Answer:
9
Step-by-step explanation:
First you would need to subtract all the irrelevant students.
So, subtract 4 from 36, which is 34.
34 - (10 + 15) =
34 - 25 =
9
The answer is 9 pupils.
What is the slope of the line? What is the y-intercept of the line? y = 2x + 5
Slope intercept form of a line is, y = mx + c where m is the slope and c is constant.
Judging the given equation y = 2x + 5
Slope (m) of the line is 2,
y-intercept of the line,
y = 2x + 5
y = 2×0 + 5
y = 5
Answered by GAUTHMATH
Answer:
m = 2
y intercept = 5
Step-by-step explanation:
The given equation of the line is ,
[tex]\implies y = 2x +5[/tex]
We know that the Standard equation of Slope Intercept Form of the line is,
[tex]\implies y = mx + c[/tex]
Where ,
m is slope c is y interceptOn comparing to the Standard form of the line we get ,
[tex]\implies Slope = 2 [/tex]
[tex]\implies y - intercept= 5[/tex]
The question is in the photo
Answer:
Step-by-step explanation:
This is a right triangle because angle V is 90. Draw out a right triangle and put V at the 90 degree angle. It doesn't matter where you put U or T; you get the same cos value for T regardless of how you place your other 2 angles. The things you need to know are that UT is the hypotenuse of the triangle, side VU is across from angle T, and side TV is across from angle U.
The cos ratio is side adjacent to the reference angle over the hypotenuse.
Our reference angle is T, so we are looking for the side next to T that is NOT the hypotenuse. This side measures 33; the hypotenuse measures 65, so the tangent ratio of T is
[tex]tanT=\frac{33}{65}[/tex]
Find the circumference of this circle
using 3 for TT.
C = ?
[tex]{ \bf{ \underbrace{Given}}}[/tex]:
Diameter of the circle "[tex]d[/tex]" = [tex]36[/tex]
Value of [tex]π[/tex] = [tex]3[/tex]
[tex]{ \bf{ \underbrace{To\:find}}}[/tex]:
The circumference "[tex]C[/tex]" of the circle.
[tex]{ \bf{ \underbrace{Solution }}}[/tex]:
[tex]\sf\pink{The\:circumference \:"C"\:of\:the\:circle\:is\:108.}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
We know that,
[tex]\sf\purple{Circumference\:of\:a\:circle \:=\:πd }[/tex]
[tex] = 3 \times 36[/tex]
[tex] = 108[/tex]
Therefore, the circumference of the circle is [tex]108[/tex].
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]
Answer:
[tex]\Longrightarrow: \boxed{\sf{108}}[/tex]
Step-by-step explanation:
Apply the formula for the circle's circumference.
[tex]\text{Circumference circle formula:}[/tex]
[tex]\Longrightarrow: \sf{C=\pi d}[/tex]
[tex]\Longrightarrow:\sf{C=?}\\\\\Longrightarrow:\sf{\pi =3}\\\\\Longrightarrow:\sf{d=36}[/tex]
Multiply.
[tex]\sf{3*36=\boxed{\sf{108}}[/tex]
Therefore, the correct answer is 108.I hope this helps! Let me know if you have any questions.
id like some help here... if possible.
Answer:
use average seep hours
top = 77/12 = 6.4 (most)
middle = 6 (middle)
bottom = 50/9 = 5.5 (least)
Step-by-step explanation:
Evaluate the expression. 24.32
2^4×3^2 = 144
___________
Answer:
144 would be the answer.
Step-by-step explanation:
Question:- [tex]2^{4}[/tex] · [tex]3^{2}[/tex]
[tex]2^{4}[/tex] = 2 x 2 x 2 x 2
= 4 x 2 x 2
= 8 x 2
= 16
[tex]3^{2}[/tex] = 3 x 3
= 9
So, [tex]2^{4}[/tex] · [tex]3^{2}[/tex] = 16 x 19
= 144
Circle w has a radius of 20 in and central right angle. VWX find the length of VX. Leave answer in terms of pi
The arc length is 10 Pi
(I don't know for sure, but its what I got)
the sum of all the exponents on all the variables of a term
plsss answer
Answer:
Answer: for polynomials in two or more variables, the degree of a term is the sum of the exponents of the variables in the term; the degree (sometimes called the total degree) of the polynomial is again the maximum of the degrees of all terms in the polynomial
Factorise this equasion
X^2-5
Answer:
(x - [tex]\sqrt{5}[/tex] )(x + [tex]\sqrt{5}[/tex] )
Step-by-step explanation:
x² - 5 ← is a difference of squares and factors in general as
a² - b² = (a - b)(a + b) , then
x² - 5
= x² - ([tex]\sqrt{5}[/tex] )²
= (x - [tex]\sqrt{5}[/tex] )(x + [tex]\sqrt{5}[/tex] )
Choose the graph of y = -3 sin x.
