Imagine you derive the following expression by analyzing the physics of a particular system: M= (mv2r)(mGr2). Simplify the expression for M using the techniques mentioned above.

Answer:

18.24 seconds

Explanation:

First you convert the km/h to m/s, 70km/h=(175/9)m/s,85km/h=(425/18)m/s.

You know it took 10 seconds for the police to reach 85 km/h. Calculate the distance that the car is ahead of the police (175/9)*10=1750/9m. Then by divide 1750/9 with 425/18, you will get the value 8.24. Add the 10 seconds with the 8.24 you will get 18.24 sec which is the total time.

Answer:

299.4 MeV

Explanation:

For 40 Ar

Number of neutrons = 22

Number of protons= 18

Mass of each proton = 1.007277 amu

Mass of each neutron= 1.008665 amu

Total mass of protons= 18 × 1.007277 amu = 18.130986 amu

Total mass of neutrons = 22 × 1.008665 amu = 22.19063 amu

Total mass of protons and neutrons= 18.130986 + 22.19063 = 40.321616 amu

Mass defect = 40.321616 amu - 40 amu

Mass defect = 0.321616 amu

Since 931 is the conversion factor from amu to MeV

Binding energy = 0.321616 amu × 931 = 299.4 MeV

Binding energy = 299.4 MeV

The question is missing. Here is the complete question.

A point charge Q moves on the x-axis in the positive direction with a speed of 160 m/s. A point P is on the y-axis at y = + 20mm. The magnetic field produced at point P, as the charge moves through the origin is equal to  -0.6μT k. What is the charge Q? [tex]\mu_{0}=4.\pi.10^{-7}[/tex]T.m/A)

Answer: Q = [tex]-0.015.10^{-3}[/tex]C

Explanation: Magnetic Field (B) is a vector field, i.e., has magnitude and direction, and describes the distribution of magnetic force in the space around. It happens when an electrical charge is in movement.

Its magnitude is determined by the formula:

[tex]B = \frac{\mu_{0}}{4.\pi}\frac{Qvsin(\theta)}{r^{2}}[/tex]

where

[tex]\mu_{0}[/tex] is the vacuum permeability constant;

r is the distance between charge and a point you want to know the magnetic field;

θ is the angle between velocity and distance r;

For this question, magnetic field has that magnitude when charge is passing through the origin. So, angle between velocity and distance is 90°.

Calculating to determine charge:

[tex]-0.6.10^{-6} = \frac{4.\pi.10^{-7}}{4.\pi}\frac{Q.160.sin(90)}{(2.10^{-2})^{2}}[/tex]

[tex]-0.6.10^{-6} = 10^{-7}\frac{Q.160.1}{(2.10^{-2})^{2}}[/tex]

[tex]-2.4.10^{-10} = Q.160.10^{-7}[/tex]

[tex]Q = \frac{-2.4.10^{-10}}{160.10^{-7}}[/tex]

[tex]Q = -0.015.10^{-3}[/tex]

Charge Q is [tex]-0.015.10^{-3}[/tex]C or [tex]-0.015[/tex]mC.

Answer:

The interpretation including its given subject is listed in the subsection below on explanatory.

Explanation:

Homeostasis should be any mechanism of self-regulation from which an individual seeks to preserve equilibrium when adapting to requirements better suited towards its existence.

Two mechanisms are given below:

Answer:

A) W= 200N, B) m = 20.4 kg , C) N = 200 N , D)  F = 100 N ,

E) F_reaction = 200 N , F)  F _net = 40 N

Explanation:

This exercise can be solved using Newton's second law

A) The gravitational force is the weight of the block

          Fg = W = m g

          W = 200 N

B) m = W / g

          m = 200 / 9.8

          m = 20.4 kg

C) Normal is the reaction of the floor to the weight of the block

          N-W = 0

          N = W

          N = 200 N

D) we write Newton's second law on the x-axis

          F - fr = 0

          F = fr

the friction force equation is

         fr = μ_s N

         fr = μ_s W

subtitute

          F = 0.50 200

         F = 100 N

E) As the forces in the natural are in pairs, by Newton's third law or law of action and reaction, the block responds with a force of equal magnitude, but opposite direction

