of the truck in opposite direction

Action force on the car = Reaction force on the car

ma_c = Ma_t

a_t = ma_c / M

we substitute

a_t = (833 × 1.5) / 1808

a_t = 1249.5 / 1808

a_t = 0.6911 m/s²    

Therefore, the acceleration of the truck a_t is 0.6911 m/s²

An electric heater is 90% efficient. How much useful energy is produced from 8000 J?

Answers

Answer:

7200J

Explanation:

you have to find 90 percent of 8000 J to find total efficiency

True or False: The speed of an object changes if the net work done on it is zero. ​

Answers

Answer:

false

Explanation:

If the net work done on an object is zero, it follows that its change in kinetic energy is also zero. Therefore, its speed remains the same.

I think the answer is false

a person lifts a book 2 meters off the ground using 50 n of force how much work was done

Answers

Answer:

100 joules

Explanation:

you cant use this all the time to solve it all the time but 50x2 is 100

A person lifts a book 2 meters off the ground using 50 n of force how much work was done was 100 joules.

What is Work done?

When an object is moved across a specific distance by an external force, work is the quantity of energy that is transmitted to the object.

The quantity of energy transmitted to an object through work is referred to as the work done on the thing.

Force on and displacement of the object are the two basic parts of work done on an object. For a force to exert its force along an object's path of motion, the object must be moved along that path. The units of measurement for work, force, and displacement are joules, newtons, and meters, respectively.

Therefore,  A person lifts a book 2 meters off the ground using 50 n of force how much work was done was 100 joules.

To learn more about Work done, refer to the link:

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George burnt his fingertips so badly that he can't feel anything with them anymore.
Which part of his skin must have been damaged?

O papillary layer

Hypodermis

hyperdemis

subcutaneous layer

Answers

the part tht is mostly damaged is papillary

George burnt his fingertips so badly that he can't feel anything with them anymore, then the papillary layer part of his skin must have been damaged, therefore the correct answer is option A.

What is thermal energy?

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

As given in the problem George burnt his fingertips so badly that he can't feel anything with them anymore.

Option A is the appropriate response since George must have injured the papillary layer of his skin if his fingertips were burned so badly that he can no longer feel anything with them.

Learn more about thermal energy here, refer to the link given below ;

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Determine the force of gravitational attraction between the Earth and the moon. Their masses are 5.98 x 1024 kg and 7.26 x 1022 kg, respectively

Answers

Answer:

[tex]F=1.95\times 10^{20}\ N[/tex]

Explanation:

Mass of Earth, [tex]m_e=5.98 \times 10^{24}\ kg[/tex]

Mass of Moon, [tex]m_m=7.26\times 10^{22}\ kg[/tex]

The distance between Earth and the Moon is, [tex]d=384,400\ km[/tex]

We need to find the force of gravitational attraction between the Earth and the moon. The force of gravity is given by :

[tex]F=G\dfrac{m_em_m}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{5.98 \times 10^{24}\times 7.26\times 10^{22}}{(384400 \times 10^3)^2}\\\\F=1.95\times 10^{20}\ N[/tex]

So, the required force is [tex]1.95\times 10^{20}\ N[/tex].

An object moves with a positive acceleration. Could the object be moving with increasing speed, decreasing speed or constant speed

Answers

Answer:

Increasing speed.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

In this scenario, an object moves with a positive acceleration. Thus, the object is moving with an increasing speed and as such it has acceleration in the same direction as its velocity with respect to time.

What happens to friction if the velocity is constant? What will it equal to and what formula can be used to find it? Is it Fn = Ff?

Answers

Answer:

If the velocity is constant there is no friction it will equal to zero. It is Fn=Ff

Explanation:

How many years does it take for the number of americium-241 nuclei to decrease
from 10 000 to 5000?
Time =
years=

Answers

Answer:

432 years

Explanation:

the half life of americium-241 is approx. 432 years, and the half life means the time it takes for half of the atoms to decay. hope this helps!

what do you already know about asexual and sexual reproduction?

Answers

Answer:

Explanation:

Sexual reproduction is when a male and female have sexual inter course an and produce sex cells. A males sex cell is the sperm and the Females sex cell is the ova or egg cells.

Mass is:

A.how much an object weighs


B.everything around you


C.how much matter is in an object


D.the state of matter such a as solid liquid or gas

Answers

Answer:

C-How much matter is in an object

Explanation:

Explain how scientific knowledge develops through making observations about the natural world. FOR SCIENCE!

Answers

Ree i did dibdjd did djd for g dd d the update is the only way I have the best one pls fix this plz fix

Answer number four because it is one of the factors evaluating science

During an automobile crash test, the average force exerted by a solid wall on a 1,700 kg car that hits the wall is measured to be 170,000 N over a 0.14 s time interval. What was the initial speed of the car (in m/s) prior to the collision, assuming the car is at rest at the end of the time interval

Answers

Answer:

14 m/s

Explanation:

Step One:

Given data:

mass of automobile m= 1700kg

Force F= 170,000 N

time t= 0.14s

v= ??