Step-by-step explanation:
the graph should look something like this
help me pls i don't ge this
Answer:
9. The area of rectangle S is four times bigger than rectangle R
10. (1, 3)
Step-by-step explanation:
To find the solution of the two linear equations:
y=x+2
y=-2x+5
x+2=y=-2x+5
3x=3
x=1
y=1+2
y=3
(1,3)
Why does it say your phone is being attacked and then said something with 26 when I go on a website is it lying or do I have a virus?
Answer:
If you go to a website that has a red (or orange) triangle with an exclamation mark next to the link, it's an untrusted site. The things you list (your phone is being attacked and then said something with 26..) are likely to be scam ads (probably viruses). Therefore, I do not recommend you to click the ads or enter that site again.
2x^2 - 4x + 5 x = -3
What is the distance between
(
−
5
,
−
5
)
(−5,−5)left parenthesis, minus, 5, comma, minus, 5, right parenthesis and
(
−
9
,
−
2
)
(−9,−2)left parenthesis, minus, 9, comma, minus, 2, right parenthesis?
Answer:
do you have a pic of the problem
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
the answer is the sqare rute of 25 which is 5
Which of the following shows 5x + 17 + 8x – 9 + 2y in simplest terms?
Answer:
5x+8x+17-9+2y
13x+8+2y
Answer:
13x+8+2y
Step-by-step explanation:
5x+8x=13x
17–9=8
2y=2y
AABC has vertices at A(5,1), B(-3,1), and C(-2,5).
Point D is located on the intersection of the altitude and AB, in such a way that D has coordinates at
(-2,1).
Given that is a standard normal random variable, find for each situation (to 2 decimals). a. The area to the left of is . (Enter negative value as negative number.) b. The area between and is . c. The area between and is . d. The area to the left of is . e. The area to the right of is . (Enter negative value as negative number.)
Answer:
-0.80
1.66
0.26
2.56
-0.50
Step-by-step explanation:
The values are the probability values either to the right or left of a given z - value ;
The Z - values could be obtained using the standard normal distribution table or a calculator :
Using the Z probability calculator ;
Area to the left of z is 0.2119
1.)
P(z < z) = 0.2119
z = - 0.8
2.)
Area between - z and z = 0.9030
Area to the left of z = 0.9030 plus
Area to the right of z = (1 - 0.9030) / 2 = 0.097/2 = 0.0485
(0.9030 + 0.0485) = 0.9515
P(z < z) = 0.9515
z = 1.66
3.)
Area between - z and z = 0.2052
Area to the left of z = 0.2052 plus
Area to the right of z = (1 - 0.2052) / 2 = 0.7948/2 = 0.3974
(0.2052 + 0.3974) = 0.6026
P(z < z) = 0.6026
z = 0.26
D.)
The area to the left of z is .9948
P(Z < z) = 0.9948
z = 2.562
E.)
The area to the right of z is .6915.
P(Z < z) = 1 - 0.6915
P(Z < z) = 0.3085
z = - 0.5
How would the one-step equation x/5 = 5 be solved?
Multiply both sides by 1/5
Multiply both sides by the reciprocal of 1/5
Divide 5 by both sides
Divide one side by 5
Answer:
2nd option
Step-by-step explanation:
Given
[tex]\frac{x}{5}[/tex] = 5 ( multiply both sides by 5, the reciprocal of [tex]\frac{1}{5}[/tex] to clear the fraction )
x = 25
Of the four choices given, which two, when written as a system, have a solution of (-4,5)?
х
-1
2
3
5
y
2
-1
-2
-4
2x+y=-3
-2x+y=-3
Х
-1
2.
3
7
0
-3
4
-8
2x+y=-3 and
Х
--1
2
3
5
y
2.
-1
-2
-4
0-2x+y=-3 and
х
-1
2
3
5
у
2.
-1
-2
-4
Answer:
both choices with 2x+y = -3
Step-by-step explanation:
to have the solution (-4, 5), that point must be on both equations/functions, meaning it must be on either one.
in other words, if the point is not on at least one of the functions, it cannot be a solution for that system.
the given function
2x + y = -3
looks like for the point (-4, 5)
2×-4 + 5 = -3
-8 + 5 = -3
-3 = -3
correct.
but
-2x + y = -3
looks like for (-4, 5)
-2×-4 + 5 = -3
8 + 5 = -3
13 = -3
wrong. the point is not on this function.
as we can therefore rule out 2 of the answer options, the other 2 most be correct.