         F_reaction = 200 N

F and G) We write Newton's second law

         F - fr = m a

         fr =  N = μ_k mg

         F - μ_k m g = m a

        μ_k = (F - ma) / mg

        μ_k  = (200 - 20.4 1.96) / 200

        μ_k = 0.8

In general, the coefficient of kinetic friction is lower than the static one

the net force is

       F_net = F -fr = F - μ_k W

       F_net = 200 - 0.8 200

       F _net = 40 N

Answer:

m₂ = 15660 kg

Explanation:

Given that,

Before collision,

Mass of box car 1, m₁ = 8700 kg

Speed of box car 1, u₁ = 14 m/s

Speed of box car 2, u₂ = 0 (at rest)

After collision,

The two stick together and move off with a speed of 5 m/s

Let m₂ is the mass of the second car. As cars stick together, it is a case of inelastic collision. Using the conservation of momentum as follows :

[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\8700\times 14+0=(8700+m_2)5\\\\121800=43500+5m_2\\\\121800-43500=5m_2\\\\m_2=\dfrac{78300}{5}\\\\m_2=15660\ kg[/tex]

So, the mass of the second car is 15660 kg.

Answer:

15000 kg

Explanation:

m1v1+m2v2=(m1m2)Vf

8700(15)=(8700+m)5.5

130500=8700+m(5.5)

130500/5.5=8700+m

130500-8700=m

m=15027.3 kg

Answer:

False

Explanation:

This is because according to newtons second law which says the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. So take for example a net a net force in opposite direction will cause an object to slow down.

velocity vector here is not the same as acceleration vector

Answer:

1 second later the vehicle's velocity will be:

[tex]v(1)= 6\,\,\frac{m}{s} \\[/tex]

5 seconds later the vehicle's velocity will be:

[tex]v(5)=14\,\,\frac{m}{s}[/tex]

Explanation:

Recall the formula for the velocity of an object under constant accelerated motion (with acceleration "[tex]a[/tex]"):

[tex]v(t)=v_0+a\,t[/tex]

Therefore, in this case [tex]v_0=4\,\,\frac{m}{s}[/tex]  and [tex]a=2\,\,\frac{m}{s^2}[/tex]

so we can estimate the velocity of the vehicle at different times just by replacing the requested "t" in the expression:

[tex]v(t)=v_0+a\,t\\v(t)=4+2\,\,t\\v(1)=4+2\,(1) = 6\,\,\frac{m}{s} \\v(5)=4+2\,(5)=14\,\,\frac{m}{s}[/tex]

Answer:

The detector temperature doesn't affect retention time

Explanation:

Retention time is one of the chromatographic parameters. Is defined as the time of a compound spends from injection to detection.

A solute in GC is added to the injector where is volatilized. When volatilized, it pass through a column until the detector.

The detector temperature doesn't affect retention time. To change retention time you must change injector temperature or column temperature. An increase in column or injector temperature results in a decrease in retention time.

Answer:

54.4ev

Explanation:

Using

E = - me⁴Z²/8Eo²h²n²

Where n= 1

Z= 1

h=6.6E-31Js

me= 9.1x 10-31kg

Eo=8.85E-12m-3 kg-1 s4 A2

So by substituting

E= -(9.1x 10-31kg)⁴x 1²/8(8.85E-12m-3 kg-1 s4 A2)² x (6.6E-31Js)² x 1²

So E= 54.4ev

Answer:

4.8E-19C

Explanation:

Charge is calculated by getting the net sum of protons and electrons

So

87protons - 84electrons= +3

So the charge of the ion is +3

But 1proton= 1.6*10^-19C

So charge will be 3 x 1.6E-19C

4.8x10^-19C

Answer:

A.46.7mph

B.50mph

Explanation:

We know that from the data given

Julie drove 50 miles at a speed of 38 mph, and another 50 miles for 62mph. Thus , for the first 50 miles, she drove for the following time

T1= distance/speed

====> 50/38= 1.3hrs

the next 50 miles, she drove for

T2= 50/62

= 0.8hrs

So average speed is

Totaldistance/ total time

100/2.1

= 46.7mph

B. Because the time she used driving at 35 mph is the same amount of time she used driving at 65 mph, the average speed is just the average of the two speeds given which is

(50+50)/2 = 50mph

Explanation:

Answer:

46.95 mph

50 mph

Explanation:

first, we start by finding the average speed. The average speed if given by the relation

Average Speed = Total distance / Total Time

from the question, we know that

total distance is 100 mi

total time is time of the first distance + time of the second distance

t = (50mi / 38) + (50mi / 62)

t = 1.32 + 0.81

t = 2.13 hrs

Then, the average speed going to grandmothers house will be

Speed = 100mi / 2.13 hrs

Speed = 46.95 mph

on her return trip

speed on the first distance * half the time + speed on the second distance * half the time

x = V1 * t/2 + V2 * t/2

100 = 38 * t/2 + 62 * t/2

100 = 100 * t/2

t/2 = 100/100

t/2 = 1

t = 2 hrs

The average speed then will be, = 100 mi / 2 hrs = 50mph

Answer:

The  force is [tex]F_1 = 400.8 \ N[/tex]

Explanation:

From the question we are told that

   The first  diameter is  [tex]d_1 = 4.0 \ cm = 0.04 \ m[/tex]

   The second diameter is  [tex]d_2 = 8.0 \ cm = 0.08 \ m[/tex]

Generally the first area is  

         [tex]A_1 = \pi * \frac{d^2_1 }{4}[/tex]

=>      [tex]A_1 = 3.142 * \frac{0.04^2}{4}[/tex]

=>       [tex]A_1 = 0.00126 \ m^2[/tex]

The  second area is  

     [tex]A_2 = \pi * \frac{d^2_2 }{4}[/tex]

     [tex]A_2 = 3.142 * \frac{0.08^2}{4}[/tex]

     [tex]A_2 = 0.00503 \ m^2[/tex]

For a hydraulic press the pressure at both end must be equal .

Generally  pressure is mathematically represented as

    [tex]P = \frac{F}{A}[/tex]

=>  

   [tex]\frac{F_1}{A_1 } = \frac{F_2}{A_2 }[/tex]

=>   [tex]F_1 = \frac{1600}{0.00503} * 0.00126[/tex]

=>    [tex]F_1 = 400.8 \ N[/tex]

Answer:The answer is option A.

Momentum=mass×velocity.

Orange train=mass is 200 and velocity is 1.

which is 200×1=200kgm/s.

The initial momentum of the orange train is 200 kgm/s.

The orange train is having mass of 200 kg and it is travelling with speed of 1 m/s.

                     So, the orange trains momentum will be ,

                               P = mv

                            ∴ P = 200 x 1

                            ∴ P = 200 kgm/s

Therefore, the initial momentum of the orange train is 200kgm/s.

Learn more about momentum here -

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Answer:

Manometer is a measures to the atmospheric measure.

Barometer is a measure to the atmospheric pressure.

Explanation:

Answer:

The  depth of stream to the student is  [tex]d_1 = 0.2932 \ m[/tex]

Explanation:

From the question we are told that

   The actual  depth of the stream is [tex]d = 39 \ cm = 0.39 \ m[/tex]  

    The  refractive index of the water is  [tex]n = 1.33[/tex]

Generally the apparent depth of the stream is mathematically represented as

         [tex]d_1 = \frac{d}{1.33}[/tex]

substituting values

        [tex]d_1 = \frac{ 0.39}{1.33}[/tex]

        [tex]d_1 = 0.2932 \ m[/tex]

Answer:

and the forces acting on the particle as a function of time.

Explanation:

The principle of linear impulse and momentum is obtained by integrating the equation of motion with respect to time. hope this helps you :)

The linear impulse and momentum equation is obtained by integrating the force acting on the object with respect to time.

The Linear Impulse is defined as the momentum exerted by a force during a time interval.

The linear impulse and momentum equation is obtained by integrating the force with respect to time.

From the equation of the impulse-momentum theorem:

∆p = J

where,

∆p is the change in momentum of the object,

J is the impulse applied to it.

The impulse is defined as the product of force and the time over which the force is applied.

Thus, we can write the impulse as:

J = ∫ F dt

where,

F is the force acting on the object,

dt is the time interval during which the force acts.

By substituting this expression for J in the momentum equation,

we get:

∆p = ∫ F dt

which is the linear impulse-momentum equation.