Required

The velocity of the car

Step two:

From the expression given below, we can find the velocity

Ft= mv

make v subject of the formula

v= Ft/m

v= 170000*0.14/1700

v=23800/1700

v=14 m/s

Determine the maximum velocity and maximum acceleration of a particle which moves in simple harmonic motion with an amplitude of 0.2 in and a period of 0.1 s.

Answers

Answer:

The maximum velocity and maximum acceleration of the particle are approximately 12.566 inches per second and 789.568 inches per square second.

Explanation:

The equation of motion for the position of a particle experimentating a simple harmonic motion ([tex]x(t)[/tex]), measured in inches, is described by the following expression:

[tex]x(t) = A\cdot \cos \left(\frac{2\pi\cdot t}{T} +\phi\right)[/tex] (1)

Where:

[tex]A[/tex] - Amplitude, measured in inches.

[tex]t[/tex] - Time, measured in seconds.

[tex]T[/tex] - Period, measured in seconds.

[tex]\phi[/tex] - Phase, measured in radians.

Then, we obtain the formulas for the velocity and acceleration of the particle by differentiating (1):

[tex]v(t) = -\frac{2\pi\cdot A}{T}\cdot \sin \left(\frac{2\pi\cdot t}{T}+\phi \right)[/tex] (2)

[tex]a(t) = -\left(\frac{2\pi}{T} \right)^{2}\cdot A\cdot \cos \left(\frac{2\pi\cdot t}{T}+\phi \right)[/tex] (3)

From (2) and (3) we find that maximum velocity ([tex]v_{max}[/tex]), measured in inches per second, and maximum acceleration ([tex]a_{max}[/tex]), measured in inches per square second, are defined by the following formulas:

[tex]v_{max} = \frac{2\pi\cdot A}{T}[/tex] (4)

[tex]a_{max} = \left(\frac{2\pi}{T} \right)^{2}\cdot A[/tex] (5)

If we know that [tex]A = 0.2\,in[/tex] and [tex]T = 0.1\,s[/tex], then the maximum velocity and maximum acceleration of the particle are, respectively:

[tex]v_{max} = \frac{2\pi\cdot (0.2\,in)}{0.1\,s}[/tex]

[tex]v_{max} \approx 12.566\,\frac{in}{s}[/tex]

[tex]a_{max} = \left(\frac{2\pi}{0.1\,s} \right)^{2}\cdot (0.2\,in)[/tex]

[tex]a_{max} \approx 789.568\,\frac{in}{s^{2}}[/tex]

The maximum velocity and maximum acceleration of the particle are approximately 12.566 inches per second and 789.568 inches per square second.

When an object executes a to and fro motion is said to be a simple harmonic motion. The maximum velocity and maximum acceleration of the particle will be 12.566 in/s and 789.568  in/s².

What is simple harmonic motion?

When an object executes a to and fro motion in the definite plane when it is tied with the string. The type of motion will be the simple harmonic motion.

Simple harmonic motion is a form of periodic motion in mechanics and physics in which the restoring force on the moving item is directly proportional to the size of the object.

The value of maximum velocity is given by the formula in the SHM motion is

[tex]\rm V_{max = \frac{2\pi A}{T}[/tex]

[tex]\rm V_{max} = \frac{2\times 3.14 \times 0.2 }{0.1}[/tex]

[tex]\rm V_{max = 12.566 \;in/sec[/tex]

The value of maximum acceleration is given by the formula in the SHM motion is

[tex]\rm a_{max}=(\frac{2\pi}{T} )^2.A\\\\ \rm a_{max}=(\frac{2\times 3.14 }{0.1} )^2 \times 0.2 \\\\ \rm a_{max}=789.568\; in/sec^2[/tex]

Hence the maximum velocity and maximum acceleration of the particle will be 12.566 in/s and 789.568  in/s²

To learn more about the simple harmonic motion refer to thr link;

https://brainly.com/question/17315536

the amount of power exerted by a machine that applies a force of 550 N over a distance of 10 m in a time of 5 seconds

Answers

Answer:

The meaning of work is a force that acts on an object and the object moves in respond and the meaning of power is how much work is done in a given amount of time. The two terms are related by is that power is the rate of doing work.

Explanation:

If California experienced drought, which system would be responsible for it and WHY?

Answers

Answer:

California has one of the most variable climates of any U.S state, and often experiences very wet years followed by extremely dry ones . The state's reservoirs have insufficient capacity to balance the water supply between wet and dry years

Explanation:

PLEASE MARK ME AS BRAINLIEST

A motorcycle moving 18.8 m/s has
57800 J of KE. What is its mass?