The two equations which when written as a system has a solution of (-4, 5) is; 2x + y = -3 and 2x + y = -3
Inequalities
The correct equations must have same output with the given one when we place -4 and 5 for x and y respectively.
Now, for 2x + y = -3
At x = -4, and y = 5 we have;
2(-4) + 5 = -3
Same with the right hand side.
For -2x + y = -3;
At x = -4, and y = 5 we have;
-2(-4) + 5 = 13
Not the same with the right hand side.
Thus, the two equations with 2x + y = -3 are correct
Read more about Inequalities at; https://brainly.com/question/24372553
How many solutions does the equation 5X +10 equals 5X - 8 have
A: zero
B: one
C:Two
D: infinity many
Answer:
zero
Step-by-step explanation:
5x+10 = 5x-8
5x-5x = -8-10
0 = -18
so zero
A triangle ABC is right angled at A, AL is perpendicular to BC. Prove that angle BAL= angle BCA.
Step-by-step explanation:
triangle BCA=BAL bcoz Angle BCA= Angle BAL
PLEASE HELP SUMMER SCHOOL!!!!
Ed is 7 years older than Ted. Ed’s age is also times Ted’s age. How old are Ed and Ted?
A.
Ted is 15 years old, and Ed is 22 years old.
B.
Ted is 14 years old, and Ed is 21 years old.
C.
Ted is 13 years old, and Ed is 20 years old.
D.
Ted is 12 years old, and Ed is 19 years old.
Answer:
EXPLAINED ON THE ATTACHED
Which expression is equivalent to −10x−10+2x+9?
Answer:
-8x - 1
General Formulas and Concepts:
Algebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
-10x - 10 + 2x + 9
Step 2: Simplify
Combine like terms (x): -8x - 10 + 9Combine like term: -8x - 1[tex]\huge\textsf{Hey there!}[/tex]
[tex]\large\textsf{-10x - 10 + 2x + 9}[/tex]
[tex]\huge\textsf{COMBINE the LIKE TERMS}[/tex]
[tex]\large\textsf{-10x + 2x - 10 + 9}[/tex]
[tex]\large\textsf{-10x + 2x}\\\\\large\textsf{ = \bf -8x}[/tex]
[tex]\large\textsf{-10 + 9}\\\\\large\textsf{ = \bf -1}[/tex]
[tex]\boxed{= \large\textsf{\bf -8x - 1}}\large\checkmark[/tex]
[tex]\boxed{\boxed{\huge\textsf{Answer: \bf -8x - 1 }}}\huge\checkmark[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
The graph of y=x^3+x^2-6x is shown....
hello,
" a turning point is defined as the point where a graph changes from either increasing to decreasing, or decreasing to increasing"
a)
[tex]y=x^3+x^2-6x\\\\y'=3x^2+2x-6=0\\x=\dfrac{-2-\sqrt{76} }{6} \approx{-1.786299647...}\\or\\x=\dfrac{-2+\sqrt{76} }{6} \approx{1.1196329...}\\[/tex]
b)
Zeros are -3,0,2.
Sol={-3,0,2}
The solution of the graph function y=x³+x²-6x are -3 , 0 and 2
What is graph?The link between lines and points is described by a graph, which is a mathematical description of a network. A graph is made up of certain points and the connecting lines. It doesn't matter how long the lines are or where the points are located. A node is the name for each element in a graph.
We have the function
y=x³+x²-6x
now, equating it to 0
x³+x²-6x = 0
x² + x - 6= 0
x² - 3x + 2x -6 =0
x(x -3) + 2(x -3)
x= 3 and -2
Now, ew can see from the that the equation is touching the x-axis at three points and it will represent three zeroes of the equation.
So, the solution of the graph are -3 , 0 and 2
Learn more about graph here:
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La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?
Answer:
Falso.
Step-by-step explanation:
Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:
(a) El exponente es cero.
(b) El exponente es un negativo impar.
(c) El exponente es un negativo par.
(d) El exponente es un positivo impar.
(e) El exponente es un positivo par.
(a) El exponente es cero:
Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.
(b) El exponente es un negativo impar:
Considérese las siguientes expresiones:
[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]
Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:
[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]
[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]
[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]
Si [tex]n[/tex] es impar, entonces:
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]
Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.
(c) El exponente es un negativo par.
Si [tex]n[/tex] es par, entonces:
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]
Puesto que [tex]d' = c'[/tex], la proposición es verdadera.
(d) El exponente es un positivo impar.
Considérese las siguientes expresiones:
[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]
[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]
Si [tex]n[/tex] es impar, entonces:
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]
(e) El exponente es un positivo par.