Learn more about the linear impulse here:

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0.37 dg

1 dg ....... 100 mg

x dg .........37 mg

x = 1×37/100 = 37/100 = 0.37 dg

Answer:

A) f = 1.28x10¹⁵ Hz

B) y = 0.20 m

Explanation:

A) The frequency of light can be found as follows:

[tex] f = \frac{c}{\lambda} [/tex]

Where:

c: is the speed of light = 3.0x10⁸ m/s

λ: is the wavelength

The wavelength can be calculated using the following equation:

[tex] sin(\theta) = \frac{\lambda(m - 1/2)}{d} [/tex]

Where:

m = 3, d = 6 μm, θ = 5.6°        

[tex] \lambda = \frac{d*sin(\theta)}{m - 1/2} = \frac{6 \cdot 10^{-6} m*sin(5.6)}{3 - 1/2} = 2.34 \cdot 10^{-7} m [/tex]      

Now, the frequency is:

[tex] f = \frac{c}{\lambda} = \frac{3.0 \cdot 10^{8} m/s}{2.34 \cdot 10^{-7} m} = 1.28 \cdot 10^{15} Hz [/tex]    

Hence, the frequency of light used for this experiment is 1.28x10¹⁵ Hz.

B) The distance between the second bright fringe and central fringe (y) is:

[tex] tan(\theta) = \frac{y}{D} [/tex]        

[tex] y = D*tan(\theta) = 2 m*tan(5.6) = 0.20 m [/tex]

Therefore, the distance between the second bright fringe and central fringe is 0.20 m.

I hope it helps you!

Answer:

The puck moves a vertical height of 2.6 cm before stopping

Explanation:

As the puck is accelerated by the spring, the kinetic energy of the puck equals the elastic potential energy of the spring.

So, 1/2mv² = 1/2kx² where m = mass of puck = 39.2 g = 0.0392 g, v = velocity of puck, k = spring constant = 59 N/m and x = compression of spring = 1.3 cm = 0.013 cm.

Now, since the puck has an initial velocity, v before it slides up the inclined surface, its loss in kinetic energy equals its gain in potential energy before it stops. So

1/2mv² = mgh where h = vertical height puck moves and g = acceleration due to gravity = 9.8 m/s².

Substituting the kinetic energy of the puck for the potential energy of the spring, we have

1/2kx² = mgh

h = kx²/2mg

= 59 N/m × (0.013 m)²/(0.0392 kg × 9.8 m/s²)

= 0.009971 Nm/0.38416 N

= 0.0259 m

= 2.59 cm

≅ 2.6 cm

So the puck moves a vertical height of 2.6 cm before stopping

Answer:

Current can be induced in a lot of ways. I'll try and list as much of these methods as I can here.

1. Moving a bar magnet relative to a wire coil

2. Moving a wire coil relative to a magnet.

3. Move a wire coil that has electricity flowing though it relative to a wire coil without electricity flowing through it.

4. Moving a current carrying circuit relative to a non-current carrying circuit

5. Rapidly opening and closing the switch of a current carrying circuit beside a non current carrying circuit.  

6. Moving a bar magnet through the middle of a  wire coil.

7. Moving a wire coil through a magnet

8. Moving a circuit relative to a magnetic field.

The main idea is to cause a change in the magnetic field, or to change the available area of the wire loop, or to change the angle between the field and the loop.

Answer: [tex]v_{rms} =[/tex] 273m/s

Explanation: Root Mean Square Speed of an atom or molecule is the speed of a particle in a gas. It is the average speed a particle in a gas can have.

It can be calculated:

[tex]\frac{1}{2}mv^{2} = \frac{3}{2} k_{B}T[/tex]

[tex]v^{2} = \frac{3k_{B}T}{m}[/tex]

[tex]v = \sqrt{\frac{3k_{B}T}{m}}[/tex]

m is mass of one atom or molecule in kg.

An atom of Arsenic sublimes at 614°C. Converting to Kelvin:

T = 614 + 273 = 887K

Molecular mass of As4 is approximately 0.3kg.

[tex]m = \frac{0.3}{6.10^{23}}[/tex]

[tex]m=5.10^{-25}[/tex]kg

Calculating Root mean square speed :

[tex]v = \sqrt{\frac{3*1.4.10^{-23}*887}{5.10^{-25}}[/tex]

[tex]v = \sqrt{745.08.10^{2}[/tex]

v = 273m/s

The root mean square speed of As4 is approximately 273m/s.