Answers

Answer:

m = 327.07 kg

Explanation:

Given that,

Kinetic energy of a motorcycle, E = 57800 J

Velocity of the motorcycle, v = 18.8 m/s

We need to find the mass of the motorcycle. The kinetic energy of an object is given by :

[tex]E=\dfrac{1}{2}mv^2[/tex]

m is mass

[tex]m=\dfrac{2E}{v^2}\\\\m=\dfrac{2\times 57800 }{(18.8)^2}\\\\m=327.07\ kg[/tex]

So, the mass of the motorcycle is 327.07 kg.

g Observer A, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed of 0.624c and determines its lifetime to be 159 ns. (a) Observer A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory

Answers

Answer:

[tex]D=29.7648m[/tex]

Explanation:

From the question we are told that

Speed of the particle[tex]V=0.624c[/tex]

Lifetime [tex]t=159ns[/tex]

Generally the equation for distance is mathematically given by

[tex]D=Vt[/tex]

[tex]D=0.624c*159*10^-^9[/tex]

[tex]D=0.624*3*10^8*159*10^-^9[/tex]

[tex]D=29.7648m[/tex]

Therefore the markers are [tex]D=29.7648m[/tex] apart

how do you use vectors daily without realizing it was a vector?

I need help ASAP !!!

Answers

Explanation:

Vectors are quantities that has both magnitude and direction. A vector is described in terms of quantity and the direction it is headed.

There are different forms of vectors that are used in our daily life.

When we describe the motion of a car and the direction it is heading, we are simply talking about its velocity which is a vector. When we say James treks 2km from his school to the house everyday, we are simply describing his displacement. When we apply a force to push the table from one corner of the room to another point, is simply a vector When we change position, it is a vector application.

NEED Answer asap plz!!

Answers

Answer:

I think a is the right not clear but

A 22.0 kg child is riding a playground merry-go- round that is rotating at 40.0 rev/min. What centripetal force must

Answers

Answer:

F = 482.51 N

Explanation:

Given that,

Mass of a child, m = 22 kg

Angular velocity of the merry-go-round, [tex]\omega=40\ rev/min[/tex]

Let the radius of the path, r = 1.25 m

We need to find the centripetal force acting on the child. The formula for the centripetal force is given by :

[tex]F=m\omega^2r\\\\=22\times (4.18879)^2\times 1.25\\\\=482.51\ N[/tex]

So, the required centripetal force is 482.51 N.

What percentage of the acceleration at Earth's surface is the acceleration due to gravity at the position of a satellite located 489 km above Earth

Answers

Answer:

Explanation:

The formula for variation in the value of g due to height h is given by the following relation .

g₁ = g₀ ( 1 - h / R )

g₁ and  g₀ are value of acceleration due to gravity at height h from surface and at surface and  R is radius of the earth .

R = 6370 km , h = 489 km ( given )

g₁ = g₀ ( 1 - 489 / 6370 )

= .923 g₀

g₁ in percent terms = .923 x 100

= 92.3 % .

The angular velocity (in rpm) of the blade of a blender is given in. If θ=0rad at t=0s, what is the blade's angular position at t=20s?

Answers

Answer:

θ = 20.9 rad

Explanation:

In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship

           w = θ / t

           θ = w t

if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians

suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system

          w = 10 rpm [tex](\frac{2\pi rad}{1 rev}) ( \frac{1 min}{60 s} )[/tex]

= 1,047 rads

let's calculate

          θ = 1,047 20

          θ = 20.9 rad

A small block with mass 0.0425 kg slides in a vertical circle of radius 0.525 m on the inside of a circular track. During one of the revolutions of the block, when the block is at the bottom of its path, point A, the magnitude of the normal force exerted on the block by the track has magnitude 4.05 N. In this same revolution, when the block reaches the top of its path, point B, the magnitude of the normal force exerted on the block has magnitude 0.660 N.

Required:
How much work was done on the block by friction during the motion of the block from point A to point B?

Answers

Answer:

[tex]W=-0.501075J \approx -0.5J[/tex]

Explanation:

From the question we are told that

Mass of block [tex]M=0.425kg[/tex]

Radius of circle [tex]r=0.525m[/tex]

Force  of track [tex]F_t=4.05N[/tex]

Normal Force on block[tex]F_n=0.660[/tex]

Generally the equation for Velocity of block is mathematically Given by the law of conservation of energy

[tex]4.05=(0.425kg*9.8)+(0.425kg*v^2)/0.525[/tex]

[tex]v=\sqrt{\frac{0.525*(4.05-(0.0425*9.8)}{0.0425} }[/tex]

[tex]V=-6.69 \approx 7m/s[/tex]

For initial velocity

0.660 = 0.0425 x u^2/0.525 - 0.0425 x 9.8

[tex]v=\sqrt{0.525*\frac{(0.660+(0.0425*9.8)}{0.0425} }[/tex]

[tex]V=-3.646 \approx 4m/s[/tex]

Generally the equation for work done is mathematically Given by

[tex]Wf=(0.5mu^2 - 0.5mv^2) -mg(2R)[/tex]

[tex]Wf=(0.5(0.0425)(4) - 0.5(0.0425)(7) -(0.0425)(9.8)(2*0.525)[/tex]

[tex]W=-0.501075J \approx -0.5J[/tex]

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