Considérese las siguientes expresiones:
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]
Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.
Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.
Your vacation cabin on the lake has three rooms. The bathroom is 12' X 6', the bedroom is 14' X 18' and the great room is 20' X 30'. The ceiling height is 10'. What is the total volume of your cabin? Group of answer choices 9420 Cubic Feet 9240 Cubic Feet 9240 Square Feet 9420 Square Feet
Answer: [tex]9240\ ft^3[/tex]
Step-by-step explanation:
Given
Dimension of the bathroom is [tex]12'\times 16'[/tex]
Dimension of the bedroom is [tex]14'\times 18[/tex]
Dimension of the great room is [tex]20'\times 30'[/tex]
Height of the ceiling is [tex]h=10'[/tex]
Total area of the cabin
[tex]\Rightarrow A=12\times6+14\times 18+20\times 30\\\Rightarrow A=72+252+600\\\Rightarrow A=924\ ft^2[/tex]
Volume of the cabin is [tex]V=A\times h[/tex]
[tex]\Rightarrow V=924\times 10\\\Rightarrow V=9240\ ft^3[/tex]
If a car is moving on a straight line with a velocity of 40 m/s and it changes its velocity to 60 m/s in 4 seconds, calculate its acceleration.
Answer:
5m/s²
Step-by-step explanation:
Given :-
Initial Velocity = 40m/s Final velocity = 60 m/sTime = 4sTo Find :-
The acceleration .Solution :-
We know that the rate of change of velocity is called acceleration. Therefore ,
[tex]\sf\implies a = v - u / t \\ [/tex]
[tex]\sf\implies a = 60m/s - 40m/s/ 4 \\ [/tex]
[tex]\sf\implies a = 20m/s \div 4 \\[/tex]
[tex]\bf\implies a = 5m/s^2[/tex]
For each function below, identify and enter the percent rate of change per unit, t. Round to the nearest tenth of a percent.
Then use the drop-down menus to classify each as exponential growth or decay
The percentage rate of change of the given functions is given by the
derivative of their natural logarithm.
Responses:
[tex]f(t) = 1.18^t[/tex]
16.6%, exponential growth[tex]g(t) = 2^{-2 \cdot t}[/tex]
-138.6%, exponential decay[tex]h(t) = 1.19^{\frac{t}{10} }[/tex]
1.7%, exponential growth[tex]k(t) = 0.13^t[/tex]
-204%, exponential decayWhich method is used to determine the percentage rate of change?The percentage rate of change can be presented as follows;
[tex]Percentage \ rate \ of \ change = \mathbf{100 \times \dfrac{d}{dt} ln \left(f(t)\right)}[/tex]
[tex]f(t) = \mathbf{ 1.18^t} \ gives;[/tex]
[tex]100 \times \dfrac{d}{dt} \left( ln \left(1.18^t\right) \right) = \mathbf{ 100 \times ln(1.18)} \approx \underline{16.6\%}[/tex], exponential growth[tex]g(t) = \mathbf{2^{-2 \cdot t} }\ gives;[/tex]
[tex]100 \times \dfrac{d}{dt} \left( ln \left(2^{-2 \cdot t}\right) \right) = \mathbf{ 100 \times -2 \times ln(2)} \approx \underline{ -138.6 \%}[/tex] , exponential decay
[tex]h(t) = \mathbf{1.19^{\frac{t}{10} } }\ gives;[/tex]
[tex]100 \times \dfrac{d}{dt} \left( ln \left(1.19^{\frac{t}{10} }\right) \right) = \mathbf{ 100 \times \dfrac{10 \cdot ln(1.19)}{100}} \approx 1.7 \%[/tex], exponential growth
[tex]k(t) = \mathbf{ 0.13^t} \ gives;[/tex]
[tex]100 \times \dfrac{d}{dt} \left( ln \left(0.13^t }\right) \right) = \mathbf{100 \times ln(0.13)}\approx -204 \%[/tex], exponential decay
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Find the 66th term of the arithmetic sequence 25, 10, -5, ...
Answer:
1000
Step-by-step explanation:
Given data
we have the sequence
25, 10, -5, ...
we want to find the 66th term, let us apply the formula
an = a + (n – 1)d
a= 25
n= 66
d= 15
substitute
a66= 25+(66-1)15
a66= 25+(65)*15
a66= 25+975
a66= 1000
Hence the 66th term is 1000
Find the values of x and y.
Answer:
since y is across from 60 so
y=60
and on the bottom it is 15 so
x+3=15
x=12
Hope This Helps!!!
a) Work out the value of 10
Step-by-step explanation:
√10= 1.414×2.236
= ±3.162
hope it is helpful to you ☺️