Answer:

Nitrogen 13

Explanation:

We need fill in the blank the nuclide symbol for the missing particle in the following nuclear equation.

[tex]X\rightarrow ^0e_1+^{13}C_6[/tex]

In this reaction, the emission of positron takes place. The atomic number in the LHS and the RHS should be same. So,

[tex]^{13}_7 N \rightarrow ^0e_1+^{13}C_6[/tex]

So, the LHS have nitrogen 13, a radioactive isotope.

Answer:

 Q = 80000 cal  

Explanation:

La expresin para el calor es

           Q = m [tex]c_{e}[/tex]ce ΔT

el calor especifico del agua es  ce= 1 cal/gr ºC

la temperatura de ebullición del agua es Ef = 100ºC y partimos de la temperatura ambiente To= 20 OC

           Q = m 1 ( 100 – 20)

            q= 80 m

en el ejercicio no se da la masa de agua, pro podemos suponer,  pote lleva 1 litros  = 100 G

            Q = 80 1000  

            Q = 80000 cal  

Answer:

(a) The magnetic energy density in the field is 6.366 J/m³

(b) The energy stored in the magnetic field within the solenoid is 5 kJ

Explanation:

magnitude of magnetic field inside solenoid, B = 4 T

inner diameter of solenoid, d = 6.2 cm

inner radius of the solenoid, r = 3.1 cm = 0.031 m

length of solenoid, L = 26 cm = 0.26 m

(a) The magnetic energy density in the field is given by;

[tex]u _B = \frac{B^2}{2\mu_o} \\\\u _B = \frac{(4)^2}{2(4\pi*10^{-7})}\\\\u_B = 6.366*10^6 \ J/m^3[/tex]

(b) The energy stored in the magnetic field within the solenoid

[tex]U_B = u_B V\\\\U_B = u_B AL[/tex]

[tex]U_B = u_B(A)(L)\\\\U_B = 6.366*10^6(\pi * 0.031^2)(0.26) \\\\U_B = 4997.69 J\\\\U_B = 5 \ KJ\\[/tex]

Answer:

The correct answer is d

Explanation:

In this exercise they ask us which statement is correct, for this we plan the solution of the problem, this is a Doppler effect problem, it is the frequency change due to the relative speed between the emitter and the receiver of sound.

The expression for the Doppler effect of a moving source is  

f ’= (v / (v- + v_s) f  

From this expression we see that if the speed the sound source is different from zero feels a change in the  frequency.

The correct answer is d

Answer:

[tex]1.12056\times 10^{-8}\ N[/tex].

Kramer could try blowing air on the bowling pin.

Explanation:

[tex]m_1[/tex] = Mass of bowling ball = 7 kg

[tex]m_2[/tex] = Mass of bowling pin = 1.5 kg

[tex]r[/tex] = Distance between them = 0.25 m

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Force of gravity is given by

[tex]F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 7\times 1.5}{0.25^2}\\\Rightarrow F=1.12056\times 10^{-8}\ N[/tex]

The force of gravity between the ball and the pin is [tex]1.12056\times 10^{-8}\ N[/tex].

Kramer could try blowing air on the bowling pin.

Answer:

Pressure, [tex]P=1.84\times 10^7\ Pa[/tex]

Explanation:

Given that,

Force with which pickaxe strikes is 3600 N

The end of the pickaxe measure 15mm by 13mm.

We need to find the pressure exerted on the pipe by the pickaxe. Pressure exerted is equal to the force acting per unit area. So,

[tex]P=\dfrac{F}{A}[/tex]

A = 15 mm × 13 mm = 195 mm² = 0.000195 m²

So,

[tex]P=\dfrac{3600\ N}{0.000195\ m^2}\\\\P=18461538.46\ Pa\\\\\text{or}\\\\P=1.84\times 10^7\ Pa[/tex]

Answer:

that there would be more clouds.

Explanation:

one of the cycles is precipitation. without water there would be no rain and clouds are what causes the rain to come down

Answer:

it's D or 4 that there would be more clouds

Explanation:

hoped it helped!!